Question 4 of 11
A student is making an electrical cord. Which sentence explains how she
should build the cord?
O A. Place metal around the plastic, because electric charges move
easily in metal.
O B. Place metal around the plastic, because electric charges hardly
move in metal
C. Place plastic around the metal wires, because electric charges
hardly move in plastic.
D. Place plastic around the metal wires, because electric charges
move easily in plastic.
SUBNE

Answers

Answer 1

Answer: C

C. Place plastic around the metal wires, because electric charges

hardly move in plastic.

Answer 2

Answer:

C is the correct answer

Explanation:


Related Questions

Why is there an upper limit to the mass that can be supported by electron degeneracy pressure?

Answers

Electron degeneracy pressure is a specific manifestation of the more general occurrence of quantum degeneracy pressure.

What is mass electron degeneracy pressure?

Electron degeneracy pressure will halt the gravitational slump of a star if its mass is below the Chandrasekhar limit (1.44 solar masses). This is the pressure that averts a white dwarf star from collapsing. Electron degeneracy pressure occurs when electrons are squeezed into a very small volume. Since their positions are well-known, they gain a large momentum in obedience to Heisenberg's uncertainty principle. This momentum generates a pressure that is temperature-independent and can result in helium flash. in stars. Electron degeneracy occurs at a solidity of about 106 kg/m3.

So we can conclude that  The electron degeneracy pressure is taken by (n.v.p) where n is the number density, and v is the mean speed of the degenerate electrons.

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The tension in a ligament in the human knee is approximately proportional to the extension of the ligament, if the extension is not too large.If a particular ligament has an effective spring constant of 150 N/mm as it is stretched, what is the elastic energy stored in the ligament when stretched by 0.780 cm?

Answers

Given that the spring constant of the ligament is

\(\begin{gathered} K=150\text{ N/mm} \\ =\frac{150N}{10^{-3}\text{ m}} \\ =150\times10^3\text{ N/m} \end{gathered}\)

The displacement of the ligament is

\(\begin{gathered} x=0.78\text{ cm} \\ =0.78\times10^{-2}\text{ }m \end{gathered}\)

We have to find elastic energy.

Elastic energy is given by the formula

\(U=\frac{1}{2}kx^2\)

Substituting the values, the elastic energy will be

\(\begin{gathered} U=\frac{1}{2}\times(150\times10^3)\text{ }\times(0.78\times10^{-2})^2 \\ =\text{ 5.85 J} \end{gathered}\)

Thus, the elastic energy of the ligament is 5.85 J.

Clark Grizwald put a neon green blinking tree that weights 2.3 kg on top of his house 50 meters off the ground but he didn't tie it down right. How much velocity does the blinking tree have when it is 2 meters from the ground? Solve

Answers

The magnitude of the velocity the blinking tree has when it is 2 meters from the ground is 21.8 m/s.

Conservation of energy

To calculate the velocity of the blinking tree when it is 2 meters from the ground, we can use the principles of conservation of energy.

First, let's determine the potential energy of the tree when it is 50 meters off the ground. The potential energy (PE) can be calculated using the formula:

PE = mgh

Where:

m = mass of the tree (2.3 kg)

g = acceleration due to gravity (9.8 m/s^2)

h = height (50 m)

PE = 2.3 x 9.8 x 50

PE = 1131 J

Next, we can calculate the potential energy of the tree when it is 2 meters from the ground:

PE = mgh

Thus:

PE = 2.3 x 9.8 x 2

PE = 45.04 J

According to the conservation of energy principle:

PE(initial) = PE(final) + KE(final)

1131 J = 45.04 J + KE(final)

Now, let's solve for the kinetic energy (KE) at the final position:

KE(final) = PE(initial) - PE(final)

KE(final) = 1131 J - 45.04 J

KE(final) = 1085.96 J

KE = (1/2)mv^2

1085.96 J = (1/2) x 2.3 kg x v^2

Thus

v^2 = (2 x 1085.96 J) / 2.3 kg

v^2 = 474.76 m^2/s^2

v ≈ 21.8 m/s

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a car traveling at 28.4 m/s undergoes a constant deceleration of 1.92 m/s2 when the breaks are applied. How many revolutions does each tire make before the car comes to a stop

Answers

Complete Question

a car traveling at 28.4 m/s undergoes a constant deceleration of 1.92 m/s2 when the breaks are applied. How many revolutions does each tire make before the car comes to a stop? Assume that the car does not skid and that each tire has a radius of 0.307 m. Answer in units of rev.

