Prepare the operating activities section of the statement of cash flows for peach computer using the indirect method. (list cash outflows and any decrease in cash as negative amounts.)

Answer:

a y=3/2× Pls help me do me one

a

Answer:

y=1/2x+5

Step-by-step explanation:

What we have so far is y=1/2x+?

We need to find the y-intercept. Using the info we have right now we can find the y-intercept with this.

y=mx+b

(1/2)=(1/2)(-9)+b

0.5 =-4.5+b

5=b

y=1/2x+5

The answer to the question is that the numbers 6 and 8 are positive even sequential integers.

Consecutive numbers are those that follow one another continually, from lowest to largest. For instance, the numbers 1, 2, 3, 4, 5, and so on are all consecutive.

The answer provided below has been developed in a clear step by step manner. Let the the two positive even consecutive integers be 2n and (2n+2) According to the question the one less than the square of the smaller integer is given as

\(2n^2-1\)

\(4n^2-1\)

Here the positive consecutive integers are 2n and 2n+2 because for any value of n if it is multiplied by 2 then it becomes positive and further on adding 2 it remains even.

Now the three more than the four times the the larger number is given as

4(2n+2)+3

8n+8+3

8n+11

\(4n^2-1\) = 4(2n+2)+3

\(4n^2-1\) = 8n+8+3

\(4n^2-1\) = 8n+11 +1

\(4n^2-8n-12\) = 0

\(n^2-2n-3\) = 0

Now solving the given quadratic equation to get the positive value of n

Please refer to solution in this step.

Therefore the value of n is given as

n = +2 ± \(\sqrt{4-((4 )(1)-(3))}\)/2

2 ±\(\sqrt{16/2}\)

1 ±2

the positive smaller integer is

2n= 2(1+2)

2n=6

and the positive greater integer is

2n+2 = 8

Hence the positive even consecutive integers are 6 and 8 .

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It is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

In the given scenario, it is not completely true that based only on the r and p values listed above, you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

Let's first understand what is meant by the term "moderator.

"Moderator: A moderator variable is a variable that changes the strength of a connection between two variables. If there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents, scientists investigate whether this bivariate relationship is moderated by age.

Therefore, based on the values of r and p, it is difficult to determine if age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

As we have to analyze other factors also to determine whether the age is a moderator or not, such as the sample size, the effect size, and other aspects to draw a meaningful conclusion.

So, it is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.

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The length of the sides of the rhombus JKLM is 12 units.

A rhombus is one of parallelograms. The opposite sides of a rhombus are parallel, and the opposite angles are equal. Furthermore, all of the sides of a rhombus are the same length, and the diagonals intersect at right angles.

In the problem, the sides of rhombus JKLM are:

JK = 2x + 4

JM = 3x

Since the length all of the sides of a rhombus are the same, then:

JM = JK

3x = 2x + 4

Substract both sides by 2x:

3x - 2x = 2x + 4 - 2x

x = 4

To find the length of a side, substitute x = 4 into:

JM = 3x

JM = 3(4) = 12

Hence, the length of the sides of the given rhombus is 12.

The picture in your question is missing. Most likely it was like on the attached picture.

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Answer:

12

Step-by-step explanation:

JK = JM

2x + 4 = 3x

x = 4

JK = JM = 3 x 4 = 12

The largest area of the rectangle is 6502.5 square feet.

Given that,

Using fence parallel to one of the rectangle's sides, a cattle rancher wants to surround a rectangular area and divide it into four pens (see the figure below). To finish the task, 510 feet of fencing are available.

We have to find what could the four pens' combined total area be.

We know that,

The rectangular shape's length is l and its width is b.

