Answer: C
C. Place plastic around the metal wires, because electric charges
hardly move in plastic.
Answer:
C is the correct answer
Explanation:
Why is there an upper limit to the mass that can be supported by electron degeneracy pressure?
Electron degeneracy pressure is a specific manifestation of the more general occurrence of quantum degeneracy pressure.
What is mass electron degeneracy pressure?Electron degeneracy pressure will halt the gravitational slump of a star if its mass is below the Chandrasekhar limit (1.44 solar masses). This is the pressure that averts a white dwarf star from collapsing. Electron degeneracy pressure occurs when electrons are squeezed into a very small volume. Since their positions are well-known, they gain a large momentum in obedience to Heisenberg's uncertainty principle. This momentum generates a pressure that is temperature-independent and can result in helium flash. in stars. Electron degeneracy occurs at a solidity of about 106 kg/m3.
So we can conclude that The electron degeneracy pressure is taken by (n.v.p) where n is the number density, and v is the mean speed of the degenerate electrons.
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The tension in a ligament in the human knee is approximately proportional to the extension of the ligament, if the extension is not too large.If a particular ligament has an effective spring constant of 150 N/mm as it is stretched, what is the elastic energy stored in the ligament when stretched by 0.780 cm?
Given that the spring constant of the ligament is
\(\begin{gathered} K=150\text{ N/mm} \\ =\frac{150N}{10^{-3}\text{ m}} \\ =150\times10^3\text{ N/m} \end{gathered}\)The displacement of the ligament is
\(\begin{gathered} x=0.78\text{ cm} \\ =0.78\times10^{-2}\text{ }m \end{gathered}\)We have to find elastic energy.
Elastic energy is given by the formula
\(U=\frac{1}{2}kx^2\)Substituting the values, the elastic energy will be
\(\begin{gathered} U=\frac{1}{2}\times(150\times10^3)\text{ }\times(0.78\times10^{-2})^2 \\ =\text{ 5.85 J} \end{gathered}\)Thus, the elastic energy of the ligament is 5.85 J.
Clark Grizwald put a neon green blinking tree that weights 2.3 kg on top of his house 50 meters off the ground but he didn't tie it down right. How much velocity does the blinking tree have when it is 2 meters from the ground? Solve
The magnitude of the velocity the blinking tree has when it is 2 meters from the ground is 21.8 m/s.
Conservation of energyTo calculate the velocity of the blinking tree when it is 2 meters from the ground, we can use the principles of conservation of energy.
First, let's determine the potential energy of the tree when it is 50 meters off the ground. The potential energy (PE) can be calculated using the formula:
PE = mgh
Where:
m = mass of the tree (2.3 kg)
g = acceleration due to gravity (9.8 m/s^2)
h = height (50 m)
PE = 2.3 x 9.8 x 50
PE = 1131 J
Next, we can calculate the potential energy of the tree when it is 2 meters from the ground:
PE = mgh
Thus:
PE = 2.3 x 9.8 x 2
PE = 45.04 J
According to the conservation of energy principle:
PE(initial) = PE(final) + KE(final)
1131 J = 45.04 J + KE(final)
Now, let's solve for the kinetic energy (KE) at the final position:
KE(final) = PE(initial) - PE(final)
KE(final) = 1131 J - 45.04 J
KE(final) = 1085.96 J
KE = (1/2)mv^2
1085.96 J = (1/2) x 2.3 kg x v^2
Thus
v^2 = (2 x 1085.96 J) / 2.3 kg
v^2 = 474.76 m^2/s^2
v ≈ 21.8 m/s
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a car traveling at 28.4 m/s undergoes a constant deceleration of 1.92 m/s2 when the breaks are applied. How many revolutions does each tire make before the car comes to a stop
Complete Question
a car traveling at 28.4 m/s undergoes a constant deceleration of 1.92 m/s2 when the breaks are applied. How many revolutions does each tire make before the car comes to a stop? Assume that the car does not skid and that each tire has a radius of 0.307 m. Answer in units of rev.
