Question 81 point)
Ms. Vetter has not worked out in a long time. She is trying to lift her pet bunny cage off the ground to put into her car for their trip to Bunnyville
to visit some of her pet bunnies ancestors. If Ms. Vetter does not have enough _____ _____ she can use a simple machine to help her lift the cage off the ground and into her car.

A.craft supplies
B.big muscles
C.mechanical force
D.mechanical advantage

Answer:

Ionic bond

Explanation:

Hope it helps ya

One full weather station reports  wave passing a spot every second is equivalent to a frequency of 1 Hz. The frequency is 48=12=0.5 Hz if 4 waves pass a spot in 8 seconds.

The number of cycles that make up a time unit is the frequency. The frequency of a wave with a 30-second period is therefore 1 30 = 0.033 cycles per second, or 0.033 Hertz (Hz).

A wave's speed and wavelength vary as it crosses a border and enters a new medium, but its frequency doesn't.

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The minimum force of friction required to hold the system of Figure in equilibrium is 50 Newton.

What is frictional force?

Frictional force is the force produced when two surfaces slide against and touch each other. The surface texture and amount of force needing them together have the biggest an impact on these forces. The amount of frictional force is influenced by the object's position and angle.

The forces of adhesion between the sites of contact areas of the surfaces, which are always minutely uneven, are the primary cause of friction between objects. The action of the imperfections of the harder surface tilling across the softer surface shears these "fused" connections, causing friction.

If an object is placed against an object, then the frictional force will be the same as the weight of the object. If an object is pushed against the surface, then the frictional force will be increased and become extra than the weight of the object.

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Explanation

The uniformly accelerated motion is a motion that is characterized for having a movement in a straight line and a constant acceleration and different of zero, to find the initial speed we can use the formula:

so

Step 1

a)let

b) now, replace in the formula and solve for vi

therefore, the answer is

B. 60 m/s

I hope this helps you

We push a car to the distance of 33.939m if we do 28000J work , exerting a force of 825N.

F = applied force

S = distance moved

=28000J/825N

=33.939meter

Thus, we can conclude that the distance moved by the car is 33.939m.

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Answer:

2.67 ohm

Explanation:

V=IR

R=V/I

In which V is voltage and I is current and R is resistance

The energy input at aphelion (farthest from the sun) is 92% of the intensity at perihelion (closest to the sun) because of the inverse-square law, which states that the intensity of radiation decreases with the square of the distance from the source.

However, the difference in energy input does not solely explain the difference in surface temperature from winter to summer.

Other factors, such as the Earth's axial tilt, atmospheric composition, and cloud cover also play a role in determining the surface temperature.

Evidence from climate models and observations indicate that changes in these factors, especially changes in the number of greenhouse gases in the atmosphere, can have a significant impact on global temperature patterns.

In conclusion, while the inverse-square law affects the intensity of solar radiation, it is not the sole factor in determining surface temperature, and the role of other factors must be considered to fully understand seasonal and climatic variations.

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The force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is 12.4 N.

Start by calculating the change in velocity (Δv) experienced by the object. This can be done by subtracting the initial velocity v₁ from the final velocity v.

Δv = v - v₁ = ((8î + 3) - 5k) - ((4î - 5) + 3k)

= 8î + 3 - 5k - 4î + 5 - 3k

= 4î - 8k + 8

Next, calculate the acceleration (a) using the formula:

a = Δv / t

where t is the time interval, given as 10 seconds.

a = (4î - 8k + 8) / 10

= (0.4î - 0.8k + 0.8) m/s²

The force (F) required to accelerate the object can be found using Newton's second law:

F = m * a

where m is the mass, given as 40 kg.

F = (40 kg) * (0.4î - 0.8k + 0.8) m/s²

= (16î - 32k + 32) N

Simplify the expression to obtain the final answer:

F = 16î - 32k + 32 N

≈ 12.4 N

Therefore, the force needed to accelerate a mass of 40 kg from velocity v₁ = (4î - 5) + 3k)m/s to v = (8î + 3) - 5k)m/s in 10 seconds is approximately 12.4 N.

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During the first two minutes of flight, the SRB and main engine accelerate at a rate of 52.16 m/s2.

Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. The provided parameters are the engine's initial velocity (u), its end velocity (v), and the time of motion (t), which is equal to two minutes (2 x 60 s).

