Question 4
3 pts
I am approaching a traffic light at a speed of 135 km/h when I suddenly notice that
the light is red. I slam on my brakes and come to a stop in 4.29 seconds. What is the
acceleration of the car as I screech to a complete stop? (Note that an object that slows down
simply has a negative acceleration.)
& show work please I want to also understand

Answer:

11.2 m/s

Explanation:

We need to first figure out how long it took to reach the ball's max height:

Vf = 0

Vi = 30 m/s

a = -9.81 m/s^2

t = ?

---------------

Vf = Vi + at

0 = 30 + (-9.81)t  --->  -30 = -9.81t  ---> 3.058 = t

t = 3.058 s

---------------

We can now solve the problem by subtracting the given time (4.2s) by the max height time (3.058s) and plugging that into a kinematic equation for Vf:

Vi = 0

a = 9.81 m/s^2

t = (4.2s - 3.058s) = 1.142 s

Vf = ?

---------------

Vf = Vi + at

Vf = 0 + (9.81)*(1.142)  ---> Vf = 11.203

---------------

The velocity of the ball after 4.2s is 11.2 m/s

Answer:

The slopes for each of the four line segments are \(a_{A} = 6\,\frac{m}{min^{2}}\), \(a_{B} = 0\,\frac{m}{min^{2}}\), \(a_{C} = -4\,\frac{m}{min^{2}}\) and \(a_{D} = 2.667\,\frac{m}{min^{2}}\), respectively.

Explanation:

There are four line segments:

(i) Line A: \(v(0\,min) = 0\,\frac{m}{min}\), \(v(10\,min) = 60\,\frac{m}{min}\)

(ii) Line B: \(v(10\,min) = 60\,\frac{m}{min}\), \(v(15\,min) = 60\,\frac{m}{min}\)

(iii) Line C: \(v(15\,min) = 60\,\frac{m}{min}\), \(v(40\,min) = -40\,\frac{m}{min}\)

(iv) Line D: \(v(40\,min) = -40\,\frac{m}{min}\), \(v(55\,min) = 0\,\frac{m}{min}\)

The slope of each line segment represents the acceleration of the particle, which can calculated by the geometrical concept of secant line. Hence, we proceed to determine the acceleration associated with each line segment:

Line A

\(a_{A} = \frac{v(10\,min)-v(0\,min)}{10\,min-0\,min}\)

\(a_{A} = \frac{60\,\frac{m}{min}-0\,\frac{m}{min}}{10\,min-0\,min}\)

\(a_{A} = 6\,\frac{m}{min^{2}}\)

Line B

\(a_{B} = \frac{v(15\,min)-v(10\,min)}{15\,min-10\,min}\)

\(a_{B} = \frac{60\,\frac{m}{min}-60\,\frac{m}{min} }{15\,min-10\,min}\)

\(a_{B} = 0\,\frac{m}{min^{2}}\)

Line C

\(a_{C} = \frac{v(40\,min)-v(15\,min)}{40\,min-15\,min}\)

\(a_{C} = \frac{-40\,\frac{m}{min}-60\,\frac{m}{min} }{40\min-15\,min}\)

\(a_{C} = -4\,\frac{m}{min^{2}}\)

Line D

\(a_{D} = \frac{v(55\,min)-v(40\,min)}{55\,min-40\,min}\)

\(a_{D} = \frac{0\,\frac{m}{min}-\left(-40\,\frac{m}{min} \right) }{55\,min-40\,min}\)

\(a_{D} = 2.667\,\frac{m}{min^{2}}\)

The slopes for each of the four line segments are \(a_{A} = 6\,\frac{m}{min^{2}}\), \(a_{B} = 0\,\frac{m}{min^{2}}\), \(a_{C} = -4\,\frac{m}{min^{2}}\) and \(a_{D} = 2.667\,\frac{m}{min^{2}}\), respectively.

Answer:

D

Explanation:

the electromagnetic spectrum represents the full range of electromagnetic energies in order, including radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

The current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

Thévenin's theorem states that any linear network of voltage and current sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. The equivalent circuit provides the same output voltage and current as the original circuit for any external load connected to it.

