Question 2:heat (5 points) a. Describe the following heat equations and identify the indicated variables. (3 points) I. Q= mct; identify c. (1 point) ii. Q=ml vapor; identify l vapor (1 point) iii. Q= ml fusion; identify l fusion (1 point)

The force applied to the 10 kg computer was 50 Newtons.

An electrical device with the capability to accept, store, process, and output data is known as a computer.

The following formula can be used to determine the force exerted on a 10 kilogram computer that is accelerating at a rate of 5 m/s2:

Force = mass x acceleration

Where

Plugging in these values, we get:

Force = 10 kg x 5 m/s²

Force = 50 N

Therefore, the force applied to the 10 kg computer was 50 Newtons.

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Phenol red indicator changes from yellow to red in the pH range from 6.6 to 8.0.

In a 0.20 M KOH(aq) solution, KOH dissociates to form hydroxide ions (OH⁻) in water.

The hydroxide ions can react with water to produce hydroxide ions and hydroxide ions can increase the concentration of hydroxide ions in the solution, resulting in a basic pH.

Since KOH is a strong base, it completely dissociates in water, leading to a high concentration of hydroxide ions. The presence of a high concentration of hydroxide ions indicates a basic solution.

Based on the given pH range for phenol red, which changes from yellow to red between pH 6.6 and 8.0, we can infer that in a 0.20 M KOH(aq) solution, the indicator will assume a RED color.

Therefore, the correct answer is A) red.

Answer:

Method: Measure out 25 cm3 of 0.5 mol dm3 lead(II)nitrate solution and add it to a small beaker. Measure out 25 cm3 of 0.5 mol dm3 of potassium sulfate add it to the beaker and mix together using a stirring rod.

Answer:

sulphuric acid

Explanation:

Answer:

single covalent bond

Explanation:

The bond formed between two atoms each sharing one electron is called single covalent bond

The figure 1 is the structure of diamond. The type of bond in diamond is covalent sp³ bond. DIamond exists in hexagonal arrangement of carbon atoms.

Allotropes are substances formed from a single elements with different number in various size and shape. Carbon exhibit catenation property which means it can forms chains with other carbon in any large number.

The allotropes of carbon are diamond, graphene and fullerene. Diamond is hexagonal arrangement of carbons atom bonded covalently in sp³ hybridisation.

In graphene as shown in the second figure, bonded carbons atoms are arranged as layers where carbon is in sp²hybridisation. In the case of fullerenes, there are both hexagonal and pentagonal rings adjacent to each and are formed by 60-70 carbons.

In all these allotropes, the bond type between two carbons atoms is covalent. Covalent bond is formed by sharing of electrons between the two atoms.

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Answer:

The amount of water

The amount of sugar and

The amount of yeast

Explanation:

A constant variable is that variable in an experiment which must be kept the same for all groups in order not to alter the results of the experiment.

In this question, the independent variable i.e. the variable being manipulated is the TYPE OF SUGAR USED while the dependent variable i.e. variable that responds to change is AMOUNT OF ENERGY. Three different types of sugar were used viz: maltose, glucose, and sucrose. To not alter the outcome of the experiment, the constants of this experiment i.e. variables that must be the same for all groups of the experiment, include the following:

- The amount of water

- The amount of sugar

- The amount of yeast used

Answer: ahem...

Explanation: 1. True 2. reproducing 3. All of them 4. i would say true, the only thing is plants dont really digest food and it says "all" organisms... 5. B, C, and D...A is more of defense and not really "maintaining structure"

The balanced reaction equations are given below. They are all examples of double displacement.

a) balanced reaction equation of the reaction between aqueous copper(II) nitrate and aqueous potassium hydroxide, resulting in the formation of solid copper(II) hydroxide and aqueous potassium nitrate

\(Cu(NO_{3} )_{2}(aq)+2KOH(aq)\) → \(Cu(OH)_{2} (s) + 2KNO_{3}(aq)\)

b) balanced reaction equation of the double displacement between gaseous boron cyanide and liquid water resulting in the formation of solid boric acid and gaseous hydrogen cyanide

