(please help me out )In a recent year, 33.1% of all registered doctors were female. If there were 46,600 female registered doctors that year, what was the total number of
registered doctors?
Round your answer to the nearest whole number

Answer:

I recommend that you use the intercept method to graph this, since it is in standard form Ax + By = C. This means to let x = 0, and solve for y, which gives you -5y = 10, so y = -2. Let y = 0, and solve for x, which gives you 3x = 10, so x = 10/3 or approx 3.3.

Step-by-step explanation:

hope this helps if not let me know

the answer is no solution

Concepts Used:                                                                                                    

Finding x:_____________________________________________            

From the Exterior angle property, we know that the measure of an exterior angle is the sum of the 2 opposite interior angles

So, using the property

(3x-10) = (25) + (x + 15)

3x - 10 = 25 + x + 15

3x - 10 = 40 + x

3x-x - 10 = 40              [subtracting x from both sides]

2x - 10 = 40

2x = 50                        [adding 10 on both sides]

x = 25                          [dividing both sides by 2]

Hence, the value of x is 25

m angle 6= 210

I'm not sure about this question

The center of the circle will be (4, -3) and the radius of the circle will be 6 units. Then the correct option is A.

A circle can be characterized by its center's location and its radius's length.

Let the center of the considered circle be at the (h,k) coordinate.

Let the radius of the circle be 'r' units.

Then, the equation of that circle would be:

(x - h)² + (y - k)² = r²

The equation is given below.

x² - 8x + y² + 6y - 11 = 0

     x² - 8x + y² + 6y = 11​​

Then the center and the radius of the circle will be

x² - 8x + 16 + y² + 6y + 9 = 11​ + 16 + 9

             (x - 4)² + (x + 3)² = 36

             (x - 4)² + (x + 3)² = 6²

Thus, the center and the radius of the circle will be (4, -3) and 6 units respectively.

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The number of problems which are finished by Liam from his homework sheet when his homework contains 40 problems is 32.

Percentage of a number is the part of the whole number which is expressed in the fraction of hundredth. It is represented with "%" symbol.

Jenny has finished 20 of the 25 math problems on her homework sheet. Thus, the total percentage of problems he finished is,

\(n=\dfrac{20}{25}\times100\\n=80\%\)

Liam has finished the same percent of problems from his homework sheet which is 80%. His homework contains 40 problems. Thus, the number of problems has Liam finished,

\(x=\dfrac{80}{100}\times40\\x=32\)

Hence, the number of problems which is finished by Liam from his homework sheet when his homework contains 40 problems is 32.

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1) The eigenvalues of Mi are ±1.

2) All Mi are traceless.

In the given problem, we are dealing with Hermitian matrices Mi that satisfy the equation MiMj + MiMi = 2δijI, where δij is the Kronecker delta symbol and I represents the identity matrix.

To show that the eigenvalues of Mi are ±1, we can consider the eigenvector equation Mi|v⟩ = λ|v⟩, where |v⟩ is an eigenvector of Mi and λ is the corresponding eigenvalue.

Let's assume λ is an eigenvalue of Mi and |v⟩ is the associated eigenvector. Taking the inner product of both sides with ⟨v| (the conjugate transpose of |v⟩), we have:

⟨v|Mi|v⟩ = λ⟨v|v⟩

Since Mi is Hermitian, ⟨v|Mi|v⟩ is a real number. Similarly, ⟨v|v⟩ is also a real number because the inner product of a vector with its conjugate transpose is always real.

Now, let's evaluate the left-hand side of the equation using the given properties of Mi:

⟨v|Mi|v⟩ = ⟨v|MiMi + MiMi|v⟩/2 = ⟨v|2I|v⟩/2 = 2⟨v|v⟩/2 = ⟨v|v⟩

Substituting this back into the eigenvector equation, we have:

λ⟨v|v⟩ = ⟨v|v⟩

Since ⟨v|v⟩ is a nonzero real number (the norm of a vector is nonzero unless the vector is the zero vector), we can divide both sides of the equation by ⟨v|v⟩ to obtain:

λ = 1

Therefore, the eigenvalues of Mi are ±1.

To show that all Mi are traceless, we need to demonstrate that the trace of each matrix Mi is zero. The trace of a matrix is defined as the sum of its diagonal elements.

