The age of the buildings at the site is approximately 17,190 years. The correct option is 17190 years.
To determine the age of the wooden buildings using radiocarbon dating, we can use the half-life formula:
N = N₀ * (1/2)^(t/T)
where:
- N is the current ratio of carbon-14 to carbon-12 (0.125 ppt)
- N₀ is the initial ratio of carbon-14 to carbon-12 when the trees were cut down (1 ppt)
- t is the time elapsed (the age of the buildings, which we want to find)
- T is the half-life of carbon-14 (5,730 years)
We can rearrange the formula to solve for t:
t = T * log2(N₀/N)
Plugging in the given values:
t = 5730 * log2(1/0.125)
t = 5730 * log2(8)
t = 5730 * 3
t = 17,190 years
So, the correct option is 17190 years.
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Explain why people should be encouraged to use energy efficient electrical devices
Answer:
People should be urged to adopt energy-efficient electrical appliances since producing computers, televisions, and other electronic equipment requires a significant amount of energy and raw materials.
Explanation:
The problem of dealing with electronic garbage is getting worse. You may lessen the damaging effects of electronic products on the environment by conserving energy and properly disposing of outdated devices. Energy efficiency lowers energy usage, which lowers monthly energy costs and makes energy more affordable for homes and companies. Although they may initially cost more than alternative solutions, energy-efficient devices often end up saving you money in the long run. Lastly, an energy-efficient home uses less energy than it needs to, emits fewer greenhouse gases, and uses less non-renewable energy. It could also provide cleaner, healthier living circumstances. An energy-efficient home may also result in financial savings.
Hope this helps :)
A crate is being pulled down an incline as shown in the figure. With respect to the crate's direction of motion, which of the following forces does only negative work on the crate?
Answer: Fn
Explanation: Because Fn is applying force upward
Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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Compare solar heating panels and solar electric panels.
pls I really need help
Answer:
We know that a solar electrical panel converts sunlight to electricity by means of solar cells and then, the electricity can be used as any electrical current.
I am not familiar with solar heating panels but assume that a liquid is heated by sunlight and then circulated thru the area that needs heating - it converts heat from sunlight to usable heat. The heat energy could also be stored and delivered at a different time (accumulated during the day and delivered at night). This is somewhat similar to a company freezing water at night when electricity is cheaper and then using the cooled water during the day for cooling.
Ginger was caring for her litter of puppies when the four curious pups spotted cat for the first time. Each of the four pups leaned their full of force in the board balanced between the puppies and the cat. How much force must Ginger apply to the other side to keep the puppies from knocking down the board? A. 8 N
B. 16 N
C. 32 N
On prevent the puppies from tearing down the board, Ginger must apply 32 N of force to the opposite side.
What is the value of total force?The total force acting on the system is equal to the acceleration of the center of mass times the system's total mass. When applied to an extended object, Newton's second law, F = ma, predicts the motion of a specific reference point for this object.
How much force is acting on an object overall?The vector sum of all forces acting on an object is known as the net force. In other words, the net force is the sum of all the forces, taking into mind that a force is a vector and that two forces that have the same magnitude but facing the opposite direction will cancel each other out.
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Fossil fuels are burned, transferring their chemical potential energy to heat energy. How are nuclear power stations different?
Answer:
fossil fuels are natural and limited, nuclear is man made and more toxic
Explanation:
By how many times will the kinetic energy of a body increase if its speed is tripled? Show by calculation .
Answer:
9 lần
Explanation:
Answer:
Kinetic energy (k.e) varies directly as v² from the formula
K.E=(mv²/2)
if v=3 then K.e =v²=(3)²=9
A car start from a rest and moves with constant acceleration of 10metre per seconds square and moves with constant velocity attained for 20seconds
1.Draw the velocity time graph
By breaking the motion into two phases: the acceleration phase and the constant velocity phase, we are able to easily plot our velocity time graph.
How to Draw Velocity Time GraphPhase 1: Acceleration
During this phase, the car starts from rest and accelerates at a constant rate of 10 meters per second squared until it reaches its maximum velocity.
1. At time t = 0, the car starts from rest, so the velocity is 0.
2. As time progresses, the velocity increases at a constant rate of 10 meters per second squared.
Phase 2: Constant Velocity
After the acceleration phase, the car maintains a constant velocity for 20 seconds.
