On a roller coaster when does the car have potential kinetic energy and when is energy transferred?

Answers

Answer 1
Energy occurs when it is going upward. Yet when it is going downward, no energy is need because the force is pushing the cart down.
Answer 2

Answer: When the roller coaster goes to the top of the tracks there is energy

Explanation: When going up you need energy but going down the energy is being transferred downwards.


Related Questions

beam of electrons enters normally in a region of magnetic field of 0.01 t with a velocity of 106 m/s. what is the radius of the curved path traced by the beam of electrons?

Answers

The radius of the curved path traced by the beam of electrons can be calculated using the formula r = (mv)/(qB), where m is the mass of the electron, v is its velocity, q is the charge of the electron, and B is the magnetic field strength. By substituting the given values into the formula, we can determine the radius of the curved path.

When a beam of electrons enters a region of magnetic field perpendicularly, it experiences a force that causes it to move in a circular path. The radius of this curved path can be determined using the formula for the magnetic force on a moving charged particle.

The magnetic force on the electron is given by the equation F = qvB, where q is the charge of the electron, v is its velocity, and B is the magnetic field strength. Since the electron has a negative charge, it experiences a force in the opposite direction as the velocity vector. This force acts as the centripetal force that keeps the electron in a circular path.

The centripetal force is given by F = (mv*v)/r, where m is the mass of the electron and r is the radius of the curved path. Equating the magnetic force to the centripetal force, we get qvB = (mv*v)/r. Solving for r, we find that the radius of the curved path traced by the beam of electrons is r = (mv)/(qB).

Using the given values, where m = mass of electron, v = velocity of electron, and B = magnetic field strength, we can substitute them into the formula to calculate the radius of the curved path.

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What object appears in these sketches — drawn as seen through one of the first telescopes, in the early 17th century — and who drew them?
a. Earth's Moon, by Galileo Galilei
b. Mercury, by Tycho Brahe
c. Venus, by Nicholaus Copernicus
d. Earth's Moon, by Sir Isaac Newton
e. Mars, by Johannes Kepler

Answers

The Correct option is D. Earth's Moon, by Sir Isaac Newton object appears in these sketches — drawn as seen through one of the first telescopes, in the early 17th century.

Isaac Newton is widely regarded as one of the most influential physicists in history. He made groundbreaking contributions to our understanding of the laws of motion, gravity, and optics, which laid the foundation for modern physics.

Newton's three laws of motion describe how objects move in response to forces, while his law of universal gravitation explains how all objects in the universe are attracted to each other. His work on optics included the development of the reflecting telescope and the discovery of the composition of white light through the use of prisms.

Newton's contributions to physics were based on his careful observations and mathematical analysis, which allowed him to formulate precise laws that could be used to make predictions about the behavior of physical systems.

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What will the kinetic energy of a pile driver ram be if it starts from rest and undergoes a 10 kJ decrease in potential energy?a) -10 kJb) 10 kJc) 0 kJd) 5 kJ

Answers

According to the law of conservation of energy, the total energy of a system remains constant, and energy can neither be created nor destroyed, but only transferred from one form to another.

Energy is a scalar physical quantity that is associated with the ability of an object or a system to do work. It can be defined as the capacity of a system to perform work or to transfer heat.

There are various forms of energy, including:

Kinetic energy: energy possessed by an object due to its motion. It can be calculated using the formula KE = 1/2mv^2, where m is the mass of the object and v is its velocity.

Potential energy: energy possessed by an object due to its position or configuration in a system. It can be calculated using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height or distance from a reference point.

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what is the frequency, in megahertz to 1d.p, for a 1 metre wavelength?

Answers

The frequency for a 1-meter wavelength is approximately 300.0 MHz to 1 decimal place.

To find the frequency in megahertz for a 1-meter wavelength, you can use the following formula:

Frequency (in Hz) = Speed of light (m/s) / Wavelength (m)

The speed of light is approximately 300,000,000 meters per second (m/s).

