Poles are values of Laplace transform variable, s, that make denominator of transfer function zero. Zeros are values of Laplace transform variable, s, that make numerator of transfer function zero. The gain, K, is constant that multiplies entire numerator and denominator. MATLAB function, tf2zp, obtains transfer function zeros, poles, and gain given its numerator and denominator. For example, [z,p,K] = tf2zp(num,den) given a numerator, 4s2 + 165 + 12 and denominator s4 + 1253 +44s2 + 485, determine the zeros, poles, and gain of the transfer function using the tf2zp function. Poles and zeros should be ordered from largest to smallest to match the order given below. Larger number, meaning -2 > -4, NOT largest magnitude.zero(1) zero(2) pole(1) pole(2) pole(3) pole(4) gain

Answer:

a) the heat exchanger area required for the evaporator is 11178.236 m²

b) the required flow rate is 1993630.38 kg/s

Explanation:

Given the data in the question;

Water temperature near the surface = 300 K

temperature at reasonable depths ( cold ) = 280 K

power plant output W' = 2 MW

efficiency η = 3% = 0.03

we know that; efficiency η = W'\(_{power-out\) / Q\(_{supplied\)

we substitute

0.03 = 2 / Q\(_{supplied\)

Q\(_{supplied\) = 2 / 0.03

Q\(_{supplied\) = 66.667 MW = 66.667 × 10⁶ Watt

T\(h_{in\) = 300 K       T\(h_{out\) = 292 K

T\(c_{in\) = 290 K       T\(c_{out\) = 290 K    

Now, Heat transfer in evaporator;

Q = UA( LMTD )

so

LMTD = (ΔT₁ - ΔT₂) / ln( ΔT₁ / ΔT₂ )

first we get ΔT₁ and ΔT₂

ΔT₁ = T\(h_{in\) - T\(c_{out\)  = 300 - 290 = 10 K

ΔT₂ = T\(h_{out\) - T\(c_{in\)  = 292 - 290 = 2 K

so we substitute into our equation;

LMTD = (10 - 2) / ln( 10 / 2 )

LMTD = 8 / ln( 5 )

LMTD = 8 / 1.6094379

LMTD = 4.97

a) Heat transfer Area will be;

Q\(_H\) = UA( LMTD )

we substitute

66.667 × 10⁶ = 1200 × A × 4.97

66.667 × 10⁶  = 5964 × A

A = (66.667 × 10⁶) / 5964

A = 11178.236 m²

Therefore, the heat exchanger area required for the evaporator is 11178.236 m²

b) Flow rate  

we know that;

Q\(_H\) = m'C\(_P\)( \(T_{in\) - \(T_{out\) )  

specific heat capacity of water Cp = 4.18 (kJ/kg∙°C)

we substitute

66.667 × 10⁶ = m' × 4.18 × ( 300 - 292 )

66.667 × 10⁶ = m' × 33.44

m' = ( 66.667 × 10⁶ ) / 33.44

m' = 1993630.38 kg/s

Therefore, the required flow rate is 1993630.38 kg/s

Answer:

biodiversity, also called biological diversity, the variety of life found in a place on Earth or, often, the total variety of life on Earth. A common measure of this variety, called species richness, is the count of species in an area.

Explanation:

Given acceleration a = 5-3t, and its velocity is 7 at time t = 2, the value of s2 - s1 = 7

We have

= \(\frac{dv}{dt} =v't = 5-3t\\\\\int\limits^a_b {v'(t)} \, dt\)

\(= \int\limits^a_b {(5-3t)} \, dt\)

\(5t - \frac{3t^2}{2} +c\)

v2 = 5x2 -  3x2 + c

= 10-6+c

= 4+c

\(s(t) = \frac{5t^2}{2} -\frac{t^3}{2} +3t + c\)

S2 - S1

\(=(5*\frac{4}{2} -\frac{8}{2} +3*2*c)-(\frac{5}{2} *1^2-\frac{1^2}{2} +3*1*c)\)

= 6 + 6+c - 2+3+c

12+c-5+c = 0

7 = c

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Answer:

please mark me as BRAINLIEST

Explanation:

There are so many software packages available to develop HTML. The software packages can be grouped into two main categories: text-based (or code-based) editors.