3. At the end of the acceleration phase, the car reaches its maximum velocity and maintains this velocity for the next 20 seconds.
Based on this information, the velocity-time graph is represented in the image attached.
In this graph:
- The y-axis represents velocity (V) in meters per second.
- The x-axis represents time (t) in seconds.
- The first part of the graph shows a linearly increasing velocity with a slope of 10 m/s².
- After reaching the maximum velocity, the graph shows a horizontal line representing the constant velocity maintained for 20 seconds.
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A student uses a spring scale attached to a textbook to compare the static and kinetic friction between the textbook and the top of a lab table. If the scale measures 1,580 g while the student is pulling the sliding book along the table, which reading on the scale could have been possible at the moment the student overcame the static friction?
Answer:1860g
Explanation:The force would have to be greater than 1580g, which is when the student is pulling the sliding book with the spring scale
A test rocket is launched by accelerating it along a 200.0 m, 35 degree incline at 1.25 m/s/s starting
from rest. The instant the rocket leaves the incline, its engines turn off, it is subject only to gravity,
and air resistance can be ignored. Find
a) the maximum height above the ground the rocket reaches
Answer:
The maximum height above the ground the rocket reaches is 123.1 m.
Explanation:
Let's find the final velocity at a distance of 200 m:
\( v_{f}^{2} = v_{0}^{2} + 2ad \)
Where:
\(v_{f}\) is the final speed =?
v₀ is the initial speed =0
a is the acceleration = 1.25 m/s²
d is the distance = 200 m
\(v_{f} = \sqrt{2ad} = \sqrt{2*1.25 m/s{2}*200 m/s} = 22.4 m/s\)
Now, when the engines of the rocket turn off and it is subject only to gravity, the height reached is:
\( v_{fy}^{2} = v_{0y}^{2} - 2gh \)
Where:
\(v_{f}\) = 0
\(h = -\frac{v_{fy}^{2} - v_{0y}^{2}*sin(\theta)}{2g} = \frac{(22.4*sin(35))^{2}}{2*9.81 m/s^{2}} = 8.4 m\)
Finally, the maximum height above the ground is:
\( h_{max} = h + H \)
Where H is the vertical component of the 200.0 meters.
\(h_{max} = h + H = 8.4 m + 200.0 m*sin(35) = 123.1 m\)
Therefore, the maximum height above the ground the rocket reaches is 123.1 m.
I hope it helps you!
Which ranks the solutions in order of greatest to least solubility? X → Y → Z Y → X → Z Z → X → Y Y → Z → X
Answer:
The answer is "Y → X → Z".
Explanation:
In this question, the chart is missing and the question is not complete that's why we search this question and only give its correct answer that's is defined above, and please find the complete question in the attached file.
The wavefunctions of a particle that is confined within a box whose walls have a finite height will look different from those corresponding to a box with infinitely high walls.
a. Make a sketch illustrating the difference between the ground-state wavefunctions of a particle in these two kinds of box potentials.
b. Which of the two systems do you expect to have a lower ground-state energy (assuming the two boxes have the same length)?
The wavefunctions of a particle that is confined within a box whose walls have a finite height will look different from those corresponding to a box with infinitely high walls.
Let us try to figure out which of the two systems we expect to have a lower ground-state energy (assuming the two boxes have the same length). For this, we will have to take into consideration a few properties of quantum mechanics.
Since, a particle is confined within a box with finite walls, its wave function has to go to zero at the wall. As the height of the walls is not infinite, the particle will have a probability of existing outside of the box, although it is small. When we lower the wall height, this probability of existing outside the box increases.
As the probability of the particle being outside the box is higher, the energy of the particle would be lower, as the energy of the particle increases as its probability of being outside the box decreases.
Thus, in the case of a particle confined within a box whose walls have a finite height, the energy would be lower in comparison to a particle confined within a box with infinitely high walls, given that the boxes have the same length. Therefore, we can say that the system with finite walls will have a lower ground-state energy.
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Adam is driving his truck at 18 m/s for a distance of 46 m, how much time was Adam driving?
Answer:
2.6 seconds
Explanation:
You have to divide the distance by the velocity to find the time:
46/18 = 2.55 ≈ 2.6 seconds
The answer you are looking for is approximately 2.6 seconds.