For a 1-meter wavelength:

Frequency (in Hz) = 300,000,000 m/s / 1 m
Frequency (in Hz) = 300,000,000 Hz

Now, to convert the frequency from hertz (Hz) to megahertz (MHz), divide by 1,000,000:

Frequency (in MHz) = 300,000,000 Hz / 1,000,000
Frequency (in MHz) = 300 MHz

So, the frequency for a 1-meter wavelength is approximately 300.0 MHz to 1 decimal place.

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What is the initial velocity of a ball that is thrown downward at the rooftop of a 35 m building and falls to the ground after 2.25 s?

Answers

The initial velocity of the ball that was thrown downward from a height of  35 m is 4.53 m/s².

What is velocity?

Velocity is the rate of change of displacement.

To calculate the initial velocity of the ball, we use the formula below,

Formula:

s = ut+gt²/2.................... Equation 1

Where:

s = Distancet = Timeu = Initial velocityg = Acceleration due to gravity

From the question,

Given:

t = 2.25 sg = 9.8 m/s² (Thrown upward)s = 35 m

Substitute these values into equation 1 and solve for u

35 = (2.25×u)+(9.8×2.25²)/235 = 2.25u+24.812.25u = 35-24.812.25u = 10.19u = 10.19/2.25u =  4.53 m/s

Hence, the initial velocity is 4.53 m/s².

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how much voltagr is required to make 4 amperes flow throgh a resistance of 20 ohms?

Answers

To make 4 amperes flow through a resistance of 20 ohms, 80 volts of voltage are required.

Ohm's law states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. In other words, the greater the voltage, the greater the current that flows through a given resistance.


The voltage required to make 4 amperes flow through a resistance of 20 ohms can be calculated using Ohm's law:

Voltage (V) = Current (I) x Resistance (R)

Therefore, V = 4 A x 20 Ω = 80 V

So, to make 4 amps flow through a resistance of 20 ohms, 80 volts of electricity are required.

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Block B in rests on a surface for which the static and kinetic coefficients of friction are 0.59 and 0.40, respectively. The ropes are massless.What is the maximum mass of block A for which the system remains in static equilibrium?

Answers

The maximum mass of block A that can be supported by the tension in the rope is 0.59 times the mass of block B, based on the static coefficient of friction and weight of block B.

To find the maximum mass of block A that can be supported by the tension in the rope, we can use the static coefficient of friction and the weight of block B.

Here, T1 and T2 are the tensions in the ropes, and mB is the mass of block B.

Since the system is in static equilibrium, the net force on each block must be zero. Therefore, we can write the following equations:

T1 = mA_{Total} * g

where mA_{Total} is the total mass of block A and any additional mass that can be supported by the tension in the rope.

For block B:

T2 = mB * g

where g is the acceleration due to gravity.

The tension in the ropes can be expressed as:

T1 = T2 = friction

where friction is the force of friction between block B and the surface.

The tension in the ropes is equal to the force of friction between block B and the surface. Therefore, the maximum additional mass that can be supported by the tension in the rope is given by:

mA_{Max} = Ffriction / g * μs

where F is friction is the force of friction between block B and the surface,

g is the acceleration due to gravity, and

μs is the static coefficient of friction.

We can find the force of friction,

friction, using the weight of block B:

friction = μs * mB * g

Substituting this expression for friction in the equation for mA_{Max}, we get:

mA_{Max} = μs * mB

     = 0.59 * mB

Therefore, the maximum mass of block A that can be supported by the tension in the rope is 0.59 times the mass of block B.

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Please Help I will Mark Brainiest!!!
The isotope of an atom containing 40 protons and 51 neutrons suddenly has two neutrons added to it.

What isotope is created?


Zirconium-53


Zirconium-93


Antimony-93


Antimony-53

Answers

Answer:

Hey, the answer is Zirconium-93

Explanation:

Im very positive about this question, so i hope I helped you ;p

Answer:

Zirconium-93

Explanation:

when we add up the 40 protons and 53 neutrons it gives 93 and a protons and neutron 93 gives a Zirconium-93

Thanks theres your answer

Which statement about force is incorrect

A. Some forces cause objects around us to move.
B. Some forces keep objects around us from moving
C. Force is the ability to change motion and transfer matter.
D. Force causes changes in the motion and energy of matter.​

Answers

Answer:

I don't know sorry brother/sister

Explanation:

please mark as brilliant

An atom’s emission of light with a specific amount of energy confirms that

Answers

Answer: An atom's emission of light with a specific amount of energy confirms that atoms must have a dense central mass surrounded by electrons at a distance

plz mark brainliest

Answer:

It's B, electrons emit and absorb energy based on their position around the nucleus.

