PLEASE PLEASE HELP PICTURE INCLUDED

PLEASE PLEASE HELP PICTURE INCLUDED

Answers

Answer 1

Answer:

a is the answer

Explanation:


Related Questions

Identify the time interval during which the velocity of shuttle bus is zero.​

Identify the time interval during which the velocity of shuttle bus is zero.

Answers

Explanation:

during D and E, so between 13 and 16 (whatever time unit this is - hours, minutes, ... ?).

Answer:

Explanation:

The time interval 13 to 16 seconds

An excited hydrogen atom releases an electromagnetic wave to return to its normal state. You use your futuristic dual electric/magnetic field tester on the electromagnetic wave to find the directions of the electric field and magnetic field. Your device tells you that the electric field is pointing in the negative x direction and the magnetic field is pointing in the negative y direction. In which direction does the released electromagnetic wave travel

Answers

Answer: the magnetic wave will travel out of the screen.

Explanation:

Electric field direction is perpendicular to the magnetic field direction. Both are also perpendicular to the direction of the particles.

Using right hand rule to solve this problem,

This pointed finger depicts the electric field direction which the curly fingers depict the direction of the magnetic field. The pointed thumb will depict the direction in which the wave travel. Which is out of the screen.

2. A student writes the arrangement of electrons in an atom as 2, 10, 1.
Why is this wrong? What should the student have written?

Answers

Answer:

2 electrons

Explanation:

Why does current flow in a coil when a magnet is pushed in and out of the coil ?

Answers

Answer:

So the induced current opposes the motion that induced it (from Lenz's Law). When we pull the magnet out, the left hand end of the coil becomes a south pole (to try and hold the magnet back). Therefore the induced current must be flowing clockwise.

hope this helps u...

Terminal velocity. A rider on a bike with the combined mass of 100kg attains a terminal speed of 15m/s on a 12% slope. Assuming that the only forces affecting the speed are the weight and the drag, calculate the drag coefficient. The frontal area is 0.9m2 .

Answers

Answer:

0.9378

Explanation:

Weight (W) of the rider = 100 kg;

since 1 kg = 9.8067 N

100 kg will be = 980.67 N

W = 980.67 N

At the slope of 12%, the angle θ is calculated as:

\(tan \ \theta = \dfrac{12}{100} \\ \\ tan \ \theta = 0.12 \\ \\ \theta = tan^{-1}(0.12) \\\\ \theta = 6.84^0\)

The drag force D = Wsinθ

\(\dfrac{1}{2}C_v \rho AV^2 = W sin \theta\)

where;

\(\rho = 1.23 \ kg/m^3\)

A = 0.9 m²

V = 15 m/s

Drag coefficient \(C_D = \dfrac{2 *W*sin \theta}{\rho *A *V^2}\)

\(C_D =\dfrac{2 *980.67*sin 6.84}{1.23 *0.9 *15^2}\)

\(C_D =0.9378\)

A ray of light makes an angle of 35 with a plane mirror ,what is the reflection​

Answers

When a ray of light strikes a plane mirror, the angle of reflection is equal to the angle of incidence.

In this case, the ray of light makes an angle of 35 degrees with the plane mirror. Therefore, the angle of reflection will also be 35 degrees. To understand why this happens, we need to consider the properties of reflection. When light interacts with a smooth surface like a mirror, it follows the law of reflection.

According to this law, the incident ray, the reflected ray, and the normal (a line perpendicular to the mirror's surface) all lie in the same plane. The angle of incidence is the angle between the incident ray and the normal, measured on the side of the normal where the light is coming from. In this case, the angle of incidence is 35 degrees.

According to the law of reflection, the angle of reflection is the angle between the reflected ray and the normal, also measured on the side of the normal where the light is coming from. Since the incident and reflected rays are on opposite sides of the normal, the angle of reflection is also 35 degrees.

