Of the charge Q initially on a tiny sphere, a portion q is to be transferred to a second, nearby sphere. Both spheres can be treated as particles. For what value of q/Q>0.5 will the electrostatic force between the two parts have 1/3 of the maximum possible value?

C) a bicyclist riding up a steep hill

The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:

A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.

     Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.

A metal has a work function of 3.68 eV. then the maximum kinetic energy of the ejected electrons is 3.57 × 10⁻¹⁹ J, when electromagnetic waves with a wavelength of 209 nm.

Maximum kinetic energy of the ejected electrons is given by,

Kinetic energy (K.E.) = Energy of incident photons - Work function

Given,

Workfuction = 6.68 eV

wavelength = 209 nm = 209 × 10⁻⁹ m

energy of the incident photons is given by

Energy = Planck's constant × (speed of light / wavelength)

E = (6.626 × 10^-34 J·s) × (3 × 10^8 m/s) / (2.09 × 10^-7 m)

E ≈ 9.46 × 10⁻¹⁹ J

the maximum kinetic energy of the ejected electrons is

K.E. = 9.46 × 10^-19 J - 3.68 eV

So, the work function is 3.68 eV × (1.602 × 10^-19 J/eV) ≈ 5.89 × 10^-19 J.

Substituting this value into the equation:

K.E. = 9.46 × 10^-19 J - 5.89 × 10^-19 J ≈ 3.57 × 10^-19 J

Therefore, the maximum kinetic energy of the ejected electrons

3.57 × 10⁻¹⁹ J.

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A 20.0 N force is exerted on the small piston of a hydraulic system. The cross-sectional area of the small piston is 0.0500 m2.

What is meant by Hydraulic ?

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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The upward acceleration of the acrobat is 1.833 m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Mass of the acrobat; M = 588 N.

Weight of the acrobat acting downwards; W = 588 N.

Upward force provided by each of the two ropes; f = 349 N.

Hence, net force acting on the acrobat in upward direction = 2f -w

= (2×349 - 588 ) N.

= 110 N.

Hence, the upward acceleration of the acrobat is = net force/ mass

= 110/60 m/s².

=1.833 m/s².

So, the upward acceleration of the acrobat is 1.833 m/s².

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The correct answer is D. An average city

Explanation:

A neutron star differs from others due to its massive density, this means a lot of matter is compressed in a small area. Indeed, neutron stars have a mass of around 1.4 to 2.8 times the mass of the sun. But these are considerably small as they only measure around 20 kilometers, which is the size of an average city. Additionally, neutron stars are this dense because they are the result of a regular star exploding, which leads to a super-dense core, or neutron star. In this context, the mass of a neutron star is compressed to the size of an average city.

The purpose of the chiller is to remove heat from the air and is therefore denoted as option A.

This is a type of device which is referred to as type of a cooling system that removes heat by circulating heat-absorbing a refrigerant through a series of mechanisms through which the heat is released.

The result of this process is that the heat in the air is removed as a result of the refrigerant being adequately circulated and then the environment becomes cooler and is therefore the reason why it was chosen as the correct choice.

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Answer:

18.89cm

Explanation:

As we know that the person is standing 5m in front of the camera

\(d_0=5m=500cm\)

The focal length of the lens =50cm

f=50 cm

By Lens formula we have:

\(\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}\\\dfrac{1}{50} = \dfrac{1}{d_i} + \dfrac{1}{500}\\\dfrac{1}{d_i} =\dfrac{1}{50}-\dfrac{1}{500}\\\dfrac{1}{d_i}=0.018\\d_i=55.56cm\)

By the formula of magnification

\(\dfrac{h_i}{h_o} = \dfrac{55.56}{500}\\\\h_i = \dfrac{55.56}{500} \times h_o\\\\ h_o=1.70m=170cm\\\\Therefore: h_i=\dfrac{55.56}{500} \times$ 170 cm\\\\h_i =18.89 cm\)

The height of the image formed is 18.89cm.

