Occupants of cars hit from behind, even at low speed, often suffer serious neck injury from whiplash. During a low‑spee rear‑end collision, a person's head suddenly pivots about the base of the neck through a 50∘ angle, a motion that lasts 220 ms.The distance from the base of the neck to the center of the head is typically about 20 cm, and the head normally comprises about 6.0% of body weight.Model the motion of the head as having a uniform speed over the course of its pivot. Compute answers to two significant figures.1. What is the acceleration ????centacent of the head during the collision?2. What force ????F does the neck exert on the head of a 65 kg65 kg person in the collision? Neglect the force of gravity on the head, and report the answer in units of both newtons and pounds.3. Would headrests mounted to the backs of the car seats help protect against whiplash? Why or why not?a. Yes. A headrest applies an upward force on the head, along the direction of the neck, that cancels the downward force applied by the neck.b. Yes. A headrest ensures that both the head and the body experience the same forward force at roughly the same time.c. No. A headrest applies a mostly horizontal force to the head, so does not affect the mostly vertical force applied by the neck during whiplash.d. No. A headrest reduces the angle traversed by the head, not the speed of the head relative to the body, thus it does not affect the force that the neck applies to the head.

Dense because food do be dense tho

Answer:

a = ω^2 A      formula for max acceleration (ignoring sign)

V = ω A         formula for max velocity

V^2 = ω^2 A^2 = a A   from first equation

E = 1/2 M V^2 = 1/2 * 2.98 * 3.55 * .0805 = .426 J

(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule

The height difference that stabilizes between the surfaces of the mercury in the U-tube is approximately 0.142 m.

To solve this problem, we can use the principle of continuity and Bernoulli's equation. The principle of continuity states that the mass flow rate of a fluid is constant, so A1v1 = A2v2, where A is the cross-sectional area and v is the velocity of the fluid at two different points in the tube. Bernoulli's equation states that the total energy of a fluid (the sum of its kinetic energy, potential energy, and pressure energy) is conserved along a streamline.

Let h be the height difference between the surfaces of the mercury in the U-tube. Then, the pressure difference between the two points in the tube (at the wide and thin parts) is ΔP = ρgh, where ρ is the density of the mercury and g is the acceleration due to gravity.

From the principle of continuity, we have A1v1 = A2v2. Since the tube is horizontal, the potential energy of the fluid is the same at both points. Thus, Bernoulli's equation reduces to:

1/2 ρv1^2 + P1 = 1/2 ρv2^2 + P2,

where P is the pressure of the fluid at two different points in the tube. Since the air is the same at both points, P1 = P2. The air density is also given, ρair = 1.3 kg/m^3, and the air velocity is given, v1 = 15 m/s. We can find v2 by rearranging the equation A1v1 = A2v2 to v2 = (A1/A2)v1, where A1 = πr1^2 and A2 = πr2^2 are the cross-sectional areas of the wide and thin parts of the tube, respectively. Substituting the given values, we get v2 = 60 m/s.

Thus, Bernoulli's equation becomes:

1/2 ρairv1^2 = 1/2 ρairv2^2 + ρgh + P,

where P is the pressure of the air at the wide part of the tube. Since P1 = P2, we can cancel the pressure terms, and solve for h:

h = (v1^2 - v2^2)/(2g) * (ρair/ρmercury)

= (15^2 - 60^2)/(2*9.81) * (1.3/13600) ≈ 0.142 m

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Warm, moist air rises because of the difference in densities between warm, moist air and cold air, which is essential for the formation of clouds.

The moisture in the air condenses into minute water droplets or ice crystals when warm, wet air rises and cools. Clouds are made up of these suspended ice crystals and water droplets.

By reflecting sunlight back into space and storing heat, clouds play a significant part in the Earth's climate system, influencing temperature and weather patterns.

Although lightning is frequently connected to clouds, moist air does not directly cause lightning to occur. Electric charge builds up in the atmosphere, typically during thunderstorms, which leads to lightning.

Snow is created by the freezing of water vapor in the atmosphere, just as stars are created by the gravitational collapse of gas and dust clouds in space.

