"Part B? Question
The total resistance in a circuit with two parallel resistors is 2 ohms and $R_1$ is 6 ohms. Using the equation for R₂, in terms of Rt and R₁, what is R₂ ?
R₂ is ohms."

In soccer, when a foul is committed by a member of the opposing team, the opposing team is awarded various types of kicks depending on the location of the foul.

Goal Kick: A goal kick is awarded to the defending team when the attacking team last touched the ball before it went out of bounds over the goal line, either on the ground or in the air, and not scoring a goal. It is taken from within the defending team's goal area. A goal kick does not result in any points for either team.

Free Kick: A free kick is awarded to the team that was fouled. The location of the free kick depends on the severity and location of the foul. If the foul occurred within the opposing team's penalty area, a penalty kick may be awarded, which is taken from the penalty spot, 12 yards away from the goal line.

The opposing team must be at least 10 yards away from the ball. Points can be scored directly from a free kick if the ball is kicked into the opponent's goal without touching any other player. The number of points scored depends on the rules of the competition but is typically counted as one goal.

Drop Kick: A drop kick is not typically awarded as a result of a foul. It is a type of restart used to begin or resume play after a stoppage, such as a goal being scored or a halftime break. The player drops the ball and kicks it just after it touches the ground. Points can be scored if the ball crosses the opponent's goal line and into the goal.

Corner Kick: A corner kick is awarded to the attacking team when the ball goes out of bounds over the goal line, with the defending team being the last to touch it. The kick is taken from the corner nearest to where the ball went out of play. Points can be scored directly from a corner kick if the ball is kicked into the opponent's goal without touching any other player.

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A unit load of not less than 1/4 volt-amperes per square foot is included for storage spaces other than dwelling units.

The unit load can be described as the size of an assemblage into which a number of items are combined for ease of storage and handling, for example, a pallet load expresses a unit load that can be moved easily with a pallet jack, or a container load expresses a unit for shipping purposes.

A unit load can pack tightly into a warehouse rack, truck, or intermodal container, yet can be broken apart at a distribution point, generally a distribution center, or wholesaler, for sale to consumers or for use.

A unit load can be defined as the basic storage and transport unit arranged on modular support or in packaging to ensure efficient handling.

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Answer:

v₃ = 1.25[m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of the amount of movement and momentum.

That is, the amount of movement is preserved before and after the collision. Let's propose an equation, in which the elements to the left of the equal sign represent the moment before the collision and to the right the moment after the collision.

\(P=m*v\)

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

\((m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}\)

m₁ = mass of the first railroad = 2096 [kg]

m₂ = mass of the second railroad = 6280 [kg]

v₁ = velocity of the first railroad before the collision = 5 [m/s]

v₂ = velocity of the second railroad before the collision = 0 (initially at rest)

v₃ = velocity of the group after the collision [m/s]

Now replacing:

\((2096*5)+(6280*0)=(2096+6280)*v_{3}\\10480=8376*v_{3}\\v_{3}=1.25[m/s]\)

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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a. Her x position at t = 0.80 s is 0.0832 m

b. Her y position at t = 0.80 s is -28.8 m

c. Her x velocity component at t = 0.80s is 2.08 m/s

d. her y velocity component at t = 0.80s is -3.6 m/s

Since the skateboarder travels on a horizontal surface with an initial velocity of 3.6 m/s toward the south and a constant acceleration of 2.6 m/s² toward the east.

Now since she starts from the origin, to find her x position after 0.80 s, using the equation of motion for the x - components of motion,

x = ut + 1/2at² where

So, substituting the values of the variables into the equation, we have

x = ut + 1/2at²

x = 0 m/s × 0.8 s + 1/2 × 2.6 m/s² × (0.8 s)²

x = 0 m + 1.3 m/s² × 0.64 s²

x = 0 m + 0.832 m

x = 0.832 m

So, her x position at t = 0.80 s is 0.0832 m

Using the equation of motion for her y - components of motion, her y position is y = ut + 1/2at² where

So, substituting the values of the variables into the equation, we have

y = ut + 1/2at²

y = -3.6 m/s × 0.8 s + 1/2 × 0 m/s² × (0.8 s)²

y = -3.6 m × 0.8 s + 0

y = -28.8 m

So, her y position at t = 0.80 s is -28.8 m

Using the equation of motion for her x - component of motion, her x velocity compoent after t = 0.8 s is

v = u + at where

So, we have

v = u + at

v = 0 m/s + 2.6 m/s² × 0.8 s

v = 0 m/s + 2.08 m/s

v = 2.08 m/s

So, her x velocity component at t = 0.80s is 2.08 m/s

Using the equation of motion for her y - component of motion, her xyvelocity compoent after t = 0.8 s is

v = u + at where

So, we have

v = u + at

v = -3.6 m/s + 0 m/s² × 0.8 s

v = -3.6 m/s + 0 m/s

v = -3.6 m/s

So, her y velocity component at t = 0.80s is -3.6 m/s

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The tension in spring A is T = W/(2cosθ)

Tension is the stretching force in a spring.

Let

Resolving the tension in each spring vertically, so we can have that

Now the vertical component of the tension in each equals the weight. So, we have that

Tcosθ + Tcosθ = W

Adding them together, we have that

2Tcosθ = W

Dividing both sides by 2cosθ, so, we can have that

T = W/2cosθ

Thus, the tension in each spring is T = W/(2cosθ)

So, the tension in spring A is T = W/(2cosθ)

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The final velocity of the red ball is 18 m/s.

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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Answer:

Resistance in circuit = 0.53 ohm (Approx.)

Explanation:

Given:

Flow of current in circuit = 15 amp

Potential difference = 8 Volts

Find:

Resistance in circuit

Computation:

In an electrical system, resistance is a stopper of a material to electric current.

Resistance in circuit = Potential difference / Flow of current in circuit

Resistance in circuit = 8 / 15

Resistance in circuit = 0.53 ohm (Approx.)

Answer:

(a) 102 cm/s

(b) 0.490 cm²

Explanation:

(a) Use Bernoulli equation.

P₁ + ½ ρ v₁² + ρgh₁ = P₂ + ½ ρ v₂² + ρgh₂

0 + ½ ρ v₁² + ρgh₁ = 0 + ½ ρ v₂² + 0

½ ρ v₁² + ρgh₁ = ½ ρ v₂²

½ v₁² + gh₁ = ½ v₂²

½ (25.0 cm/s)² + (980 cm/s²) (5.00 cm) = ½ v²

v = 102 cm/s

(b) The flow rate is constant.

v₁ A₁ = v₂ A₂

(25.0 cm/s) (2.00 cm²) = (102 cm/s) A

A = 0.490 cm²

Answer:

a. The acceleration would increase.

Explanation:

because we know that

F=ma

m= mass and a= acceleration

so Mass is same for the cart in any situation that's why only acceleration could increase.

Answer:

A

Explanation:

because when the cart is pushed at 10N it at 5.0 the when u increase the N it will keep on increasing...

The sum of the currents through all the branches in the parallel circuit is 0.3 A.

A parallel circuit is a type of circuit which comprises branches so that the current divides and only part of it flows through any branch.

The voltage, or potential difference, across each branch of a parallel circuit is the same, but the currents may vary.

The sum of the current flowing in any branch of a parallel circuit is determined by applying Ohms law as follows;

I = V/R₁ + V/R₂ + V/R₃

where;

Thus, If the current leaving the cell in a parallel circuit is 0.3 A, then it implies that the resultant current or total current in the parallel circuit is 0.3 A.

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The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

68.5 meters

Explanation:

To solve this problem, we can use trigonometry and create a right triangle with the river as the hypotenuse.

Let's call the width of the river "w". We can use the sine function to find the length of the opposite side of the triangle (the distance from the surveyor to the tree).

sin(33.4°) = opposite/hypotenuse

sin(33.4°) = w/x

w = x * sin(33.4°)

w = 118 m * sin(33.4°)

w = 68.5 m

Therefore, the width of the river is approximately 68.5 meters.

The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Given :

One particle, of mass m , moves with a speed v in the x-direction, and another particle, of mass 2 m , moves with a speed v/2 in the y-direction.

To Find :

The velocity of the center of mass of these two particles.

Solution :

Speed of mass m, \(v\ \hat i\).

Speed of mass 2m , \(\dfrac{v}{2}\ \hat{j}\) .

Speed of center of mass is given by :

\(v_{cm }= \dfrac{m\times( v\ \hat{i}) + 2m \times \dfrac{v}{2}\ \hat{j} }{m + 2m}\\\\v_{cm}=\dfrac{v( \hat{i} + \hat{j})}{3}\)

Hence, this is the required solution.

