One-fourth of adults in the United States are not active at all.

true

false

The material used before doubling will produce light at a frequency of 0.056 Hz.

The number of times a wave occurs repeatedly in a second is known as frequency.

The formula provides the frequency as,

\(\rm v = \lambda \times f \\\\\ \rm f = \frac{v}{\lambda} \\\\ \rm f = \frac{3 \times 10^8}{532 \times 10^-9} \\\\ \rm f = 3 \times 10^{12} \\\\ f= 0.056 \ Hz\)

Therefore, the material used before doubling will have an output light frequency of 0.056 Hz.

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Answer:

a and c

Explanation:

Answer:

hi = 12mm or 1.2cm

Explanation:

XOXO

Kit ^w^

A slide projector has a magnification of 50. 12mm or 1.2cm.

Bringing an object as close to the eye as feasible when wishing to observe an object's details is instinctual. The angle that an object subtends at the eye increases with proximity to the eye, making it appear larger.

However, if an item is too near, the eye will no longer be able to generate a distinct image. The creation of a "virtual image" that may be comfortably observed is made possible by the use of a magnifying lens between the observer and the object.

The magnifier should be positioned exactly in front of the eye to provide the clearest image possible. Once a clear image of the thing is present, the object of interest is brought closer to the eye.

Therefore, A slide projector has a magnification of 50. 12mm or 1.2cm.

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Applying Newton's third law, these two impulsive forces are equal and opposite i.e. If the time of contact is t, the impulse of the force F21 is equal to the change in momentum of the first object. The impulse of force F12 is equal to the change in momentum of the second object.

A 264 kg merry-go-round spinning at 24 rpm has its angular velocity reduced to 14.3 rpm after a 35.4 kg person jumps on.

To tackle this issue, we really want to utilize protection of precise energy. At first, the carousel is turning at a specific precise speed and has a specific snapshot of dormancy. At the point when John bounces onto the carousel, he expands the snapshot of inactivity, which makes the carousel delayed down. Notwithstanding, since precise energy is monitored, the result existing apart from everything else of dormancy and rakish speed should stay steady.

To begin with, we should track down the snapshot of idleness of the carousel:

I =\((1/2)mr^2\)

where

m = 264 kg (mass of the carousel)

r = 1.385 m (span of the carousel, which is half of the width)

I = \((1/2)(264 kg)(1.385 m)^2\) = 255 kg\(m^2\)

Then, how about we convert the underlying precise speed of the carousel from rpm to rad/s:

w_i = (24 rpm)(2π rad/1 rev)(1 min/60 s) = 2.51 rad/s

The underlying precise force of the framework is then:

L_i = Iw_i = (255 kg \(m^2\))(2.51 rad/s) = 642.05 kg \(m^2/s\)

At the point when John hops onto the carousel, the snapshot of inactivity of the framework increments to:

I_f = I + m*\(r^2\)

where

m = 35.4 kg (mass of John)

r = 1.385 m (span of the carousel)

I_f = (264 kg)\((1.385 m)^2\) + (35.4 kg)\((1.385 m)^2\)= 429.78 kg \(m^2\)

To find the last precise speed of the framework, we can utilize protection of rakish energy:

L_i = L_f

Iw_i = I_fw_f

Settling for w_f, we get:

w_f = (Iw_i)/I_f = (255 kg \(m^2/s\))(2.51 rad/s)/(429.78 kg \(m^2\)) = 1.50 rad/s

At long last, we can change over the last precise speed from rad/s back to rpm:

w_f = (1.50 rad/s)(60 s/2π rad)(1 fire up/1 turn) = 14.3 rpm

Consequently, the rakish speed of the carousel, in rpm, after John hops on is 14.3 rpm.

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True. Various heat-related disorders can be brought on by inadequate hydration combined with exposure to extreme heat and humidity.

One of three disorders brought on by excessive heat, with heat cramps being the least dangerous and heatstroke being the most serious, is heat exhaustion. High temperatures, particularly when there is also a high humidity level, and intensive physical activity are the main causes of heat illness.

According to T8 CCR Section 3395, "Heat Illness" refers to a dangerous medical illness caused by the body's incapacity to handle a specific amount of heat. Examples of this ailment include heat cramps, heat exhaustion, heat syncope, and heat stroke.

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To double the frequency of a vibrating stretched string with a fixed wavelength, the string tension needs to be increased by a factor of four (4).

