Q1. A man wants to install a surveillance mirror in his shop, which mirror should he use?(1)

a) Convex mirror

b) Concave mirror

c) Plane mirror

d) Both (a) and (b)​

The lithosphere is the solid layer of Earth, the hydrosphere is the water-based part, and the atmosphere is the air, they work together to shape the biosphere.

The lithosphere is the soil part that composes the Earth's planet (i.e., the soil), the hydrosphere refers to oceans and all water bodies, while the atmosphere is the layer of air. These three layers interact with biotic factors to shape the biosphere.

In conclusion, the lithosphere is the solid layer of Earth, the hydrosphere is the water-based part, and the atmosphere is the air, they work together to shape the biosphere.

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Since the rope is parallel to the table, the tension in the rope is also equal to the force acting on the cart.  The acceleration of the cart will be obtained as 1.32 m/s².

Since the rope is parallel to the table, the forces acting on the system are the tension in the rope (T) and the weight of the hanging block (m1g). Since the rope is parallel to the table, the tension in the rope is also equal to the force acting on the cart.

The acceleration of the system can be found using Newton's second law:

ΣF = ma

where ΣF is the net force on the system, m is the total mass of the system, and a is the acceleration of the system.

The net force on the system is given by:

ΣF = T - m₁g

Substituting the given values, we get:

ΣF = T - m₁g = ma

To solve for the acceleration, we need to find the tension in the rope (T). We can do this by considering the torque on the pulley. The torque on the pulley is equal to the product of the force and the radius of the pulley (τ = Fr). The torque due to the weight of the hanging block is equal to m1g * r, and the torque due to the tension in the rope is equal to T * r. Since the pulley is not accelerating, the net torque on the pulley must be zero:

Στ = m₁g * r - T * r = I * α

where I is the moment of inertia of the pulley and α is the angular acceleration of the pulley. Since the pulley is not slipping, the linear acceleration of the cart is equal to the angular acceleration of the pulley divided by the radius of the pulley (a = α * r).

Substituting for α and a, we get:

m₁g * r - T * r = I * a / r

Solving for T, we get:

T = (m₁g + I * a / r)

Substituting this expression for T into the equation ΣF = T - m₁g, we get:

ma = (m₁g + I * a / r) - m₁g

Simplifying, we get:

a = g * m₁ / (m₂ + I / r²)

Substituting the given values, we get:

a = (9.81 m/s²) * 2.0 kg / (4.0 kg + 0.4 kg-m² / (0.2 m)²) = 1.32 m/s²

Therefore, the acceleration of the cart is 1.32 m/s².

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Answer:

decreases, decreases

Explanation:

Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.

In a mixed economy, economic decisions are made by both the government and consumers.

The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.

In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.

The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.

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Answer:

In econ: When supply and Demand are equal

Explanation:

Equilibrium is when something evens out

Answer:

The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it. ... This is called Ohm's law.

Explanation:

I Looked It Up. So It May Be Wrong But I Hope This Helps!

Answer:

The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it. ... This is called Ohm's law.

Answer:

Hello your question lacks some information and that is the distance

At r = 0.150 m (outside the cable)  note :  (μ 0 = 4π × 10-7 T · m/A)

answer: 4.7 * 10^-6 T

Explanation:

R1 = 0.03 m

R2 = 0.07 m

R3 = 0.1 m

Inner conductor carries current = 4.5A in one direction

outer conductor carries current = 8A in opposite direction

Determine the value of magnetic field at r = 0.150 m

net current = 8 - 4.5 = 3.5 A

∴ β ( value of  magnetic field )

= ( 4π * 10^-7 * 3.5 ) / ( 2π * 0.150 )

= 4.4*10^-6 / 0.94

= 4.7 * 10^-6 T

The luminosity of this star in units of the solar luminosity would be: 483.7L.

To calculate the luminosity, we would use the different values given and the formula for luminosity.

Temperature = 9305K

Star's radius = \(5.90 * 10^{9} m\\\)

Luminoisty of the star

Luminosity of the sun

= \(\frac{4π * (5.90 * 10^9)^2 * 5.67 * 10^-8 * 9305^4 W}{3.846 * 10^26 W}\)

= 483.7L

This is the unit for luminosity.

