Rebecca's family uses their house's heating system to stay warm in the winter. How do they know when their system is at equilibrium?A. The house temperature balances the set temperature and the system shuts off.B. The house temperature is changing and the system is rapidly changing from on to off then back again.C. The house temperature is lower than the set temperature and heat is on.D. The house temperature is higher than the set temperature and the cooling is on.

Therefore, the power of the porter is 441,450 J/s, or approximately 441.5 watts.

The work done by the porter in lifting the 50 kg bag up the stairs can be calculated as the product of the force applied and the distance moved.

The force applied is the weight of the bag, which is given by:

F = m * g

where m is the mass of the bag and g is the acceleration due to gravity, which is approximately 9.81 m/s². Substituting the given values, we get:

F = 50 kg * 9.81 m/s²

F = 490.5 N

The distance moved by the porter in lifting the bag up one staircase is 30 cm, and the porter climbs 10 staircases in 10 seconds, which gives a speed of:

v = (10 * 30 cm) / 10 s

v = 30 cm/s

The power of the porter is the rate at which work is done, which can be calculated as:

P = W / t

where W is the work done and t is the time taken. Substituting the values, we get:

P = F * d * v / t

P = 490.5 N * 10 * 30 cm * 30 cm/s / 10 s

P = 441,450 J/s

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Answer:

Explanation:

Given

final speed v = 30.0m/s

initial velocity u = 0m/s

Time taken t = 1.00s

Required

constant acceleration of the police car a

Substitute the given parameters into this equation of motion

v = u + at

30 = 0 +1a

30 = a

a = 30.0m/s²

Hence the magnitude of the constant acceleration of the police car is 30.0m/s²

The efficiency of motor is 90.58%.To determine the efficiency of the motor, we need to calculate the input power and the output power, and then divide the output power by the input power

The input power can be calculated using the formula:

Input Power = Voltage × Current

Given that the voltage is 230 V and the current is 24 A, we have:

Input Power = 230 V × 24 A

Input Power = 5520 W (or 5.52 kW)

The output power of the motor is given as 5 kW (since it is a 5 kW motor).

Now, we can calculate the efficiency:

Efficiency = (Output Power / Input Power) × 100%

Efficiency = (5 kW / 5.52 kW) × 100%

Efficiency ≈ 90.58%

Therefore, the efficiency of this motor is approximately 90.58%.

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Answer:

I think it's B, I may not be right so take this with a grain of salt

Explanation:

At the maximum height the particles position has been shown as \(\frac{R}{3}\).

The given parameters;

The velocity of the particle is given as;

\(v^2 = \frac{GM}{2R}\)

The total mechanical energy of the particle is given as;

\(-\frac{GMm}{R} + \frac{1}{2} mv^2 = - \frac{GMm}{R} + \frac{1}{2} mv^2\)

At maximum height the final velocity of the particle is zero.

\(-\frac{GMm}{R} + \frac{1}{2} mv^2 = - \frac{GMm}{R +h}\)

\(-\frac{GMm}{R} + \frac{1}{2} m\times \frac{GM}{2R} = - \frac{GMm}{R +h}\\\\-\frac{GMm}{R} + \frac{GMm}{4R} = - \frac{GMm}{R +h}\\\\- \frac{3GMm}{4R} = - \frac{GMm}{R +h}\\\\- \frac{3}{4R} = - \frac{1}{R+ h} \\\\3(R+ h) = 4R\\\\3R + 3h = 4R\\\\3h = 4R - 3R\\\\3h = R\\\\h = \frac{R}{3}\)

Thus, at the maximum height the particles position has been shown as \(\frac{R}{3}\).

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Answer:

460.52 s

Explanation:

Since the instantaneous rate of change of the voltage is proportional to the voltage in the condenser, we have that

dV/dt ∝ V

dV/dt = kV

separating the variables, we have

dV/V = kdt

integrating both sides, we have

∫dV/V = ∫kdt

㏑(V/V₀) = kt

V/V₀ = \(e^{kt}\)

Since the instantaneous rate of change of the voltage is -0.01 of the voltage dV/dt = -0.01V

Since dV/dt = kV

-0.01V = kV

k = -0.01

So, V/V₀ = \(e^{-0.01t}\)

V = V₀\(e^{-0.01t}\)

Given that the voltage decreases by 90 %, we have that the remaining voltage (100 % - 90%)V₀ = 10%V₀ = 0.1V₀

So, V = 0.1V₀

Thus

V = V₀\(e^{-0.01t}\)

0.1V₀ = V₀\(e^{-0.01t}\)

0.1V₀/V₀ = \(e^{-0.01t}\)

0.1 = \(e^{-0.01t}\)

to find the time, t it takes the voltage to decrease by 90%, we taking natural logarithm of both sides, we have

㏑(0.01) = -0.01t

So, t = ㏑(0.01)/-0.01

t = -4.6052/-0.01

t = 460.52 s

The force between these charges, according to Coulomb's law would be -54 N.

