please help PLEASE NOW

Journal prompt to be answered in 2 fully developed paragraphs

Prompt: What are some products (or programs) that you could purchase to help your performance in your current physical activity? How would the product (or program help)? Do you really think it is effective? Use specific examples from your experience.

Answers

Answer 1

You could purchase a fitness tracker to help your performance in your current physical activity.

Fitness tracker would help you in the area of goal setting.

Fitness trackers are effective because they have helped my friends to improve workout routine.

What are some products and programs that do help to physical activity?

Wearable fitness trackers can monitor data like heart rate, number of steps taken, distance traveled, and number of calories burned.

Supplements including protein powders, creatine, and beta-alanine can enhance recovery, muscular growth, and endurance.

Working with a coach or personal trainer can help you attain your fitness objectives by offering personalized training regimens, comments on form and technique, and accountability.

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Related Questions



What is the resistance of a resistor attached to a 1.5 V battery if the current in the circuit is 0.15 A?​

Answers

Answer:10 ohms

Explanation:

Current=0.15A

Voltage=1.5v

Resistance=voltage ➗ current

Resistance=1.5 ➗ 0.15

Resistance=10 ohms

2. An archer shoots an arrow. The action force is the bowstring against the arrow, The reaction force is...
a. Air resistance against the bow
b. Arrow's push against the bowstring
c. Grip of the archer's hand on the bow

Answers

Answer:b the arrows push against the bow string

Explanation:

The reaction force will be  Arrow's push against the bowstring.

Option b is correct.

From Newton's Third Law of  Action & Reaction, It  states that for every action  in nature there is an equal and opposite reaction.

It means that  If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Therefore, If an  archer shoots an arrow. The action force is the bowstring against the arrow, The reaction force will be  Arrow's push against the bowstring

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6.
least 2 m. If the same car is moving with the speed 80K/h,what is the minimum stopping distance?
A car moving with a speed of 40 km/h can be stopped by applying the brakes after at-

Answers

The minimum stopping distance of the car is determined as 8 m.

What is the minimum stopping distance?

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

d is the minimum stopping distanceu is the initial velocitya is the acceleration of the car

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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calculate the gravitational potential Energy of the ball relative to the ground before being thrown

calculate the gravitational potential Energy of the ball relative to the ground before being thrown

Answers

Given,

The mass of the ball, m=0.11 kg

The height of the ball before it was thrown, h₁=0.24 m

The height of the ball after it was caught by Donald, h₂=0.82 m

The gravitational potential energy is the energy stored in an object due to its position above the ground.

The gravitational potential energy of the ball before being thrown is given by,

\(E=\text{mgh}_1\)

On substituting the known values,

\(\begin{gathered} E=0.11\times9.8\times0.24 \\ =0.26\text{ J} \end{gathered}\)

Thus the gravitational potential energy of the ball relative to the ground, before being thrown is 0.26 J

Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)

Answers

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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A ball is thown-up in the air. if its initial velocity is 15 m/s. its velocity after 1.0 second is [--------------]m/s (give your answer to 2 s.f.)

Answers

Answer:

Intial velocity=15m/s

Time=1 second

Acceleration due to gravity=-10m/s²

Therefore,

v=u+at

v=15+(-10×1)

v=15-10

v=5m/s

Evaluate the formula x² =
(n-1)s²

when o = 2.94, n=39, and s=3.15.
x² = (Round to three decimal places as needed.)

Evaluate the formula x =(n-1)s0when o = 2.94, n=39, and s=3.15.x = (Round to three decimal places as

Answers

Answer:

x² = ((n-1)s²)/o²

x² = (39 - 1) * (3.15)² / (2.94)²

x² = 38 * 9.9225 / 8.6436

x² = 43.7598

Rounding to three decimal places, x² = 43.760. Therefore, the value of x² is 43.760 when o = 2.94, n = 39, and s = 3.15.

Explanation:

Math

Snelgrove describes a fishing disaster that occurred where he grew up in Canada in an effort to
explain how we are now experiencing "shifting baselines." Explain what he means by this term.

Answers

Answer:

A “shifting baseline” in the context of marine locations (and the video this question is linked to) is that our expectations of what the ocean can produce is not fully realized due to us having not seen the best in our lifetime.

Explanation:

Not the best but should be better than the other answer. It takes what was said by Snelgrove into account instead of just guessing or ignoring half of the answer.

A “shifting baseline” in terms of marine locations  is that the expectations of what the ocean can produce. He means huge fish and nowadays you can get the same fish but only half its size.

What is shifting baseline ?

A shifting baseline can be defined as a type of change where a system is measured against previous reference points represent a significant changes from an  earlier state of the system.

The concept was discovered by the fisheries scientist Daniel Pauly in his paper "Anecdotes and baseline shifting syndrome of fisheries".

