Recall that impulse = momentum (FAt = Ap and that Ap is just mx v). How long (time) must a group of people pull with a force of 600N on a stalled 1500kg car to give it a velocity of 1.5m/s? Report your answer to the nearest hundredth (X.XX)​

Answer:

The temperature when the resistance is 9.61 ohms is -17.3°C. The resistance of the wire when the temperature is 45°C is 11.45 ohms.

Explanation:

Answer:

Explanation:

m

forces: forces applied to an object in opposite directions that are not equal in size. Unbalanced forces result in a change in motion. friction: the force that opposes the motion or tendency toward motion of two objects that are in contact.

Answer:

the answer is a....,.......

Answer:

Part 1:

Option B is correct (It will remain unchanged).

Part 2:

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Option E is correct (It will be half as fast/long.)

Part 4:

Option C is correct (It will increase by a factor of √ 2.)

Explanation:

Formula we are going to use:

V=f*λ

Where:

V is the speed of Sound

f is the frequency of wave

λ is the wavelength.

The speed of wave , tension and linear density have following relation:

\(V=\sqrt{F/\rho}\)

Where:

V is the speed of Sound (Initial)

F is the tension in string (Initial)

\(\rho\) is the linear density of string (Constant)

Terms:

V' is the new speed

f' is the new frequency

λ' is the wavelength

Solution:

Part 1:

From \(V=\sqrt{F/\rho}\):

Speed of Sound is independent of the frequency of shaking so speed well remain unchanged.

Option B is correct (It will remain unchanged)

Part 2:

If F'=2F then

\(V=\sqrt{F/\rho}\)

\(V'=\sqrt{F'/\rho}\\V'=\sqrt{2F/\rho}\\V'= \sqrt{2} * \sqrt{F/\rho}\\V'=\sqrt{2}V\)

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Formula we are going to use:

V=f*λ

Given f'=2f,

Even though frequency is doubled we will keep velocities same. V=V' in order to find the changing wavelength.

V'=f'*λ'

f*λ=f'*λ'

f*λ=2f*λ'

Solving above Equation:

λ'=λ/2

Option E is correct (It will be half as fast/long.)

Part 4:

T'=2T means \(V'=\sqrt{2}V\) (From Part 1)

f'=f

Now:

V'=f'*λ'

\(\sqrt{2}f*\lambda=f'*\lambda '\\\sqrt{2}f*\lambda=f*\lambda '\\ \lambda '=\sqrt{2}*\lambda\)

Option C is correct (It will increase by a factor of √ 2.)

Answer:

Some of the copper wire needs to be exposed so that the battery can make a good electrical connection. ... You need to do this because the direction of a magnet field depends on the direction of the electric current creating it. The movement of electric charges creates a magnetic field.

Explanation:

In an electromagnet, it must the wire be connected to the battery for the magnet to work the current is flowing through into the wire once it is introduced.

The magnetic field is defined as the field the magnetic materials generate or when an electric charge moves in a field region that generates the magnetic field.

As we know, the electricity is often used to generate a magnetic field in electromagnets.

The current is flowing through into the wire once it is introduced, from either a battery or maybe another source of electricity. The looped wire is magnetized as if it were a magnetic material as a function of the magnetic field created around it.

Thus, in an electromagnet, it must the wire be connected to the battery for the magnet to work the current is flowing through into the wire once it is introduced.

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Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

THIS LAW IS TRUE AS IT ALSO HAVE A REAL LIFE EXAMPLE.

Examples of Newton's 1st Law : If you slide a hockey puck on ice, eventually it will stop, because of friction on the ice. It will also stop if it hits something, like a player's stick or a goalpost.

(a) The magnitude of the angular momentum of the system is 5,252 kg m²/s.

(b) The rotational energy of the system is 2,826 J.

(c) The new moment of inertia is 31.25 Kgm².

(d) The new speed of each astronaut is 420.15 m/s.

(e) The new rotational energy of the system is 65.82 kJ.

(f) The work is done by the astronauts in shortening the rope -45,317,098 KJ.

(a) To calculate the magnitude of the angular momentum of the system, we can use the following equation:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. Since we are treating the astronauts as particles, we can assume they are point masses and use the formula for the moment of inertia of a point mass:

I = mr²

where m is the mass of each astronaut and r is the distance between them. The angular velocity can be found from the linear velocity and the distance between the astronauts:

ω = v/r

Putting in the given values, we get:

r = 5.00 m

m = 90.5 kg

v = 5.80 m/s

I = 2(mr²) = 2(90.5 kg)(5.00 m)²

              = 4,525 kg m²

ω = v/r = 5.80 m/s / 5.00 m

           = 1.16 rad/s

L = Iω = (4,525 kg m²)(1.16 rad/s)

          = 5,252 kg m²/s

Therefore, the magnitude of the angular momentum of the system is 5,252 kg m²/s.