To find the current I in the circuit using Thévenin's theorem, we need to follow these steps:

Step 1: Find the Thévenin equivalent voltage (Vth) across the 4 kΩ resistor.

To find Vth, we need to first find the open circuit voltage (Voc) across the 4 kΩ resistor. We can do this by removing the 4 kΩ resistor and finding the voltage between its two terminals using a voltage divider:

Voc = 6 kΩ/(2 kΩ + 6 kΩ) x 2 mA = 1.2 V

Next, we need to find the Thévenin equivalent resistance (Rth) across the 4 kΩ resistor. To do this, we need to short-circuit all the independent voltage sources (in this case, there is only one) and find the equivalent resistance seen from the terminals of the 4 kΩ resistor. With the 2 mA current source shorted out, the 2 kΩ and 4 kΩ resistors are in parallel:

Rth = 2 kΩ || 4 kΩ = 1.33 kΩ

Step 2: Replace the original circuit with the Thévenin equivalent circuit.

We can now replace the original circuit with the Thévenin equivalent circuit, which consists of a voltage source Vth = 1.2 V in series with a resistor Rth = 1.33 kΩ.

Step 3: Find the current I through the 4 kΩ resistor in the Thévenin equivalent circuit.

To find the current I, we can use Ohm's law:

I = Vth/(Rth + 4 kΩ) = 1.2 V/(1.33 kΩ + 4 kΩ) = 0.199 mA

Therefore, the current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

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ANSWER

False.

EXPLANATION

Nuclear binding energy is the energy that is required to split the nucleus (of an atom) into nucleons: protons and neutrons.

The binding energy of a nucleus is always positive because nuclei require energy to separate them and it is impossible for nuclei to gain energy by being separated.

Therefore, the answer is false.

Answer:

0.001 A

Explanation:

Applying,

V = IR.............. Equation 1

Where V = Voltage of the motor, I = current, R = resistance

make I the subject of the equation

I = V/R.............. Equation 2

From the question,

Given: V = 1000 V, R = 1 MΩ = 10⁶ Ω

Substitute these values into equation 2

I = 1000/10⁶

I = 10⁻³ A

I = 0.001 A

Answer:

dont ask me

Explanation:

Answer:

c and d

Explanation:

I got your back bro ;)

Answer:

C and D

Explanation:

Answer:

It’s b

Explanation:

Everyone else is wrong and I tried this and got it right

Answer:

the answer is b or "The sound wave will not be generated, so there will be no echoes received."

Explanation:

what are the answer choices?

The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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Answer:

Explanation:

In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.

So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.

Answer:

isotopes

Explanation:

Isotopes are atoms of the same element that have different numbers of neutrons but the same number of protons and electrons. The difference in the number of neutrons between the various isotopes of an element means that the various isotopes have different masses.

BRAINLIEST PLSS

Answer:

N = 648.55[N]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F =  Forces applied [N]

m = mass = 73.2 [kg]

a = acceleration = 0.950 [m/s²]

Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.

By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.

\(-m*g + N = -m*a\\\)

where:

g = gravity acceleration = 9.81 [m/s²]

N = normal force (or weight) measured by the scale = 83.4 [N]

Now replacing:

\(-(73.2*9.81)+N=-73.2*0.950\\-718.092+N=-69.54\\N = -69.54+718.092\\N = 648.55[N]\)

The acceleration has a negative sign, this means that the elevator is descending at that very moment.

The time it takes for blood to travel from the aorta to the capillaries is 20 seconds. This can be calculated using the equation: t = v₁ - v₂ / a , where v₁ is the initial velocity (10 cm/s), v₂ is the final velocity (0.5 mm/s), and a is the acceleration (0.4 cm/s²). Therefore, t = 10 cm/s - 0.5 mm/s / 0.4 cm/s² = 20 s.

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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Answer:

A) 4.035 × 10^(9) J

B) 9.29 × 10^(9) J

Explanation:

We are given;

Capacitance of the original capacitor; C = 1.33 F

Potential difference given to the original capacitor; V = 77.9 kV = 77.9 × 10³ V

A) The formula for Potential energy (U) for the original capacitor is given as:

U = ½CV²

Plugging in the relevant values, we have;

U = ½ × 1.33 × (77.9 × 10³)²

U = 4.035 × 10^(9) J

B) We are told that the capacitor with dielectric constant of 427, was replaced with one possessing a dielectric constant of 983.

