Plains and mountains are examples of formed by processes that shape Earth's surface.

Answer:

Explanation: you can choose B or C but i would choose C

The torque due to gravity about the pivot of the uniform board is 294 N·m.

The torque due to gravity about the pivot of a uniform board can be determined by considering the weight of the board acting at its center of mass. The torque is given by the formula:

Torque = Weight × Distance

First, we need to calculate the weight of the board. The weight can be determined using the formula:

Weight = Mass × Acceleration due to Gravity

Given that the mass of the board is 12.0 kg and the acceleration due to gravity is approximately 9.8 m/\(s^{2}\), we can substitute these values into the formula:

Weight = 12.0 kg × 9.8 m/\(s^{2}\)

Calculating the expression gives us:

Weight ≈ 117.6 N

Next, we need to determine the distance between the pivot and the center of mass of the board. Since the board is uniform, the center of mass is located at its midpoint. The length of the board is given as 5.00 m, so the distance is half of the length:

Distance = 5.00 m ÷ 2 = 2.50 m

Finally, we can calculate the torque:

Torque = Weight × Distance = 117.6 N × 2.50 m = 294 N·m

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Answer:

Neil Armstrong was the astronaut

a dropped softball will fall a vertical distance of approximately 4.9 meters (16.1 feet) during the first second of free fall, neglecting air resistance.

When an object is dropped from rest near the surface of the Earth, it is subject to the force of gravity, which causes it to accelerate downwards. The acceleration due to gravity is approximately 9.8 meters per second squared, which means that the velocity of the object increases by 9.8 meters per second (or 32.2 feet per second) for each second it falls.

During the first second of free fall, the object starts from rest and accelerates at a constant rate of 9.8 meters per second squared. Using the equations of motion, we can calculate the distance it falls during this time:

d = 1/2 * a * t^2

where d is the distance, a is the acceleration, and t is the time. Plugging in the values for the first second of free fall, we get:

d = 1/2 * 9.8 m/s^2 * (1 s)^2
d = 4.9 meters

Therefore, a dropped softball will fall a vertical distance of approximately 4.9 meters (16.1 feet) during the first second of free fall, neglecting air resistance.

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Answer:drfdcfrfvgtgy6hbhhbhyg vcfrfr5tgvcfrtg vcdftghegthetrgbdgtthethe3thet

Explanation:

Sdwerftyrujtnyhbvcrdefgswthyujdehrtgfyhrjfuygtdhjueyrtgehwu3y4tgrehjwheyrgdhbnsjhfgvbdnhgfdhjsdehbrvbdensdvfgreyhsdgrftyhedggrfdhsgfv

We are given that a cyclist A is moving at a constant speed of 21 m/s. The equation of position with respect to the time of an object moving at a constant speed is the following:

Where:

Substituting the values we get:

Cyclist B starts at the position 30 meters is moving at a constant acceleration. The formula for the position of an object moving at a constant acceleration is the following:

Where:

Since the object begins at rest this means that the initial velocity is zero. If we set its starting point at the origin then the initial position is zero. Now, we substitute the values:

Solving the operations:

Since we are asked to determine the time when they are at the same distance we need to set both equations equal:

Now, we divide both sides by 2;

Now, we subtract "7t" from both sides:

We get an equation of the form:

To solve the equation we will factor the left side:

We need to find two numbers such that their product is 10 and their algebraic sum is -7. Those numbers are -5 and -2:

Now, we set both factors equal:

For the second factor:

The two times are then 5s and 2s.

To meet the goal of averaging 90 km/h over the entire trip, the average speed in the second half of the journey should be 132 km/h.

Let's assume the total distance of the trip is D kilometers. In the first half of the trip, you covered D/2 kilometers at an average speed of 48 km/h. The time taken for the first half can be calculated as (D/2) / 48.

To average 90 km/h over the entire trip, the total time taken for the entire trip should be D / 90. Since the time taken for the first half is (D/2) / 48, the time available for the second half is D / 90 - (D/2) / 48.

Now, we need to find the average speed for the second half that will cover the remaining distance, which is D/2, in the available time. We can set up the equation:

(D/2) = Average speed in the second half * [D / 90 - (D/2) / 48]

Simplifying the equation, we get:

1 = Average speed in the second half * [(1/90) - (1/96)]

Solving for the average speed in the second half, we find it to be approximately 132 km/h.

Therefore, the average speed in the second half of the journey should be 132 km/h to maintain an average speed of 90 km/h

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Edit: The complete question is

You plan a car trip on which you want to average 90 km/h. You cover the first half of the distance at an average speed of only 48 km/h. What must your average speed be in the second half of the trip to meet your goal?

maximum acceleration  when maximum force of 420 kn horizontally against the tracks, whereas at maximum velocity (300 km/h), it exerts a force of about 150 km is 0.656 m/s²

Given Maximum force exerted by Train = 42OKN

dice , F = 150 KN .