He described that the way which radically depleted fisheries were evaluated by experts used the state of the fishery at the start of their  baseline.

Areas which swarmed with a specific species may have experienced long term decline which is considered the appropriate reference point for current populations.

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10. Refraction occurs...
A. only with light waves
B. at any, unpredictable time
C. when a wave changes speed
D. only at a wave front
E. All of the above

Answers

The answer is C! Good luck!


PLEASE HELP AND SHOW WORK,THANK YOU!!
4) Suppose that two identical
mass planets are sitting
million miles apart. At that
distance the planets have a
gravitational force of 1,000,000 N.
If the planets are moved
to two million miles apart, what
is the new gravitational force
between them?

Answers

The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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If the distance doubles, what happens to the force?
a. Reduced by half
b. Reduced by 1/4
c. Stays the same
d. Quadruples

Answers

i think that it is D

If you know the position vectors of a particle at two points along its path and also know the time it took to move from one point to the other, can you determine the particles instantenious velocity? its average velocity? explain.

Answers

We need the position vectors of a particle at two points along its path and also know the time it took to move from one point to the other to find the instantaneous velocity but not the average velocity.

What is the velocity?

We need to take a moment to be able to explain to ourselves again the meaning of the term velocity. Let us recall that the term velocity would have to do with the change in the position of an object with time.

We know that the velocity is a vector quantity and as such we must have to look at the direction in which the distance that has been covered has passed through and this is something that we must keep in  mind as we work through this question.

Now, we know that the velocity is the change in position as such we need the two positions of the object and the approximate time taken to make the change.

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A boat sails for 24 km pointed in the direction [40° S of WI. A constant current moves the boat 8 km [30° W of N]. If the trip takes 3 hours, find the boats resultant velocity


Please brainliest, really need it!!!

Answers

The resultant velocity of the boat is 7.5 km/h.

What is the resultant displacement of the boat?

The resultant displacement of the boat is calculated as follows;

Sum of the vertical displacement of the boat is calculated as;

∑Fy = -24 km sin(50)  + 8 km sin(60)

∑Fy = -11.5 km

Sum of the horizontal displacement of the boat is calculated as;

∑Fx = -24 km cos(50)  - 8 km cos(60)

∑Fx = -19.4 km

The resultant displacement is calculated as follows;

d = √ (-11.5² + 19.4²)

d = 22.55 km

The resultant velocity of the boat is calculated as follows;

v = ( 22.55 km ) / ( 3 hrs )

v = 7.5 km/h

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Earth satellite whose height is 35786 km then find its distance velocity

help me it's urgent i mark u brainlist

Answers

A satellite must orbit at the speed of about 11,300 km per hour.

What is Orbital speed?

The satellite's altitude above the Earth affects the speed of its orbit. A satellite must orbit at a speed of roughly 11,300 km/h in order to keep its orbit 35,786 km above the Earth. The satellite can complete one rotation in precisely 24 hours thanks to its orbital velocity and distance.

Because the satellite always passes directly over the same location. So-called "Geostationary Orbits" are the best type of orbit for meteorological satellites.

The satellite may therefore remain in orbit for a longer period of time the higher the orbit. A satellite like the moon can remain in orbit for centuries at higher altitudes where the vacuum of space is almost complete.

Therefore, A satellite must orbit at the speed of about 11,300 km per hour.

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How did Einstein’s and Newton’s theories differ in terms of explaining the cause of gravity?
thank you

Answers

Answer:

Newton's theory identified mass as the factor that causes gravity. On the other hand, Einstein's theory identified the curvature of space-time as the factor that causes gravity.

Answer:

Hey mate...

Explanation:

This is ur answer....

In the 17th century Newton concluded that objects fall because they are pulled by Earth's gravity. Einstein's interpretation was that these objects do not fall. According to Einstein, these objects and Earth just freely move in a curved spacetime and this curvature is induced by mass and energy of these objects.

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Using the data below, what would be the independent variable?

A. Type of Coke (Diet Coke or Coca Cola)

B. Trial number

C. Height of Explosion

D. Number of Mentos

Answers

A. Type of Coke (Diet Coke or Coca Cola)

what is the value of pi(8.104)^2 written with correct significant numbers

Answers

Answer:206.3

Explanation:

The resistance RT of a platinum varies with temperature T(°C), as measured on the constant-volume gas thermometer according to the equation RT = Ro(1+AT+BT^2). Where A = 3.8×10^-3°C^-1 and B = -5.6×10^-7°C^-2. Calculate the temperature that would be on indicated on a platinum thermometer, when the gas scale reads 200°C.​

Answers

The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.