Consider the trace of Mi:

Tr(Mi) = Tr(MiMi + MiMi)/2 = Tr(2δiiI)/2 = Tr(2I)/2 = Tr(I) = dim(I)

Since the identity matrix I has dimensions equal to the size of Mi (4x4 in this case), the trace of I is equal to the dimension of I. Therefore, Tr(Mi) = dim(I).

However, the trace of Mi is also given by the sum of its eigenvalues. From Step 1, we know that the eigenvalues of Mi are ±1. Since the sum of ±1 is zero, the trace of Mi is also zero.

Hence, we have shown that all Mi are traceless.

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Answer:

The answer is C≈49.64

Answer:

C=2πr=2·π·7.9≈49.63716

Step-by-step explanation:

brainliest??

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

For question 5:

For point a:

\(\to y=x^2\)

For point b:

\(Maximum (0,0)\)

For point c:

\(Domain: (-\infty,+ \infty)\\\\Range: (-\infty, 0)\)

For question 6:

For point a:

\(\to y=-x^2\)   (the negative sign is used to change the direction of the parabola)

For point b:

\(Maximum (0,0)\)

For point c:

\(Domain: (-\infty,+ \infty)\\\\Range: (0,+\infty)\)

Answer:

Equilateral triangles are sometimes

acute triangles.

Scalene triangles are never

acute triangles.

Right triangles are never

acute triangles.

Obtuse triangles are always

isosceles triangles.

The sum of all edges of the regular quadrilateral Pyramid is approximately 66.68 cm.

The sum of all edges of a regular quadrilateral pyramid, we need to determine the number of edges in the pyramid and then calculate their total length.

A regular quadrilateral pyramid has a base that is a regular quadrilateral, meaning all sides of the base have the same length. Let's assume that each side of the base has a length of "a" cm.

The perimeter of the base is given as P = 30 cm, so each side of the base measures 30 cm divided by 4 (since there are four equal sides) which is 7.5 cm.

Now, let's consider the lateral face of the pyramid. A regular quadrilateral pyramid has four lateral faces, each of which is an isosceles triangle. The perimeter of a lateral face is given as 27.5 cm. Since there are three edges in each lateral face, the length of each edge is 27.5 cm divided by 3, which is approximately 9.17 cm.

Therefore, the sum of all the edges in the pyramid is calculated as follows:

Sum of edges = (4 × a) + (4 × 9.17)

Since we know that each side of the base (a) is 7.5 cm, we can substitute this value into the equation:

Sum of edges = (4 × 7.5) + (4 × 9.17)

            = 30 + 36.68

            = 66.68 cm

Hence, the sum of all edges of the regular quadrilateral pyramid is approximately 66.68 cm.

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Hope you could understand.

If you have any query, feel free to ask.

Answer:-6

Step-by-step explanation:

18=9x(n+8) so if "n" = -7 then -6+8 is 2, and 2x9 is 18

Answer:

A data represent an exponential function because there is a common ratio of 1

Answer:

(5h-4t)(5h+4t)

Step-by-step explanation:

25h² - 16t²

adding  and subtracting 20ht from it        (√25 and √16 = 5x4 = 20):

25h² + 20ht - 20ht -16t²

factor:

(5h-4t)(5h+4t)

Answer:

(5h - 4t)(5h + 4t)

Step-by-step explanation:

25 h² - 16t² ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

Then

25h² - 16t²

= (5h)² - (4t)²

= (5h - 4t)(5h + 4t) ← in factored form

Answer:

answer of question 28 is 8/13(D)

Answer:

Step-by-step explanation:

When using the substitution method we use the fact that if two expressions y and x are of equal value x=y, then x may replace y or vice versa in another expression without changing the value of the expression.

Solve the systems of equations using the substitution method

{y=2x+4

{y=3x+2

We substitute the y in the top equation with the expression for the second equation:

2x+4            =      3x+2

4−2              =        3x−2

2===             =         x

To determine the y-value, we may proceed by inserting our x-value in any of the equations. We select the first equation:

y= 2x + 4

We plug in x=2 and get

y=  2⋅2+4 = 8

The elimination method requires us to add or subtract the equations in order to eliminate either x or y, often one may not proceed with the addition directly without first multiplying either the first or second equation by some value.

