Platinum-182 has a half-life of 3 minutes. If you have a 120-gram sample of Platinum
how much of that sample will remain after 6 half-lives.

Answers

Answer 1

The sample of Platinum-182 that will remain after 6 half-lives is 1.875 grams

Using the formula of half-life,

Half-life: This is the time taken for half the sample of a radioactive substance to disintegrate.

⇒ Formula

M' = M/2ⁿ............................... Equation 1

⇒ Where:

M' = Sample of Platinum-182 that will remain after 6 half-livesM = Original sample of Platinum-182n = Number of half-lives

From the question,

⇒ Given:

M = 120 gramsn = 6 half-lives

⇒ Substitute these values into equation 1

M' = 120/2⁶M' = 120/64M' = 1.875 grams

Hence, The sample of Platinum-182 that will remain after 6 half-lives is 1.875 grams

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Related Questions

Help me , what is the properties of fluids ? ​

Answers

Some of the most fundamental concepts of fluid properties are temperature, density, and composition.

The properties of fluids are Density,Viscosity,Temperature, Pressure,Specific Volume,Specific Weight,Specific Gravity.

What are patients most likely to prepare as part of their right to make decisions about end of life care under federal legislation

Answers

Patients are most likely to prepare "advance directives" as part of their right to make decisions about end-of-life care under federal legislation.

what is an adam and a moreculw and a half note ???

Answers

i think it is 12 because

if every Galaxy have black hole in center than is that mean there used to humongous star that collapsed that formed galaxy and supermassive black hole?​

Answers

Answer:

Yes, It does mean that there was a Red Giant in the middle of the galaxy.

Explanation:

The star at the middle of the galaxy will forever stay at the middle from the gravity it has on itself and it implodes and turns into a black hole with a mass equal to at least 10 suns

an ideal gas at 20centigree In a press 1.5×10pa and compress,a.isothamally,b.adaibatically until it volume in 1/3 in each case reversible.calculate in each case the final pressure and temperature of d gas (the ratio all specific capacity=Cp/Cv=1.4​

Answers

a) The final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\) and 293 K, respectively, while  b) the final pressure and temperature for the adiabatic compression are\(5.58*10^5 Pa\) and 515 K, respectively.

a. Isothermal compression:

For an isothermal process, the temperature remains constant. Therefore, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.

Since the process is isothermal, we can write:

\(P_1V_1 = P_2V_2\)

where P1 and V1 are the initial pressure and volume, and\(P_2\)and\(V_2\)are the final pressure and volume.

We are given that the volume is compressed to 1/3 of its original volume, so\(V_2 = (1/3)V_1\). Substituting this into the equation above gives:

\(P_2 = (V_1/V_2)P_1 = 3P_1\) = \(4.5*10^5 Pa\)

To find the final temperature, we can use the ideal gas law again:

PV = nRT

Rearranging, we get:

T = PV/(nR)

Substituting the values we know, we get:

T = (\(1.5*10^5\)Pa)(V1)/(nR)

Since the process is isothermal, the temperature remains constant, so the final temperature is the same as the initial temperature:

T2 = T1 = 293 K

b. Adiabatic compression:

For an adiabatic process, there is no heat transfer between the gas and its surroundings. Therefore, we can use the adiabatic equation:

PV^γ = constant

where γ = Cp/Cv is the ratio of specific heats.

Since the process is adiabatic and reversible, we can write:

\(P_1V_1\)^γ = \(P_2V_2\)^γ

We are given that the volume is compressed to 1/3 of its original volume, so V2 = (1/3)V1. Substituting this into the equation above gives:

\(P_2 = P_1(V_1/V_2)\)^γ = \(P_1\)\((3)^{(1.4)\) = \(5.58*10^5 Pa\)

To find the final temperature, we can use the adiabatic equation again:

\(T_2 = T_1(P_2/P_1)\)^((γ-1)/γ) = T1(5.58/1.5)^(0.4) = 515 K

Therefore, the final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\)and 293 K, respectively, while the final pressure and temperature for the adiabatic compression are \(5.58*10^5\) Pa and 515 K, respectively.

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We have 3 gears meshed with the following teeth. A – 20; B – 50; C – 30. Another set of gears have the following teeth. X – 20; Y – 25; Z – 30. Assuming gears A and X are running at the same rpm. Which statement is correct?