1.
A frictionless piston-cylinder device initially contains R-134a at 1000 kPa and 20 C. Heat is added to the system until it reaches a temperature of 100 C.
(a) Find the change in specific enthalpy h in kJ/kg and
(b) Draw the T-V diagram.

Answers

The change in specific enthalpy is, ∆h = h2 - h1 = 358.41 - 251.81 = 106.6 kJ/kg

Given:

Pressure, P1 = 1000 kPa

Temperature, T1 = 20 C = 20+273.15 = 293.15 K

Pressure, P2 = P1 = 1000 kPa

Temperature, T2 = 100 C = 100+273.15 = 373.15 K

The equation for specific enthalpy, h is:h = u + Pv

Here, u is the specific internal energy and Pv is the product of pressure and specific volume.

The given piston-cylinder device is frictionless.

Hence, the process is adiabatic and isentropic.

The change in specific enthalpy can be obtained by using the property relation between specific enthalpy, pressure and temperature.

Change in specific enthalpy is given by,

∆h = h2 - h1

where, h1 is the specific enthalpy at state 1 and h2 is the specific enthalpy at state

2. Using steam tables, we can find the specific enthalpy at the given states.

State 1:

Using steam table at 1000 kPa, we get the specific enthalpy as h1 = 251.81 kJ/kg.

State 2:Using steam table at 1000 kPa, we get the specific enthalpy as h2 = 358.41 kJ/kg.

The change in specific enthalpy is,

∆h = h2 - h1 = 358.41 - 251.81 = 106.6 kJ/kg

Part (a) is completed.

Now, let's move towards Part (b) which is to draw T-V diagram.

We know that,

v1 = v2 [As the process is isentropic]

At state 1:Using steam tables at 1000 kPa, we get v1 = 0.002997 m³/kg

.At state 2:Using steam tables at 1000 kPa, we get v2 = 0.01761 m³/kg.

Now, plotting these two states on T-v diagram,

We can draw a straight line passing through these two points as the process is isentropic

Here, AB represents the process as the process is isentropic. It is a straight line since the specific volume is constant at each state during this process

And, A represents the state 1 and B represents the state 2

Therefore, the T-V diagram is as shown in the below figure.

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describe the phases of the moon along with a picture.​

Answers

Answer:

The eight Moon phases:

Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.

The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.

The 8 phases (in order) are:New moon.Waxing Crescent.First Quarter.Waxing Gibbous.Full moon.Waning Gibbous.Third Quarter.Waning Crescent.

Explanation:

Hope it is helpful....

describe the phases of the moon along with a picture.

Answer: i think u can put this The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon

Don't forget to drop a heart have a happy friday

A basketball weighing 0.63 kg is dropped from a height of 6.0 meters onto a court. Use the conservation of energy equation to determine the velocity of the ball at a height of 2.0 meters above the court.

Answers

Answer:

The velocity of the ball at a height of 2.0 meters above the court is approximately 8.85 m/s

Explanation:

The given parameters of the ball are;

The mass of the ball, m = 0.63 kg

The height from which the ball is dropped, h₁ = 6.0 meters

The height at which the velocity of the ball is sought, h₂ = 2 meters

The initial potential energy of the ball, P.E. = m·g·h₁ = 0.63 × 9.8 × 6.0  = 37.044

The initial potential energy of the ball, P.E.₁ = 37.044 J

The potential energy of the ball, when the ball is at 2 meters above the court, P.E.₂ = m·g·h₂ = 0.63 × 9.8 × 2.0 = 12.348

The potential energy of the ball, when the ball is at 2 meters above the court, P.E.₂ = 12.348 J

From M.E> = P.E. + K.E.