Following are the calculations for the main engine and SRB's acceleration.

a= Δv / Δt

a=7600-1341 /2*60s

a=52.16 m/s²

Consequently, 52.16 m/s2 is the acceleration of the main engine and SRB during the first two minutes of flight.

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Answer:

   t = 2.09 10⁻³ s

Explanation:

We must solve this problem in parts, first we look for the acceleration of the electron and then the time to travel the distance

let's start with Newton's second law

        ∑ F = m a

the force is electric

        F = q E

we substitute

        q E = m a

        a = \(\frac{q}{m} \ E\)

        a = \(\frac{1.6 \ 10^{-19}}{ 9.1 \ 10^{-31} } \ 7.8 \ 10^{-9}\)

        a = 1.37 10³ m / s²

now we can use kinematics

        x = v₀ t + ½ a t²

indicate that rest starts v₀ = 0

        x = 0 + ½ a t²

        t = \(\sqrt{\frac{2x}{a} }\)

        t = \(\sqrt{\frac {2 \ 3 \ 10^{-3}}{ 1.37 \ 10^3} }\)

        t = 2.09 10⁻³ s

The comet will have the most gravitational potential energy at : ( B ) Point A

Given that the gravitational potential energy between two bodies is expressed as

Ux = - GMm / d ------ ( 1 )

where :

G = gravitational constant

M = mass of larger body ( sun )

m = mass of comet

d = distance between the bodies

Therefore the greater the distance ( d ) between the bodies the less negative the potential gravitational energy the smaller body will possess. from the image attached below, the point on the orbit that is farthest from the sun is Point A

Hence we can conclude that the comet will have the most gravitational potential energy at : ( B ) Point A

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Answer: its letter c

Explanation:

The tension T₁ on the left side of the rope is 698 N.

Equilibrium is a State of balance in which opposing forces are balanced, of when there is no net change in system. It is a State of rest or balance due to the equal action of opposing forces.

\($$From equilibrium along $x$ direction$$\begin{aligned}T_1 \sin 15 & =T_2 \cos 10 \\\frac{T_1}{T_2} & =\frac{\cos 10}{\sin 15} \\T_1 & =3.8 T_2\end{aligned}\)

\($$From equilibrium along y direction$$\begin{aligned}T_1 \cos 15+T_2 \sin 10 & =m g \\\left(3.8 T_2\right) \cos 15+T_2 \sin 10 & =(72)(9.8) \\T_2 & =\frac{(72)(9.8)}{(3.8) \cos 15+\sin 10} \\& =183.55 \mathrm{~N} \\& =184 \mathrm{~N}\end{aligned}\)

\($$From equation,$$\begin{aligned}T_1 & =3.8 T_2 \\& =3.8(183.55 \mathrm{~N}) \\& =698 \mathrm{~N}\end{aligned}$$\)

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Complete question:

A 72 Kg Man Is Being Pulled Away From A Burning Building As Shown In The Figure. T1= 15 Degrees On The "Y" Access T2= 10....

Calculate the tension T1 on the left side of the rope, in newtons, if the man is in static equilibrium.

Calculate the tension T2 on the right side of the rope, in newtons, if the man is in static equilibrium.

In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated

When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.

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The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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To convert 813 into grams if it is already in grams, then the value remains as 813 grams. If it is in pounds, 813 pounds would be approximately 368,646.696 grams. If it is in kilograms, 813 kilograms would be equal to 813,000 grams.

To convert 813 into grams, we need to know the unit of measurement you're referring to. Grams are typically used to measure the weight of objects, but without additional context, it's difficult to provide an accurate answer.

If you are referring to 813 grams, then the conversion is straightforward, as it is already in grams.

If you are referring to another unit, such as pounds or kilograms, we can convert it to grams:

If you meant 813 pounds, one pound is approximately equal to 453.592 grams. Therefore, 813 pounds would be approximately 368,646.696 grams.

If you meant 813 kilograms, one kilogram is equal to 1,000 grams. Therefore, 813 kilograms would be equal to 813,000 grams.

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Answer: Contact force

a. Applying break in a vehicle.

d. The speed of ball rolling on ground is reduced

Non contact force

b. A coconut falling from a coconut tree.

c. The planets revolving around the sun.

