To find the speed based on the position function, you have to derivate the function in terms of time (x)
\(\begin{gathered} f^{\prime}(x)=v(x)=11+22cos(x) \\ \end{gathered}\)\(\begin{gathered} v(x)=0=11+22cos(x) \\ -11=22cos(x) \\ -0.5=cos(x) \\ x=\frac{2}{3}\pi \end{gathered}\)\(\begin{gathered} f(x)=11x+22sin(x) \\ f(x)=11(\frac{2}{3}\pi)+22sin(\frac{2}{3}\pi) \\ f(x)=\frac{22}{3}\pi+19.0526 \\ f(x)=42.09m \end{gathered}\)the candle had 350 J of energy in the chemical store. As it burned, 250 J was transferred by lighting to the surrounding
Answer:
Efficiency = 71%
Explanation:
Given the following data:
Output energy = 250 Joules
Input energy = 350 Joules
To find efficiency;
\( Efficiency = \frac {Out-put \; energy}{In-put \; energy} * 100 \)
Substituting into the equation, we have;
\( Efficiency = \frac {250}{350} * 100 \)
\( Efficiency = 0.7143 * 100 \)
Efficiency = 71.43 ≈ 71%
Therefore, the efficiency of the candle is 71 percent.
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.30 seconds later. What is the acceleration of the rocket?
The constant acceleration of a rocket launched upward, calculated knowing that the time it takes for a bolt that falls off the side of the rocker was 6.30 seconds, is 5.68 m/s².
When the rocket is launched straight up with constant acceleration, the acceleration of the rocket is given by:
\( v_{f_{r}} = v_{i_{r}} + at \)
Where:
\(v_{f_{r}}\): is the final velocity of the rocket
\(v_{i_{r}}\): is the initial velocity of the rocket = 0
a: is the acceleration
t: is the time
After 4 seconds, the final speed of the rocket will be the initial speed of the bolt, so:
\( v_{f_{r}} = v_{i_{b}} = at = 4a \)
When the bolt falls off the side of the rocket, the bolt hits the ground 6.30 seconds later.
The initial height of the bolt will be the final height of the rocket, and vice-versa. With this, we can take the final height of the bolt as zero.
\( y_{f_{b}} = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2} \)
\( 0 = y_{i_{b}} + v_{i_{b}}t - \frac{1}{2}gt^{2} \)
\( y_{i_{b}} = \frac{1}{2}9.81*(6.30)^{2} - 4a*6.30 = 194.7 - 25.2a \)
Now, as we said above, this height (of the bolt) will be the final height of the rocket, so:
\( y_{f_{r}} = y_{i_{r}} + v_{i_{r}}t - \frac{1}{2}gt^{2} \)
\( 194.7 - 25.2a = 0 + 0 - \frac{1}{2}a(4)^{2} \)
\( a = \frac{194.7}{33.2} = 5.86 m/s^{2} \)
Therefore, the acceleration of the rocket is 5.68 m/s².
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What force F in N is required to keep the block moving at constant velocity to the right? The mass of the block is 4 kg, coefficient of kinetic friction is 0. 8 and the angle is 30°
The force required to keep the block moving at a constant velocity to the right is equal to the force of kinetic friction. In this case, the force required is 31.36 N.
To calculate the force required to keep the block moving at a constant velocity to the right, we need to consider the forces acting on the block.
1. First, let's find the gravitational force acting on the block. The formula for gravitational force is F_gravity = m * g, where m is the mass of the block and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Plugging in the values, we get F_gravity = 4 kg * 9.8 m/s^2 = 39.2 N.
2. Next, let's determine the force of kinetic friction acting on the block. The formula for kinetic friction is F_friction = μ * N, where μ is the coefficient of kinetic friction and N is the normal force. The normal force is equal to the gravitational force acting on the block, which we calculated earlier as 39.2 N.
Plugging in the coefficient of kinetic friction, μ = 0.8, we get F_friction = 0.8 * 39.2 N = 31.36 N.
3. Since the block is moving at a constant velocity, we know that the net force acting on the block is zero. Therefore, the force required to keep the block moving at a constant velocity to the right is equal to the force of kinetic friction.
In this case, the force required is 31.36 N.
1. Gravitational force (F_gravity) is calculated using the formula F_gravity = m * g, where m is the mass of the block and g is the acceleration due to gravity (approximately 9.8 m/s^2). In this case, F_gravity = 4 kg * 9.8 m/s^2 = 39.2 N.
2. Kinetic friction force (F_friction) is determined using the formula F_friction = μ * N, where μ is the coefficient of kinetic friction and N is the normal force. The normal force is equal to the gravitational force acting on the block, which we calculated earlier as 39.2 N. Plugging in the coefficient of kinetic friction, μ = 0.8, we get F_friction = 0.8 * 39.2 N = 31.36 N.
3. Since the block is moving at a constant velocity, the net force acting on the block is zero.
Therefore, the force required to keep the block moving at a constant velocity to the right is equal to the force of kinetic friction. In this case, the force required is 31.36 N.
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ANSWER RIGHT AND YOU WILL GET BRAINLIEST * A car is traveling with a constant speed of 20 m/s. If the car has a mass of 1300 kg, what is its kinetic energy?
Answer:
260,000 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\ \)
v is the velocity
m is the mass
From the question we have
\(k = \frac{1}{2} \times 1300 \times {20}^{2} \\ = 650 \times 400 \\ = 260000\)
We have the final answer as
260,000 JHope this helps you
you are being asked to design a parallel-plate capacitor having a capacitance of 1.00f and a plate separation of 1.00mm. calculate the required surface area of each plate. is this plate size realistic?
1.1×10^8 m^2 is the required surface area of each plate. is this plate size realistic.
How is the capacitance of a parallel plate capacitor calculated?The formula C=Ad C = A d, where C is the value of the capacitance, A is the area of each plate, d is the distance between the plates, and is the permittivity of the material between the plates of the parallel capacitor, gives the capacitance for parallel plate capacitors (dependent on its geometry).
C=εoA /d
∴A= Cd / εo
=(1)(10)^-3 /8.86×10 ^(−12)
=1.1×10^8 m^2
hence the surface area of each plate 1.1×10^8 m^2.
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LSE
9. A car accelerates constantly from 3 m/s to 8 m/s in 10 s and then travel with
constant speed for another 7 s.
(a)
Sketch the speed-time graph.
(b)
Determine its acceleration for the first 10 s of the journey.
(c)
Calculate the total distance travelled by the car.
The students tested each solution. They started each test with a bowl with one cup of water and 30 grams of oil on top. They recorded the mass of each bowl with water and oil before and after each test. They also described the results of each test. Solution Mass of Bowl Before Mass of Bowl After Description Scooping the oil with a spoon 212 g 196 g The spoon easily picked up a lot of the oil at first. As the amount of oil decreased, it got too hard to pick up the oil. Trying to remove more oil spread it around the bowl. Absorbing the oil with a paper towel 214 g 160 g The paper towel absorbed the oil really well at first. As the amount of oil decreased, the paper towel started to pick up a lot of water. The paper towel couldn't get all of the oil. Using soap to break up the oil 210 g 216 g Adding the soap rapidly cleared the oil from the top of the water. It went to the sides of the bowl. With mixing, the oil all broke up as the water got sudsy. Question After reading the results of each test, identify an advantage and a disadvantage of each solution. Drag each result to the correct location on the table. Each result can be used more than once, but not all results will be used. removes clean water with oildisperses oil on surfaceremoves all oil from the waterspreads oil around surfaceleaves all oil in the waterremoves some oil from water
Each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.
The three solutions tested to remove oil from water are scooping the oil with a spoon, absorbing the oil with a paper towel, and using soap to break up the oil. Each solution has its advantages and disadvantages. Scooping the oil with a spoon is an effective solution to remove a significant amount of oil quickly. However, it is not a practical solution for removing a large amount of oil. The disadvantage is that it spreads the oil around the surface of the water and leaves some oil in the water. Absorbing the oil with a paper towel can effectively remove a lot of oil. The advantage is that it removes some oil from the water, leaving it relatively clean. However, it also picks up a lot of water and can't get all of the oil. Using soap to break up the oil is a good solution that removes all of the oil from the water. The advantage is that it removes all of the oil from the water, leaving it clean. However, the disadvantage is that it disperses the oil on the surface of the water, making it harder to remove from the sides of the bowl. In conclusion, each solution tested has its advantages and disadvantages. The most effective solution depends on the situation and the amount of oil that needs to be removed from the water.
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QuestionA ball is thrown at a speed of 20m/s at an angle of 30 o with the horizontal. The maximum height reached by the ball is (use g=10m/s^2)A2mB3mC4mD5m
The maximum height reached by the ball is 5 meters (option D).
We can use the following equation:
h = (v^2 * sin^2 θ) / (2g) where h is the maximum height, v is the initial velocity (20 m/s), θ is the angle (30 degrees), and g is the acceleration due to gravity (10 m/s^2).
Plugging in the values, we get:
h = (20^2 * sin^2 30) / (2 * 10)
h = (400 * 0.25) / 20
h = 5 meters
Therefore, the answer is D) 5m.
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In which of the following instrument is the image that is formed erect
a. Pin hole camera b. Simple camera c. microscope d. periscope
Answer:
C. microscope
Explanation:
A simple microscope is magnifying glass, an ordinary double convex lens having a short focal length that produces virtual and erect image.
When a light ray is reflected from a surface, the ratio of the angle of incidence to the angle of reflection is
Answer:
equal to 1
Explanation:
When any ray of light falls or strikes on a surface, the ray is reflected back and the angle of reflection is equal to angle of the incidence, where both the angles are always measured from the path of light that is normal to surface of the point at which the ray of light strikes the surface. This is called as the laws of reflection of light.
And therefore, the ratio of the angle of incidence to the angle of reflection is always equal to 1.
A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?
The ratio of time of flight for inelastic collision to elastic collision is 1:2
The given parameters;
mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂Considering inelastic collision, the final velocity of the system is calculated as;
\(m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\\)
The time of motion of the system form top of the table is calculated as;
\(v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)\)
Considering elastic collision, the final velocity of the system is calculated as;
\(m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2\)
Apply one-directional velocity
\(u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1\)
Substitute the value of \(v_1\) into the above equation;
\(m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)\)
where;
\(v_2\) is the final velocity of the block after collision
Since the bullet bounces off, we assume that only the block fell to the ground from the table.
The time of motion of the block is calculated as follows;
\(v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)\)
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
\(\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2\)
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since the synthesizer is an electronic instrument, oscillation is not a factor in sound generation. T/F
Oscillation is a fundamental factor in sound generation for synthesizers, as they use electronic circuits to generate and control oscillations of various frequencies and waveforms to create different sounds. So, this statement is false
In a synthesizer, an electronic instrument, oscillation is an essential factor in sound generation. Oscillators in a synthesizer generate periodic waveforms, which are then processed and shaped to create various sounds. These oscillations form the basis of the electronic sound produced by the instrument.
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A 90 kg astronaut Travis is stranded in space at a point 12 m from his spaceship. In order to get back to his ship, Travis throws a 0.50 kg piece of equipment so that it moves at a speed of 4 m/ s directly away from the spaceship towards the left . How long will it take him to reach the ship? *hint find his speed after the collision and consider it a constant speed all the way back to his spaceship*
Answer:
Explanation:
This is a recoil problem, which is just another application of the Law of Momentum Conservation. The equation for us is:
\([m_av_a+m_ev_e]_b=[m_av_a+m_ev_e]_a\) which, in words, is
The momentum of the astronaut plus the momentum of the piece of equipment before the equipment is thrown has to be equal to the momentum of all that same stuff after the equipment is thrown. Filling in:
\([(90.0)(0)+(.50)(0)]_b=[(90.0)(v)+(.50)(-4.0)]_a\)
Obviously, on the left side of the equation, nothing is moving so the whole left side equals 0. Doing the math on the right and paying specific attention to the sig fig's here (notice, I added a 0 after the 4 in the velocity value so our sig fig's are 2 instead of just 1. 1 is useless in most applications).
0 = 90.0v - 2.0 and
2.0 = 90.0v so
v = .022 m/s This is the rate at which he is moving TOWARDS the ship (negative was moving away from the ship, as indicated by the - in the problem). Now we can use the d = rt equation to find out how long this process will take him if he wants to reach his ship before he dies.
12 = .022t and
t = 550 seconds, which is the same thing as 9.2 minutes
the amount of gravitational force that acts on a space vehicle while in earth orbit is
The amount of gravitational force that acts on a space vehicle while in earth orbit is almost zero but not absolute zero.
There is no ground force or opposing natural force to gravity.
Because the earth is not a perfect sphere, the value of "g" is lowest at the equator. At the equator, its radius is at its largest. Thus, the equator is the location where g will be smallest according to the equation
g = GM/R2.
All items in the planet's gravitational field will be lost in space if gravity abruptly vanishes. We would experience levity. Essentially, if gravity is equal to zero, then there will be no acceleration caused by gravity.
Astronauts can float within their spaceship or outside during a spacewalk in microgravity. Moving heavy stuff is simple. Astronauts, for instance, can merely use their fingertips to manipulate machinery weighing hundreds of pounds.
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What is the temperature of an incandescent lamp filament
Answer:
about 5000 °F
Explanation:
what does the 4 mean in 4Cu(NO3)2
1) subscript 2) exponent 3) multiplier 4) coefficient
Answer:
4) Coefficent in science
A mass hanging from a spring is set in motion and its ensuing velocity is given by v(t)=3πcosπt for t≥0. Assume that the positive direction is upward and s(0)=0. a. Determine the position function for t≥0. b. Graph the position function on the interval [0,3]. c. At what times does the mass reach its lowest point the first three times? d. At what times does the mass reach its highest point the first three times?
The integral of 3πcosπt is -3πsinπt, so the position function is:s(t) = -3πsinπt
a. The position function is given by the integral of the velocity function:
s(t) = int v(t) dt = int 3πcosπt dt
The integral of 3πcosπt is -3πsinπt, so the position function is:
s(t) = -3πsinπt
b.The graph of the position function is shown below. The mass reaches its lowest point when the sine function is equal to -1, and its highest point when the sine function is equal to 1.
c. The mass reaches its lowest point the first three times at times t = 2π/3, 4π/3, and 6π/3.
d. The mass reaches its highest point the first three times at times t = π/3, 5π/3, and 7π/3.
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match the columns
please answer this question
it's urgent
Answer:
1. b
2. e
3. a
4. c
5. d
hope dis helps ^-^
What will a medium-mass star become at the very end of its life cycle?
a red giant
a black hole
a black dwarf
a neutron star
What a medium-mass star becomes after a planetary nebula; a very bright, dense mass about the size of the planet Earth. ... The process that generates all of the energy that a star produces. Supernova. A Red Super Giant explodes into this when it runs out of elements to fuse together.
The process that generates all of the energy that a star produces. Supernova. A Red Super Giant explodes into this when it runs out of elements to fuse together. Hence option A is correct.
What is red giant ?A red giant is a bright giant star of low or intermediate mass (approximately 0.3-8 solar masses (M)) that has reached the end of its evolutionary cycle. The outer atmosphere is inflated and tenuous, resulting in a wide radius and a surface temperature of 5,000 K (4,700 °C; 8,500 °F) or less. The appearance of red giants ranges from yellow-white to reddish-orange, and includes spectral types K and M, as well as class S and most carbon stars.
Hence option A is correct.
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what are the luminosity class and spectral type of a star with an effective temperature of 5000 k and a luminosity of 100 lsun?
K type. A giant star is a star with a luminosity class + spectral type of 100 lsun and an absolute temperature of 5000 k.
What exactly is a star's luminosity?The total quantity of energy emitted by a star or other astronomical object each second is expressed as luminosity, or L. Therefore, this is how much power a star produces. The bolometric luminosity of a star is the total power production at all wavelengths.
What is an illustration of luminosity?Something's luminosity refers to its capacity to emit light or to reflect light. A big, sparkling diamond's brightness is its most distinguishing feature. You might use the word "luminosity" to describe a vivid and colorful oil painting or to praise the brilliance of a sunset.
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024 (part 1 of 3) 10.0 points
A 2.0 kg block is pushed 3.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 29.0° with the horizon-
tal, as shown in the figure.
The acceleration of gravity is 9.81 m/s².
2 kg
3 m
29°
Drawing not to scale.
If the coefficient of kinetic friction between
the block and the wall is 0.30, find
a) the work done by the force on the block.
Answer in units of J.
The work was done by the force on the block of 2 kg with an acceleration gravity of 9.81 \(m/s^2\) and at an angle of \(29^o\) 42.83 J.
What is work done?When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.
To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.
Given:
The mass, m = 2 kg,
The acceleration, g = 9.81 \(m/s^2\),
θ = angle between block and surface kinetic friction = μ
Calculate the work done by the formula given below,
\(W_{fy}\) = F sinθ
\(W_{fy}\) = (\(mgsin\)θ)/ (sinθ - μ * cosθ)
Substitute the values
\(W_{fy}\) = \((2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o\)
\(W_{fy}\) = 42.83 J
Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of 9.81 \(m/s^2\), and at an angle of \(29^o\) is 42.83 J.
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what happens to the water pressure at the bottom of a geyser when some of the water above gushes out? what is the result?
The water pressure at the bottom of a geyser decreases when some of the water above gushes out. The result is a decrease in pressure which can cause more water to boil and generate steam, leading to a geyser eruption.
Geysers are hot springs that periodically erupt with boiling water and steam. This happens because water in the ground is heated by magma, which causes it to rise and accumulate in underground reservoirs. As the water heats up, it creates pressure that eventually forces it to escape through a narrow opening, creating the geyser's signature eruption.
As the pressure decreases, the boiling point of the water at the bottom also decreases. If the temperature of the water at the bottom is higher than its new boiling point, it will boil and generate steam. The steam then forces more water out of the geyser, creating an eruption.
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At resonance, a driven RLC circuit has VC = 5.0 V , VR = 8.0 V , and VL = 5.0 V . What is peak voltage across the circuit?
Answer:
V = 18v
Explanation:
total voltage= VC + VR + VL
total voltage= 5 + 8 + 5
total voltage= 18v
Se tiene un péndulo cuyo frecuencia de oscilación es de 0.4 Hz. Cual sera la frecuencia de oscilacion de otro péndulo cuya longitud es el triple del anterior
Answer:
f = 0.365 Hz
Explanation:
The angular velocity of a simple pendulum is
w = \(\sqrt{g/L}\)
angular velocity and frequency are related
w = 2π f
we substitute
2π f = \(\sqrt{g/L}\)
Let's find the initial length of the pendulum
L = \(\frac{g}{4\pi^2 } \ f_o\)
L₀ = \(\frac{9.8}{4 \pi ^2} \ 0.4\)
L₀ = 0.6206 m
Indicates that the length of the chord triples
L = 3 L₀
L = 3 0.6206
L = 1.8618 m
let's find the frequency
f = \(\frac{1}{2\pi } \ \sqrt{\frac{9.8}{1.8618} }\)
f = 0.365 Hz
Question 21 Marks: 1 Minimum wash water temperature in a hospital laundry isChoose one answer. a. 146 to 150 degrees F b. 160 to 167 degrees F c. 170 to 178 degrees F d. 185 to 196 degrees F
The option b, 160 to 167 degrees F, is likely the correct answer.
The primary goal of laundering healthcare linens is to remove soil and microbial contamination to prevent the spread of infections. The temperature of the wash water is a critical factor in achieving this goal because it directly affects the effectiveness of the cleaning and disinfection process.
According to the CDC guidelines, the minimum wash water temperature for processing healthcare linens is 160 to 165 degrees Fahrenheit (71 to 74 degrees Celsius). This temperature range is based on the fact that most bacterial pathogens and viruses are killed at temperatures above 160 degrees Fahrenheit.
It is important to note that different types of healthcare linens may have different temperature requirements based on their fabric type and level of contamination. For example, some delicate fabrics may require lower temperatures to prevent damage, while heavily soiled linens may require higher temperatures to ensure effective cleaning.
In addition to temperature, other factors such as the duration of the wash cycle, detergent selection, and mechanical action are also important in achieving effective cleaning and disinfection of healthcare linens. Proper training and adherence to established laundry protocols are essential to ensure that healthcare linens are processed safely and effectively.
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an object in motion will have a speed which is a scaler , or ( blank ) which is a vector .
Answer:
Velocity
Explanation:
Objects in motion usually have a speed which is scalar or velocity which is a vector.
A scalar quantity is one with magnitude but has no directional attribute.
A vector quantity is one with both magnitude and directional attribute.
Speed is a scalar quantity that describes the magnitude of motion a body accrues.
Velocity is a vector quantity that describes both the magnitude of motion and the direction of motion in a body.
What is the acceleration of softball if it has a mass of 5 kg and hits the catchers glove with a force of 35 N
Answer:
50m/s2^
Explanation:
We know , by newton's law of motion .
F=ma
a=f/m
a=25/0.5
a=50m/s2^
Therefore , the acceleration of a softball is .
Answer:
7 m/s²
Explanation: Force = Mass x acceleration
Also note that 1 N = 1 kg.m/s²
a=F/ m
a= 35 N/ 5 kg = 35 kg.m/ s² ÷ kg Aside:( so you cross out the kg)
a= 7 m/s²
What value of resistor R gives the circuit in the figure a time constant of 22 μs ?
The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.
The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:
RC = τ, where R is the resistance and C is the capacitance of the circuit.
Rearranging the above formula, we get:R = τ / C
Where τ is the time constant and C is the capacitance of the circuit.
From the figure, the capacitance is given as 0.1 μF
.Substituting the values of τ and C in the above formula, we get:
R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)
R = 220 Ω
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transformación en fisica
Answer:
transformation into physics??? were you asking for the translation or what?
Answer:
Explanation:
Un CAMBIO FÍSICO es una transformación en la que no varía la naturaleza de la materia. ... Cuando en una transformación de la materia una o más de estas sustancias puras "desaparecen" se está produciendo un cambio químico o reacción química.
Where does diffusion occur in the excretory system
Answer:
Diffusion of water, salts, and waste products occurs in the kidneys. Diffusion of calcium from food into cells occurs in the intestines. Molecules are not the only things that can diffuse. Heat from the body diffuses away in the form of sweat that evaporates.
Explanation:
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