Where;

M.E = The total mechanical energy of the ball = Constant

P.E. = The potential energy of the ball

K.E. = The kinetic energy of the ball

By the conservation of energy principle, we have;

The potential energy lost by the ball = The kinetic energy gained by the ball

The potential energy lost by the ball = P.E.₁ - P.E.₂ = 37.044 - 12.348 = 24.696

The potential energy lost by the ball = 24.696 J

The kinetic energy gained by the ball = 1/2·m·v² = 1/2×0.63×v²

Where;

v = The velocity of the ball

∴ The potential energy lost by the ball at 2.0 meters above the court = 24.696 J = The kinetic energy gained by the ball at 2.0 meters above the court = 1/2×0.63×v²

24.696 J = 1/2×0.63 kg ×v²

v² = 24.696 J / (1/2×0.63 kg) = 78.4 m²/s²

∴ v = √(78.4 m²/s²) = 8.85437744847 m/s

The velocity of the ball at a height of 2.0 meters above the court, v ≈ 8.85 m/s.

a rocket takes off from earth and reaches a speed of 100 m/s in 10.0 s. if the exhaust speed is 1500 m/s and the mass of fuel burned is 100 kg, what was the initial mass of the rocket?

Answers

1318.31 J is the work produced by the Carnot engine each cycle.

A Carnot Engine: What Is It?

Leonard Carnot devised the Carnot engine, a hypothetical thermodynamic cycle. It calculates the highest feasible efficiency that a heat engine can have while converting heat into work and when operating between two reservoirs.

Given;reservoir for

high temperatures,

Th = 435 kRiver

water temperature,

Tl = 280 every cycle,

absorbed heat energy,

Q = 3700 J

Calculate the amount of work completed every cycle as;

W=Q(T1/Tn)Where;

W is the completed work

.Q represents the total heat absorbed each cycle.

The cold liquid's temperature is Tl.

The hot reservoir's temperature is T.

w= Q( 1-T1/Th)

w= 3700 (1-280/435)

W= 3700(1-0.6437)

W =1318.31J

As a result, the carnot engine produces 1318.31 J of work each cycle which is the mass of the rocket

when functioning under the current circumstances

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An Object with a mass o 5.13kg placed on top of a spring compresses it by 0.25m (a) what is the force constant of the spring (b) How high will this object go when the spring releases its energy?

Answers

The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,

F = kx

Therefore,

k = F/x

We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,

K = 50.174/0.25 N/m

K = 200.696 N/m

Therefore, The Spring Constant is 200.696 N/m

On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:

h = \(1/2 kx^{2}\)

We know that k=200.696 N/m and x=0.25 m. Therefore the height is:

h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)

h = 2.5087 m

Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

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in the quantum mechanical view of the atom, electrons are confined to charge clouds called

Answers

Electrons are confined to charge clouds called orbitals.

What are the charge clouds called that electrons are confined to in the quantum mechanical view of the atom?

In the quantum mechanical view of the atom, electrons are described by wave functions, which give the probability of finding an electron at a particular location around the nucleus.

These wave functions are represented by charge clouds called orbitals. The shape and size of an orbital is determined by the principal quantum number, which relates to the energy level of the electron.

The concept of orbitals is important in understanding chemical bonding and reactivity, as the number and arrangement of electrons in an atom's orbitals determines its chemical properties. For example, the number of valence electrons in an atom's outermost orbital determines its ability to form chemical bonds with other atoms.

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Which is an example of a physical change?


cake baking

gasoline combusting

salt dissolving

iron rusting

Answers

Answer:

salt dissolving

Explanation:

hope it helps

Salt dissolving because if the water evaporates the salt will return to a solid state

How are measurements such as mass and volume different from measurements such as velocity and acceleration?

Answers

Measurements such as mass and volume are scalar quantities that only have magnitude, while measurements such as velocity and acceleration are vector quantities that have both magnitude and direction.

Scalar quantities, like mass and volume, describe physical properties of objects without considering their direction. For example, the mass of an object tells us how much matter it contains, and the volume tells us the amount of space it occupies. These measurements can be expressed using a single value and appropriate units.