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If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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Answer:

B

Explanation:

bc all the other answers seem way to simple and boring

When a block is launched with initial speed 2.2 m/s up a 35° frictionless ramp then ramp slides up to 0.43m.

The work-energy theorem explains that net work done by the forces on an object is equal to change in its kinetic energy.

We can also say that work done on a body is equal to the net change in its energy.

Given angle = 35°

initial speed = 2.2m/s

Applying work - energy theorem,

Wgravity = KE

-m *g *sin ∅ * S =1/2* (0- 2.2²)

-9.81*sin 35° *S= 1/2 *(0- 2.2² )

S= 0.43m

Ramp slides up to 0.43m.

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The effort distance of a lever should be increased to lift a heavier load because it provides a mechanical advantage, allowing for easier lifting of the load.

The effort distance of a lever should be increased to lift a heavier load because it allows for a mechanical advantage that compensates for the increased weight.

In a lever system, the effort distance is the distance between the point of application of the input force (effort) and the fulcrum, while the load distance is the distance between the point of application of the output force (load) and the fulcrum. The mechanical advantage of a lever is determined by the ratio of the load distance to the effort distance.

By increasing the effort distance, the mechanical advantage of the lever system is increased. This means that for the same input force (effort), a greater output force (load) can be achieved. When dealing with a heavier load, a higher mechanical advantage is required to overcome the increased resistance.

By increasing the effort distance, the lever system can effectively multiply the applied force, making it easier to lift the heavier load. This allows for the redistribution of force and facilitates the efficient use of human effort in various applications, such as in construction, engineering, and even everyday tools like scissors and pliers.

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Answer:

6.7 seconds

Explanation:

d=(1/2)at^2

equation

1000=(1/2)45t^2.

substitute

2000=45t^2.

multiply by 2 for both sides

44.44=t^2.

divide both sides by 45

6.7=t

take the square root of both sides

Answer:

750m/s

Explanation:

v = fλ = (1500 Hz)(0.5 m) = 750m/s

Answer:

0.5 m and 1500 Hz divided by 750 m/s equals 750 m/s.

Explanation:

Brainliest pls!

A procedure known as magnetic separation can be used to extract magnetic elements from coal.

This method makes use of the magnetic characteristics of some materials to distinguish them from non-magnetic materials like coal. A description of how magnetic separation can be used to remove magnetic components from coal is given below:

Putting a magnetic field around the coal and magnetic material mixture is the first step in the magnetization process. This can be achieved by creating an electromagnetic field or by putting the mixture close to a powerful magnet.

Magnetism: Magnetic materials, such as iron atoms or magnetite that are frequently found in coal, will be drawn to the magnetic field and become magnetized. They line up their magnetic moments with the magnetic field's direction.

Separation: The magnetic coal components can be physically separated from the non-magnetic coal once they have been magnetized. To create this separation, there are numerous techniques:

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90.1 g of ice are still present in the container. Calculating the heat received by the ice to melt and the heat lost by the tea is necessary until it reaches an equilibrium temperature of 33.1 ◦C .

Consider how much energy is required to melt one kilogramme of ice at zero degrees to produce one kilogramme of water at zero degrees. The energy required to melt one kilogramme of ice is determined by Q = mLf = (1.0 kg)(334 kJ/kg) = 334 kJ using the equation for a change in temperature.

In order to calculate how much heat is gained by the ice melting, we must first calculate how much heat is lost by the tea as it cools from 33.1 °C to 0.0 °C.

Tea loses the following amount of heat: q1 = m1CT1 = 0.185 kg) (4186 J/kg C) (33.1 C - 0.0 C) = 26298.93 J.

Heat required for ice to melt is given by the formula: q2 = m2Hf = (0.0903 kg)(333.55 kJ/kg) = 30062.56 J

We may set q1 = q2 to get the mass of ice still present because the system is in thermal equilibrium:

m2 = q2/Hf = 333.55 kJ/kg / 30062.56 J = 0.0901 kg

Finally, we round the mass to two significant digits and convert it to grammes:

m2 = 90.1 g

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Answer:

I have strawberry blonde/brown hair blue eyes and a girl lol

Explanation:

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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Stochastic impacts of radiation allude to those that happen arbitrarily and are not reliant upon the portion got. These impacts are related to the likelihood of events and incorporate disease and hereditary changes. Non-stochastic impacts, then again, have a limit, and their seriousness increments with expanding portions.

Models incorporate radiation consumption and intense radiation conditions. Understanding the qualification among stochastic and non-stochastic impacts of radiation is significant in fields like radiation security, atomic medication, and radiobiology.

It assists in setting radiation with dosing limits, creating well-being rules, and carrying out suitable radiation safeguarding measures. By separating these impacts, experts can evaluate and deal with the dangers related to openness to ionizing radiation all the more successfully.

This information guides choices in regard to radiation wellbeing conventions, word-related openness limits, and the improvement of radiation therapy systems in medication.

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46)

Since air resistance is ignored, both cannonballs will fall with the same acceleration due to gravity, which is approximately 9.8 m/s^2. The horizontal velocity of cannonball A does not affect its vertical motion, so it will fall at the same rate as cannonball B.

The time it takes for an object to fall to the ground from a certain height is given by the formula t = sqrt(2h/g), where t is the time, h is the initial height, and g is the acceleration due to gravity.

For cannonball B, which is dropped from a height of 20 meters, the time it takes to reach the ground is:

t = sqrt(2h/g) = sqrt(2*20/9.8) = 2.02 seconds

For cannonball A, which is fired horizontally with a velocity of 5 m/s, the time it takes to reach the ground is also 2.02 seconds, since the vertical motion is the same as cannonball B.

Therefore, both cannonballs will hit the ground at the same time.

47)

The recoil speed of the cannon can be calculated using the principle of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.

Before firing, the total momentum of the system is zero, since the cannon and cannonball A are at rest. After firing, the cannonball A has a momentum of 5 kg * 5 m/s = 25 kg m/s to the right, so the cannon must have an equal and opposite momentum to the left in order to conserve momentum.

The mass of the cannon is 500 kg, so its momentum after firing will be:

p = -25 kg m/s

The velocity of the cannon can be found using the equation:

p = mv

where p is the momentum, m is the mass, and v is the velocity. Solving for v, we get:

v = p/m = (-25 kg m/s) / (500 kg) = -0.05 m/s

Since the momentum of the cannon is negative, the recoil velocity is also negative, indicating that the cannon will move to the left after firing. The magnitude of the recoil velocity is 0.05 m/s, or approximately 0.18 km/h.

Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.

Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.

Hope this helped!

Answer:g

Explanation:

you have to times the two numbers

Answer:

J. 6.7 g/cm³

Explanation:

Density = Mass/Volume

D = 14.7g/2.2cm³ ≈ 6.7 g/cm³

Answer:  a stretch of 2

Explanation: because it 2 (x) - 3

Answer:

Explanation:

A. in

Point of the wave where the medium is the most compressed.

Option e is correct.

When moving through a medium, mechanical longitudinal waves are also known as compressional or compression waves because they generate compression and rarefaction. They are also known as pressure waves because they create pressure changes.

Areas of compression and rarefaction can be seen in longitudinal waves. Because the particles are packed closely together, compressions are areas of tremendous pressure. Because the particles are scattered farther apart, rarefactions are areas of low pressure.

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Answer:

A

Explanation:

We will increase the amplitude of the wave by a factor of 4 If we want to double this rate

Transverse wave, travels in a way in which points on a wave oscillate along paths at right angles of 90 degrees to the direction of the wave.

We see that energy transported along a wave path is directly proportional to the square of the amplitude.

E =kA^2

Therefore, we will increase the amplitude of the wave by a factor of 4 If we want to double this rate.

Option B

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Answer:

Graph C

Explanation:

This is the answer because it is the only one that shows the vehicle accelerate to a constant speed before stopping and slowing down.