Answer:
The value is \(N = 109 \ rev\)
Explanation:
From the question we are told that
The speed of the car is \(u = 28.4 \ m/s\)
The constant deceleration experienced is \(a = 1.92 \ m/s^2\)
The radius of the tire is \(r = 0.307 \ m\)
Generally from kinematic equation we have that
\(v^2 = u^2 + 2as\)
Here v is the final velocity which is 0 m/s
So
\(0^2 = 28.4^2 + 2 * 1.92 * s\)
=> \(s = 210.04 \ m\)
Generally the circumference of the tire is mathematically represented as
\(C = 2 \pi r\)
=> \(C = 2 * 3.142 * 0.307\)
=> \(C = 1.929 \ m\)
Generally the number of revolution is mathematically represented as
\(N = \frac{ s}{C}\)
=> \(N = \frac{210.04}{1.929}\)
=> \(N = 109 \ rev\)
In the diagram, R₁ = 40.0 , R2= 25.4 , and R3 = 70.8 . What is the equivalent resistance of the group?
According to the diagram the equivalent resistance of the group is
40.05 ohms
How to find the equivalent resistanceThe equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1
Resistors in parallel is solved by
Resistors in parallel = 1/25.4 + 1/70.8
Resistors in parallel = 0.0535 ohms
Equivalent resistance
Equivalent resistance = Resistors in parallel + Resistor in series
Equivalent resistance = 0.0535 + 40
Equivalent resistance = 40.0535
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To increase the potential energy of the system, what did you have to do?
Answer:
You can use work to add kinetic energy to a system or to increase potential energy in the system.
Explanation:
Potential energy stored in any system can be released as kinetic energy. Kinetic energy can be transformed to do work or to increase potential energy.
hope this helped
When a falling meteoroid is at a distance above the Earth's surface of 3.50 times the Earth's radius, what is its acceleration due to the Earth's gravitation?
Answer:
0.484 m/s²
Explanation:
To solve this question, we would apply the formula for calculating gravitational acceleration at any distance.
g = GM/r², where
g = acceleration due to gravity
G = gravitational constant
r = radius of the meteoroid
Radius of the earth is given as 6371 km
The meteoroid is located at a distance 3.5 times the radius of the earth, so
r = R + 3.5R = 4.5R
r = 28670 km
Mass of the earth is, 5.97*10^24 kg
Now, we proceed to substitute our values into the earlier equation
g = GM/r²
g = (6.67*10^-11 * 5.97*10^24) / 28670²
g = 398.2*10^12 / 822*10^12
g = 0.484 m/s²
Thus, it's acceleration due to earth's gravitation is 0.484 m/s²
What exercises can help reduce stress?
which of the following describes the net force on an object?
A. The sum of all forces acting on an object
B. The Gravitational force minus any contact forces on an object.
C. The difference between the normal force and the Gravitational force acting on an object.
D. the sum of all forces acting on an object in the same direction.
The statement that describes the net force on an object is the sum of all forces acting on an object (option A).
What is net force?Net force is sum of all forces acting on an object in a single plane.
When a force is applied to a body, not only is the applied force acting, there are many other forces like gravitational force, frictional force and the normal force that balances the other force.
The sum of all these forces acting on the object whether in the same or opposite direction is regarded as the net force.
Therefore, the statement that describes the net force on an object is the sum of all forces acting on an object.
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HELP QUICK! Please can anyone do the other half for me
Answer:
9) c
10) c
11) d
12) d
Explanation:
I think it's helps you
In outer space, a constant force is applied to a 33.2 kg probe initially at rest. The probe moves a distance of 101 m in 15 s. What acceleration does this force produce? What is the magnitude of the force?
Answer:
a
=
F
M
a
=
137
30.8
x
=
1
2
a
t
2
x
=
1
2
⋅
137
30.8
⋅
13
2
x
=
375.86
Explanation: Hope this helps ;)
If a seagull drops a shell from rest at a height of 16 m , how fast is the shell moving when it hits the rock
Answer:
We know:
V1 = 0m/s
a = 9.8m/s
D = 16m
So we can solve for V2 with a kinematic equation.
V2^2 = 2a*D
V2^2 = 2(9.8)(16)
V2^2 = 313.6
V2 = 17.7m/s
Explanation:
If a seagull drops a shell from rest at a height of 16 m, the shell would have been moving with a velocity of when it hits the rock
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
The expression for total mechanical energy is as follows
ME= PE+KE
As for the given problem, If a seagull drops a shell from rest at a height of 16 m , as the seagull drops from that height the potential energy stored is converted into kinetic energy,
height = 16 m
1/2mv²= mgh
v = √(2gh)
m is the mass of the object
v is the velocity of the object
by substituting the respective values
v = √(2×9.81×16)
v =17.71 meter/ seconds
Thus ,shell would have been moving with a velocity of 17.71 meters/ seconds when it hit the rock.
