Blood with oxygen is always sent to the spleen and brain. The spleen serves largely as a blood filter and is located in the upper far left area of the abdomen. Only oxygenated blood is given to it deoxygenated blood is given to the lungs and gills.
Only oxygenated blood enters the spleen. Deoxygenated blood is delivered to the gills and lungs for oxygenation. The hepatic portal system delivers deoxygenated blood to the liver as well.Deoxygenated blood is transformed into oxygenated blood by the lungs. Diffusion occurs in the lungs to oxygenate the blood.The upper left portion of the abdomen, right beneath the rib cage, contains the spleen, a spongy, squishy organ roughly the size of a person's fist. The splenic artery transports blood from the heart to the spleen.To know more about blood with oxygen
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It takes tiffany 0. 25 hours to get to school in the mornings. She lives 4. 5 miles away from the school. At what speed (in miles per hour) is she traveling to get there?.
If It takes Tiffany zero.25 hours to get to school in the mornings. She lives 4.5 miles far away from the faculty, then the speed of traveling off the Tiffany would be 28.96 kilometers per hour.
velocity of touring = general distance traveled by means of the Tiffany / general time
velocity of touring = 4.5 × 1.609 / 0.25
= 28.96 kilometers per hour
Speed in physics is a scalar quantity that refers to the rate at which an object moves, usually expressed in units of meters per second (m/s) or kilometers per hour (km/h). It is defined as the distance an object travels per unit of time, which means that it only takes into account the magnitude of the object's motion and not its direction.
Instantaneous speed refers to the speed of an object at any given moment, while average speed is calculated over a period of time. The speed of an object can be influenced by several factors, such as the forces acting upon it and the medium through which it is moving.
In addition to speed, there are other related concepts in physics, such as velocity, which includes both the speed and direction of an object's motion, and acceleration, which describes the fee at which an item's speed modifications over time.
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Which of the following is NOT a scientific hypothesis?
A. Neon atoms emit red light.
B. There is an attractive force between the earth and moon.
C. Halle Berry is attractive.
D. Summer days are hottest
E. The sky is blue.
The following statement is not a scientific hypothesis:
C. Halle Berry is attractive.
A scientific hypothesis is a proposed explanation for an observation or pattern in nature that can be tested through further investigation and experimentation. It should be testable, falsifiable, and based on evidence.
Neon atoms emit red light. This is a scientific hypothesis that can be tested and confirmed by looking at the spectrum of light emitted by neon atoms.
B. There is an attractive force between the earth and moon. This is a scientific hypothesis that can be tested and confirmed by measuring the force of gravity between the earth and moon.
D. Summer days are the hottest of the year. This is a scientific hypothesis that can be tested and confirmed by collecting temperature data during the summer months.
E. The sky is blue. This is a scientific hypothesis that can be tested and confirmed by observing the sky under different atmospheric conditions.
The statement "Halle Berry is attractive" is a subjective opinion that cannot be tested or confirmed through scientific investigation, hence it is not a scientific hypothesis. Attractiveness, as a concept, can vary widely based on personal, cultural, and social factors.
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How much heat energy must be added to the gas to expand the cylinder length to 16.0 cm ?
This question is incomplete, the complete question is;
A monatomic gas fills the left end of the cylinder in the following figure. At 300 K , the gas cylinder length is 14.0 cm and the spring is compressed by65.0 cm . How much heat energy must be added to the gas to expand the cylinder length to 16.0 cm ?