Answers

gear C and Z will run at the same RPM

RPM is not a unit, according to the International System of Units (SI). The word "revolution" is a semantic annotation rather than a unit, which explains this. RPM formula sign must be f for (rotational) frequency and or for angular velocity due to the measured physical quantity. s−1  or Hz is the basic SI-derived unit that corresponds. The radians per the second unit are used to express angular speed.

As a result, a disc rotating at 60 RPM  is considered to be rotating at either 2 rad/s or 1 Hz, where the former refers to angular velocity and the latter to the rate of revolutions per second.

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We have 3 gears meshed with the following teeth. A 20; B 50; C 30. Another set of gears have the following

A truck accelerates from rest at a rate of 2.3 m/s2 for 12 seconds and then the driver hits the brakes and the truck accelerates at a rate of -1.6 m/s2 for 9 seconds. What is the A) final velocity and B) final displacement?

Answers

The final velocity of the truck is determined as 13.2 m/s.

The final displacement of the truck is determined as 183.6 m.

Velocity of the truck after 12 seconds

The velocity of the truck after 12 seconds is calculated as follows;

v = u + at

where;

v is the final velocity of the truck after 12 seconds

u is the initial velocity of the truck

t is the time of motion

a is the acceleration of the truck

v = 0 + 2.3(12)

v = 27.6 m/s

Final velocity of the truck

The velocity of the truck after 9 seconds is calculated as follows;

v = u + at

where;

v is the final velocity of the truck after 9 secondsu is the velocity of the truck after 12 secondst is the time of motiona is the deceleration of the truck

v = 27.6 m/s   +  (-1.6)(9)

v = 13.2 m/s

Final displacement of the truck

v² = u² + 2as

13.2² = 27.6² + 2(-1.6)s

174.24 = 761.76 - 3.2s

3.2s = 761.76 - 174.24

3.2s = 587.52

s = 587.52/3.2

s = 183.6 m

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PLZ HELP ASAP
With number 10 above

PLZ HELP ASAP With number 10 above

Answers

Answer:

P = 1500 Watt

Explanation:

Mechanical Work and Power

Mechanical work is the amount of energy transferred by a force.

Being F the magnitude of the force vector and s the distance, the work is calculated as:

W=F.s

Power is the amount of energy transferred or converted per unit of time. In the SI, the unit of power is the watt, equal to one joule per second.

The power can be calculated as:

\(\displaystyle P=\frac {W}{t}\)

Where W is the work and t is the time.

The force to be considered is the weight of the mass of m=100 kg, \(g= 10\ m/s^2\):

F = 100 * 10 = 1000 N

The distance is s=3 m, thus the work done by the weight lifter is:

W = 1000 N * 3 m

W = 3000 J

Finally, the power is:

\(\displaystyle P=\frac {3000}{2}\)

P = 1500 Watt

A very dense 1500-kg point mass (A) and a dense 1200-kg point mass (B) are held in place 1.00 m apart on a frictionless table. A third point mass is placed between the other two at a point that is 20.0 cm from B along the line connecting A and B. When the third mass is suddenly released, find the magnitude and direction (toward A or toward B) of its initial acceleration.

Answers

Answer:

Explanation:

Let m be the third point mass

Force pulling toward A

Fa = Gm(1500)/0.800² = 2343.75Gm

Force pulling toward B

Fb = Gm(1200)/0.200² = 30000Gm

Net force acting on m

30000Gm - 2343.75Gm = 27656.25Gm

a = F/m = 27656.25Gm/m = 27656.25G

a = 27656.25(6.674 x 10⁻¹¹) = 1.8457... x 10⁻⁶ m/s² towards mass B

A main-sequence star at a distance of 20 pc is barely visible through a certain telescope. The star subsequently ascends the giant branch, during which time its temperature drops by a factor of three and its radius increases a hundredfold. What is the new maximum distance at which the star would still be visible in the same telescope?

Answers

Answer:

Explanation:

The surface area of a star estimated by the energy emitted per sq meter yields the overall luminosity, which can be represented mathematically as:

\(L= 4 \pi R^2 \sigma T^4 --- (1)\)

where;

L ∝ R²T⁴

and;

R = radius of the sphere

σ = Stefans constant

T = temperature

Also; The following showcase the relationship between flux density as well as illuminated surface area as:

\(F = \dfrac{L}{A}\)

where

A = 4πd² and L ∝ R²T⁴

\(F = \dfrac{R^2T^4}{4 \pi d^2} \\ \\ F \alpha \dfrac{R^2T^4}{ d^2} --- (2)\)

Given that:

distance d₁ = 20 pc

Then, using equation (2)

\(F_1 \ \alpha \ \dfrac{R^2_1T^4_1}{ d^2_1}\)

However, we are also being told that there is a temp. drop by a factor of 3;

So, the final temp. \(T_2 = \dfrac{T_1}{3}\); and the final radius is \(R_2 = 100R_1\) since there is increment by 100 folds.