Total fencing= 2l + 5b=510 feet

2l +5b =510 feet

We can write as,

l=1/2(510-5b)

Total area of the rectangle is length into breath

A(b) = l × b

A(b) = 1/2(510-5b)×b

A(b)= 1/2(510b -5b²)

For maximum area

A'(b)=0

1/2(510b -5(2b))=0

b=51

We get l as

l = 1/2(510-5b)

l = 1/2(510-5(51))

l = 127.5

Total area of the rectangle is 127.5 × 51

Total area of the rectangle is 6502.5 square feet.

Therefore, The largest area of the rectangle is 6502.5 square feet.

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The Surface area of a cuboid with length 10 cm breadth 10 cm and height 9 cm is 560 cm².

Here, length of cuboid is 10 cm

         breadth of cuboid is 10 cm

         and height of cuboid is 9 cm

Surface Area of Cuboid = 2 (lb + bh + lh)

                                         = 2 (10X10 + 10X9 + 10X9)

                                        = 2 (100 + 90 + 90)

                                        = 2 X 280

Surface Area of Cuboid = 560 cm²

Thus, the Surface area of a cuboid with length 10 cm breadth 10 cm and height 9 cm is 560 cm².

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The minimum value of the function using Legrange equations is m = -2

Given data:

To find the minimum value of the function f(x, y, z) = x² - 4x + y² - 6y + z² - 2z + 5, subject to the constraint x + y + z = 3, we can use Lagrange multipliers.

Let's define the Lagrangian function L as:

L(x, y, z, λ) = f(x, y, z) - λ(g(x, y, z))

where g(x, y, z) represents the constraint equation x + y + z = 3.

So, we have:

L(x, y, z, λ) = x² - 4x + y² - 6y + z² - 2z + 5 - λ(x + y + z - 3)

To find the minimum, we need to find the critical points of L by taking the partial derivatives with respect to x, y, z, and λ, and setting them equal to zero:

∂L/∂x = 2x - 4 - λ = 0 (1)

∂L/∂y = 2y - 6 - λ = 0 (2)

∂L/∂z = 2z - 2 - λ = 0 (3)

∂L/∂λ = x + y + z - 3 = 0 (4)

From equation (1), we have:

2x - 4 - λ = 0

2x = λ + 4

x = (λ + 4)/2

From equation (2), we have:

2y - 6 - λ = 0

2y = λ + 6

y = (λ + 6)/2

From equation (3), we have:

2z - 2 - λ = 0

2z = λ + 2

z = (λ + 2)/2

Substituting these values into equation (4), we have:

(λ + 4)/2 + (λ + 6)/2 + (λ + 2)/2 - 3 = 0

λ + 4 + λ + 6 + λ + 2 - 6 = 0

3λ + 6 = 0

λ = -2

Now, substituting λ = -2 back into the equations for x, y, and z:

x = (-2 + 4)/2 = 1

y = (-2 + 6)/2 = 2

z = (-2 + 2)/2 = 0

So, we have found the critical point (x, y, z) = (1, 2, 0) which satisfies the constraint equation x + y + z = 3.

Therefore, we conclude that the critical point (1, 2, 0) gives a minimum value for the function f(x, y, z) subject to the constraint x + y + z = 3.

Hence, the minimum value of the function is f(1, 2, 0) = (1)² - 4(1) + (2)² - 6(2) + (0)² - 2(0) + 5 = -2.

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Answer:

Step-by-step explanation:

The given trigonometric expression is :

11 cos^2 x +3 sin^2 x+6sinx cosx +5

or, we can write it as,

(9 cos^2 x + 2 cos^2 x) + (2 sin^2 x + sin^2 x) + 6sinx cosx +5

Again, after rearranging the terms, we can write the whole expression as,

(9 cos^2 x + sin^2 x + 6sinx cosx) + (2 cos^2 x + 2 sin^2 x) + 5

Then if you factor the following underlined section as you would with a polynomial:

(9 cos^2 x + sin^2 x + 6sinx cosx) + (2 cos^2 x + 2 sin^2 x) + 5

You get:

(3 cos x + sin x)^2 + 2 (cos^2 x + sin ^2 x) + 5

Now, the term inside the second bracket (cos^2 x + sin ^2 x) is a very popular trigonometric identity and it's value is equal to one.

So, now the whole expression becomes,

(3 cos x + sin x)^2 +7

Now, the maximum and the minimum value of the whole expression depends upon the maximum and the minimum value of the term (3 cos x + sin x), which is of the form (a cosx + b sinx),

The maximum and minimum value of (a cosx + b sinx) is relatively easy to find.

So, I've attached a screenshot from a relevant document below:

Here, a=3 and b=1,

So, R= √10

As the value of cosine of any angle lies between -1 to 1, so the value of the value of expression cos(x − α) will lie between -1 to 1.

Hence, the maximum and the minimum value of (a cosx + b sinx) will be -R and R and all the values of the expression will lie between them.

i.e., in our case between (-√10) to √10.

Again, coming back to our original expression,

(3 cos x + sin x)^2 +7

The value of the term in bracket will lie between (-√10) and √10.

But, there is a catch here, as the squares of negative terms come out be positive, hence we can't take the negative term to find the minimum value of our expression. the minimum value of the expression will be at the minimum non-negative value in the range, which is zero.

So, the minimum value will be,

(0)^2 + 7=7

and the maximum value will be,

(√10)^2 +7 = 17

Answer:

12

Step-by-step explanation:

24/2=12

Answer:

hear is ur answer....

Step-by-step explanation:

Observation market research is a technique which involves directly observing consumers or another target audience in their natural environment - for instance, watching how shoppers stop outside a fashion retailer, what they are drawn to in a window display and which direction they go after entering the store.

Step-by-step explanation:

we have to simplify it as much a possible.

that means we divide top and bottom by the same whole number, until we cannot find any other number except for 1, where there is no remainder for these divisions.

so, usually if we don't see the solution right away, we go along the prime numbers starting with 2 :

can we divide 48 and 54 by 2 without remainder ?

yes, and the result is then

24/27

can we divide 24 and 27 by 2 without remainder ?

no. going to the next prime number : 3

can we divide 24 and 27 by 3 without remainder ?

yes, and the result is

8/9

can we divide 8 and 9 by 3 without remainder ?

no. and there is no other prime number I can divide both numbers with.

so, 8/9 is the lowest or simplest form.

In a right triangle, the measure of acute angles is represented by x and 2x -15 then the value of x is equal to 35.

As given in the question,

In a right triangle,

One of the angle is of measure 90°.

Other two angles are acute angles.

Measure of two acute angles are given as x and 2x -15.

Sum of the three angles in a triangle is 180°.

x + 2x -15 + 90° = 180°

⇒3x +75° = 180°

⇒ 3x = 105°

⇒ x = 35°

Therefore, in a right triangle, the measure of acute angles is represented by x and 2x -15 then the value of x is equal to 35.

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Answer:

I believe the answer is D.)13 movies per month.

Step-by-step explanation:

Answer:

D. 13 movies per month.

Step-by-step explanation:

Answer:

261

I hope this helps!

Answer:

answer

volume= 252 yd^3 .

The width of Fiona's TV will be 15 inches.

The Pythagoras theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides.

Given that;

Fiona’s TV screen is 20 inches long.

And, The diagonal measures 25 inches.

Now,

Since, Fiona’s TV screen is 20 inches long.

And, The diagonal measures 25 inches.

Let the width of the Fiona's TV = x

So, By definition of Pythagoras theorem we get;

⇒ 25² = 20² + x²

Solve for x as;

⇒ 625 = 400 + x²

⇒ x² = 625 - 400

⇒ x² = 225

⇒ x = √225

⇒ x = 15 inches

Thus, The width of Fiona's TV = 15 inches

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The right triangle, like the other triangles, has three sides, three vertices, and three angles. The difference between the other triangles and the right triangle is that the right triangle has a 90  angle.

To find missing angles and sides and round to the nearest tenth, you can use different methods depending on the given information and the type of triangle or shape involved.

Some common methods include:
Trigonometric ratios (sine, cosine, tangent) for right triangles.
Angle sum property or exterior angle property for triangles.
Pythagorean theorem for right triangles.
Law of cosines and law of sines for non-right triangles.
To help find the missing angles and sides of a triangle, you need certain information about the triangle, such as known angle and side measurements, or information about the properties of the triangle.

Without this information, no concrete calculations can be made.

Provide the necessary information or describe the problem in more detail and we will help you find the missing corners and sides of the triangle and round it to tenths.

Remember to always check if any additional information is given, such as side lengths or angles ' 7 and to apply the appropriate formula or property to find the missing value.

Round your answer to the nearest tenth as specified.

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Vectors that appear to be equal is OB, m, o', p and qin, r, and s.

Let's discuss it further below.

In this question, vectors m through t are given in the figure. There are eight vectors: m, n, o, o', p, q, r, and s. The question asks to identify the groups of vectors that appear to be equal.

From the given figure, we can see that m and o' are parallel to each other and are of the same length. Thus, they are equal to each other. Also, vectors p and q are parallel to each other and are of the same length. So, they are equal to each other. Thus, we can conclude that m, o', p, and q are equal to each other.

Then, vectors n and r are parallel to each other and are of the same length. Thus, they are equal to each other. Also, vectors r and s are parallel to each other and are of the same length. So, they are equal to each other. Thus, we can conclude that n and r and s and r are equal to each other.

Therefore, the groups of vectors that appear to be equal are OB, m, o', p and qin, r, and s.

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Answer:

A

Step-by-step explanation:

it's gain because 10,500 is bigger than 10,000

Answer:

62 sq in is the area of the mat

Step-by-step explanation:

the area of the mat = total area added minus the original area of the water color painting.

length of the mat is:L = 20 in + 1 in + 1 in because 1 in  is added to each sideL = 22 inwidth of the mat is:w = 9 in + 1 in + 1inw = 11 in

Area mat = (22 in x 11 in) - ( 20 in x 9 in)

area mat = 62 sq in is the area of the mat

Branily?:)

Answer:

x = 5 and y = 7

Step-by-step explanation:

Given that,

PT = x+2, TR=y, QT=2x, TS=y+3

We need to find the value of x and y.

The diagonal of a parallelogram bisect each other. It means,

PT = TR and QT = TS

ATQ,

y = x+2 ...(1)

and

y+3 = 2x ....(2)

Subtracting equation (1) and (2).

y-(y+3) = x+2-2x

y-y-3 = 2-x

-3 = 2-x

x = 2+3

x = 5

Put the value of x in equation (1).

y = 5 + 2

y = 7

Hence, the values of x and y are x = 5 and y = 7.

Answer:

^ they are correct

Step-by-step explanation:

The expression which are equals to 6⁻¹⁰ are as follow,

option A. (1 /6² )⁵ , Option b. 6⁻³ / 6⁷ , Option ( 6⁻⁵ )².

The expression is equal to,

6⁻¹⁰

Simplify all the given options to find the equivalent expression to 6⁻¹⁰.

(1 /6² )⁵

Apply law of exponent here,

= ( 1 / 6¹⁰)

= 6⁻¹⁰

Option A. is correct answer.

6⁻³ / 6⁷

Apply law of exponent we get,

= 6⁻³⁻⁷

= 6⁻¹⁰

Option B. is correct answer.

( 6⁵ × 6⁻³ )/ 6⁻⁸

= 6⁵⁻³⁺⁸

= 6¹⁰

It is not the correct answer.

( 6⁻⁵ )²

Apply law of exponent here

= 6⁻¹⁰

Option D. is the correct answer.

6⁻⁵ × 6²

= 6⁻³

It is not correct option.

Therefore, the expression equivalent to the given expression are option A. (1 /6² )⁵ , Option b. 6⁻³ / 6⁷ , Option ( 6⁻⁵ )².

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Step-by-step explanation:

y³ + 5y

2³ + 5 × 2

8 + 10

18...

Hi!

\(\diamondsuit\) Plug in 2 for y:

\(\boldsymbol{2^3+5(2)}\)

\(\diamondsuit\) Cube 2 first:

\(\boldsymbol{8+5(2)}\)

\(\diamondsuit\)  Multiply 5 times 2 next:

\(\boldsymbol{8+10}\)

\(\diamondsuit\) Add.

\(\boldsymbol{18}\)

Therefore,

\(\stackrel{\heartsuit}{\boxed{\boxed{\boldsymbol{Answer:~~18}}}}\)

I hope I helped, have an amazing rest of your day!

If you need any explanation or clarification - comment! :)

Answer:

See below

Step-by-step explanation:

Jim

10 m starting point and speed is 15 m/min:

Chris

30 m starting point and speed is 10 m/min

The given system of linear equations consists of four equations with four variables: x, y, z, and w. To solve the system, we can use various methods, such as Gaussian elimination or matrix operations.

By performing row operations, we can reduce the system to its row-echelon form or solve it directly to find the values of x, y, z, and w. We will solve the system of linear equations using the method of Gaussian elimination. The augmented matrix representation of the system is:

[1 1 2 -1 | -2]

[0 3 1 2 | 2]

[1 1 0 3 | 2]

[-3 0 1 2 | 5]

First, we'll perform row operations to transform the matrix into the row-echelon form:

R2 = R2 - 3R1

R3 = R3 - R1

R4 = R4 + 3R1

The resulting matrix after these operations is:

[1 1 2 -1 | -2]

[0 0 -5 5 | 8]

[0 0 -2 4 | 4]

[0 3 1 2 | 5]

Next, we'll perform additional row operations to further simplify the matrix:

R4 = R4 - 3R2

The matrix now becomes:

[1 1 2 -1 | -2]

[0 0 -5 5 | 8]

[0 0 -2 4 | 4]

[0 3 1 2 | -19]

Finally, we'll perform the last row operation:

R3 = R3 + 2R2

The matrix is now in row-echelon form:

[1 1 2 -1 | -2]

[0 0 -5 5 | 8]

[0 0 0 14 | 20]

[0 3 1 2 | -19]

From this row-echelon form, we can solve for the variables. Starting from the bottom row, we obtain:

3w + z + 2w = -19, which simplifies to 5w + z = -19.

Next, we have 0x + 0y - 5z + 5w = 8, which simplifies to -5z + 5w = 8.

Lastly, x + y + 2z - w = -2.

At this point, we have three equations with three variables: x, y, and z. By solving this simplified system, we can find the values of x, y, and z.

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Regarding the graphs of the functions \(h(x) = x^2 - 4\) and \(g(x) = (x - 4)^2,\) the following statements are true:

The vertex of the graph of h(x) is located at (0, -4), while the vertex of the graph of g(x) is located at (4, 0).

The vertex represents the minimum or maximum point of the parabola.

The graph of h(x) opens upwards, indicating a positive coefficient for the \(x^2\)  term, while the graph of g(x) also opens upwards due to the positive coefficient of the squared term \((x - 4)^2.\)

The graph of h(x) intersects the x-axis at x = -2 and x = 2, indicating the solutions to the equation \(x^2 - 4 = 0.\)

On the other hand, the graph of g(x) intersects the x-axis at x = 4, representing the solution to the equation \((x - 4)^2 = 0.\)

It's important to note that the graph of h(x) is a standard quadratic function, while the graph of g(x) is a quadratic function with a horizontal shift of 4 units to the right.

The differences in their vertex, x-intercepts, and shape indicate these variations between the two functions.

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