Answer:
the required heat energy is 16 J
Explanation:
Given the data in the question;
Lets consider the ideal gas equation;
PV = nRT
from the image, we calculate initial pressure;
Pi = ( 2000N/M × 0.06m) / 0.0008 m²
Pi = 15 × 10⁴ Pa
next we find Initial velocity
Vi = (0.0008 m²)(0.14) = 1.1 × 10⁻⁴ m²
now we find the number of moles
n = [(15 × 10⁴ Pa)(1.1 × 10⁻⁴ m²)] / 8.31 J/molK × 300K
N = 6.6 × 10⁻³ mol
next we calculate the final temperature;
Pf = ( 2000N/m × 0.08) / 0.0008 m²
Pf = 2 × 10⁵ Pa
Calculate the final Volume
Vf = (0.0008 m² × 0.16 m = 1.28 × 10⁻⁴ m³
we also determine the final temperature
\(T_{f}\) = (2 × 10⁵ Pa × 1.28 × 10⁻⁴ m³) / 6.6 × 10⁻³ × 8.31 J/molK
\(T_{f}\) = 466.8 K
so change in temperature ΔT
ΔT = 466.8 K - 300K = 166.8 K
we then calculate the change in thermal energy
ΔU = nCΔT
ΔU = ( 6.6 × 10⁻³ mol ) × 12.5 × 166.8K
ΔU = 13.761 J
C is the isochoric molar specific heat which is equal to 3R/2 for monoatomic
now we calculate the work done;
W = 1/2 × K( x\(_{i\\}\)² - x\(_{f\\}\)² )
W = 1/2 × ( 2000 N/m) ( 0.06² - 0.08² )
= - 2.8 J
and we then calculate the heat energy using the following expression;
Q = ΔU - W
we substitute
Q = 13.761 - (- 2.8 J)
Q = 13.761 + 2.8 J)
Q = 16 J
Therefore, the required heat energy is 16 J
find the power of a lift that transfers 450 J of energy in 15 seconds.
Answer: P=30W
Explanation:
formula is p=w/t
p = power
w = work
t = elapsed time
input variables, solve then simplify.
The power of a lift that transfers 450 J of energy in 15 seconds is 30 watts.
Power is defined as the rate of doing work, i.e. the amount of work done per unit time.
Mathematically, it can be represented as follows:
Power = Work done / time taken
Therefore, the power of a lift that transfers 450 J of energy in 15 seconds can be calculated as follows:
Power = Work done / time taken= 450 J / 15 s= 30 W
Therefore, the power of the lift is 30 watts.
To explain further, we know that power is measured in watts (W), and it is the rate at which work is done or energy is transferred.
Here, we are given that the lift transfers 450 J of energy in 15 seconds.
We can find the power of the lift by dividing the amount of work done by the time taken to do it. By substituting the given values, we get the power of the lift as 30 W.
In simple terms, this means that the lift can transfer energy at a rate of 30 joules per second. This can also be interpreted as the lift can do 30 joules of work in one second.
Hence, we can conclude that the power of the lift is 30 watts.
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At a temperature of 300 K, the pressure of the gas in a deodorant can is 3 atm.
Calculate the pressure of the gas when it is heated to 900 K.
The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.
What is the pressure of the gas when it is heated to 900 Kelvin?Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.
It is expressed as;
P₁/T₁ = P₂/T₂
From the data:
Initial pressure P₁ = 3 atmInitial temperature T₁ = 300 KFinal pressure P₂ = ?Initial temperature T₂ = 900 KWe substitute our values into the expression above and solve for final pressure.
P₁/T₁ = P₂/T₂
P₁T₂ = P₂T₁
P₂ = P₁T₂ / T₁
P₂ = ( 3 atm × 900 K ) / 300 K
P₂ = 9.0 atm
Therefore, the final pressure is 9.0 atm.
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Superconducting cables conduct current with no resistance. Consequently, it is possible to pass huge currents through the cables, which, in turn, can produce very large forces. Two straight, parallel superconducting cables 4.5 mm apart (between centers) carry equal currents of 15000 A in opposite directions. Find the magnitude and direction of the force per unit length exerted by one conductor on the other. Should we be concerned about the mechanical strength of these wires
Answer:
Explanation:
Force per unit length between two cables at distance d carrying current I₁ and I₂ can be given by the following expression .
F = 10⁻⁷ x 2I₁ I₂ / d
I₁ = I₂ = 15000 A
F = 10⁻⁷ x 2I₁ I₂ / d
= 10⁻⁷ x 2 x 15000² / 4.5 x 10⁻³ m
= 10000 N .
