Answer:
For C is B and for D is A
Explanation:
B because that's where the b car will do all the force to go up, and A because there the car doesn't have to do any force other than the natural, and it already brings that on it's own.
An apartment has the dimensions 18 m by 9 m by 6 m. The temperature is 25°C, and the relative humidity is 59 percent. What is the total mass (in kg) of water vapor in the air in the apartment?
The total mass of water vapor in the air in the apartment can be calculated using the formula for absolute humidity. The total mass is approximately 5.04 kg.
To calculate the total mass of water vapor in the air, we need to determine the volume of the apartment and then use the formula for absolute humidity.
Calculate the volume of the apartment: The volume of the apartment can be calculated by multiplying its dimensions: Volume = length x width x height = 18 m x 9 m x 6 m = 972 cubic meters.
Determine the vapor pressure: The relative humidity of 59 percent indicates that the air is holding 59 percent of the maximum amount of water vapor it can hold at the given temperature.
Find the saturation vapor pressure: The saturation vapor pressure is the maximum pressure of water vapor that air can hold at a given temperature. At 25°C, the saturation vapor pressure is approximately 3.17 kPa.
Calculate the actual vapor pressure: The actual vapor pressure can be calculated by multiplying the saturation vapor pressure by the relative humidity: Actual vapor pressure = Relative humidity x Saturation vapor pressure = 0.59 x 3.17 kPa = 1.867 kPa.
Calculate the mass of water vapour: The mass of water vapor can be determined using the formula for absolute humidity: Mass = Absolute humidity x Volume = (Actual vapor pressure / (0.287 kJ/(kg·K) x Temperature)) x Volume. In this case, the temperature is 25°C, which is 298 K.
Mass = (1.867 kPa / (0.287 kJ/(kg·K) x 298 K)) x 972 m^3 = 5.04 kg.
Therefore, the total mass of water vapor in the air in the apartment is approximately 5.04 kg.
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Light of wavelength 519 nm passes through two slits. In the interference pattern on a screen 4.6 m away, adjacent bright fringes are separated by 4.0 mm. What is the separation of the two slits
Answer:
The appropriate solution is "0.597 mm".
Explanation:
Given that:
Wavelength,
\(\lambda = 519 \ nm\)
or,
\(=519\times 10^{-9}\)
Distance,
\(D=4.6 \ m\)
Separated by,
\(\beta = 4.0 \ mm\)
or,
\(=4.0\times 10^{-3}\)
As we know,
⇒ \(\beta=\frac{\lambda D}{d}\)
or,
The separation of two slits will be:
⇒ \(d=\frac{\lambda D}{\beta}\)
By putting the values, we get
\(=\frac{(519\times 10^{-9})(4.6)}{4.0\times 10^{-3}}\)
\(=5.97\times 10^{-4}\)
or,
\(=0.597 \ mm\)
A refrigerator requires 10 J of work and exhausts 65 J of heat per cycle. What is the refrigerator's coefficient of performance
Answer:
The refrigerator's coefficient of performance is 5.5.
Explanation:
Given;
work required, W = 10 J
heat exhausts per cycle, Q = 65 J
determine the energy removed from the cold reservoir, which is inside the refrigerator;
\(W_{in} = Q_H - Q_C\)
10 = 65 - Qc
Qc = 65 - 10
Qc = 55
The coefficient of performance of heat pump used for cooling id given by;
\(COP = \frac{Q_C}{W_{in}}\\\\COP = \frac{55}{10}\\\\ COP = 5.5\)
Therefore, the refrigerator's coefficient of performance is 5.5.
The required value of coefficient of performance of refrigerator is 5.5 .
Given data:
The amount of work input to the refrigerator is, W = 10 J.
The heat output from the refrigerator is, Q = 65 J.
The ratio of heat removed from the system to the work done to remove the heat, is known as the coefficient of performance of refrigerator. Then, the expression is given as,
COP = Q'/W
Here, Q ' is the amount of heat removed from the system. And its value is,
W = Q - Q'
Q' = Q - W
Then the COP is,
COP = (Q -W)/W
COP = 55/10
COP = 5.5
Thus, we can conclude that the required value of coefficient of performance of refrigerator is 5.5 .
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If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial speed of 5 m/s, the snowboarder is moving to the right on the upper level. His final speed in this case is 3 m/s. Suppose this situation is repeated on planet Epsilon, where gravity is less than gravity on earth.
A. Would the height of the hill on Epsilon cause a reduction in speed from 4 m/s to 0 greater than, less than, or equal to the height of the corresponding hill on earth? Explain.
