One method that is used to grow nanowires (nanotubes with solid cores) is to initially deposit a small droplet of a liquid catalyst onto a flat surface. The surface and catalyst are heated and simultaneously exposed to a higher-temperature, low-pressure gas that contains a mixture of chemical species from which the nanowire is to be formed. The catalytic liquid slowly absorbs the species from the gas through its top surface and converts these to a solid material that is deposited onto the underlying liquid-solid interface, resulting in construction of the nanowire. The liquid catalyst remains suspended at the tip of the nanowire. Consider the growth of a 15-nm-diameter silicon carbide nanowire onto a silicon carbide sururface. The surface is maintained at a temperature of Ts = 2400 K and the particular liquid catalyst that is used must be maintained in the range 2400 K ≤ Tc ≤ 3000 K to perform its function. Determine the maximum length of a nanowire that may be grown for conditions characterized by h = 105 W/m2.K and T[infinity] = 8000 KT. Assume properties of the nanowire are the same as for bulk silicon carbide.

Hi! Your question involves the conventional procedure that requires one behavior and two antecedent stimulus conditions. In this procedure, responses are reinforced in the presence of the stimulus condition SD, but not in the presence of the other stimulus condition, S∆.

Step-by-step explanation:

1. A stimulus (SD) is presented, signaling that reinforcement is available for the specific behavior.
2. The individual performs the desired behavior in the presence of SD.
3. The behavior is reinforced (e.g., through reward or praise), strengthening the association between the behavior and SD.
4. Another stimulus (S∆) is introduced, signaling that reinforcement is not available for the behavior.
5. The individual performs the behavior in the presence of S∆.
6. The behavior is not reinforced in the presence of S∆, allowing the individual to learn that this specific behavior is not effective in this condition.

Through this procedure, the individual learns to perform the desired behavior only in the presence of the SD stimulus, while refraining from performing the behavior in the presence of the S∆ stimulus.

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The conventional procedure you are referring to is known as discrimination training. It involves one behavior and two antecedent stimulus conditions, the SD (discriminative stimulus) and the S∆ (delta stimulus).

The procedure you are referring to is called the Discrimination Training Procedure, which is a method used to teach animals and humans to discriminate between two stimuli. The conventional procedure requires presenting one behavior and two antecedent stimulus conditions.

This means that the individual is asked to perform a specific action or behavior when presented with a particular stimulus, but not when presented with another stimulus.
In this procedure, responses are reinforced in the presence of one stimulus condition, the SD, but not in the presence of the other stimulus, the S∆. This means that if the individual performs the desired behavior when presented with the SD, they will receive some form of reward or reinforcement. However, if they perform the behavior when presented with the S∆, they will not receive any reward or reinforcement.

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Answer:

c. Although PM and FM techniques are classified as angular modulation techniques, they cannot be used interchangeably i.e., modulated with FM and demodulated with PM, and vice versa.

Explanation:

Phase modulation is modulation pattern for conditioning communication signals for transmission. PM signals appears to change frequency with message wave. Both PM and FM are angular modulation techniques. The message in PM wave is captured in phase changes.

Answer:

Typically, diesel trucks cost more than those with gas engines, especially when you're first buying them, as diesel is usually featured as an add-on for gas-powered cars. Diesel add-ons can cost over $5,000 for midsize trucks and around $10,000 for heavy-duty trucks.

Explanation:

Make me brain pls

False. The Kutta condition is a mathematical principle used in fluid mechanics to determine the behavior of fluids around objects, such as wings.

The Kutta condition is a principle in aerodynamics that refers to the behavior of flow around the trailing edge of a wing.

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No, the physical address 346E0 cannot be the starting address for a segment. This is because the starting address of a segment must be aligned with the segment's size or boundary, which is determined by the processor's architecture.

Segment boundaries are defined by 16-byte or 4-byte boundaries, depending on the segment's use. Therefore, the starting address of a segment must be a multiple of 16 or 4, respectively, depending on the segment type.

In the given address 346E0, the last digit is 0, which indicates that it is a multiple of 16. However, we do not have enough information about the processor architecture and segment size to determine whether this is an appropriate starting address for a segment.

In general, when defining a segment, it is important to ensure that the starting address is properly aligned with the segment's boundary to avoid any issues with memory access and processing.

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Given the Z-transform of impulse response of a stable LTI system is:

\(h(z) = 2z / (z-1)\)

we have to decompose the above rational Z-transform to partial fractions. This is done by applying the partial fraction decomposition techniques.