Thus;

U = ½ × 1.33 × (983/427) × (77.9 × 10³)²

U = 9.29 × 10^(9) J

Answer:

Am doing well am fine thank you

Answer:

D.some of its potential energy is transformed into kinetic energy each time it falls.

Look up "Everything You Need To Know About Math In One Big Fat Notebook pdf." It's the best thing I've ever been given, I have it with me in math class all the time and I've aced every test. I have it with me right now and it has everything I've ever been taught about math in it so it might help you.

Hello,

Let's consider the temperature in any scale be "x".

Then,

• Temperature in Celsius = x °C

• Temperature in Kelvin scale = x K

Answer:

A

Explanation:

i hope u have a great day

Winds that are blowing over short distances is called local winds. They are dependent on the local geography.

Local winds are caused by the air moving between high and low pressure regions in confined spaces. Each form of wind differs slightly from the others since there are various sorts of winds. Local winds will always have a big impact on a region's climate.

When there is a significant  temperature difference between two nearby earth locations, local winds are produced. In other terms, a wind is produced when hot air rises more quickly than cold air.

Local winds are produced as a result of the landmass of the continent warming and cooling at a different rate than the oceans. The locations of the warm and cold air masses determine the direction of local winds.

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The kinetic energy of the first block just at the foot of the incline is 78.4J, the kinetic and gravitational potential energies of the first block halfway down the incline are same, and which is equal to 39.2J. The speeds of the two blocks just after their collision interchange with the values before collision.

To find the answer, we need to know about the concept of collision and kinetic energy.

                 \(TE=KE+PE\\T=PE=m_1gh=(0.4*9.8*20)=78.4 J\)

                   \(TE=KE=78.4J\)

                          \(U'=m_1gh'=mg\frac{h}{2} \\U'=39.2J\)

                      \(TE=78.4 J\\KE'+PE'=78.4J\\KE'=78-U'=78.4-39.2=39.2J\)

                            \(KE=\frac{1}{2} mv^2=78.4J\\v=\sqrt{\frac{2KE}{m} } =4m/s\)

               \(\frac{1}{2}m_1u_1^2+ \frac{1}{2}m_2u_2^2=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_2v_2^2\)

                 \(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

                            \(m_1=m_2=m\\u_1=4m/s\\u_2=0\\v_1=?\\v_2=?\)

                       \(\frac{1}{2}m*4^2=\frac{1}{2}m(v_1^2+v_2^2)\\(v_1^2+v_2^2)=16\)  from resolving KE equation.

                        \(4m=m(v_2+v_1)\\4=v_2+v_1\\v_1=4-v_2\) From resolving momentum conservation.

                            \(v_2=4m/s\\v_1=0\)

Thus, we can conclude that, the kinetic energy of the first block just at the foot of the incline is 78.4J, the kinetic and gravitational potential energies of the first block halfway down the incline are same, and which is equal to 39.2J. The speeds of the two blocks just after their collision interchange with the values before collision.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

Anisotropy, in physics, the quality of exhibiting properties with different values when measured along axes in different directions. Anisotropy is most easily observed in single crystals of solid elements or compounds, in which atoms, ions, or molecules are arranged in regular lattices.

Explanation:

HOPE IT HELPS

Answer: table

Explanation:

Answer:Table

Explanation:

A table is a way to represent data , but does not identify trends in the data

The correct answer is Option B. The statement "they have the same A-number but different Z-number" is true .

Atoms of the same element only differ because one of the atoms has more electrons, making it an ion.

This difference does not affect the mass of the atom, which is determined by the sum of its protons and neutrons, represented by the atomic mass or A-number.

The number of protons in an atom is called the atomic number or Z-number.

The Z-number of an element is unique to it. All the atoms of a given element have the same number of protons.

Thus, for example, all carbon atoms have six protons, making the Z-number of carbon 6.

However, different isotopes of an element can have different numbers of neutrons.

This means that they have a different atomic mass or A-number.

Therefore, they have the same A-number but different Z-number.

Therefore the correct Option is B.

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