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Show all work. Write the equation, plug in numbers, and get answer with unit.
9. A child sits on a dock and notices that 8 wavelengths pass the end of the dock in 4 seconds. What is
the frequency of the waves passing the dock? What is the period of the waves?
10. A pendulum oscillates 12 times in 4 seconds.
a. What is the frequency of the pendulum's oscillations?
b. What is the period of the pendulum's oscillations?
11. water wave has a frequency of 2 Hz, and there are 3 meters between each crest on the wave. How
fast is the wave moving?
12. Sound waves travel at roughly 340 m/s at room temperature. The minimum hearing range of a
human is 20 Hz. What is the wavelength of this wave?
I

Answers

The frequency is the inverse of time period of a wave and the time period of a wave is the time taken divided by number of cycles or wave.

What is Frequency and period of a wave?

A wave is a propagating dynamic disturbance of different quantities. Frequency is the number of waves which are passing by a specific point of time per second. And, time period is the time which the wave takes for one wave cycle to complete.

Frequency of a wave can be calculated by reciprocal of time taken.

Frequency of a wave = 1/ Time period

The time period is the time in which one wave.

9. The time period of the wave = Time taken/ Number of waves or cycles

Time period = 4/ 8

Time period = 1/2 or 0.5 sec

Frequency of a wave = 1/ T

Frequency of a wave = 1/ 0.5 = 2⁻¹

10. The time period of the pendulum's oscillations = 4/ 12 = 1/3 = 0.33 sec

The frequency of the pendulum's oscillations = 3.03 sec⁻¹

11. Speed of a wave = wavelength of a wave × frequency of the wave

Speed of a wave = 3 × 2

Speed of a wave = 6 meters per second

12. Wavelength of the wave will be the ratio of speed of the wave and frequency of the wave.

Wavelength (λ) = Speed of the wave (v)/ frequency of the wave (f)

Wavelength = 340/ 20

Wavelength = 170 meters

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In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the energy of the spring at the start

Answers

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

final speed of the box, v = 10 m/s

Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

¹/₂ x 8 x 10² = Ux

400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

PLS HELP!!!!
by pushing the crate up the ramp rather than lifting it to the platform, you are using ________ force, but moving the crate a ____________ distance


A) more; less
B) more; greater
C) less; greater
D) the same amount; greater

Answers

Answer:

a

Explanation:

rwggwh4

The Milky Way is our home galaxy. Which of the following are the main components of a galaxy?
A.
gravity, sedimentary rocks, and water


B.
ice, meteoroids, and minerals


C.
orbits, cores, and eclipses


D.
gas, dust, and stars

Answers

Answer:

D

Explanation:

most probable answers. I miss however here few things like eg. dark matter

Measurement is advantageous in daily life. Why?​

Answers

Answer:

Measurements play an important role in daily life because they are useful to do basic tasks, such as take a child's temperature with a thermometer, make time estimations, measure out medicine and find weights, areas and volumes of different materials or substances

Hope this helps you ❤️❤️Mark me as brainliest ❤️

A is thrown up into the air with initial vem/s. How fast is the ball moving when it first reachemeters?

Answers

Once the ball is thrown, the only force acting on it is gravity, which means that it's acceleration is -9.81 m/s² (negative means downward).

List the known and unknown quantities from the question.

u = initial velocity = 20 m/s

v = final velocity = ? m/s

g = acceleration due to gravity = -9.81 m/s²

t = time interval = ? s

s displacement = 11 m

Before calculating the time it takes for the ball to reach 11 m, the final velocity needs to be calculated using the following kinematic equation.

v² = u² + 2gs

v = √(u² + 2gs)

= √((20 m/s)² + (2x-9.81 m/s² x 11 m)) = 13.57 m/s V=

Calculate the time it takes the ball to reach 11 m using the following kinematic equation.