\(h(z) = 2z / (z-1) = A / (z-1) + Bz\)

After the multiplication of (z-1) on both sides, we get

\(2z = A + Bz(z = 1) => A = 2z = 2\)

\(B = 2 / (z-1)\) Now, h(z)

\(h(z) = 2 / (z-1) + 2z / (z-1)^2\)

Now, we know the Z-transform of unit impulse function δ(n), which is:

\(Z{δ(n)} = 1\)

the Z-transform of h(n) can be expressed as:\(H(z) = Z{h(n)} = 2 / (z-1) + 2z / (z-1)^2\)Now, applying the inverse Z-transform on H(z), we get the h(n), as follows:

\(h(n) = L^-1 {H(z)} = L^-1 { 2 / (z-1) } + L^-1 { 2z / (z-1)^2 }\)

\(h(n) = 2δ(n) + 2n u(n)\) Where,\(L^-1 { 2 / (z-1) } = 2δ\)(n)and,\(L^-1 { 2z / (z-1)^2 } = 2n u(n)\)

Therefore, the impulse response h(n) for the given Z-transform is 2δ(n) + 2n u(n).

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The 3-stage parametric equalizer adjustments on a Yaesu FT-DX10 are high frequency, middle frequency, and low frequency.

What is parametric equalizer?
This illustration demonstrates how to create parametric equalizer filters. Digital filters known as parametric equalisers are used in audio to modify the frequency content of a sound input. By permitting adjustments to the gain, centre frequency, and bandwidth of each filter, parametric equalisers offer capabilities beyond those of graphic equalisers. Graphic equalisers, on the other hand, only let you change the gain of the each filter. Typically, second-order IIR filters are used to create parametric equalisers. These filters have the issue of having relatively wide ripple or transition areas due to their low order, and when multiple of them are combined in a cascade, they may overlap. The ability to create high-order IIR parametric equalisers is provided by Audio ToolboxTM. Such high-order designs provide each filter's shape much greater flexibility.

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No matter how many traffic lanes or if a turn lane is present, drivers in both directions of a two- or multi-lane highway are required to stop and remain stopped until the flashing red bus lights are turned off.

Only lanes of traffic moving in the same direction as the school bus must come to a complete stop. To get to their home, students shouldn't have to cross four or more lanes of traffic. The school bus had to stop. To get to their home, students shouldn't have to cross four or more lanes of traffic. On a two-lane road, when a school bus stops and flashes its red lights, traffic coming from either direction must stop before passing the bus. on multilane roads. on roadways with dividers.

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Answer:

i) SF = 0.83

ii) 10 psi

iii) 3.16 psi

iv) 0.0083

Explanation:

Constant load = 1000 Psi

mean resistance = 1200 psi

Probability of failure = 1.9 * 10^-3

Determine

i) Safety factor

S.F =  1 / (mean load / load design ) = 1 / ( 1200 / 1000 ) = 0.83

ii) Standard deviation

1.9 X 10^-3 = e  ( -1/2 ( μ / б) ^3  /  (2.5 * 6  )

0.004756 = e^- 20000 / б^3

hence std = 10 psi

iii) Variance

= \(\sqrt{10}\) = 3.16 psi

iv) coefficient of variation

Cv = std / mean resistance

    = 10 / 1200 = 0.0083

Answer:

building a bridge

Explanation:

you would have to sketch ideas to see what the bridge would look like and you need to know what to add to it to enhance the percentage of it working. if you sketch it you would have an idea of the process also

Building a bridge is an occasion in which an explanatory sketch would be used.

Sketches of explanations are created to demonstrate form, structure, and function. They accurately and objectively communicate a design, placing more emphasis on explanation than pitch. Outside of the design team, explanation sketches must be understandable.

Exploratory sketches, often referred to as thinking drawings, are a type of personal communication that frequently serve as the starting point for brand-new product concepts.

During a brainstorming session or for personal usage in a design notebook, these quick sketches are meant to quickly capture ideas. Exploratory research aims to study the important aspects of a topic that hasn't gotten much attention.

Thus, it is Building a bridge.

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Answer:

Explanation:

The internal combustion engine is an engine in which ignition and combustion take place in the engine(in one place), the invention of the ICE was an integral part of the industrial revolution, as there was increasing demand for power, and manual labor could not suffice, especially during the mid 19 century.

