open "" "" then input each integer from the file and output the integer as a separate line on the console.

The false statement about most machine learning models is that: B. they are flexible enough to handle all issues you might see in your dataset (lack of data, incorrect data, etc).

Machine learning (ML) is also referred to as deep learning or artificial intelligence (AI) and it can be defined as a subfield in computer science which is typically focused on the use of data-driven techniques (methods), computer algorithms, and technologies to develop a smart computer-controlled robot with an ability to automatically perform and manage tasks that are exclusively meant for humans or solved by using human intelligence.

Generally speaking, machine learning models are designed and developed to accept numerical data (numbers) or collections of numerical data (numbers) as an input.

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The ratio of maximum shear stresses in the hollow and solid bars is (15/16).To calculate the ratio of torsional stiffnesses between a hollow and solid bar, and the ratio of their maximum shear stresses, we can use the concept of polar moment of inertia (J) and the torsion formula.

Ratio of Torsional Stiffnesses: The torsional stiffness of a bar is proportional to its polar moment of inertia. For a solid bar, the polar moment of inertia is given by J_solid = (π/32) * (d^4), where d is the diameter of the solid bar.

For a hollow bar with an inner diameter of d/2, the polar moment of inertia is given by J_hollow = (π/32) * (d^4 - (d/2)^4).

The ratio of torsional stiffnesses (K) between the hollow and solid bars is then: K = J_hollow / J_solid = [(d^4 - (d/2)^4)] / d^4 = (15/16)

Ratio of Maximum Shear Stresses: The maximum shear stress (τ_max) in a bar under torsion is given by the formula τ_max = (T * r) / J, where T is the applied torque and r is the radial distance from the center of the bar.

Since both the hollow and solid bars are subjected to the same torque, the ratio of their maximum shear stresses will be the same as the ratio of their polar moments of inertia:

τ_max_hollow / τ_max_solid = J_hollow / J_solid = (15/16)

Therefore, the ratio of maximum shear stresses in the hollow and solid bars is (15/16).

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The correct answer is Specific weight: w = [weight ÷ volume] = [9N ÷ 0.001m³] = 9000N/m³Density: w = [ × g] Where, g = acceleration due to gravity = 9.81m/sec². Specific gravity: G = [density of liquid ÷ density of water] As you know, The density of water = 1000kg/m³.

The density of a substance is divided by the density of water at 4 degrees Celsius to determine its specific gravity. The density of the substance and the density of the water must be represented in the same units for the calculation.distinguishes  While specific weight has dimensions, specific gravity is a dimensionless number. The gravitational field has no effect on a material's specific gravity, but it does have an effect on a material's specific weight. A substance's "Specific Gravity" is determined by dividing its mass by the mass of an equivalent volume of water at the same pressure and temperature.

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Answer:

) You must create a Low Pass Filter for an audio amplifier. You must pass 10khz and block

60khz. In designing this, you must choose a cutoff frequency exactly half way between

these two frequencies. In addition, you must use a 0.2uF capacitor in you LPF circuit.

Given these criteria, analyze this circuit, and determine the necessary resistor value in

Ohms. Find the output Voltage at both ends of the spectrum. Based on your results, is

this a good design? NOTE: You MUST show your work (when using MS Word, choose

“Insert”--- “Equation”). (6 marks)

a. Solve for fc

b. Solve for R

c. Solve for Vout at 10khz

d. Solve for Vout at 60khz

e. Good design> (yes or no with an explanation)

Explanation:

Answer:

240

Explanation:

The highest voltage typically encountered on the job by a residential electrician is C. 240 volts.

Voltage is the measure of the difference in electrical power between two points in a circuit.

It is like the force that pushes electric charges in a circuit and is measured in volts (V) and affects how strong the electric current flows in a wire.

In many countries, the United States included, residential electrical systems often use a split-phase setup with a voltage of 120/240 volts.

This voltage is widely used for things like household appliances, lights, and other electrical needs in homes.

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Answer:

The volume percent of graphite is 91.906 per cent.

Explanation:

The volume percent of graphite (\(\% V_{Gr}\)) is determined by the following expression:

\(\%V_{Gr} = \frac{V_{Gr}}{V_{Gr}+V_{Fe}} \times 100\,\%\)

\(\%V_{Gr} = \frac{1}{1+\frac{V_{Gr}}{V_{Fe}} }\times 100\,\%\)

Where:

\(V_{Gr}\) - Volume occupied by the graphite phase, measured in cubic centimeters.