Example:

2x−2y = 8

x+y = 1

We now wish to add the two equations but it will not result in either x or y being eliminated. Therefore we must multiply the second equation by 2 on both sides and get:

2x−2y = 8

2x+2y = 2

Now we attempt to add our system of equations. We commence with the x-terms on the left, and the y-terms thereafter and finally with the numbers on the right side:

(2x+2x)  + (−2y+2y) =  8+2

The y-terms have now been eliminated and we now have an equation with only one variable:

4x = 10

x= 10/4 =2.5

Thereafter, in order to determine the y-value we insert x=2.5 in one of the equations. We select the first:

2⋅2.5−2y     =  8

5−8             = 2y

−3               =2y

−3/2            =y

y                 =-1.5

Answer:

1. No, because a system of linear equations in two variables may have, zero,  or infinietley solutions.

2. true because the answer of a system is the intersect, not where the lines cross a grid.

3.a. y=2x+4

y=3x+2

2x+4=3x+2

4-2=3x-2

2=x

b.y=2x+4

y=2*2+4=8

c. 2.2.5-2y=8

5-8=2y

=3=2y

-3/2=y

y=1.5

Step-by-step explanation:

answers for teh complete assigment

Answer:

The graph of the polynomial function f(x) = x^4 + x^3 - 2x^2 will depend on the behavior of the function as x approaches infinity and negative infinity, as well as the location and behavior of any local extrema.

To determine the behavior of the function as x approaches infinity and negative infinity, we can look at the leading term of the polynomial, which is x^4. As x becomes very large (either positive or negative), the x^4 term will dominate the expression, and f(x) will become very large in magnitude. Therefore, the graph of the function will approach positive or negative infinity as x approaches infinity or negative infinity, respectively.

To find any local extrema, we can take the derivative of the function and set it equal to zero:

f(x) = x^4 + x^3 - 2x^2

f'(x) = 4x^3 + 3x^2 - 4x

Setting f'(x) equal to zero, we get:

4x(x^2 + 3/4x - 1) = 0

The solutions to this equation are x = 0 and the roots of the quadratic expression x^2 + 3/4x - 1. Using the quadratic formula, we can find these roots to be:

x = (-3 ± sqrt(33))/8

Therefore, the critical points of the function are x = 0 and x = (-3 ± sqrt(33))/8.

To determine the behavior of the function near each critical point, we can use the second derivative test. Taking the second derivative of f(x), we get:

f''(x) = 12x^2 + 6x - 4

Evaluating f''(0), we get:

f''(0) = -4

Since f''(0) is negative, we know that x = 0 is a local maximum of the function.

Evaluating f''((-3 + sqrt(33))/8), we get:

f''((-3 + sqrt(33))/8) = 11 + 3 sqrt(33)/2

Since f''((-3 + sqrt(33))/8) is positive, we know that x = (-3 + sqrt(33))/8 is a local minimum of the function.

Evaluating f''((-3 - sqrt(33))/8), we get:

f''((-3 - sqrt(33))/8) = 11 - 3 sqrt(33)/2

Since f''((-3 - sqrt(33))/8) is also positive, we know that x = (-3 - sqrt(33))/8 is another local minimum of the function.

Based on this information, we can sketch the graph of the function as follows:

Therefore, the statement that describes the graph of this polynomial function is: "The graph of the function has a local maximum at x = 0 and two local minima at x = (-3 ± sqrt(33))/8. As x approaches infinity or negative infinity, the graph of the function approaches positive or negative infinity, respectively."

Answer: A. 7pi>21.

7 times pi is 21.9911486, which is more than 21, which would mean this equation is correct.

n +4 is 7.14159265, which means that the less than sign should be facing the opposite way, this one is incorrect.

3 times pi minus 1 is 5.14159265, which is less than nine, meaning the greater than sign should be facing the opposite way, this equation is incorrect.

Lastly 12/4pi is 0.954929659, which is less than 1, the sign once again is facing the wrong way, this problem is incorrect.

This means our correct answer is A. 7pi>21.

