Please answer thank you!

Answer:

Carbon Monoxide.

Regular equipment maintenance practices should include checking the recovery device for refrigerant leaks.

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Answer:

The efficiency of a DC generator is maximum when those losses proportional to the square of the load current are equal to the constant losses of the DC generator. This relation applies equally well to all rotating machines, regardless of the type of machine.

Explanation:

Answer:

I dont unverstand your question

F=m*a

F=80*20

F =1600 ans"

Answer: basically we are asked to find it's force and the formula that helps us to find force is Force= Mass× Acceleration

so let's put out the given and what we need to find

GIVEN. Solution

F=m.a

Mass= 1300. F=1300kg×20m/s

speed (Acceleration)=20m/2. F=26000Kg.m/s

Force=? F=26000N

N stands for Newton and the reason that it comes Newton is because it is the SI-unit of Force and the result of kg×m/s.

1) The number of gallons of water lost in a week would be approximately (2.3 m³/s * 604,800 seconds) * (1000 liters/m³) * (0.264172 gallons/liter).

2) The density of the copper sample is approximately 8.32 g/cm³ (347.5 g / 41.8 cm³).

To calculate the number of gallons of water lost in a week, we first need to determine the volume of water that flows through the stream in one week.

Given:

Flow rate of the stream = 2.3 m³/s

To convert the flow rate to the volume of water in one week, we need to convert the time unit from seconds to weeks. There are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and 7 days in a week.

1 week = 7 days * 24 hours * 60 minutes * 60 seconds = 604,800 seconds

Volume of water in one week = Flow rate * Time

Volume of water in one week = 2.3 m³/s * 604,800 seconds

Now, let's convert the volume from cubic meters (m³) to gallons.

1 cubic meter = 1000 liters

1 liter = 0.264172 gallons

Volume in gallons = (Volume in cubic meters) * (1000 liters/m³) * (0.264172 gallons/liter)

Finally, we can calculate the number of gallons of water lost in a week.

Volume in gallons = (2.3 m³/s * 604,800 seconds) * (1000 liters/m³) * (0.264172 gallons/liter)

Please note that the flow rate might change due to various factors, but for the given scenario and assumptions, this calculation provides an estimate.

1b) To calculate the density of the copper sample, we'll use the formula:

Density = Mass / Volume

Given:

Mass of the copper sample = 347.5 g

Volume of the copper sample = 41.8 cm³

Density = 347.5 g / 41.8 cm³

=8.32 g/cm³

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The entropy of 2 moles of and ideal gas expanding freely to 3 times it's initial volume is 18.3J/k

The following formula is required:

∆S = nx R x ℓn x (Vf/Vi)

Where

n = number of moles of gas (n = 2)

R = gas constant (R = 8.314 J/(mol * K))
Vf = final volume (Vf = 3.V1)

Vi = intial volume

Vi = 1L (Asumption )

∆S = 2 x 8.314 x 1.099

∆S =18.3 j/K

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Translation:

Calculate the entropy of 2 moles of an ideal gas expanding freely to three times its initial volume, use: ∆S =n・R・ℓn (Vf / Vi)

For the creation and production of mechanical components, including shafts, the American Society of Mechanical Engineers (ASME) offers standards and guidelines.

The ASME B107.1 "Standard for Socket Cap, Shoulder, Set, and Butt Screws (Inch Series)" code, which offers guidelines for the design and manufacture of shafts used with socket head screws, is one of the commonly used codes for shaft design.

The ASME B31.1 "Power Piping Code," which offers standards for the design and execution of piping systems used to transfer power, is another frequently used ASME code for shaft design.

The specific ASME code that is suited for a given application will rely on the needs and specifications of the that specific project. It is crucial to note that these are only two instances of ASME codes that can be used for shaft design.

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It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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The easiest way for the hotel to control for potential bias in their statistics would be to survey visitors at various periods throughout the year.

The hotel can make sure that the data in its survey of visitors is representative of those who stay there during various seasons, for various periods of time, and through various booking channels by conducting surveys of guests at random times throughout the year.

By solely surveying specific visitor subsets, any potential bias that might result will be reduced.

The most popular kind of guest satisfaction survey is the post-stay survey, which is given to guests after they have left the property and asks them about various elements of their stay.

Therefore, The easiest way for the hotel to control for potential bias in their statistics would be to survey visitors at various periods throughout the year.

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fitb. two of the most common types of communications hardware are _modems___ and network adapters

Answer:

A comprehensive Invitation for Bid (IFB) solicitation will describe the planned project in detail, lay out submission requirements including deadlines, project scope and duration, minimum qualifications, mandatory service standards, and required warranties.

All of the given are sources of particulate matter except road construction.

Since, Both option (a) combustion of biofuels and option (b) incomplete natural gas combustion are sources of particulate matter, as they both release small particles into the air that can be harmful to human health and the environment.