(b) To calculate the rotational energy of the system, we can use the following equation:

E = (1/2)Iω²

Putting in the values for I and ω that we found in part (a), we get:

E = (1/2)(4,525 kg m²)(1.16 rad/s)²

  = 2,826 J

Therefore, the rotational energy of the system is 2,826 J.

(c) When the distance between the astronauts is shortened to 5.00 m, the moment of inertia of the system changes. We can calculate the new moment of inertia using the parallel axis theorem:

I = Icm + md²

where Icm is the moment of inertia about the center of mass (which remains the same), m is the mass of each astronaut, and d is the distance between each astronaut and the center of mass (which is half the original distance, or 2.50 m).

The new moment of inertia is:

I = Icm + 2md²

 = 2(m(2.50 m)²)

 = 31.25 kg m²

Therefore the new moment of inertia is 31.25 Kgm².

(d) To find the new speeds of the astronauts, we can use the conservation of angular momentum:

L = Iω = L'

where L is the initial angular momentum (which we found in part (a)) and L' is the new angular momentum (which we can find using the new moment of inertia and the new distance between the astronauts, which is 5.00 m).

Solving for ω', we get:

ω' = L' / I = L / I'

Putting in the values, we get:

L' = L = 5,252 kg m²/s

I' = 31.25 kg m²

ω' = 5,252 kg m²/s / 31.25 kg m² = 168.06 rad/s

The new speed of each astronaut is the tangential velocity at a distance of 2.50 m from the center of mass, which can be found using the formula:

v = ω'r

where r is the distance from the center of mass. Putting in the values, we get:

v = 168.06 rad/s * 2.50 m = 420.15 m/s

Therefore, the new speed of each astronaut is 420.15 m/s.

(e) To find the new rotational energy of the system after the astronauts have shortened the rope to 5.00 m, we can use the conservation of angular momentum:

L = Iω

where L is the angular momentum of the system, I is the moment of inertia of the system, and ω is the angular speed of the system. Since the rope is assumed to have negligible mass, we can treat the system as two point masses moving in a circle around their center of mass. The moment of inertia of this system can be calculated as:

I = 2mr²/5

where m is the mass of each astronaut and r is the distance between them. Initially, the moment of inertia of the system is:

I = 2 * 90.5 kg * (10.0 m / 2)² / 5

= 3638 kg m²

The initial angular momentum of the system is:

L = Iω = 3638 kg m² * (5.80 m/s) / (10.0 m / 2)

          = 4213.6 kg m²/s

After the astronauts have shortened the rope to 5.00 m, the moment of inertia of the system is:

I' = 2 * 90.5 kg * (5.00 m / 2)² / 5

  = 1352.5 kg m²

Since the angular momentum of the system is conserved, the new angular speed of the system is:

ω' = L/I' = 4213.6 kg m²/s / 1352.5 kg m² = 3.115 rad/s

E' = (1/2)I'ω'² = (1/2) * 1352.5 kg m² * (3.115 rad/s)²

                    = 65,817.6 J

                    = 65.82 kJ

Therefore, the new rotational energy of the system is 65.82 kJ.

(f) The work done by the astronauts in shortening the rope is:

W = ∫F dl = (F' - F) ∫dl

   = (6,043,064.25 N - 630.56 N) * (-7.50 m)

   = -45,317,098 KJ

Therefore, the work is done by the astronauts in shortening the rope -45,317,098 KJ.

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Answer:

1.loudness

2.pitch

3.shrillness

The charge on the segment ds is  \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

As Q is uniformly distributed over semicircel so,charge density

\(\lambda=\frac{Q}{s}=\frac{Q}{\pi r}\)

so in ds region charge: \(dQ=\frac{Q}{\pi a}ds=\frac{Q}{\pi a}ad\theta= \frac{Q}{\pi} d\theta\)

In physics, a uniformly distributed charge refers to a charge distribution where the charge density is constant throughout the given volume or surface. In other words, the amount of charge per unit volume or unit area is the same everywhere within the region.

Uniformly distributed charge is an important concept in electrostatics, which is the study of the behavior of electric charges at rest. The electric field produced by a uniformly charged object has a particularly simple form, and this makes it easier to calculate the electric field at any point outside the charged object using Gauss's Law.

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the complete question is:

What is the charge on a segment ds?

Express your answer in terms of some, all, or none of the variables Q, a, θ, dθ, and the constant π.