Answer:

The value is  \(N = 109 \ rev\)      

Explanation:

From the question we are told that

    The speed of the car is  \(u = 28.4 \ m/s\)

     The constant deceleration experienced is  \(a = 1.92 \ m/s^2\)

      The radius of the tire is  \(r = 0.307 \ m\)

     

Generally from kinematic equation we have that

      \(v^2 = u^2 + 2as\)

Here  v is the final velocity which is  0 m/s

   So

         \(0^2 = 28.4^2 + 2 * 1.92 * s\)

=>      \(s = 210.04 \ m\)

Generally the circumference of the tire is mathematically represented as

         \(C = 2 \pi r\)

=>      \(C = 2 * 3.142 * 0.307\)    

=>      \(C = 1.929 \ m\)

Generally the number of revolution is mathematically represented as

         \(N = \frac{ s}{C}\)    

=>     \(N = \frac{210.04}{1.929}\)

=>     \(N = 109 \ rev\)      

In the diagram, R₁ = 40.0 , R2= 25.4 , and R3 = 70.8 . What is the equivalent resistance of the group? ​

In the diagram, R = 40.0 , R2= 25.4 , and R3 = 70.8 . What is the equivalent resistance of the group?

Answers

According to the diagram the equivalent resistance of the group is

40.05 ohms

How to find the equivalent resistance

The equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1

Resistors in parallel is solved by

Resistors in parallel = 1/25.4 + 1/70.8

Resistors in parallel = 0.0535 ohms

Equivalent resistance

Equivalent resistance = Resistors in parallel + Resistor in series

Equivalent resistance = 0.0535 + 40

Equivalent resistance = 40.0535

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To increase the potential energy of the system, what did you have to do?

Answers

Answer:

You can use work to add kinetic energy to a system or to increase potential energy in the system.

Explanation:

Potential energy stored in any system can be released as kinetic energy. Kinetic energy can be transformed to do work or to increase potential energy.

hope this helped

When a falling meteoroid is at a distance above the Earth's surface of 3.50 times the Earth's radius, what is its acceleration due to the Earth's gravitation?

Answers

Answer:

0.484 m/s²

Explanation:

To solve this question, we would apply the formula for calculating gravitational acceleration at any distance.

g = GM/r², where

g = acceleration due to gravity

G = gravitational constant

r = radius of the meteoroid

Radius of the earth is given as 6371 km

The meteoroid is located at a distance 3.5 times the radius of the earth, so

r = R + 3.5R = 4.5R

r = 28670 km

Mass of the earth is, 5.97*10^24 kg

Now, we proceed to substitute our values into the earlier equation

g = GM/r²

g = (6.67*10^-11 * 5.97*10^24) / 28670²

g = 398.2*10^12 / 822*10^12

g = 0.484 m/s²

Thus, it's acceleration due to earth's gravitation is 0.484 m/s²

What exercises can help reduce stress?

Answers

Running,Swimming,Cycling,Dancing

which of the following describes the net force on an object?

A. The sum of all forces acting on an object
B. The Gravitational force minus any contact forces on an object.
C. The difference between the normal force and the Gravitational force acting on an object.
D. the sum of all forces acting on an object in the same direction. ​

Answers

The statement that describes the net force on an object is the sum of all forces acting on an object (option A).

What is net force?

Net force is sum of all forces acting on an object in a single plane.

When a force is applied to a body, not only is the applied force acting, there are many other forces like gravitational force, frictional force and the normal force that balances the other force.

The sum of all these forces acting on the object whether in the same or opposite direction is regarded as the net force.

Therefore, the statement that describes the net force on an object is the sum of all forces acting on an object.