\(V_{Fe}\) - Volume occupied by the ferrite phase, measured in cubic centimeters.

The volume of each phase can be calculated in terms of its density and mass. That is:

\(V_{Gr} = \frac{m_{Gr}}{\rho_{Gr}}\)

\(V_{Fe} = \frac{m_{Fe}}{\rho_{Fe}}\)

Where:

\(m_{Gr}\), \(m_{Fe}\) - Masses of the graphite and ferrite phases, measured in grams.

\(\rho_{Gr}\), \(\rho_{Fe}\) - Densities of the graphite and ferrite phases, measured in grams per cubic centimeter.

Let substitute each volume in the definition of the volume percent of graphite:

\(\%V_{Gr} = \frac{1}{1 +\frac{\frac{m_{Gr}}{\rho_{Gr}} }{\frac{m_{Fe}}{\rho_{Fe}} } } \times 100\,\%\)

\(\%V_{Gr} = \frac{1}{1+\left(\frac{m_{Gr}}{m_{Fe}} \right)\cdot \left(\frac{\rho_{Fe}}{\rho_{Gr}} \right)}\times 100\,\%\)

Let suppose that 100 grams of cast iron are available, masses of each phase are now determined:

\(m_{Gr} = \frac{2.5}{100}\times (100\,g)\)

\(m_{Gr} = 2.5\,g\)

\(m_{Fe} = 100\,g - 2.5\,g\)

\(m_{Fe} = 97.5\,g\)

If \(m_{Gr} = 2.5\,g\), \(m_{Fe} = 97.5\,g\), \(\rho_{Fe} = 7.9\,\frac{g}{cm^{3}}\) and \(\rho_{Gr} = 2.3\,\frac{g}{cm^{3}}\), the volume percent of graphite is:

\(\%V_{Gr} = \frac{1}{1+\left(\frac{2.5\,gr}{97.5\,gr} \right)\cdot \left(\frac{7.9\,\frac{g}{cm^{3}} }{2.3\,\frac{g}{cm^{3}} } \right)} \times 100\,\%\)

\(\% V_{Gr} = 91.906\,\%\)

The volume percent of graphite is 91.906 per cent.

"Friction course typically uses PG 64-22 or PG 70-22 binders in its makeup to provide high skid resistance and improved durability."

A friction course, also known as a high friction surface treatment, is a type of pavement surface treatment used to improve the skid resistance of roadways, particularly in wet or slippery conditions. The friction course is composed of a layer of high-quality aggregates, typically granite or quartz, and a polymer-modified asphalt binder that provides excellent adhesion and durability. The polymer-modified binder used in the friction course is often a Performance Grade (PG) binder, which is selected based on its high-temperature performance and resistance to rutting and cracking. PG 64-22 and PG 70-22 binders are commonly used in friction courses due to their high-temperature viscosity, which helps to maintain aggregate embedment and prevent stripping, as well as their low-temperature stiffness, which provides excellent skid resistance in cold weather conditions.

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(a) Confidence Interval ≈ (11.72, 12.08). (b) Confidence Interval ≈ (11.64, 12.16) and (c) The confidence level of the interval is at least 95%.

To find the confidence intervals for the mean sugar content, we can use the formula:

Confidence Interval = Sample Mean ± (Critical Value * Standard Error)

where the critical value is based on the desired confidence level and the standard error is calculated as the standard deviation divided by the square root of the sample size.

a. 95% confidence interval:

The critical value for a 95% confidence level is approximately 1.96.

Standard Error = 1.1 / sqrt(140) ≈ 0.093

Confidence Interval = 11.9 ± (1.96 * 0.093)

Confidence Interval ≈ (11.72, 12.08)

b. 99% confidence interval:

The critical value for a 99% confidence level is approximately 2.58.

Standard Error = 1.1 / sqrt(140) ≈ 0.093

Confidence Interval = 11.9 ± (2.58 * 0.093)

Confidence Interval ≈ (11.64, 12.16)

c. The given interval is (11.81, 11.99). This interval falls entirely within the 95% confidence interval calculated in part a. Therefore, the confidence level of the interval is at least 95%.

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The property of real numbers is shown below is associative property of addition. The correct option is C.

According to the associative property of addition, you can arrange the addends in several ways without changing the result.

According to the commutative property of addition, you can rearrange the addends without altering the result.