It will be repelling force ie they will repel each other because current is in opposite direction .
No , we should not be concerned about mechanical strength because force does not depend on it .
Jennifer is walking at 1.63 m\s. If Jennifer weighs 583 N, what is the magnitude of her momentum?
Given that Jennifer is walking at 1.63 m/s and her weight is 583 N. Therefore, the magnitude of her momentum is 96.97 Kg•m/s
How to determine Jennifer's mass Weight (W) = 583 NAcceleration due to gravity (g) = 9.8 m/s²Mass (m) =?
m = W / g
m = 583 / 9.8
m = 59.49 Kg
How to determine Jennifer's momentum Mass = 59.49 KgVelocity = 1.63 m/sMomentum =?Momentum = mass × velocity
Momentum = 59.49 × 1.63
Momentum = 96.97 Kg•m/s
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. The nearest star, Proxima Centauri is 4.0 x 10 km away. Calculate the time it takes light signal from the earth to the star? How many years will it take a spacecraft travelling with speed of 0.0001c to reach Proxima Centauri. (c = 3 x 10 ms).
It would take approximately 1.33 x 10^8 seconds (or about 42 years) for a light signal from Earth to reach Proxima Centauri. For a spacecraft traveling at 0.0001c, it would also take about 42 years to reach Proxima Centauri.
To calculate the time it takes for a light signal to travel from Earth to Proxima Centauri, we can use the formula:
Time = Distance / Speed
Given:Distance to Proxima Centauri = 4.0 x 10^13 km (convert to meters by multiplying by 10^3, as 1 km = 10^3 m)
Speed of light (c) = 3 x 10^8 m/s
Converting the distance to meters:
Distance = 4.0 x 10^13 km * 10^3 = 4.0 x 10^16 m
Using the formula, we can calculate the time it takes for the light signal to travel:
Time = Distance / Speed = (4.0 x 10^16 m) / (3 x 10^8 m/s)
Time ≈ 1.33 x 10^8 seconds
To calculate the number of years it would take for a spacecraft traveling at a speed of 0.0001c to reach Proxima Centauri, we need to divide the distance by the speed of the spacecraft.
Speed of spacecraft (v) = 0.0001c = 0.0001 * 3 x 10^8 m/s = 3 x 10^4 m/s
Time = Distance / Speed = (4.0 x 10^16 m) / (3 x 10^4 m/s)Time ≈ 1.33 x 10^12 seconds
To convert seconds to years, divide the time by the number of seconds in a year:
Number of years ≈ (1.33 x 10^12 seconds) / (3.1536 x 10^7 seconds/year)
Number of years ≈ 42 years
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URGENT: Testing shows that a sample of wood from an artifact contains 50% of the
original amount of carbon-14. Given that the half-life of carbon-14 is 5730
years, how old is the artifact?
O A. 22,920 years
B. 11,460 years
C. 5730 years
O D. 2865 years
Answer:
Im so so sorry but I do now know how to do this
Explanation:
A car travels 20.0 km due north and then 95.0 km in a direction 60.0° west of north, as in Figure 1.15. Find the magnitude and direction of a single vector that gives the net effect of the car's trip. This vector is called the car's resultant disblacement.
Answer:
R = 95 km, 30° west of north
Explanation:
You didn't post a figure, but I think I can picture it.
60 west of north = 30 north of west
sin30 = y/95
y = sin30(95) = 47.5
cos30 = x/95
x = cos30(95) = 82.3
∑y = 20 + 47.5 = 67.5
∑x = 82.3
R² = 82.3² + 47.5² = 9029.54
R = √9029.54 = 95 (magnitude of the Resultant vector)
∅ = tan⁻¹ 47.5/82.3 = 30 north of west
Which line represents an object that is in motion where the acceleration is zero and the velocity is to the north?