V = u + gt

Solve for t.

t = (v-u)/g

t (13 57 m/s - 20 m/s)/(-981 m/s²) = 0.655 s

A 70 kg stunt pilot begins pulling out of a dive into a vertical circle. If the plane's speed at the lowest point of the circle is 80 m/s, what is the apparent
weight of the pilot at the lowest point of the pullout? The pilot experiences a force of 5g from the centripetal acceleration at the bottom of the dive.
O
3880 N
о
3430 N
0
4116 N
3986 N

Answers

Answer:

Apparent weight of pilot due to centripetal acceleration:

m v^2 / R = 5 g m = 5 * 70 * 9.8 = 3430 N

Weight of pilot = 70 * 9.8 = 686 N

Total = 3430 + 686 = 4116 N

Nativism was rejected in the late 1600’s and early 1700’s by a group, of philosophers called:

Answers

Answer:

Nativism was rejected in the late 1600’s and early 1700’s by a group, of philosophers called?

Empiricists Is the Correct Answer!

xXxAnimexXx

Happy Labor day!

5.
Find the equation of the circle tangential to the line 3x-4y+1=0 and with
centre at (4,7).
20​

Answers

Answer:  (x - 4)² + (y - 7)² = 9

Explanation:

The equation of a circle is: (x - h)² + (y - k)² = r²    where

(h, k) is the centerr is the radius

Given: (h, k) = (4, 7)

Find the intersection of the given equation and the perpendicular passing through (4, 7).

3x - 4y = -1

     -4y = -3x - 1

        \(y=\dfrac{3}{4}x-1\)

              \(m=\dfrac{3}{4}\)      -->      \(m_{\perp}=-\dfrac{4}{3}\)

\(y-y_1=m_{\perp}(x-x_1)\\\\y-7=-\dfrac{4}{3}(x-4)\\\\\\y=-\dfrac{4}{3}x+\dfrac{16}{3}+7\\\\\\y=-\dfrac{4}{3}x+\dfrac{37}{3}\)

Use substitution to find the point of intersection:

\(x=\dfrac{29}{5}=5.8,\qquad y=\dfrac{23}{5}=4.6\)

Use the distance formula to find the distance from (4, 7) to (5.8, 4.6) = radius

\(r=\sqrt{(5.8-4)^2+(4.6-7)^2}\\\\r=\sqrt{3.24+5.76}\\\\r=\sqrt9\\\\r=3\)

Input h = 4, k = 7, and r = 3 into the circle equation:

(x - 4)² + (y - 7)² = 3²

(x - 4)² + (y - 7)² = 9

5.Find the equation of the circle tangential to the line 3x-4y+1=0 and withcentre at (4,7).20

. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)

Answers

a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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Need help for this Asap please ​

Need help for this Asap please

Answers

The coefficient of static friction between the block of wood and the table is 0.449.

How to calculate the friction

The weight of the block of wood is Mg = 4.0 kg × 9.81 m/s^2 = 39.24 N.

The coefficient of static friction μs is given by the equation μ_s = fs/N, where N is the normal force from the table.

Since the block is not accelerating vertically, we know that N = Mg, so we have:

μs = fs/N = 17.64 N / 39.24 N = 0.449

Therefore, the coefficient of static friction between the block of wood and the table is 0.449.

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what is the suns purpose

Answers

Answer:

The Sun provides Life to the Earth

Explanation:

The Sun is made up of mostly Hydrogen and some Helium, and it is in delicate balance with both gravity trying to pull it in while the power of fusion pushes it outwards. The fusion creates energy, which is used to keep our delicate world in balance with the sun.

A spring running horizontally has areas with the coils closer together and areas with them farther apart. A label A points to areas where they are closer together. A label B points to areas where they are farther apart. A label C sits near a bracket connecting the center of two successive areas with the coils farther apart, which are separated by an area of closer coils.


THE CORRECT ANSWERS IS the first one is C second is B and last is A
FOR edge Physics

Answers

Your description suggests that the spring's coils are not distributed evenly throughout, with some regions having coils that are closer together than others.

What does it mean when the compressions of a longitudinal wave are far separated?

The wave's energy determines how close the particles are together during compressions and how far apart they are during rarefactions.

What are the names of the regions where the coils are most distant?

A rarefaction is an area where the coils are widely spaced, maximising the spacing between coils. A rarefaction is the lowest density point in a medium through which a longitudinal wave is propagating.

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In winter morning, as soon as we wake the air inside the room is cold but if up, the out and return to the same room, we we goo feel warm, why?​

Answers

Answer:

it is all because of nature

What is the mass of a block of lead that is 30cm by 80cm by 60cm?

Answers

Calculating the mass of the block requires a bit of work. The formula for the volume of a rectangular solid is V = l*w*h, where V is the volume, l is the length, w is the width, and h is the height. Using the dimensions given, we can calculate the volume of the block as 30*80*60 = 144000 cubic centimeters.

The density of lead is approximately 11.34 grams per cubic centimeter. To calculate the mass of the block, we can use the formula m = V*d, where m is the mass, V is the volume, and d is the density. Plugging in the values we get m = 144000*11.34 = 1,634,400 grams or approximately 1.63 metric tons.

So, the mass of the block of lead is approximately 1.63 metric tons.


So how should i get (i)
Still didn’t get it ?

So how should i get (i)Still didnt get it ?

Answers

Answer & Explanation:

using a ruler measure the distance between the pivot and the center point of the load  

note : prevent zero error

So how should i get (i)Still didnt get it ?


The string will break if the tension in
it exceeds 0.180 N. What is the
smallest possible value of d (in cm)
before the string breaks?

Answers

Answer:

define d first?

you need to list more variables

Answer:

list more valuable unit

how deep is the event horizon

Answers

Explanation:

The supermassive black holes that the Event Horizon Telescope is observing are far larger; Sagittarius A*, at the center of the Milky Way, is about 4.3 million times the mass of our sun and has a diameter of about 7.9 million miles (12.7 million km), while M87 at the heart of the Virgo A galaxy is about 6 billion solar ..

Given the information in the velocity vs. time graph, what is the displacement of the object after 1 second?


_____ m


After 3 seconds?


_____ m


After 5 seconds?


_____ m


Thank you!!!

Given the information in the velocity vs. time graph, what is the displacement of the object after 1

Answers

The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

What is displacement?

The displacement of an object is the change in the position of the object.

displacement of the object after 1 second

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

displacement of the object after 3 second

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

displacement of the object after 5 second

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons

Answers

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

Why the electron number cannot be used instead?

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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A net force of 34N is applied to accelerate an object at a rate of 2.5m/s2. What is the mass of the object?

Answers

Answer: Mass= 13.6 kg

Explanation:

F = m * a

34 = m (2.5)

m = 34 / 2.5

m = 13.6 kg

Please help!
A tennis ball falls off a shelf and bounces several times. Each bounce is lower than the one before. Soon the ball stops. Why doesn’t the ball keep bouncing?

A) some of the energy is changed into mass

B) The energy becomes stored in the ball

C) Energy is transferred to the air and ground

Answers

Answer:

c

Explanation:

energy isn't stored and it doesn't change to mass

The ball has some kinetic energy when it hits the floor, but some of it is changed, so it loses some of it each time it bounces. After a few bounces, the ball has so little kinetic energy remaining that it stops bouncing. Thus, option C is correct.

What doesn’t the ball keep bouncing?

Since the gravitational potential energy, which can be transformed back into kinetic energy on the rebound, increases with the drop height, the consequent bounce height will likewise rise.

Because it has the most elasticity, the rubber ball will rebound the highest when all three balls are dropped from the same height. Because rubber is incredibly elastic, it squishes or compresses as it touches the ground but immediately snaps back to its original shape.

Therefore, Additionally, some energy is changed into other forms like heat and sound. The majority of these additional energy sources are lost and not recovered, causing the ball to bounce back to a lesser height.

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X= -5, 1, 7,10,22 f(x)= 7,2,0,1,18 what is the domain of the range is 1

Answers

Answer:

Well if X= -5, 1, 7, 10, 22 and if f(x)= 7, 2, 0, 1, 18 than there is your answer.

Explanation:

[X= 1]

Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?

Answers

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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