Now;

\(F_2 \ \alpha \ \dfrac{R^2_2T^4_2}{ d^2_2}\)

SInce;

\(F_1 = F_2\)

It implies that:

\(\dfrac{R^2_1T^4_1}{ d^2_1 } = \dfrac{R^2_2T^4_2}{ d^2_2} \\ \\ d_2 = \sqrt{\dfrac{R_2^2T_2^4}{R_1^2T_1^4}}(d_1)\)

Replacing all our values, we have:

\(d_2 = \sqrt{\dfrac{(100R_1)^2 \times (\dfrac{T_1}{3})^4}{R_1^2T_1^4}}(20 ) \\ \\ d_2 = \sqrt{\dfrac{(100)^2 }{3^4}}(20 ) \\ \\ d_2 = \sqrt{\dfrac{(100)^2 }{3^4}}(20 ) \\ \\ d_2 =222 \ pc\)

What is the scientific weight of a 50kg box on Earth?

Answers

The scientific weight of a 50 kg mass which is usually the product of the mass and gravitation is 500 N.

The scientific weight refers to the weight of an object on the Earth.

As we know, according to the third law of Newton, there is always an equal and opposite reaction to every object.

If we are putting mass on the Earth, then there will be the gravitational force working on the body.

So, the weight becomes the product of mass and gravity.

Given,

Mass = 50 kg.

Let us assume the gravitational force to be 10 N

Now, the weight of the box becomes

Weight = 50 * 10 = 500 N

Therefore the scientific weight of a 50 kg mass which is usually the product of the mass and gravitation is 500 N.

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What kind of energy do plants convert light energy from the sun

Answers

Answer: chemical energy

Explanation:

Chemical Energy is the type of energy that plants convert light energy from the sun.


A car with a momentum (impulse) of 20,000 kg m/s collides with a wall and comes to a rest in 0.1 seconds. How much
force is absorbed by the car (and the driver)?

Answers

Answer:

» Force is 200,000 Newtons

Explanation:

\({ \tt{force = \frac{impulse}{time} }} \\ \\ { \tt{force = \frac{20000}{0.1} }} \\ \\ { \tt{force = 200000 \: newtons}}\)

Find the order of magnitude of the following physical quantities.
B) The mass of the Moon’s atmosphere: 25,000 kg
(c) The mass of Earth: 5.97×1024 kg
(d) The mass of the Moon: 7.34×1022 kg
(e) The Earth-Moon distance (semi-major axis): 3.84×108 m

Answers

The order of magnitude of the given physical quantities would be  B < E < D < C

What are significant figures?

In positional notation, significant figures refer to the digits in a number that is trustworthy and required to denote the amount of something, also known as the significant digits, precision, or resolution.

Here, the order of magnitude of the following physical quantities is as follows

B.The mass of the Moon’s atmosphere: 25,000 kg ⇒ 10 ⁴

C.The mass of Earth: 5.97×10²⁴ kg ⇒ 10²⁴

D.The mass of the Moon is 7.34×10²² kg⇒ 10²²

E.The Earth-Moon distance (semi-major axis): 3.84×108 m ⇒  10⁸

Thus, the order of magnitude of the given physical quantities would be  B < E < D < C

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A stone is dropped in a river surface of water,if it takes 4 seconds to reach surface of water, calculate the velocity with which the stone strikes on the water surface​

Answers

Answer:from,

v=at+u then ,time=4seconds

we take u=initial speed which is zero

(0)

 now, v=(10x4+0)m/s

then, velocity/speed is 40m/s

Explanation:from firt newton's laws of motion where from acceleration is rate of change of speed then we generate the eqn where now the stone was falling fat a certain height were we include acceleration due to gravity and multiply to time and sum to initial speed to get

a flexible container at an initial volume of 8.15 l 8.15 l contains 8.51 mol 8.51 mol of gas. more gas is then added to the container until it reaches a final volume of 13.7 l. 13.7 l . assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Answers

The number of moles of gas added to the container is -3.56 mol, and the negative sign means that the number of moles of gas decreased, or in other words, the gas was compressed.

The number of moles of gas can be calculated using the Ideal Gas Law:

PV = nRT

where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.

