Answer:
E = 550 V/m = 550 N/C
Explanation:
The formula for calculating the potential difference between two points in an electric field is given as follows:
ΔV = E.Δr
where,
ΔV = Potential Difference between points P and Q = 55 V
Δr = Distance between P and Q = 0.1 m
E = Magnitude of Electric Field = ?
Therefore, using these values in the equation, we get:
55 V = E(0.1 m)
E = 55 V/0.1 m
E = 550 V/m = 550 N/C
Because, volt/meter is equivalent to Newton/Coulomb.
Derive an expression of total energy Kinetic energy plus potential energy in rolling motion
The derivation of the total energy Kinetic energy plus potential energy in rolling motion is shown in the image attached.
What is the total energy Kinetic energy plus potential energy in rolling motion?In rolling motion, the total energy is the sum of the kinetic energy and the potential energy. Rolling motion is a combination of rotational and translational motion, and the energy of rolling can be expressed as follows:
Total energy = Kinetic energy + Potential energy
The derivation has been done and shown in the image attached here.
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if you have an acceleration of 15m/s^2, what does it mean?
A spring stretches 0.294-m when a 0.360-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.431-kg mass resting on a frictionless table as in Fig. 11–5. The mass is pulled so that the spring is stretched 0.250-m from the equilibrium point, and released from rest.
Determine:
(a) the spring stiffness constant k.
The spring constant k based on the information is 12.0 N/m.
How to calculate the valueFrom the information, a spring stretches 0.294-m when a 0.360-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.431-kg mass resting on a frictionless table.
The spring constant k is the force required to stretch or compress the spring by a unit distance. In this case, the spring is stretched by 0.294 m when a 0.360 kg mass is suspended from it.
This means that the force exerted by the spring is equal to the weight of the mass, which is 0.360 kg x 9.8 m/s^2 = 3.53 N.
Therefore, the spring constant k is:
= 3.53 N/0.294 m
= 12.0 N/m.
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A 0.14 kg ball is dropped from a height and hits the ground at a velocity of -9 m/s (the negative sign shows the downward direction of the ball's motion). After
touching the ground for a short period of time, the ball bounces back at a velocity of +8.5 m/s. What is the impulse on the ball due to the floor?
Answer:
Impulse = Δp = 2.45 kg m/s
Explanation:
Impulse = change in momentum = final momentum - initial momentum
The initial momentum of the ball before hitting the ground is given by:
m * v_i = 0.14 kg * -9 m/s = -1.26 kg m/s
The final momentum of the ball after bouncing back is given by:
m * v_f = 0.14 kg * 8.5 m/s = 1.19 kg m/s
So the change in momentum is:
Δp = v_f - v_i = 1.19 kg m/s - (-1.26 kg m/s) = 2.45 kg m/s
Impulse = Δp = 2.45 kg m/s
the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm
The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.
What is the image and object distance?The object and image distance formed by the lens is calculated by applying the following lens formula.
v + u = 40 ------- (1)
v/u = 3 ------------ (2)
v = 3u
Substitute v into equation (1);
3u + u = 40
4u = 40
u = 40/4
u = 10 cm
The image distance = 3u
= 3 x 10 cm
= 30 cm
Thus, the object distance is 10 cm and the image distance is 30 cm.
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The Sun radiates energy at a rate of about 4×1026W. At what rate is the mass decreasing?
4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.
The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.
To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.
Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.
ΔE = 4×10^26 W
c = 3×10^8 m/s (speed of light)
Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².
Substituting the values, we have:
Δm = (4×10^26 W) / (3×10^8 m/s)²
Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.
This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.
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can anyone write for me all the equation of linear motion
All the equations of motion are as follows, Displacement (s) equation, Final velocity (v) equation, Average velocity (v_avg) equation, Displacement (s) equation with average velocity, and Displacement (s) equation.
Equations of MotionIn terms of its motion as a function of time, equations of motion define how a physical system behaves. In more detail, the equations of motion define how a physical system behaves as a collection of mathematical functions expressed in terms of dynamic variables.
s = ut + (1/2)at^2v = u + atv_avg = (u + v) / 2s = v_avg * ts = (u + v) / 2 * tv^2 = u^2 + 2asIn conclusion, equations of motion define how a physical system behaves in terms of how its motion changes over time.
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What image is produced by placing an object 4 cm away from a convex lens of focal length 8 cm? draw the ray diagram and discuss the obtain result
The image is formed 8cm in front of the lens and is a real image.
