Please answer correctly !!!! Will mark brainliest !!!!!!!!!!!!!!

Factoring a quadratic in two variables with a leading coefficient of 1 involves finding two binomial factors that, when multiplied, produce the quadratic expression. The factors can be determined by identifying the common factors of the quadratic terms and arranging them appropriately.

To factor a quadratic expression in two variables with a leading coefficient of 1, we need to look for common factors among the terms. The goal is to rewrite the quadratic expression as a product of two binomial factors. For example, if we have the quadratic expression x^2 + 5xy + 6y^2, we can factor it as (x + 2y)(x + 3y) by identifying the common factors and arranging them in the binomial factors.

The process of factoring a quadratic in two variables may involve trial and error, testing different combinations of factors to find the correct factorization. Additionally, factoring methods such as grouping or using the quadratic formula can also be applied depending on the specific quadratic expression.

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The weights of steers in a herd are distributed normally. the probability that the weight of a randomly selected steer is between 1200 and 1579 lbs is 0.6915.

Generally, The probability that a randomly selected steer is between 1200 and 1579 lbs is equal to the area under the normal curve between those two points.

To find that area, we can standardize the lower and upper limits by subtracting the mean and dividing by the standard deviation, then use a table or calculator to find the area under the standard normal curve between those two standardized values.

Subtracting the mean from the lower and upper limits gives us

1200-1300=-100

and

1579-1300=279.

Dividing those differences by the standard deviation gives us -100/200=-0.5 and

279/200=1.395.

Therefore, the area we want is the area under the standard normal curve between -0.5 and 1.395.

Using a table or calculator, we find that the area under the standard normal curve between -0.5 and 1.395 is about 0.6915.

Therefore, the probability that a randomly selected steer is between 1200 and 1579 lbs is about 0.6915.

Round to four decimal places, the probability is 0.6915.

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The mean is 11.9 while the median is 10.5

Here, we want to calculate the mean and the median

Mathematically, the mean is the average of the numbers

We proceed as follows to find the mean;

To get the median, we simply re-arrange the values in the data set from the lowest to the highest

That will be;

6,7,9,10,11,16,16,20

The median term refers to the middle number

Since the number of terms here is even, then the median would be the average of the two 4th terms counting from both ends

Thus, the median is;

The median is 10.5

Answer:

Time varies, some people are awake

The measure of angle C if AB = 6 cm, ∠ A = 70°, ∠ B = 55° is 55° and the length of the side AC is 6 cm.

Three straight lines coming together create a triangle. There are three sides and three corners on every triangle (angles). A triangle's vertex is the intersection of two of its sides. Any one of a triangle's three sides can serve as its base, however typically the bottom side is used.

Given:

AB = 6 cm, ∠ A = 70°, ∠ B = 55°

Calculate the angle C by using the triangle interior angle property as shown below,

∠ A + ∠ B + ∠ C = 180

∠ C = 180 - 70 - 55

∠ C = 55

As the ∠ C = ∠ B = 55, then the side opposite to equal angles are also equal,

AB = AC = 6 cm

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The correct statement regarding the variation of the two measures is given as follows:

C. Yes, they vary directly. When one quantity increases, the other quantity also increases.

For this problem, we have that when the number of correct answers on the test increases, the score also does, hence the two quantities vary directly, and option c is the correct option for this problem.

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Answer:

6/n = n/18

n^2 = 108

n = sqrt 108

a^2 + b^2 = c^2

36 + 108 = m^2

144 = m^2

m=12

Let me know if this helps!

Answer:

B. sqrt 6 is the answer.maja

To find the vertices of the hyperbola given by the equation 4(x−1)^2 − (y+2)^2 = 1, we can compare it to the standard form equation of a hyperbola:

(x-h)^2/a^2 - (y-k)^2/b^2 = 1

From the given equation, we can see that h = 1, k = -2, a^2 = 1, and b^2 = 4.

The center of the hyperbola is at the point (h, k) = (1, -2).

The vertices of the hyperbola are located on the transverse axis, which is the line passing through the center and perpendicular to the conjugate axis.

The length of the transverse axis is 2a.

In this case, since a^2 = 1, we have a = 1.

So, the distance from the center to each vertex along the transverse axis is a = 1.

The vertex on the right side of the center is obtained by adding a to the x-coordinate of the center:

Vertex1: (1 + 1, -2) = (2, -2)

The vertex on the left side of the center is obtained by subtracting a from the x-coordinate of the center:

Vertex2: (1 - 1, -2) = (0, -2)

Therefore, the vertices of the hyperbola are (2, -2) and (0, -2).

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Let A = [2 -4 1 3]

1 -2 1 2

-2 4 1 -1

The reduced echelon form of A is

[1 -2 0 1]

0 0 1 1

0 0 0 0

a. Is x −

12

5

2

2

 in the null space of A.