On the other hand, vector quantities, like velocity and acceleration, involve both magnitude and direction. Velocity is the rate at which an object changes its position, and acceleration is the rate at which its velocity changes. These measurements require both numerical values and a specific direction to fully describe the motion of an object.

Understanding the distinction between scalar and vector quantities is crucial in accurately representing and analyzing various physical phenomena and their mathematical relationships.

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if it is known that the toggle clamp is a machine, what assumptions can be made about it? check all that apply. (you must provide an answer before moving to the next part.)

Answers

A toggle clamp is a tool that you use to firmly secure components or pieces in place, frequently but not always as part of a production process.

What is toggle clamp?

A toggle clamp is a device that you employ, often but not exclusively as part of a production process, to firmly place components or parts in place. A toggle clamp's main characteristics are its rapid action and ability to be easily turned on and off by an operator.

Toggle clamps also lock in place firmly. Because of this, toggle clamps are frequently employed in production lines where components need to be held firmly and quickly removed during routine manufacturing procedures.

Toggle clamps come in six primary categories: vertical toggle clamps, horizontal toggle clamps, plunger toggle clamps (also known as push action toggle clamps), hook action toggle clamps, plier action toggle clamps, and cam action toggle clamps.

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Two +1 C charges are separated by 3000 m. What is the magnitude of the electric force

Answers

¡Hello!

Topic: Electrostatic

For calculate electric force, we can apllicate formula:

                                                \(\boxed{\boxed{\bold{F = k * \frac{q*q'}{r^{2} } } } }\)

\(\sqrt{\) F = Electric Force

\(\sqrt{\) k = Coulomb Constant = 9x10^9

\(\sqrt{\) q = Charges = 1 C

\(\sqrt{\) r = Distance = 3000 m

Let's replace according the information, and let's resolve it:

F = 9x10^9 * (1 * 1) / 3000²

F = 9x10^9 * 1 / 9000000

F = 9x10^9 * 1.1111111e-7

F = 1000 N

Result:

The electric force is of 1000 N

Good luck

Rising and falling like a gentle waltz, the dandelion seeds _______.

Which phrase is most appropriate for the diction and style of the sentence?

A.
dropped heavily onto the wet ground
B.
fell and scattered across the lawn
C.
danced lightly on the cool breeze
D.
blew like a hurricane across the yard

Answers

B

Explanation:

yeah but I don't know what

An object is accelerating if there is a change in speed and which factor? A. direction B. displacement C. time D. position

Answers

Answer:

time bc speed uses time

Explanation:

hope it helps♡ ;)

An object is accelerating if there is a change in speed and there is a change in direction, therefore the correct answer is option A.

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

Even if the magnitude of the velocity not changing even the change in the direction would lead to acceleration,

uniform circular motion is one of the best examples where the speed is constant but the direction is changing continuously

Thus, An object is accelerating if there is a change in speed and there is a change in direction, therefore the correct answer is option A.

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The sputnik one satellite orbiting earth mass equals 5.98×10 to the 24th power kilograms in a circle of radius 6.96×10 to the six power meters what was its orbital velocity

Answers

Answer:

7572 m/s

Explanation:

The force between two masses separated by a distance r is given as:

\(F=G\frac{m_1m_2}{r^2}\)

Where F is the attractive force between 2 masses, m1 and m2, r is the distance between the centres of the masses and G is the universal gravitation constant, which is \(6.674*10^-11 Nm^2/kg^2\)

The mass of the earth (\(m_1\)) is far greater than the mass of the sputnik (\(m_2\)). Therefore \(m_1m_2=m_1\). The mass of the sputnik is neglected, therefore:

\(F=G\frac{m_1}{r^2}=\frac{(6.674*10^{-11})(5.98*10^{24})}{(6.96*10^6)^2} = 8.2389N\)

But F is actually centripetal acceleration, a = v²/r

\(8.2389 = v^2 / 6.96*10^6\\v=7572m/s\)

The motor turns the disk with an angular velocity of ω=(3t2 3t)rad/s, where t is in seconds. - Part ADetermine the magnitude of the velocity of the point A on the disk when t = 3 s. - Part BDetermine the magnitudes of the n and t components of acceleration of the point A on the disk when t = 3 s

Answers

The motor turns the disk with an angular velocity of ω = (3\(t^{2}\), 3t)rad/s, where t is in seconds.