What is the nature of the image?We would have to remind ourselves that if we are looking at the lens then we have to be looking at any reflecting surface that we know. There are two kinds of lens that we have, we have the concave and the convex lens.
We know that the focal length of the convex lens is positive thus we have;
1/f = 1/u + 1/v
f = focal length
u = object distance
v = image distance
Thus;
1/8 = 1/4 - 1/v
1/v = 1/4 - 1/8
v = (0.25 - 0.125)^-1
v = 8 cm
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1. Which distance is the greatest?
O 7000 meters
O 99.99 meters
O 4.5 x 10³ meters
O 9.0 x 10² meters
Answer:
7000 meters
Explanation:
obviously 99.99 is less than 7000
10 cubed is 10 × 10 × 10, 1000, × 4.5 is 4500, which is less than 7000
10 squared is 100, which × 9 is only 900, which is also less than 7000
have a good day
what is the magnitude of its velocity just before it strikes the ground, if the bottle was thrown straight out horizontally from the tower with a speed of 11.8 m/s?
There's not enough given information to find the answer.
The horizontal velocity has no effect on anything that happens vertically. To find the object's vertical speed when it hits the ground, we need to know what height it was dropped from, and that's not given in the question.
Since the bottle is falling vertically, the vertical displacement s is the height of the tower from which it was thrown.
If a bottle is thrown horizontally from a tower, its initial vertical velocity is 0 m/s since there is no vertical component to its initial velocity. The only force acting on the bottle in the vertical direction is gravity, which causes it to accelerate downward at a rate of approximately 9.81 m/s² (assuming Earth's gravity).
Since the initial vertical velocity is 0 m/s and the acceleration is 9.81 m/s², you can use the following kinematic equation to find the magnitude of its velocity just before it strikes the ground:
v2=u2+2as
Where:
v is the final vertical velocity (which we're trying to find)
u is the initial vertical velocity (0 m/s)
a is the acceleration due to gravity (-9.81 m/s², negative because it's acting downward)
s is the vertical displacement (which is the height of the tower)
Since the bottle is falling vertically, the vertical displacement
s is the height of the tower from which it was thrown.
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define stress engineering science
Answer:
Stress, in physical sciences and engineering, force per unit area within materials that arises from externally applied forces, uneven heating, or permanent deformation and that permits an accurate description and prediction of elastic, plastic, and fluid behaviour.
I hope it's helpful!
I need help with part B plsss !!
The time taken for the object to travel the given height is determined as 12.48 seconds.
What is time of motion?
Time of motion of an object is the total time taken by the object to travel a given height or distance.
Time taken for the boulder to reach the groundThe time of motion of the boulder is calculated as follows;
h = vt + ¹/₂gt²
where;
h is the height of fallv is the initial velocityt is the time of motiong is acceleration due to gravity1300 = 43t + 0.5(9.8)t²
1300 = 43t + 4.9t²
4.9t² + 43t - 1300 = 0
solve the quadratic equation using formula method as shown below;
a = 4.9, b = 43, c = -1300
t = 12.48 seconds
Thus, the time taken for the object to travel the given height is determined as 12.48 seconds.
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What is the displacement of a car traveling 34 km North on I985 then 20 km South on I985
Answer:
34 - 20 = 14 km North on 1985
Explanation:
Explanation:
The displacement of the car is 14km North
34 - 20 = 14km
Find the principal stresses and corresponding principal directions for the stresses given in Problem 2.6. Check the result with other methods such as Mohr's circle.
The principal stresses and corresponding principal directions for the stresses in a problem can be found using various methods, one of which is Mohr's circle.
What is Mohr's circle?
Mohr's circle is a graphical representation of a two-dimensional stress state. Given the stress tensor components, the Mohr's circle can be used to visualize and determine the maximum and minimum normal stresses (i.e., the principal stresses) and the orientation of the planes on which they act (i.e., the principal directions).
It is important to note that finding the principal stresses and directions requires a thorough understanding of stress analysis, including stress transformation and the use of Mohr's circle. If you have access to the full problem statement, I would be happy to help you work through the solution.
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Three 40-Ω lightbulbs and three 80-Ω lightbulbs are connected in series.(a) What is the total resistance?(b) What would be their resistance if all six were wired in parallel?
(a)
In order to find the series total resistance, we need to add all resistances:
\(R_{eq}=R_1+R_2+R_3+R_4+R_5+R_6\)If three resistances are 40 ohms and three are 80 ohms, we have:
\(\begin{gathered} R_{eq}=40+40+40+80+80+80\\ \\ R_{eq}=360\text{ ohms} \end{gathered}\)(b)
Now, since the resistances are in parallel, we need to use the expression below:
\(\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\frac{1}{R_4}+\frac{1}{R_5}+\frac{1}{R_6}\)So we have:
\(\begin{gathered} \frac{1}{R_{eq}}=\frac{1}{40}+\frac{1}{40}+\frac{1}{40}+\frac{1}{80}+\frac{1}{80}+\frac{1}{80}\\ \\ \frac{1}{R_{eq}}=\frac{3}{40}+\frac{3}{80}\\ \\ \frac{1}{R_{eq}}=\frac{6}{80}+\frac{3}{80}\\ \\ \frac{1}{R_{eq}}=\frac{9}{80}\\ \\ R_{eq}=\frac{80}{9}\text{ ohms} \end{gathered}\)A chair of weight 130 N N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F F = 37.0 N N directed at an angle of 41.0 ∘ ∘ below the horizontal and the chair slides along the floor.Using Newton's laws, calculate n n , the magnitude of the normal force that the floor exerts on the chair.
The magnitude of the normal force that the floor exerts on the chair is 124.154.
The second law of Newton provides a numerical description of force. A body's momentum is equal to the sum of its mass and velocity. In a sense, momentum is a vector quantity that has both magnitude and velocity. A body can change its momentum, velocity, or both when force is applied to it. One of the most significant rules of traditional physics is Newton's second law of motion.
The formula for Newton's law is as follows for a body of constant mass m:
F = ma,
Weight = 130N
Force = 37
Directed angle θ = 41°
N = 130 + F sinθ
N = 130 + (37) ( sin 41°)
N = 130 + 37 × -0.158
N = 130 + (-5.846)
N = 124.154
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(Need help! please and thank you!) :)
The choice that most accurately illustrates the system in the image is closed system.
option C.
What is a closed system?
A closed system is a physical system that does not exchange matter with its surroundings, but may exchange energy. In other words, the total amount of matter within the system remains constant, but energy may flow into or out of the system.
Closed systems are commonly used in physics and thermodynamics to study the behavior of isolated systems. Examples of closed systems include a sealed container with a fixed amount of gas, a planet with a fixed amount of mass, or a closed electrical circuit where energy can flow in and out, but no matter enters or leaves the system.
So the diagram illustrates a closed system since there is exchange of energy between the system and the surroundings.
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Think of 3 ways that an environment might change. Be specific and explain how
this change could impact plants, animals, or foodwebs
Answer:
don't know
Explanation:
Which of the following are true for Martin and his brother?
Answer:
All the statements above are true for martin and his brother in the book "My Brother Martin".
The late Dr. Martin Luther King Jr.'s older sister and renowned educator Christine King Farris collaborate with renowned illustrator Chris Soentpiet to tell this "outstanding" (School Library Journal) and motivational tale of how a boyhood event sparked a movement that would alter the course of history. In "My Brother Martin," Martin Luther King tells us what it was like to be a young kid of seven. Martin Luther King Jr. was a little boy who played jokes, practised the piano, and made friends without taking race into consideration long before he rose to fame as a global visionary.
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Convert 27 Fahrenheit to Celsius
Answer:
27 degrees Fahrenheit is -2.78°c
A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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you made $100,000 this year. you have $0 in adjustments, $11,500 in deductions and $7,300 in exemptions. What is your taxable increase?
The tax rate you will pay is displayed in tax brackets for each category of taxable income.
Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.
Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.
As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.
Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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A 7.30 kg sign hangs from two wires. The first wire is attached to the left end, and pulls 28.0 N directly left. What is the y-component of the force of the second wire?
Answer:
Approximately \(71.6\; {\rm N}\) (assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\).)
Explanation:
Refer to the diagram attached. Forces on this object are:
Tension on the left, from the wire on the left end.Tension on the right, from the wire on the other end.Weight, from the planet.Assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\), the magnitude of the weight of the sign would be:
\(\begin{aligned}(\text{weight}) &= m\, g \\ &= (7.30\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}) \\ &\approx 71.6\; {\rm N}\end{aligned}\).
Note that weight points downwards (negative) and is entirely in the vertical direction. As a result, the \(y\)-component of weight would be equal to \((-71.6)\; {\rm N}\).