When a string is under tension and clamped at its ends, it can vibrate at specific frequencies determined by its tension, mass per unit length, and the length of the string. The frequency of vibration is inversely proportional to the wavelength of the wave produced on the string.

In this scenario, we want to double the frequency of vibration while keeping the wavelength constant. Since frequency is directly proportional to the square root of tension, we need to increase the tension by a certain factor to achieve our desired frequency.

Using the equation for frequency in terms of tension and other variables, we can deduce that to double the frequency, the tension must be increased by a factor of four (4). This means that the new tension will be four times the original tension.

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Answer:

If you want definition, here it is:

Dispersion is defined to be the spreading of white light into its full spectrum of wavelengths. Refraction is responsible for dispersion in rainbows and many other situations. The angle of refraction depends on the index of refraction, as we saw in The Law of Refraction.

Human activities can increase landslide chances because it is responsible for clear-cutting, mining and quarrying, bad agricultural practices, and construction activities.

Yes, in some cases, human activities can give to causing landslides. Many human-caused landslides can be kept away from or mitigated. They are usually a result of building roads and structures without adequate grading of slopes, badly planned alteration of drainage patterns and disturbing old landslides.

In the study area, landslides seriously threaten the safety of people's lives and things and endanger transportation infrastructures. huge rainfall, an earthquake, or a combination of both commonly trigger a landslide.

So we can conclude that Some human activities, especially road construction, farmland allowance for building construction, and agricultural reclamation.

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Answer:

\(R_s = 0.093 \Omega\)

Explanation:

Voltage of the car battery = 12.0 V

Voltage drop in the battery = 3.4 V

The remainder of the voltage is the starter voltage, that is:

Starter voltage = Initial battery voltage - voltage drop

Starter voltage = 12.0 - 3.4

Starter voltage, \(V_{s}\) = 8.6 V

Current drawn by starter, \(I_s\) = 93 A

According to Ohm's law: \(V_s = I_s R_s\)

Starter Resistance, \(R_s\) = \(V_s/I_s\)

\(R_s = 8.6/93\\R_s = 0.093 \Omega\)

To divide a signal frequency by 4, two flip-flops are required.

Each flip-flop has two possible states: 0 and 1. By connecting the output of one flip-flop to the input of the next flip-flop in a specific configuration, the combination of flip-flop states can be used to divide the frequency.

In this case, a binary counter with two flip-flops is sufficient to divide the frequency by 4. The two flip-flops will count in binary from 00 to 11 and then reset back to 00, completing one full cycle. This effectively divides the input frequency by 4.

Therefore, the correct answer is b. 2

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Answer:

A simple machine having a velocity ratio of 3 simply means that the ratio of the distance moved by effort to the distance moved by load is equal to 3.

Explanation:

A simple machine can be defined as a type of machine with no moving parts but can be used to perform work.

Basically, a simple machine allows for the transformation of energy into work. The six simple machines are;

I. Inclined plane.

II. Screw.

III. Wheel and axle.

IV. Lever.

V. Wedge.

VI. Pulley.

Mathematically, the velocity ratio of a simple machine is given by the formula;

\( Velocity \; ratio = \frac {Distance \; moved \; by \; effort}{Distance \; moved \; by \; load} \)

Hence, a simple machine having a velocity ratio of 3 simply means that the ratio of the distance moved by effort to the distance moved by load is equal to 3.

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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Porter's Five Forces is a framework used to analyze the competitive intensity and attractiveness of an industry. The five forces are: Threat of New Entrants, Bargaining Power of Suppliers, Bargaining Power of Buyers, Threat of Substitute Products or Services and Intensity of Competitive Rivalry.

Threat of New Entrants: This force considers the ease or difficulty for new competitors to enter an industry. It includes barriers to entry such as high capital requirements, economies of scale, brand loyalty, and government regulations.

Example: The airline industry is known for its high barriers to entry due to the significant capital required to purchase aircraft, establish routes, and secure necessary licenses and permits. Additionally, established airlines often have loyal customer bases and strong brand recognition, making it challenging for new entrants to compete effectively.

Bargaining Power of Suppliers: This force assesses the power suppliers have over the industry in terms of pricing, quality, and availability of inputs. It considers factors such as the concentration of suppliers, uniqueness of their products, and their ability to forward integrate.