HOPE THIS HELPS & GOOD LUCK

Answer:

Nick is 49 kg

Step-by-step explanation:

Let N be Nick's weight in kg and R be Rick's weight in kg

We have the ratio

\(\frac{N}{R}=\frac{7}{5}\)   ==> \(R=\frac{5N}{7}\)

The second statement can be mathematically stated as

N - 4 = R + 10  (If Nick loses 4kg and Rick gains 10kg they are both same wt)

Substitute for R in terms of N

\(N - 4 = \frac{5N}{7}+10N\)

\(N - \frac{5N}{7} = 14\)

Multiplying both sides by 7 will get rid of the denominator

7N -5N = 98 ==> 2N=98  ==> N=49

We can easily verify our answer

If Nick is 49, Rick must be (5/7)49 = 35.

N-4 = 49-4 = 45

R+10 = 35 + 10 = 45

And we see they are both the same value

There are over 6 quadrillion ways to make starting hands for Derek, Margaret, and Lenny!

We can start by finding the number of ways to choose 7 cards out of the 52 for Derek, then the number of ways to choose 7 cards out of the remaining 45 for Margaret, and then the remaining cards (which will form Lenny's hand).

The number of ways to choose 7 cards out of 52 is:

C(52,7) = 133,784,560

Once Derek has his 7 cards, there are 45 cards remaining, so the number of ways to choose 7 cards for Margaret is:

C(45,7) = 45,379,620

Finally, Lenny gets the remaining cards, so there is only one way to choose his hand.

Therefore, the total number of ways to make starting hands for all three players is:

133,784,560 x 45,379,620 x 1 = 6,081,679,822,404,800

So there are over 6 quadrillion ways to make starting hands for Derek, Margaret, and Lenny!

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Grace can use the fraction 3 / 5 of the distance from point A and 2 / 5 of the distance from point B to determine the x coordinate of point C.

Herein we find the case of a point partitioning a line segment by observing a given ratio. The equation that observes this fraction is shown below:

AC / BC = 2 / 3

AC / AB = 2 / 5

Vectorially speaking, this is equivalent to the following equation:

C(x, y) - A(x, y) = (2 / 5) · [B(x, y) - A(x, y)]

C(x, y) = (3 / 5) · A(x, y) + (2 / 5) · B(x, y)

If we know that A(x, y) = (3, 2) and B(x, y) = (6, 11), then the coordinates of point C are, respectively:

C(x, y) = (3 / 5) · (3, 2) + (2 / 5) · (6, 11)

C(x, y) = (9 / 5, 6 / 5) + (12 / 5, 22 / 5)

C(x, y) = (21 / 5, 28 / 5)

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Answer:

Step-by-step explanation:

Fractions represent a division problem where the numerator is divided by the denominator. For example, the fraction 3/4 represents the division of 3 by 4, which can be written as 3 ÷ 4. This is why it makes sense that fractions are about division.

Furthermore, fractions are used to represent parts of a whole or a group. When we divide a whole into equal parts, we are essentially dividing the whole into groups, with each group having the same size. For example, if we divide a pizza into 8 equal slices, each slice represents 1/8th of the pizza. We can also think of this as dividing the pizza into 8 equal groups, with each group having one slice.

Therefore, fractions are a natural way to represent division, as they allow us to express how many parts we have out of a whole or a group, and how big each part is relative to the whole or group.

There are 18 candy per ounce in the jar, using the unit rate.

Unit rate is the amount of a certain item related to a single unit of another item.

In the question, we are given that there are 252 pieces of candy in a 14 ounce jar.

We are asked for the pieces of candy which are there per ounce in the jar, which will be the unit rate of number of candies per ounce.

The pieces of candy in a 14 ounce jar is given to be 252.

Thus, the number of candy per ounce in the jar can be calculated as:

14 ounce ⇒ 252 candy

or, 1 ounce ⇒ 252/14 candy = 18 candy.

Thus, there are 18 candy per ounce in the jar, using the unit rate.

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There are 18 pieces of candy per ounce in the jar.

What is a unitary method?

⇒ The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

We have been given that 252 pieces of candy are in a 14-ounce jar.

We need to find the number of pieces of candy that should be there in the jar per ounce.

The number of pieces of candy per ounce is given by

⇒ Number of pieces of candy / Quantity of jar

= 252/14

=18

Hence, there are 18 pieces of candy per ounce in the jar.

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The Standard form of a number is also known as "Scientific notation". The form is:

Where the coefficient "a" is a number from 1 to 10, but not including 10, and the exponent "b" is an Integer. The base is always 10.

By definition, the decimal point must be after the first digit of the coefficient.

In this case, in order to write 36 in Standard form, you must move the decimal point one place to the left:

Notice that the exponent is 1 because you had to move the decimal point one place to the left in order to locate it after the first digit of the coefficient.

Now, to write the exponent form of a number is:

Where the exponent "n" indicates how many times "b" must be multiplied by itself.

You know that:

Then:

The answer is:

a. Exponent form:

b. Standard form:

Answer: The form of payment that Courtney can lose and not get back would be cash.

Step-by-step explanation:

The reason why cash couldn't be returned back because it doesn't have a piece of U.S money wouldn't have a specific certified owner that they can be returned to.

Other forms of payment like credit cards, debit cards, and checks have specific bank information with the card holder's name on it so if Courtney actually lost one of those, she would be most likely to receive it back without any complicated  verification process.

Therefore, Courtney would not be able to receive her cash back if she accidentally loses it. Hope this helps you with your Imagine Math homework or assignment!

-From Certified 5th Grade Honors Student

Calculate the distance d(p, q) between p and q.3. If d(p, q) is less than the minimum distance, update the minimum distance variable.4. When all pairs of points have been checked, return the pair of points with the minimum distance.

The brute force approach for the closest pair algorithm is a basic operation that finds the two closest points among the given set of points. This algorithm is simple but requires more time than other approaches. The algorithm's running time is O(n²) for n points and is not appropriate for large datasets because the time complexity would be extremely high. It works by comparing each pair of points and calculating the distance between them. The pair of points with the minimum distance is then returned as the closest pair.Here is how the algorithm works: 1. Define a distance function d(p, q) for points p and q.2. Set a minimum distance variable to an arbitrarily large number.3. For each point p in the set of points: 1. For each point q in the set of points: 1. If p and q are the same point, skip to the next q.2. Calculate the distance d(p, q) between p and q.3. If d(p, q) is less than the minimum distance, update the minimum distance variable.4. When all pairs of points have been checked, return the pair of points with the minimum distance.

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Recognize, group, add or subtract, simplify, change sign, and distribute coefficients to simplify polynomials.

1. Recognize and group related terms.

2. Use addition or subtraction to combine similar terms.

3. Make the polynomial simpler.

Coefficients should be distributed and combined.

5. Change the sign of the coefficients of similar terms.

6. Make the polynomial simpler.

The first step in adding or subtracting polynomials is to recognise and group similar terms. Finding terms that have similar variable powers is necessary because these are the terms that can be merged. The next step is to combine the like terms by either adding or deleting once they have been found. The coefficient of the term being subtracted must have its sign altered to the opposite in order to subtract.The polynomial can be made simpler by deleting any parentheses and merging any coefficients after like terms have been combined. The next step is to distribute and combine coefficients if there are numerous terms. This entails doubling the term's coefficients before combining it with terms of the same variable powers. The polynomial can then be simplified by adding or subtracting the coefficients of comparable terms. For instance, combining related terms can result in the polynomials

(3x + 2) and (3x - 4), which simplify to (3x + 2 + 3x - 4). (6x – 2).

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Answer:

Option (C)

Step-by-step explanation:

If two functions are f(x) and k(x),

(f o g)(x) = f[g(x)]

From the question given in the picture attached,

We have to find the value of (h o k)(1).

(h o k)(x) = h[k(x)]

              = h[k(1)]

              = h(3) [Since, k(1) = 3]

              = 28 [Since, h(3) = 28]

Therefore, (h o k)(1) = 28 will be the answer.

Option (C) will be the correct option.

The correct option is C.

If two functions are f(x) and k(x),

(f o g)(x) = f[g(x)]

Now according to the picture

We have to find the value of (h o k)(1).

(h o k)(x) = h[k(x)]

              = h[k(1)]

              = h(3) [Since, k(1) = 3]

              = 28 [Since, h(3) = 28]

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