Answer:

1.) 7.3 m/s 2.) 6.1 m/s

Explanation:

To calculate the initial horizontal velocity with just degrees and velocity alone is pretty simple. The formula is     Velocity*cos(degrees)

eg 9.5*cos(40)

2.  To calculate the initial vertical velocity with just degrees and velocity alone is pretty simple. The formula Velocity*sin(degrees)

eg 9.5*sin(40)

If only balanced forces act on an object it will keep moving in the same speed and direction.

This is defined as the type of quantity which has both magnitude and direction.

\Having balanced forces will bring about equilibrium which is  why the obect will move in the same speed and direction.

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Answer:

A.Radio waves

Explanation:

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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Answer:

blue

Explanation:

nswer the following about two objects, A and B, whose motion produced ihe following ... "A" starts with a greater (t) position. Since they ... since you are moving away from the origin

Answer:

opaque = 4

malleable = 3

ductile = 2

lustrous (or whatever the bottom word is) = 1

Explanation:

Answer:

Atmosphere

Explanation:

Hydrogen,

H

2

, is one of the lightest gases that can be found on Earth. The other gas is helium, and these two gases are both lighter than air, because they have a high degree of buoyancy.

This means that the air below it is pushing up with a greater force than the air above it is forcing it down.

Explanation:

RAM(RANDOM ACCESS MEMORY)

Answer:

reduces the amount of force necessary for lifting heavy items and it redistributes the direction of the force that's necessary to lift the heavy items

Answer:

ΔU = - 310.6 J (negative sign indicates decrease in internal energy)

W = 810.6 J

Explanation:

a.

Using first law of thermodynamics:

Q = ΔU + W

where,

Q = Heat Absorbed = 500 J

ΔU = Change in Internal Energy of Gas = ?

W = Work Done = PΔV =

P = Pressure = 2 atm = 202650 Pa

ΔV = Change in Volume = 10 L - 6 L = 4 L = 0.004 m³

Therefore,

Q = ΔU + PΔV

500 J = ΔU + (202650 Pa)(0.004 m³)

ΔU = 500 J - 810.6 J

ΔU = - 310.6 J (negative sign indicates decrease in internal energy)

b.

The work done can be simply calculated as:

W = PΔV

W = (202650 Pa)(0.004 m³)

W = 810.6 J

Answer:

Explanation:

The three physical characteristics of a sound stimulus and their corresponding perceptual characteristics are as follows:

1. Frequency: Frequency refers to the number of vibrations or cycles per second that occur in a sound wave. It is measured in hertz (Hz). Frequency gives rise to the perception of pitch. Pitch is the subjective perception of how high or low a sound is. Higher frequencies are perceived as higher pitches, while lower frequencies are perceived as lower pitches. For example, a sound wave with a higher frequency would be perceived as a higher-pitched sound, like a whistle, whereas a sound wave with a lower frequency would be perceived as a lower-pitched sound, like a deep bass note.

2. Amplitude: Amplitude is the magnitude or intensity of a sound wave and is usually measured in decibels (dB). It represents the amount of energy carried by the sound wave. Amplitude gives rise to the perception of loudness. Loudness is the subjective perception of the strength or intensity of a sound. Greater amplitudes are perceived as louder sounds, while smaller amplitudes are perceived as quieter sounds. For instance, a sound wave with a higher amplitude would be perceived as a louder sound, like a thunderclap, whereas a sound wave with a lower amplitude would be perceived as a softer sound, like a whisper.

3. Timbre: Timbre refers to the quality or tone color of a sound. It is the characteristic that allows us to distinguish between sounds with the same pitch and loudness. Timbre is influenced by the complex combination of different frequencies, amplitudes, and waveforms present in a sound wave. It gives rise to the perception of the unique "sound signature" of an instrument or voice. For example, a guitar and a piano playing the same note at the same loudness would still sound different due to their distinct timbres. Timbre enables us to identify and differentiate between various musical instruments and voices.