We can solve this problem applying "Coulomb's Law" which states-

\(\qquad\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ \)

\( \qquad\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)

Where-

According to the given parameters -

Now that required values are given, so we can plug the values into the formula and solve for Force -

\(\qquad\qquad \:\sf\underline{Force = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ \)

\( \longrightarrow \sf Force = 9\times 10^9 \times \dfrac{ 3\times 10^{-6}\times -5 \times 10^{-6}}{\bigg(5\times 10^{-2}\bigg)^2}\\ \)

\( \longrightarrow \sf Force = -\dfrac{9\times 5\times 3\times 10^{9} \times 10^{-12}}{25\times 10^{-4}}\\ \)

\( \qquad\longrightarrow \sf Force =- \dfrac{135 \times 10^{9-12+4}}{25}\\ \)

\( \qquad\longrightarrow \sf Force = - \dfrac{\cancel{135}}{\cancel{25}}\times 10\\ \)

\( \qquad\longrightarrow \sf Force = -5.4 \times 10\\ \)

\( \qquad\qquad\longrightarrow \sf \underline{Force = \boxed{\sf{-54 N}}} \\ \)

Explanation:

The answer is B: 1250. Hope this helps.

Answer:

Answer:  12

1 mole of H2O contains  1 mole of H and 2 moles of O

That means that are 3 molecules in 1 mole of H2O

Answer:

Heating it

Explanation:

Helps the salt dissolve faster and is more effective when heated up :)

The answer is A. by heating it

Answer:

Explanation:

From the given information:

Distance \(d_i = 4.8 \times 10^{10} \ m\)

Speed of the comet \(V_i = 9.1 \times 10^{4} \ m/s\)

At distance \(d_2 = 6 \times 10^{12} \ m\)

where;

mass of the sun = \(1.98 \times 10^{30}\)

\(G = 6.67 \times 10^{-11}\)

To find the speed \(V_f\):

Using the formula:

\(E_f = E_i + W \\ \\ where; \ \ W = 0 \ \ \text{since work done by surrounding is zero (0)}\)

\(E_f = E_i + 0 \\ \\ K_f + U_f = K_i + U_i \\ \\ = \dfrac{1}{2}mV_f^2 + \dfrac{-GMm}{d^2} = \dfrac{1}{2}mV_i^2+ \dfrac{-GMm}{d_i} \\ \\ V_f = \sqrt{V_i^2 + 2 GM \Big [ \dfrac{1}{d_2}- \dfrac{1}{d_i}\Big ]}\)

\(V_f = \sqrt{(9.1 \times 10^{4})^2 + 2 (6.67\times 10^{-11}) *(1.98 * 10^{30} ) \Big [ \dfrac{1}{6*10^{12}}- \dfrac{1}{4.8*10^{10}}\Big ]}\)

\(\mathbf{V_f =53.125 \times 10^4 \ m/s}\)

Answer:

Attitude, motivation and determination

Explanation:

Let me know if I'm right.

The factors leading to the success through the challenging physical activities are Attitude, motivation and determination.

Although the information regarding the live session is not mentioned, but as a general point of view, the major factors that need to considered while undergoing through the challenging physical activities are as follows:

Thus, we can conclude that the factors leading to the success through the challenging physical activities are Attitude, motivation and determination.

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If the force provided by the engine of a toy car decreases, the car will slow down and eventually come to a stop.

1. The force provided by the engine of a toy car is responsible for propelling it forward at a constant speed. This force overcomes any friction or resistance acting on the car.

2. When the force provided by the engine decreases, there is a reduction in the overall force acting on the car. As a result, the force can no longer counteract the resistance and friction effectively.

3. The resistance and friction acting on the toy car, such as air resistance and the friction between the wheels and the surface, start to have a greater impact on the car's motion.

4. With a reduced force from the engine, the car begins to slow down gradually. The deceleration occurs because the opposing forces now have a greater influence on the car's motion.

5. As the force continues to decrease, the opposing forces eventually surpass the remaining force from the engine. Consequently, the toy car slows down even more and eventually comes to a complete stop.