Part A The magnitude of the velocity of point A at t = 3s is

|v| = r|ω| = r|(27, 9)| = r√(\(27^{2}\)+\(9^{2}\))

Part B At t = 3s, αn = 3 rad/\(s^{2}\), and the normal component of acceleration is

an = rαn = rαcos(90°) = -rα = -r(3) = -3r

Let's start with the given information

Angular velocity, ω = (3\(t^{2}\), 3t) rad/s

To solve the problem, we need to find the velocity and acceleration of point A on the disk. We can use the following equations

v = rω (for velocity)

a = rα (for acceleration)

Where r is the distance of point A from the center of the disk, and α is the angular acceleration.

Part A

To find the magnitude of the velocity of point A when t = 3s, we need to find the value of ω at t = 3s, and then calculate the velocity using the above equation.

Given ω =  (3\(t^{2}\), 3t) rad/s

At t = 3s, ω = (27, 9) rad/s

Let the radius of the disk be r. Then the velocity of point A is

v = rω

The magnitude of the velocity is

|v| = |rω| = r|ω|

We are given that the disk is rotating counterclockwise, so the velocity vector at point A is tangent to the circle, and has a direction perpendicular to the radius.

Therefore, the magnitude of the velocity of point A at t = 3s is

|v| = r|ω| = r|(27, 9)| = r√(\(27^{2}\)+\(9^{2}\))

Part B

To find the magnitudes of the n and t components of acceleration of point A when t = 3s, we need to find the value of α at t = 3s, and then calculate the acceleration using the above equation.

Since the angular velocity is changing with time, we need to find the angular acceleration using the derivative of the angular velocity

α = dω/dt

Given ω =  (3\(t^{2}\), 3t) rad/s

Differentiating with respect to t, we get

α = (6t, 3) rad/\(s^{2}\)

At t = 3s, α = (18, 3) rad/\(s^{2}\)

Let the tangential and normal components of acceleration be at and an respectively. Then, we have

a = rα = rat + ran

The tangential component of acceleration is given by

at = rαt

where αt is the tangential component of angular acceleration. Since the disk is rotating counterclockwise, the direction of αt is along the tangent to the circle at point A, and is perpendicular to the radius.

Therefore, at t = 3s, αt = 18rad/\(s^{2}\), and the tangential component of acceleration is:

at = rαt = rαsin(90°) = rα = r(18) = 18r

The normal component of acceleration is given by

an = rαn

Where αn is the normal component of angular acceleration. The direction of αn is perpendicular to the tangent and the radius, and points towards the center of the circle.

Therefore, at t = 3s, αn = 3 rad/\(s^{2}\), and the normal component of acceleration is

an = rαn = rαcos(90°) = -rα = -r(3) = -3r

Hence, the magnitudes of the tangential and normal components of acceleration of point A at t = 3s are

|at| = 18r

|an| = 3r

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a 2.0 kg ball is dropped from a height of 20 m onto a soft surface and rebounds to a height of 5.0 m . what is the magnitude of the impulse exerted on the ball by the floor?

Answers

Based on the data provided, the impulse of the floor on the ball is 59.4 Ns.

What is the impulse of the floor on the ball?

Using the equation of motion to determine the velocity at the end of the fall

v^2 = u^2 + 2gh

Where v is velocity at the end of fall

u is initial velocity = 0

g is acceleration due to gravity = 9.81 m/s^2

h is height = 20

Taking downward velocity as negative and up as positive

v^2 = 0 + 2 (9.81)(20)

v^2 = 392.4

v = - 19.8 m/s

The velocity, v after bouncing is calculated also:

u = 0

g = 9.81 m/s^2

h = 5.0 m

v^2 = 0 + 2(9.81)(5)

v^2 = 98.1

v = 9.904 m/s

Impulse = change in momentum Impulse = m(v- u)

Impulse = 2.0 × (9.9 -(-19.8)

Impulse = 59.4 Ns

Therefore, the impulse of the floor on the ball is 59.4 Ns.

