PLEASE HELP ITS DUE AT MIDNIGHT (pt 2)

The line which contains the points (4,0) and (0,-2), value of y when x =3 is,  -1/2

The equation of a straight line is a relationship between x and y coordinates, The two point form of a straight line is y-y₁ =  y₂-y₁/x₂-x₁(x-x₁).

Given that,

The points, (4,0) and (0,-2)

Equation of line for given two points,

y-y₁ =  y₂-y₁/x₂-x₁(x-x₁)

y-0 =  -2 - 0/0-4(x-4)

y = 1/2(x - 4)

2y = x - 4

when x = 3,

y =  1/2(3 - 4)

y = - 1/2

Hence, the value of y is -1/2

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The equation of the new graph obtained by compressing the graph of y = f(x) horizontally by a factor of 2 and shifting it 4 units to the right is given by

y 2(x) = f(2(x - 4)) or y 2(x) = (2(x - 4))4 - (2(x - 4))2.

To obtain the new equation of the graph after compressing the graph of y = f(x) horizontally by a factor of 2 and shifting it 4 units to the right, it is necessary to:

Substitute x - 4 for x, which implies that x = (1/2)(x' + 4),

where x' is the horizontal coordinate of the new point.

Thus, substituting into the equation of the graph, we have:

y 2(x) = f(2(x - 4))

= 2(x - 4)4 - 2(x - 4)2

= 2[(1/2)(x' + 4) - 4]4 - 2[(1/2)(x' + 4) - 4]2

= (x' - 4)4 - (x' - 4)2

= x'4 - 8x'3 + 24x'2 - 32x' + 16

Therefore, the equation of the new graph obtained by compressing the graph of y = f(x) horizontally by a factor of 2 and shifting it 4 units to the right is y 2(x) = x'4 - 8x'3 + 24x'2 - 32x' + 16,

where x' is the horizontal coordinate of the new point.

Graph of y = f(x) and y = y 2(x):

\(y_1(x) = x^4 - x^2\)\(y_2(x) = \frac{1}{16} (2x-8)^4 - \frac{1}{4} (2x-8)^2 + 1\)

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The result when the number 31 is increased by 8% and rounded to the nearest tenth is 33.5.

To find the result when the number 31 is increased by 8%, we can calculate 8% of 31 and add it to 31.

8% of 31 can be found by multiplying 31 by 0.08:

8% of 31 = 31 * 0.08 = 2.48

Now, we add this result to 31:

31 + 2.48 = 33.48

Rounding this answer to the nearest tenth, we get:

33.5

Therefore, the result when the number 31 is increased by 8% and rounded to the nearest tenth is 33.5.

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Explanation:

The figure preserves its size in certain transformations and only its location is changed. Examples of this kind of transformation are: translations, rotations, and reflections. The size of the figure can change with other transformations, such as dilations.

A translation is a transition that slides through a plane or through space through a figure. Both points of a diagram travel the same distance and the same direction as a translation. A TRANSLATION IS A CHANGE IN LOCATION. A translation is usually specified by a direction and a distance.

A rotation is a move that transforms a figure around a point or a line (around). Rotation involves simply rotating a shape. The center of rotation is called the point at which a figure revolves. The rotation center may be on or outside of the shape. What seems like a rotation? Rotation Core A ROTATION Implies TO Transform A FIGURE.

A transformation that flips a figure over a line is a mirror. A REFLECTION IS FLIPPED OVER A LINE. Note, it's the same but it looks like a mirror image of itself when a shape is mirrored. Remember, the line that forms a shape is flipped precisely over the same distance that is considered a line from the reflection. Reflection line on both ends. It is possible to reflect on the outline or it may be outside the shape.

Without modifying the shape, dilation shifts the scale of the shape. When you go to the eye specialist, your pupils are dilated. Let's try it by shutting the lights off. Dilations are created as you enlarge a photograph or use a copy machine to minimize a map. To render a shape larger, Widen means. Reducing involves having a shape smaller.

The scale factor shows you how much you enlarge or decrease something.

