sarah was always looking for bargains, and she was talking about the number of refurbished and reconditioned electronics on companies' website. her friend alexis, a marketing major, explained to her that this was one of the results of the growth of which process?group of answer choicesproduct-life extensionsreverse supply chainsrecyclingprofit maximization

When you simulated a single charge next to a line of negative charge, the field and equipotential lines around the line of charge differed from when the negative charge was a point charge.

When you simulated a single charge next to a line of negative charge, the field and equipotential lines around the line of charge differed from when the negative charge was a point charge as follows: The line of negative charge generates a uniformly negative electric field perpendicular to the line of charge, unlike the point charge, which produces a radial electric field. Equipotential lines in this case would be straight, parallel lines, with the voltage increasing as they approach the point charge in the case of the point charge. The equipotential lines around a line of negative charge are perpendicular to the line of charge, unlike the equipotential lines around a point charge, which are radial to the point charge. The field strength of the line of negative charge decreases with distance, unlike the field strength of the point charge, which decreases with the square of the distance from the point charge. Therefore, when you simulated a single charge next to a line of negative charge, the field and equipotential lines around the line of charge differed from when the negative charge was a point charge.

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50.545 degrees with a positive x-axis and a weight of 133.909 pounds. the direction and strength of these forces' combined effect

A modest but significant amount of a certain characteristic is present in anything if it has a degree of that attribute. However, their salaries do provide them some freedom. There is some cause for cautious optimism.

Degree (Celsius) (Celsius) Temperature readings are frequently made in degrees Celsius. Degrees Celsius are denoted by the sign °C. By designating 0°C as the freezing point of water and 100°C as its boiling point, the Celsius scale is produced.

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Explanation:

Mitochondria are essential parts of many eukaryotes, but they are useless without oxygen. Therefore, chloroplasts are extremely important. They produce breathable air for life. Root hairs are seen to not have chloroplasts as their job is to collect water and nutrients.

Answer:

The angle of the Sun's rays:

At about June 21 the sun is directly overhead at about 23 deg north of the equator

On about Dec 21 the sun is directly overhead at about 23 deg south of the equator

It is this tilt 23 deg to the ecliptic (path of earth about sun) that causes the major temperature changes on earth

Tracer wire. Tracer wire is an electrical wire that is buried alongside non-metallic pipes during installation. The correct answer is d) .

The tracer wire is then connected to a locating device that can be used to locate the pipe in the future. This is important for maintenance and repair work, as well as for preventing damage to the pipe during excavation or construction. Survey monuments are typically used to mark property boundaries or survey points, while location markers and radio transmission chips are not commonly used for locating non-metallic pipes.

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The correct prescription for the eyeglasses that would serve the same purpose as the contact lenses is +2.40 diopters.

When wearing the contact lenses with a refractive power of 1.90 diopters, the man is able to read books held no closer than 0.265 m from his eyes. To find the prescription for the eyeglasses, we need to calculate the additional refractive power required to achieve the same focusing ability at a different distance. Using the lens formula

1/f = 1/v - 1/u,

where f is the focal length, v is the image distance, and u is the object distance, we can calculate the focal length of the contact lenses.

Since the person can read books held no closer than 0.265 m, the object distance (u) would be 0.265 m. The image distance (v) would be the distance from the contact lenses to the eyes, which is 0.020 m. The calculated prescription for the eyeglasses is +2.40 diopters, which means that eyeglasses with a refractive power of +2.40 diopters would enable the man to read books held at a distance of 0.020 m.

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Answer:

2.93 mm

Explanation:

If you stack 3 nickels on a table, e the table is their center of gravity 2.93 mm

The Centre of gravity is a theoretical term, where the body’s total weight is thought to be concentrated and it predicts the behavior of a moving body when acted on by gravity.

It is also useful in designing static structures like buildings and bridges, the center of gravity is identical to the centre of mass.

For the Moon, the centre of mass is very close to its geometric centre and its centre of gravity is slightly towards the Earth due to the stronger gravitational force on the Moon’s near side.

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Answer:

it increasees

Explanation:

its 100% acurate dont worry

Answer:I think it would be 0

Explanation:

Both are pushing with 100n therefore it will not move

Without the specific form of the velocity field given, it is not possible to provide an answer on the circulation and its direction around a triangle.