\(2B(CN)_{3} (g) + 6H_{2} O\) → \(2H_{3} BO_{3} (s)+6HCN(g)\)

c) balanced reaction equation between solid calcium silicate and gaseous hydrogen fluoride resulting in the formation of gaseous silicon fluoride, solid calcium fluoride and liquid water

\(CaSiO_{3}(s) + 6HF (g)\) → \(SiF_{4}(g)+CaF_{2}(s)+3H_{2}O(l)\)

d) balanced reaction equation between cyanogen gas and liquid water resulting in formation of aqueous oxalic acid and gaseous ammonia

\((CN)_{2}(g) + 4H_{2} O (l)\) → \(H_{2} C_{2} O_{4} (aq) +2NH_{3} (g)\)

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Answer:

I think B is the answer so hope

Answer:

It's C

Explanation:

The synthesis of nylon requires solutions of 5% hexamethylenediamine and 5% adipoyl chloride. This polymer will form between layers of the solutions. To remove the nylon, one can choose to dissolve it in the 5% hexamethylenediamine or in the 5% adipoyl chloride.

Nylon, a synthetic polymer, is produced from the combination of adipoyl chloride and hexamethylenediamine. This process is called the synthesis of nylon. Nylon is a highly flexible material that is resistant to wear and tear, as well as chemical and heat degradation. The synthesis of nylon requires solutions of 5% hexamethylenediamine and 5% adipoyl chloride, respectively, for the two reactants to be mixed together.

The reaction between these two chemicals is exothermic, which means that it releases heat. The heat generated in the reaction drives the reaction forward, resulting in the formation of nylon. The chemical formula for nylon is (-CO-NH-)n, where n is a large number that reflects the degree of polymerization. To remove the nylon, it is soaked in an acid solution. The acid dissolves the nylon, separating it into its constituent components, which can then be purified and reused.

The most commonly used acid for this process is hydrochloric acid. The process of removing nylon from its solvent is called the "acid-catalyzed hydrolysis of nylon." Nylon is used in a variety of applications, including textiles, packaging materials, and electrical components, among others. Its properties make it ideal for use in applications that require durability, strength, and flexibility. Nylon's physical properties, including its resistance to heat and chemical degradation, make it ideal for use in applications such as electrical insulation, packaging materials, and textiles.

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Answer:

it destroy the surrounding area

Answer: the atomic size will decrease

Explanation:

Answer:

It will remain the same because it is moving up and down to and fro it can not increase nor decrease or else will become an ion

Answer:

Quantum numbers of the outermost electron in potassium:

Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the \(4s\) orbital (fourth \(s\) orbital.)

The quantum number \(n\) (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, \(n = 4\) for this electron.

The quantum number \(l\) (the angular momentum quantum number) specifies the shape (\(s\), \(p\), \(d\), etc.) of an electron. \(l = 1\) for \(s\!\) orbitals (such as the one that contains this electron.

Quantum numbers \(n\) and \(l\) specify the shape of an orbital. On the other hand, the magnetic quantum number \(m_l\) specifies the orientation of these orbitals in space.

However, \(s\) orbitals are spherical. Regardless of the value of \(n\), the only possible \(m_l\) value for electrons in \(s\!\) orbitals is \(m_l = 0\).

The spin quantum number \(m_s\) distinguishes between the two electrons in an orbital. The two possible values of \(m_s \!\) are \((+1/2)\) and \((-1/2)\). Typically, the first electron in an orbital is assigned an upward (\(\uparrow\)) spin, which corresponds to \(m_s = (+1/2)\).

Exergonic: Reactions with negative delta G°’ values are exergonic reactions that release free energy.Exergonic means that the reaction will occur spontaneously. The value of delta G°’ is less than zero.

Endergonic: When the delta G°’ value is positive, the reaction is endergonic. These are reactions that need to be powered by an external force to occur.

At equilibrium: When delta G°’ = 0, the reaction is at equilibrium. The forward and reverse reactions occur at the same rate, and the concentrations of reactants and products do not change. Thus, the reaction is at equilibrium.

