Answer:
B. 16 ohms
Explanation:
The two resistors in this circuit are in series, so the equation for equivalent resistance is \(R_{eq} = R_{1}+R_{2}\) where R1 and R2 are the two resistors in the circuit.
\(R_{eq} = R_{1}+R_{2}=8.0+8.0=16.0\) Ω
Justification:
The resistors in this circuit are in series, so the equivalent resistance is found by adding the values of the two resistors.
An object has a mass of 35 kg, and it's pulled to the left by F₁ = 20.0
N, and to the right by F2= 30.0 N along the same line of action of force.
What would be the acceleration?
Force.
A force is an influence that has the power to alter an object's motion. A massed object's velocity can be changed or accelerated by a force. A force is a vector quantity since it has both magnitude and direction.
The mass of a physical body is a measure of its entire makeup. It also measures inertia, or the body's resistance to acceleration when a net force is applied. The strength of a body's gravitational pull on other bodies is also influenced by its mass. Kg is used as the fundamental mass unit.
Acceleration is the rate at which the velocity of an object modifies with respect to time. The direction of the net force acting on an object determines its acceleration.
As we know,
Force = mass x acceleration
Therefore, acceleration = force / mass
= {(35 / 30) - (35 / 20)} kgN
= 0.583 kgN towards right
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What type of Circuit do they use in a home? WHY ? (Simple circuit / Parallel circuit / Series circuit)
Answer:
Parallel Circuits
Explanation:
Loads can be operated on their own. If you had a series circuit, adding another light would dim the rest!
What is the Kinetic Energy of a 15 kg object that is moving with a velocity of 12 m/s?
What kind of situation can you think would be a benefit of reducing friction?
Answer:
Wear and tear of an object is not desirable as it reduces its life. This is more so in case of moving parts in automobiles and machinery. Therefore, efforts are made to reduce friction between moving parts. Friction between moving parts is usually reduced by introducing a substance between the moving surfaces.
Explanation:
List one benefit and one limitation of using scientific models.
Answer:
the benefit is that they can see and experiment on the model but some times the model isn't accurate resulting in immediate failure
im only 13 sorry if this is wrong i tried.
The weight of a cart with a mass of 150 kg is. _N. (Use 9.8m/s2 for the acceleration due to gravity.)
Answer: it’s 1,470 N
Explanation:
Since F=m*a then 150*9.8=1,470.
Weight of given cart is 1,470 N
Given that:
Mass of cart = 150 kg
Acceleration due to gravity = 9.8 m/s²
Find:
Weight of cart
Computation:
Weight = m × g
Weight of cart = Mass of cart × Acceleration due to gravity
Weight of cart = 150 × 9.8
Weight of cart = 1,470 N
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solar panels generate electricity using photovoltaic cells that receive sunlight. to protect these cells from moisture while allowing sunlight to pass through, engineers must design a cover for the solar panel that is
1. waterproof and transmits light.
2. very flexible and reflects lights.
3. stronger than steel and bends light.
4. cold to touch and absorbs light
Answer:
waterproof and transmits light.
Answer:
waterproof and transmits light.
Explanation:
Which of the following particle is responsible for the transfer of static charge?
A. Neutron
B. Electron
C. Proton
D. A & C
Answer:
B. Electron
Static charge is produced by electron transfer.
Explanation:
Answer A: The neutron does not possess a charge and is said to be neutral.
Answer D: Protons and neutrons never move from object to object.
Only negative charges can move freely from one object to another. The energy that comes from these charges particles is called electrical energy.
....
Hope this answer can help you.
The answer is an electron.
8. A projectile launched horizontally with a speed of 10.0 m/s hits the ground in 1.2 seconds. If the projectile
had been launched at 20 m/s in the same direction, it would have hit the ground in
a. 0.6 seconds
b. 1.2 seconds
c. (2.4 seconds
d. 4.8 seconds
Answer:a
Explanation:
A carnot engine is operated between two heat reservoirs at temperatures of 520 k and 300 k.a. If the engine receives 6.45 kJ of heat energy from the reservoir at 520 K in each cycle, how many joules per cycle does it reject to the reservoir at 300 K?b. How much mechanical work is performed by the engine during each cycle?