However, road construction does not typically involve the release of particulate matter into the environment.

Hence, Based on the information you provided, the answer would be option (c) road construction.

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This script requires the use of a circle structure because to find the high number lesser than,999 is more complex and time consuming so we take help from the circle structure.

What's circle structure?

You can constantly run one or further lines of law using circle structures in Visual Basic. The statements in a circle structure can be repeated formerly for each element in a collection, formerly until a condition is True, formerly until a condition is False, or a destined number of times.

To find the high number lesser than,999 we use

defget_prime( number)

if number == 2

return True#Number is high, exit system

if number 2 == 0

return False#Number isn't high, exit system

for n in range( 3, int( number), 2)#Start at 3, end at number, proliferation by 2

if number n == 0

return False#Number isn't high, exit system

return True#Number passed all tests, is provably high

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We must break down the forces acting on the eyeball into their component parts to calculate the required values ​​of T and (theta), and we must use the concept of equilibrium, which states that the net force acting on an object and net torque are both zero.

Let us examine in more detail the forces affecting the eyeball:

The equations for balancing in the x and y directions will now be presented as:

No pressure is acting in the x-direction, so the tension force is zero in that direction: T * cos(θ) = 0

T * sin(θ) + \(\rm F_1 + F_2 - F_3\)= 1200N (net pull force of 1200N in y-direction due to tension force in y-direction, f1, f2 and f3)

Let us now find the value of T and θ:

From the x-direction equation, we get:

T * cos(θ) = 0

T = 0

From the y-direction equation, we get:

0 + 500N + 800N - 600N = 1200N

T * sin(θ) = 1200N

T = 1200N / sin(θ)

Since T cannot be both 0 and 1200N, it implies that sin(θ) must be equal to 1:

sin(θ) = 1

To find θ, we take the inverse sine (or arcsine) of 1:

θ = arcsin(1)

The arcsine of 1 is 90 degrees or π/2 radians.

Therefore, the values are T = 1200N / sin(θ) = 1200N / 1 = 1200N and θ = 90 degrees or π/2 radians.

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Answer:

moving by turning over and over on an axis

A) one.

A virus typically requires only one host or carrier to replicate and initiate an infection.

Viruses are microscopic infectious agents that are composed of genetic material (DNA or RNA) surrounded by a protein coat. They lack the ability to reproduce on their own and depend on host cells to replicate. When a virus infects a host cell, it hijacks the cellular machinery to replicate its genetic material and produce more virus particles. These newly formed viruses can then go on to infect other cells within the same host or be transmitted to other individuals, initiating a chain of infection.

So, the correct answer is A) one.

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The set of numbers for which the square root of a number is greater than the square of the number is (0, 1).

In this range, the square root function grows faster than the squaring function.

For example, the square root of 0.25 is 0.5, while the square of 0.25 is 0.0625.

Since 0.5 is greater than 0.0625, the condition holds true. This is consistent for all numbers within the open interval (0, 1), where the endpoints are excluded.

The other sets mentioned, such as [0, 1], [1, 0], and (1, 0), do not meet the given criteria for all the numbers in the set.

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ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.

ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.

The person that is correct based on the 2 statements from Tech A and Tech B is; Tech B

A mass flow sensor is defined as a sensor that is used to measure the mass flow rate of air entering a fuel-injected internal combustion engine and then sends a voltage that represents the airflow to the electronic control circuit.

However, for Tech A is incorrect and so the correct answer is that Tech B is right because his statement corresponds with the definition of mass flow sensor.

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Answer:

Tech B is correct.

Explanation:

A mass flow sensor is basically sensor that checks the mass flow rate (hence the name) and then produces an electrical signal that copies the airflow going to the electronic control circuit. Smart technology, eh?

You don't have to give me brainliest, but I would greatly appreciate it! Thanks mate!

To print a photopolymer part faster with the same material and accuracy, you can increase the scan speed if you also decrease the laser power.

When using photopolymer materials in 3D printing, the scan speed refers to the speed at which the laser moves across the build area to cure the material. By increasing the scan speed, the laser moves faster, reducing the overall printing time. However, increasing the scan speed alone may compromise the accuracy of the printed part.

To maintain the same level of accuracy while increasing the scan speed, it is necessary to decrease the laser power. This ensures that the material is adequately cured even with the increased speed, preventing any quality issues or incomplete curing.

Therefore, the correct answer is to decrease the laser power.

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Hotel Fire Safety Directors are not authorized to order a full building evacuation of guests. Therefore, option (C) is correct.

Hotel Fire Safety Directors are individuals who are responsible for ensuring the safety of guests and employees in the event of a fire emergency in a hotel or other hospitality establishment.

They are typically appointed by the hotel management and must have knowledge of fire safety regulations and protocols, as well as the ability to lead and manage a team during an emergency.