Explanation:

The contact force is the force which exerts when one object or entity comes in contact with other object or entity. For example, on application of break the vehicle stops, the force is applied on the breaks to stop the vehicle. The ball rolling on the ground the speed reduces so the application of force on the ground also reduces.

The non contact force is the force one object exerts on the other without coming in direct contact with the other object. The force exerted by one object on other due to gravity is a non contact force. The coconut falling on the ground and planets revolving around the sun are examples of non contact force due to gravity.

The density of the unknown liquid is 1000 kg/m³.

Density is a measure of how much mass is contained in a given volume of a substance. It is calculated by dividing the mass of a substance by its volume. The unit of density is typically expressed in kilograms per cubic meter (kg/m³) in the SI system of units.

Let's start by using the equation for pressure in a liquid:

P = ρgh

where P is the pressure, ρ is the density, g is the acceleration due to gravity, and h is the height of the liquid.

For the mercury barometer, the pressure is atmospheric pressure, which we'll call Patm. So we have:

Patm = ρHggh

where Hg is the density of mercury and h is the height of the mercury column.

For the unknown liquid barometer, the pressure is also atmospheric pressure, and we know that the height of the unknown liquid column is 13.6 times greater than the height of the mercury column. So we have:

Patm = ρunknownghunknown

where unknown is the density of the unknown liquid and known is the height of the unknown liquid column.

Now we can set these two equations equal to each other and solve for the unknown density:

ρHggh = ρunknownghunknown

Divide both sides by gh:

ρHg = ρunknown * 13.6

Divide both sides by 13.6:

ρunknown = (ρHg / 13.6)

The density of mercury is 13,600 kg/m³, so we can plug that in and simplify:

ρunknown = (13600 kg/m³ / 13.6)

ρunknown = 1000 kg/m³

So the density of the unknown liquid is 1000 kg/m³.

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When people become dependent on their partners and don't want to leave them, it can have a variety of negative consequences for their physical, emotional, and mental health.

Firstly, dependency can cause a loss of personal identity and self-esteem. When individuals become overly dependent on their partners, they may begin to define themselves solely in terms of their relationship. This can lead to a loss of personal identity and a decrease in self-esteem, as they feel that they cannot function independently.

Secondly, dependency can create a power imbalance in the relationship. The partner who is more dependent may feel that they have to do whatever it takes to keep their partner happy and maintain the relationship. This can lead to a sense of powerlessness and a lack of control over their own lives, which can be damaging to their mental health.

Thirdly, dependency can cause individuals to tolerate unhealthy or abusive behaviors from their partner. When individuals become too dependent on their partners, they may fear losing them and therefore tolerate behaviors that are unhealthy or even abusive. This can have serious negative consequences for their physical and mental health, as well as their overall well-being.

Finally, dependency can make it difficult to leave an unhealthy relationship. Individuals who are overly dependent on their partners may fear being alone, and may feel that they cannot function without their partner. This can make it difficult to leave an unhealthy or abusive relationship, even when it is necessary for their well-being.

Overall, becoming overly dependent on a partner can have serious negative consequences for an individual's physical, emotional, and mental health. It is important for individuals to maintain a sense of personal identity and independence, and to recognize when a relationship is unhealthy or abusive, so that they can take steps to protect their well-being.

Answer:

The main difference between organ and organelle is that organ is a large part of an organism, composed of tissues which perform similar functions whereas organelle is a specialized structure found inside cells, which carries out a specific life process. Organelles form cells.

Explanation:

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Life forms can only operate effectively if their structure matches the function they are to perform. Cells have various organelles that function differently from one another to keep the cell active.

An organelle is a subcellular structure that, like an organ, has one or more specific jobs to do in the cell.

The nuclei, which store genetic information, mitochondria, which produce chemical energy, and ribosomes, which assemble proteins, are among the more important cell organelles.

They are involved in a variety of processes, including energy production, protein and secretion formation, toxin elimination, and response to external signals.

Cellular organelles' structure is related to their function. The cristae of mitochondria for example increase the surface area available for respiration in the organelle maximizing energy production.

Thus, this can be taken as the difference between an organelle's structure and its function.

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Answer:

276.12 pC

Explanation:

We are given that

Area,A=\(2.6 cm^2=2.6\times 10^{-4}m^2\)

Where \(1 cm^2=10^{-4} m^2\)

\(d=0.25 mm=0.25\times 10^{-3} m\)

\(1mm=10^{-3} m\)

Potential difference, V=30  V

We have to find the charge on the capacitor when the plates are pulled to a separation of 0.55 mm.