When more than two numbers are added together or multiplied, the outcome is always the same, regardless of how the numbers are arranged.

This is known as the associative property. As an illustration, 2 (7 6) = (2 7) 6. 2 + (7 + 6) = (2 + 7) + 6.

Thus, the correct option is C.

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To determine the convective and radiative heat fluxes to the wall at x = 0, we can use the following equations:

1. Convective heat flux:

q_conv = h * (T_s - T_∞)

2. Radiative heat flux:

q_rad = α * σ * (T_s^4 - T_∞^4)

where:

Given:

T_∞ = 20°C

T_sur = 40°C

h = 20 W/(m²·K)

α = 0.78

T_s = 24°C

Let's calculate the convective and radiative heat fluxes:

1. Convective heat flux:

q_conv = 20 * (24 - 20) = 80 W/m²

2. Radiative heat flux:

q_rad = 0.78 * 5.67 × 10^-8 * ((24 + 273.15)^4 - (20 + 273.15)^4) = 238.17 W/m²

Therefore, the convective heat flux to the wall at x = 0 is 80 W/m², and the radiative heat flux is 238.17 W/m².

In this scenario, the one-dimensional plane wall is exposed to both convective and radiative heat transfer. The convective heat transfer occurs due to the temperature difference between the surface of the wall (T_s) and the surrounding ambient temperature (T_∞), which is characterized by the convective heat transfer coefficient (h). The convective heat flux represents the amount of heat transferred per unit area through convection.

The radiative heat transfer, on the other hand, occurs due to the temperature difference and the emissivity/absorptivity of the wall's exposed surface (α). The radiative heat flux depends on the Stefan-Boltzmann constant (σ) and the fourth power of the temperatures involved (T_s and T_∞). The emissivity/absorptivity of the surface determines how efficiently it radiates and absorbs thermal radiation.

In this case, since the surroundings are considered "large," we assume that the temperature of the surroundings (T_sur) remains constant and unaffected by the wall's heat transfer. This assumption simplifies the analysis by focusing only on the heat exchange between the wall and the ambient environment.

By applying the equations for convective and radiative heat fluxes, we can calculate the respective contributions to the total heat transfer at the wall's exposed surface.

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The simplified equations for each of the next state representations AP, BP, and CP in the 3-bit counter using D flip-flops are as follows  -

AP = (A' * B' * C') + (A' * B * C) + (A * B' * C) + (A * B * C')

BP = (A' * B * C') + (A' * B * C) + (A * B' * C') + (A * B' * C)

CP = (A' * B' * C) + (A' * B * C') + (A * B' * C') + (A * B * C')

These equations define the next state outputs based on the current state inputs A, B, and C.

The equations for the next state representations in the 3-bit counter using D flip-flops determine the conditions under which the outputs AP, BP, and CP will be set to high (1).

The equations combine the current state inputs A, B, and C using logical operations such as AND, OR, and NOT to determine the next state outputs.

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Answer:

a) \(L = 1.5\)

\(L_q = 0.9\)

\(W = \dfrac{1 }{8 } \, hour\)

\(W_q = \dfrac{3}{40 } \, hour\)

\(P = \dfrac{3}{5 }\)

b) The new backacter should be recommended

c) The additional backacter should not be deployed

Explanation:

a) The required parameters are;

L = The number of customers available

\(L = \dfrac{\lambda }{\mu -\lambda }\)

μ = Service rate

\(L_q\) = The number of customers waiting in line

\(L_q = p\times L\)

W = The time spent waiting including being served

\(W = \dfrac{1 }{\mu -\lambda }\)

\(W_q\) = The time spent waiting in line

\(W_q = P \times W\)

P = The system utilization

\(P = \dfrac{\lambda }{\mu }\)

From the information given;

λ = 12 trucks/hour

μ = 3 min/truck = 60/3 truck/hour = 20 truck/hour

Plugging in the above values, we have;

\(L = \dfrac{12 }{20 -12 } = \dfrac{12 }{8 } = 1.5\)

\(P = \dfrac{12 }{20 } = \dfrac{3}{5 }\)

\(L_q = \dfrac{3}{5 } \times \dfrac{3}{2 } = \dfrac{9}{10 } = 0.9\)

\(W = \dfrac{1 }{20 -12 } = \dfrac{1 }{8 } \ hour\)

\(W_q = \dfrac{3}{5 } \times \dfrac{1}{8 } = \dfrac{3}{40 } \, hour\)