The ICE made it possible for tasks that demand intensive power consumption to come through to reality, it was as a result of the invention of the ICE that road transportation was made easier for mankind, as the means of transport then was the use of beast of burden, now we have cars, airplanes ship, etc, essentially the invention of ICE reduced the tedious task man would have to engage in for his daily needs

Answer:

Metamorphic manufacturing

Explanation:

I don't know what form of an answer you wanted but I hope this helps :)

Answer:

An improper integral is a definite integral that has either or both limits infinite or an integrand that approaches infinity at one or more points in the range of integration

Explanation:

Answer:

the actual specific work required by the compressor to operate is 2425.88 kJ/kg

Explanation:

Given that;

h₁ = 1350 kJ/kg

h₂₅ = 3412 kJ/kg

compressor efficiency П_ise = 0.85

we know that;

compressor efficiency П_ise = isentropic work / actual work

П_ise = (h₂₅ - h₁) / (h₂ - h₁ )

so

0.85 =  (h₂₅ - h₁) / (actual work )

Actual work = (h₂₅ - h₁) / 0.85

Actual work = (3412 - 1350) / 0.85

Actual work = 2062 / 0.85

Actual work = 2425.88 kJ/kg

Therefore the actual specific work required by the compressor to operate is 2425.88 kJ/kg

Answer:

the length will be 1.058

Explanation:

coefficient of linear expansivity of Aluminum, = 25 x 10⁻⁶ ⁰C⁻¹

coefficient of linear expansivity of steel, = 12 x 10⁻⁶ ⁰C⁻¹

Change in length of aluminum; ΔL = **ΔT

Change in length of steel; ΔL = **ΔT

difference in length of Aluminum and steel;

- = 0.55 m, for this difference to remain constant, then ΔL = ΔL

From the equation above, = 0.55 +

Since, ΔL = ΔL, then **ΔT = **ΔT

At constant temperature, the equation becomes;

* = *

Recall;

To calculate the length of the steel beam;

Therefore, the length of the steel beam is 1.058 m

Answer:

Plotters

Explanation:

https://en.wikipedia.org/wiki/Plotter

Answer:

Updated question

The big ben clock tower in London has clocks on all four sides. If each clock has a minute hand that is 11.5 feet in length, how far does the tip of each hand travel in 52 minutes?

The distance traveled by the tip of the minute hand of the clock would be 62.59 ft

Explanation:

Let us assume the shape of the clock is circular.

the minute hand is equal to the radius = 11.5 ft

Diameter = radius x 2

Diameter = 11.5 x 2 = 23 ft

The distance traveled by the tip of the minute hand can be calculated thus;

the fraction of the circumference traveled by the minute hand would be;

52/60 = 0.8667

Circumference of the clock would be;

C = pi x d

where C is the circumference

pi is a constant

d is the diameter

C = 3.14 x 23

C = 72.22 ft

Therefore the fraction of the circumference covered by the minute hand would be;

72.22 ft x 0.8667 = 62.59 ft

Therefore the distance traveled by the tip of the minute hand of the clock would be 62.59 ft

The steps that should be taken to evaluate the team member's level of competence are:

The method that I will use to resolve this problem if you somehow didn't receive the desired expertise is to ask a person from my team to teach me how to do it as well as consult external people or the internet.

Long used as a framework, competencies help direct employees' behavior toward the issues that are most important to an organization and contribute to success.

Therefore, They can offer a standard method to coordinate, pick out, and nurture talent. For workers, as well as managers, and ultimately the organization, the advantages are obvious.

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The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.

Power is the energy transferred per unit time.

Torque is find out by

P = 2πNT/60

10000 = 2π x 2000 x T / 60

T =47.74 N.m

The gear ratio Ne / Ns =4/1

Ns =2000/4 = 500

Ts =Ps x 60/(2π x 500)

Ts =190.96 N.m

Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))

τ max =T/J x D/2
where d₁ = 30mm = 0.03 m

           d₀ = 30 +(2x 4) = 38mm =0.038 m

Substitute the values into the equation, we get

τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)

τ max = 28.98 MPa.

Thus, the maximum shear stress in the tube is 28.98 MPa.

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Answer:

John should detail his Scrum Master.

Explanation:

The Team Lead or Scrum Master coordinates the tasks of individual team members and supports the progress of the team. The Scrum Master usually receives instructions from the Product Owner and then ensures that the tasks are performed accordingly.  She also coaches the Development Team and works with the Product Owner to carry out daily development activities.  She also drives the Scrum Values and Principles, ensuring that the team members understand and practice them.

Answer:

Foot

Explanation:

It is. trust me

Answer:

True.

Explanation:

The three-point suspension system can be found on all industrial trucks and this is what promotes stability to the truck. This system forms a triangle with imaginary lines, which represents the zone of stability as shown in the question above. This is because the truck's steering axle stabilizes on a pivot pin that is placed in the center of the axle, this being the first point of the suspension system. This point is projected through imaginary lines to two diagonal points, forming the center of stability.

Answer:

0.1375 rad/s

Explanation:

Speed of car = 55 ft/s

We are to find angular velocity, which is θ.

There are mistakes in this question. It should be θ not 8 and r = 400 ft

Radius r = 400ft

Speed = velocity = 55 ft/s

We Express transverse of velocity

Vθ = rθ

Vθ = 400θ

Then magnitude

V = √(Vr)²+(Vθ)²

55 = √0² + 400θ²

55 = √160000θ

55 = 400θ

We find the value of θ

θ = 55/400

= 0.1375rad/s

The angular velocityθ = 0.1375 rad/s

The pressure in the steam line is 1,44 atm.

Streamlined defined as a graph showing the pressure at which a liquid and its vapor are in equilibrium at any temperature. Steam pressures and temperatures in current practice have reached 97–164 bar and 480–565°C or 593°C. The rate of enhancement in efficiency with enhancement in pressure becomes less as the pressure enhances. The steam work through from the boiler into the steam mains. Firstly, the pipework is cold and heat is transformed into it from the steam. The air surrounding the pipes is also cooler rather than the steam, so the pipework will begin to lose heat to the air. Insulation fitted around the pipe will reduce this heat loss considerably.

The height of a steam gauge = 15 ft = 4,572 m

the gauge reads 450 psi

1 psi = 14.7 atm

450 psi = 6,615 atm

We can use this formula to calculate the pressure:

P = F/h

Pressure (P) = 6,615 atm : 4,572 m = 1,44 atm

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A 3-to-5 decoder is a combinational circuit that takes a 3-bit input and produces a 5-bit output. The logical functions for each of the 5 outputs can be represented as follows:

Output Y0 = F(A, B, C) = A'BC'

Output Y1 = F(A, B, C) = AB'C'

Output Y2 = F(A, B, C) = AB'C

Output Y3 = F(A, B, C) = ABC'

Output Y4 = F(A, B, C) = ABC

In the above equations, A, B, and C represent the 3 input bits. The prime (') denotes the complement of a variable.

These logical functions determine the output values based on the input combination. Each output corresponds to a specific combination of the input bits. For example, when A=0, B=0, and C=0, the output Y0 will be 1, while all other outputs will be 0.

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Answer:

La temperatura Kelvin que corresponde a 0 ºB es 493.15 Kelvin.

Explanation:

Sabemos que el punto de congelación del agua es 273.15 Kelvin y, según el enunciado, -60 ºB. Asimismo, el punto de ebullición de esta sustancia es 373.15 Kelvin y, según el enunciado, -10 ºB. Asumiendo una relación lineal, podemos determinar la temperatura en escala Kelvin equivalente a 0 ºB mediante la siguiente extrapolación:

\(T = 373.15\,K+\left[\frac{373.15\,K-273.15\,K}{-10\,^{\circ}B-(-60\,^{\circ}B)}\right]\cdot [0\,^{\circ}B-(-60\,^{\circ}B)]\)

\(T = 493.15\,K\)

La temperatura Kelvin que corresponde a 0 ºB es 493.15 Kelvin.

Answer:

Question 1 A 1020 Cold-Drawn steel shaft is to transmit 20 hp while rotating at 1750 rpm. Calculate the transmitted torque in lbs. in. Ignore the effect of friction. Answer with three decimal points. 60.024 Question 2 Based on the maximum-shear-stress theory, determine the minimum diameter in inches for the shaft in Q1 to provide a safety factor of 3. Assume Sy = 57 Kpsi. Answer with three decimal points. 0.728 Question 3 If the shaft in Q2 was made of ASTM 30 cast iron, what would be the factor of safety? Assume Sut = 31 Kpsi, Suc = 109 Kpsi 0 2.1 O 2.0 O 2.5 0 2.4 2.3 O 2.2

Explanation:

hope it helps