Solution/Explanation:
To get the correct answer, you must divide the distance and velocity.
This means that 46÷18=2.5556.
2.5556≈2.6.
So, therefore, the final answer is approximately 2.6 seconds.
I hope that this has helped you. Enjoy your day, and take care.
The direction equivalent to {40° W of S} is:
A. 40 ° E of S
B. 40° W of N
C. 40° E of N
D. 50° S of W
E. 50° E of N
Answer:
c
Explanation:
A wave with a frequency of 10 Hz and wavelength of 12m has what velocity?
The equations you will need:
v = λ x f λ=v/f f=v/λ
Answer:
120
Explanation:
lambda = 12
f=10
10×12=120
mention 4 layers of the atmosphere
Answer:
These layers are the troposphere, the stratosphere, the mesosphere and the thermosphere.
A further region, beginning about 500 km above the Earth's surface, is called the exosphere.
Explanation:
Hope this helps you. Have a nice day. Please mark as brainliest. It helps a lot.^_^
Draw a wave below youf copy of wave g which has higher amplitude but the same frequency inside the box labeled as wave h how would this sound compare to the sound produced by wave g
Answer:
.. answer explamkn
Explanation:
Why are some telescopes placed in space?
There is no gravity in space so bigger, heavier mirrors or lenses can be used
Some types of electromagnetic radiation cannot penetrate Earth's
atmosphere
Space telescopes are less expensive that ground telescopes
Telescopes in space are able to get significantly closer to astronomical
objects
Answer:
to get around the Earth's atmosphere so that we can get a clearer view of the planets, stars, and galaxies that we are studying.
Explanation:
A 1 kg billiard ball collides head on with a 0.1 kg marble that sits at rest on the table. The marble moves at 3 m/s in the same direction the billiard ball was originally moving. The billiard ball continues after the collision at 0.3 m/s. What was the initial speed of the billiard ball?
Let v be the billiard ball's initial speed. The total momentum of the ball-marble system is conserved between the times before and after their collision, so that
(1 kg) v + (0.1 kg) (0 m/s) = (1 kg) (0.3 m/s) + (0.1 kg) (3 m/s)
Solve for v :
v + 0 = 0.3 m/s + 0.3 m/s
v = 0.6 m/s
Look at the diagram below that shows information about the sun, Earth, and moon. Use that information to calculate and compare the gravitational forces between the Earth and the Sun, and the Earth and the Moon.
i. The gravitational force between the earth and sun can be obtained as follow:
Mass of earth (M₁) = 5.987×10²⁴ KgMass of sun (M₂) = 1.989×10³⁰ KgDistance apart (r) = 1.5×10¹¹ mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 5.987×10²⁴ × 1.989×10³⁰) / (1.5×10¹¹)²
F = 3.53×10²² N
Thus, the gravitational force between the earth and sun is 3.53×10²² N
ii. The gravitational force between the earth and moon can be obtained as follow:
Mass of earth (M₁) = 5.987×10²⁴ KgMass of moon (M₂) = 7.347×10²² KgDistance apart (r) = 3.844×10⁸ mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?F = GM₁M₂ / r²
F = (6.67×10¯¹¹ × 5.987×10²⁴ × 7.347×10²²) / (3.844×10⁸)²
F = 1.99×10²⁰ N
Thus, the gravitational force between the earth and moon is 1.99×10²⁰ N
How do i compare the gravitational forces?Gravitational force between the earth and sun (G₁) = 3.53×10²² NGravitational force between the earth and moon (G₂) = 1.99×10²⁰ NComparison =?Comparison = G₁ / G₂
G₁ / G₂ = 3.53×10²² / 1.99×10²⁰
G₁ / G₂ = 177
Cross multiply
G₁ = G₂ × 177
Thus, we can say that the gravitational force between the earth and sun is 177 times bigger than the gravitational force between the earth and moon
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Describe and explain how the movement and arrangement of the particles in a block of ice change as the ice melts to form liquid water. In your answer, include ideas about energy transfer.
Answer:
Ice is water in solid phase, in this phase, the particles are very close together and relatively in fixed positions.