Now that we have the values for TH, TC, and QH, we can insert them into equation (1) to obtain QC=QH (TC/TH)=6.45kJ(300K/520K)=3.72kJ. A negative indication is proof that the heat leaves the engine.
How to solve?When provided, When the Carnot engine was operating, the hot side temperature (TH) was 520 K, while the cold side temperature (TC) was 300 K.
The heat that the engine absorbed at the hot side is provided as QH = 6.45 kJ, and we are requested to calculate the heat that was discarded at the cool reservoir, QC.
By knowing TH ,TC and QH
we can get QC
using equation 20.13 in the form
QC =−QH (TC/TH )
Now we can plug our given values for TH ,TC and QH into equation (1) to get QC
QC=−QH (TC/TH)=−6.45kJ(300K/520K )= −3.72kJ
A negative indicator indicates that the engine is losing heat.
How is the work output of a Carnot engine determined?effectiveness is WQH=1TCTH. The efficiency of a Carnot engine with a hot reservoir of boiling water and a cold reservoir of freezing cold water, for instance, will be 1(273/373)=0.27, or little over 25% of the heat energy is converted into usable work. Of course, these temperatures are in degrees Kelvin.
The Carnot efficiency formula is what?the operating fluid's maximum and minimum temperatures at full power. Construct the equations while assuming that the Carnot efficiency is 1 TC/TH. [0.75; 0; 0.5; 100; 1000 K; 500 K] P6.2.
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HELP ASAP
A. 1.09 A
B. 1.20 A
C.0.910 A
D. 0.830 A
Answer:
The answer should be: 1.20 A
Explanation:
why is a polarized filter helpful to a photographer? A. it transmits all light
Answer:
It blocks some light, but not all.
Explanation:
The point of polarization is to get the light to travel in a single plane. The light waves occur in a single plane. The direction of the vibration of the waves is the same. With two polarized filters, it is possible to block out nearly all the light.
Imagine diving 150 feet beneath the sea. You are looking for sponges, which is not very exciting, but it’s your job. Now imagine coming across the wreck of an ancient ship! That’s what happened to some divers off the island of Antikythera (an-tee-KITH-er-ah) in the Mediterranean Sea. The ship had been on the seafloor for almost 2000 years. Divers found coins, statues, musical instruments, and many other precious items in the shipwreck. The greatest treasure of all, however, was a collection of corroded metal gears. Nothing like them had ever been found before or has ever been found since. They seem to fit together in a complicated way. They are part of a machine that scientists call the Antikythera mechanism.
It took scientists many years to figure out what the mysterious machine was for. Eventually, scientists used x-rays to view the gears and other parts inside the machine. They were also able to read ancient Greek writing on some of the parts. Using this new information, scientists realized the Antikythera mechanism was built by ancient astronomers to predict patterns in the appearance of the sun, the planets that people were able to observe, and especially the Moon.
Ancient Greek astronomers had been observing the Moon and keeping track of its appearance for hundreds of years. Looking over all their observations, they noticed patterns. The astronomers assumed the same patterns that had been going on for hundreds of years would keep going into the future. They built the Antikythera mechanism to predict events in the future based on the patterns they had observed.
A user of the Antikythera mechanism could turn a dial on one side of the mechanism to choose a date and time, either in the past or in the future. The gears would spin into place, predicting the appearance and position of the Moon and other bodies at that time. The machine had pointers and other displays to show its predictions. For example, ancient astronomers knew there would be a full moon every 29 and a half days. There was a ball on the Antikythera mechanism that traced the phases of the moon. The ball was white on one side (representing the side of the moon illuminated by the sun) and black on the other (representing the dark side of the moon). As the user turned the date dial of the machine, the little moon ball would spin to show what phase the moon would be in on that date.
The Antikythera mechanism also traced patterns that took much longer to repeat. For instance, ancient astronomers knew that occasionally, on the night of a full moon, a lunar eclipse happens. During a lunar eclipse, the fully illuminated face of the full moon goes dark for a time. However, they noticed that this didn’t happen every full moon—in fact, over a year would sometimes pass between their observations of lunar eclipses. Through careful record-keeping, the ancient astronomers realized that eclipses, although rare, happened in patterns. They kept track of the patterns and recorded that knowledge in the workings of the Antikythera mechanism. As a user turned the date dial of the Antikythera mechanism, the mechanism counted the days and displayed exactly when people in Greece could expect to observe a lunar eclipse.