Example: In the smartphone industry, major suppliers of components like microchips and display screens hold significant bargaining power. These suppliers provide essential inputs, and their products may have limited alternatives or require specialized manufacturing processes. As a result, smartphone manufacturers must negotiate favorable terms with these suppliers to ensure a reliable supply chain and competitive pricing.

Bargaining Power of Buyers: This force examines the power customers have in influencing prices, demanding better quality or service, and potentially switching to alternative products or suppliers. It considers factors such as buyer concentration, product differentiation, and switching costs.

Example: The retail industry experiences strong buyer power, particularly in highly competitive markets. Customers have access to various options, and their ability to compare prices and products easily through online platforms empowers them to demand competitive pricing, promotions, and high-quality products and services.

Threat of Substitute Products or Services: This force looks at the availability of alternative products or services that can satisfy customer needs. It considers factors such as price-performance trade-offs, switching costs, and customer loyalty.

Example: The rise of streaming services such as Netflix, Amazon Prime Video, and Hulu posed a significant threat to traditional cable and satellite TV providers. These streaming platforms offer a wide range of content at competitive prices, allowing customers to switch from traditional TV services to streaming options, resulting in a decline in subscriber numbers for traditional providers.

Intensity of Competitive Rivalry: This force evaluates the level of competition among existing firms in the industry. It considers factors such as the number and size of competitors, industry growth rate, product differentiation, and exit barriers.

Example: The soft drink industry, dominated by major players like Coca-Cola and PepsiCo, experiences intense competitive rivalry. These companies fiercely compete for market share through advertising campaigns, new product launches, pricing strategies, and distribution channels. The rivalry is further intensified by the high market saturation and the limited scope for differentiation among similar products.

The interconnection of these forces lies in their collective influence on the competitive dynamics and profitability of an industry. Changes in one force can trigger a chain reaction that impacts the others. For instance, a high threat of new entrants may lead to increased competitive rivalry as existing firms strive to defend their market share. Similarly, a strong bargaining power of buyers can limit the pricing power of suppliers and impact their profitability. Understanding these interconnections helps businesses assess the overall attractiveness and competitive landscape of an industry and develop appropriate strategies to thrive within it.

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Answer:

Galanthus flowers have bulb roots that store large amounts of food.

Answer:

roller coaster is very nice to see

Answer:

when all forces acting on an object remain the same

None of the choices is correct.

Equilibrium is the condition when all forces acting on an object are balanced. Then, the object doesn't accelerate.  It continues in constant, uniform motion. It moves at a constant speed (which may be zero), and in a straight line.

Answer:

7.5m/s

Explanation:

Law of conservation of momentum: momentum in a system before collision equals to that after collision/

5kg*3m/s=2kg*v

15kgm/s=2kg*v

v=7.5m/s

A uniform electric field is one in which the magnitude and direction of the electric field are constant throughout the region of space. In this situation, the electric field is directed toward the right.

One important characteristic of an electric field is its strength, which is measured in units of volts per meter (V/m). The strength of an electric field is directly proportional to the magnitude of the charge creating the field and inversely proportional to the square of the distance from the charge.

Given that the electric field is uniform and directed toward the right, we can conclude that there is a source of charge somewhere to the left of the region of space. The magnitude of the electric field will depend on the magnitude of the charge and the distance from the charge to the region of space.

In terms of the statement that is correct about this situation, it is difficult to provide a definitive answer without more information. However, we can make some general observations.

One possibility is that there is a positive charge located to the left of the region of space. In this case, the electric field would be directed toward the right, as shown in the figure. Another possibility is that there is a negative charge located to the right of the region of space. In this case, the electric field would still be directed toward the right, but it would be repelling the negative charge.

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So free point OK ty see ya!

Answer:19.1m

Explanation:

Since the distance between them is 2.7 meters, the boat will also move a distance of 2.7 meters for Juliet to meet Romeo.

Displacement is the distance travelled in a specific direction. It is a vector quantity.

Given that Romeo (77kg) sings to Juliet (55kg) in the rear of a rowboat and he is 2.7 m away from Juliet. If after the song, Juliet carefully moves to the rear of the boat (away from the shore) to kiss Romeo which is 2.7 meters away, the distance covered by the 80 kg boat will also be equal to 2.7 m.

Since the distance between them is 2.7 meters, the boat will also move a distance of 2.7 meters for Juliet to meet Romeo.