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Given :

Speed of bus for first 16 hours is , u = 15 km/h .

Distance he walked for next 0.4 hour is , v = 4.5 km/h .

To Find :

The average speed for the whole  journey.

Solution :

Average speed is given by :

\(v_{avg}=\dfrac{u_1t_1+u_2t_2}{t_1+t_2}\\\\v_{avg}=\dfrac{15\times 16 + 4.5\times 0.4}{16+0.4}\\\\v_{avg}=14.74\ km/h\)

Therefore , the average speed of the journey is 14.74 km/h .

Hence , this is the required solution .

If the universe were to suddenly begin shrinking rather than continuing to expand, it would have a significant effect on the cosmic microwave background radiation (CMB).

The CMB is the afterglow of the Big Bang and is observed as a nearly uniform background radiation in all directions. It is thought to have been emitted when the universe was about 380,000 years old and had cooled enough for neutral atoms to form.

If the universe were to suddenly begin shrinking, the photons in the CMB would lose energy as they travel through the contracting space. This would cause the CMB radiation to shift to shorter wavelengths, which is known as blue-shifting.

Therefore, the correct answer is B. It would blue-shift.

The two kinds of data that can be collected during an experiment are qualitative and quantitative data.

Numbers are used to convey quantitative data, which are measurements of values or counts. Numerical variables are the subject of quantitative data.

Qualitative data are represented by a name, symbol, or number code and are measurements of "types." Data concerning categorical variables make up qualitative data.

To provide a complete picture of a population, quantitative and qualitative data are frequently combined since they produce distinct results. For instance, if yearly income statistics are acquired (quantitative), occupation data might also be gathered (qualitative) to learn additional specifics about the average annual income for each type of profession.

Depending on whether the variable of interest is numerical or categorical, it is possible to acquire both quantitative and qualitative data from the same data unit.

Therefore, the two kinds of data that can be collected during an experiment are qualitative and quantitative data.

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The vector characteristics of the electric field allow to find the result for the electric field at the point of interest is;

Given parameters.

    1) Electric charges:

    2)Charge positions

   3) Points of interest r = (0,0,1) = 1 \(\hat k\)  

To find.

the electric field at point r.

The intensity of the electric field is given by the ratio of the electric force to the positive test charge at the point of interest.

          \(E= k \frac{q}{r^2 }\)  

where E is the electric field, k the constant of Coulomb, q the charge and r the distance.

In the attached we see a diagram of the test charges and the distance to the point of interest on the z axis.

The total field is the vector addition of the fields created by each charge

          \(E_{total} = E_1 +E_2\)

Let's look for the components of each electric field.

Field created by charge q₁

          tan θ = \(\frac{z}{x}\)  

          tan θ = 1/1 = 1

          tea = 45º

x-axis

          cos 45 = \(\frac{E_{1x}}{E_1}\)

z axis

          sin 45=  \(\frac{E_{1z}}{E_1}\)  

          E₁ₓ = E₁ cos 45

          \(E_{1z}\)  = E₁ sin 45

Field created by load 2

y-axis

        cos 45 = \(\frac{E_{2y}}{E_2}\)  

z- axis

        sin 45 = \(\frac{E_{2z}}{E_2}\)  

        \(E_{2y}\) = E2 cos 45

        \(E_{2z}\) = E2 sin 45

We look for the components of the total electric field, where the signs are taken from the direction of the vectors in the attached.

    \(E_{total} = - E_{1x} \hat i + E_{2y} \hat j + ( E_{1z} - E_{2z} ) \hat k\)

Let's substitute.

         \(E_{total } = - E_1 cos 45 \hat i + E_2 cos 45 \hat j + (E_1 sin 45 - E_2 sin 45) \hat k\)

Let's find the distance for each charge to the test point using the Pythagorean Theorem.

         r₁₃² = x² + z²

         r₁₃² = 1 + 1

         r₁₃² = 2

         r₂₃² = y² + z²

         r₂₃² = 1² + 1²

         r₂₃² = 2

Let's look for the magnitud of the electric fields.