Answer:
what do the lines look like
What type of tv uses a VfL for backlighting
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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with an armature resistance of 0.03 2 and a field resistance of
41.67 2. The motor has compensating windings, so armature
reaction can be ignored. Mechanical and core losses may be
assumed to be negligible for the purposes of this problem. The
motor is assumed to be driving a load with a line current of 126 A
and an initial speed of 1103 r/min. To simplify the problem,
assume that the amount of armature current drawn by the motor
remains constant.
A. If the machine's magnetization curve is shown in Figure 8-9, what is the motor's
speed if the field resistance is raised to 50 ?
B. Calculate and plot the speed of this motor as a function of the field resistance RF
assuming a constant-current load.
R₁ = 0.03 2
EA
IA
IF
IL
RF + Radj
LF
+
250 V
A. The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min
A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:
EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.
Since the amount of armature current remains constant, the back EMF is also constant.
Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:
IF = (250 V - EA)/(RF + R₁)
At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.
If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.
Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:
kϕN/IF1 = kϕN/IF2
N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min
Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.
B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:
N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min
where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.
Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.
A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.
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A small car moving at 20 m/sec collides head on with an oncoming large truck moving at 25 m/sec. Which vehicle undergoes the largest change in its momentum
Answer:
The truck will undergo the largest change in momentum if it has a greater mass than the small car.
Explanation:
The change in momentum of an object can be calculated using the equation:
Δp = m * Δv
where Δp represents the change in momentum, m represents the mass of the object, and Δv represents the change in velocity.
Since we are comparing the change in momentum of the car and the truck, we need to consider the masses of both vehicles.
Let's assume the mass of the car is represented by m_car, and the mass of the truck is represented by m_truck.
Since both vehicles collide head-on, the change in velocity (Δv) will be the difference between their initial velocities, considering that they are moving in opposite directions:
Δv = v_truck - v_car
Now, let's compare the change in momentum for the car and the truck:
For the car:
Δp_car = m_car * Δv
For the truck:
Δp_truck = m_truck * Δv
Comparing the magnitudes of the change in momentum, we can neglect the negative sign:
|Δp_car| = |m_car * Δv|
|Δp_truck| = |m_truck * Δv|
Since both Δv and Δp are positive values, we can conclude that the vehicle with the greater mass will undergo the largest change in its momentum.
Therefore, if the mass of the truck (m_truck) is greater than the mass of the car (m_car), then the truck will undergo the largest change in its momentum. Conversely, if the mass of the car is greater, then the car will undergo the largest change in its momentum.
Suppose that a series RL circuit is connected to a voltage source whose input voltage (Vin) is shown in the figure above. As shown in the figure above, the input voltage Vin = Vmax only within time interval 0 ≤ t ≤ T. The input voltage Vin = 0 outside this time interval. Assume that initially (at t = 0), no current is flowing in this circuit (I = 0)! A Determine the output voltage Vout as a function of time t! B Assume that the time interval T is very short so that T → 0, and also assume the the maximum voltage Vmax is quite high, so that VmaxT ≈ Φimp. Show that the output voltage Vout can be approximated by the following equation : Vout(t) ≈ Φimp τ e −t/τ where τ = L R
A. The output voltage, Vout, as a function of time, t, in a series RL circuit can be determined using the equation: Vout(t) = Vmax * (1 - e^(-t/τ)), where τ = L/R.
B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can approximate the output voltage Vout using the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.
A. To determine the output voltage Vout as a function of time t in a series RL circuit, we use the following equation:
Vout(t) = Vmax * (1 - e^(-t/τ))
Here, Vmax is the maximum input voltage, τ = L/R is the time constant of the circuit (where L is the inductance and R is the resistance).
B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can make the following approximation:
Vout(t) ≈ Vmax * e^(-t/τ)
In this case, we substitute VmaxT with Φimp, which is the total magnetic flux in the circuit.
Rearranging the equation, we get:
Vout(t) ≈ Φimp * e^(-t/τ)
This approximation is valid when the time interval T is very small compared to the time constant τ of the circuit and when the maximum voltage is sufficiently high.