Hotel Fire Safety Directors are responsible for implementing and maintaining the Fire Safety Plan, which includes conducting fire drills, training and supervising the Fire Brigade, and distributing applicable parts of the Fire Safety Plan to all employees. They must also work closely with the local fire department to ensure compliance with local fire safety regulations and protocols.

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Crystal systems are a way of classifying the geometric arrangement of atoms in a crystal lattice based on their symmetry. There are seven main crystal systems: Cubic, Tetragonal, Orthorhombic, Rhombohedral, Monoclinic, Triclinic, and Hexagonal.

Aluminum, copper, and iron all belong to the face-centered cubic (FCC) crystal system, which is a type of cubic crystal system. In the FCC arrangement, the crystal lattice consists of a cube with atoms at each corner and an additional atom at the center of each face of the cube. This arrangement is characterized by close-packed planes of atoms and efficient packing.

In the case of aluminum, copper, and iron, their atomic structures exhibit the FCC arrangement. The atoms of these elements arrange themselves in a face-centered cubic pattern, resulting in their crystalline structure.

The FCC crystal system is known for its symmetry and high packing efficiency, making it common among various metallic elements. It is worth noting that not all metals belong to the FCC crystal system, as different elements can have different crystal structures based on their atomic arrangements.

In summary, aluminum, copper, and iron belong to the face-centered cubic (FCC) crystal system, which is characterized by a close-packed arrangement of atoms and high packing efficiency.

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A full-wave rectifier with a capacitor-input filter that can output 35 V DC, support a 3.3 k load, and have a maximum peak-to-peak ripple voltage of 0.5 V requires a filter capacitor with a minimum capacitance of 892 F.

Average The arithmetic mean is calculated by adding a set of numbers, dividing by their count, and then taking the result. For instance, the average of 2, 3, 4, 5, 7, and 10 is 5, which is obtained by dividing 30 by 6.

The alternating current and voltage values in a circuit are given as instantaneous values. I equals 1/2sin(100 t) A. V = 12sin(100 t + 3).

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b) 100 percent cant be achieved by any single set of input. The if and else statements in while loop can be covered in different iteration by example (x=5 k=5 y=-4 covers blocks A, B, C, D, E, F, G, H, J. All except I). The if and else statements outside the while can't be covered simultaneosuly though.

c) Basis path possible (7):

1. A-B-G-H-J

2. A-(B-C-D-F)-B-G-H-J

3. A-(B-C-D-F)-B-G-I-J

4. A-(B-C-E-F)-B-G-H-J

5. A-(B-C-E-F)-B-G-I-J

6. A-(B-C-D-F)-B-C-E-F-B-G-I-J

7. A-(B-C-D-F)-B-C-E-F-B-G-H-J

Using the control structure of a program or module as a foundation, basis path testing is a white-box testing technique. A control flow graph is created using this structure, and as part of testing, different possible paths that are present in the graph are executed.

Choosing the paths in the control flow graph that offer a foundational set of execution paths through the program or module is a technique known as "basis path testing."

This testing necessitates complete program knowledge because it is based on the control structure of the program. Following four steps, test cases are created using this technique:

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A common application that is used for the rod and tube type of control is in a duct-mounted limit control.

A control system can be defined as a type of input and output system that is designed and developed to typically maintain stable (constant) conditions and processes, usually without excessive human interference.

In Control engineering, a duct-mounted limit control is a control system that is commonly used for the operation of the rod and tube type of control.

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Answer:

Visual connectivity refers to the tangible aspects of a space; extent to which a place can be viewed from other places. It is believed that the design properties of a spatial layout of an atrium leaves unobstructed views horizontally and vertically.

Explanation:

Answer:

1700 kg

Explanation:

Determine the total mass of the oil, m, by multiplying the density,

p= 850 kg/m3

to the volume, V = 2m3 or m=p x v.

m=pxv.

m= p x v = 850 kg / m3 x 2

m3 = 1700 kg

Given,Beamwidth in azimuth=1 degreeScanning rate=24 revolutions per minuteRadar pulsing frequency=600 HzTo find the number of pulses illuminate a target within a scan:The time required for 1 revolution of the antenna can be calculated as1 rev= 60 seconds/24 rev/min = 2.5 seconds.The azimuthal angle for a beam width of 1 degree is 0.5 degrees.

Therefore, the time required to scan an angle of 1 degree can be calculated as follows:The time taken for scanning 1 degree= (0.5/360) x 2.5 seconds= 0.0034722 seconds = 3.47 millisecondsThe time taken for a single pulse to illuminate the target is given by the reciprocal of the pulsing frequency.Number of pulses that illuminate the target in a scan = 1 scan/(time taken for a single pulse to illuminate the target)Number of pulses that illuminate the target in a scan= 1/ (1/600 Hz x 0.0034722 sec)Number of pulses that illuminate the target in a scan= 514.85 or 515 pulses.Therefore, the number of pulses that illuminate a target within a scan is approximately equal to 515.

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