The circulation of a vector field around a closed curve is the line integral of the vector field along that curve. In the case of a triangle, we need to compute the circulation along each of its three edges and then sum them up. The direction of circulation can be determined based on the orientation of the triangle, which is typically defined as counterclockwise. If the circulation is positive, the direction is counterclockwise, while a negative circulation indicates a clockwise direction. The specific form of the velocity field needs to be provided to compute the circulation around the triangle.

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Answer:

F=9.14N

Explanation:

using the formula

W=Fdcosθ

where

F -is the magnitude of the force applied(F)

d- is the distance the object travels(10m)

θ- is the angle between the force and the distance vectors(40°)

W- work done joules(70J)

by substituting

W=Fdcosθ

70=F×10×cos40

making F the subject of formula

F=70/10×0.7660

F=70/7.66

F=9.138

F=9.14N

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Answer:

Without specific information about the land in question, it is difficult to provide a definitive answer. However, there are some general attributes of land that can make it more suitable for mining activities:

1. Mineral deposits: The presence of valuable mineral deposits, such as gold, copper, or iron, is the most obvious attribute that would make land suitable for mining.

2. Accessibility: A site that is easily accessible by roads or other transportation infrastructure would be more convenient and cost-effective for mining companies to operate.

3. Topography: Flat or gently sloping terrain can make it easier to construct mining facilities and move equipment and materials.

4. Soil type: The type of soil can affect the ease of excavation and the stability of mining operations.

5. Water resources: Availability of water for mining activities, such as processing and dust control, is essential.

6. Climate: The climate can impact the timing and duration of mining operations and the types of equipment needed to operate in certain conditions.

7. Legal and regulatory environment: The presence of favorable laws and regulations can make it easier for mining companies to operate and obtain necessary permits.

These are just a few examples of attributes that can make land more suitable for mining. However, it is important to note that mining can have significant environmental and social impacts, and these factors must also be taken into account when considering the suitability of land for mining.

Answer: A method of classifying stars by their temperatures and compositions.

Explanation:

The Morgan-Keenan Spectral Classification system is a method of classifying stars by their temperatures and compositions.

The primary factor used to categories stars is their temperature.

The Morgan-Keenan luminosity class (MK or MKK) was developed as a result of the Harvard spectral classification classification scheme does not completely describe the star as it cannot distinguish between stars with the same temperature but different luminosities.

Since then, class I stars have been separated into Ia-O, Ia, and Ib, and classes VI (sub-dwarf), and D (white dwarf) have been added, replacing the original roman numerals between I (supergiant star) and V (main sequence).

The original Harvard classification of the star is supplemented by the MK luminosity class in order to fully define it. For instance, the entire classification of the Sun, which is a main sequence G2 star, is G2V.

The MK luminosity class is added to the Harvard classification of the star in order to fully define it.

A method of classifying stars by their temperatures and compositions is applied in Morgan-Keenan Spectral Classification system.

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Answer:

Net force = 320N

acceleration = 8 m/s^2

Explanation:

From the diagram, the two forces are moving in the same direction, hence;

Net force on the body will be the sum of the force;

Net Force on the body = 180N + 140N

Net Force on the body = 320N

Given

Mass of the body = 40kg'

Based on Newton's second law;

a = F/m

a = 320/40

a = 8m/s^2

Hence the acceleration of the body is 8m.s^2

The distance d traveled by an object under uniformly accelerated motion while it changes its speed from v_o to v_f with an acceleration a is given by the formula:

Since the car travels initially at 16m/s and it stops, then v_0=16m/s and v_f=0. Replace those values into the formula, as well as a=-4m/s^2 to find the stopping distance for the car:

Therefore, the stopping distance for the car is 32 meters.

Answer:

No, gravitational force is a force having infinite range. It only reduces to an extent that astronauts cannot feel it.

Explanation:

Answer:

3. 9600m/s

4. 2.5m/s

Explanation:

To find the final velocity of the object which accelerates at 40m/s/s for four minutes, we first need to convert the 4 minutes to seconds. There are 60 seconds in a minute so 4 minutes is equal to 4x60 = 240 seconds.

To calculate the final velocity we just multiply the acceleration rate by the time, so 40x240=9,600 m/s

The final velocity of the object would be 9600m/s.

If an object's final velocity was 115m/s after 45 seconds then we need to find out how much it accelerated in that 45 seconds to find the starting velocity. 45x2.5=112.5 It increased in speed by 112.5m/s over 45 seconds, so its initial speed was 112.5m/s slower than its final speed. 115-112.5=2.5, the object's starting velocity was 2.5m/s.