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As a spaceship's velocity gets closer to the speed of light with respect to an external observer, what will the observer report regarding the length of the spaceship and the time kept by a clock on the spaceship?

A) the length will decrease and the clock will run more slowly.

B) the length will decrease and the clock will run faster.

C) the length will increase and the clock will run more slowly.

D) the length will increase and the clock will run faster.

Answers

A) the length will decrease and the clock will run more slowly. According to the theory of relativity, as an object approaches the speed of light, its length contracts in the direction of motion.

This phenomenon is known as length contraction. Therefore, from the perspective of an external observer, the length of the spaceship will appear to decrease as its velocity approaches the speed of light. Additionally, time dilation occurs, which means that the time experienced by a clock on the spaceship will slow down relative to the time experienced by the observer. As the velocity of the spaceship approaches the speed of light, the clock on the spaceship will appear to run more slowly compared to the observer's clock. Therefore, option A) correctly describes what the observer will report regarding the length of the spaceship and the time kept by a clock on the spaceship.

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power sources connected in parallel should have the same VOLTAGE OUT PUT:T/F

Answers

Power sources that are connected in parallel should have the same voltage output. This statement is true.

What does it mean when we say two power sources are connected in parallel?  Power sources are connected in parallel to increase the current output. This means that the positive terminals of the power sources are connected to the other positive terminals, and the negative terminals of the power sources are connected to the other negative terminals. This results in the voltage output remaining the same, but the current output increasing. This is useful when more current is required for a particular application. To summarize, when power sources are connected in parallel, the voltage output should remain the same, and the current output should increase.

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DESPERATE WILL GIVE BRAINLIST AND THANKS (PLZ HURRY)
Which statement is FALSE about Redi & Pasteur’s experiments?

Redi’s independent variable was jar coverings.


Pasteur’s independent variable was boiled broth.


Pasteur’s dependent variable was the growth of microbes (bacteria).


Both experiments were conducted gather evidence to disprove spontaneous generation.

Answers

Answer:

B

Explanation:

Its not litteral

Q. Diagram shows a sound wave as being displayed on an oscilloscope screen. Draw the waveform of another sound wave on the same diagram which has twice the pitch and is half as loud.

Answers

Answer:

i want points

Explanation:

Which characteristics do Venus and Earth share?A. similar size, mass and densityB. same direction of rotationC. slow revolution period around the SunD. atmosphere composed only of carbon dioxide.

Answers

The characteristics that Venus and Earth share are:

A. Similar size, mass, and density: Venus and Earth are often referred to as sister planets because they have similar sizes, masses, and densities.

Venus has a diameter of about 12,104 kilometers, while Earth has a diameter of about 12,742 kilometers. The mass and density of both planets are also comparable.

B. Same direction of rotation: Both Venus and Earth have a prograde rotation, meaning they rotate in the same direction as they orbit the Sun.

They rotate from west to east, with Venus completing one rotation in about 243 Earth days, while Earth takes approximately 24 hours for a full rotation.

C. Slow revolution period around the Sun: Venus has a longer orbital period around the Sun compared to Earth.

Venus takes about 225 Earth days to complete one revolution around the Sun, whereas Earth completes a revolution in approximately 365.25 days.

D. Atmosphere composed mostly of carbon dioxide: Venus has a thick atmosphere primarily composed of carbon dioxide (about 96%).

Earth's atmosphere, on the other hand, consists mostly of nitrogen (about 78%) and oxygen (about 21%), with only trace amounts of carbon dioxide.

In summary, the characteristics that Venus and Earth share include similar size, mass, and density, same direction of rotation, and a slow revolution period around the Sun.

However, their atmospheric compositions differ significantly, with Venus having a predominantly carbon dioxide atmosphere while Earth has a different composition dominated by nitrogen and oxygen.

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