We know that

Charge ,\(Q=\frac{\epsilon_0 A V}{d}\)

Where \(\epsilon_0=8.85\times 10^{-12}\)

Using the formula

\(Q=\frac{8.85\times 10^{-12}\times 2.6\times 10^{-4}\times 30}{0.25\times 10^{-3}}\)

\(Q=2.7612\times 10^{-10} C\)

\(Q=276.12p C\)

\(1 pC=10^{-12} C\)

When the plates are now pulled to a separation of 0.55 mm.Then, the charge on the plates remain same because the  battery has been disconnected.

Therefore, charge on the capacitor=276.12 pC

For the first 6 kg block, the speed after the collision will be 2.5 m/s. For the second 6 kg block, the speed after the collision will be zero since it sticks to the first 6 kg block.

Speed is a measure of how quickly an object moves or how quickly a task is performed. It is usually measured in units of distance per unit of time, such as metres per second, miles per hour, or kilometres per hour. Speed is an important concept in physics and is used to describe motion of all kinds, from elementary particles to everyday objects such as cars, planes, and rockets.

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To show an object's direction and location, motion maps are employed. The motion map provides the following information about the object's position and speed: With a high velocity, the object begins to travel away from the origin.

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Answer:

Hooking up the bulb to the battery in a series arrangement will draw the least amount of current.

Explanation:

In this case now, the bulb will serve as the load on the battery (resistance).

For the current to last longer, the least amount of energy must be drawn.

The least amount of energy will be drawn when the arrangement provides the maximum resistance possible.

Let us take the resistance of each bulb as 'R'

If we arrange the bulbs in series, then, the total resistance will be

Rt = R + R = 2R

at a EMF of V from the battery, current I through the battery will be

I = V/2R

If we arrange the bulbs in parallel, then , the total resistance will be

1/Rt = 1/R + 1/R

1/Rt = 2/R

therefore

Rt = R/2

at an EMF of V from the battery, the current I that will be drawn through the battery will be

I = 2V/R

we see that arranging the bulbs in parallel draws 4 times the current compared to arranging the bulb in series

From the above, we see that arranging the bulbs in series provides the maximum resistance, which means a lesser amount of current is drawn from the battery

Thus, the statement 'the buoyant force on the block exerted by the water is equal to the weight of the volume of water displaced by the block' is correct.

In the figure, (FB)block is buoyant force on block, (FB)steel is buoyant force on steel object, Wsteel is weight of the steel object, Wblock is weight of the steel block, and 7 is tension in the string. is

Weight of an object acts always in downwards.

Buoyant force on an object which is placed in a fluid is always upward direction. When the buoyant force is equal to the weight of the object, then the object floats in the fluid.

From the Archimedes principle, the buoyant force exerted by a fluid on an object which is placed in it is equal to the weight of the fluid displaced by the object.

Thus, the statement 'the buoyant force on the block exerted by the water is equal to the weight of the volume of water displaced by the block' is correct.

When the block is floating, the buoyance force supported by the water is equal to the total weight of the block and steel object. Thus, the statement the buoyant force on the block is equal to its weight is not correct.

As the steel object is at rest in the water, then the net force acting on it is zero.

(F ret )steel  =0

T+(F B ) steel -W steel =0 W steel =T+(F B ) steel

Therefore,

T<W steel

Thus, the statement tension in the string is less than weight of the steel object is correct.

If the weight of the steel object is equal to the buoyant force, then the tension in the string should be zero. But the steel object is hanging with the string, so tension never is zero.

Thus, the statement 'the buoyant force on the steel object is equal to its weight' is not correct.

If the tension in the string is equal to the weight of the steel object, then the buoyant force on the steel object should be zero. But any object in a fluid should experiences the buoyant force.

Thus, the statement 'the tension in the string is equal to the weight of the steel object' is not correct.

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

Asexual reproduction requires less energy and will produce more offspring over time

Explanation:

Answer:

rapid mode of multiplication

Explanation:

in asexual reproduction they reproduce faster

The effort distance of a lever should be increased to lift a heavier load because it provides a mechanical advantage, allowing for easier lifting of the load.

The effort distance of a lever should be increased to lift a heavier load because it allows for a mechanical advantage that compensates for the increased weight.