The time constant τ is determined by the values of inductance (L) and resistance (R) in the circuit. It represents the characteristic time scale over which the current and voltage in the circuit change in response to a voltage or current input.
Therefore, in the given scenario, when T is very small and Vmax is high, we can approximate the output voltage Vout(t) in the series RL circuit by the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.
Note: The symbol Φimp in the equation represents the total magnetic flux in the circuit.
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When you think about and describe the characteristics of a giraffe, what type of model are you using?
Answer:
The giraffe is the tallest of all mammals. It reaches an overall height of 18 ft (5.5 m) or more. The legs and neck are extremely long. The giraffe has a short body, a tufted tail, a short mane, and short skin-covered horns
The efficiency of combine double pulley is 60% How much load is lifted usin SON effort I
The load lifted by the double pulley with the given efficiency and applied effort is determined as 30 N.
What is the amount of load lifted?The amount of load lifted by the pulley is calculated by applying the formula for efficiency of a machine as follows;
E = L / E x 100%
where;
L is the load overcome or output workE is the effort applied or the input workThe amount of load lifted by the pulley is calculated as;
60 = L / 50 x 100%
60 = 100L / 50
100L = 50 x 60
100 L = 3000
L = 3000 / 100
L = 30 N
Thus, the amount of load lifted by the pulley is 30 N.
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The complete question is below:
the efficiency of combine double pulley is 60%. how much load is lifted using 50n effort?
Which digits in a measurement are always significant? Check all that apply.
zeros to the left of the decimal point
zeros between nonzero numbers
zeros to the right of the decimal point
nonzero numbers
zeros to the right of both the decimal point and a nonzero number
O zeros to the left of both the decimal point and a nonzero number
Answer:
zeros between nonzero numbers
nonzero numbers
zeros to the right of both the decimal point and a nonzero number
Explanation: edge 2020
How much work is it to push a box (mass 150 kg) up an incline (angle 15 degrees with the horizontal) that is 8.1 meters long, if the coefficient of kinetic friction between the box and the incline is 0.4
Given that,
Mass of a box, m = 150 kg
It is pushed at an angle of 15 degrees with the horizontal.
It is 8.1 m long.
The coefficient of kinetic friction between the box and the incline is 0.4
To find,
The work done in pushing the box.
Solution,
First let's see the net force acting on the box.
\(F_{net}=mg\sin\theta+f_k\\=mg\sin\theta+\mu_k mg\cos\theta\)
Work done is given by :
W = force × displacement
\(W=(mg\sin\theta+\mu_k mg\cos\theta)\times s\\\\=150\times 10(\sin15+8.1\times \cos15)\times 8.1\\\\=98206.24\\\\or\\\\=98.2\ kJ\)
So, the required work done is 98.2 kJ.
Which statement best describes how resources are distributed?
according to it's nature
. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)
a}The work is done by the piston in the process is 199 cal.
b) The increase in internal energy of the gas is 703 cal
c) The heat was supplied to the gas is 3771 J
(a) To calculate the work done by the piston, we can use the formula:
Work = P * ΔV
Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:
Work = P * (\(V_2 - V_1\))
Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:
PV = nRT
\(V_1 = (nRT_1) / P_1\)
\(V_2 = (nRT_2) / P_2\)
Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).
Substituting the values into the equation, we have:
V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal
V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal
Therefore, the work done by the piston is:
Work = 1 atm * (796 cal - 597 cal) = 199 cal
(b) The increase in internal energy of the gas can be calculated using the equation:
ΔU = n * C * ΔT
Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).