The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we will have to use the given formula. RT = Ro(1+AT+BT²) .....(i)We know that the gas scale reads 200°C. Therefore, we can substitute T = 200°C in equation (i).RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648)Thus, the resistance that the platinum thermometer would indicate is 1.648 times the reference resistance Ro at 0°C. This is the solution to the problem.In summary, The given equation is RT = Ro(1+AT+BT²), where A = 3.8×10⁻³°C⁻¹ and B = -5.6×10⁻⁷°C⁻². To determine the temperature that would be indicated on a platinum thermometer when the gas scale reads 200°C, we substituted T = 200°C in equation (i) to get RT = Ro (1 + A × 200 + B × 200²) = Ro (1 + 0.76 - 0.112) = Ro (1.648).

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why does all the water of the earth not get evaporated during hot summer days?​

Answers

Answer:

Water has a high latent heat of vaporization, so it takes a large amount of heat to get converted into vapor. Although evaporation takes place continuously, there is simply not enough heat produced to evaporate all the water on earth at once.

You are trying to determine the identity of an unknown metal object using density. You measure the volume by displacement using a graduated cylinder. The initial volume is 14.7 mL, and the final volume is 23.5 mL. The mass is measured using a balance and is determined to be 68.895 g. The calculation you use to find the answer is: $$

Answers

The formula you use is Density = (mass) / (volume) .

The calculation for this particular object is

Density = (68.895 g) / (23.5 mL - 14.7 mL)

Density = (68.895 g) / (8.8 mL)

Density = 7.8 g/mL

a) Define the Inverse Square Law and show that the field strength, E of a single charge Q acting on a test charge Q at a distance x from it along its field is given by
(b) A circuit consists of a variable resistor R connected in series with an ammeter and a cell. A voltmeter is connected in parallel across the variable resistor R. the cell is of e.m.f E and internal resistance r. For a certain value of R, the voltmeter reads 4V and the ammeter reads 1A. When R is adjusted, the voltmeter reads 2V and the ammeter reads 2.5A. Draw the circuit diagram and calculate the values of E and r.​

Answers

a. The Inverse Square Law states that the intensity or strength of a physical quantity decreases with the square of the distance from its source.

b. The values of E and r in the given circuit are: E = 4V (e.m.f. of the cell) and r = ∞

How to explain the information

a. In the context of electrostatics, the Inverse Square Law describes the relationship between the electric field strength and the distance from a charged particle.

b. For the first scenario (V = 4V and I = 1A), we have:

4V = 1A * R1,

R1 = 4Ω.

For the second scenario (V = 2V and I = 2.5A), we have:

2V = 2.5A * R2,

R2 = 0.8Ω.

Total resistance in the circuit (when ammeter reads zero current) is given by:

= R1 + R2 + r.

Since the ammeter reads zero current, we have:

E = I * R_total,

4V = 0A * R_total,

R_total = ∞ (infinity).

Therefore, we can conclude that the internal resistance r of the cell is infinite (or very high compared to the resistances in the circuit).

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An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike

Answers

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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A 23900N/C electric field points down. What is the value of a charge placed in the field if it experiences a force of 7520N up?

Answers

Answer:

0.315C

Explanation:

Force/Electric field

7520N/23900C

The nose is relation to the foot

Answers

RLLY?

Explanation:

ALSO

MY DAD ALWAYS TELLS ME THAT IF YOUR FEET ARE COLD THAT YOU NEED TO PUT A HAT ON?!?!?!?!?!

Discussion of the experiments with the dynamics track: Newton’s laws

Answers

Experiments with the dynamics track provide a practical and visual way to demonstrate the laws of motion proposed by Newton, which are still fundamental to our understanding of physics today.

What is Newton's First Law?

Newton's first law of motion states that an object at rest will remain at rest, and an object in motion will continue to move at a constant velocity in a straight line, unless acted upon by an unbalanced force. To demonstrate this, a cart or ball can be placed on the track and allowed to roll with no additional forces acting on it. The object will continue to move at a constant velocity until it is stopped by friction or another force.

Experiments with a dynamics track can provide insights into the fundamental laws of motion proposed by Sir Isaac Newton. The dynamics track consists of a track with a level, smooth surface, which allows objects to slide or roll along it with minimal friction. The experiments usually involve a cart or a ball, and various additional objects such as weights, springs, and pulleys, to test the laws of motion.

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Is the force exerted by the scale on the superball greater than, less than, or equal to the force exerted by the scale on the clay

Answers

Answer: A glob of very soft clay is dropped from above onto a digital scale. The clay sticks to the scale on impact. A graph of the clay's velocity vs. time, clay (t), is given, with the upward direction defined as positive.

The experiment is then repeated, but instead of using the clay glob, a superball with identical mass is dropped from the same height onto the scale.

Both the clay and the superball hit the scale 2.9s after they are dropped. Assume that the duration of the collision is the same in both cases and the force exerted by the scale on the clay and the force exerted by the scale on the superball are constant.