Hence, the \(y\)-component of these forces would be:
\(0\; {\rm N}\) for the wire on the left end, since this tension is entirely horizontal (entirely in the \(x\)-direction,)\((-71.6)\; {\rm N}\) for the weight, which points downwards, andNot yet found for the tension from the other wire.Since forces on the object to be balanced, forces need to be balanced in each component. For forces in the \(y\)-component to be balanced, forces in the vertical direction need to add up to \(0\; {\rm N}\):
\(0\; {\rm N} + (-71.6)\; {\rm N} + (\text{$y$-component of tension on the right}) = 0\; {\rm N}\).
Hence, the \(y\)-component of the tension from the wire on the right end would be \(71.6\; {\rm N}\).
An increase in voltage results in
If the current is held constant, an increase in voltage will result in an increase in resistance.
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7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.
The tension in the strings are 31.47 and 19.25 N respectively.
Mass of the block, m = 3 kg
From the figure, consider the vertical components,
T₁ sin45° + T₂ sin30° = mg
(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4
Also, consider the horizontal components,
T₁ cos45° = T₂ cos30°
T₁/√2 = T₂ x√3/2
T₁ = T₂ x √3/2 x √2
So,
T₁ = 0.612T₂
Applying in the first equation,
(T₁/√2) + (T₂/2) = 29.4
(0.612T₂/1.414) + 0.5T₂ = 29.4
0.434 T₂ + 0.5 T₂ = 29.4
0.934 T₂ = 29.4
Therefore, the tension,
T₂ = 29.4/0.934
T₂ = 31.47 N
So, the tension,
T₁ = 0.612 T₂
T₁ = 0.612 x 31.47
T₁ = 19.25 N
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what is the force that every mass experts on every other mass called?
Answer: The forces of gravity
Explanation: The consequence of this phenomenon is that every mass exerts a so-called "force of mutual attraction" on every other mass. The attractive force that the celestial bodies exert on other masses by virtue of their total mass is called the force of gravity.
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A particle, whose acceleration is constant, is moving in the negative x direction at a speed of 4.38 m/s, and 13.3 s later the particle is moving in the positive x direction at a speed of 7.95 m/s.
Part A: What is the particle’s acceleration in m/s2?
Part B: What is the particle’s velocity, in m/s, 13.3 s before it was moving in the negative x direction at a speed of 4.38 m/s?
Part C: When is the particle at rest? Express this answer as a time in seconds elapsed since it was moving in the negative x direction at a speed of 4.38 m/s?
solve all parts please
The particle’s acceleration is 0.268 m/s².
The initial velocity of the particle before 13.3 seconds is 3.56 m/s.
The time when the particle is at rest is 32.68 seconds.
Acceleration of the particleThe acceleration of the particle is calculated as follows;
a = Δv/Δt
a = (7.95 m/s - 4.38 m/s) / 13.3 s
a = 0.268 m/s²
Initial velocity of the particle before 13.3 secondsu = at
u = 0.268 m/s² x 13.3 s
u = 3.56 m/s
Time when the particle is at rests = ut + ¹/₂at²
0 = -4.38t + ¹/₂(0.268)t²
0.134t² = 4.38t
0.134t = 4.38
t = 32.68 seconds
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Part A
Compute the x and y components of vector A.
Express your answers in meters to three siginificant figures. Enter your answers separated by
A comma
The component of vector A in the x direction will be -11.01 meters. and in the y direction will be 9.18 meters.
What is meant by vectors?A quantity or phenomenon with independent qualities for both magnitude and direction is called a vector. The term can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields, and weight are examples of vectors in nature.
What are examples of vectors?Vector quantities can also include things like movement, acceleration, force, momentum, weight, the speed of light, a gravitational field, current, and more.
component of vector A in x direction = A cos theta
= 12 cos(53)
= -11.01 meters
component of vector A in y direction = A sin theta
= 12 sin (53)
= 9.18 meters
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An environmentally conscious physics student 250 N
mows her lawn with a push mower, exerting
a force of 250 N along the handle as shown. 40°
How much force is actually being used to push
the mower along the grou
The force actually being used to push the mower along the ground is 191 N.
When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.
To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.
To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:
Horizontal component = Applied force * cos(angle)
Plugging in the values, we get:
Horizontal component = 250 N * cos(40°)
Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.
Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.
By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.
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