6. If the force provided by the engine becomes extremely low or nonexistent, the opposing forces will completely overpower the forward force, causing the toy car to stop moving altogether.

In summary, when the force provided by the engine of a toy car decreases, the car's speed decreases, and it eventually comes to a stop due to the increased influence of opposing forces.

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Answer:

a

Explanation:

Iced tea is a mixture because it contains different compounds, such as tea leaves and water.

A glass of iced tea is considered a mixture. A mixture is a combination of two or more substances that are physically combined and can be separated through physical means. The correct option is option (A).

A mixture is a combination of two or more substances that are physically combined and can be separated through physical means, such as filtration or evaporation. In the case of iced tea, it is typically made by dissolving tea leaves or instant tea powder in water, adding sweeteners, and possibly other ingredients such as lemon juice or ice cubes.

These components can be separated and exist individually. Therefore, the correct answer is (A) -  A mixture

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1. The electric field pattern due to charged sphere A can be represented by lines radiating outward from the sphere.

2. The magnitude of the charge on sphere A is approximately 0.0833 Coulombs.

3. The electrostatic force experienced by sphere B when placed at point P is approximately 2.675 x 10^-4 Newtons.

1. These lines should be evenly spaced and symmetric around the sphere, indicating a radial field pattern. Since the electric field at point P is directed towards sphere A, the field lines should point inward towards the sphere. Thus, the electric field pattern would resemble a series of concentric circles with lines converging towards the center of sphere A.

2. To calculate the magnitude of the charge on sphere A, we can use the formula for the electric field strength (E) due to a point charge:

E = k * (Q / r^2)

where k is the electrostatic constant (approximately 9 x 10^9 N m^2/C^2), Q is the charge on the sphere, and r is the distance from the sphere to the point P.

From the given information, we have E = 3 x 10^7 N/C and r = 0.5 m. Plugging these values into the formula and solving for Q:

3 x 10^7 N/C = (9 x 10^9 N m^2/C^2) * (Q / (0.5 m)^2)

Simplifying the equation, we find:

Q = (3 x 10^7 N/C) * (0.5 m)^2 / (9 x 10^9 N m^2/C^2)

Q ≈ 0.0833 C (Coulombs)

Therefore, the magnitude of the charge on sphere A is approximately 0.0833 Coulombs.

3. When sphere E, which has an excess of 105 electrons, is placed at point P, it will experience an electrostatic force due to the interaction with sphere A. The electrostatic force between two charges can be calculated using Coulomb's law:

F = k * (|q1| * |q2|) / r^2

where k is the electrostatic constant, q1 and q2 are the charges on the spheres, and r is the distance between them.

Since each electron carries a charge of approximately -1.6 x 10^-19 C, the excess charge on sphere E is:

q2 = 105 electrons * (-1.6 x 10^-19 C/electron)

Plugging in the values and the given distance of 0.5 m, we have:

F = (9 x 10^9 N m^2/C^2) * (|0.0833 C| * |-1.6 x 10^-19 C|) / (0.5 m)^2

Simplifying the equation, we find:

F ≈ 2.675 x 10^-4 N (Newtons)

Therefore, the electrostatic force experienced by sphere E when placed at point P is approximately 2.675 x 10^-4 Newtons.

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Direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

Given:

Apparent power (S) = 10 KVA = 10,000 VA

Line voltage (V) = 380 V

Frequency (f) = 50 Hz

Xd = 12 ohms

Xq = 8 ohms

Ra = 1 ohm

Power factor (pf) = 0.8 lagging

Load angle (δ) = 16.15 degrees

(i) Armature current's direct axis and quadrature axis components

We know that the apparent power is given by S = 3VLILcos(φ), where VL is the line voltage, IL is the line current, and φ is the angle between them. For a star-connected alternator, line voltage is equal to phase voltage, so we can write:

S = 3Vphase Iphase cos(φ)

Iphase = S / (3Vphase cos(φ))

For a lagging power factor, cos(φ) = 0.8, so

Iphase = 10,000 / (3 x 380 x 0.8) = 10.46 A

The direct axis component (Id) and the quadrature axis component (Iq) make up the armature current.  Using the given values of Xd, Xq, and Ra, we can calculate these components as follows:

Id = (VL - IaRa) / Xd

Iq = (VL - IaRa) / Xq

where Ia is the magnitude of the armature current, which is equal to the magnitude of the line current divided by √3. Thus,

Ia = Iphase / √3 = 10.46 / √3 = 6.03 A

Substituting the given values:

Id = (380 - 6.03 x 1) / 12 = 30.28 A

Iq = (380 - 6.03 x 1) / 8 = 46.92 A

(ii) Excitation voltage of the generator:

The excitation voltage (E) of the generator is given by:

E = Vphase + IqXq

Substituting the given values:

E = 380 + 46.92 x 8 = 765.36 V

Therefore, the direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

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Answer: My bad bro. Just tryna get me some points g

Explanation: tuff

Answer:

Explanation:

D=s*t

D=(20)(45)

D=900m.

hope it helps

Answer:

The  displacement is  \(A_r = 6.071 \ cm\)

Explanation:

From the question we are told that

   The initial displacement is \(A_o = 10 \ cm\)

     The displacement at the end of first oscillation is  \(A_d = 9.05 \ cm\)

Generally the damping constant of this damped oscillator is mathematically represented as  

           \(\eta = \frac{A_d}{A_o}\)

substituting values

           \(\eta = \frac{9.05}{10}\)

        \(\eta = 0.905\)

The displacement after 4 more oscillation is mathematically represented as

       \(A_r = \eta^4 * A_d\)

substituting values

      \(A_r = (0.905)^4 * (9.05)\)

      \(A_r = 6.071 \ cm\)

Answer:

Displacement reached is 6.0708 cm

Explanation:

Formula for damping Constant "C"

\(C^n=\frac{A_2}{A_1}\)                  where n=1,2,3,........n

Where:

\(A_2\) is the displacement after first oscillation    

\(A_1\\\) is the initial Displacement

\(A_1=10\ cm\\A_2=9.05\ cm\\\)

In our case, n=1.

\(C=\frac{9.05}{10}\\C=0.905\)

After 4 more oscillation, n=4:

\(C^4=\frac{A_6}{A_2}\)                                        

Where:

\(A_6\) is the final Displacement after 4 more oscillations.

\(A_6=(0.905)^4*(9.05)\\A_6=6.0708\ cm\)

Displacement reached is 6.0708 cm

Series, Parallel, and  mixed Series-Parallel  are the 3 types of electrical circuits.

An electric circuit is a path that current can go. An electric circuit is made up of a battery or generator, a device that feeds the charged particles that make up the current with energy, a device that utilizes the current, such as a light, an electric motor, or a computer, and the connecting wires or transmission lines. Two essential principles that quantitatively define how electric circuits work are Kirchhoff's rules and Ohm's law.

Circuits in parallel and series. Electric circuits can be divided into several groups. Only direct current flows in a circuit in one direction. An alternating-current circuit transfers electricity that pulses back and forth frequently every second, like in the majority of domestic circuits. (For a more detailed description of direct- and alternating-current circuits, see electricity. Direct electric current and electricity

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Answer:

AYE

Explanation:

Answer:

5.48 m/s.

Explanation:

Use the formula a=v^2/r.

Answer:

25 m

Explanation:

Let's assume that its acceleration is constant. We can determine the acceleration of the object by its definition

\(a= \frac{\Delta v}{\Delta t} = \frac{10-0(\frac ms)}{5 s} = 2 \frac m{s^2}\)

Now we can write the equation of motion

\(s(t)= s_0 + v_0t + \frac12at^2\)

where, the two terms \(s_0\ v_0\) represent the initial position and velocity respectively. Replacing the values we have ("from rest" means that initial velocity is 0)

\(s(5) = 0+0(5)+\frac12 2 (5)^2 = 25 m\)

Answer:

Osmosis will happen, after 24 hours, the egg will be plump.

Explanation:

Answer:

142 dB

Explanation:

The separation distance in B is a number times greater than in A, then the force of attraction in B is less than A.

The force of attraction between two charged object is determined by applying Coulomb's law.

Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.

Mathematically, this law is written as;

F = Kq₁q₂/r²

where;

From the formula given above, as the distance of separation increases, the magnitude of the force of attraction between the charges decreases. Also, as the distance of separation between the charges decreases, the magnitude of the force of attraction between the charges increases.

Thus, the magnitude of the force of attraction between charged objects is a function of the magnitude of the charges and distance of separation between the charges.

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Answer:

Economics definition, the science that deals with the production, distribution, and consumption of goods and services, or the material welfare of humankind.

The ship's velocity after a half minute (in m/s) is 170 m/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The final velocity can be obtained as illustrated below:

5 = (v – 20) / 30

Cross multiply

v – 20 = 5 × 30

v – 20 = 150

Collect like terms

v = 150 + 20

v = 170 m/s

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