p12. the magnitude of the dipole moment associated with an atom of iron in an iron bar is 2.1 x 10-23 j/t. assume that all the atoms in the bar, which is 5.0 cm long and has a cross sectional area of 1.0 cm2 , have their dipole moments aligned. (a) what is the dipole moment of the bar? (b) what torque must be exerted to hold this magnet perpendicular to an external field of magnitude 1.5 t? (the density of iron is 7.9 g/cm3 .)

The vector of the bucket is a force of 47.4 pounds acting at an angle of 39 degrees with the horizontal.

To find the vector of the bucket, we need to first calculate the net force acting on it. This can be done by resolving the given forces into their horizontal and vertical components and then adding them up.

1. Resolving Jill's force:

Jill pulled at an angle of 30 degrees with a force of 20 pounds. We can resolve this into its horizontal and vertical components as follows:

Horizontal component = 20 cos(30)

= 17.32 pounds

Vertical component = 20 sin(30)

= 10 pounds

2. Resolving Jack's force:

Jack pulled at an angle of 45 degrees with a force of 28 pounds.

We can resolve this into its horizontal and vertical components as follows:

Horizontal component = 28 cos(45)

= 19.8 pounds

Vertical component = 28 sin(45)

= 19.8 pounds

3. Adding up the components:

To find the net horizontal and vertical components, we can add up the horizontal and vertical components of the two forces as follows:

Net horizontal component = 17.32 + 19.8

= 37.12 pounds

Net vertical component = 10 + 19.8

= 29.8 pounds

4. Finding the vector:

Now that we have the net horizontal and vertical components, we can use the Pythagorean theorem to find the magnitude of the vector as follows:

Magnitude = sqrt((37.12)^2 + (29.8)^2)

= 47.4 pounds

Finally, we need to find the direction of the vector. We can use trigonometry to find this as follows:

Tanθ = Net vertical component / Net horizontal component = 29.8 / 37.12θ

= tan^-1(29.8 / 37.12)

= 39 degrees (approx.)

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Answer:

kinetic

Explanation:

Answer:

medium

Explanation:

A substance or particle that wave travel through is called medium. There are two main types of such medium, some contains particles and some are vacuums.

Answer:

If the charges have the same sign, so that qsqt>0, then the potential energy decreases as the charges separate; if the charges have opposite sign, the potential energy increases from negative infinity.

Explanation:

I hope this answered your question!

The space probe launched in 2012 with 2.0 kg of plutonium-238 (238Pu) is utilized for thermoelectric power sources in spacecraft.

Plutonium-238 (238Pu) is an isotope of plutonium that undergoes radioactive decay, emitting heat in the process.

This unique property makes it an ideal choice for generating power in space missions where sunlight is limited, such as deep space probes or missions to distant planets. The heat produced by the radioactive decay of 238Pu is converted into electricity using thermoelectric materials.

In the context of the space probe launched in 2012, the 2.0 kg of 238Pu serves as the fuel for the thermoelectric power source.

The heat generated by the decay of the plutonium is harnessed to produce electricity through the Seebeck effect.

Thermocouples, made from two dissimilar materials, are used to create a temperature gradient. As the heat flows across the junction of the thermocouple, it creates a voltage difference that can be utilized to power the spacecraft's instruments, systems, and communication devices.

The use of 238Pu as a power source offers several advantages for space missions.

Unlike solar panels, which are dependent on sunlight, thermoelectric generators powered by plutonium-238 can operate in deep space or in regions where solar energy is insufficient.

This is particularly crucial for missions that venture beyond the orbit of Mars or explore dark, shadowed areas where sunlight is scarce.

Additionally, the longevity of 238Pu's decay heat allows for prolonged power generation, ensuring continuous operation and data transmission over long-duration missions.

Plutonium-238 (238Pu) is a scarce and highly valuable resource due to its applications in space exploration. It is primarily produced through the irradiation of neptunium-237 in nuclear reactors.