...

WYSIWYG editors

Macromedia Dreamweaver.

Microsoft FrontPage.

Adobe GoLive.

Answer: A. yes

Explanation:

The National Fire Protection Association (NFIPA) 704 Diamond Label system helps firefighters and employees easily recognize the hazardous substances stored on the site is A) True.

The NFPA 704 Diamond Label is a standardized system used to identify the level of hazard posed by various substances. The label consists of a diamond-shaped sign with four sections, each color-coded to indicate the degree of hazard posed by the substance.

The system helps firefighters and other first responders quickly identify the potential risks posed by hazardous materials, which can help them make informed decisions and take appropriate safety measures.

Therefore, By providing clear and easily recognizable information about the hazards posed by various substances, the NFPA 704 Diamond Label system helps to promote safety and reduce the risk of accidents and incidents involving hazardous materials.

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The given statement is true about the fact that the Diamond Label system helps firefighters and employees easily recognize the hazardous substances stored on the site.

The Standard System for the Identification of the Hazards of Materials for Emergency Response is a safety standard that describes how hazardous materials are identified for emergency responders.

The National Fire Protection Association (NFIPA) 704 makes it simple for employees and firemen to identify the many types of hazardous materials housed on the property.

The National Fire Protection Association publishes it to complement the labeling system for emergency responders and to be useful to those operating under regular circumstances.

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Answer:

mark me as a brainleast

Explanation:

209781

Answer:

29.9

Explanation:

data

mass(m)= 0.1kg, c=3.32KJ/kg, final temperature= 95, initial temperature= 5

heat transferred Q= mc (T2-T1)

=0.1 ×3.32 ×(95-5)= 29.88

Q= 29.9KJ

NOTE; The x was use as multiplication sign

Answer: hydraulic retention time,τ=28.67 hours

Explanation:

The hydraulic retention time  τ (tau),  is given as  The volume of the settling tank(V) divided by the influent flowrate(Q)

τ =V/Q

But Volume is not known  and is given as

Volume =  surface area  x depth of the tank

= 8000 ft² X 12 ft

= 96,000 ft³

Also, the influent flow rate is in mgd ( million gallons per day), we change  it to  ft³/sec so as to be in same unit with the volume in ft³

1 million gallons/day = 1.5472286365101 cubic feet/second

0.6mgd =  1.5472286365101 cubic feet/second  x 0.6

=0.93cubic feet/second

τ =V/Q

96,000 ft³/0.93 ft³/sec

τ=103,225.8 secs

changing to hours

103,225.8 /3600 =28.67 hours

The hydraulic retention time =28.67 hours

To put out a class D metal fire, you must smother the fire and eliminate the oxygen element in the fire.

A class D fire is a type of fire that cannot be extinguished by water. This is because adding water to it reacts with other elements in the fire intensifying the fire even more.

Smothering in this context involves adding a solution like carbon dioxide (CO2) into the fire, this results in a reduction of oxygen in the atmosphere surrounding the class D fire.

By so doing, smothering the fire eliminates the oxygen element in the fire, thereby extinguishing the fire.

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Answer:  System Consists Of 1 Kg Of CO2 (Cp = 46.4 J Moll K:') Gas Initially At 1 Bar And 300K. The System Undergo

Explanation:

The magnitude of the force per unit cross-sectional area exerted by the inside wall of the pipe on the fluid between sections (1) and (2) is approximately 833.33 lbf/ft^2.

Since the flow is choked at section (2), the Mach number at this location is equal to 1. From the conservation equations for adiabatic, steady, one-dimensional flow, the static pressure at section (2) can be calculated as p0,2 = p0,1 * (2/(gamma + 1))^(-gamma/(gamma-1)) = 38.53 psia, where gamma is the ratio of specific heats.

Using the definition of the Mach number, the static temperature at section (2) can be calculated as T0,2 = T0,1 / (1 + (gamma-1)/2 * Ma1^2) = 365.44R. Assuming ideal gas behavior, the density of the fluid at section (2) can be calculated as rho2 = p0,2 / (R * T0,2) = 0.044 lbm/ft^3, where R is the gas constant.

From the conservation of momentum equation for one-dimensional flow, the force per unit cross-sectional area exerted by the inside wall of the pipe on the fluid between sections (1) and (2) can be calculated as F/A = (p0,1 - p0,2) / (gamma * R * T0,1) * A2 / A1 = 833.33 lbf/ft^2, where A2 / A1 is the area ratio of sections (2) and (1), respectively.

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Answer:

what are the options available?

Answer:

the clothing you wear, what's in the air (gases), surrounding and weather

Carrier fitting is used to be a support system to complete secret in the wall and supports the load of the fixture by means of a suitable feature plate and base support firmly tie up to the floor.

Carrier means the term used to create a pipe, which carries a liquid or gas from its source to its destination and is laid underground, it is also used to support system. The drain in the conveyance pipe will discharge groundwater into the pipe or contaminate the environment with the product flowing in the pipe. The advantage of this is that it offers options to meet installation codes and demands while allowing flexibility to design a functional and compact plumbing drainage system.

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Due to variation in environmental and geological factors, two soil samples from 50 kilometers are expected to have different mineral composition.

1. Two soil samples separated by 50 kilometers are expected to have different mineral compositions and particle size distributions due to variations in geological and environmental factors. Soil is formed through the weathering and breakdown of rocks, which can differ in composition and characteristics depending on the type of rock and geological history of the area. Environmental factors such as climate, topography, and vegetation can also affect soil formation and characteristics. Therefore, the soil samples in two different areas can have different mineral compositions and particle size distributions depending on the local geology and environment.

2. The three physical properties that can be utilized to visually identify different types of rocks are color, texture, and grain size. Color can indicate the presence of certain minerals in the rock, which can help identify the type of rock. Texture refers to the size and arrangement of mineral grains in the rock, which can vary depending on the type of rock and how it was formed. Grain size can also help identify the type of rock, as different rock types have characteristic grain sizes that can be observed with the ordinary eye or under a microscope. Other physical properties that can be used to identify rocks include hardness, density, and porosity.

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Answer:

\(D=0.41m\)

Explanation:

From the question we are told that:

Discharge rate \(V_r=0.35 m3/s\)

Distance \(d=4km\)

Elevation of the pumping station \(h_p= 140 m\)

Elevation of the Exit point \(h_e= 150 m\)

Generally the Steady Flow Energy Equation SFEE is mathematically given by

\(h_p=h_e+h\)

With

\(P_1-P_2\)

And

\(V_1=V-2\)

Therefore

\(h=140-150\)

\(h=10\)

Generally h is give as

\(h=\frac{0.5LV^2}{2gD}\)

\(h=\frac{8Q^2fL}{\pi^2 gD^5}\)

Therefore

\(10=\frac{8Q^2fL}{\pi^2 gD^5}\)

\(D=^5\frac{8*(0.35)^2*0.003*4000}{3.142^2*9.81*10}\)

\(D=0.41m\)

Answer:

2)

a)  to the right of the dipole    E_total = kq [1 / (r + a)² - 1 / r²]

b)To the left of the dipole      E_total = - k q [1 / r² - 1 / (r + a)²]

c) at a point between the dipole, that is -a <x <a  

      E_total = kq [1 / x² + 1 / (2a-x)²]

d) on the vertical line at the midpoint of the dipole (x = 0)

E_toal = 2 kq 1 / (a ​​+ y)² cos θ

Explanation:

2) they ask us for the electric field in different positions between the dipole and a point of interest. Using the principle of superposition.

This principle states that we can analyze the field created by each charge separately and add its value and this will be the field at that point

Let's analyze each point separately.

The test charge is a positive charge and in the reference frame it is at the midpoint between the two charges.

a) to the right of the dipole

The electric charge creates an outgoing field, to the right, but as it is further away the field is of less intensity

           E₊ = k q / (r + a)²

where 2a is the distance between the charges of the dipole and the field is to the right

the negative charge creates an incoming field of magnitude

           E₋ = -k q / r²

The field is to the left

therefore the total field is the sum of these two fields

           E_total = E₊ + E₋

           E_total = kq [1 / (r + a)² - 1 / r²]

we can see that the field to the right of the dipole is incoming and of magnitude more similar to the field of the negative charge as the distance increases.

b) To the left of the dipole

The result is similar to the previous one by the opposite sign, since the closest charge is the positive one

E₊ is to the left and E₋ is to the right

          E_total = - k q [1 / r² - 1 / (r + a)²]

We see that this field is also directed to the left

c) at a point between the dipole, that is -a <x <a

In this case the E₊ field points to the right and the E₋ field points to the right

                      E₊ = k q 1 / x²

                      E₋ = k q 1 / (2a-x)²

                      E_total = kq [1 / x² + 1 / (2a-x)²]

in this case the field points to the right

d) on the vertical line at the midpoint of the dipole (x = 0)

    In this case the E₊ field points in the direction of the positive charge and the test charge

    in E₋ field the ni is between the test charge and the negative charge,

the resultant of a horizontal field in zirconium on the x axis (where the negative charge is)

                      E₊ = kq 1 / (a ​​+ y) 2

                      E₋ = kp 1 / (a ​​+ y) 2

                      E_total = E₊ₓ + E_{-x}

                      E_toal = 2 kq 1 / (a ​​+ y)² cos θ

e) same as the previous part, but on the negative side

                        E_toal = 2 kq 1 / (a ​​+ y)² cos θ

When analyzing the previous answer there is no point where the field is zero

The different configurations are outlined in the attached

3) We are asked to repeat part 2 changing the negative charge for a positive one, so in this case the two charges are positive

a) to the right

in this case the two field goes to the right

           E_total = kq [1 / (r + a)² + 1 / r²]

b) to the left

            E_total = - kq [1 / (r + a)² + 1 / r²]

c) between the two charges

E₊ goes to the right

E₋ goes to the left

            E_total = kq [1 / x² - 1 / (2a-x)²]

d) between vertical line at x = 0

E₊ salient between test charge and positive charge

           E_total = 2 kq 1 / (a ​​+ y)² sin θ

In this configuration at the point between the two charges the field is zero

Answer:

When a force is exerted on an object it can change the object's speed, direction of movement or shape. Pressure is a measure of how much force is acting upon an area. Pressure can be found using the equation pressure = force / area. Therefore, a force acting over a smaller area will create more pressure

Explanation:

hope it will become helpful to you ☺️☺️

Answer:

u need to plan it out

Explanation:

u need to plan it out

Answer:

use the turn 1 degrees option and put a repeat loop on it

Explanation:

u can add sound in ur loop

Answer:

a

Explanation:

Answer:

Executive Summary

Explanation:

It is Executive Summary because I used process of elimination. Constraints are set backs. Project objectives are the goals that you want to achieve. Project development cycle are basically the steps that will be used.

Answer:

Thermal energy is measured using a thermometer denominated in Fahrenheit, Celsius and Kelvin

Answer:

I think A is correct

The two technicians are right in their given assessment about the use of collapsible steering columns and collapsible brake pedals to reduce the risk of trapping the driver's feet.

This refers to the vehicular movement from one point to another, obeying traffic rules, and respect for other drivers and pedestrians.

Hence, we can see that with regards to safe driving, the opinions of both Technicians A and B are both correct as they both want the safety of the car and the driver.

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You can read about it here https://www.cornellcollege.edu/information-technology/policies/technology-policies/limitations-of-laptops.shtml