B. Consider the hill on Epsilon discussed in part A. If the initial speed at the bottom of the hill is 5 m/s, will the final speed at the top of the hill be greater than, less than, or equal to 3 m/s? Explain.
(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
Conservation of mechanical energy
The effect of height and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;
ΔK.E = ΔP.E
¹/₂m(v²- u²) = mg(hi - hf)
¹/₂(v²- u²) = g(0 - hf)
v² - u² = -2ghf
v² = u² - 2ghf
where;
v is the final velocity at upper levelu is the initial velocityhf is final heightg is acceleration due to gravitywhen u² = 2gh, then v² = 0,
when gravity reduces, u² > 2gh, and v² > 0
Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).
Final speedv² = u² - 2ghf
where;
u is the initial speed = 5 m/sg is acceleration due to gravity and its less than 9.8 m/s²v is final speedhf is equal heightSince g on Epislon is less than 9.8 m/s² of Earth;
5² - 2ghf > 3 m/s
Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.
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Question 11 of 25
In the circuit below, resistors R₁ and R₂ are in parallel. What is the equivalent
1
1
resistance? (R₁ = 30 22,R₂ = 20 2) (
A
+A)
Ptot R₁
S₁
S₂
R₁
S₂ S
ww
R₂
1
R₂₂k
Answer:
60 ohms
Explanation:
To find the equivalent resistance of two resistors R₁ and R₂ in parallel, we can use the formula:
1/Req = 1/R₁ + 1/R₂
where Req is the equivalent resistance.
Substituting the values given, we get:
1/Req = 1/30 + 1/20
Simplifying, we get:
1/Req = 1/60
Multiplying both sides by Req, we get:
Req = 60 ohms
Therefore, the equivalent resistance of the two resistors R₁ and R₂ in parallel is 60 ohms.
A girl of mass 60 kg runs up a flight of 20 steps of
0.5m high in 10 seconds. find the average
power developed [g=10m /s²]
Here ur ans.
By :-Utsav Xettri
Note : pls mrk me banlist.
When a disrupted part of a wetland ecosystem is left alone so that nature can help restore it to what it once was, what are people counting on occurring? explain..
Answer: When a disrupted part of the ecosystem is left alone so that nature can help restore itself what people are counting on happening is secondary succession
Explanation:
3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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(03.05 HC)The table below represents the data found by dragging solid brass weights across adesk with a spring scale. If the acceleration due to gravity is 9.81 m/s2, what masswould experience a frictional force of 2 N?Normal Force (N) 1.5 4.1 Frictional Force (N) 0.4 1.0O 4.0 kgO 0.86 kgO 0.54 kgO 8.3 kg
Answer: 0.54kg
Explanation:
The gravitational potential energy of a 88 kg person in a building that is 385 m tall is 332,024 J. The person then jogs up the stairs, an additional distance of 100 meters.
How would the potential energy of the person be affected?
A) There would be no change.
B) The potential energy would double.
C) The potential energy would increase almost 25%
D) The potential energy would decrease more than 50%.
Answer:
Part C
Explanation:
The potential energy would increase almost 25%
. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification
The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.
Given:
Object height (h) = 5 cm
Focal length of the convex lens (f) = 10 cm
Object distance (u) = 15 cm (positive since it's on the same side as the incident light)
To determine the nature, position, and size of the image, we can use the lens formula:
1/f = 1/v - 1/u
Substituting the given values:
1/10 = 1/v - 1/15
To simplify the equation, we find the common denominator:
3v - 2v = 2v/3
Simplifying further:
v = 30 cm
The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.
To find the magnification (M), we use the formula:
M = -v/u
Substituting the values:
M = -30 / 15 = -2
The magnification is -2, indicating that the image is inverted and twice the size of the object.
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A 300-Watt electric wheelchair has a mass of 50 kg and carries its 50 kg occupant at a constant velocity up a long ramp. About how much time does it take the wheelchair to reach the top of 10 meters high ramp?
The time taken for the wheelchair to reach the top of the ramp will be 32.7 seconds.
What is Power?Power is the time rate at which work is accomplished.
Energy divided by time is a rate of work because, the energy is a change in energy and a change in energy equals to workdone.