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HELP QUICK! Please can anyone do the other half for me

HELP QUICK! Please can anyone do the other half for me

Answers

Answer:

9) c

10) c

11) d

12) d

Explanation:

I think it's helps you

In outer space, a constant force is applied to a 33.2 kg probe initially at rest. The probe moves a distance of 101 m in 15 s. What acceleration does this force produce? What is the magnitude of the force?

Answers

Answer:

a

=

F

M

a

=

137

30.8

x

=

1

2

a

t

2

x

=

1

2

137

30.8

13

2

x

=

375.86

Explanation: Hope this helps ;)


If a seagull drops a shell from rest at a height of 16 m , how fast is the shell moving when it hits the rock

Answers

Answer:

We know:

V1 = 0m/s

a = 9.8m/s

D = 16m

So we can solve for V2 with a kinematic equation.

V2^2 = 2a*D

V2^2 = 2(9.8)(16)

V2^2 = 313.6

V2 = 17.7m/s

Explanation:

If a seagull drops a shell from rest at a height of 16 m, the shell would have been moving with a velocity of when it hits the rock

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

The expression for total mechanical energy is as follows

ME= PE+KE

As for the given problem, If a seagull drops a shell from rest at a height of 16 m , as the seagull drops from that height the potential energy stored is converted into kinetic energy,

height = 16 m

1/2mv²= mgh

v = √(2gh)

m is the mass of the object

v is the velocity of the object

by substituting the respective values

v = √(2×9.81×16)

v =17.71 meter/ seconds

Thus ,shell would have been moving with a velocity of 17.71 meters/ seconds when it hit the rock.

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As shown, the two charges are 3 cm apart. What will happen to this force if the distance between the charges is doubled? Use proportional reasoning to find the answer and then check by moving the charges.​

As shown, the two charges are 3 cm apart. What will happen to this force if the distance between the

Answers

Answer:

if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value. If the charges come 10 times closer, the size of the force increases by a factor of 100. The size of the force is proportional to the value of each charge.

When charges are 3 centimeters apart if the distance between the charges is doubled, the force between them is reduced by a factor of four.

What is Coulomb's Law?

Coulomb's law can be stated as the product of the charges and the square of the distance between them determine the force of attraction or repulsion acting in a straight line between two electric charges.

F= k Q₁Q₂/r²

Where F is the force between two charges

As given in the problem, the two charges are 3 centimeters apart, then we have to find out what will happen to this force if the distance between the charges is doubled.

As per Coulomb's law, the force is inversely proportional to the square of the distance between charges.

Thus, the force between them is reduced by a factor of four.

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Remember: Weight (newtons) = mass* gravity and 1 kg = 2.2 pounds. 14. A typical NFL lineman weighs around 314 pounds. Calculate the weight in Newtons.​

Answers

1,401.88 N is the required weight of the man using the given conversion factor.

Determining the weight of an object

To calculate the weight of a typical NFL lineman in Newtons, we need to first convert the weight from pounds to kilograms using the conversion factor of 1 kg = 2.2 pounds:

314 pounds ÷ 2.2 pounds/kg = 142.73 kg

Next, we can use the formula Weight (newtons) = mass * gravity, where gravity is approximately 9.81 m/s^2 (meters per second squared):

Weight (newtons) = 142.73 kg * 9.81 m/s^2 = 1,401.88 N

The required weight in Newton of the man is 1,401.88 N

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Help plz!:( it’s for physics but it has like math !!
(SHOW ALL WORK)

1) A 30-kg object is accelerated at a rate of 3m/s2. how much force does the object have?

2)A ball is thrown w/ a force of 50N and travels 4m. how much work is done to the ball?

3) Joey pushes on a door that is stuck with 400 N of force but is unable to move it. How much work has he done?

4) A toy car does 300j of work in 15 sec. how much power did the car use?

5)A 60w light bulb burns for 2 min. how much work was done?

6) how much power is used if it takes Frank (a 450 N boy) 3 sec to run 2 meters?

Answers

Answer:

1. 90N

2. 200N

3. 400N

4.20w

5.7200N

Explanation:

1.F=ma

30 * 3 = 90

2.W=FD

50 * 4=200

4. P=W/t

300/15=20

5.W= Pt. 2minutes = 120sec

60*120 = 7200

A vertical spring stretches 3.4 cm when a 12-g object is hung from it. The object is replaced with a block of mass 26 g that oscillates up and down in simple harmonic motion. Calculate the period of motion.

Answers

Answer:

Period of motion is approximately 0.5447  seconds

Explanation:

We start by calculating the constant "k" of the spring which can be derived from the fact that an object of mass 12 g produced a stretch of 3.4 cm: (we write everything in SI units)

F = k * x

0.012 kg * 9.8  m/s^2 = k 0.034 m

k = 0.012 kg * 9.8  m/s^2 / (0.034 m)

k = 3.46 N/m

now we use the formula for the period (T) of a spring of constant k with a hanging mass 'm':

\(T=2\pi\,\sqrt{\frac{m}{k} }\)

which in our case becomes:

\(T=2\pi\,\sqrt{\frac{0.026}{3.46} } \approx 0.5447\,\,sec\)

An electric heater uses 0,5 MJ when connected to a 220 V supply for 30 minutes. Calculate the power rating of the heater and the current drawn from the supply.

Answers

The power rating of the heater is 277.8 W and the current drawn from the supply is 0.07015mA.

The power is obtained from the ratio of work and time and the power is measured in watts(W). The current is defined as the flow of electrons in the circuit and it is measured in ampere(A).

From the given,

The energy of the electric heater = 0.5MJ = 0.5×10⁶ J

Voltage (V) = 220 V

time (t) = 30 minutes = 30×60 s = 1800 s.

To find power (P):

Power = Energy / Time

          = 0.5×10⁶ / 1800

          = 277.77 W

Power of the electric heater = 277.8 W

To find current from the given:

Power (P) = V×I×t

Current (I) = P/(V×t)

                = 277.8 / (220×1800)

               = 0.7015 mA

The current drawn from the supply is 0.7015 mA.

Hence, the power rating of the heater is 277.8 W and the current drawn from the supply is 0.7015 mA.

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A rubber balloon is filled with normal air and sealed, and the gas inside is
heated with an electrical coil. A) What happens to the particles inside the balloon
when the gas inside is heated? B) How does this affect the force the particles
strike the balloon wall? C) Use the kinetic theory to predict the effect of heating
the gas inside a balloon on the volume (size) of the balloon.

Answers

Answer:

wait, wont the balloon pop if there is gas inside?

Explanation:

a 25-cm-long glass stirring rod at a laboratory temeprature of 20 c is placed in an autoclave and heated to 150 c. by about how much does the rod expand

Answers

In order to reach a chambers temperature of a minimum of 250°F (121°C) for just a set amount of time—typically 30–60 minutes—autoclaves employ saturation steam with a pressure of around 15 square inches per square.

What kind of heat is in an autoclave?

To eliminate any potential microbiological life on a contaminated load, autoclaves use steam heat. Once a cargo, also known as goods, has gone through a complete sterilising cycle, it is deemed sterile.

Why would a lab need an autoclave?

An autoclave is used to sterilise surgical instruments, lab equipment, pharmaceutical products, and other things. It has the capacity to sterilise devices of all shapes and sizes as well as hollow items, liquids, solids, and solids. The dimensions, architecture, and operation of autoclaves vary.

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An astronaut measure the period of a mass spring system on Earth. How would the period be affected if the astronaut measured the period of the same mass spring system on the moon? (Moon's gravity = 1/6 Earth's gravity.)

Answers

An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?

Answers

Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

2. When things happen the force is said to be ————.

Answers

The answer is what is Starwars

1. Lifting an elevator 18m takes 100kJ. If doing so takes 20s, what is the average power of the elevator during the process?