Man of a train = 640 metric tons = 640, 000kg

velocity = 300 km/ hr

a ) The maximum acceleration , when force on track is

maximum and drag is minimum . It occurs when speed is 0 .

Ftrain - O = M Amax .

Amax = Ftrain/m

420 * 10³ N/640000N

amax = 0.656 m/s²

b ) A top speed , a=0

Ftrain - Fdrag = 0

Fdrag = 150 KN

The rate at which an object's velocity changes in a straight line under an imbalanced force is known as acceleration. When forces are evenly distributed, there is no longer any net force, which prevents any movement. The relationship between these three concepts is provided by Newton's second law, which also explains how an imbalanced force affects an object's motion.

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It is difficult to see the bulge at the middle of the Milky Way Galaxy with visible light due to several factors. First, the bulge is located far away from us, approximately 27,000 light-years, which means the light has to travel a long distance before reaching our eyes or telescopes.

Second, the Milky Way Galaxy is filled with interstellar dust and gas that absorb and scatter visible light, causing a phenomenon called interstellar extinction. This makes it challenging for the visible light from the bulge to pass through and reach us without significant loss of intensity.
Additionally, our line of sight to the bulge is through the plane of the galaxy, where the concentration of dust and gas is highest. This further exacerbates the problem of interstellar extinction and reduces the visibility of the bulge in visible light.
To overcome these challenges, astronomers rely on other wavelengths of light, such as infrared and radio waves, which are less affected by interstellar dust and gas. By using these wavelengths, we can gain a better understanding of the structure and properties of the Milky Way's central region.

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The centripetal acceleration of the racecar is 2500 m/s^2.

The centripetal acceleration of a racecar going around a turn can be calculated using the following formula:

a = v^2 / r

where:

a is the centripetal acceleration

v is the speed of the racecar, and

r is the radius of curvature of the turn.

Centripetal acceleration is important in many real-world applications, such as the motion of satellites around the Earth, the movement of cars on circular roads and amusement park rides, and the movement of electrons in an atom. The magnitude of centripetal acceleration determines the tightness of the circular path and how much the object is being pulled towards the center. Understanding centripetal acceleration is essential for designing and analyzing various systems and processes.

Given the values:

v = 50 m/s

r = 30 meters

We can substitute these values into the formula and solve for a:

a = v^2 / r

a = (50 m/s)^2 / 30 m

a = 2500 m/s^2

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Answer:

Both particle and wave properties

Explanation:

Light is defined as a particle and a wave, and even as a combination of a particle and a wave. A unit of light is the photon. Higher energy photons behave like particles and low energy photons behave like waves.

Experiments performed with light indicate that light exhibits both particle and wave properties.

Answer:

Volumetric cylinders (would appreciate brainliest

Explanation:

Volumetric cylinders and volumetric flasks are used to measure volume of liquids contained in them. They are calibrated for volume included in them - this is indicated by the marking "IN". The liquid has accurate volume when it reaches the corresponding marking on the scale.

Answer:

Two tectonic plates move horizontally past one another along Earth’s surface, forming long fault lines.

Answer:

Plates move apart

Explanation:

At a transform boundary, plates move apart. At a divergent boundary, plates separate. Convection currents in the mantle contribute to tectonic plate movement.

The amount of work done by the ideal gas is 2475J.

The magnitude of the work done when a gas expands is therefore equal to the product of the pressure of the gas times the change in the volume of the gas.

w=−PΔV

The negative sign associated with the above equation indicates that the system loses energy. If the volume increases at constant pressure (ΔV > 0), the work done by the system is negative, indicating that a system has lost energy by performing work on its surroundings.

According to this question, an ideal gas initially at 50.0m³ at 1000.0 Pa expands to a volume of 300.0 m³ after heating. The work done can be calculated as follows:

W = -P∆V

W = - (0.0099 × {300000L - 50000L)

W = - (0.0099 × 250000)

W = 2475J

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Using the time dilation formula we find that the required speed is 0.79 0.79 0.79 c. It move very fast.

Definition of time dilation

A slowing of time in accordance with the theory of relativity that occurs in a system in motion relative to an outside observer and that becomes apparent especially as the speed of the system approaches that of light. — called also time dilatation.

The idea of "absolute time" was our default for millennia. But time is relative, as gravity and motion both cause time to dilate. Both space and time coordinates are needed to describe an object in our Universe.

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Answer:

D) πR/7,200 m/s

Explanation:

Let's call the speed of the moon "v".