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As shown, the two charges are 3 cm apart. What will happen to this force if the distance between the charges is doubled? Use proportional reasoning to find the answer and then check by moving the charges.
Answer:
if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value. If the charges come 10 times closer, the size of the force increases by a factor of 100. The size of the force is proportional to the value of each charge.
When charges are 3 centimeters apart if the distance between the charges is doubled, the force between them is reduced by a factor of four.
What is Coulomb's Law?Coulomb's law can be stated as the product of the charges and the square of the distance between them determine the force of attraction or repulsion acting in a straight line between two electric charges.
F= k Q₁Q₂/r²
Where F is the force between two charges
As given in the problem, the two charges are 3 centimeters apart, then we have to find out what will happen to this force if the distance between the charges is doubled.
As per Coulomb's law, the force is inversely proportional to the square of the distance between charges.
Thus, the force between them is reduced by a factor of four.
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Remember: Weight (newtons) = mass* gravity and 1 kg = 2.2 pounds. 14. A typical NFL lineman weighs around 314 pounds. Calculate the weight in Newtons.
1,401.88 N is the required weight of the man using the given conversion factor.
Determining the weight of an objectTo calculate the weight of a typical NFL lineman in Newtons, we need to first convert the weight from pounds to kilograms using the conversion factor of 1 kg = 2.2 pounds:
314 pounds ÷ 2.2 pounds/kg = 142.73 kg
Next, we can use the formula Weight (newtons) = mass * gravity, where gravity is approximately 9.81 m/s^2 (meters per second squared):
Weight (newtons) = 142.73 kg * 9.81 m/s^2 = 1,401.88 N
The required weight in Newton of the man is 1,401.88 N
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Help plz!:( it’s for physics but it has like math !!
(SHOW ALL WORK)
1) A 30-kg object is accelerated at a rate of 3m/s2. how much force does the object have?
2)A ball is thrown w/ a force of 50N and travels 4m. how much work is done to the ball?
3) Joey pushes on a door that is stuck with 400 N of force but is unable to move it. How much work has he done?
4) A toy car does 300j of work in 15 sec. how much power did the car use?
5)A 60w light bulb burns for 2 min. how much work was done?
6) how much power is used if it takes Frank (a 450 N boy) 3 sec to run 2 meters?
Answer:
1. 90N
2. 200N
3. 400N
4.20w
5.7200N
Explanation:
1.F=ma
30 * 3 = 90
2.W=FD
50 * 4=200
4. P=W/t
300/15=20
5.W= Pt. 2minutes = 120sec
60*120 = 7200
A vertical spring stretches 3.4 cm when a 12-g object is hung from it. The object is replaced with a block of mass 26 g that oscillates up and down in simple harmonic motion. Calculate the period of motion.
Answer:
Period of motion is approximately 0.5447 seconds
Explanation:
We start by calculating the constant "k" of the spring which can be derived from the fact that an object of mass 12 g produced a stretch of 3.4 cm: (we write everything in SI units)
F = k * x
0.012 kg * 9.8 m/s^2 = k 0.034 m
k = 0.012 kg * 9.8 m/s^2 / (0.034 m)
k = 3.46 N/m
now we use the formula for the period (T) of a spring of constant k with a hanging mass 'm':
\(T=2\pi\,\sqrt{\frac{m}{k} }\)
which in our case becomes:
\(T=2\pi\,\sqrt{\frac{0.026}{3.46} } \approx 0.5447\,\,sec\)
An electric heater uses 0,5 MJ when connected to a 220 V supply for 30 minutes. Calculate the power rating of the heater and the current drawn from the supply.
The power rating of the heater is 277.8 W and the current drawn from the supply is 0.07015mA.
The power is obtained from the ratio of work and time and the power is measured in watts(W). The current is defined as the flow of electrons in the circuit and it is measured in ampere(A).