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Answer:

The IMF

Explanation:

The IMF can influence solar weather by disrupting the earth's magnetosphere. The effect is like widening a hole; making more energy and particles enter the magnetosphere.

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The other responses are all essentially correct, but I'd want to offer a somewhat different perspective. This one is a little more technical, but it offers an intriguing perspective, in my opinion.

One of the first things I would mention is the fact that orbits are ellipses rather than circles. The phrases apogee and perigee are used because of this. The apogee is the orbit's highest point, while the perigee is its lowest point, giving the shape of an ellipse. A circular orbit is just an ellipse with the same apogee and perigee. However, apogee and perigee are not the crucial variables from an orbital perspective; rather, apoapsis and periapsis are.

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Answer:

Acceleration = Final velocity - initial velocity / time take

65-35=30 , 30/5=6

Acceleration = 6m s-2

Explanation:

Answer:

308,000 or 30.8×10^3

Explanation:

v=f×lamda

v is ?, f is 875Hz, lamda is 352m

v=875×352

v=308,000

v=30.8×10^3 m/s

Answer:

t = 2.40 s

Explanation:

It just told me

Answer:

Explanation:

a ) The motion is one dimensional , so motion is along x - axis , starting from origin ( 0 , 0 )

b ) Initial velocity is 18.5 m /s when boat is situated at origin . When he displaces by 250 m along x axis and his position is ( 250 , 0 ) along x axis , his velocity becomes 36 m /s . Both his velocity and acceleration is along x - axis.

c ) Initial velocity vi = 18.5 m /s

final velocity vf = 36 m/s

Displacement x  = 250 m

Acceleration a = ?

Most appropriate formula is given below .

vf² = vi² + 2 a x

2ax = vf² - vi²

x =  ( vf² - vi² ) / 2 a

d )

Putting the given values

36² - 18.5² / 2 x 250

= 1296 - 342.25 / 500

= 1.9 m /s².

f ) Time interval t = ?

Required formula

vf = vi + at

t = (vf - vi ) / a

Putting the values

t = (30 - 18.5) / 1.9

= 6.05 second .

0.1 km/min

Explanation:

1 km every 10 minutes

The quantity of charge on a plastic tube that has been rubbed with animal fur and gained 3. 8 x 10^9 electrons is The quantity of charge on the plastic tube is 3.8 x 10^9 electrons.

The quantity of charge on the plastic tube is 3.8 x 10^9 electrons. To calculate this value, we can use the equation q = n*e, where q is the charge, n is the number of electrons and e is the elementary charge (1.6 x 10^-19 C). Substituting in the values given, we get q = 3.8 x 10^9 * 1.6 x 10^-19 = 6.08 x 10^-10 C.  This means that the plastic tube has gained a charge of 6.08 x 10^-10 Coulombs, which is equivalent to 3.8 x 10^9 electrons.

This can be explained by the process of triboelectricity, which is the transfer of electrons between two materials due to rubbing them together. In this case, the animal fur must have had a higher electron affinity than the plastic, which caused electrons to be transferred from the fur to the plastic tube.

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Answer:evaporation or de-

vaporation  i think

The statement is True.

Weight lifting is an example of anaerobic exercise. Anaerobic exercise involves short bursts of intense physical activity that do not require significant amounts of oxygen.

Weight lifting typically involves lifting heavy weights for a short period of time, which requires the muscles to produce energy without oxygen.

During anaerobic exercise, the body relies on stored sources of energy, such as creatine phosphate and glycogen, rather than oxygen, to fuel the muscles.

Therefore, weight lifting is considered an example of anaerobic exercise.

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If you approach a light beacon while traveling at one half the speed of light (0.5c) you will measure the speed of light from the beacon to be 0.5 c.

Anti-collision lights, sometimes referred to as beacon lights or strobe lights, are a series of lights that must be installed on every aircraft in order to increase visibility to other aircraft and prevent collisions by alerting other pilots. Light-emitting diodes have lately replaced the incandescent bulbs that were previously used.

Beacon lights are most frequently made of red, amber or yellow, blue, green, and white. Red is used to convey stern warnings about hazards or danger and is most frequently seen on vehicles operated by law enforcement or fire departments.

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