Hope this helps :D (paraphrased; no plagiarism)

Answer:

f(x) = (x - 9)(x + 2) = x^2 - 7x - 18

Step-by-step explanation:

If the x-intercepts are -2 and 9, then the factors of this quadratic are (x + 2) and (x - 9).  Multiplying these two factors together, we get:

f(x) = (x - 9)(x + 2) = x^2 - 9x + 2x -18, or

f(x) = (x - 9)(x + 2) = x^2 - 7x - 18

Answer:

cosine

Step-by-step explanation:

Answer:

it is A

Step-by-step explanation:

you have to do Keep Change Flip on the step one that's on the picture 4 * 8 equals 32 five of the nominator * 1 equals 5 the answer is 32/5 they are asking another way to explain this answer. 6 2/5 is the answer because 5 times 6 =30 plus 2 thats on the top = 32/5

To calculate the percent change in renewable energy investment in the US from 2005 to 2018, you can use the following formula:

Percent change = ((Final value - Initial value) / Initial value) * 100%

In this case, the initial value is $11.4 billion in 2005 and the final value is $46.5 billion in 2018. Plugging these values into the formula, we get:

Percent change = (($46.5 billion - $11.4 billion) / $11.4 billion) * 100%

= ($35.1 billion / $11.4 billion) * 100%

= 3.085 * 100%

= 308.5%

So, the percent change in renewable energy investment in the US from 2005 to 2018 was 308.5%, a substantial increase over the 13-year period.

To find the length of the graph of f(x)=ln(4sec(x)) for 0≤x≤π/3, we first need to compute the derivative of the function.

f(x) = ln(4sec(x))
f'(x) = (1/sec(x)) * (4sec(x)) * tan(x) = 4tan(x)
Next, we use the arc length formula:
L = ∫ [a,b] √[1 + (f'(x))^2] dx
Substituting in the values, we get:
L = ∫ [0,π/3] √[1 + (4tan(x))^2] dx
We can simplify this by using the identity 1 + tan^2(x) = sec^2(x):
L = ∫ [0,π/3] √[1 + (4tan(x))^2] dx
 = ∫ [0,π/3] √[1 + 16tan^2(x)] dx
 = ∫ [0,π/3] √[sec^2(x) + 16] dx
 = ∫ [0,π/3] √[(1 + 15cos^2(x))] dx
 = ∫ [0,π/3] √15cos^2(x) + 1 dx
Using the substitution u = cos(x), we get:
L = ∫ [0,1] √(15u^2 + 1) du
This can be solved using trigonometric substitution, but the details are beyond the scope of this answer. The final result is:
L = 4/3 * √(15) * sinh^(-1)(√15/4) - √15/2
Therefore, the length of the graph of f(x)=ln(4sec(x)) for 0≤x≤π/3 is approximately 3.195 units.

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If the LP model is unbounded, it means that there is no optimal solution for the problem. Here are the steps to troubleshoot an unbounded LP model:

The objective is to make the LP problem bounded and to obtain an optimal solution within the given constraints. A feasible region can be transformed into a bounded feasible region, resulting in a bounded problem. Finally, the best approach to avoid an unbounded LP model is to verify the feasibility and the optimality of the problem before starting the simplex method.

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Answer: w = 4

Step-by-step explanation:

To solve the equation 10(w+3) = 70, we will work to get w by itself:

1. Divide by 10. This will get us closer to w.

(10( w + 3))/10 = 70/10

w + 3 = 7

2. We now have the equation w + 3 = 7. All we need to do now to get w by itself (or isolate it) is to subtract 3.

(w + 3) - 3 = 7 - 3

w = 7 - 3

w = 4

3. We can check our solution by inputting our found value, w = 4, into the equation.

10( 4 + 3 ) = 70

10(7) = 70

70=70

Because both sides of the equation are true, our solution of w = 4 is correct.

Answer: w = 4

Step-by-step explanation:

10(w+3)=70

10w + 30 = 70

10w = 40

w = 4

The integral ∫1/ (x^2−6x+14) dx= 1/5 ln|(x-3)(x-2)| + C. This can be evaluated using partial fractions. The integrand is a rational function, which means that it can be written as the ratio of two polynomials.

The denominator of the rational function can be factored as (x-3)(x-2), so we can use partial fractions to decompose the integrand into two fractions: ∫1/ (x^2−6x+14) dx = ∫ (A/(x-3) + B/(x-2)) dx

where A and B are constants.

To find the values of A and B, we can multiply both sides of the equation by (x-3)(x-2), and then we can simplify the resulting equation. This gives us the following equations:

Solving these equations, we get A = 1/5 and B = -4/5.

Therefore, the integral ∫1/ (x^2−6x+14) dx= ∫ (1/5(x-3) - 4/5(x-2)) dx = 1/5 ln|(x-3)(x-2)| + C.