From the given,
The energy of the electric heater = 0.5MJ = 0.5×10⁶ J
Voltage (V) = 220 V
time (t) = 30 minutes = 30×60 s = 1800 s.
To find power (P):
Power = Energy / Time
= 0.5×10⁶ / 1800
= 277.77 W
Power of the electric heater = 277.8 W
To find current from the given:
Power (P) = V×I×t
Current (I) = P/(V×t)
= 277.8 / (220×1800)
= 0.7015 mA
The current drawn from the supply is 0.7015 mA.
Hence, the power rating of the heater is 277.8 W and the current drawn from the supply is 0.7015 mA.
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A rubber balloon is filled with normal air and sealed, and the gas inside is
heated with an electrical coil. A) What happens to the particles inside the balloon
when the gas inside is heated? B) How does this affect the force the particles
strike the balloon wall? C) Use the kinetic theory to predict the effect of heating
the gas inside a balloon on the volume (size) of the balloon.
Answer:
wait, wont the balloon pop if there is gas inside?
Explanation:
a 25-cm-long glass stirring rod at a laboratory temeprature of 20 c is placed in an autoclave and heated to 150 c. by about how much does the rod expand
In order to reach a chambers temperature of a minimum of 250°F (121°C) for just a set amount of time—typically 30–60 minutes—autoclaves employ saturation steam with a pressure of around 15 square inches per square.
What kind of heat is in an autoclave?To eliminate any potential microbiological life on a contaminated load, autoclaves use steam heat. Once a cargo, also known as goods, has gone through a complete sterilising cycle, it is deemed sterile.
Why would a lab need an autoclave?An autoclave is used to sterilise surgical instruments, lab equipment, pharmaceutical products, and other things. It has the capacity to sterilise devices of all shapes and sizes as well as hollow items, liquids, solids, and solids. The dimensions, architecture, and operation of autoclaves vary.
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An astronaut measure the period of a mass spring system on Earth. How would the period be affected if the astronaut measured the period of the same mass spring system on the moon? (Moon's gravity = 1/6 Earth's gravity.)
An astronaut measure the period of a mass spring system on Earth.
The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.
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An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?
Answer: the radius of the circular path is approximately 1637.58 meters.
Explanation:
The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:
F_c = m * g * tan(banking angle)
Where:
F_c is the centripetal force
m is the mass of the airplane
g is the acceleration due to gravity
tan(banking angle) is the tangent of the banking angle
Now, the centripetal force is also given by the formula:
F_c = (m * v^2) / r
Where:
v is the speed of the airplane
r is the radius of the circular path
Equating the two expressions for F_c, we get:
(m * g * tan(banking angle)) = (m * v^2) / r
Canceling out the mass (m) on both sides of the equation, we have:
g * tan(banking angle) = v^2 / r
Solving for r, we get:
r = (v^2) / (g * tan(banking angle))
Substituting the given values:
v = 400 km/h = 400,000 m/h
g = 9.8 m/s^2
banking angle = 20°
Converting the speed to m/s:
v = 400,000 m/h * (1/3600) h/s = 111.11 m/s
Converting the banking angle to radians:
banking angle = 20° * (π/180) rad/° = 0.3491 rad
Now, substituting the values into the formula:
r = (111.11^2) / (9.8 * tan(0.3491))
r ≈ 1637.58 meters
Therefore, the radius of the circular path is approximately 1637.58 meters.
2. When things happen the force is said to be ————.
1. Lifting an elevator 18m takes 100kJ. If doing so takes 20s, what is the average power of the elevator during the process?
2. How much work can a 0.4 hp electric mixer do in 15 s?
Answer:
1. Power = 5000 Watts
2. Workdone = 11185.5 Joules
Explanation:
Given the following data;
1. Distance = 18 m
Energy = 100 KJ = 100,000 Joules
Time = 20 seconds
To find the average power of the elevator;
Power = energy/time
Power = 100000/20
Power = 5000 Watts
2. Power = 0.4 HP
Time = 15 seconds
Conversion:
1 horsepower = 745.7 Watts
0.4 horsepower = 0.4 * 745.7 = 298.28 Watts
To find the amount of work done by the electric mixer;
Work done = power * time
Workdone = 745.7 * 15
Workdone = 11185.5 Joules
In an experiment, a 0.028-kilogram rubber stopper is attached to one end of a string. A student whirls the stopper overhead in a horizontal circle with a radius of 1.0 meter. The stopper completes 10 revolutions in 10 seconds.