In summary, frequency determines the pitch perception of a sound, amplitude influences the perception of loudness, and timbre defines the unique quality or tone color of a sound. These physical characteristics directly relate to the corresponding perceptual characteristics, providing us with a rich and diverse soundscape in our auditory experience.

Answer:

3980.89 ohms

Explanation:

The capacitive reactance is expressed as;

\(X_c = \frac{1}{2 \pi fC}\)

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = \(40 * 10^{-6}F\)

Substitute into the formula:

\(X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c = \frac{1}{0.0002512}\\X_c = 3,980.89\)

Hence the  total capacitive reactance is 3980.89 ohms

The magnitude of the force acting at point O is determined as 240 N.

The magnitude of the force at point O is calculated by applying the principles of moment as shown below.

sum of the clockwise moment = sum of the anticlockwise moment

F₀(2 m + 2m + 2m) = 260 N (2m + 2 m ) +  200 N ( 2 m )

where;

6F₀ = 260 (4) + 200(2)

6F₀ = 1,440

F₀ = 1440 / 6

F₀ = 240 N

Thus, the magnitude of the force acting at point O is determined as 240 N.

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Answer:

B. 2 Hz

Explanation:

Given parameters:

Period of the wave  = 0.5Hz

Unknown:

Frequency of the wave  = ?

Solution:

Frequency is the number of waves that passes through a point.

Period is the time taken for a number of waves to pass through a point.

  Period is the inverse of frequency

  Frequency  = \(\frac{1}{t}\)  

 t is the period

  Frequency  = \(\frac{1}{0.5}\)  = 2Hz

Answer:2

Explanation:

Answer:

B. Directly above the center of the magnet.

Explanation:

The magnetic field lines of a bar magnet emerge from the magnet's north pole and re-enter the magnet at the south pole. Therefore, the magnetic field lines point from north to south within the magnet. Based on this, we can determine that:

A. In the center of the magnet between the two poles, the magnetic field lines point from north to south and are therefore not pointing to the right.

B. Directly above the center of the magnet, the magnetic field lines point downward and to the south, so they are not pointing to the right.

C. To the right of the north pole, the magnetic field lines point to the right.

D. To the left of the south pole, the magnetic field lines also point to the right.

Therefore, the location where the magnetic field does NOT point to the right is B, directly above the center of the magnet.

Answer:

Heat stroke

Explanation:

Heat Stroke is the most serious heat-related illness and requires immediate medical attention.

Answer:

Heat Stroke is the most serious heat-related illness and requires immediate medical attention. Symptoms include: confusion, fainting, seizures, very high body temperature and hot, dry skin or profuse sweating. CALL 911 if a coworker shows signs of heat stroke.

Explanation:

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The power being dissipated by the appliance is approximately 0.182 W.

To determine the power being dissipated by the appliance, we need to use Ohm's Law and the formula for power:

Ohm's Law: V = IR

where V is the voltage, I is the current, and R is the resistance.

Power formula: P = IV

where P is the power, I is the current, and V is the voltage.

First, let's find the current through the circuit:

V_battery = V_appliance + V_voltmeter

where V_battery is the voltage of the battery, V_appliance is the voltage across the appliance, and V_voltmeter is the voltage across the voltmeter.

Rearranging this equation to solve for V_appliance:

V_appliance = V_battery - V_voltmeter

V_appliance = 15.0 V - 11.3 V

V_appliance = 3.7 V

Now we can use Ohm's Law to find the current:

I = V_appliance / R

I = 3.7 V / 75.0 Ω

I = 0.0493 A

Finally, we can use the power formula to find the power:

P = IV

P = 0.0493 A x 3.7 V

P = 0.182 W

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--The complete question is, An idealized voltmeter is connected across the terminals of a 15.0 V battery. A 75.0 Ω appliance is also connected across the battery terminals. When the voltmeter measures 11.3 V, how much power is being dissipated by the appliance?--

Answer:

A.

Explanation:

Im just guessing because it sounds like it describes a hypothesis the most and you said its urgent

Answer:

d. down welling, mixing

Explanation:

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