We know that the period (T) of the moon is given by: T = 20 hours = 20 hours * 3600 seconds/hour = 72000 seconds

We can relate the speed of the moon to its period and distance using the formula:

v = 2πR/T, where R is the distance of the moon from the center of the planet.

In this case, the distance is 5R, so:

v = 2π(5R)/T

= 2π(5R)/72000 seconds

= (πR)/7,200 seconds

So the speed of the moon is (πR)/7,200 m/s.

Therefore, the answer is D) πR/7,200 m/s.

To find the current in the resistor, we can use Ohm's Law and the concept of equivalent resistance. Thus, option A is correct.

First, let's calculate the equivalent resistance of the three cells connected in parallel. When resistors are connected in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances:

1/Req = 1/R1 + 1/R2 + 1/R3

Given that R1 = R2 = R3 = 22 Ω (internal resistance of each cell), we can substitute the values:

1/Req = 1/22 + 1/22 + 1/22

1/Req = 3/22

Taking the reciprocal of both sides, we find:

Req = 22/3 Ω

Now we can use Ohm's Law to calculate the current (I) in the resistor. Ohm's Law states that the current flowing through a resistor is equal to the voltage across it divided by its resistance:

I = V/R

Given that V = 1.1 V (emf of each cell) and R = 32 Ω (resistance), we can substitute the values:

I = 1.1/32

Calculating this value, we find:

I ≈ 0.034375 A

Therefore, the current in the resistor is approximately 0.034375 A.

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The charge at the higher potential is the one placed a distance r from the origin with a charge of q.

Define variables
- Charge at the origin: q₁ = q
- Charge at a distance r: q₂ = q
- Charge at a distance 2r: q₃ = 2q

Recall the formula for electric potential V = kQ/r, where k is the electrostatic constant (8.99 x 10^9 Nm²/C²), Q is the charge, and r is the distance from the charge.

Calculate the electric potential at the location of each charge.
- V₁ (potential at q₁): Since q₁ is at the origin, the electric potential V₁ = 0 (potential at the location of the charge itself is not considered).
- V₂ (potential at q₂): V₂ = k(q₁ + q₃)/(r)
- V₃ (potential at q₃): V₃ = k(q₁ + q₂)/(2r)

Compare the electric potentials.
- V₂ = k(2q + q)/(r) = k(3q)/(r)
- V₃ = k(2q)/(2r) = k(q)/(r)

Comparing the two potentials, V₂ = 3V₃.

Since V₂ > V₃, the charge at a distance r (q₂ = q) is at a higher potential.

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Top-down processing is used when we interpret new stimuli in light of our prior knowledge. The image focused on each retina is from a slightly different angle because we have two eyes in two separate places. Binocular disparity is the term for this phenomenon.

There are two main approaches to making meaning of stimuli: bottom-up and top-down. Bottom-up processing occurs when we let the data itself, free of any preconceived ideas, shape our perception.

In top-down processing, we interpret what we perceive by drawing on our prior knowledge and expectations.

According to the theory of "top-down processing," our brains first build a notion of the overall picture based on prior knowledge before breaking it down into more detailed information. We use our perceptual set—past experiences, expectations, and emotions—to interpret the world around us.

Therefore, when we process new stimuli based on our past experiences, we are using top-down processing.

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Answer:

D !!!

Explanation:

Answer:

D

Explanation:

Answer:

Explanation:

The main cause of different parts of the earth receiving different amounts of solar energy is as a result of the tilt of the Earth. Having different latitudes also play a role in that, as latitudes are used to measure the distances between places on earth(together with longitude) receiving different amounts of solar energy also leads to having different atmospheric circulation. Making some places have more heat, while other places have lesser heat energies. Logically, the areas with higher presence of solar energy are going to be hotter than places with lesser presence of solar energy.

(a) The proton will move in the positive z direction.

(b) The work done by the electric field is 1.44 × \(10^{-17\) J, and work done is defined as the dot product of the displacement and electric field vectors, taking into account the angle between them.

(c) The change in electric potential energy of the charged particle is also 1.44 × \(10^{-17\) J, which is equal to the negative of the work done by the electric field.

(d) The speed of the charged particle can be determined using the work-energy theorem which is 1.85 * \(10^5\) m/s

(a) Since the electric field is acting in the negative z direction and the proton has a positive charge, it will experience a force in the opposite direction and move in the positive z direction.

(b) The work done by the electric field is defined as the dot product of the displacement vector and the electric field vector:

\(work = |d| * |E| * cos(theta)\)

where |d| is the magnitude of the displacement vector, |E| is the magnitude of the electric field, and theta is the angle between the two vectors. In this case, the electric field and displacement vectors are parallel, so the angle between them is 0 degrees. The work done is given by work = |d| * |E| * cos(0) = |d| * |E|. Plugging in the values, work = (2.85 cm) * (253 N/C) = 721.05 N cm/C or 1.44 × \(10^{-17\) J.