(b) The service rate with the new backacter = 1.5 minutes/truck which is thus;

μ = 60/1.5 trucks/hour = 40 trucks/hour

\(P = \dfrac{12 }{40 } = \dfrac{3}{10}\)

\(W = \dfrac{1 }{40 -12 } = \dfrac{1 }{38 } \, hour\)

\(W_q = \dfrac{3}{10 } \times \dfrac{1}{38 } = \dfrac{3}{380 } \, hour\)

λ = 12 trucks/hour

Total cost = \(mC_s + \lambda WC_w\)

m = 1

\(C_s\) = GH¢ = 1300

\(C_w\) = 400

Total cost with the old backacter is given as follows;

\(1 \times 1000 + 12 \times \dfrac{1}{8} \times 400 = \$ 1,600.00\)

Total cost with the new backacter is given as follows;

\(1 \times 1300 + 12 \times \dfrac{1}{38} \times 400 = \$ 1,426.32\)

The new backacter will reduce the total costs, therefore, the new backacter is recommended.

c)

Here μ = 3 min/ 2 trucks = 2×60/3 truck/hour = 40 truck/hour

\(\therefore W = \dfrac{1 }{40 -12 } = \dfrac{1 }{38 } \, hour\)

Total cost with the one backacter is given as follows;

\(1 \times 1000 + 12 \times \dfrac{1}{8} \times 400 = \$ 1,600.00\)

Total cost with two backacters is given as follows;

\(2 \times 1000 + 12 \times \dfrac{1}{38} \times 400 = \$ 2,126.32\)

The additional backacter will increase the total costs, therefore, it should not be deployed.

The tari's total standard machine-hours allowed for last year's output 600,000 hours

Budgeted at start of year:  $100,000 fixed manufacturing overhead  for 500,000 machine hours

Standard = $100,000 / 500,000 hours = $0.2 fixed overhead / maching hour

At end of year, manufacturing overhead volume was $20,000 favorable which means

$20000 / $1=0.2 = 100000 additional hours.

Total Standard Machine Allowance Allowed for output = 500,000 + 100,000 = 600,000 hours.

the use of one machine running for an hour as a basis for cost estimation and operating effectiveness evaluation. In order to determine the contribution margin per machine hour for a specific product: a. Total cost per unit divided by the quantity of machine hours required to produce each unit of the target product. The manufacturing overhead cost divided by the activity driver yields the predetermined overhead rate. For instance, if machine hours were the activity driver, you would divide overhead costs by the anticipated number of machine hours.

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You get a result immediately from Euler's formula:

e ^(i π/2) = cos(π/2) + i sin(π/2) = 0 + i * 1 = i

Answer:

Mach number = 0.68168

The flow should be treated as compressible.

Explanation:

Given that:

The altitude of a commercial jet = 35000

The properties of air at that given altitude are as follows:

Pressure = 24.577 kPa

Temperature T = 50.78176° C

Temperature T = ( 50.78176 + 273 )K = 328.78176 K

\(\varphi = 0.38428 \ kg/m^3\)

The velocity is also given as: 550 mph = 245.872 m/s

Therefore, the sonic velocity is firstly determined by using the formula:

\(a = \sqrt{ \vartheta \times R \times T\\)

\(a = \sqrt{1.4 \times 287 \times 323.78176\)

\(a = \sqrt{130095.5112\)

a = 360.68755 m/s

Then, we can calculate the Mach number by using the expression:

\({Mach \ number = \dfrac{V}{a}}\)

\(Mach \ number = \dfrac{245.872}{360.68755}\)

Mach number = 0.68168

b) Ideally, all flows are compressible because the Mach number is greater than 0.3, suppose the Mach number is lesser than 0.3, then it is incompressible.

A nozzle-2 inclined at an angle of 30 degrees (with horizontal) is added to the system and both water jets strike at some point. For Nozzle-2, upon contact, water exits the plate 40% upwards and the remaining downwards.

Assuming frictionless flow and neglecting gravity effects, this paper examines the trajectories and forces exerted on the jet by each nozzle.The paths of the jets are defined by a momentum balance between the jet and the forces it encounters.

The jets' trajectory and force are dependent on the velocity of the stream entering the nozzle. The paths of the jets can be influenced by the interaction between the jets and the forces caused by the collisions between the two fluid streams in the impact zone.The velocities of the streams flowing through each nozzle should be comparable and symmetric for the nozzles to be coordinated. When the pressures are different, the path of the stream is also changed. If the downstream pressure of the two streams is unequal, they will impact at different positions on the plate.