22. Determine the speed of the whirling stopper.
23. Calculate the magnitude of the centripetal force on the whirling stopper. [Show all work, including the equation and substitution with units.]
Hi there!
22.
We can calculate the speed by first calculating the period of the stopper.
1 period = time taken for one revolution
10 rev/10 sec = 1 rev/sec
Since it takes 1 second for the stopper to make a complete circle, its velocity can be found using the equation for circumference:
\(v = \frac{2\pi r}{t} = \frac{2\pi (1)}{1} = \boxed{2\pi \approx 6.28 m/s}\)
23.
The centripetal force can be solved for using the following:
\(F_c = \frac{mv^2}{r}\)
m = mass (kg)
v = velocity (m/s)
r = radius (m)
Fc = Centripetal force (N)
Plug in the givens:
\(F_c = \frac{0.028(2\pi)^2}{1} = \boxed{1.105 N}\)
calculate the quantity of heat absorbed by 14 g
of water that warms from 30 ∘C
to 98 ∘C
The quantity of heat absorbed by 14 g of water that warms from 30 ∘C to 98 ∘C is approximately 4087.84 J.
What is heat absorbed?
Heat absorbed refers to the amount of thermal energy that is taken in by a substance or system during a process, such as heating up or melting.
The amount of heat absorbed by a substance is given by the equation:
Q = m * c * ΔT
Where:
Q = amount of heat absorbed or releasedm = mass of the substancec = specific heat capacity of the substanceΔT = change in temperature of the substanceFor water, the specific heat capacity is approximately 4.18 J/g°C.
Using the given values, we can calculate the amount of heat absorbed by the water as follows:
m = 14 g
c = 4.18 J/g°C
ΔT = (98°C - 30°C) = 68°C
Q = 14 g * 4.18 J/g°C * 68°C = 4087.84 J
Therefore, the quantity of heat absorbed by 14 g of water that warms from 30 ∘C to 98 ∘C is approximately 4087.84 J.
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Approximately how long will it take light to travel to 1.7 AU in minutes? Use 3 × 108 m/s for the speed of light. unanswered
Answer:
14.1mins
Explanation:
We know that
Time =Distance/Speed
So
= 1.7 au/ (3 E8 m /s )
= 1.7 x 1.496 x 10^11 m /(3 x 10^8 m /s
Converting Au to meters (1.7 x 1.496 x 10^11 m)
= 847.7 s
=14.1 mins
Answer:
Time = 847.73 s = 14.12 min
Explanation:
The distance traveled by an object travelling at a constant speed is given by the following formula:
Distance = (Speed)(Time)
Time = Distance/Speed
where,
Distance = 1.7 AU
converting it into meters:
Distance = (1.7 AU)(1.496 x 10¹¹ m/1 AU) = 2.543 x 10¹¹ m
Speed = 3 x 10⁸ m/s
Therefore, using these values in the equation we get:
Time = (2.543 x 10¹¹ m)/(3 x 10⁸ m/s)
Time = 847.73 s = 14.12 min
Mark takes a 45 minute bike ride through the canyon a total of 4 kilometers what is his speed
Answer:
5.33 km /hr
Explanation:
45 minutes is 3/4 or .75 hr
4 km / .75 hr = 5 1/3 or 5.33 km/hr
A car Excel accelerates from rest to a velocity of 5 m/s in 4 seconds. What is its average acceleration over this period of time
Answer:
1.25
Explanation:
acceleration = velocity÷time
Answer:
Its acceleration is 1.25 meters/second2
Explanation:
The car's average acceleration would be 1.25m/s^2 or 1.25meters/second/second. That looks to be the fourth one you've listed.
A system consists of two uncharged metal spheres, each suspended on an insulating string and connected to the other by a thin
conducting wire. A positively charged rod is brought near, but does not touch, the left sphere, and the sphere is attracted to the rod. Which
of the following is correct about the net charge on the right sphere as a result?
The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.
Electrostatic attractionSince the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.
The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.
According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.
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what is the life cycle of a high mass star?
Answer:
they begin their life as a nebula, become a protostar, eventually becoming a main sequence star and finally becoming a red giant
Explanation: