One statement of the first law of thermodynamics is that:___________.
a. the amount of work done on a system is dependent of pathway.
b. the total work done on a system must equal the heat absorbed by the system.
c. the heat flow in or out of a system is independent of pathway.
d. the total energy flow in or out of a system is equal to the sum of the heat transferred to or from the system and the work done by or on the system.
e. in any chemical process the heat flow must equal the change in enthalpy.

Answer:

Process used for separating grains from the stalks is known as threshing, In this process, stalks are beaten to free the grain seeds.

Answer:

Threshing is extraction of wheat germ from the stalk. In today's usage the combine tractor cuts and threshes the wheat at the same time. Imagine a big lawn mower with a rotating drum inside.

The drum turns and shakes the germ out of the wheat, the seeds falling through small holes onto a conveyor belt one way, the leftover grass dumping out the other way. The grain is poured into a truck driving beside the combine.

In old times, grain had to be beaten out of the grass on a Threshing Floor.

Answer:

I may not have the answer so i'll just give up some hints.

Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s. Choose how long the object is falling. In this example, we will use the time of 8 seconds. Calculate the final free fall speed (just before hitting the ground) with the formula v = v₀ + gt = 0 + 9.80665 * 8 = 78.45 m/s . Find the free fall distance using the equation s = (1/2)gt² = 0.5 * 9.80665 * 8² = 313.8 m .h = 0.5 * 9.8 * (1.5)^2 = 11m. b. V = gt = 9.8 * 1.5 = 14.7m/s. A feather and brick dropped together. Air resistance causes the feather to fall more slowly. If a feather and a brick were dropped together in a vacuum—that is, an area from which all air has been removed—they would fall at the same rate, and hit the ground at the same time.When an object's point is taller the thing that is going down it will go faster than when the point is lower. EXAMPLE: The object is the tennis ball if you drop it down the higher hill it will be faster than if you drop it down a shorter hill. In other words, if two objects are the same size but one is heavier, the heavier one has greater density than the lighter object. Therefore, when both objects are dropped from the same height and at the same time, the heavier object should hit the ground before the lighter one.

I hope my little bit (big you may say) hint help you with your question.

The change of distance with respect to time is defined as speed.  Speed is a scalar quantity. The speed of brick while hits the ground is 9.90 m/sec.

The change of distance with respect to time is defined as speed.  Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

m is the mass of block =2.0 Kg

u is the initial velocity of fall =0 m/sec

h is the distance of fall = 5.0 m

g is the acceleration of free fall =10m/sec²

v is the hitting velocity of brick=?

According to Newton's third equation of motion

\(\rm v^2=u^2+2gh\\\\ \rm v^2=2gh\\\\ \rm v= \sqrt{2gh}\)

\(\rm v= \sqrt{2\times 9.81 \times 5.0} \\\\ \rm v=9.90\;m/sec\)

Hence the speed of the brick while hits the ground is 9.90 m/sec.

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Answer:

bouncing  a baskletball

Explanation:

Answer:someone kicking a soccer ball.

Explanation:

Because the ball isn’t in motion until acted on by another object (the foot)

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

    \(v_y =  5.14 \  m/s\)

b

\(\Delta t = 0.5248 \ s \)

Explanation:

From the question we are told that

The maximum height is H = 2.70

The Range is R = 12.9 m

Generally from projectile motion we have that

\(Range = \frac{ u^2 sin2(\theta)}{g}\)

\(12.9 = \frac{ u^2 sin2(\theta)}{g}\)

Generally from trigonometric identity

\(sin 2(\theta) = 2sin (\theta) cos(\theta)\)

So

\(12.9 = \frac{ u^2 2sin(\theta) cos(\theta)}{g}\)

=> \(u^2 * 2sin(\theta) cos(\theta) = 12.9 * g\)

\(u^2 * 2sin(\theta) cos(\theta) = 12.9 * 9.8\)

\(u^2 *2sin(\theta) cos(\theta) = 126.42 \ \cdots (1)\)

Also the maximum height is

\(H = \frac{u^2 sin^2 (\theta)}{2g}\)

=> \(2.70 = \frac{u^2 sin^2 (\theta)}{2g}\)

=> \(u^2 sin^2 (\theta) = 2.70 * 2 * g\)

=> \(u^2 sin^2 (\theta) = 2.70 * 2 * 9.8\)

=> \(u^2 sin^2 (\theta) = 52.92\cdots (2)\)

Dividing equation 2 by (1)

\(\frac{u^2 sin^2 (\theta)}{u^2 *2sin(\theta) cos(\theta)} =\frac{52.92}{126.42 }\)

=> \(tan(\theta ) = \frac{52.92}{126.42 }\)

=> \(\theta = tan^{-1} [0.4186]\)

=> \(\theta =22.71^o \)

So

From equation 1

\(u^2 *2sin(22.71) cos(22.71) = 126.42 \ \cdots (1)\)

=> \(u = 13.322 \ m/s\)

Generally the vertical component of the initial velocity is mathematically evaluated as

\(v_y = usin (\theta)\)

=> \(v_y = 13.322 * sin (22.71)\)

=> \(v_y = 5.14 \ m/s\)

Generally the time taken is mathematically represented as

\(\Delta t = \frac{u sin (\theta )}{g}\)

=>      \(\Delta t =  \frac{13.322 sin (22.71 )}{9.8}\)

=> \(\Delta t = 0.5248 \ s \)

(a) The distance  the car travels during your reaction time is 2.83 m.

(b) The total distance traveled by the car before stopping is 97.8 m

To find the distance traveled during the reaction time, we need to find the velocity after the reaction time and then use it to find the distance traveled.

78 km/h = 78,000 m/h ÷ 3600 s/h = 21.67 m/s

After the reaction time, the velocity is equal to the initial velocity plus the acceleration during the reaction time:

v = v₀ + at

v = 21.67 m/s - (4.6 m/s²)(0.130 s)

v = 21.67 m/s - 0.599 m/s

Finally, the distance traveled during the reaction time is given by:

d = v₀t  + ¹/₂at²

d  = 21.67  x 0.130 s    +    ¹/₂(-4.6) x (0.130)²

d = 2.83 m

B) To find the total distance traveled before stopping, we need to find the time it takes for the velocity to reach 0.

The velocity after the reaction time is equal to 21.67 m/s - 0.599 m/s = 21.07 m/s.

Using the equation v = v₀ + at, we can find the time it takes to come to a stop:

t = -v₀ / a

t = -21.07 / -4.6

t = 4.58 s

The total distance traveled can be found using the equation:

d =  v₀t  + ¹/₂at²

d  = 21.67 x 4.58  + ¹/₂(-4.6) x 4.58

d = 97.8 m

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The time taken for the cannonball to move upward before stopping, given that is was fired directly upward at 300 m/s is 30.6 seconds

Velocity and time are related according to the following equation of motion

v = u + gt

Where

From the question given above, the following data were obtained:

The time taken for the cannonball to move upward before stopping can be obtained as illustrated below:

v = u - gt (since the ball is going against gravity)

0 = 300 - (9.8 × t)

0 = 300 - 9.8t

Collect like terms

-9.8t = 0 - 300

-9.8t = -300

Divide both sides by -9.8

t = -300 / -9.8

t = 30.6 seconds

Thus, the time taken is 30.6 seconds

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Answer:

The maximum elongation of the spring is 0.5 meters.

Explanation:

The statement is incorrect. The correct form is:

A 2-kg block is attached to a horizontal ideal spring with a spring constant of 200 newton per meter. When the spring has its equillibrium length, the block has a speed of 5 meters per second. What is the maximum elongation of the spring?

The block experiments a simple harmonic motion, where there are no non-conservative forces and the total energy is the sum of translational kinetic energy of the mass and the elastic potential energy of the spring. The maximum elongation of the spring is done when elastic potential energy reach its maximum. By the Principle of Energy Conservation, the maximum elastic potential energy is equal to the maximum translational kinetic energy, which corresponds to the instant when the mass reaches the equilibrium position. Then, the equation modelling the system is:

\(U_{max} = K_{max}\) (1)

Where:

\(U_{max}\) - Maximum elastic potential energy of the spring, measured in joules.

\(K_{max}\) - Maximum translational kinetic energy of the mass, measured in joules.

By definitions of the maximum elastic potential energy of the spring and the maximum translational kinetic energy of the mass, the expression above is expanded and simplified:

\(\frac{1}{2}\cdot k\cdot x_{max}^{2} = \frac{1}{2}\cdot m \cdot v_{max}^{2}\)

\(x_{max} = \sqrt{\frac{m}{k} }\cdot v_{max}\) (2)

Where:

\(x_{max}\) - Maximum elongation of the spring, measured in meters.

\(m\) - Mass, measured in kilograms.

\(k\) - Spring constant, measured in newtons per meter.

\(v_{max}\) - Maximum speed of the mass, measured in meters per second.

If we know that \(m = 2\,kg\), \(k = 200\,\frac{N}{m}\) and \(v_{max} = 5\,\frac{m}{s}\), then the maximum elongation of the spring is:

\(x_{max} = \sqrt{\frac{2\,kg}{200\,\frac{N}{m} } }\cdot \left(5\,\frac{m}{s} \right)\)

\(x_{max} = 0.5\,m\)

The maximum elongation of the spring is 0.5 meters.

The radius of a hemisphere with a volume of 61326 ft^3 , to the nearest tenth of a foot is 30.827 f.

The volume of a sphere with radius R is known to be:

V = (4/3)*pi*R^3

in where pi = 3.14

A hemisphere is half a sphere, its volume is half that of a sphere, and its volume is as follows for a hemisphere of radius R:

V' = (1/2)*(4/3)*pi*R^3

Now that we are aware of the volume of our hemisphere:

V' = 61326 ft^3

The equation is then easy to solve:

61326 ft^3 = (1/2)*(4/3)*pi*R^3

For R.

(We need the diameter, but knowing the radius is a good place to start because the diameter is equal to two times the radius.)

61326 ft^3 = (1/2)*(4/3)*pi*R^3

61326 ft^3 = (4/6)

*3.14*R^3

61326 ft^3*(6/4*3.14) = R^3

∛( 61326 ft^3*(6/4*3.14) ) = R = 30.827 f

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Change of state due to cooling is due to the removal of thermal energy from a substance. A substance changes states, such as from a gas to a liquid or from a liquid to a solid, when its particles lose kinetic energy as it loses heat and moves more slowly. Eventually, the particles reorganize into a more ordered form with less energy. The term "solidification" or "freezing" refers to this process.

Answer:

There are many advantages of geothermal energy but also some challenges ... than the air, it can act as a heat sink/ source with a geothermal heat pump just ... The largest single disadvantage of geothermal energy is that it is location specific. ... energy does not typically release greenhouse gases, there are many of these .

The advantage of using geothermal energy is that It reduces greenhouse emissions. Geothermal energy has a lot of advantage.

Geothermal energy is the thermal energy in the Earth's crust that comes from the planet's creation and radioactive decay of components in nearly equal amount.

The advantage of using the geothermal energy is;

A. It is available only in limited areas.

B. It can cause air and groundwater pollution.

C. It is difficult to transport from place to place.

Following is an advantage of using geothermal energy

D. It reduces greenhouse emissions.

Hence, option D is correct.

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Answer:

the answer is D I tought

Vegetable oil does not burn if we use it while frying it because liquid oil itself does not burn. Rather, it is the vapor from oil that has reached its boiling and vapor point that ignites.

There are three things, for our purposes, to understand. The flash point, the fire point, and the ignition point. The ignition point is responsible for burning. To avoid oil burns, carefully and gently lower the food into the oil with your hands or tongs, and make sure that it drops away from you.

When oil starts to smoke it will impart a burnt, bitter flavor thanks to a substance released called acrolein. During this process, harmful compounds called polar compounds may also be released as a byproduct of the breakdown of that oil as it's exposed to heat.

Therefore, vegetable oil does not burn if we use it while frying it because liquid oil itself does not burn.

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Answer:

A. Heat flowing from cold to hot

Explanation:

The second law of thermodynamics speaks about entropy and directions of processes. These directions go only in one direction, just as time moves only in one direction, as we know it. It is impossible to see time moving forward in a different sense. In the same way, the processes associated with heat transfer, go in a single direction this direction is associated with bodies at different temperatures. Where heat is transferred from a higher temperature body to a lower temperature body.

Heat transfer processes from a cold body to a hot body, do not exist and can not be achieved in a natural way.

Answer:

C

Explanation:

The circuit is a series circuit since all of the components are connected in a single path.

The current that flows through each component is the same, and the voltage across each component is proportional to its resistance.

In this circuit, there are two resistors, R1 and R2, and a battery with an electromotive force (EMF) of E.

The voltage across each resistor can be determined using Ohm's law, which states that

V = IR,

where V is the voltage

           I is the current

           R is the resistance.
The total resistance of the circuit can be calculated using the formula:

R = R1 + R2.

Using Ohm's law, the current in the circuit can be found by dividing the voltage by the total resistance:

I = E / R
The voltage across each resistor can be found using

V1 = IR1 and V2 = IR2.

The total voltage of the circuit is equal to the sum of the voltages across each resistor

V = V1 + V2

Substituting the equations for V1 and V2 into the equation for V, we get;

V = I(R1 + R2)
Thus, we can use the following equations to solve for the different variables in the circuit:
R = R1 + R2
I = E / R
V1 = IR1
V2 = IR2
V = I(R1 + R2)
Using these equations, we can calculate the current, voltage, and power of the circuit.

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The w (work) for an automobile engine that generates 2268J of heat that must be carried away by the cooling system with the internal energy changes by -2789J in this process is 521 Joules.

Work, in physics, is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, for a constant force aligned with the direction of motion, the work equals the product of the force strength and the distance traveled.

The heat evolved by the system (q) = - 2268J

The change in internal energy, dU = -2789J

From the first law of thermodynamics q = dU + W

So work done by the engine will be calculated as follows

W = q - dU

= -2268J - (-2789)J
= +521J

Therefore the work for engine, which represents the work available to push the pistons in this process, is 521J.

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Answer:

the ticket collector is moving at 2.00 mi/h in the same direction, the relative speed of the ticket collector to the person on the train is 65.0 mi/h - 2.0 mi/h = 63.0 mi/h.

Explanation:

From the point of view of a person on the train, the ticket collector is moving at a speed of 63.0 mi/h. To determine this, we need to subtract the speed of the train from the speed of the ticket collector in the same direction. Since the train is moving at 65.0 mi/h

Answer:

yes?

Explanation:

I don’t really understand your question

The distance around Earth's equator is about 24,000 miles. Thus, rotational velocity at Earth's equator is 1000 miles/hour.

Every point on an object that is revolving about an axis has the same angular velocity. The tangential velocity of points distant from the axis of rotation is, nevertheless, different from that of points closer to the axis of rotation. Rotational velocity and an angular frequency vector are other names for angular velocity.

Given that,

The distance around Earth's equator is about 24,000 miles.

Time to complete one Rotation = 24 hours.

Thus, velocity = distance/time

or, velocity = 24,000 miles / 24 hours

or, velocity = 1000 miles/hour.

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Answer:

Use equation 1/2 * m * v²

Explanation:

where m = mass in kg

and v = velocity in m/s

plug accordingly.

Answer:

One that is larger than the object and real

Explanation:

When positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of charge movement.

In the given scenario, if positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds (10 μs), we can infer the following about the magnitude and direction of the current:

1. Magnitude of the Current: The magnitude of the current is determined by the total charge passing through a given point in the wire per unit time. Since both positive and negative charges are moving, the total charge passing through a point will be the sum of the magnitudes of the charges. If the number of positive and negative charges is equal, the magnitudes of their charges will also be equal. Therefore, the total charge passing through the point will be the sum of equal positive and negative charges, resulting in a net charge of zero. In this case, the magnitude of the current will be zero.

2. Direction of the Current: The direction of the current is determined by the flow of positive charges. In a copper wire, the positive charges are not free to move. Instead, it is the negatively charged electrons that are free to move. Due to conventional current flow convention, the direction of the current is considered opposite to the direction of the electron flow. Therefore, even though both positive and negative charges are moving horizontally, the direction of the current will be in the opposite direction to the movement of the charges.

In summary, in the given scenario, where positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of the charge movement.

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The relative density of aluminum is 2.7. This means that aluminum is 2.7 times denser than water, which is the reference substance often used for comparing densities

The relative density (also known as specific gravity) of a material is the ratio of its density to the density of a reference substance. In this case, we are given the density of aluminum as 2.7 x 10^3 kg/m^3.

To find the relative density, we need to compare it to the density of the reference substance. The most commonly used reference substance for relative density is water, which has a density of 1000 kg/m^3.

Relative density = Density of the material / Density of the reference substance.Relative density = (2.7 x 10^3 kg/m^3) / (1000 kg/m^3)

Relative density = 2.7

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The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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The water level tries to be horizontal, even beneath the tilted mug. That means that in the "lower half" of the mug, the water penetrates inside the mug. The pressure and density of the air stays nearly constant, so air must penetrate outside the mug on the other side. Now, it is geometrically possible for the air to escape in the direction of the arrow and create bubbles.

It's actually encouraged to do so, I think, because the pressure of the air is slightly higher than the pressure of water at the beginning of the arrow. Why? Because the pressure is nearly uniform in the whole confined air – the hydrostatic altitude-dependence in the air is negligible due to the air's low density – and it is equal to the pressure of water at the horizontal level beneath the mug. At the beginning of the arrow, the hydrostatic pressure is lower, so the air has the inclination to move to the right in the direction of the water, and it eventually gets outside the "vertically beneath the mug" space and it may escape.

I hope that I don't have to explain why bubbles of the air move "up" in water whenever they can. ;-)

The critical angle at which the bubbles start to from is determined by the surface tension: the bubbles don't want to be too small because of this additional force and a small initial excess of the pressure may fail to be enough to form such bubbles. Approximately when it becomes possible for the minimal sustainable bubbles to form and escape, they will.

Pressure in a liquid depends on the direction the pressure gauge is pointing. This statement is False.

The direction the pressure gauge is pointing has no bearing on the pressure within a liquid. The direction of the pressure gauge has no bearing on the pressure at a given place in a liquid. The depth of the point and the liquid's density determine the pressure at every point in the liquid. Any spot in a liquid experiences constant pressure that is evenly transmitted in all directions.

Pressure is defined as force per unit area. i.e. P = F/A it gives the force on unit area. its SI unit is Pascal (Pa) which is equal to N/m². is a scalar quantity. its dimensions are [M¹ L⁻¹ T⁻²].

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Answer:

B

Explanation:

The answer to this is B because nitrogen gas is N2 and they are chemically bonded not simply mixed.

The total distance covered by the car is 300 miles.

The total displacement covered by the car is zero.

The average speed of the car is 17.88 m/s.

The average velocity of the car is also zero.

Distance between the points A and B, d = 150 miles

Time taken by the car to travel from A to B, t₁ = 3 hours

Time taken by the car to travel from B to A, t₂ = 5 hours

a) Given that the car travelled from A to B and then back to A.

Therefore, the total distance covered by the car is,

Distance = 2 x d

Distance = 2 x 150

Distance = 300 miles

Since the car is travelling from A to B and then returning back to the initial point A, the total displacement covered by the car is zero.

b) The speed with which the car travelled from A to B is,

v₁ = d/t₁

v₁ = 150/3

v₁ = 50 miles/hr

v₁ = 22.35 m/s

The speed with which the car travelled from B to A is,

v₂ = d/t₂

v₂ = 150/5

v₂ = 30 miles/hr

v₂ = 13.41 m/s

Therefore, the average speed of the car is,

v = (v₁ + v₂)/2

v = (22.35 + 13.41)/2

v = 17.88 m/s

As, the total displacement of the car is zero, the average velocity of the car is also zero.

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Answer:

Explanation:

Hay muchos recursos en línea que pueden ayudarte a aprender cómo resolver este tipo de problemas. Por ejemplo, puedes consultar el documento 1 del MIT OpenCourseWare que explica los métodos de solución para problemas electrostáticos en inglés. También puedes ver el documento 2 de ResearchGate que contiene soluciones a algunos ejercicios de electrostática en español. Otra opción es visitar el sitio web youphysics.education 3 que tiene muchos problemas y soluciones de electrostática en español.

An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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