The mechanism showed WHEN an eclipse would happen, but it didn’t show WHY an eclipse would happen. The astronomers who made the Antikythera mechanism knew that the Moon seems to shine because it is illuminated by light from the sun. They also knew that an eclipse of the Moon happens when Earth blocks the sunlight and makes a shadow on the Moon. They did not know exactly why this happened at some times and not others.
Today astronomers can explain why lunar eclipses happen when they do. Lunar eclipses are caused by Earth blocking sunlight from reaching the Moon. For Earth to block the sunlight, it has to be between the sun and the Moon. Not only that, but the sun, Earth, and the Moon have to line up exactly, with Earth in the middle. When they line up in this way, Earth blocks the sunlight and the Moon goes dark. Eclipses only happen on the night of a full moon, because the full moon is the phase when the sun, Earth, and the Moon line up with Earth in the middle.
If this is true, why don’t lunar eclipses happen every time the Moon is full? Why did the ancient astronomers have to wait so long between observations of eclipses? It’s because the Moon’s orbit around Earth is slightly tilted out of alignment. During most full moons, the sun, Earth, and the Moon are lined up, but they are not lined up EXACTLY. For the three bodies to line up exactly, the Moon has to be exactly in the right spot on its tilted orbit. That happens very infrequently. The makers of the Antikythera mechanism knew how unusual this was, but they didn’t understand the reason—now you do!
1) Describe how it is possible for Lunar Eclipses to happen. Use evidence from the reading to explain how this happens.
2) Describe the main factor that leads to a lunar eclipse instead of a full moon.
Answer:
A lunar eclipse occurs when the Moon moves into the Earth's shadow. ... The only light reflected from the lunar surface has been refracted by Earth's atmosphere. This light appears reddish for the same reason that a sunset or sunrise does: the Rayleigh scattering of bluer light.
Lunar eclipses can only happen when the Moon is opposite the Sun in the sky, a monthly occurrence we know as a full Moon. But lunar eclipses do not occur every month because the Moon's orbit is tilted five degrees from Earth's orbit around the Sun. Without the tilt, lunar eclipses would occur every month.
Explanation:
In a 92 s interval, 562 hailstones strike a glasswindow of area 1.216 m² at an angle 64° to thewindow surface. Each hailstone has a mass of2 g and speed of 5.8 m/s.If the collisions are elastic, find the averageforce on the window.Answer in units of N.
Given that the number of hailstones is n = 562
The mass of hailstone is m = 2 g = 0.002 kg
The speed of hailstone is v = 5.8 m/s
The time taken will be t = 92 s
The angle is
\(\theta=64^{\circ}\)We have to calculate the force.
The force can be calculated by the formula
\(\begin{gathered} F=\text{ force due to one hailstone }\times numberofhailstones\text{ } \\ =m\frac{v}{t}\sin \theta\times n \end{gathered}\)Substituting the values, the force will be
\(\begin{gathered} F=\text{ }\frac{\text{0.002}\times5.8\times\sin 64^{\circ}\times562}{92} \\ =0.063\text{ N} \end{gathered}\)What is the tension in the string once the box begins to move? Express your answer to two significant figures and include the appropriate units T 48.634N X Incorrect
T=30.4N. This solution has explained Newton's Second Law, the concept of tension and the required steps have been provided to calculate the tension force.
The concept of Newton's laws of motion. What is Newton's Second Law? Newton's second law is a crucial law of motion. It helps to explain how an object accelerates when the resultant force acts on it. The law states that the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass. The acceleration of the object is given by F = ma, where F is the net force acting on the object, m is the mass of the object, and a is the acceleration of the object.
What is tension? Tension is a term used in physics and engineering to describe the force applied through a rope, cable, or wire. A tension force is exerted by a string or a rope that is pulled tight from both ends and can be calculated using the following formula: Tension force = weight of the object in the direction of the force + force required to overcome friction From the given data, Weight of the box, w = 15.3 N Force applied to move the box,
F = 30.4 NH
The force required to overcome the friction = F - w = 30.4
15.3 = 15.1 N
Since the string is pulling the box in the opposite direction to the force of friction, we need to consider the net force acting on the box.
Net force, F
net = F
force of friction = 30.4 15.1 15.3 N Using Newton's second law, we get
F net = ma
15.3 = 2.5a
Solving for a, we geta = 15.3/2.5, 6.12 m/s²
Since the tension in the string is the same as the force required to move the box, we have:
Tension force = force required to move the box = F = 30.4 N
Therefore, the tension in the string once the box begins to move is 30.4 N (to two significant figures).
The tension in the string once the box begins to move is 30.4 N.
Therefore, the correct answer is T=30.4N. This solution has explained Newton's Second Law, the concept of tension and the required steps have been provided to calculate the tension force. The calculations have been shown step-by-step to get a clear understanding of the solution.
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tell what physical property of the emitting matter can be determined by each of the 3 kinds of spectra
The three kinds of spectra can be used to determine different physical properties of the emitting matter.
Three kinds of spectrums :
1. Continuous spectrum: This type of spectrum is produced by a hot, dense matter, such as a solid or dense gas.
It displays a range of wavelengths or colors without any gaps.
The physical property that can be determined using a continuous spectrum is the temperature of the emitting matter.
analyzing the peak wavelength and the distribution of energy, you can calculate the temperature using Wien's Law.
2. Emission spectrum: This spectrum is produced by hot, low-density gas.
It displays bright, distinct lines at specific wavelengths, which correspond to the energy levels of the emitting atoms.
The physical property that can be determined using an emission spectrum is the chemical composition of the emitting matter.
Each element has a unique set of emission lines, so you can identify the elements present in the matter by comparing its emission lines to known reference spectra.
3. Absorption spectrum: This spectrum is produced when light passes through a cooler, low-density gas, and the gas absorbs specific wavelengths, leaving dark lines at those positions.
The physical property that can be determined using an absorption spectrum is the chemical composition of the absorbing matter, similar to the emission spectrum.
By comparing the absorption lines to known reference spectra, you can identify the elements present in the matter.
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What is the approximate tangential speed of an object orbiting Earth with a radius of 1.8 x 108 m and a period of 2.2
x 104 s?
O 7.7 x 10-4 m/s
O 5.1 x 10 m/s
7.7 x 104 m/s
5.1 x 105 m/s
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In the case where the period is 2.2 x 104 s, the rotational speed is given by 1 / 2.2 x 104 = 4.55 x 10-5 rad/s. Utilizing the equation v = r, we can find the tangential speed. in which the rotating speed is
The linear or tangential speed is denoted by v.
r stands for radius. The result is that v = 4.55x10-5(1.8x108), or 5.1 x 104 m/s.
A sentence's object is defined as what?To refer to the item or person that is the target of an action, we typically use the word "object." Alternatively, the recipient. In a sentence, a verb's action is transferred to a noun or pronoun as a direct object. Usually, it responds to the inquiries what or whom. relating to the verb.
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what is v^2=0.05-4.9 please i need this asap
Answer:
v =2.02
Explanation:
v^2=0.05-4.9
v^2=-4.85
square root both side
v=2.02
^^^^this is a not a perfect square
A volume current density is given in cylindrical coordinates by NP) up ſ(p) = 10 2 (A/m) Find H everywhere, using the integral form of Ampere's Law
H everywhere is 20π p A/m in the azimuthal direction, where p is the radial coordinate in cylindrical coordinates.
The integral form of Ampere's Law relates the magnetic field H to the current passing through a closed loop. In cylindrical coordinates, the current density is given by J(r, θ, z) = N·P(r)·uϕ(θ), where N is the number of turns per unit length, P(r) is the volume current density, and uϕ(θ) is the unit vector in the azimuthal direction.
To find H everywhere, we consider a closed loop in the azimuthal direction (ϕ) at a fixed radial distance p. Along this loop, the length element dl is in the azimuthal direction, and the magnetic field H is also in the azimuthal direction.
Applying Ampere's Law, the integral of H·dl over the closed loop equals μ0 times the total current enclosed by the loop. Since the current is uniform and flowing in the azimuthal direction, the total current enclosed is J·2πp, where J is the volume current density and 2πp is the path length along the loop at radial distance p.
Setting up the integral and solving, we have:
H·2πp = μ0·J·2πp
H = μ0·J = μ0·N·P(r) = 20πp A/m.
Therefore, H everywhere in the azimuthal direction is given by H = 20πp A/m.
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Most electromagnets have a core?
A) Why is iron usually used for the core
B) What would happen if you used steel instead
Iron has strong ferromagnetic properties and that is why it is used as core in electromagnets. However, iron can easily be demagnetized but steel cannot. Steel forms permanent magnet.
What is an electromagnet ?An electromagnet is a material which can form a magnetic field in the presence of an electric field. The magnetic field strength depends on the nature of the material as well the strength of the electric field.
Iron is a metal exhibiting strong ferromagnetic properties. The magnetic field lines can align along the applied field and it can be lost when the applied field is removed.
Therefore, iron can be demagnetized when the switch is off. If we use steel instead it would be very difficult to demagnetize and will form a permanent magnet.
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A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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On an air hockey table, when the table is on, pucks glide freely when hit. When the table is off, pucks do not travel as far when hit. Explain in as much detail as you can why this occurs and what allows this to occur, using Newton’s 1st Law.
Answer:
On an air hockey table, when the table is on, pucks glide freely when hit. When the table is off, pucks do not travel as far when hit. Explain in as much detail as you can why this occurs and what allows this to occur, using Newton’s 1st Law.
Newton's 1st Law, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will remain in motion with a constant velocity unless acted upon by an unbalanced force.
In the case of an air hockey table, the air flow created by the table's motor serves as the unbalanced force that affects the movement of the puck. When the table is on, the motor creates a cushion of air that flows across the surface of the table, allowing the puck to glide freely with little resistance. This air flow reduces the friction between the puck and the table, allowing the puck to travel farther when hit.
However, when the table is turned off, there is no longer a cushion of air to reduce friction between the puck and the table. This increased friction slows down the puck more quickly, causing it to travel a shorter distance when hit. The puck is also more likely to come to a complete stop when it reaches the edges of the table, as the lack of air flow makes it more difficult for the puck to bounce off the table's walls.
In summary, the air flow created by the motor on an air hockey table serves as an unbalanced force that reduces friction and allows the puck to travel farther. Without this air flow, the increased friction between the puck and the table causes the puck to slow down more quickly, resulting in shorter travel distances and a higher likelihood of coming to a complete stop.
before pushing down the piston, the pressure of the gas is 1.0 x 105 pa.pushinbg the piston reduces the volume of the gas from 500cm3 to 240cm3. calculate the final pressure of the gas
The final pressure of the gas is p2 = 2.085 * 10^5 pa.
Boyle's law is a gas law that states that the pressure exerted by a gas (of a given mass at a constant temperature) is inversely proportional to the volume it occupies. That is, if the temperature and quantity of gas are constant, the pressure and volume of the gas are inversely proportional.
Boyle's Law states that a change in the volume occupied by a gas (at a constant amount and temperature) leads to a change in the pressure exerted by the gas. The following mathematical formulation of this law is possible:
P1V1 = P2V2
Given,
Initial Volume, v1 = 500 cm3
Final Volume, v2 = 240 cm3
Initial Pressure, p1 = 1.0 * 10^5 pa
Final Pressure, p2
We know that,
p1 v1 = p2 v2
1.0 * 10^5 * 500 = p2 * 240
p2 = 2.085 * 10^5 pa
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which best describes what happens with the sonar to sound pulses from a ship after they hit the ocean floor?
Answer:
With sonar, what happens to sound pulses from a ship after they hit the ocean floor? ... They bounce back to the ship.
Explanation:
Which of these neutron stars must have had its angular momentum changed by a binary companion? (a) a pulsar that pulses 30 times per second (b) a pulsar that pulses 600 times per second (c) a neutron star that does not pulse at all.
The neutron star that pulses 600 times per second must have had its angular momentum changed by a binary companion.