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A chip without PMOS transistor is easier because pMOS transistor would not avaiable to offer a conductive path for a node all the way to the ground voltage.

Microprocessors are constructed out of transistors. In particular, they're built out of metal-oxide-semiconductor (MOS) transistors. There are kinds of MOS transistors — positive-MOS (pMOS) and negative-MOS (nMOS). Every pMOS and nMOS comes prepared with 3 primary components — the gate, the source, and the drain. NMOS and pMOS are the primary types of MOSFET. The primary difference between NMOS and pMOS is that, in NMOS, the source and the drain terminals are made from n-kind semiconductors meanwhile, in pMOS, the source and the drain are made from p-kind semiconductors.

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Answer:

1. True

2. True

3. False

Explanation:

The office location is where the soil layer is not uniform. The thickness of the soil varies which could lead to doors being jammed. The engineer needs to estimate the differential in clay soil.

The inclined surface can hold less weight than a vertical surface. The capacity to hold the weight is due to the gravitational force which is exerted to the load.

Answer:

Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.

Placing the two Product Backlog items back onto the Product Backlog ensures that the Scrum Team maintains focus on the highest priority tasks and improves the overall project outcomes.

In a Scrum Team, the Product Backlog is a dynamic and prioritized list of features, enhancements, and bug fixes to be completed in the project. When two Product Backlog items are placed back onto the Product Backlog, it means they need further refinement, reprioritization, or reconsideration before being included in a future Sprint.
The team has determined that the two items are not ready for development in the current Sprint or might require additional information or changes. By placing them back onto the Product Backlog, the team ensures they are addressing the most important and well-defined items first, leading to a more efficient and effective development process. The Product Owner will reassess the priorities and refine the items as needed, in collaboration with stakeholders and the development team.

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To calculate the magnitude of the voltage drop Vab, we first need to find the current flowing through the circuit when switch S1 is closed and switch S2 is open. This can be done using Ohm's Law (V = IR), where V is voltage, I is current, and R is resistance.

1. Identify the total resistance in the circuit. Since switch S2 is open, the current will only flow through the resistors connected to switch S1.
2. Apply Ohm's Law to calculate the current flowing through the circuit: I = V/R, where V is the voltage source, and R is the total resistance.
3. Calculate the voltage drop across each resistor using Ohm's Law (V = IR).
4. Determine Vab, which is the voltage drop between points A and B.

To find the magnitude of the voltage drop Vab when switch S1 is closed and switch S2 is open, you need to follow these steps: identify the total resistance in the circuit, calculate the current using Ohm's Law, find the voltage drop across each resistor, and finally determine the voltage drop between points A and B (Vab).

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When calculating the magnitude of the voltage drop (Vab) across a circuit with switch S1 closed and switch S2 open, you need to consider the circuit configuration, the resistances, and the voltage source.

To accurately answer this question, I would need specific information about the circuit components such as resistor values and the voltage source value. However, I can explain the process:
1. With switch S1 closed and switch S2 open, identify the active portion of the circuit.
2. Determine the total resistance (Rt) of the active circuit.
3. Apply Ohm's Law (V = I * R) to find the current (I) flowing through the circuit. (If the voltage source is given)
4. Calculate the voltage drop (Vab) across the desired portion of the circuit using the current and the resistance of that portion.

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The current is I=12/1000, which simplifies to 0.012 amps or 12 milliamps.

Plugging these values into the equation, we get I=12/1000, which simplifies to 0.012 amps or 12 milliamps. It's important to note that the current in a circuit is dependent on the voltage and resistance in the circuit. If either of these values were to change, the current would also change accordingly. Additionally, it's important to ensure that the components in the circuit can handle the amount of current that is flowing through them to prevent damage or overheating.

Current in electric circuits refers to the flow of electric charge. It is the rate at which electric charges, typically electrons, move through a conductor. Current is measured in amperes (A) and is represented by the symbol "I". In a closed circuit, where there is a complete path for the electric charges to flow, a voltage difference (potential difference) is applied across the circuit.

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Answer:

Betbtybrbytntrnyrnrynunjhjhnthnnhtnnthnhtnnhnhrnntnthhnhnhtnthn

Explanation:

Answer:

b i think is the correct answer

Explanation:

it was a bit hard but i used a ohms calculator

u should try it. it will help

Current is defined as the flow of electrical charge carriers, which are often electrons or electron-deficient atoms. The correct option is B.