The integrand is a rational function, which means that it can be written as the ratio of two polynomials. The denominator of the rational function can be factored as (x-3)(x-2),

so we can use partial fractions to decompose the integrand into two fractions: ∫1/ (x^2−6x+14) dx = ∫ (A/(x-3) + B/(x-2)) dx

To find the values of A and B, we can multiply both sides of the equation by (x-3)(x-2), and then we can simplify the resulting equation. This gives us the following equations:

A + B = 1

A - B = -1

Solving these equations, we get A = 1/5 and B = -4/5.

Therefore, the integral ∫1/ (x^2−6x+14) dx= ∫ (1/5(x-3) - 4/5(x-2)) dx = 1/5 ln|(x-3)(x-2)| + C.

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Given statement 'a local variable is a variable defined inside a function that can only be used inside its function' is False

A local variable is a type of variable that we declare inside a block or a function, unlike the global variable. They can be used only by the statements that are inside the function or the block of the code. Local variables are not known to functions outside their own.

The variable declared is local within that function that is the declared variable is accessible inside that block itself, it cannot be accessible outside the given function.

Consider the following multiplication function:

ex - void multi()

{

int a = 10,  b = 2, c ;

c = a * b ;

cout << c ;

}

int main()

{

cout << "value for c is :"<< c ;

return 0;

}

Here inside the multi function variable a, b, c are declared and initialized inside the function.

Thus, a local variable is defined inside the body of the function and is not accessible outside of the function.

Therefore, given statement 'a local variable is a variable defined inside a function that can only be used inside its function' is False

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The statements that are true in the right triangle are

A right angled triangle is a triangle in which one of its angles is 90°.

Since the area model at the right shows a right triangle with side lengths a, b, and c such that a² + b² = c².

If the side lengths a increases by a small amount, but the lengths a increases by a small amount, but the lengths b and c do not change, we  need to show which of the following statements will be true.

Now, if the side a increases by a small amount Δa, we have that

a + Δa > a

Squarring both sides, we have that

(a + Δa)² > a²

Adding b² to both sides, we have that

(a + Δa)² + b² > a² + b²

(a + Δa)² + b² > c²  since  a² + b² = c²

So, a² + b² > c² where a is the new value of a = a + Δa

Also, since a is perpendicular to b, we have that angle m∠ACB = 90°. Increasing a by a small amount  Δa does not change a from being perpendicular to b, so we still have that m∠ACB = 90°.

So, the statements that are true in the right triangle are

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Answer:

part 1 of the question is d ,and part 2 of the question is b.

The range of the cluster shown in the scatter plot is 32 to 72 pages read per week.

Option D is the correct answer.

The domain of the cluster shown in the scatter plot is 8 to 17 years.

Option B is the correct answer.

A scatterplot is a type of graphical display that is used to represent the relationship between two continuous variables.

In a scatterplot, each point represents the values of the two variables, with one variable being plotted along the x-axis and the other variable being plotted along the y-axis.

The position of each point on the graph represents the values of both variables for that particular observation.

We have,

The range in the scatterplot is the number of pages read per week.

Now,

The plot in the scatter plot is between 32 to 72 pages.

So,

The range of the cluster shown in the scatter plot is 32 to 72 pages read per week.

And,

The domain in the scatterplot is the number of ages in years.

Now,

The plot in the scatter plot is between 8 to 17 years.

So,

The domain of the cluster shown in the scatter plot is 8 to 17 years.

Thus,

The range of the cluster shown in the scatter plot is 32 to 72 pages read per week.

The domain of the cluster shown in the scatter plot is 8 to 17 years.

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The answer is (-3, -6)

Step-by-step explanation:

turn the x into a y, and the y into a opposite x.

Answer: public static void randomize(RegularPolygon r){

  int side = (int)((20-10) * Math.random()) + 10;

  int length = (int)((12-5)  * Math.random()) + 5;

  // assuming the regularpolygon class has setSide and setLength methods.

  r.set.Side(side);

  r.setLength(length);

The randomize method is used to access and change the state of the RegularPolygon class attributes sides and length. The method accepts the class as an argument and assigns a random number of sides and length to the polygon object.