In a lever system, the effort distance is the distance between the point of application of the input force (effort) and the fulcrum, while the load distance is the distance between the point of application of the output force (load) and the fulcrum. The mechanical advantage of a lever is determined by the ratio of the load distance to the effort distance.

By increasing the effort distance, the mechanical advantage of the lever system is increased. This means that for the same input force (effort), a greater output force (load) can be achieved. When dealing with a heavier load, a higher mechanical advantage is required to overcome the increased resistance.

By increasing the effort distance, the lever system can effectively multiply the applied force, making it easier to lift the heavier load. This allows for the redistribution of force and facilitates the efficient use of human effort in various applications, such as in construction, engineering, and even everyday tools like scissors and pliers.

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Answer:

a) \(s_{T} = 30\,m\), b) \(t = 5\,min\), c) \(\Delta t = 6.667\,s\), d) \(\Delta s_{R} = 33.333\,m\), e) \(t' = 11.667\,s\), f) The rabbit won the race.

Explanation:

a) As turtle moves at constant speed, its position is determined by the following formula:

\(s_{T} = v_{T}\cdot t\)

Where:

\(t\) - Time, measured in seconds.

\(v_{T}\) - Velocity of the turtle, measured in meters per second.

\(s_{T}\) - Position of the turtle, measured in meters.

Then, the position of the turtle when the rabbit starts to run is:

\(s_{T} = \left(0.5\,\frac{m}{s} \right)\cdot (60\,s)\)

\(s_{T} = 30\,m\)

The position of the turtle when the rabbit starts to run is 30 meters.

b) The time needed for the turtle to finish the race is:

\(t = \frac{s_{T}}{v_{T}}\)

\(t = \frac{150\,m}{0.5\,\frac{m}{s} }\)

\(t = 300\,s\)

\(t = 5\,min\)

The time needed for the turtle to finish the race is 5 minutes.

c) As rabbit experiments a constant acceleration until maximum velocity is reached and moves at constant speed afterwards, the time required to reach such speed is:

\(v_{R} = v_{o,R} + a_{R}\cdot \Delta t\)

Where:

\(v_{R}\) - Final velocity of the rabbit, measured in meters per second.

\(v_{o,R}\) - Initial velocity of the rabbit, measured in meters per second.

\(a_{R}\) - Acceleration of the rabbit, measured in \(\frac{m}{s^{2}}\).

\(\Delta t\) - Running time, measured in second.

\(\Delta t = \frac{v_{R}-v_{o,R}}{a_{R}}\)

\(\Delta t = \frac{10\,\frac{m}{s}-0\,\frac{m}{s}}{1.50\,\frac{m}{s^{2}} }\)

\(\Delta t = 6.667\,s\)

The time taken by the rabbit to reach maximum speed is 6.667 s.

d) On the other hand, the position reached by the rabbit when maximum speed is reached is determined by the following equation of motion:

\(v_{R}^{2} = v_{o,R}^{2} + 2\cdot a_{R}\cdot \Delta s_{R}\)

\(\Delta s_{R} = \frac{v_{R}^{2}-v_{o,R}^{2}}{2\cdot a_{R}}\)

\(\Delta s_{R} = \frac{v_{R}^{2}-v_{o,R}^{2}}{2\cdot a_{R}}\)

Where \(\Delta s_{R}\) is the travelled distance of the rabbit from rest to maximum speed.

\(\Delta s_{R} = \frac{\left(10\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(1.50\,\frac{m}{s^{2}} \right)}\)

\(\Delta s_{R} = 33.333\,m\)

The distance travelled by the rabbit from rest to maximum speed is 33.333 meters.

e) The time required for the rabbit to finish the race can be determined by the following expression:

\(t' = \frac{\Delta s_{R}}{v_{R}}\)

\(t' = \frac{150\,m-33.333\,m}{10\,\frac{m}{s} }\)

\(t' = 11.667\,s\)

The time required for the rabbit from rest to maximum speed is 11.667 seconds.

f) The animal with the lowest time wins the race. Now, each running time is determined:

Turtle:

\(t_{T} = 300\,s\)

Rabbit:

\(t_{R} = 60\,s + 6.667\,s + 11.667\,s\)

\(t_{R} = 78.334\,s\)

The rabbit won the race as \(t_{R} < t_{T}\).