Current is defined as the flow of electrical charge carriers, which are often electrons or electron-deficient atoms. The capital letter 'I' is a typical sign for current. The ampere, denoted by A, is the standard unit.

The relationship between current(I), resistance(R), and voltage(V) is written as:

V = IR

Given circuit has a total resistance of 10 ohms and 30 volts. Therefore, the total current that can be drawn from the circuit is,

30 volts = I × 10 ohms

I = 30/10 amp

I = 3 A

Hence, the correct option is B.

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Answer:

Yes it is possible. Grain size is often determined by the rate so Firstly reduce the average grain diameter of an undeformed alloy specimen form 0.040 mm to 0.10mm

The electronic components that could be used in making of energy saving switch are:​

Transistors as  well as other kinds of semiconductor devices are known to be tools or element that can be used in the making of switches. In its use or applications.

Note that the base or gate of a transistor, based  on the kind of transistor that is known to be in use, and it is one that is often employed as a form of control element to be able to switch on as well as switch off the current that often exist between the emitter as well as the collector or the source and that of the drain.

Note also that the electronic components that are able to  store energy in regards to electronic devices, are known to be capacitors and coils (inductors) and they often play a key function of temporarily saving  energy. One key role of a capacitor is to save an electric charge.

Therefore, The electronic components that could be used in making of energy saving switch are:​

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This statement is true. When working with parallel circuits, each branch provides a separate path for the current to flow.

As a result, even if one part of the circuit is turned off, the current may still be flowing through the other branch(es). This can create a potentially dangerous situation if someone assumes that the entire circuit is de-energized and starts working on it. Therefore, it is possible for current to continue to flow in one part of the circuit even though another part of the circuit is turned off. This can lead to safety hazards, as well as inaccurate measurements or calculations if the current flow is not properly accounted for

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Angular velocity: The rate of change of angular displacement of a body with respect to time is angular velocity. It is de Angular velocity:

Angular velocity is a physical quantity used to describe the rate of change of angular displacement of an object or particle with respect to time. It is measured in radians per second (rad/s) or degrees per second (°/s). The angular velocity is a vector quantity and its direction is perpendicular to the plane of rotation. The magnitude of the angular velocity depends on the rate of change of the angle swept by an object as it rotates about a fixed point. It is commonly used in fields such as physics, engineering, and astronomy to describe the motion of rotating objects or particles. It is also an important parameter for understanding the dynamics of rotating systems and can be used to calculate other physical quantities such as angular acceleration, torque, and moment of inertia.

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Answer:

The mass flow rate of cooling water required to cool the refrigerant is \(123.788\,\frac{kg}{min}\).

Explanation:

A condenser is a heat exchanger used to cool working fluid (Refrigerant 134a) at the expense of cooling fluid (water), which works usually at steady state. Let suppose that there is no heat interactions between condenser and surroundings.The condenser is modelled after the First Law of Thermodynamics, which states:

\(\dot Q_{ref} - \dot Q_{w} = 0\)

\(\dot Q_{ref} = \dot Q_{w}\)

\(\dot m_{ref}\cdot (h_{ref, in} - h_{ref,out}) = \dot m_{w}\cdot (h_{w, out} - h_{w,in})\)

The mass flow rate of the cooling water is now cleared:

\(\dot m_{w} = \dot m_{ref }\cdot \frac{h_{ref,in}-h_{ref,out}}{h_{w,out}-h_{w,in}}\)

Given that \(h_{ref,in} = 808.34\,\frac{kJ}{kg}\), \(h_{ref, out} = 88.82\,\frac{kJ}{kg}\), \(h_{w,out} = 104.83\,\frac{kJ}{kg}\) and \(h_{w,in} = 62.98\,\frac{kJ}{kg}\), the mass flow of the cooling water is:

\(\dot m_{w} = \left(7.2\,\frac{kg}{min} \right)\cdot \left(\frac{808.34\,\frac{kJ}{kg}-88.82\,\frac{kJ}{kg} }{104.83\,\frac{kJ}{kg}-62.98\,\frac{kJ}{kg} } \right)\)

\(\dot m_{w} = 123.788\,\frac{kg}{min}\)

The mass flow rate of cooling water required to cool the refrigerant is \(123.788\,\frac{kg}{min}\).