Since the pressure and temperature remain constant, we can equate the initial and final state of the gas:

n1 × (8.15 L) × (T) = n2 × (13.7 L) × (T)

Dividing both sides by T, we get:

n1 × 8.15 L = n2 × 13.7 L

Solving for n2:

n2 = (n1 × 8.15 L) / (13.7 L)

n2 = (8.51 mol) × (8.15 L) / (13.7 L)

n2 = 4.95 mol

So, the number of moles of gas added to the container is:

n2 - n1 = 4.95 mol - 8.51 mol = -3.56 mol.

Note that the answer is negative, which means that the number of moles of gas decreased, or in other words, the gas was compressed.

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You push a cart with mass 30 kg forward, giving it an acceleration of 5 m/s2How much force did you apply? O A. 0.17 N O B. 35 N O C. 75 N O D. 150 N ​

Answers

Answer:

150N

Explanation:

To find the force applied remember that force equals to Mass multiply by the Acceleration.

F=Ma

=30*5

=150N

Answer:

150N

Explanation:

F = m*a = 30 * 5 = 150 N

the space Hubble Telescope is orbiting earth at a constant speed of 20m/s.The distance between it and planet earth is 100m.The radius of planet earth is 300km. How long will it take for the Space Hubble Telescope to make a complete rotation?​

Answers

It will take the Hubble Telescope 94,247 seconds or 26.18 hours to complete one full rotation around the Earth.

Rotation time of the Space Hub Telescope

The Hubble Telescope is in a circular orbit around the Earth at a constant speed of 20 m/s. The distance between the telescope and the center of the Earth is:

300 km + 100 m = 300,100 m.

Orbital period T of the Hubble Telescope = T = 2πr / v

where

r is the radius of the orbit v is the orbital speed.

In this case, r = 300,100 m and v = 20 m/s, so:

T = 2π(300,100 m) / (20 m/s) = 94247 seconds

Thus, it will take the Hubble Telescope approximately 94,247 seconds, or about 26.18 hours, to complete one full rotation around the Earth.

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Explore Suppose you are in a partially darkened room holding a flat piece of white cardboard in one hand and a converging lens of focal distance Convex lens 6.3 x 10 m in your other hand. You want to form an image of the window in front of you, which is at a distance of 1.74 m in front of the lens. (A) Find how far behind the lens the cardboard should be held to form as sharp an image as possible. (B) If the height of the window is 1.00 m, find the height of its image Object height 0.05 m Image height -0.05 m
Object distance 0.40 m Image distance 0.40 m Conceptualize The rays of light from any given point on the window refract as they pass through the lens to meet at a point behind the lens A ray that is parallel to the optical axis on either side of the convex lens passes through the focal point on the opposite side, and a ray through the center of the lens is undeflected. If the cardboard is held at the location where the rays traced in this way meet, an image focused as well as possible would be seen on the cardboard Categorize We apply the thin lens formula to calculate the image distance from the object distance and focal length. (A) Find how far behind the lens the cardboard should be held to form as sharp an image as possible Analyze The image distance q can be calculated from the thin lens formula: which can be rearranged as: (B) If the height of the window is h = 1.00 m, find the height of its image. Analyze The ratio of the image height h' to the object height h is the magnification M given by: h' 9 Then: C 9 1.74 m (1.00 m) =- h' Finalize The minus sign in the height corresponds to an inverted image. Finalize Notice also what happens if the sign of the focal length is changed, corresponding to a diverging lens (in the simplest case a concave lens) as illustrated in the Active Figure for concave lens. The rays from a given point on the object meet to form an image only when the rays are imagined to extend back towards the object, where they converge (as seen in the Active Figure). This is where the rays would appear to come from if you were holding the diverging lens in front of you while looking at the window. Would the image of the window be smaller or larger than the window in this case? What sign would q have?

Answers

For a converging lens, the focal point is the point at which converging light rays cross; for a diverging lens, the focal point is the point from which diverging light rays appear to originate.

Where do diverging rays come from?The focal length f is the measurement from the lens's centre to its focal point. Diverging light will come from a point on a far-off object. Diverging light rays will emanate from a point at a very far object. Parallel light beams spread out when they pass through a diverging lens. These light rays appear to the spectator to originate from the focal point on the opposite side of the lens. Together, these beams create a virtual image. A ray that is parallel to the axis and approaching a convex diverging mirror appears to be coming from the focal point F behind the mirror due to reflection. Convex mirrors are also known as diverging mirrors because they diverge the light rays that strike their surfaces.

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Hint: sin2θ + cos2θ = 1 .
Consider the 692 N weight held by two
cables shown below. The left-hand cable had
tension 570 N and makes an angle of θ2 with
the ceiling. The right-hand cable had tension
530 N and makes an angle of θ1 with the
ceiling. a) What is the angle θ1 which the righthand cable makes with respect to the ceiling?
Answer in units of ◦.
b) What is the angle θ2 which the left-hand
cable makes with respect to the ceiling?
Answer in units of ◦.

Answers

a) The angle θ1 which the righthand cable makes with respect to the ceiling is  sin^(-1)(692 N / 530 N).

b) The angle θ2 which the left-hand cable makes with respect to the ceiling is  sin^(-1)(692 N / 570 N).

We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).

We may apply the ideas of trigonometry and vector addition to address this issue.

a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.

T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).

T1sin(θ1) = 692 N

We may rearrange the equation to find 1:

θ1 = sin^(-1)(692 N / T1)

We can find 1 by substituting the given tension value, T1 = 530 N:

θ1 = sin^(-1)(692 N / 530 N)

b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.

The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).

T2sin(θ2) = 692 N

To find θ2, we can rearrange the equation:

θ2 = sin^(-1)(692 N / T2)

Substituting the given tension value T2 = 570 N, we can solve for θ2:

θ2 = sin^(-1)(692 N / 570 N)

Calculating these angles using the given tension values will provide the answers in degrees.

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1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.

2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.

1. A ball is at rest on the top of a hill (see the figure).At the top of the hill, the ball will have

Answers

1. At the top of the hill, the ball will have the maximum value of its gravitational potential energy and the minimum value of its kinetic energy. As the ball rolls down the hill, its gravitational potential energy is converted to kinetic energy when it gets to the ground.

2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.

19. What energy transformation occurs in a battery?
A. chemical energy to thermal energy
C. electric energy to chemical energy
B. chemical energy to electric energy
D. thermal energy to chemical energy

Answers

i think correct answer is b

Answer:

B.chemical energy changes to electric energy.

Explanation:

I hope l helped you. ❤❤

When people do a bungee jump theyare asked how much they weigh. Why?​

Answers

Answer:

The elasticity of the bungee cord reduces the gravitational forces applied on the body during bungee jumping. For example, if a 100-pound individual jumps from a building and encounters 900 pounds of deceleration force, they will feel 9 "G's" of force.

hopefully this'll help

have a nice day!!! :D

some psychologists believe that eating disorders representative fence against unconscious conflicts related to sexual development. These psychologists have adopted a _____ approach to eating disorders.

Answers

Some psychologists believe that eating disorders represent a defense against unconscious conflicts related to sexual development. These psychologists have adopted a Psychoanalytic approach to eating disorders.

What is a Psychoanalytic approach?

A psychoanalytic approach is based on the idea that our unconscious thoughts, feelings, and motivations can have a powerful influence on our behavior by focusing on helping individuals to gain insight into their unconscious processes, recognize and resolve conflicts, and modify their behavior.

Therefore, with this data, we can see that a Psychoanalytic approach is based on unconscious mental processes to develop a cure.

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If the distance doubles, what happens to the force?
a. Reduced by half
b. Reduced by 1/4
c. Stays the same
d. Quadruples

Answers

i think that it is D

Which diagram is the best model for a solid?
Substance A
Substance B
О Substance C

Answers

Answer:

This link was diagram

Explanation:

https://doubtnut.app.link/FnsNC80Dccb

What are the charged particles that form when atoms gain or lose electrons?
1.Ions
2.Bonds
3.Valence Electrons

Answers

Answer:

Ions

Explanation:

2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m

Answers

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Answer this one and u give you more points Need this now. This question has two parts. First, answer part A. Then, answer part B. Part A: Which statement best summarizes the theme of the text? O A. Tokyo is the best city in the world. O B. It is a long way from San Francisco to Tokyo 0 C. Sometimes we have to try something new to enjoy it. O D. Many things in Japan are different from what an American is used to. Part B: Which sentence from the text best supports your answer in part A? D A. "It was July, and Todd wanted to hang out with his friends." B. He had never eaten pickled vegetables, but the taste was not bad. C. Due to being awake during the protracted flight, Todd was exhausted and slept well. D. The sushi in San Francisco was not nearly as good.​

Answers

Answer: Part A its C

Part B is B

Explanation:

Need a 5 paragraph essay in the eartsh layers and how they function/ benefit the earth!

Answers

There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.

However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.

Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.

Explanation:

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