Power = Workdone/Time taken
P = (mgh)/t
Where;
Power = 300watts
m = 50kg + 50kg
m = 100kg
g = 9.8m/s2
h = 10 meters
300 = (100 x 9.8 x 10) / t
t = 9800/300
t = 32.7seconds
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Set three resistances to 2, 3, and 5 Ohms in series, and determine the current in the circuit with an ammeter. Take the snapshot of the screen showing the circuits and the reading of the ammeter. Then, replace these three resistors with just one resistance of 10 Ohm. Determine the current running in the circuit. Take a snapshot showing the circuits and the reading of the ammeter. Is the current the same as in the previous experiment with the three resistors
Answer:
the current in the circuit must be the same.
Explanation:
The equivalent resistance in a series circuit is the sum of the resistances
in this case
R_{eq} = R₁ + R₂ + R₃
we calculate
R_{eq} = 2 + 3 + 5
R_{eq} = 10 Ω
We can see that the equivalent resistance is equal to the resistance to be changed, so the current in the circuit must be the same.
The only change there may be is due to the tolerances of the resistors
What is the answer to the unfilled box in the screenshot?
The answer to the unfilled box in the screenshot which demands the area under the graph is 600unit²
What is the Area of a Triangle?The area of a triangle is the space situated within the three sides of a triangle. It is calculated through the assistance of series of formulas which dependent on the kind of triangle and is portrayed in square units such as cm², inches², m² and so on.
Following that analogy:
The area of the shape above which is triangular is calculated with the formulary;
A = h(b)/2
Key: A: area; h: height; b: base. By extension,
A = 20 (60)/2
= 1200/2
= 600unit²
Therefore, one can conclude that the area under the graph is 600cm²
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Define Refraction and give some knowlegde about it
A coastal community needs to know the sustainable yield of grouper for its upcoming fishing season. Examine the sustainable yield model for grouper fish below.
A cumulative bar graph for the sustainable yield model is shown over four years. It shows the number of adult fish measured in thousands from 0 to 7 on the vertical axis. Each bar shows the sum of population and surplus for the years of reproduction. For each bar, population is constant at 2.2. For year 1, surplus is 0. For year 2, surplus is 4.4. For year 3, surplus is 1.8. For year 4, surplus is 2.8.
How many adult groupers can be sustainably caught during the fishing season in year three?
2,200
1,800
4,000
4,400
The sustainable yield of adult groupers that can be caught during the fishing season in year three is 4,000.
To determine the sustainable yield of adult groupers for the fishing season in year three, we need to consider the surplus for that year. According to the information provided, the surplus for year three is 1.8 thousand (or 1,800).
The sustainable yield represents the number of adult groupers that can be caught while maintaining the population at a stable level. In this model, the sustainable yield is equal to the sum of the population and surplus for the corresponding year.
For year three, the population is constant at 2.2 thousand, and the surplus is 1.8 thousand. Adding these values together gives us:
Sustainable Yield = Population + Surplus = 2.2 + 1.8 = 4 thousand (or 4,000)
Therefore, the sustainable yield of adult groupers that can be caught during the fishing season in year three is 4,000.
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Can anyone please help me
To solve this problem, we can use Coulomb's law, which states that the electric force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.
We can then use the electric force to find the electric field at the location of q3 and the initial acceleration of q3.
a) To find the electric field at the location of q3, we can first find the electric force on q3 due to q1 and q2 and then use the definition of the electric field, which is the electric force per unit charge. The electric force on q³ due to q¹ and q² is:
F1 = k x q¹ x q³/ r1²
F2 = k x q² x q³ / r2²
where r¹ and r² are the distances from q¹ and q² to q³, respectively, and k is Coulomb's constant.
Since q³ is equidistant from q¹ and q², we have r¹ = r² = 0.20 m. Substituting the given values, we get:
F1 = (9.0 x 10⁹ N-m²/C²) x (4.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = 1.8 N
F2 = (9.0 x 10⁹ N-m⁻²/C²) x (-6.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = -5.4 N
The negative sign of F2 indicates that the force on q³ due to q² is in the opposite direction to the force due to q¹.
The net electric force on q3 is the vector sum of the forces due to q1 and q2:
Fnet = F1 + F2 = 1.8 N - 5.4 N = -3.6 N
The electric field at the location of q³ is then:
E = Fnet / q³ = (-3.6 N) / (2.0 x 10⁻⁶ C) = -1.8 x 10⁻⁶N/C
The negative sign of the electric field indicates that the field is directed towards q².
b) To find the initial acceleration of q³, we can use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration:
Fnet = ma
where m is the mass of q³ and a is its initial acceleration.
Substituting the given values, we get:
-3.6 N = (2.0 x 10⁻⁶ kg) x a
Solving for a, we get:
a = -1.8 x 10³ m/s²
The negative sign of the acceleration indicates that it is directed towards q².
c) The direction of the initial acceleration of q³ is towards q².
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find the power of a lift that transfers 450 J of energy in 15 seconds.
Answer: P=30W
Explanation:
formula is p=w/t
p = power
w = work
t = elapsed time
input variables, solve then simplify.
The power of a lift that transfers 450 J of energy in 15 seconds is 30 watts.
Power is defined as the rate of doing work, i.e. the amount of work done per unit time.
Mathematically, it can be represented as follows:
Power = Work done / time taken
Therefore, the power of a lift that transfers 450 J of energy in 15 seconds can be calculated as follows:
Power = Work done / time taken= 450 J / 15 s= 30 W
Therefore, the power of the lift is 30 watts.
To explain further, we know that power is measured in watts (W), and it is the rate at which work is done or energy is transferred.
Here, we are given that the lift transfers 450 J of energy in 15 seconds.
We can find the power of the lift by dividing the amount of work done by the time taken to do it. By substituting the given values, we get the power of the lift as 30 W.
In simple terms, this means that the lift can transfer energy at a rate of 30 joules per second. This can also be interpreted as the lift can do 30 joules of work in one second.
Hence, we can conclude that the power of the lift is 30 watts.
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Propose an experiment that could be used to demonstrate that friction is a contact force?
Pls help
What improvements were made in measuring system with the introduction of standard units?
Answer:
Standard units are commonly used units of measurement, which help us measure length, height, weight, temperature, mass and more. These units are standardised, which means that everyone gets the same understanding of the size, weight and other properties of objects and things.
Explanation:
Which is the best description of biodiversity?
1. All animals in an ecosystem
2. The variety of the type of life within the biosphere
3. The study of life
3. The variety of plants on Earth
Answer:2
Explanation:
2. What is the mass of an object if it has a weight of 80.0 N near the earth's surface?
Answer:
Explanation:
20
A loudspeaker of mass 15.0 kg is suspended a distance of h = 1.00 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l = 2.70 m .
1. What is the tension T in each of the cables?
Use 9.80 m/s2 for the magnitude of the free-fall acceleration.
Answer:
To solve the problem, we use the equations of equilibrium to find the tension in each cable holding up the loudspeaker. Since the loudspeaker is in equilibrium, the sum of the forces acting on it is zero. The weight of the loudspeaker is calculated first, and then we use trigonometry to find the horizontal and vertical components of the tension in one of the cables. We then apply the equation of equilibrium in the y direction to find the tension in each cable. The final answer is that the tension in each cable is approximately 81.1 N, which balances the weight of the loudspeaker.
___
Given:
Mass of loudspeaker (m) = 15.0 kg
Distance from ceiling (h) = 1.00 m
Length of cable (l) = 2.70 m
Acceleration due to gravity (g) = 9.80 m/s^2
Weight of loudspeaker:
Fg = mg
Fg = (15.0 kg)(9.80 m/s^2)
Fg = 147 N
Horizontal and vertical components of tension in one cable:
sinθ = h/l
sinθ = 1.00 m / 2.70 m
θ = sin^(-1)(1.00/2.70)
θ ≈ 21.6°
T_x = T sinθ
T_y = T cosθ
where T is the tension in the cable.
Equation of equilibrium in y direction:
ΣF_y = 2T cosθ - Fg = 0
Solving for T:
2T cosθ = Fg
T = Fg / (2 cosθ)
Plugging in the values:
T = (147 N) / (2 cos(21.6°))
T ≈ 81.1 N
Draw the Free- Body diagram of the 37 kilogram glass falling to the floor in a vacuum.
Then, use Newton’s Second Law to calculate how much force the glass hits the floor with.
Answer:
362.6 N
Explanation:
\(F_{g}=mg\)
\(F_{g}=37\cdot9.8\)
\(F_{g}=362.6\ N\)
Therefore, the force that the glass hits the floor with is 362.6 N
As explained by the second law of thermodynamics, which example of energy transformation could never occur?
A.**The 400 J of heat added to the operating gas of a heat engine is transformed into 400 J of work.
B.The 400 J of kinetic energy of a rolling ball is transformed into 400 J of heat.
C.A refrigerator removes 100 cal of heat from a bottle of milk while using 75 cal of electrical energy.
D.A heat engine does 25 J of work while expelling 10 J of heat to the cold reservoir.
The example of energy transformation that could never occur, as explained by the second law of thermodynamics, is the 400 J of heat added to the operating gas of a heat engine is transformed into 400 J of work. Option A is correct.
The second law of thermodynamics states that in any energy transformation, the total entropy (measure of disorder) of a closed system will always increase or remain constant. It means that some energy will always be wasted as heat and cannot be completely converted into useful work. The second law of thermodynamics is a fundamental law of nature that governs energy transformations.
It states that in any energy transformation process, the total entropy (measure of disorder) of a closed system will always increase or remain constant. Entropy can be thought of as a measure of the amount of energy that is unavailable to do useful work. It is impossible to transform all 400 J of heat into work without generating any waste heat. This is because the heat engine must expel some heat to the cold reservoir to comply with the second law. Option A is correct.
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A 2.3 kg block on a frictionless incline of 27 degrees. The acceleration of gravity is 9.8 m/s2. Answer in units of ms. What is the normal force on the block...
The normal force on the block is approximately 20.05 N.
What is force acting on a body?Force describes the interaction between objects or between an object and its environment. It causes a change in the motion of the body it acts upon.
The normal force, which counteracts the force of gravity dragging the block downward, is the force generated by the slope acting perpendicular to its surface. As the incline has no friction, there is no force acting parallel to its surface.
To ascertain the parts of the force of gravity pulling on the block, we can apply trigonometry. There are two parts to the force of gravity: one that is parallel to the incline's surface and the other that is perpendicular to it. The weight of the block, mg, where m is its mass and g is its gravitational acceleration, is equal to the component of gravity perpendicular to the inclination. mg sin θ, where is the angle of the incline, is the component of gravity that is parallel to the incline.
To calculate the acceleration of the block moving down the incline, we can apply Newton's second law, F = ma. The component of gravity parallel to the inclination, or mg sin θ, represents the net force exerted on the block. As a result, we have:
\(mg sin(theta) = ma\)
To solve for a, we obtain:
\(a = g sin(theta)\)
Substituting the given values, we get:
\(a = 9.8 m/s^2 * sin(27°)\) ≈ \(4.69 m/s^2\)
Now that we know the normal force acting on the block, we can use Newton's second law once more. The component of gravity's force perpendicular to the incline is equal in magnitude to the normal force and moves in the opposite direction. As a result, we have:
\(mg cos(theta) = N\)
Inputting the values provided yields:
\(N = 2.3 kg * 9.8 m/s^2 * cos(27°)\) ≈ \(20.05 N\)
Therefore, the normal force on the block is approximately 20.05 N.
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Question 14 (1 point)
One star has a temperature of 20,000 K and another star has a temperature of 8,000
K. Compared to the cooler star, how much more energy per second (how many times
more energy) will the hotter star radiate from each square meter of its surface?
We have that the more energy per second to radiated by the hotter is mathematically given as
Energy per second=256
Energy per second to radiated
Question Parameters:
One star has a temperature of 20,000 K
and another star has a temperature of 8,000
Generally the equation for the Energy per second is mathematically given as
Energy per second is Proportional to T^4
Where
T=20000/8000
T=4
therefore
Energy per second=4^4
Energy per second=256
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The mass of 25cm3 of ivory was found to be 0.045kg Calculate the density of ivory in Sl units.
Answer: the density of ivory in SI units is 1800 kg/m^3.
Explanation: To calculate the density of ivory in SI units, we use the formula density = mass/volume. We are given the mass of 25 cm^3 of ivory as 0.045 kg. Since volume is in cm^3, we need to convert it to SI units of m^3. 1 cm^3 is equal to 1 milliliter (ml), so 25 cm^3 is equal to 25 ml. To convert ml to m^3, we use the conversion factor 1 ml = 10^-6 m^3. We then substitute the values of mass and volume into the density formula and simplify. The resulting density is expressed in units of kg/m^3, which are the SI units for density. Therefore, the density of ivory in SI units is 1800 kg/m^3.
A 66 kg driver gets into an empty taptap to start the day's work. The springs compress 2.3×10−2 m
. What is the effective spring constant of the spring system in the taptap?
Enter the spring constant numerically in newtons per meter using two significant figures
Explanation:
You want N/m
N = 66 * 9.81
m = 2.3 x 10^-2 m
66* 9.81 / 2.3 x 10^-2 = 28150 = 28 000 N/m to two S D
A roller coaster is at the top of a 72m hill and weighs 966N. What is the potential energy of the roller coaster Potential Energy = Weight x HeightWeight = Potential Energy / HeightHeight = Potential Energy / WeightWeight = Mass x 10Mass = Weight / 10
We will have the following:
We will determine the potential energy as follows:
\(P=966N\cdot72m\Rightarrow P=69552J\)