Explanation:

In the legend of William Tell, Tell is forced to shoot an apple from his son's head for failing to show respect to a high official. In our case, let's say Tell stands 8.7 meters from his son while shooting. The speed of the 144-g arrow just before it strikes the apple is 20.4 m/s, and at the time of impact it is traveling horizontally. If the arrow sticks in the apple and the arrow/apple combination strikes the ground 8 m behind the son's feet, how massive was the apple

Answers

Answer:

M = 0.31 kg

Explanation:

This exercise must be done in parts, let's start by finding the speed of the set arrow plus apple, for this we define a system formed by the arrow and the apple, therefore the forces during the collision are internal and the moment is conserved

let's use m for the mass of the arrow with velocity v₁ = 20.4 m / s and M for the mass of the apple

initial instant. Just before the crash

          p₀ = m v₁ + M 0

instant fianl. Right after the crash

          p_f = (m + M) v

          p₀ = p_f

          m v₁ = (m + M) v

          v =\(\frac{m}{m+M} \ v_1\)                          (1)

now we can work the arrow plus apple set when it leaves the child's head with horizontal speed and reaches the floor at x = 8 m. We can use kinematics to find the velocity of the set

          x = v t

          y = y₀ + \(v_{oy}\) t - ½ g t²

when it reaches the ground, its height is y = 0 and as it comes out horizontally, \(v_{oy} = 0\)

          0 = h - ½ g t²

          t² = 2h / g

     

For the solution of the exercise, the height of the child must be known, suppose that h = 1 m

            t = \(\sqrt{ \frac{ 2 \ 1}{9.8} }\)

            t = 0.452 s

let's find the initial velocity

             v = v / t

             v = 8 / 0.452

             v = 17.7 m / s

From equation 1

              v = m / (m + M) v₁

              m + M = \(m \ \frac{v_1}{v}\)

              M = m + m \  \frac{v_1}{v}

we calculate

              M = 0.144 + 0.144  \(\frac{20.4}{17.7}\)

              M = 0.31 kg

A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle \theta\:=\:θ = 35.4 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?

Answers

Answer:

The velocity is  \(v = 2.84 1 \ m/s\)

Explanation:

The  diagram showing this set up is shown on the first uploaded image (reference Physics website )

From the question we are told that

    The mass is  m =  4 kg

    The  length of the string is \(L = 2.0 \ m\)

    The constant angle is  \(\theta = 35.4 ^o\)

     

Generally the vertical forces acting on the mass to keep it at equilibrium vertically is mathematically represented as

           \(Tcos (\theta ) - mg = 0\)

=>        \(mg = Tcos (\theta )\)

Now let the force acting on mass horizontally be k  so from SOHCAHTOA rule

         \(sin (\theta ) = \frac{k }{T}\)

=>      \(k = T sin \theta\)

Now this k is also equivalent to the centripetal force acting on the mass which is mathematically represented as

          \(F_v = \frac{m v^2}{r}\)

So

          \(k = F_v\)

Which

=>       \(T sin \theta= \frac{ m v^2}{ r }\)

     

So

        \(\frac{Tsin (\theta )}{Tcos (\theta )} = \frac{mg}{ \frac{mv^2}{r} }\)

=>      \(Tan (\theta ) = \frac{v^2}{ r * g }\)

=>      \(v = \sqrt{r * g * tan (\theta )}\)

Now the radius is evaluated using SOHCAHTOA rule as

       \(sin (\theta) = \frac{ r}{L}\)

=>    \(r = L sin (\theta)\)

substituting values

       \(r = 2 sin ( 35.4 )\)

       \(r = 1.1586 \ m\)

So

       \(v = \sqrt{1.1586* 9.8 * tan (35.4 )}\)

       \(v = 2.84 1 \ m/s\)

A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V.

Discuss the similarities and differences between the electrical force on a charge and the magnetic force on a charge.

Answers

Explanation:

Both are field dependent. Electric force is dependent on charge, while Magnetic force is dependent on current or rate of charge flow

Describe how electromagnetic waves are formed and travel through space.

Answers

Answer:

Electromagnetic waves are created by a charged particle that generates an electric field. The electric field creates a magnetic field. As the charged particle moves, the electric field and magnetic field keep changing, which causes the wave to move.

Explanation:

I just answered the question and this is the sample response

Electromagnetic waves are propagated as electric and magnetic fields at right angles with each other. Electromagnetic waves can travel through space.

What are electromagnetic waves?

The electromagnetic waves are composed of electric and magnetic fields which are inclined at right angles to each other. We must note that  these waves do not require a medium of propagation as they travel through space.

Hence, electromagnetic waves are propagated as electric and magnetic fields at right angles with each other.

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