Please answer the following question (in image).

Answer:

4 times that of nitrogen gas, N2.

Explanation:

Let R1 be the rate of diffusion of nitrogen gas, N2.

Let R2 be the rate of diffusion of Hydrogen gas, H2.

Let M1 be the molar mass N2

Let M2 be the molar mass of H2.

Next, we shall determine the molar mass of N2 and H2.

This is illustrated below below:

Molar mass of N2 (M1) = 2 x 14 = 28 g/mol

Molar mass of H2 (M2) = 2 x 1 = 2 g/mol

Finally, we shall determine the rate of diffusion of Hydrogen gas, H2 as follow:

R1/R2 = √(M2/M1)

M1 = 28

M2 = 2

R1/R2 = √(M2/M1)

R1/R2 = √(2/28)

R1/R2 = √(1/14)

R1/R2 = 0.27

Cross multiply

R1 = R2 × 0.27

Divide both side by 0.27

R2 = R1/0.27

R2 = R1 × 1/0.27

R2 = R1 × 4

R2 = 4R1

Therefore, the rate of diffusion of H2 (R2) is 4 times that of N2 (R1)

Answer:

b. between 2 s and 4 s

Explanation:

2-4 was both 3m/s

The velocity of sphere A after the collision is 1.67 m/s to the right. The kinetic energy of the system of spheres A and B after the first collision is 7.14 J.

p initial = m A * v A + m B * v B

p initial = (0.600 kg)(4.00 m/s) + (1.80 kg)(2.00 m/s)

p initial = 3.60 kg m/s

After the collision, the momentum of the system is:

p final = m A * v A' + m B * v B'

p initial = p final

m A * v A + m B * v B = m A * v A' + m B * v B'

Substituting the given values and solving for v A', we get:

v A' = (m A * v A + m B * v B - m B * Δv B) / m A

v A' = (0.600 kg)(4.00 m/s) + (1.80 kg)(2.00 m/s) - (1.80 kg)(1.00 m/s) / 0.600 kg

v A' = 1.67 m/s to the right

The kinetic energy of the system after the collision, we can use the formula:

K AB(ii) = (1/2) * m A * v A'²  + (1/2) * m B * v B'²

Substituting the given values, we get:

K AB(ii) = (1/2)(0.600 kg)(1.67 m/s)² + (1/2)(1.80 kg)(3.00 m/s)²

K AB(ii) = 7.14 J

The energy an item possesses as a result of its motion is known as kinetic energy. It is a scalar quantity and depends on both the mass and velocity of the object. The formula for calculating kinetic energy is KE = 1/2 mv^2, where KE represents kinetic energy, m represents the mass of the object, and v represents the velocity of the object.

As an object moves, its kinetic energy increases proportionally to its speed. The greater the mass of the object or the faster its velocity, the more kinetic energy it possesses. Conversely, as an object comes to a stop, its kinetic energy decreases and is converted to other forms of energy, such as potential energy or heat. Kinetic energy is a fundamental concept in physics and is important in understanding many natural phenomena.

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Complete Question:-

Find the kinetic energy K AB(ii) of the system of spheres A and B after the first collision. Express your answer with the appropriate units. View Available Hint(s) Sphere A. of mass 0.600 kg, is initially moving to the right at 4.00 m/s. Sphere B, of mass 1.80 kg, is initially to the right of sphere A and moving to the right at 2.00 m/s. After the two spheres collide, sphere B is moving at 3.00 m/s in the same direction as before.

(a) What is the velocity (magnitude and direction) of sphere A after this collision?

(b) Is this collision elastic or inelastic?

(c) Sphere B then has an off-center collision with sphere C, which has mass 1.60 kg and is initially at rest. After this collision, sphere B is moving at 19.0° to its initial direction at 1.80 m/s. What is the velocity ( magnitude and direction) of sphere C after this collision?

(d) What is the impulse (magnitude and direction) imparted to sphere B by sphere C when they collide?

(e) Is this second collision elastic or inelastic?

(f) What is the velocity (magnitude and direction) of the center of mass of the system of three spheres (A, B, and C) after the second collision?