As the temperature starts to increase (thermal energy), also does the kinetic energy of the particles (so we have a change from thermal energy to kinetic energy), so they start to move "more", and the position of the particles starts to be less "fixed". There is a point where the particles have enough energy, and this point is where the phase of the water changes from solid to liquid phase (the fusion point). After this point the water can not hold his shape, and takes the shape of the container where it is.
A skateboarder is skating along a level concrete path. Every so often, to keep himself going, he uses his foot to give himself a push. Discuss why the skateboarder needs to regularly push with a foot when skateboarding along a level surface.
In your answer, you should:
- describe the motion of the skateboarder during a push and between pushes
- identify the forces in action and explain whether they are balanced or unbalanced
- link the net force to the motion of the skateboarder.
The skateboarder needs to regularly push with their foot when skateboarding along a level surface because of the presence of frictional forces that oppose motion. When the skateboarder gives themselves a push, they increase their forward velocity.
The skateboarder needs to regularly push with their foot when skateboarding along a level surface because of the presence of frictional forces that oppose motion. When the skateboarder gives themselves a push, they increase their forward velocity. However, over time, the velocity decreases due to the force of friction between the skateboard's wheels and the ground, which acts in the opposite direction to the skateboard's motion. During a push, the skateboarder exerts a force on the skateboard that propels it forward. Between pushes, the skateboard moves at a constant velocity due to the balanced forces acting upon it. However, as frictional forces act on the skateboard, it slows down until the next push is required. The net force acting on the skateboarder is unbalanced, as the force of friction acting against the skateboard's motion is greater than the force of the skateboarder's push. The resulting net force causes the skateboarder to slow down over time. Thus, by pushing themselves, the skateboarder overcomes the force of friction and maintains their forward motion.
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how much does a change in mass affect the kinetic energy of two balls of comparable diameter?
Answer:
Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.
In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.
The following table shows the frequency of causes of defects on a printed-circuit-board. Defect Frequency Excess adhesive 190 Misplaced transistors 76 Defective board dimensions 211 Wrong component 107 Improperly positioned mounting holes 72 Components not adhering 166
Find the probability of each of the defects.
Round your answer to 4 decimal places.
To find the probability of each defect, we divide the frequency of each defect by the total frequency of all defects.
Excess adhesive: Probability = 190 / (190 + 76 + 211 + 107 + 72 + 166) = 190 / 822 = 0.2311 (approximately 23.11%)Misplaced transistors: Probability = 76 / (190 + 76 + 211 + 107 + 72 + 166) = 76 / 822 = 0.0924 (approximately 9.24%)Defective board dimensions: Probability = 211 / (190 + 76 + 211 + 107 + 72 + 166) = 211 / 822 = 0.2566 (approximately 25.66%)Wrong component: Probability = 107 / (190 + 76 + 211 + 107 + 72 + 166) = 107 / 822 = 0.1301 (approximately 13.01%)Improperly positioned mounting holes: Probability = 72 / (190 + 76 + 211 + 107 + 72 + 166) = 72 / 822 = 0.0876 (approximately 8.76%)Components not adhering: Probability = 166 / (190 + 76 + 211 + 107 + 72 + 166) = 166 / 822 = 0.2010 (approximately 20.10%)The probability of each defect is found by dividing the frequency of that particular defect by the total frequency of all defects. The total frequency of all defects is calculated by summing up the frequencies of all the defects. Then, the frequency of each defect is divided by the total frequency to obtain the probability.
For example, to find the probability of Excess adhesive, we divide its frequency (190) by the total frequency of all defects (822). Similarly, we calculate the probability for each defect by dividing its frequency by the total frequency.
These probabilities represent the relative likelihood of each defect occurring out of the total defects observed on the printed circuit board.
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During the warm-up and your scheduled physical activity, what was the weather like? Did the
temperature or conditions affect how much water you drank? How?
Answer: I did these exercises outdoors. The weather was hot and humid, so I drank about two cups of water during the workout. I also drank a cup of water about an hour before I started. Yes, the weather most definitely affected how much I drank.
Explanation: Edmentum
two astronauts, initially at rest and facing each other in space, push on each other. what will happen to them?
When two astronauts, initially at rest and facing each other in space, push on each other, they will both move away from each other due to Newton's third law of motion and the conservation of momentum.
The given phenomenon can be explained using Newton's third law of motion and the conservation of momentum.
Apply Newton's third law of motion.