Neutron stars that pulse are known as pulsars and their pulses are caused by their rotation. The rate of pulsation is directly related to the neutron star's angular momentum. A pulsar that pulses faster must have a smaller radius and higher angular velocity than a pulsar that pulses slower.
Therefore, a pulsar that pulses 600 times per second must have a very small radius and high angular velocity, which can only be achieved by a change in its angular momentum. The most likely cause of this change in angular momentum is a binary companion transferring angular momentum to the pulsar.
In conclusion, a neutron star that pulses 600 times per second is the one that must have had its angular momentum changed by a binary companion.
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two identical cars are moving straight down a highway under identical conditions, except car b is moving 5 times as fast as car a. how many times more work is needed to stop car b
Car B is moving 5 times as fast as car A, its kinetic energy will be 25 times greater. Therefore, to stop car B, 25 times more work would be needed compared to stopping car A.
The kinetic energy of an object is given by the formula:
KE = (1/2)mv^²,
where m is the mass of the object and v is its velocity.
Let's consider car A's velocity as v, and car B's velocity as 5v.
The kinetic energy of car A is KE_A
= (1/2)m(v^²)
The kinetic energy of car B is KE_B
= (1/2)m((5v)^²)
= 25(1/2)mv^²
= 25KE_A.
As we can see, car B has 25 times more kinetic energy than car A.
Since the work required to stop an object is directly proportional to its kinetic energy, it follows that stopping car B would require 25 times more work compared to stopping car A.
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A scientific theory is a hypothesis supported by many experiments
True or False
Answer:
I believe it is True... I hope it is correct :)
Explanation:
Answer : False
Explanation :
What is the momentum of a 35.0 kg cannonball fired from a cannon with a velocity of 500.0 m/s?
Answer:
p = 17500 kg*m/s
Explanation:
p = mv
p = 35.0 kg * 500.0 m/s = 17500 kg*m/s
The momentum of a 35.0 kg cannonball fired from a cannon with a velocity of 500.0 m/s will be equal to 17500 \(\dfrac{kg.m}{s}\)
What is momentum ?
When any body which is having a mass and is in the motion carry momentum with it.
The formula for finding the momentum of any body is given by
\(Momentum = Mass\times Velocity\)
Given that-
\(Mass = 35 kg\)
\(Velocity = 500\) \(\dfrac{m}{s}\)
\(Momentum = 35\times500\)
\(momentum= 17500 \dfrac{kg.m}{s}\)
Hence The momentum of a 35.0 kg cannonball fired from a cannon with a velocity of 500.0 m/s will be equal to 17500 \(\dfrac{kg.m}{s}\)
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A wave has a frequency of 34 Hz and a wavelength of 2.0 m. What is the
speed of the wave? Use V= fx.
A. 17 m/s
B. 68 m/s
C. 0.059 m/s
D. 36 m/s
Answer:
v=FX
v=34(2.0)
v=68m/s
A rocket's orbital maneuver requires a speed increase of 1.05 ✕ 103 m/s. If its engine has an exhaust speed of 2.25 ✕ 103 m/s, determine the required ratio
Mi/Mf of its initial mass to its final mass. (The difference Mi − Mf equals the mass of the ejected fuel.)
The ratio of the rocket's initial mass to final mass is 1.595
How to find the ratio of the rocket's initial mass to is final mass?Usng the rocket formula, for change in speed
Δv = v㏑(Mi/Mf) where
v = speed of exhaust, Mi = initial mass and Mf = final massGiven that a rocket's orbital maneuver requires a speed increase of 1.05 × 10³ m/s. If its engine has an exhaust speed of 2.25 × 10³ m/s,
So,
Δv = 1.05 × 10³ m/s and v = 2.25 × 10³ m/sMaking (Mi/Mf) subject of the formula, we have
(Mi/Mf) = exp(Δv/v)
So, substituting these into the equation for the rocket speed, we have
(Mi/Mf) = exp(Δv/v)
(Mi/Mf) = exp(1.05 × 10³ m/s/2.25 × 10³ m/s)
(Mi/Mf) = exp(0.467)
(Mi/Mf) = 1.595
So, the ratio of the rocket's initial mass to final mass is 1.595
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