No external forces act on any of the spheres in this problem. ?

To respond, one can say:

Venus and Mars are two planets in our solar system. Venus is the second planet from the Sun and is similar in size and composition to Earth. It is often referred to as Earth's "sister planet."

Mars, on the other hand, is the fourth planet from the Sun and is smaller than Earth. It is often referred to as the "Red Planet" due to its reddish appearance in the sky.

Both Venus and Mars have been the focus of much scientific study, particularly regarding their potential for supporting life.

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The energy transferred to the system is equal to the work done. For the endothermic process work done is negative. The power of the system is the product of work and time. Hence, the power is 315000 watt.

Endothermic reactions are those which absorbs energy into the system. Thus the surrounding temperature gets decreased.

The calorimetric equation connecting the heat transferred q, with the specific heat, mass and temperature difference is  written as:

q = m c ΔT

Here, the heat energy transferred is equal to the work done on the system. Hence W = - 1050 J

Power of the system is the product of work done and time taken for the energy transfer.

Power = W.dt

w = - 1050 J

t = 5 min = 300 s

Then P = 1050 J × 300 = 315000 watt.

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The sun is Yellow, red, orange, and blue. Therefore option B is correct.

The star is moving toward an observer. Therefore option B is correct.

39. The type of radioactive decay represented by the equation provided Gamma. Therefore option A is correct.

40. The statement is completed correctly by the information which states that the coal in Alberta has a lower carbon content than coal in other parts of Canada, resulting in reduced greenhouse gas emissions.

29. graph B depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth.

30. The correct sequence of colors representing the changing temperature from the surface to the atmosphere of the sun is Yellow, red, orange, and blue. Therefore option B is correct.

1. When a star undergoes a blue shift, it indicates that the star is moving toward an observer. Therefore option B is correct.

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Answer:12

Explanation:Average speed=Total Distance divided by Total Time.

Answer:

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside

Answer:

The change in time for the first quarter is  seconds.  = 2.07

The change in time for the second quarter is  seconds.

=1.09

The change in time for the third quarter is  seconds.

=0.95

The change in time for the fourth quarter is  seconds.=0.81

Explanation:

Hope this helped.

Answer: Equal to the mass of the carbon plus the mass of the oxygen

Explanation:

The solution is since the molar enthalpy of combustion for magnesium is 620 kJ/mol.

Enthalpy of Combustion (EoC) is the amount of energy released when a fuel is oxidized by an oxidizing agent.

25.5 kj of energy are released during the burning of a 1.0 g sample of magnesium to create MgO.

Magnesium has a molecular weight of 24.35g.

A mole of magnesium weighs 24.35 g.

1g = 1/24.35

The release of 25.5 kJ is for 0.04 moles.

25.5 * 1/.04 for 1 mole

= 620 kj/mol

As a result, magnesium has a molar enthalpy of combustion of 620 kJ/mol.

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A.The incline angle needs to be around 78.52° for the sphere to accelerate linearly at 0.70g.

B. The right answer is c. More than 0.70g of acceleration would be experienced.

(a) To find the incline angle for the uniform solid sphere with linear acceleration 0.70g, we can use the equation for the acceleration of a rolling sphere down an incline:

a = (5/7) * g * sin(theta)

Where a is the linear acceleration, g is the gravitational acceleration (9.81 m/s²), and theta is the incline angle. We are given a = 0.70g, so we can solve for theta:

0.70g = (5/7) * g * sin(theta)

Divide both sides by g:

0.70 = (5/7) * sin(theta)

Now, divide both sides by (5/7):

(0.70 * 7)/5 = sin(theta)

0.98 = sin(theta)

To find the angle, take the inverse sine of 0.98:

theta = sin^(-1)(0.98) ≈ 78.52°

So, the incline angle must be approximately 78.52° for the sphere to have a linear acceleration of 0.70g.