(c) The change in electric potential energy of the charged particle is equal to the negative of the work done by the electric field. Therefore, the change in electric potential energy is also 1.44 × \(10^{-17\) J.

(d) The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. Since the proton starts from rest, the work done by the electric field is equal to the change in kinetic energy. The work done is given by work = (1/2) * m * \(v^2\), where m is the mass of the proton and v is its final velocity. Rearranging the equation, v = \(\sqrt((2 * work) / m)\). Plugging in the values,

\(v = \sqrt((2 * 1.44 * 10^{-17} J) / (1.67 * 10^{-27} kg))\) = 1.31 × \(10^5\) J/kg or 1.85 * \(10^5\) m/s

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An Electron will undergoes the lesser acceleration

An electron is a negatively charged particle of equivalent magnitude to a proton, which is positively charged. Therefore, they will feel the same amount of electric force when exposed to an electric field. As a result, the relationship between acceleration and mass will be inverse. An electron will accelerate more quickly than a proton because an electron has a lower mass.

Due to their opposite polarity, an electron and a proton are attracted to one another by an electrical force of equal strength when they are placed in an electric field. However, because of their opposing charges, the force will act in the opposite direction.

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Sound intensity is inversely proportional to the square of the distance traveled by the sound.

Sound, a mechanical disturbance from a state of equilibrium that propagates through an elastic material medium. The sound travels in all the mediums i.e. solid, liquid, and gas.

According to the question, the sound frequency which he is hearing is 20dB when he is standing 8m away from the engine.

Sound intensity is inversely proportional to the square of the distance traveled by the sound. Thus;

r1^2 divide by r2^2 = L2divideL1

where r= distance (m)

L= sound intensity (decibel dB)

8squared divide by 4 squared = L2 divide 20 dB

L2 = 4 × 20

L2= 80 dB

This means that the sound is increased from 20 dB to 80 db.

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Visible light, ultraviolet rays, and X-rays are all forms of electromagnetic radiation, with differences in their wavelengths, frequencies, and energies.

Visible light is the part of the electromagnetic spectrum that human eyes can perceive. It has a wavelength range of 400-700 nanometers, with violet having the shortest wavelength and red having the longest. Visible light can be refracted, reflected, and diffracted, and it can be split into its component colors using a prism.

Ultraviolet (UV) rays have shorter wavelengths and higher frequencies than visible light. They have wavelengths between 10-400 nanometers. UV radiation is classified as UVA, UVB, and UVC, with UVC having the shortest wavelength and highest energy. UV rays can cause damage to DNA and can cause sunburn and skin cancer.

X-rays have even shorter wavelengths and higher frequencies than UV rays. X-rays have wavelengths between 0.01-10 nanometers. They can penetrate through materials that visible light and UV radiation cannot, such as body tissues and bones, making them useful in medical imaging. X-rays are also produced in outer space and can be used to study the universe.

In summary, the main differences between these types of electromagnetic radiation are their wavelengths, frequencies, and energies, which determine their properties and potential applications.

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Answer:

b

Explanation:

Answer:

‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍‍

Explanation:

Here,

Mass=16,500kg.

speed=14 m/s.

we know that,

\(\tt{ p=m×v }\) ⠀

where,

p=momentum

m=mass

v=velocity

according to the question,

\(\tt{ momentum =mass×velocity }\) ⠀

\(\tt{ 16500×14 }\) ⠀

\(\tt{ 231000~kg.m/s }\) ⠀

so,

velocity of the car is 231000kg.m/s

Answer:

Explanation:

a) work=Force times distance. given force is 888N and distance travelled is 22M

work= 888 x 22 = 19536J or 1.954x10^5J

b) work = 1111 x 22= 24442J or 2.444x10^5J

c) putting on a larger engine means that there are gonna be more force applied to the go cart. therefore the cart will travel the same distance faster

a. The amount of work done by the go cart engine is 19,536 Nm.

b. The amount of work done when a bigger engine is used is 24,442 Nm.

c. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

Given the following data:

a. To determine the amount of work done by the go cart engine:

Mathematically, the work done by an object is given by the formula;

\(Work\;done = Force \times distance\)

Substituting the given parameters into the formula, we have;

\(Work\;done = 888 \times 22\)

Work done = 19,536 Nm.

b. To determine the amount of work done when a bigger engine is used:

\(Work\;done = Force \times distance\)

\(Work\;done = 1111 \times 22\)

Work done = 24,442 Nm.

c. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

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