Charge q₁

        \(E_1 = k \frac{q_1}{r_{13}^2}\)  

        E₁ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₁ = 20 N / m

Charge q₂

        \(E_2 = k \frac{q_2}{r_{23}^2}\)  

        E₂ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₂ = 20 C / N

Let's substitute in the expression of the total eletric field.

         \(E_{total} = -20 \ cos45 \ \hat i + 20 \ cos 45\ \hat j + ( 20 -20) sin 45 \ \hat k\)

         \(E_{total} = 14.1 ( - \hat i + \hat j) \ \frac{N}{C}\)  

In conclusion using the vector characteristics of the electric field we can find the result for the electric field at the point of interest is;

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Answer:

the average acceleration due to gravity on earth is 9.8m/s2 and on moon it is 1/6 of the earths acceleration due to gravity

Answer:

earth attracts moon by means of acceleration due to gravity

Explanation:

Answer:

B........................

Option A) 3.9 km is the correct answer. the magnitude of Rhea's displacement vector is approximately 3.92 km.

In order to find out the magnitude of Rhea's displacement vector, we have to add up all of the displacement vectors.

Then we can use the Pythagorean theorem to calculate the magnitude of the resultant vector.

Since Rhea is first driving north for 2.4 km and then west for 3.1 km, we can represent her displacement vectors as follows: Δx = 0 km and Δy = 2.4 km for the first vector, and Δx = -3.1 km and Δy = 0 km for the second vector.

We can then add these vectors together by adding their components: Δx = 0 km + (-3.1 km) = -3.1 km and Δy = 2.4 km + 0 km = 2.4 km.

This gives us a resultant vector of -3.1 km east and 2.4 km north.

Using the Pythagorean theorem, we can find the magnitude of this vector: \(\sqrt{(\(-3.1 km)^{2} + (2.4 km)^{2} ) } = \sqrt{(9.61 + 5.76) km^{2} } = \sqrt{15.37 km^{2} } \approx 3.92 km.\)

Therefore, the magnitude of Rhea's displacement vector is approximately 3.92 km.

Therefore, option A) 3.9 km is the correct answer.

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Answer:

Potential energy

Explanation:

Potential energy is stored energy

The correct measuring tool is a Graduated cylinder. The correct option is B

Tangential speed refers to the linear speed or velocity of an object along its circular path, specifically in the direction tangent to the circle. It represents how fast an object is moving along the circumference of the circle at a given point.

The other options are not suitable for measuring the time it takes for the toy to complete one revolution around the circle for the following reasons:

A) Force probe: A force probe is used to measure forces, not time. It would not provide accurate timing information for the toy's revolution.

C) Meterstick: A meterstick is used to measure lengths and distances. It cannot directly measure time, which is required to determine the time for one revolution.

D) Spring scale: A spring scale is used to measure forces. It would not provide accurate timing information for the toy's revolution.

On the other hand, a graduated cylinder is a cylindrical container with markings indicating volume. While it is primarily used for measuring the volume of liquids, it can also be used as a timing tool in this scenario. By filling the graduated cylinder with a known volume of liquid and placing it under the toy's path, the time it takes for the toy to complete one revolution can be measured by observing the displacement of the liquid level in the graduated cylinder over time.

Therefore, the correct answer is option B.

The question is incomplete , I think the question is,

One end of a string is attached to the ceiling - with the other end attached to toy. The toy can be set into motion such that travels in horizontal circular path , constant tangential speed as shown above: Which of the following measuring tools could be used to determine the time it takes for the toy to complete one revolution around the circle? String

A) Force probe

B) Graduated cylinder

C)Meterstick

D) Spring scale Toy

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Our muscles need more oxygen to make energy (in the form of ATP) while we workout.

When the respiratory rate picks up to fulfill this need, more oxygen can enter the body and more carbon dioxide can be exhaled.

Student 3 is breathing more forcefully than usual in this situation because of the high temperature and physical activity.

The respiratory system is the organ system engaged in this process.

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# complete question:

A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:

Student 1: Wow! I am so hot and sweaty! I need some water to cool down.

Student 2: My cheeks are really red.