The production and handling of 238Pu require strict safety measures due to its high radioactivity. Furthermore, the dwindling global supply of 238Pu has posed challenges for future space missions relying on this isotope.

The development of alternative power sources and the search for innovative ways to produce and utilize plutonium-238 remain areas of active research in the field of space exploration.

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Molded-case circuit breaker is type of circuit breaker is the most prevalently used for 15-ampere to 2,500-ampere systems.

The molded-case circuit breaker uses electromechanical (thermal magnetic) trip units . It provides protection by using a temperature sensitive device with a current sensitive electromagnetic device. Both these devices on the trip mechanism.

A molded case circuit breaker is a type of electrical protection device that can be used for a wide range of voltages and frequencies.  

The wide range of current ratings available from molded-case circuit breakers allows them to be used in a wide variety of applications. MCCBs ranges from 15 amperes to 2500 amperes .This allows them to be used in both low-power and high-power applications.

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Answer:

5Hz

Explanation:

Frequency = No. of waves per second

10 waves are produced in 2 seconds

in one second 10/2 waves are produced

(ie) 5 waves are produced in 1 second

Therefore the frequency of wave is 5 Hz

The comparison of two quantities by division of two similar quantities is called ratio and proportion and the given statement is true.

A ratio is a way of comparing amounts. A ratio shows the number of times an amount is contained in another, or how much bigger one amount is than another.

The two numbers are both parts of the whole, If I need to mix some cement, then I could add two parts cement to four parts sand. Hence the ratio 2:4 (6 parts in total). The written bis important; 4:2 would give a different mix.

Ratios are written to their simplest form. In the figure to the right we have 15 red dots and five green dots. The ratio is 15:5; however, this can be reduced to the simplest form as we do with fractions.

The ratio as we can see in the graphic is also 3:1, if you look at the relationship of the numbers 15:5 as is 3:1, we can see that 3 is multiplied by 5 to get 15 and so is the one to get five.

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The acceleration of the block is 6.4 m/s².

To calculate the acceleration of the block, we need to consider the forces acting on it.

The applied force is 40 N, and since it is the only horizontal force in the direction of motion, it is the net force acting on the block.

The frictional force opposing the motion is 8 N.

The acceleration, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).

The net force is the difference between the applied force and the frictional force:

40 N - 8 N = 32 N.

Now, we can plug the values into Newton's second law:

32 N = 5 kg × a.

Solving for the acceleration (a), we get

a = 32 N / 5 kg

a = 6.4 m/s².

Therefore, the acceleration of the block is 6.4 m/s².

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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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A kilowatt hour is a unit of d) energy.

A kilowatt hour (kWh) is a unit of energy, which is commonly used to measure the amount of energy consumed by electrical devices over time. One kilowatt hour is equivalent to the energy consumed by a 1,000-watt device operating for one hour.

It is not a unit of current, voltage, or resistance, which are all measures of the properties of the electrical system itself, rather than the energy being used. Kilowatt hours are used by utilities to measure the amount of electricity consumed by households and businesses, and are often used to calculate electricity bills.

In summary, a kilowatt hour is a measure of the amount of energy consumed, and is an important concept in understanding electricity usage and costs. So a kilowatt hour is a unit of d) energy.

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Answer:

1476 J

Explanation:

From the question,

Net Work done = Net force× distance moved by net force.

W' = (F-F')×d................... Equation 1

Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.

Given: F = 150 N, F' = 37 N, d = 12 m

Substitute these values into equation 1

W' = (150-37)×12

W' = 123×12

W' = 1476 J.

hence the Net Work done by the object is 1476 J

Answer:

Gases move from high-pressure areas to low-pressure areas. And the bigger the difference between the pressures, the faster the air will move from the high to the low pressure. That rush of air is the wind we experience.

Explanation:

The magnitude of the external magnetic field is approximately 0.194 Tesla.

To solve this problem, we can use the equation for the magnetic force on a current-carrying wire:

F = BILsinθ

where F is the magnetic force, B is the magnitude of the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

Given:

Length of the wire, L = 0.19 m

Current, I = 7.6 A

Angle, θ = 17°

Force, F = 6.2 x \(10^{-3}\)N

Substituting the given values into the equation, we have:

6.2 x \(10^{-3}\) N = B * 0.19 m * 7.6 A * sin(17°)

Simplifying the equation, we can solve for B:

B = (6.2 x \(10^{-3}\) N) / (0.19 m * 7.6 A * sin(17°))

Calculating this expression, we find:

B ≈ 0.194 T

Therefore, the magnitude of the external magnetic field is approximately 0.194 Tesla.

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Answer: In the Physics models, we do not take into account the energy change by the friction of moving components

Explanation:

In order to use GPS, four satellites are needed to calculate a location's latitude and longitude.

The receiver must account for the effects of the ionosphere and troposphere, which can cause delays in signal transmission or variations in signal speed. Using information on the distances to three satellites and the location of the satellite at the moment the signal was transmitted, the receiver may determine its own three-dimensional position. An atomic clock that is synchronized to GPS is required to calculate distances from these three signals. Nevertheless, the receiver eliminates the need for an atomic clock by getting a readout from a fourth satellite. The receiver uses four satellites to calculate latitude, longitude, altitude, and time.

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The self inductance can be calculated as 4.444 Henry.

The inductor will store energy = 20 joule,

current = 3 ampere.

     The current carrying conductor which allows or opposes the change of flow of current is known as self-inductance. The rate of change of current can also be given through self inductance.

Formula can be given  for the energy in the inductor as,

                      E = 1 / 2 × L × I² joule.

where as,    E - Energy

                    L - Inductance

                    I - Current flowing through the coil.

The equation can be rearranged as,

                      L =  2 E/ I²

                         =  2 × 20 / 3²

                         =  40 / 9

Hence,           L =  4.4444 Henry

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Answer:

Energy conversion

Explanation:

We regularly use automobile which runs on the chemical energy of the fuels such as diesel and petrol, the chemical energy from the fuel would convert into the thermal energy which is used to drive the engine of the vehicle,further the thermal energy converted into the mechanical energy which is used to drive the prime mover of the automobile.

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

We frequently utilize vehicles that operate on chemical energy from fuels like diesel and gasoline.

This chemical energy is transformed into thermal energy, which drives the engine of the vehicle, and then mechanical energy, which drives the prime mover of the vehicle.

Thus, we can say that the transfers and transformations of energy are necessary to operate the technology.

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Answer:

Mitochondria and plastids are the two organelles that contain their own genetic material. Both these organelles have their own DNA and ribosomes.

A star's location on the main sequence is primarily determined by its mass. The main sequence is a prominent region on the Hertzsprung-Russell (H-R) diagram where the majority of stars reside.

This diagram plots the luminosity (or absolute magnitude) of stars against their surface temperature (or spectral class). Stars on the main sequence are in a stable state of hydrogen fusion, where they convert hydrogen into helium in their cores, releasing energy in the process.

The mass of a star directly influences its position on the main sequence. Stars with higher masses have greater gravitational forces and, therefore, higher core temperatures and pressures. These higher temperatures and pressures enable more efficient hydrogen fusion and result in greater luminosity. Consequently, more massive stars are located at the upper end of the main sequence and are typically hotter and more luminous.

On the other hand, less massive stars have lower core temperatures and pressures, leading to less efficient hydrogen fusion and lower luminosity. These stars are located at the lower end of the main sequence and tend to be cooler and less luminous.

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Answer:527 m

Explanation:

The displacement or distance travelled by the airplane during the given period is 526.5m

Given the data in the question;

constant acceleration; \(a = 3.0m/s\)

Initial velocity; \(u = 21m/s\)

Final velocity; \(v = 60m/s\)

Displacement or distance; \(s = ?\)

To find the displacement or distance the plane has travelled during the given period, we use the Third Equation of Motion:

\(v^2 = u^2 + 2as\)

Where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement.

Lets make "s" the subject of the formula

\(s = \frac{v^2-u^2}{2a}\)

We substitute our given values into the equation

\(s = \frac{(60m/s)^2 - (21m/s)^2}{2 \ *\ 3m/s^2} \\\\s = \frac{(3600m^2/s^2) - (441m^2/s^2)}{6m/s^2}\\\\s = \frac{3159m^2/s^2}{6m/s^2}\\\\s = 526.5m\)

Therefore, The displacement or distance travelled by the airplane during the given period is 526.5m  

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The angle theta (θ) is a geometric angle that can have a value in the range of 0 to 360 degrees or 0 to 2π radians, depending on the unit of measurement used.

The angle theta (θ) is a geometric angle that can have a value in the range of 0 to 360 degrees or 0 to 2π radians, depending on the unit of measurement used. This is because a full circle contains 360 degrees or 2π radians, and any angle can be expressed as a multiple of this full circle.

When measuring angles in degrees, the range of theta is typically given as 0 ≤ θ ≤ 360 degrees. This means that theta can take on any value between 0 degrees and 360 degrees, inclusive.

When measuring angles in radians, the range of theta is typically given as 0 ≤ θ ≤ 2π radians. This means that theta can take on any value between 0 radians and 2π radians, inclusive.

It's worth noting that angles can also have negative values or values greater than 360 degrees or 2π radians, but these are typically considered to be outside the standard range of theta.

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Answer:

A

Explanation:

if its wronge im so sorry

The effective value of g, the acceleration of gravity, at 6700m , above the Earth's surface is 9.79 m/s².

Given:

G=gravitational constant = 6.67x10⁻¹¹ m³/(kg.s²)

M=the Earth's mass = 5.97x10²⁴ kg

r=  Earth's radius = 6371 km  +6700m

r=6371000m+6700m

r=6377700m

For gravitation we use following:

F=GmM/r^2

which on further derivation gives

ma=GmM/r^2 , which results in

a=GM/r^2

Now putting the values in a=GM/r^2

a=6.67x10⁻¹¹ m³/(kg.s²)*5.97x10²⁴ kg/6377700^2

a=9.79 m/s²

Hence, The effective value of g, the acceleration of gravity, at 6700m , above the Earth's surface is 9.79 m/s².

then at 7000km i.e. 7000000m

All will be same except r= 6371000m+7000000m

r=13371000m and

r^2 =1.78*10^14.

putting values

a=6.67x10⁻¹¹ m³/(kg.s²)*5.97x10²⁴ kg/1.78*10^14.

a=2.23*10^28 m/s.

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Answer:

thrust

Explanation:

Answer:

thrust

Explanation:

Answer:

400m

Explanation:

distance = speed x time

20 x 20

=400m

Answer:

jumping, pulling a elastic band, bouncing a ball

Explanation:

when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.

When we pull an elastic band, it automatically returns to its original position. The more you pull the more force it generates. This is the same when you pull or compress a spring. The action (applied force) is stored as energy and is released as a reaction with an equal and opposite force

A ball is able to bounce because of the reaction from the ground. If there was no reaction then the ball would not bounce but rather stick to the ground.

Answer:

1. Amplitude.

2. Rarefaction.

3. Wavelength.

4. Compression.

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission. Some of the properties of sound waves as it travels through a medium such as solid, liquid and gas includes the following;

1. Amplitude: the density of the medium's particles at the compressions of the waves.

2. Rarefaction: the part of a wave where the particles of the medium are farther apart. This ultimately implies that, it is part of a longitudinal wave in which the particles that make up the matter for the movement of the wave are separated by a greater distance.

3. Wavelength: the distance between compressions or rarefactions i.e the distance between two successive compressions or refractions.

4. Compression: the part of a wave where the particles of the medium are closer together. This ultimately implies that, it is part of a longitudinal wave in which the particles that make up the matter for the movement of the wave are closer together.

Answer:

here is the answers .......