(b) If a frictionless block were to slide down the incline at that angle, its acceleration magnitude would be more than 0.70g. This is because the sphere's acceleration is reduced due to its rotation. A frictionless block doesn't have any rotation, so its acceleration down the incline is given by:

a_block = g * sin(theta)

Since sin(theta) is greater than the (5/7) factor in the sphere's acceleration equation, the acceleration of the frictionless block will be more than 0.70g. Therefore, the correct answer is c. The acceleration magnitude would be more than 0.70g.

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A uniform solid sphere rolls down an incline, the incline angle if the linear acceleration of the center of the sphere is to have magnitude 0.70g can be determined using-

The linear acceleration of the center of a uniform solid sphere rolling down an inclined plane is determined by the inclination angle of the plane.

It is determined by the formula a= g sin θ, where g is the acceleration due to gravity and θ is the angle of inclination.

For the linear acceleration of the center of the sphere to have a magnitude of 0.70g, we substitute 0.70g for a in the formula.

\(θ = sin⁻¹ (0.70) = 44.92°\)

Therefore, the inclination angle must be approximately 44.92 degrees for the linear acceleration of the center of the sphere to have a magnitude of 0.70g.

(b) If a frictionless block were to slide down the incline at that incline angle, would its acceleration magnitude be more less than or equal to 0.70g?

The acceleration of a frictionless block sliding down an inclined plane is determined by the formula a= g sin θ, where g is the acceleration due to gravity and θ is the angle of inclination.

Since the inclination angle of the plane is the same as in part (a), we can substitute 44.92° for θ in the formula

\(a= g sin θ = 9.81 × sin 44.92° = 6.78 m/s²\)

Since the magnitude of the acceleration of the block is less than 0.70g, the acceleration magnitude would be less than 0.70g. Therefore, option (b) is the correct answer.

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Considering the equivalence between mass and energy given by the expression of Einstein's theory of relativity, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.

The equivalence between mass and energy is given by the expression of Einstein's theory of relativity, where the energy of a body at rest (E) is equal to its mass (m) multiplied by the speed of light (c) squared:

E=m×c²

This indicates that an increase or decrease in energy in a system correspondingly increases or decreases its mass, and an increase or decrease in mass corresponds to an increase or decrease in energy.  

In other words, a change in the amount of energy E, of an object is directly proportional to a change in its mass m.

In this case, you know:

Replacing:

E= 1.05 kg× (3×10⁸ m/s)²

Solving:

E= 9.45×10¹⁶ J

Finally, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.

Learn more:

Answer:

populations found in equatorial areas will have the darkest skin (most eumelanin) and populations at higher latitudes will have lighter skin

Explanation:

if its right i cant really see what the question is asking

The possible valid accesses for an array a and vector v, each with 10 elements is given below:Array: a[0], a[1], a[2], a[3], a[4], a[5], a[6], a[7], a[8], a[9]Vector: v[0], v[1], v[2], v[3], v[4], v[5], v[6], v[7], v[8], v[9]

The term array is used to define a set of similar data types that are stored in contiguous memory blocks. The index of an array starts at 0, which means the first element of the array is stored at index 0. In the case of arrays, the elements must be of the same data type.The term vector is defined as a dynamic array, which means that the size of the vector can be changed during runtime. Vectors are defined in the same way as arrays, except that they have a dynamic size limit and can be easily resized.

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After considering all the statements about the implications of Hubble's Law, the false statement is not present.

The first statement is that although galaxies move away from each other, they themselves are not expanding in size. This statement is true. Hubble's Law states that the distance between galaxies is increasing over time, but it does not imply that the galaxies themselves are expanding in size. Instead, the expansion of the universe is causing the space between the galaxies to stretch out.

The second statement is that if you were observing the universe from a distant galaxy, you would not see all the galaxies (except those in your own group) moving away from you. This statement is also true. Hubble's Law applies to the large-scale structure of the universe, and the motion of individual galaxies within a group or cluster can be influenced by other factors such as gravity. So if you were in a distant galaxy, you would not see all other galaxies moving away from you due to these local effects.

The third statement is that the law implies that the whole universe must be expanding. This statement is true. Hubble's Law provides evidence that the universe is expanding uniformly in all directions, which suggests that the expansion is happening on a global scale rather than being caused by some local effect.

The fourth statement is that the law can be used to measure distances to remote galaxies for which we can measure a Doppler shift. This statement is also true. Hubble's Law relates the distance between galaxies and their recessional velocity, which can be measured using the Doppler shift of their light. By measuring the redshift of light from a distant galaxy, we can determine how fast it is moving away from us and use this information to estimate its distance.

Finally, the fifth statement is that the law does not require us to be at the center of the expanding universe. This statement is true. Hubble's Law is based on the observation that all galaxies are moving away from each other, regardless of their location in the universe. This means that there is no special point in the universe that can be considered the "center" of the expansion.

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The statement: An aircraft that flies faster than the speed of sound is said to be supersonic is true because supersonic refers to speeds that exceed the speed of sound.

When an aircraft travels at a speed faster than the speed of sound (approximately 767 miles per hour or 1,235 kilometers per hour at sea level), it is said to be supersonic.

At this point, the aircraft is moving faster than the sound waves it generates, resulting in a shock wave known as a sonic boom. The shock wave creates a characteristic loud noise heard on the ground.

Aircraft designed for supersonic flight, such as the Concorde or military jets like the F-22 Raptor, are built to withstand the aerodynamic challenges and increased temperatures that occur at these high speeds. The term "supersonic" distinguishes these aircraft from subsonic aircraft, which fly at speeds below the speed of sound.

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Additional time taken before the ball passes the tree branch is 1.13s.

Here we have to find the additional time.

Given data:

Initial velocity(u) = 15.8 m/s

x is the height at which the ball reaches the greatest height after the height of 6.81m.

Height =( 6.81 + x)m

Final velocity (v) = 0

Acceleration due to gravity (g) = 9.8 m/s²

Formula:

v = u + at

0 = 15.8 - 9.8t

t = 15.8/ 9.8

 = 1.66s

Now we have:

Average velocity = Average distance/ average time

0 + 15.8/ 2 = (x + 6.81)/ 1.66

7.9 × 1.66 = x + 6.81

13.114 - 6.81 = x

x = 6.30

As the distance is 6.30.

So the additional time taken is:

Average velocity = Average distance/ Average time

0+ v/ 2 = 6.30 / t

v = 12.6/t

Now we have

v = u + at

a = v-u/t

-9.8 =( 0 - 12.6/t)/ t

9.8 = 12.6/ t²

t² = 12.6/ 9.8

  = 9/ 7

t = 3/ 2.645

 = 1.13s

Therefore the time taken is 1.13s.

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Answer:

13.7 J

Explanation:

In absence of air resistance, the mechanical energy of the object is conserved during the fall: this means that the initial gravitational potential energy that it has at the beginning of the fall will be entirely converted into kinetic energy when the book is just about the hit the ground.

Therefore, this also means that we can calculate the mechanical energy at the beginning of the fall, as this will be equal to the mechanical energy just before the book hits the ground.

At the beginning of the fall, the mechanical energy is all gravitational potential energy:

where

m = 0.5 kg is the mass of the book

is the acceleration of gravity

h = 2.8 m is the height above the ground

Substituting,

Since Alejandro hopes to combine the findings from the collected studies and draw a general conclusion regarding the subject, he is using statistical tool of inference.

There are basically 2 types of statistical tools:

Descriptive tools are used to describe data. They include the use of tables, graphs, measures of dispersion, measures of central tendencies, etc.

Inferential tools are used to deduce conclusions from data. They include measures of significant differences, probability, correlation and regression, etc.

In this case, Alejandro would need to subject the data collected from the 35 studies to inferential statistical analysis tools in order to be able to make relevant conclusions.

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Answer:

Most aircraft that leave trails aren't leaving smoke. It's condensed water vapour; essentially, clouds. These are called contrails. This can be caused by the water in the engine exhaust condensing, or by the disruption of the air by the passage of the aircraft triggering the condensation of water that was already present. Some aerobatic aircraft have smoke generators which leave much thicker and more visible trails which can be turned on and off and don't depend on particular atmospheric conditions. White is most common but other colours are possible.

Answer:1.47

Explanation:

I got it correct on accelus

for example

1. drinking water at least after 1 hour beacuse if we immediately drink water just after meal it dilutes the HCL produced in our stomach which hinders the digestion process

2.picking up tomatoes for salads which contains oxalic acid

3.Cutting apples which contains malic acid with knife then after sometimes it will trun into brown due to oxidation of iron present in a apple.

A few examples of real science that demonstrate how scientific research and exploration contribute to our understanding of the world around us are the Human genome project, Mars exploration, and Climate Change Studies.

Human Genome Project:

The Human Genome Project (HGP) is a real scientific endeavor that aimed to map and sequence all the genes in the human genome. It involved an international collaboration of scientists and researchers to understand the genetic makeup of humans.

Mars Exploration:

Various space agencies, such as NASA and ESA, have conducted real scientific missions to explore Mars. Rovers like Curiosity and Perseverance have been sent to the Martian surface to study its geology, and atmosphere, and search for signs of past life.

Climate Change Studies:

Climate change research is an ongoing scientific field that investigates the causes and effects of global climate change. Scientists collect and analyze data from various sources, including satellite observations, weather stations, and ice core samples, to study trends and changes in Earth's climate over time.

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Answer:Joe's velocity leaving the ground is 1.00 m/s.

Explanation: The velocity of Joe immediately after leaving the ground can be calculated using the formula v = at, where a is the acceleration and t is the time. Joe's acceleration can be found using the equation F = ma, where F is the net force and m is the mass.So, Joe's acceleration can be calculated as a = F/m = 100N / 90kg = 1.11 m/s^2.Then, using v = at, we can calculate Joe's velocity as v = 1.11 m/s^2 x 0.9 s = 1.00 m/s. Therefore, Joe's velocity immediately after leaving the ground is 1.00 m/s.

Answer:

\(\beta=B=8.05\mu T\)

Explanation:

The density of the magnetic flux is given by the following formula:

\(\beta=\frac{\Phi_B}{A}=\frac{ABcos\theta}{A}=Bcos\theta\)

The normal vector A and the vector of the magnitude of the magnetic field are perpendicular, then, the angle is zero:

The magnitude of the magnetic field is calculated by using the formula for B at a distance of x to a point in the plane of the loop:

\(B=\frac{\mu_oIR^2}{2(x^2+R^2)^{3/2}}\)

For x = 0 you have:

\(B=\frac{\mu_oIR^2}{2R^3}=\frac{\mu_oI}{2R}\)

R is the radius of the circular loop and its values is:

\(R=\sqrt{\frac{A}{\pi}}=\sqrt{\frac{0.5m^2}{\pi}}=0.39m\)

Then, you replace in the equation for B with mu_o = 4\pi*10^-7 T/A:

\(B=\frac{(4\pi*10^{-7}T/A)(5A)}{2(0.39m)}=8.05*10^{-6}T=8.05\mu T\)

and the density of the magnetic flux is

\(\beta=B=8.05\mu T\)

Answer:

3

Explanation:

The apparent weight of the egg is 0.264N

Here the rocket is accelerating upward from the surface of the earth. The egg is on the rocket.

The acceleration due to gravity is 4.4m/\(s^{2}\).

The mass of a chicken egg is 0.060 kg.

Form Newton's second law, the net force acting on a body is equal to the product of mass and acceleration due to gravity.

So form Newton's second law we know the formula i.e.,

                     F = mass × acceleration

                        = 0.06 × 4.4

                        = 0.264N

Therefore the apparent weight of the egg is 0.264N.

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Answer: long handle

Explanation: they are better for tree planting and other hole-digging. Long shovel handles can reach deep into a hole. And you'll get better leverage, which is easier on your back. ... The lighter the shovel, the easier time you will have digging.

A measure of mass per unit of volume. It is how much material a certain volume contains. ... If the volume of the object stays the same but the mass of the object increases then its density becomes greater.