Substituting the values into the equation, we have:
ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal
(c) The heat supplied to the gas can be calculated using the equation:
Q = ΔU + Work
Substituting the values calculated in parts (a) and (b), we have:
Q = 703 cal + 199 cal = 902 cal
Since 1 cal = 4.184 J, the heat supplied to the gas is:
Q = 902 cal * 4.184 J/cal ≈ 3771 J
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Which statements are inconsistent with Dalton’s atomic theory as it was originally stated? Why?
a. All carbon atoms are identical.
b. An oxygen atom combines with 1.5 hydrogen atoms to form a water molecule.
c. Two oxygen atoms combine with a carbon atom to form a carbon dioxide molecule.
d. The formation of a compound often involves the destruction of one or more atoms.
Statement b and d are inconsistent with Dalton's atomic theory.
Dalton's atomic theory, as originally stated, includes the following postulates:
All matter is made up of tiny, indivisible particles called atoms.
All atoms of a given element are identical in mass and properties.
Compounds are formed when atoms of different elements combine in fixed ratios.
Chemical reactions involve the rearrangement of atoms; no atoms are created, destroyed or changed into atoms of another element.
Statement b contradicts postulate 3 by suggesting that a water molecule is formed from 1.5 hydrogen atoms and 1 oxygen atom. However, in Dalton's theory, atoms combine in whole-number ratios to form compounds.
Statement d contradicts postulate 4 by suggesting that the formation of a compound involves the destruction of one or more atoms. However, in Dalton's theory, atoms are neither created nor destroyed in chemical reactions. Instead, they are rearranged to form new compounds.
Statement a and c are consistent with Dalton's atomic theory as all atoms of a given element are identical in mass and properties and compounds are formed when atoms of different elements combine in fixed ratios.
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7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.
The tension in the strings are 31.47 and 19.25 N respectively.
Mass of the block, m = 3 kg
From the figure, consider the vertical components,
T₁ sin45° + T₂ sin30° = mg
(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4
Also, consider the horizontal components,
T₁ cos45° = T₂ cos30°
T₁/√2 = T₂ x√3/2
T₁ = T₂ x √3/2 x √2
So,
T₁ = 0.612T₂
Applying in the first equation,
(T₁/√2) + (T₂/2) = 29.4
(0.612T₂/1.414) + 0.5T₂ = 29.4
0.434 T₂ + 0.5 T₂ = 29.4
0.934 T₂ = 29.4
Therefore, the tension,
T₂ = 29.4/0.934
T₂ = 31.47 N
So, the tension,
T₁ = 0.612 T₂
T₁ = 0.612 x 31.47
T₁ = 19.25 N
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Help please ( with out links ).
2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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A 1.0 m string with a 5 g stopper on the end is whirled in a vertical circle. The speed of the stopper is 8 m/s at the top of the circle. (A) What is the speed of the stopper at the bottom of the circle? (HINT: Use energy conservation principles!) (10.2 m/s) (B) What is the tension in the string when the stopper is at the top of the circle? (0.27 N) (C) What is the tension in the string when the stopper is at the bottom of the circle?
Answer:
Explanation:
A )
At the bottom of the circle , the potential energy of the stopper is converted into kinetic energy
1/2 m V² = mg x 2r + 1/2 mv²
m is mass of stopper , V is velocity at the bottom , r is radius of the circular path which is length of the string , v is velocity at the top
1/2 V² = g x 2r + 1/2 v²
V² = g x 4r + v²
V² = 9.8 x 4 + 8²
V² = 103.2
V = 10.16 m/s
B )
If T be the tension at the top
Net downward force
= mg + T . This force provides centripetal force for the circular motion
mg +T = mv² / r
T = mv²/r -mg
= m ( v²/r - g )
= .005 ( 8²/1 -g )
= .005 x 54.2
= .27 N .
C ) At the bottom
Net force = T - mg , T is tension at the bottom , V is velocity at bottom
T-mg = mV²/r
T = m ( V²/r +g )
= .005 ( 10.16²/1 +9.8)
= .005 x 113
= .56 N .
4. A tankful of liquid has a volume
of 0.2m3. What is the volume in (a)
lities (b) cm3 (c)ml
Explanation:
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A cat that weighs 4 kilograms is moving at a velocity of 1 m/s. What is the kinetic energy?
The kinetic energy of the cat is 2 joules (J).
The kinetic energy of an object can be calculated using the formula KE = 1/2 * mass * velocity^2.
The kinetic energy of an object can be calculated using the formula:
Kinetic Energy (KE) = 0.5 * mass * velocity^2
In this case, the mass of the cat is 4 kilograms, and its velocity is 1 m/s. Plugging these values into the formula:
KE = 0.5 * 4 kg * (1 m/s)^2
Simplifying the equation:
KE = 0.5 * 4 kg * 1 m^2/s^2
KE = 0.5 * 4 kg * 1
KE = 2 kg
Therefore, the kinetic energy of the cat is 2 joules (J).
Kinetic energy is the energy possessed by an object due to its motion. In this case, the cat's kinetic energy is determined by its mass and velocity. The formula for kinetic energy demonstrates that it is directly proportional to the mass and square of the velocity. As the mass increases, the kinetic energy also increases. Similarly, as the velocity increases, the kinetic energy increases exponentially.
In this example, the cat's kinetic energy is relatively low due to its mass and velocity values. If the cat were moving at a higher velocity or had a greater mass, the kinetic energy would be significantly higher. Kinetic energy is an important concept in understanding the energy associated with moving objects and is utilized in various fields such as physics, engineering, and sports science.
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Based on the diagram, which statement explains how energy is conserved
during this chemical reaction?
A
Reaction progress
Potential energy
of a system
B
OA. The potential energy lost by the reaction system (B) is gained by
the surroundings.
B. The potential energy lost by the reaction system (C) is also lost by
the surroundings.
← PREVIOUS
OC. The potential energy changes indicated by C and B involve energy
lost by the surroundings.
The potential energy changes indicated by C and B involve energy lost by the surroundings. Therefore, option B is correct.
Potential energy is the energy possessed by an object due to its position or condition. It is often associated with the potential for the object to do work or undergo a change. The concept of potential energy arises from the interactions between objects or within a system.
Potential energy is converted into other forms of energy, such as kinetic energy (energy of motion) when the object or system undergoes a change or is acted upon by external forces.
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Your question is incomplete, most probably the correct answer is this:
Based on the diagram, which statement explains how energy is conserved during this chemical reaction? (A) is also gained by the surroundings. B. The potential energy changes indicated by C and B involve energy lost by the surroundings. C. The potential energy lost by the reaction system (C) is also lost by the surroundings. D. The potential energy lost by the reaction system (B) is gained by the surrounding
Lana's class is studying the various kinds of energy found on a playground
Which of the following would be the BEST way to test for an equal transformation of energy on a playground?
СА
Using the slide, Lana could measure her kinetic energy when she was climbing up the ladder, measure her potential energy before she slid down, and her total energy used at the bottom of the slide. If the amount of potential
energy and kinetic energy added up to equal the total amount of energy used, it would show an equal transformation of energy
OB
Using the slido, Lana could measure her potential and kinetic energy sitting at the top of the slide, and then she could measure her kinetic and potential energy at various points while sliding to the bottom of the total value of
her potential energy and her kinetic energy were equal at every measuremont, it would show that there had been an equal transformation
C
Using the swing, Lana could measure her potential energy when she was sitting still on the swing, and she could measure her kinetic energy when the swing was in motion. If the kinetic energy was twice the amount of her
potential energy, it would show there had boon an equal transformation of potential energy to kinetic energy
D
Using the soesaw, Lana could measure her potential energy when she was in motion, and she could measure her kinetic energy when she was resting. If her kinetic and potential energy were equal, it would show that there
had been an equal transformation
If the amount of potential energy and kinetic energy added up to equal the total amount of energy used, it would show an equal transformation of energy.
What is Energy?This can be defined as the ability or capacity to do work. The potential and kinetic energy equals the total amount of energy involved when Lana was on the playground.
This depicts an equal transformation of energy which is why the most appropriate choice in this scenario is option A.
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