Answer:

+70 km/h north

Explanation:

Answer:North/speeding up

Explanation:

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The  voltage is \(\epsilon = 0.40163 \ V\)

The  direction of the induced current is clockwise

Explanation:

From the question we are told that

   The number of turns is  N  = 17

     The  magnetic field is  \(B_2 = 0.5 \ T\)

     The diameter is  \(d = 3.8 \ cm = 0.038 \ m\)

      The  time interval is \(dt = 0.24 \ s\)

The induce emf is mathematically represented as

       \(\epsilon = - N \frac{d\phi}{dt}\)

       \(\epsilon = - N \frac{d ( B_2 - B_1 ) A }{dt}\)

Here \(B_1\) is the magnetic field experienced by the coil before entering the magnetic field given in the question  i.e  \(B_1 = 0\)

Here the negative sign show that the induced voltage is moving in a direction opposite to the change magnetic flux

  The  area is mathematically represented as

      \(A = \pi \frac{d^2}{4}\)

=>  \(A = 3.142 * \frac{ 0.038^2 }{4}\)

=>   \(A = 0.01134 \ m^2\)

Hence

     \(\epsilon = - 17 * \frac{ 0.5 * 0.01134 }{ 0.24}\)

     \(\epsilon = 0.40163 \ V\)

The  direction of the induced current is the same as that of induced voltage

    Thus the direction is clockwise

Answer:

The correct answer is d.

Theories are constructed after there is numerous data collected during the experiment.

Explanation:

hope it helps

Answer:

Here's ur answer

Explanation:

It is deflected by both electric and magnetic field because it carries negative charge

Hope it's helpful.. if so mark me as brainlist n thank me..

Answer:

30 m

General Formulas and Concepts:

Energy

Gravitational Potential Energy: \(\displaystyle U_g = mgh\)

Kinetic Energy: \(\displaystyle KE = \frac{1}{2}mv^2\)

Law of Conservation of Energy

Explanation:

Step 1: Define

Identify variables

[Given] m = 0.8 kg

[Given] g = 10 m/s²

[Given] U = 240 J

[Solve] h

Step 2: Solve for h

Answer:

yes

Explanation:

Answer:

Hmm looks tricky

Explanation:

Answer:

- 0.33 m/s

Explanation:

An illustration is shown above,

In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,

m1u1 - m2u2 = (m1 + m2)v

Where,

m1 = mass of the first object

u1 = initial velocity of the first object

v1 = final velocity of the first object

m2 = mass of the second object

u2 = initial velocity of the second object

v2 = final velocity of the second object

Therefore,

(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v

12 - 16 = 12v

-4 = 12v

Divide both sides by 12,

-4 / 12 = 12v / 12

-1 / 3 = v

v = -0.33 m/s

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Thanks

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Answer:

4.05×10⁶ N.

Explanation:

The following data were obtained from the question:

Breadth (B) = 4 m

Length (L) = 10 m

Standard pressure (P) = 101325 Nm¯²

Force (F) =..?

Next, we shall determine the area of the wall. This can be obtained as follow:

Area (A) = length (L) × breadth (B)

A = 10 × 4

A = 40 m²

Finally, we shall determine the force exerted on one side of the wall as follow:

Standard pressure (P) = 101325 Nm¯²

Area (A) = 40 m²

Force (F) =.?

Pressure (P) = Force (F) /Area (A)

101325 = F/40

Cross multiply

F = 101325 × 40

F = 4.05×10⁶ N.

Therefore, a force of 4.05×10⁶ N was exerted on one side of the wall.

The frequency of oscillation of the swing is 0.25 Hz.

The time period of oscillation of the swing is 4 s.

The length of the vine of the swing is 3.97 m.

The restoring force acting on Mohammed is 692.9 N.

Mass of Mohammed, m = 50 kg

Angle made by the vine with the vertical, θ = 45°

Number of complete swings made by Mohammed, n = 30

Time taken for this swing, t = 2 minutes = 120 seconds

a) The frequency of the swing is defined as the number of complete oscillations in one second.

So, the frequency of oscillation of the swing is,

f = n/t

f = 30/120

f = 0.25 Hz

b) The time period of oscillation of the swing is,

T = 1/f

T = 1/0.25

T = 4 s

c) The expression for the time period is given by,

T = 2π√(l/g)

T² = 4π² x (l/g)

l/g = T²/4π²

Therefore, the length of the vine of the swing is,

l = T²g/4π²

l = 4² x 9.8/4 x (3.14)²

l = 3.97 m

d) The restoring force acting on Mohammed,

F = mg sinθ

F = 50 x 9.8 x sin 45°

F = 490 x 1/√2 = 490/1.414

F = 692.9 N

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Answer:

The final speed of electron=\(5.93\times 10^6m/s\)

Explanation:

We are given that

Initial velocity, u=0

Potential, V=100 V

We have to find the final speed.

Mass of electron, \(m=9.1\times 10^{-31} kg\)

Charge on electron, q=\(1.6\times 10^{-19}C\)

We know that

\(qV=\frac{1}{2}mv^2-\frac{1}{2}mu^2\)

Using the formula

\(1.6\times 10^{-19}\times 100=\frac{1}{2}\times 9.1\times 10^{-31} v^2-0\)

\(v^2=\frac{2\times 1.6\times 10^{-19}\times 100}{9.1\times 10^{-31}}\)

\(v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 100}{9.1\times 10^{-31}}}\)

\(v=5.93\times 10^6m/s\)

Hence, the final speed of electron=\(5.93\times 10^6m/s\)

2.5 mL of Thallium-201 should be injected to administer a recommended dose of 3.0 mCi.

Thallium-201 is a radioisotope that is used in brain scans to detect brain cancer. It is used in nuclear medicine as a radiopharmaceutical. The recommended dose for Thallium-201 is 3.0 mCi. If a vial of Thallium-201 contains 60. mCi in 50. mL, we can determine the number of milliliters that should be injected by using proportionality.A proportion can be used to compare two ratios and solve for an unknown value. For example, if x is the unknown value we are trying to solve for and a/b and c/d are two ratios that are equal, we can write a proportion:

a/b = c/d.

Cross-multiplying gives us the equation

ad = bc.

This formula can be used to solve for the unknown value x. For this problem, we can use a proportion to solve for the number of milliliters that should be injected. Let x be the number of milliliters that should be injected. Then we have the following ratio:

3.0 mCi / x mL = 60. mCi / 50. mL

To solve for x, we can cross-multiply:

3.0 mCi * 50. mL = 60. mCi * x mL150. mCi mL = 60. mCi x mCx = (150. mCi mL) / (60. mCi) x = 2.5 mL

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Explanation:

The orbiting period of a satellite at a height h from earth' surface is

T=2πr32gR2

where r=R+h.

Then, T=2π(R+h)R(R+hg)−−−−−−−−√

Here, R=6400km,h=1600km=R/4

T=2πR+R4−−−−−−√R(R+R4g)−−−−−−−−−⎷=2π(1.25)32Rg−−√

Putting the given values,

T=2×3.14×(6.4×106m9.8ms−2)−−−−−−−−−−−−√(1.25)32=7092s=1.97h

Now, a satellite will appear stationary in the sky over a point on the earth's equator if its period of revolution around the earthh is equal to the period of revolution of the earth up around its own axis whichh is 24h. Let us find the height h of such a satellite above the earth's suface in terms of the earth,'s radius.

Let it be nR.Then

T=2π(R+nR)R(R+nRg)−−−−−−−−−−√

=2π(Rg)−−−−−√(1+n)32

=2×3.14(6.4×106m/s9.8m/s2)−−−−−−−−−−−−−−−⎷(1+n)32

(5075s)(1+n)32=(1.41h)(1+n)32

For T=24h, we have (24h)=(1.41h)(1+n)32

or (1+n)32=241.41=17

or 1+n(17)23=6.61

or n=5.61

The height of the geostationary satellite above the earth's surface is nR=5.61×6400km=6.59×104km.

Answer:

\(Weight\ loss=1.6321N\)

Explanation:

From the question we are told that:

Weight \(W=85.9kg\)

Altitude \(h= 6.33 km\)

Let

Radius of Earth \(r=6380km\)

Gravity \(g=9.8m/s^2\)

Generally the equation for Gravity at altitude is mathematically given by

 \(g_s=9.8(\frac{6380}{6380+6.33})^2\)

 \(g_s=9.781m/s^2\)

Therefore

Weight at sea level

 \(W_s=9.8*85.9\)

 \(W_s=841.82N\)

Weight at 6.33 altitude

 \(W_a=9.781*85.9\)

 \(W_a=840.2N\)

Therefore

 \(Weight loss=W_s-W_b\)

 \(Weight loss=841.82-840.2\)

 \(Weight loss=1.6321N\)

The displacement of the object from 0 to 6.0 seconds is 80m.

option C.

The displacement of the object from 0 to 6.0 seconds is calculated by finding the area of the shape formed between 0 and 6 seconds.

displacement = area of trapezium

Area of trapezium ( 0 to 6 seconds ) = ¹/₂ ( a + b ) h

where;

Area of the trapezium = ¹/₂ ( 6s + 2s ) 20 m/s = 80 m

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Answer:The answer is because of the gravity and the mass formed in the sun, the magnetic field reacts to it and leaves a fault on earth. wind goes by the earth and procides to be ok

Explanation:that is it

Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation: