Please help me to answer and explain how you get the answer to number 11. Thank you.

Answer:

Maximum height = 2040 m

Explanation:

We can solve the problem using kinematics.

Consider the vertical motion of the object and use the equation:

\(\boxed{v^2 = u^2 + 2as}\)

where:

• v = final velocity      (0 m/s, because when the object is at max. height, it has no vertical velocity)

• u = initial velocity    (400sin30° m/s ⇒ vertical component of 400 m/s at 30° to horizontal)

• a = acceleration      (-9.81 m/s²; considering upward acceleration to be negative)

• s = displacement    (? m; this represents the max. height of the object),

Substitute the values into the equation and solve for s :

\(0^2 = (400 sin (30 \textdegree))^2 + 2(-9.81)(s)\)

⇒ \(2(9.81)(s) = (400 sin (30 \textdegree))^2\)

⇒  \(s = 2040 \space\ m\)     (3 s.f.)

Answer:

a) the maximum shear stress τ\(_{max}\) the bar is 16T\(_{max}\) /πd³

b) the angle of twist between the ends of the bar is 16tL² / πGd⁴  

Explanation:

Given the data in the question, as illustrated in the image below;

d is the diameter of the prismatic bar of length AB

t is the intensity of distributed torque

(a) Determine the maximum shear stress tmax in the bar

Maximum Applied torque  T_max = tL

we know that;

shear stress τ = 16T/πd³

where d is the diameter

so

τ\(_{max}\) = 16T\(_{max}\) /πd³

Therefore, the maximum shear stress τ\(_{max}\) the bar is 16T\(_{max}\) /πd³

(b) Determine the angle of twist between the ends of the bar.

let theta (\(\theta\)) be the angle of twist

polar moment of inertia \(I_p}\) = πd⁴/32

now from the second image;

lets length dx which is at distance of "x" from "B"

Torque distance x

T(x) = tx

Elemental angle twist = d\(\theta\) = T(x)dx / G\(I_{p}\)

so

d\(\theta\) = tx.dx / G(πd⁴/32)

d\(\theta\) = 32tx.dx / πGd⁴

so total angle of twist \(\theta\) will be;

\(\theta\) =  \(\int\limits^L_0 \, d\theta\)

\(\theta\) =  \(\int\limits^L_0 \,\) 32tx.dx / πGd⁴

\(\theta\) = 32t / πGd⁴  \(\int\limits^L_0 \, xdx\)

\(\theta\) = 32t / πGd⁴ [ L²/2]

\(\theta\) = 16tL² / πGd⁴  

Therefore,  the angle of twist between the ends of the bar is 16tL² / πGd⁴  

a. The electric field above the planar insulating sheet is Ej = (σ/ε₀)j

b. The electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j

The electric field above the planar insulating sheet is Ej = (σ/ε₀)j

Using Gauss' law ε₀∫E.dA = q where

Now, ε₀∫E.dA = q

ε₀∫Ej.dAj = σA

ε₀∫EdA = σA

ε₀E∫dA = σA

ε₀EA = σA

ε₀E = σ

E = σ/ε₀

So, the electric field above the planar insulating sheet is Ej = (σ/ε₀)j

The electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j

Using Gauss' law ε₀∫E.dA = q where

Now, ε₀∫E.dA = q

ε₀∫-Ej.-dAj = σA

ε₀∫EdA = σA

ε₀E∫dA = σA

ε₀EA = σA

ε₀E = σ

E = σ/ε₀

So, the electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j

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Answer: the correct answer should be B

Explanation:

The statement that, best describes a difference between laser light and regular light is laser light is made of one specific color.

A laser light is a light produced by a laser

Laser itself,  is a device that emits light through a process of optical amplification based on the stimulated emission of electromagnetic radiation.

Thus, the statement that, best describes a difference between laser light and regular light is laser light is made of one specific color.

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Answer:

3.35

Explanation:

Got it on Acellus

The light of wavelength 485 nm passes through a single slit. The single between the first (m=1) and second (m=2) interference minima is 3.36°.

Diffraction is the phenomenon of bending of waves through obstacles.  

Given is the wavelength λ= 485 nm, silt width d =  8.32 *10⁻⁶ m, then the angle θ will be

d sinθ =mλ

for m=1, sin θ₁ = λ/d

for m=2, sin θ₂ = 2λ/d

Substitute the values into both expressions to find the angles,

sin θ₁ = 485 x 10⁻⁹ /  8.32 *10⁻⁶

θ₁ = 3.34°

and sin θ₂ = (2 x  485 x 10⁻⁹ )/  8.32 *10⁻⁶

θ₂ = 6.7°

The angle between m =1 and m=2 will be

θ₂ -θ₁ = 6.7° - 3.34° =3.36°

Thus, angle between the first (m=1) and second (m=2) interference minima is 3.36°.

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The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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The initial velocity of the 3250 Kg mass is 2.1 m/s. The distance covered by the larger mass in 5s is 4.7 cm.

In this problem, we have to apply the law of conservation of linear momentum. Note that;

Momentum before collision = Momentum after collision

m1u1 + m2u2 = m1v1 + m2v2

(2150 × 10) + (3250u1) = (2150 + 3250)5.22

21500 + 3250u1 = 5400 × 5.22

3250u1  = 28188 - 21500

u1 = 28188 - 21500/3250

u1 = 2.1 m/s

2) Again from the principle of conservation of linear momentum;

(0.40 × 3.5) + (0.60 × 0) = (0.40  × 0.70) + (0.60 × v2)

1.4 = 0.28 + 0.60v2

1.4 - 0.28 =  0.60v2

v2 = 1.87 cm/s

Using;

s = 1/2 ( u + v)t

s = 1/2(0 + 1.87) × 5

s = 4.7 cm

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The rate of change in velocity is known as acceleration.She thereby accelerated 0.027 m/s2 throughout her strong effort.

The rate of change in velocity is known as acceleration.Acceleration typically signals a change in speed, though this is not always the case.

Because of the shifting direction of its velocity, an item moving on a circular path at a constant speed is still accelerating. The change in velocity divided by the time interval during which that change happened is the definition of acceleration (in its simplest form).

The formula is: a= v2 - v1 /t

Where:

Initial velocity is v1.

v2: final speed

t: the amount of time required for that acceleration

introducing the specified values into the equation

a=0.027 m/s2

where

a = 3.5 m/s - 31 m/s /15 m/s

She thereby accelerated 0.027 m/s2 throughout her strong effort.

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24 volts is the voltage drop across each of the resistors in the parallel configuration.

When resistors are connected in parallel, they share the same voltage across them. Therefore, the voltage drop across each resistor in this scenario would be the same.

Given:

Power supply voltage (V) = 12 V

Resistance of each resistor (R) = 30 Ω

Since the resistors are in parallel, the total resistance (R_total) can be calculated using the formula:

1/R_total = 1/R1 + 1/R2

Substituting the values:

1/R_total = 1/30 Ω + 1/30 Ω

1/R_total = 2/30 Ω

R_total = 15 Ω

Now, we can find the current flowing through the resistors (I) using Ohm's Law:

I = V / R_total

I = 12 V / 15 Ω

I = 0.8 A

Since the voltage drop across each resistor is the same, we can find it using Ohm's Law:

V_drop = I * R

V_drop = 0.8 A * 30 Ω

V_drop = 24 V

Therefore, the voltage drop across each of the resistors in the parallel configuration is 24 volts.

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The stage of sleep which is marked by long slow delta brain waves is stage 4 and is therefore denoted as option B.

This is referred to as a sedentary state of mind and body and it is characterized by altered consciousness, reduced muscle activity and reduced interactions with surroundings.

In the deepest level of sleep, stage IV sleep it has been observed that it consists of low frequency and high-amplitude fluctuations called delta waves and the sequence from drowsiness to deep stage IV sleep usually takes about an hour thereby making it the correct choice.

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The projectile's time of flight is approximately 6.6 seconds, which is closest to option B.

An object that is shot into the air and subsequently proceeds along a curved route while being pulled by gravity is said to be in projectile motion. There is no additional propulsion or lift involved. A ball that is tossed, a bullet that is shot from a pistol, or a rocket that is launched into space are examples of things in projectile motion.

We can use the kinematic equations of motion to calculate the projectile's time of flight. The initial velocity can first be divided into its horizontal and vertical components as follows:

\(Vx = V \times cos(\theta)\\= 65 m/s \times cos(30)\\= 56.18 m/s\\Vy = V \times sin(theta)\\= 65 m/s \times sin(30)\\= 32.5 m/s\\\)

where V is the magnitude of the initial velocity, and theta is the launch angle (30 degrees).

The horizontal velocity of the projectile remains constant throughout its flight, while the vertical velocity changes due to the effect of gravity. At the highest point of the trajectory, the vertical velocity becomes zero, and the time it takes to reach this point is equal to half of the time of flight.

The time it takes for the projectile to reach the highest point can be found using the following kinematic equation:

\(V_y = V_oy + a \times t\)

where Voy is the vertical component of the initial velocity (in this case, 32.5 m/s), a is the acceleration due to gravity (-9.81 m/s^2), and t is the time it takes to reach the highest point.

\(0 = 32.5 m/s + (-9.81 m/s^2) \times t\\t = 3.32 s\)

The total time of flight can be found by doubling the time it takes to reach the highest point:

time of flight = 2 × 3.32 s

                      = 6.64 s

Therefore, the projectile's time of flight is approximately 6.6 seconds, which is closest to option B.

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For F = 60 N, the acceleration of both block A and cart B is 2.38 m/s^2, while for F = 40 N, block A and cart B have accelerations of -0.81 m/s^2 and -0.40 m/s^2 respectively, both moving backwards.

To determine the acceleration of block A and cart B, we need to draw a free body diagram for each object and apply Newton's second law, F = ma.

(a) When F = 60 N:

The forces acting on block A are the force of friction f1, the force of gravity mg1, and the applied force F. The forces acting on cart B are the force of friction f2 and the force of gravity mg2. Since the two objects are connected by a rope, they have the same acceleration a.

For block A:

F - f1 = ma

For cart B:

f1 - f2 = (m1 + m2)a

mg2 - F = m2a

Using the coefficient of friction, we can find the force of friction:

f1 = μ1N1 = μ1mg1

f2 = μ2N2 = μ2mg2

where N1 and N2 are the normal forces acting on block A and cart B, respectively.

Since the coefficient of friction is the same for both static and kinetic friction, we can assume that the block and cart are not moving relative to each other. Therefore, we can use the coefficient of static friction to find f1 and f2.

μs = 0.5

N1 = m1g1 = \((20 kg)(9.8 m/s^2) = 196 N\)

N2 = m2g2 = \((100 kg)(9.8 m/s^2) = 980 N\)

f1 = μsN1 = (0.5)(196 N) = 98 N

f2 = μsN2 = (0.5)(980 N) = 490 N

Substituting these values into the equations above, we get:

60 N - 98 N = 20 kg a

98 N - 490 N = (20 kg + 100 kg) a

980 N - 60 N = 100 kg a

Solving for a, we get:

\(a = 2.38 m/s^2\) for both block A and cart B.

(b) When F = 40 N:

Following the same steps as in part (a), we can find:

μs = 0.5

N1 = m1g1 =\((20 kg)(9.8 m/s^2) = 196 N\)

N2 = m2g2 = \((100 kg)(9.8 m/s^2) = 980 N\)

f1 = μsN1 = (0.5)(196 N) = 98 N

f2 = μsN2 = (0.5)(980 N) = 490 N

Substituting these values into the equations above, we get:

40 N - 98 N = 20 kg a

98 N - 490 N = (20 kg + 100 kg) a

980 N - 40 N = 100 kg a

Solving for a, we get:

\(a = -0.81 m/s^2\)for block A, indicating that it is moving backwards, and\(a = -0.40 m/s^2\) for cart B, indicating that it is also moving backwards.

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Answer: B im sorry if its wrong

Explanation:

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

How do digital signals work?

An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.

Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

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a) The flux is, Φ = 16.4 N·m²/C

b) If n is perpendicular to E then, Φ = 0

c) If parallel to E then, Φ = 62.8 N·m²/C

The flux through a surface is given by the equation:

Φ = E * A * cos(θ)

where E is the electric field strength, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

a) If the normal vector to the surface is at 30 degrees to E, then the flux would be:

Φ = (2.0 x \(10^3\) N/C) * π*(0.10 m)² * cos(30°) = 16.4 N·m²/C

b) If n is perpendicular to E, then the angle between them is 90 degrees and cos(90°) = 0. Therefore, the flux would be zero.

Φ = (2.0 x \(10^3\) N/C) * π*(0.10 m)² * cos(90°) = 0

c) If n is parallel to E, then the angle between them is 0 degrees and cos(0°) = 1. Therefore, the flux would be:

Φ = (2.0 x \(10^3\) N/C) * π*(0.10 m)² * cos(0°) = 62.8 N·m²/C

Note that in this case, the flux is maximum because the electric field is perpendicular to the surface.

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We can measure the flow rate of various liquid by pouring the liquid down an incline and time how long it takes each one to reach the bottom.

option C.

The flow rate of a liquid is how much fluid passes through an area in a particular time.

Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume. As liquids are incompressible, the rate of flow into an area must be equivalent to the rate of flow out of an area.

Generally, the best equipment to measure the flow rate of a liquid is flow meters. In the absence of flow meters, we can other methods such as the one given in the options.

We can pour the various liquid down an incline and time how long it takes each one to reach the bottom.

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A rope pulls a Tesla out of mud. The guy pulls a force F⊥ of 300N, and theta = 4.2°. The tension force T is 298.44__ Newton.

The problem describes a Tesla that is stuck in the mud and needs to be pulled out using a rope. the guy pulls a force F⊥ of 300N and that the angle between the rope and the horizontal plane is θ = 4.2°. The goal is to find the tension force T exerted by the rope.To solve for T, we'll need to use trigonometry. We can break the force vector into its horizontal and vertical components as follows:

Fx = F⊥ cosθ and Fy = F⊥ sinθ.

Since the rope is pulling the Tesla horizontally, the horizontal component of the force will be the tension force T. So we have:

T = Fx = F⊥ cosθ = (300 N) cos(4.2°) ≈ 298.44 N

Taking the cosine of the angle is necessary since it's the adjacent side that we're interested in, which is the horizontal component of the force. Therefore, the tension force exerted by the rope is approximately 298.44 N.

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The  concentration of the solution will be 0.25M and the concentration of the  

sodium Hydroxide is 2.5 M .

A branch of chemistry deals with the application of  the laws of definite proportions and of the conservation of mass and energy to chemical activity. The quantitative relationship between constituent in a chemical substance.  

We have given here,

Moles of sodium chloride  =  0.25moles

Let us assume the the volume of  the solution is 1 L.

Molarity = 0.25/

Molarity will be 0.25 M

The mass of sodium Hydroxide is 20g and the molar mass is 40g ,

and the Volume will be 0.2L

Molarity = 20/ 40×0.2

Molarity = 2.5 mol / L

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Given data:

* The mass of the first car is 10 metric tons.

* The initial speed of the first car is 108 km/h

* The speed of couple of both the cars after the collision is 36 km/h.

* The initial speed of the second car is zero. ial

Solution:

By the law of conservation of momentum,

where m is the mass of first car, M is the mass of second car, u_1 is the initial velocity of first car, u_2 is the initial velocity of second car, v_1 is the final velocity of first car, and v_2 is the final velocity of second car,

Substituting the known values,

Thus, the mass of the second car is 20 metric tons.

Hence, option 2 is the correct answer.

Answer:

gravity wave

Explanation:

The current (in amperes) the frying pan draws from the 500 volt circuit, given that it has a resistance of 25 ohms is 60 amperes

From the question given above, the following data were obtained:

The current drawn by the frying pan can be obtained as follow:

Voltage (V) = Current (I) × resistance (R)

Inputting the given parameters, we have:

1500 = Current × 25

Divide both sides by 25

Current = 1500 / 25

Current = 60 amperes

Thus, from the above calculation we can conclude that the current drawn by the frying pan is 60 amperes

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Answer:

it make your immune system build up from the strain your puting on you body

Explanation:

excercise is good for you  and builds muscle and blood cells

Given:

Mass of block = 2.4 kg

Acceleration = -0.8 m/s^2

Let's ifnd the coefficient of kinetic friction,

To find the coefficient of kinteic friction, apply the formula:

Where:

F is frictional force

N is the normal force.

Hence, we have:

Therefore, the coefficient of friction between the block and the surface is 0.08

ANSWER:

0.08

Answer:

The answer is "\(5.53 \ \frac{m}{s}\)"

Explanation:

apply the formula for calculating the average velocity to the relative air

\(V_{PG} =V_{PA}+V_{AG}\)

\(\Rightarrow V_{PA} = V_{PG} -V_{AG}\)

Given value:

\(V_{AG} = -2 \ \frac{m}{s}\)

\(V_{PG} =3.53\)

\(\Rightarrow V_{PA} = 3.53 - (-2) \\\\\Rightarrow V_{PA} = 3.53 +2 \\\\\Rightarrow V_{PA} = 5.53 \\\\\)

The final answer is "\(5.53 \ \frac{m}{s}\)" in the south-east direction.

Answer:

Explanation:

Displacement of train = 60 - 25 = 35 mile

= 35 x 1.6 = 56 km

duration of time = 45 - 15 = 30 minutes

= 30 x 60 = 1800 s

velocity of train = displacement / time

= 56 / 1800 = .03111 km /s

= 31.111 m / s