The velocity of the center of mass of these two particles will be \(\rm v_{cm}= \frac{v(\vec i+\vec j)}{3}\)

The change of displacement with regards to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

\(\rm V_i\) is the speed of mass m

\(\rm \frac{v}{2} \hat j\) is the speed of mass 2m

Speed of the center of mass will be;

\(\rm v_{cm}=\frac{m \times (v \hat i)+2m \times \frac{v}{2}\hat j }{m+2m} \\\\ \rm v_{cm}= \frac{v(\vec i+\vec j)}{3}\)

Hence the  velocity of the center of mass of these two particles will be \(\rm v_{cm}= \frac{v(\vec i+\vec j)}{3}\).

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The observation of his parents swinging and practicing what he saw mainly involved sensory neurons.

There are five senses in the human body, they are;

Information is passed to the central nervous system (CNS) from each of these senses.

The neurons that convey sensory information of sight, smell, touch, taste and hearing to the brain are called sensory neurons.

Thus, the observation of his parents swinging and practicing what he saw mainly involved  sensory neurons.

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Answer:

The answer is 420kgm/s

Explanation:

momentum = mass×velocity

= 12kg×35m/s

=420kgm/s

Answer:

ligma

Explanation:

Answer:

see below

Explanation:

We are here given that ,

As we know that,

\(\implies h =\dfrac{u^2\sin^2\theta}{2g} \\\)

substitute the respective values,

\(\implies 2.4 m =\dfrac{u^2\sin^245^\circ}{2\times 10} \\\)

\(\implies 2.4m =\dfrac{u^2\times \bigg(\dfrac{1}{\sqrt2}\bigg)^2}{20}\\\)

\(\implies u^2 = 40 \times 2.4 = 96 \\\)

\(\implies u^2 =\sqrt{96}\\\)

\(\implies \underline{\underline{ u \approx 9.79 \ m/s }}\\\)

secondly we know that,

\(\implies t = \dfrac{u\sin\theta}{g}\\\)

\(\implies t =\dfrac{9.79\times \sin45^\circ}{10} \\\)

\(\implies t =\dfrac{9.79\times \dfrac{1}{\sqrt2}}{10} \\\)

\(\implies \underline{\underline{ t \approx 0.69 \ s }}\\\)

and we are done!

Answer:

it will burn up in the Earth's atmosphere.

Explanation:

The structure of the Earth's atmosphere protects the surface from frequent meteoroid strikes. As a meteoroid enters the atmosphere from outer space, it moves at very high speeds. At such speeds, intense amounts of friction and heat result. This process usually causes small meteoroids to burn up in the Earth's atmosphere before ever reaching the surface.

Answer:

Lack of cleanliness

Explanation:

Dust and other debris accumulate over time. If you have pets, their hairs pile on too. These clog the lining of where the door closes. If you want your screen door to move more smoothly, you have to clean the lining more frequently.

Answer:

1/2

Explanation:

Given

c=distance

a= length

e= c/a

3/6

e= 1/2 or 0.5

Answer: In a generator, the back and forth movement of electrons as the magnet spins and opposite poles of the magnet push the electrons in opposite directions is called Alternating Current (AC).

Explanation:

Answer:

alternating current and direct current

Explanation:

yall some of these questions arent that hard, use common sense

Answer:

I= 1/2 mr^2 solve for mass m.

radius given

angular momentum: I*w=I*2

KE= 1/2 I w^2= 1/2 I *2^2

Explanation:

The mass of the uniform disc at the given moment of inertia is determined as 16.67 kg.

The mass of the uniform disc is calculated from the moment of inertia of the disc.

I = ¹/₂mr²

2I = mr²

m = (2I)/r²

where;

m = (2 x 75)/(3²)

m = 16.67 kg

Thus, the mass of the uniform disc at the given moment of inertia is determined as 16.67 kg.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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A wool sweater worn under a cotton jacket produces more static charges.

Static charge is an imbalance of electric charges within or on the surface of a material or between materials.

Static charges can be produced by two materials together (friction method).

A wool sweater worn under a cotton jacket (in the absence of lubricant like water) creates friction which enables more static charge to be produced.

Thus, a wool sweater worn under a cotton jacket produces more static charges.

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Answer:

42.9 μF

Explanation:

V = 3.50 V, Q = 150 μC

C = Q/V = 150/3.50 μF = 42.9 μF