Here is how the K’eq values should be matched with the appropriate delta G°’ values:

K'eq  a. 1 : 0kJ/mol  b. 10⁻⁵ : 22.84 kJ/mol c. 10⁴ : -28.53 kJ/mol  d. 10² : -5.69 kJ/mol  e. 10⁻¹ : 11.42 kJ/mol AG°' (kJ/mol)

Therefore, the correct match for K’eq values with the appropriate delta G°’ values are as follows:

K'eq = 10⁴ corresponds to delta G°’ = -28.53 kJ/mol, which is exergonic.

K'eq = 10⁻⁵ corresponds to delta G°’ = 22.84 kJ/mol, which is endergonic.

K'eq = 10² corresponds to delta G°’ = -5.69 kJ/mol, which is exergonic.

K'eq = 1 corresponds to delta G°’ = 0 kJ/mol, which is at equilibrium.

K'eq = 10⁻¹ corresponds to delta G°’ = 11.42 kJ/mol, which is endergonic.

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The ph of the solution at the equivalence point is 5.3. Option D is correct.

Acid-base titrations are an important analytical technique used to determine the concentration of an acid or base in a solution. In a typical acid-base titration, a solution of known concentration, called the titrant, is slowly added to a solution of unknown concentration, called the analyte, until the reaction between the two is complete.

In some cases, the pH at the equivalence point may be different from 7, depending on the strength of the acid and base being used in the titration. For example, if a weak acid is being titrated with a strong base, the equivalence point will be greater than pH 7. Conversely, if a strong acid is being titrated with a weak base, the equivalence point will be less than pH 7.

However, if the question is asking for the pH at the endpoint of the titration, rather than the equivalence point, the pH will depend on the specific indicator being used in the titration. At the endpoint, the solution will be slightly basic if a strong base is used, and the pH will be greater than 7. The exact pH at the endpoint will depend on the amount of excess base present in the solution and the specific indicator used in the titration. Option D is correct.

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Answer is D & C

Explanation:

It is not just C or D you need to select TWO options.

Speed and direction, Displacement and time can be used to determine the velocity of an object.

Velocity is the rate of change in the position of the object with respect to time, it is basically speeding the object in a specific direction.

Velocity is a  vector quantity, which shows both magnitude  and direction  where The SI unit is meter per second (ms-1).

the change in  magnitude or the direction of velocity of a body, can lead to acceleration.

The final velocity can be calculated as the simple but few calculations and basic conceptual knowledge are needed.

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If the final temperature of the water is 28.1 °c, then the identity of metal is Ag.

What is Ag metal?

With the atomic number 47 and the symbol Ag (from the Latin argentum, which is derived from the Proto-Indo-European h2er: "bright" or "white"), silver is a chemical element. It is the highest electrical, thermal, and reflectivity of all metals, and it is a soft, white, lustrous transition metal.

The Latin argentum and Sanskrit argunas, both meaning "bright," are where the word "Ag" originates. Even in the Stone Age, silver was used. Silver use dates back at least 5000 years, according to archeological findings.

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Answer:

Respiration

Explanation:

The act of breathing, simple as that!

Hope this helped!!

The molar solubility of yttrium fluoride (YF3) is 3.46 × 10-6 M.

The ksp of yttrium fluoride is 8.62 × 10-21. The molar solubility of this compound can be determined using the following formula:Ksp = [Y3+][F-]3We can set the molar solubility of yttrium fluoride as 'x'.

This is because the solubility of the yttrium fluoride will lead to the concentration of yttrium ions and fluoride ions. The Ksp expression for yttrium fluoride can be represented as follows:

Ksp = (x)(3x)3 = 27x4

where '3x' is the molar solubility of F-.

We can substitute Ksp value in the above expression and then solve for x:

8.62 × 10-21 = 27x4x = 3.46 × 10-6 M

Thus, the molar solubility of yttrium fluoride is 3.46 × 10-6 M.

To conclude, the molar solubility of yttrium fluoride (YF3) is 3.46 × 10-6 M.

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Answer:

2. chlorine

3. Copper??

4. Isotope

5. sodium, magnesium, aluminum, silicon, phosphorus, sulfur, or argon

6. Oganesson

7. Hydrogen

Hope these are right!

Answer:

91.12 gram

Explanation:

Number of moles of Ammonia = 5.36

Molecular Mass of Ammonia = 14 + 3 × 1 = 17 gram/mol

Mass = Number of moles × Molecular mass

Mass = 5.36 mol × 17 gram/mol = 91.12 gram

Answer:

V = 0.0496 L

Explanation:

Given that,

The mass of a sample, m = 352.2 g

The density pf sample, d = 7.10 g/mL

We need to find the volume of the sample. We know that the density of an object is given by :

\(d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{352.2}{7.1}\\\\V=49.6\ mL\)

or

V = 0.0496 L

So, the volume of the sample is 0.0496 L.

Answer:

January 9th 1915

Explanation:

Answer:

In 1913 he used self-built equipment to prove that every element's identity is uniquely determined by the number of protons it has. His discovery revealed the true basis of the periodic table and enabled Moseley to predict confidently the existence of four new chemical elements, all of which were found.

Answer:

We'd all freaking freeze to death and be standing there like the black beetles trend.

Explanation:

This is a joke, please don't take this seriously.

46.12 grams of water are produced when 35 grams of \(C_6H_1_0\) react with 45 grams of \(O_2\).

The balanced equation for the combustion of C6H10 (cyclohexene) with O2 is:

\(C_6H_{10} + O_2 - > CO_2 + H_2O\)

From the balanced equation, we can see that 1 mole of  \(C_6H_1_0\) reacts with 6 moles of O2 to produce 6 moles of water.

First, let's calculate the number of moles of C6H10 and O2:

Molar mass of C6H10 = 6(12.01 g/mol) + 10(1.01 g/mol) = 82.16 g/mol

Number of moles of C6H10 = mass / molar mass = 35 g / 82.16 g/mol ≈ 0.426 mol

Molar mass of O2 = 2(16.00 g/mol) = 32.00 g/mol

Number of moles of O2 = mass / molar mass = 45 g / 32.00 g/mol ≈ 1.406 mol

From the stoichiometry of the balanced equation, we can determine that 0.426 moles of C6H10 will produce 0.426 * 6 = 2.556 moles of water.

Now, let's calculate the mass of water produced:

Molar mass of H2O = 2(1.01 g/mol) + 16.00 g/mol = 18.02 g/mol

Mass of water = number of moles of water * molar mass of water

                        = 2.556 mol * 18.02 g/mol

                        ≈ 46.12 g

Therefore, approximately 46.12 grams of water are produced when 35 grams of C6H10 reacts with 45 grams of O2.

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(alt + F4) might be the answer you are looking

Explanation:

I'm not exactly sure how I came up with this answer but it is for sure the answer

Answer:

17.78 gm

Explanation:

2 H20 mole weight = 36 gm

   which leads to 32 gm   O2

36 / 32   =  20 / x      x = 17.78 gm

The pH of the solution is 2.55 and the concentrations of C₂H₅COOH and C₂H₅COO⁻ are 0.594 M and 0.00282 M respectively.

The following chemical equation describes how propanoic acid, a weak acid, will ionise in water.

C₂H₅COOH(aq) + H₂O(l) ↔ C₂H₅COO⁻(aq) + H₃O⁺(aq)

The concentration of the initial solution of propanoic acid is 0.597 M.

The Ka of propanoic acid is 1.34 × 10⁻⁵.

Let the concentration of each of the products is x.

Now, We have Ka = [C₂H₅COO⁻] [H₃O⁺] / [C₂H₅COOH] [H₂O]

or, 1.34 × 10⁻⁵ = x × x / 0.597

or, x² = 0.8 × 10⁻⁵

or, x = 2.82 × 10⁻³ M

or, x = 0.00282 M

So, concentration of C₂H₅COO⁻ = x = 0.00282 M

Concentration of C₂H₅COOH = 0.597 - 0.00282 = 0.594 M

Now, pH of solution = -log[H₃O⁺] = -log[x] = -log(0.00282) = 2.55

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