2. How much work can a 0.4 hp electric mixer do in 15 s?​

Answers

Answer:

1. Power = 5000 Watts

2. Workdone = 11185.5 Joules

Explanation:

Given the following data;

1. Distance = 18 m

Energy = 100 KJ = 100,000 Joules

Time = 20 seconds

To find the average power of the elevator;

Power = energy/time

Power = 100000/20

Power = 5000 Watts

2. Power = 0.4 HP

Time = 15 seconds

Conversion:

1 horsepower = 745.7 Watts

0.4 horsepower = 0.4 * 745.7 = 298.28 Watts

To find the amount of work done by the electric mixer;

Work done = power * time

Workdone = 745.7 * 15

Workdone = 11185.5 Joules

In an experiment, a 0.028-kilogram rubber stopper is attached to one end of a string. A student whirls the stopper overhead in a horizontal circle with a radius of 1.0 meter. The stopper completes 10 revolutions in 10 seconds.

22. Determine the speed of the whirling stopper.

23. Calculate the magnitude of the centripetal force on the whirling stopper. [Show all work, including the equation and substitution with units.]

Answers

Hi there!

22.

We can calculate the speed by first calculating the period of the stopper.

1 period = time taken for one revolution

10 rev/10 sec = 1 rev/sec

Since it takes 1 second for the stopper to make a complete circle, its velocity can be found using the equation for circumference:

\(v = \frac{2\pi r}{t} = \frac{2\pi (1)}{1} = \boxed{2\pi \approx 6.28 m/s}\)

23.

The centripetal force can be solved for using the following:

\(F_c = \frac{mv^2}{r}\)

m = mass (kg)

v = velocity (m/s)

r = radius (m)

Fc = Centripetal force (N)

Plug in the givens:

\(F_c = \frac{0.028(2\pi)^2}{1} = \boxed{1.105 N}\)

calculate the quantity of heat absorbed by 14 g
of water that warms from 30 ∘C
to 98 ∘C

Answers

The quantity of heat absorbed by 14 g of water that warms from 30 ∘C to 98 ∘C is approximately 4087.84 J.

What is heat absorbed?

Heat absorbed refers to the amount of thermal energy that is taken in by a substance or system during a process, such as heating up or melting.

The amount of heat absorbed by a substance is given by the equation:

Q = m * c * ΔT

Where:

Q = amount of heat absorbed or releasedm = mass of the substancec = specific heat capacity of the substanceΔT = change in temperature of the substance

For water, the specific heat capacity is approximately 4.18 J/g°C.

Using the given values, we can calculate the amount of heat absorbed by the water as follows:

m = 14 g

c = 4.18 J/g°C

ΔT = (98°C - 30°C) = 68°C

Q = 14 g * 4.18 J/g°C * 68°C = 4087.84 J

Therefore, the quantity of heat absorbed by 14 g of water that warms from 30 ∘C to 98 ∘C is approximately 4087.84 J.

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Approximately how long will it take light to travel to 1.7 AU in minutes? Use 3 × 108 m/s for the speed of light. unanswered

Answers

Answer:

14.1mins

Explanation:

We know that

Time =Distance/Speed

So

= 1.7 au/ (3 E8 m /s )

= 1.7 x 1.496 x 10^11 m /(3 x 10^8 m /s

Converting Au to meters (1.7 x 1.496 x 10^11 m)

= 847.7 s

=14.1 mins

Answer:

Time = 847.73 s = 14.12 min

Explanation:

The distance traveled by an object travelling at a constant speed is given by the following formula:

Distance = (Speed)(Time)

Time = Distance/Speed

where,

Distance = 1.7 AU

converting it into meters:

Distance = (1.7 AU)(1.496 x 10¹¹ m/1 AU) = 2.543 x 10¹¹ m

Speed = 3 x 10⁸ m/s

Therefore, using these values in the equation we get:

Time = (2.543 x 10¹¹ m)/(3 x 10⁸ m/s)

Time = 847.73 s = 14.12 min

Mark takes a 45 minute bike ride through the canyon a total of 4 kilometers what is his speed

Answers

Answer:

5.33 km /hr

Explanation:

45 minutes is  3/4   or   .75 hr

4 km / .75 hr = 5 1/3   or  5.33 km/hr

A car Excel accelerates from rest to a velocity of 5 m/s in 4 seconds. What is its average acceleration over this period of time

Answers

Answer:

1.25

Explanation:

acceleration = velocity÷time

Answer:

Its acceleration is 1.25 meters/second2

Explanation:

The car's average acceleration would be 1.25m/s^2 or 1.25meters/second/second. That looks to be the fourth one you've listed.

A system consists of two uncharged metal spheres, each suspended on an insulating string and connected to the other by a thin
conducting wire. A positively charged rod is brought near, but does not touch, the left sphere, and the sphere is attracted to the rod. Which
of the following is correct about the net charge on the right sphere as a result?

Answers

The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.

Electrostatic attraction

Since the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.

The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.

According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.

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what is the life cycle of a high mass star?

Answers

Answer:

they begin their life as a nebula, become a protostar, eventually becoming a main sequence star and finally becoming a red giant

Explanation:

Other Questions
How did geography impact the development of the Incan Civilization? joe has 3 coins. if joe flips all the coins at once, how many possible outcomes are in the sample space? Newton's Third Law of Motion relates to action and reaction. Which of the followingscenarios accurately names the correct action and reaction pair to apply to Newton'sThird Law?A) An arrow hitting a tree (action) after being launched (reaction)B)A car accelerating forward (action) after the driver pushes the accelerationpedal (reaction)C) A skateboard moving (action) after being pushed (reaction)D)An ax being used to hit wood (action) and the wood splitting after being hitby the ax (reaction) Calculate the percentrage of neutral form of aspirin that is present in the stomach ph 1. Answer the questions below about Line 1 and Line 2 shown below. Which of these BEST describes an investment in human capital?A)improving access to public LibrariesB)expanding free-trade agreementsLimiting on-the-job trainingD)decreasing sales taxes on a typical seismogram, ____________ will show the highest amplitudes. Cos 3 A + COS5A + COS7A+ Cos 15 A = 4 COS 4A COS5A COS6A Suppose Becky invests in an annuity that pays 4.3% annual interest, compounded monthly and contributes $225 every month for 20 years. She wants to calculate the value at the end of the 20 years and does so using the following computation: F. fluorite scratches limestone and gypsum G. Gypsum scratches talcH. Limestone scratches talc J. Calcite scratches gypsum determine the equation of the parabola graphed below. note: when responding if the number is negative you can't change the plus sign to a negative sign. just type the negative in the box (ie -4 would read -4). how long would it take for a net upward force of 1000n, to increase the speed of a 50.0kg object from 100m/s to 200 m/s three auditors checked into a hotel under one reservation. after paying $100 each to the hotel manager, they went to their individual rooms. the manager, noting that the total rate for the three rooms is $250, gives $50 to the bellboy to return to the three auditors. on the way to the rooms, the bellboy reasons that $50 would be difficult to share among three individuals, so he pockets $20 and gives each auditor $10. at this point, each person has paid $100 and gotten back $10. so they paid $90 each, for a total of $270. the bellboy kept $20, making the total $290 ($270 $20). where is the remaining $10? What is revealed in Mr. Washburn's car when the accident occurs?Suitcases.O Weapons.O Picnic supplies.O A dead body. QUESTION 14Which of the following is an example of a regulating ecosystem service?OA. Providing a water sourceOB. Human recreationOC. Energy flowOD. Carbon sequestrationQUESTION 15"Earth Overshoot Day" is most closely related to which of the following concepts?OA. SpeciationOB. Stormwater managementOC. Carrying capacityOD. Extinction 1) The image is a model showing the processes of the water cycle. Water uptake to the atmosphere occurs through the processes of evaporation and transpiration from plants where it condenses to form clouds. Clouds release the water through precipitation. During an extreme rainy season, what can we expect to happen to the surface ground water stored in ponds and lakes?A) animals drink more water, so water levels decreaseB) water levels will increase because there is more precipitationC) water levels will increase because there is more evaporation and transpirationD) water levels will decrease because there is more evaporation and transpiration xfind the volume v of the solid obtained by rotating the region bounded by the given curves about the specified line. y PLEASE HELP!!! GIVING EXTRA POINTS FOR ANYONE THAT ANSWERS CORRECTLY FIRST updating querying and presenting data from databases for operational purposes is known as What are the coordinates of the vertex of the function f(x)=x2+10x-3?(-5, -28)(-5, 28)(5,-28)(5, 28)