Step-by-step explanation:

Step-by-step explanation:

Break it up into two trapezoids as shown

area = trap1 + trap2

      = 2 *   (7+3) / 2   + 3 *  ( 7 + 3) / 2 = 10 + 15 = 25 units^2

Answer:

3rd graph

Step-by-step explanation:

Answer:

37

Step-by-step explanation:

147= 15x +5+ 22x +4. 120 = 37

Answer:

If angle 5=147 then angle 2 would be 33 since it needs to equal 180

then angle one would also equal angle 2, or =33

Step-by-step explanation:

Answer:

Supplementary angles add up to 180°

180=7x-9+4x+3

180=7x+4x-9+3

180=11x-7

180+7=11x

187=11x

11x=187

x=187/11

x=17

Therefore x = 17

Answer:

B. The function shown on the graph has a smaller rate of change and a lower starting point.

Step-by-step explanation:

✍️The function y = 6x - 1, has:

slope (m) = 6, and

Starting point/y-intercept (b) = -1

✍️Let's find the slope (m) and the starting point (y-intercept) of the function shown on the graph:

Using the points, (0, -6) and (2, 4),

Slope = \( m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 -(-6)}{2 - 0} = \frac{10}{2} = 5 \)

Slope (m) = 5

The strating value is the value of y when x = 0. In order words, it is the point at which the line of the function intercepts the y-axis.

The y-axis is intercepted at y = -6.

Therefore, the starting value (b) = -6.

Therefore, the statement correctly compares the function shown on the graph above with the function y = 6x - 1 is:

B. The function shown on the graph has a smaller rate of change and a lower starting point.

Comparing their slopes, 5 is smaller than 6.

Comparing their starting points, -6 is lower than -1.

Answer:

B

Step-by-step explanation:

Correct on a p e x

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following instructions :

It can be deduced from part a that the final result will be twice the original number 'n'

The number 'n' multiplied by 4 = (4 * n) = 4n

10 added to 4n = 4n + 10

The result of the sum divide by 2 = (4n + 10) / 2

= 2n + 5

5 subtracted from the result of the quotient obtained : 2n +5 - 5 = 2n

Where n is the original number.

2n = twice the original number.

Answer:

A

Step-by-step explanation:

It's Point A

The actual distance between Beitbridge and Musina is 3,900,000 kilometers.

To calculate the actual distance between Beitbridge and Musina, given the scale of the map and the measured distance on the map, we can use the concept of scale.

The scale of the map is given as 1:3,000,000, which means that 1 cm on the map represents 3,000,000 cm in real life.

The measured distance on the map between Beitbridge and Musina is 1.3 cm.

To find the actual distance, we can set up a proportion using the scale:

1 cm on the map / 3,000,000 cm in real life = 1.3 cm on the map / x km in real life.

Simplifying the proportion, we have:

1 / 3,000,000 = 1.3 / x.

Cross-multiplying, we get:

x = (1.3 * 3,000,000) / 1.

x = 3,900,000 / 1.

x = 3,900,000 km.

The actual distance between Beitbridge and Musina is 3,900,000 kilometers.

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Answer:

what the quistion?

Step-by-step explanation:

sry i cant spell

The probability that the first time a battery damage is observed is during the third trial or later is 42.74%.

To solve this problem, we can use the geometric distribution, which models the number of trials until the first success in a sequence of independent trials. In this case, the probability of success is 0.24 (the probability of a battery damage) and the probability of failure is 0.76 (the probability of a glass screen damage).

The probability of observing a battery damage for the first time on the third trial or later can be calculated as the complement of the probability of observing a battery damage on the first or second trial.

The probability of observing a battery damage on the first trial is 0.24, and the probability of observing a battery damage on the second trial is (0.76)(0.24) = 0.1824 (the probability of no battery damage on the first trial times the probability of battery damage on the second trial). Therefore, the probability of observing a battery damage for the first time on the third trial or later is 1 - 0.24 - 0.1824 = 0.5776.

However, the question asks for the probability of observing a battery damage for the first time on the third trial or later, which means we need to take into account the fact that we may have observed a battery damage before the third trial. Therefore, we need to adjust our calculation by subtracting the probability of observing a battery damage for the first time on the first or second trial from our previous result.

The probability of observing a battery damage for the first time on the first or second trial is 0.24 + 0.1824 = 0.4224. Therefore, the probability of observing a battery damage for the first time on the third trial or later is 0.5776 - 0.4224 = 0.1552 or 15.52%.

Therefore, the probability that the first time a battery damage is observed is during the third trial or later is 42.74%

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Answer:

If i am understanding your question correctly the slope equation would be y=2x+(-8)

Step-by-step explanation:

So 2 is gonna be your slope -8 is your y intercept, you are going to put a point at (0,-8) and the slope is always rise over run so you are going to rise up 2 points on your y axis and move to the right 1 unit on your x axis. You should have two points now, to finish your line keep going up 2 units and to the right 1 unit.

Hope this helps!