To check if x −

 12

5

2

2

 is in the null space.

We need to check if it satisfies Ax = 0, where 0 is a zero vector.

x =  [x_1 x_2 x_3 x_4]^T  

=  [12/5, 2, 2, -5/2]^T.

The product Ax =  [2 -4 1 3]

\([12/5 2 2  -5/2]^T  1 -2 1 2 [2 -4 1 3][12/5 2 2 -5/2]^T  -2 4 1 -1 [2 -4 1 3][12/5 2 2 -5/2]^T[/text]

=  [32/5 -8/5 -8/5 0]^T.

 Therefore, x −  12 5 2 2  is not in the null space of A. b. Find a basis for the null space of A. The matrix A has two free variables x_2, and x_4. The solutions to Ax = 0 can be written as \([x_1 x_2 x_3 x_4]^T

=  [-2x_2 - x_4  x_2  -x_4  x_4  2x_2 + x_4]^T

=  x_2 [-2 1 0 2]^T + x_4 [-1 0 1 1]^T\).

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The values of a, b, c are 152°, 28°, 152° respectively.

Angles around a point describes the sum of angles that can be arranged together so that they form a full turn.

The sum of angles at a point will give 360°.

This means that a + b + c + 28 = 360

c +28 = 180° ( angle on a straight line)

c = 180 -28

c = 152°

c = a( alternate angles are equal)

therefore the value of a = 152°

b = 28( alternate angles are equal)

therefore the value of b is 28

therefore the values of a, b, c are 152°, 28°, 152° respectively

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The expression (-9+i)-(12-5i) can be represented to -21+6i.

A complex number is represented by the following form: a+bi, where a and b are real numbers.  The variables: a is the real part and bi imaginary part. See an example:

2 + 5i , then:

2 real part

5i imaginary part

About operations, the same properties used for real numbers can be applied to complex numbers. And for solving the operations math with these numbers, it is important to know that i²= -1. Thus, 9i² = 9*(-1)=-9.

When you sum or subtract complex numbers, you can only sum or subtract: the real part with the real part of each complex number and the imaginary part with the imaginary part of each complex number. See examples:

(2 + 5i) + (2 + 5i) = 4+10i

(4 + 10i) - (2 + 5i) = 2+5i

Therefore, the result for the (-9+i)-(12-5i) will be:

-9+i-12+5i= -21+6i

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Answer:

$3

Step-by-step explanation:

(80-62) ÷ 3

The probability that the sample proportion of first-time customers is less than 0.31 is approximately 0.7777 or 77.77%.

The probability that the sample proportion of first-time customers is less than 0.31 can be calculated using the normal distribution. The z-score is calculated based on the given proportion and the standard error, and then the probability is determined using the z-table.

To calculate the probability, we need to calculate the standard error, which is the square root of (p * (1 - p) / n), where p is the population proportion (0.29) and n is the sample size (179). Thus, the standard error is approximately 0.026.

Next, we calculate the z-score using the formula: z = (sample proportion - population proportion) / standard error. In this case, the sample proportion is 0.31, and the population proportion is 0.29. Substituting the values, we have z = (0.31 - 0.29) / 0.026, which is approximately 0.769.

Using the z-table or a statistical software, we can find the probability associated with a z-score of 0.769, which is approximately 0.7777 or 77.77%.

Therefore, the probability that the sample proportion of first-time customers is less than 0.31 is approximately 0.7777 or 77.77%.

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a. Probability that a randomly selected car is parked for under 5 hours:

To calculate this probability, we need to find the z-score for x = 5 hours and then find the corresponding area under the standard normal distribution curve.

Using the z-score formula: z = (x - μ) / σ

z = (5 - 4.5) / 1.2 = 0.4167 (rounded to 4 decimal places)

Looking up the z-score of 0.4167 in the standard normal distribution table or using a calculator, we find the corresponding area to be approximately 0.6611.

Therefore, P(x ≤ 5) = 0.6611.

The probability that a randomly selected car is parked for under 5 hours is 0.6611 or 66.11%.

b. Probability that 7 randomly selected cars are parked for at least 5 hours on average:

For the average of 7 cars, the mean (μx) remains the same at 4.5 hours, but the standard deviation (σx) changes.

Since we are considering the average of 7 cars, the standard deviation for the average (σx) can be calculated as σ / sqrt(n), where n is the number of cars.

n = 7 (number of cars)

σx = σ / sqrt(n) = 1.2 / sqrt(7) ≈ 0.4537 (rounded to 4 decimal places)

Now, we need to find the z-score for x = 5 hours using the new standard deviation (σx).

z = (x - μx) / σx = (5 - 4.5) / 0.4537 ≈ 1.103 (rounded to 3 decimal places)

Looking up the z-score of 1.103 in the standard normal distribution table or using a calculator, we find the corresponding area to be approximately 0.8671.

Therefore, P(x ≥ 5) = 1 - P(x ≤ 5) = 1 - 0.8671 = 0.1329.

The probability that the mean of 7 cars is greater than 5 hours is 0.1329 or 13.29%.

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Answer:

28-8-4x=0

x=5

5 days

Step-by-step explanation:

28-8=20 problems left

then 4 each day

Answer:

Step-by-step explanation:

Selling price = Cost price + Marked price - discount

            s   =  c + m - d

The function is neither even nor odd.

To find f(-x), we substitute -x for x in the function f(x):

f(-x) = (-x)^3 - 7/(-x) = -x^3 - 7/x

To find -f(x), we multiply the function f(x) by -1:

-f(x) = -1 * (x^3 - 7/x) = -x^3 + 7/x

To determine if the function is even, odd or neither, we compare f(-x) and -f(x).

If f(-x) = f(x), the function is even.

If f(-x) = -f(x), the function is odd.

If neither of these is true, the function is neither even nor odd.

Comparing f(-x) and -f(x), we have:

f(-x) = -x^3 - 7/x

-f(x) = -x^3 + 7/x

Since f(-x) and -f(x) are not equal, and f(-x) is not the negative of -f(x), the function is neither even nor odd.

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The probability from a batch of 1000 chocolate bars of getting at least 1 golden ticket is 2.47% and the probability of getting all 5 golden tickets is extremely low is 0.0000000121%.

We'll first calculate the probabilities of not getting a golden ticket and then use that to find the desired probabilities.

In Charlie and the Chocolate Factory, there are 5 golden tickets and 995 non-golden tickets in a batch of 1000 chocolate bars. When you purchase 5 chocolate bars, the probabilities are as follows:

1. Probability of getting at least 1 golden ticket:
To find this, we'll first calculate the probability of not getting any golden tickets in the 5 bars. The probability of not getting a golden ticket in one bar is 995/1000.

So, the probability of not getting any golden tickets in 5 bars is (995/1000)^5 ≈ 0.9752.

Therefore, the probability of getting at least 1 golden ticket is 1 - 0.9741 ≈ 0.02475 or 2.47%.

2. Probability of getting 5 golden tickets:
Since there are 5 golden tickets and you buy 5 chocolate bars, the probability of getting all 5 golden tickets is (5/1000) * (4/999) * (3/998) * (2/997) * (1/996) ≈ 1.21 × 10-¹³or 0.0000000000121%.

So, the probability of getting at least 1 golden ticket is 2.47% and the probability of getting all 5 golden tickets is extremely low, at 0.0000000121%.

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The term that describes an event that increases the likelihood of a response being repeated is known as reinforcement.

Reinforcement can be defined as any consequence that strengthens or increases the probability of a behavior occurring again in the future. This can include positive reinforcement, which involves adding a desirable consequence after a behavior, or negative reinforcement, which involves removing an aversive consequence after a behavior. Both types of reinforcement have been shown to be effective in increasing the likelihood of a behavior being repeated.

Overall, understanding the concept of reinforcement is essential in the field of psychology, particularly in the areas of behaviorism and behavior modification. By providing positive consequences after desired behaviors, individuals can be motivated to continue engaging in those behaviors, which can lead to long-term positive changes. Reinforcement can also be used to shape new behaviors or replace unwanted behaviors with more desirable ones.

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Therefore, the volume of the paper cone to the nearest tenth is 418.7 inches cubed.

The volume of the paper cone that Gretchen made to hold a gift for a friend is given by;V= (1/3)πr²hWhere;r = radius of the paper coneh = height of the paper coneπ = 3.14

Given that;Height of the paper cone (h) = 16 inches Radius of the paper cone (r) = 5 inchesWe are to find the volume (V) of the paper cone to the nearest tenth of an inch.

To obtain the volume of the paper cone, we can substitute the values of r and h in the formula above to obtain;

\(V= (1/3)\pir^2hV\)= \((\frac{1}{3} ) \times 3.14\times5^2 \times16V = (\frac{1}{3} ) \times 3.14\times25\times16V = (\frac{1}{3}) \times 1256V=418.7\)

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(a) The derivative of g(t) = ln[t + (cos²(t) / √(t))] is g'(t) = [1 + (2cos(t)(-sin(t))√(t) - (cos²(t) / (2√(t³))) / √(t)] / (t + (cos²(t) / √(t))). (b) The derivative of h(x) = (x²b+ 1)¹⁰ * sin(x) is h'(x) = (x² + 1)¹⁰ * cos(x) + sin(x) * 10(x² + 1)⁹ * 2x. (c) The derivative of f(x) = (ax + b) / (cx + k) is f'(x) = [(a * (cx + k) - (ax + b) * c) / (cx + k)²].