Therefore, the answer will be 2.7 m

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The basis for the eigenspace corresponding to the listed eigenvalue is λ₁ = 1: Basis eigenvector v₁ = [-3/2; 1] and λ₂ = 4: Basis eigenvector v₂ = [1; -1/3].

To find the eigenspaces corresponding to the eigenvalues of a given matrix, we need to solve the equation (A - λI) v = 0, where A is the matrix, λ is the eigenvalue, I is the identity matrix, and v is the eigenvector.

Given matrix A:

A = [7 9; -2 -2]

Eigenvalues:

λ₁ = 1

λ₂ = 4

For each eigenvalue, we need to find the eigenvectors.

(A - λ₁I) v₁ = 0

Substituting the values:

([7 9; -2 -2] - 1 * [1 0; 0 1]) v₁ = 0

[6 9; -2 -3] v₁ = 0

Solving the system of equations:

6v₁ + 9v₂ = 0

-2v₁ - 3v₂ = 0

We can choose a value for v₂, say v₂ = 1:

6v₁ + 9(1) = 0

-2v₁ - 3(1) = 0

Simplifying the equations:

6v₁ + 9 = 0

-2v₁ - 3 = 0

Solving these equations, we find v₁ = -3/2.

Therefore, for λ₁ = 1, the eigenvector v₁ is [-3/2; 1].

(A - λ₂I) v₂ = 0

Substituting the values:

([7 9; -2 -2] - 4 * [1 0; 0 1]) v₂ = 0

[3 9; -2 -6] v₂ = 0

Solving the system of equations:

3v₁ + 9v₂ = 0

-2v₁ - 6v₂ = 0

We can choose a value for v₁, say v₁ = 1:

3(1) + 9v₂ = 0

-2(1) - 6v₂ = 0

Simplifying the equations:

3 + 9v₂ = 0

-2 - 6v₂ = 0

Solving these equations, we find v₂ = -1/3.

Therefore, for λ₂ = 4, the eigenvector v₂ is [1; -1/3].

In summary, the basis for the eigenspace corresponding to each eigenvalue is:

For eigenvalue λ₁ = 1: Basis eigenvector v₁ = [-3/2; 1]

For eigenvalue λ₂ = 4: Basis eigenvector v₂ = [1; -1/3]

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Answer:

4. INTERNATIONAL ASTRONOMICAL UNION

Answer:

6. force is the pull or push which changes or tends to change the (either rest or motion) of a body.

Answer:

15,000 decimeters

Explanation:

1 decameter = 100 decimeters

150 * 100

15,000

Best of Luck!

Answer:

it is b and e

Explanation:

During the hour-long assignment, the computer lab used a total of 175 watt-hours of energy. It's worth noting that watt-hours are a unit of energy, not power. Power is measured in watts, while energy is measured in watt-hours (or joules, which is the SI unit of energy).

To calculate the total energy used during the hour-long assignment, we need to add the energy used by the desktop computers and the monitors. Since the energy units are given in watt-hours, we can simply add them together to get the total energy used:

Total energy used = Energy used by desktop computers + Energy used by monitors

Total energy used = 100 watt-hours + 75 watt-hours

Total energy used = 175 watt-hours

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The x and y gravity components are 50.4 N and 109.2 N respectively, the normal force is - 109.2 N and the force of friction acting on the box is 50.4 N.

m = 12 kg

θ = 25°

W = m g

W = 12 * 10

W = 120 N

\(W_{x}\) = W sin θ

\(W_{x}\) = 120 * sin 25°

\(W_{x}\) = 50.4 N

\(W_{y}\) = W cos θ

\(W_{y}\) = 120 * cos 25°

\(W_{y}\) = 109.2 N

N = - \(W_{y}\)

N = - 109.2 N

Since the box is at rest,

∑ \(F_{x}\) = 0

\(W_{x}\) - \(F_{k}\) = 0

50.4 - \(F_{k}\) = 0

\(F_{k}\) = 50.4 N

Therefore,

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Answer:

2 meters a second or 2 m/s

Step 1;

Given,

The mass of the person, m=57.0 kg

The radius of the track, R=42.7 m

The normal force acting on the person, N=995 N

Step 2:

The centripetal force required for the person is provided by the sum of the difference in the normal force and the weight of the person.

Thus the centripetal force on the person is given by,

Where v is the speed with which the car and the person are moving and g is the acceleration due to gravity.

On rearranging the above equation,

Step 3:

On substituting the known values in the above equation,

Thus the velocity of the car is 18.08 m/s