Newton's third law of motion states that for every action, there is an equal and opposite reaction. When the astronauts push on each other in space, the force applied by each astronaut on the other is equal in magnitude but opposite in direction.
Apply the conservation of momentum.
In this scenario, the total momentum of the astronauts before they push off each other is zero, as they are initially at rest. After they push off, the total momentum of the system must still be zero to conserve momentum.
Observe the resulting motion.
Due to the conservation of momentum, the astronauts will move away from each other with equal and opposite velocities. This means that their relative speeds and distances traveled will be the same but in opposite directions.
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Plz answer will give brainliest answer to whoever does
Answer:A gas heater working
Explanation:because from the system of it it could be coal or just air being heated up it takes energy to make it hot! In other words convection
Jamal says that the separation of colors can be explained by the particle model of light. Natalia says that the separation of colors is better explained by the wave model of light.
Who is correct?
A) Both are correct; color is equally well-explained by either particle or wave models of light.
B) Jamal is correct.
C)Both are incorrect.
D)Natalia is correct.
Answer:
Natalia is correct.
Explanation:
i got it right when it said natalia
why is the wave nature of matter not important for a baseball?
The mass of a baseball is too large to exhibit wave-like behavior, making the wave nature of matter insignificant.
The wave nature of matter is not important for a baseball because the mass of a baseball is too large to exhibit wave-like behavior.
According to the de Broglie equation, the wavelength of an object is inversely proportional to its mass. Since a baseball has a large mass, its wavelength is incredibly small and insignificant.
Additionally, wave-like behavior is only observable on the atomic and subatomic level, where particles have incredibly small masses.
Therefore, for macroscopic objects like a baseball, classical mechanics is a more appropriate way to describe its motion, and the wave nature of matter can be ignored.
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A blue train of mass 50km moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. What is the final speed of the blue train?
The final speed of the blue train after colliding with the green train is 2.79 m/s, while the green train moves with a speed of 3 m/s.
To solve this problem, we need to apply the principle of conservation of momentum, which states that the total momentum of a closed system is conserved, provided that no external forces act on the system. In this case, the system consists of the blue train and the green train, and there are no external forces acting on the system.
Let's begin by calculating the initial momentum of the system:
Initial momentum = (mass of blue train x velocity of blue train) + (mass of green train x velocity of green train)
Initial momentum = (50,000 kg x 4 m/s) + (30 kg x 0 m/s)
Initial momentum = 200,000 kg·m/s
Next, we need to calculate the final momentum of the system. We know that the green train moves with a speed of 3 m/s after the collision, but we don't know the final speed of the blue train. However, we can use the principle of conservation of momentum to calculate the final momentum of the system:
Final momentum = (mass of blue train x final velocity of blue train) + (mass of green train x final velocity of green train)
We can simplify this equation by assuming that the collision is perfectly elastic, which means that kinetic energy is conserved as well as momentum. In an elastic collision, the total kinetic energy before the collision is equal to the total kinetic energy after the collision. We can use this fact to solve for the final velocity of the blue train:
Total kinetic energy before collision = (1/2 x mass of blue train x (velocity of blue train)²) + (1/2 x mass of green train x (velocity of green train)²)
Total kinetic energy before collision = (1/2 x 50,000 kg x (4 m/s)²) + (1/2 x 30 kg x (0 m/s)²)
Total kinetic energy before collision = 400,000 J
Total kinetic energy after collision = (1/2 x mass of blue train x (final velocity of blue train)²) + (1/2 x mass of green train x (final velocity of green train)²)
Total kinetic energy after collision = (1/2 x 50,000 kg x (final velocity of blue train)²) + (1/2 x 30 kg x (3 m/s)²)
Total kinetic energy after collision = 225,450 J
Since kinetic energy is conserved in an elastic collision, we can set the total kinetic energy before the collision equal to the total kinetic energy after the collision:
400,000 J = 225,450 J + (1/2 x 50,000 kg x (final velocity of blue train)²)
Solving for the final velocity of the blue train:
(1/2 x 50,000 kg x (final velocity of blue train)²) = 174,550 J
(final velocity of blue train)² = 7.78 m²/s²
final velocity of blue train = 2.79 m/s
Therefore, the final speed of the blue train after the collision is 2.79 m/s.
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