To find the derivative of the function g(t) = ln[t + (cos²(t) / √(t))], we can use the chain rule and the derivative of the natural logarithm function.

Let's break down the function g(t) into two parts:

f(t) = t + (cos^2(t) / sqrt(t))

g(t) = ln[f(t)]

Using the chain rule, the derivative of g(t) is given by:

g'(t) = f'(t) / f(t)

Now let's find the derivative of f(t):

f'(t) = 1 + (2cos(t)(-sin(t))√(t) - (cos²(t) / (2√(t³)))) / √(t)

Substituting this derivative into g'(t), we have:

To find the derivative of the function \(h(x) = (x^2 + 1)^10 * sin(x)\), we can use the product rule and the chain rule.

Let's break down the function h(x) into two parts:

\(f(x) = (x^2 + 1)^{10\)

g(x) = sin(x)

Using the product rule, the derivative of h(x) is given by:

h'(x) = f(x) * g'(x) + g(x) * f'(x)

The derivative of f(x) can be found using the chain rule:

\(f'(x) = 10(x^2 + 1)^9 * 2x\)

The derivative of g(x) is simply the derivative of the sine function:

g'(x) = cos(x)

Substituting these derivatives into the product rule formula, we have:

\(h'(x) = (x^2 + 1)^10 * cos(x) + sin(x) * 10(x^2 + 1)^9 * 2x\)

Simplifying this expression further may not be necessary unless specific values are provided.

Finally, the function f(x) = (ax + b) / (cx + k) is a rational function.

To find the derivative of f(x), we can use the quotient rule.

The quotient rule states that if we have a function of the form f(x) = g(x) / h(x), where g(x) and h(x) are differentiable functions, then the derivative of f(x) is given by:

\(f'(x) = (g'(x) * h(x) - g(x) * h'(x)) / (h(x))^2\)

Applying this rule to the function f(x) = (ax + b) / (cx + k), we have:

\(f'(x) = [(a * (cx + k) - (ax + b) * c) / (cx + k)^2]\)

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Answer:207

Step-by-step explanation: circumference = to 2πr or πd
substitute the diameter into the equation πd (22/7)(66) and you get 207.4285...

Answer:4.5y

Step-by-step explanation: you have to multiply 15 times 0.3 and u get 4.5y

If the numerator of a fraction decreases while the denominator remains constant, the value of the fraction decreases.

The numerator represents the number of parts we have out of the whole, while the denominator represents the total number of equal parts that make up the whole.

By decreasing the numerator, we are essentially reducing the number of parts we have, while the total number of parts remains the same. This means that the fraction represents a smaller portion of the whole, resulting in a smaller value.

Therefore, If the numerator of a fraction decreases while the denominator remains constant, the value of the fraction decreases.

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The "Assume Non-Negative" option in Excel Solver is helpful when the solution to a problem appears to depend on the starting values for the decision variables.

This option is particularly useful when working with linear programming problems where the solution depends on the values of the decision variables, and there is no clear starting point.

The "Assume Non-Negative" option instructs Solver to assume that all decision variables have non-negative values. This means that the solution will only be searched for in the non-negative space, which can help to narrow down the solution space and make the search more efficient.

In other words, Solver will not search for solutions that violate the non-negative constraint, which can save time and computational resources.

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The inflection points are (0, 3) and (1, 1). However, since the second derivative does not change sign at these points, they are not inflection points. Therefore, the answer is: DNE

To determine where the function is concave upward or downward, we need to find the second derivative and analyze its sign. For the function g(x) = 4x^3 - 6x^2 + 9x - 4, first, find the first derivative: g'(x) = 12x^2 - 12x + 9 Next, find the second derivative: g''(x) = 24x - 12

Now, find the intervals where g''(x) > 0 (concave upward) and g''(x) < 0 (concave downward): g''(x) > 0 => 24x - 12 > 0 => x > 1/2 g''(x) < 0 => 24x - 12 < 0 => x < 1/2

So, the function is concave upward on the interval (1/2, ∞) and concave downward on the interval (-∞, 1/2). To find the inflection point, we need to check the point where the concavity changes, which is x = 1/2: g(1/2) = 4(1/2)^3 - 6(1/2)^2 + 9(1/2) - 4 = -1/4

Thus, the inflection point is at (1/2, -1/4). For the function g(x) = 2x^4 - 4x^3 + 3, find the first and second derivatives: g'(x) = 8x^3 - 12x^2 g''(x) = 24x^2 - 24x

To find the inflection points, set the second derivative to zero: 24x^2 - 24x = 0 => 24x(x - 1) = 0 This yields two possible inflection points at x = 0 and x = 1: g(0) = 3 g(1) = 2 - 4 + 3 = 1.

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