Student 3: I am breathing so hard, I can barely catch my breath!

Explain what is happening to the students and how their bodies are trying to maintain homeostasis. Be sure to include any of the organ systems involved with each student.

Answer:

i think it's either force or time

Explanation:

just a random guess, but i think one of those are right

By separating actions that are motivated by obligation from those that are not, the first premise aids in the distinction between those actions that have moral value.

The first involves a salesman who, even though he is aware of the customer's inexperience, does not overcharge them because he does not want to risk damaging his reputation by being found out.

Because the salesman was not driven by a sense of obligation to treat the consumer fairly, Kant claims that this is not a moral issue.

The second claim is that "an action performed out of obligation has its moral significance not in the goal that it is intended to achieve.

Therefore, By separating actions that are motivated by obligation from those that are not, the first premise aids in the distinction between those actions that have moral value.

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The charge on the segment ds is  \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

As Q is uniformly distributed over semicircel so,charge density

\(\lambda=\frac{Q}{s}=\frac{Q}{\pi r}\)

so in ds region charge: \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

In physics, a uniformly distributed charge refers to a charge distribution where the charge density is constant throughout the given volume or surface. In other words, the amount of charge per unit volume or unit area is the same everywhere within the region.

Uniformly distributed charge is an important concept in electrostatics, which is the study of the behavior of electric charges at rest. The electric field produced by a uniformly charged object has a particularly simple form, and this makes it easier to calculate the electric field at any point outside the charged object using Gauss's Law.

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the complete question is:

What is the charge on a segment ds?

Express your answer in terms of some, all, or none of the variables Q, a, θ, dθ, and the constant π.

The equivalent resistance of the circuit shown  is 23 ohms.

Option A is correct.

Resistance is  described as the opposition that a substance offers to the flow of electric current.

In a series circuit, all components are connected end-to-end to form a single path for current flow.

In a parallel circuit, all components are connected across each other with exactly two electrically common nodes with the same volt.

We then 1/R = 1/100 + 1/100 + 1 /(50+ 50) +  1 /(50+ 50)

I/R = 0.04

R = 25 ohms.

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As the free magnet is brought slowly approaching the magnet that is fixed, a pull toward the fixed magnet will eventually become apparent.

The region surrounding a magnet that experiences the effects of magnetism is known as the magnetic field. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.

Compass, motor, refrigerator magnets, railroad tracks, and modern roller coasters are all examples of objects that use magnetic force. Charges that travel across its areas feel a force. All moving charges produce a magnetic field.

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60 kg m/s is the answer because you gave it and I thought you are telling ruth also you are a big questioner and also you should check with your doctor and go out and go touch the grass.

Answer:

In series: 3A

Parallel: 7,5 A

Explanation:

I added a photo of my solution

The current through the resistor when the two cells are arranged in series is 1.5A. The current through the resistor when the two cells are arranged in parallel is 1.2A.

To calculate the current through the 2-ohm resistor when the two cells are arranged in series, we first need to calculate the equivalent EMF and internal resistance of the combination.

When two cells are connected in series, their EMFs add up while their internal resistances also add up. Therefore, the equivalent EMF and internal resistance of the two cells connected in series can be calculated as follows:

Equivalent EMF = EMF of each cell x number of cells = 3 V x 2 = 6 V

Equivalent internal resistance = Internal resistance of each cell x number of cells = 1 ohm x 2 = 2 ohms

Now we can calculate the current through the 2-ohm resistor using Ohm's law:

I = V / R

where I is the current, V is the voltage across the resistor, and R is the resistance of the resistor.

Using the equivalent EMF and internal resistance values, the total resistance of the circuit can be calculated as:

Rtotal = Rresistor + Requivalent_internal_resistance = 2 ohms + 2 ohms = 4 ohms

Now we can calculate the current through the resistor:

I = V / R = 6 V / 4 ohms = 1.5 A

To calculate the current through the 2-ohm resistor when the two cells are arranged in parallel, we can first calculate the equivalent EMF and internal resistance of the combination.

When two cells are connected in parallel, their EMFs remain the same while their internal resistances decrease. Therefore, the equivalent EMF and internal resistance of the two cells connected in parallel can be calculated as follows:

Equivalent EMF = EMF of each cell = 3 V

Equivalent internal resistance = Internal resistance of each cell / number of cells = 1 ohm / 2 = 0.5 ohm

Now we can calculate the current through the 2-ohm resistor using Ohm's law and the total resistance of the circuit:

Rtotal = Rresistor + Requivalent_internal_resistance = 2 ohms + 0.5 ohm = 2.5 ohms

I = V / R = 3 V / 2.5 ohms = 1.2 A

Therefore, the current through the resistor when the two cells are arranged in series is 1.5 A. and in parallel 1.2A.

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The acceleration of a motorcycle that accelerates from rest (0m/s) to 80km/h in 4s is 5.56m/s².

Acceleration is the amount by which a speed or velocity increases (and so a scalar quantity or a vector quantity).

The acceleration of a body can be calculated using the following formula;

a = (v - u)/t

Where;

According to this question, a motorcycle accelerates from rest (0m/s) to 80km/h in 4s. The acceleration can be calculated as follows:

a = (22.2222 - 0)/4

a = 5.56m/s²

Therefore, 5.56m/s² is the acceleration of the motorcycle.

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Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\\)

From the question

mass = 2.34 kg

density = 6.45 kg/m³

We have

\(volume = \frac{2.34}{6.45} \\ = 0.36279...\)

We have the final answer as

Hope this helps you

Answer:

24.69 meters

Explanation:

sorry if it's not right.

answer:

\(h=24.69m\)

step-by-step explanation:

\(eg=mgh \\ek=\frac{1}{2} mv^2\)

eg= gravitational energy

ek= kinetic energy

now, since no mass is given of the ball, both equations on their own do nothing for us, except leave us scratching our heads wondering how to figure out the problem. but, since the question states, “and no air resistance,” we now know, according to the law of conservation of energy, that the energy of the two equations will equal each other because none of the energy has dissipated or left the system.

the amount of energy present during the initial phase of the woman about to throw the ball will be present in the final phase, which will be at its highest point (according to this problem).

so now \(eg=ek\)

knowing this, we can now set the equations equal

\(eg=ek\\mgh=\frac{1}{2} mv^2\)

the two m’s cancel out, making the mass of the ball insignificant and not influential; next, substitute the values we are given in the problem

\((22m/s),(9.8m/s^2)\\m(9.8m/s^2)h=\frac{1}{2} m(22m/s)^2\\(9.8 m/s^2)h=\frac{1}{2} (22m/s)^2\\(9.8m/s^2)h=1/2 (484m^2/s^2)\\(9.8m/s^2)h=1/2 (242m^2/s^2)\\\\h= (242m^2/s^2)/(9.8m/s^2)\)

as you can see, all units that need to be canceled out are indeed canceled, leaving us with just m, meters, which is what height is measured in

therefore, \(h=24.69m\)

Answer:

841  J/kg.K

Explanation:

The computation of the specific hear of the glass is shown below:

As we know that

E= cmΔt

where

c denotes specific heat

m denotes 0.38 kg

Δt = temperature = 22k

E denotes energy = 7032 J

Now

7032 J = (0.38) (22) (c)

7032 J = 8.36 (c)

So C = 7032 J ÷ 8.36

= 841  J/kg.K

Beth’s hygrometer is reading a temperature of 30°C and a relative humidity of 65%. The humidity in the air is 19.5 grams/cubic meter.

The actual vapor density or humidity can be determined from the relative humidity value and the saturation vapor density.

The formula that relates the actual vapor density or humidity, the relative humidity, and the saturation vapor density is given below:

Hence, the actual vapor density can be calculated as follows:

Actual vapor density or humidity = relative density * saturation vapor density / 100

From the graph;

saturation vapor density at 30°C = 30 g/cm³

relative humidity = 65%

Humidity = 65 * 30 / 100

Humidity = 19.5 g/cm³

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Answer:

When a passenger is sitting in a stationary bus it is under the law of inertia of rest that is the body resists any change in its state of rest.

Explanation:

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