Satellite A is orbiting Earth at an altitude of 500 km and Satellite B is orbiting 800 km above the surface . How does the velocity of Satellite A compare to the velocity of Satellite B ?

The correct option is A, The energy is converted to generating sound and heating the floor, rock, and surrounding air.

Energy refers to the property of an object or system that allows it to do work. Work is defined as the application of a force over a distance, and energy is required to accomplish this. Energy can exist in many forms, such as mechanical, thermal, electromagnetic, chemical, and nuclear.

The two main types of energy are kinetic energy and potential energy. Kinetic energy is the energy that an object possesses due to its motion, while potential energy is the energy that an object possesses due to its position or configuration. Energy is conserved, meaning that it cannot be created or destroyed but can only be transformed from one form to another. This is known as the law of conservation of energy,

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Complete Question;

A rock held above the ground has capacity power. because the rock falls, this capacity energy is transformed into kinetic power. eventually, the rock hits the floor and stays there. what has come about with electricity? organization of solution picks

A). The power is going to generate sound and heat the floor, rock, and surrounding air.

B). it is transformed lower back into a gravitational potential strength.

C). The rock maintains the power inner it in the form of mass energy.

D). The power is going into the ground, and as a result, the orbit of the Earth across the sun is slightly modified.

True or false: Below the wave base there is no wave action (from surface waves).  

Wave action refers to the movement of water caused by the transfer of energy from wind or other sources. Surface waves, which are waves that travel along the surface of the water, have a wave base which is the point at which the wave starts to become noticeable to the eye.

Below the wave base, there may still be some water movement due to internal waves or subsurface currents, but the surface of the water will be relatively calm and there will be no visible wave action. These internal waves and currents are caused by the movement of water within the ocean or other bodies of water and are not directly related to wind or other external sources of energy.

In summary, true or false: below the wave base there is no wave action (from surface waves).  

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Light will emerge at the same angle as it incidence on the medium.

It doesn't matter how many mediums through which light passes it will always emerge at the same angle as it is incident. As the flat bottomed glass slab will act as a glass slab and will laterally displace the light ray without changing the angle of the emergence.

When a light ray passes from a rarer to a denser medium it will bend towards normal, when a light ray passes from a denser to a rarer medium it will bend away from normal. How much the ray will bend depends on the refractive index of the material. In the case of a glass slab the amount of deviation at the point when the ray touches the dish and the deviation at the point where the ray leaves the slab nullifies each other. hence the emerging ray is parallel or latterally displaced as compared to the incident ray

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Answer:

The block that is dropped straight down will have the greatest speed before hitting the ground. This is because it has no initial horizontal velocity, so all of its potential energy is converted into kinetic energy as it falls. The other blocks have some initial horizontal velocity, so some of their potential energy is converted into kinetic energy in the horizontal direction. This means that they will have a lower speed when they hit the ground.

Explanation:

The potential energy of an object is given by the equation:

PE = mgh

KE = 1/2 mv^2

When an object is dropped, its potential energy is converted into kinetic energy. The equation for the conservation of energy can be used to express this relationship:

PE = KE

mgh = 1/2 mv^2

v^2 = 2gh

v = sqrt(2gh)

The velocity of an object that is dropped is directly proportional to the square root of the height from which it is dropped.

The blocks in the question are all dropped from the same height. However, the block that is dropped straight down has no initial horizontal velocity. The other blocks have some initial horizontal velocity. This means that the block that is dropped straight down will have a greater speed when it hits the ground than the other blocks.

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It would take 0.3639 seconds for this acceleration to occur.

Given the following data:

To find how long it takes for this acceleration to occur, we would use the first equation of motion.

Mathematically, the first equation of motion is given by the formula;

\(V = U + at\)

Substituting the values into the equation, we have;

\(12.9 = 6.03 + 2.5t\\\\2.5t = 12.9 - 6.03\\\\2.5t = 6.87\\\\t = \frac{2.5}{6.87}\)

Time, t = 0.3639 seconds

Therefore, it would take 0.3639 seconds for this acceleration to occur.

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To find the angle at which the ball enters the basket, we need to use the equations of motion for projectile motion. The equations are:
y = y0 + v0y*t - (1/2)*g*t^2
x = x0 + v0x*t
where y is the vertical position, y0 is the initial vertical position, v0y is the initial vertical velocity, g is the acceleration due to gravity, t is the time, x is the horizontal position, x0 is the initial horizontal position, and v0x is the initial horizontal velocity.

The ball enters the basket at an angle of 0° to the horizontal.

We know that
y0 = 2.4 m, v0 = 12 m/s, θ0 = 35°, and g = 9.8 m/s^2. We can find v0x and v0y using the angle:
v0x = v0*cos(θ0) = 12 m/s*cos(35°) = 9.82 m/s
v0y = v0*sin(θ0) = 12 m/s*sin(35°) = 6.92 m/s
The ball enters the basket when y = 0, so we can set the equation for y equal to 0 and solve for t:
0 = 2.4 m + 6.92 m/s*t - (1/2)*9.8 m/s^2*t^2
Using the quadratic formula, we find that t = 0.74 s or t = -0.63 s. We discard the negative value, so t = 0.74 s.
Now we can use the equation for x to find the horizontal position of the basket:
x = x0 + v0x*t = 0 + 9.82 m/s*0.74 s = 7.27 m
Finally, we can use the equation for the tangent of the angle to find the angle at which the ball enters the basket:
tan(θ) = y/x = 0/7.27 m = 0
θ = tan^-1(0) = 0°

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Answer:

1. v = 30 m/s

2. v = 5 m/s

3. f = 40 Hz

4. f = 400 Hz

5. f = 300 Hz

6. λ = 0.772 m

7. λ = 0.386 m

8. λ = 0.625 m

9. v = 100 m/s

10. v = 50 m/s

Explanation:

The relationship between frequency, wavelength, and speed of a wave is given by the following formula:

\(v = f\lambda\)

where,

v = speed of wave

f = frequency of wave

λ = wavelength

1.

f = 100 Hz

λ = 0.3 m

Therefore,

v = (100 Hz)(0.3 m)

v = 30 m/s

2.

f = 50 Hz

λ = 0.1 m

v = (50 Hz)(0.1 m)

v = 5 m/s

3.

v = 20 m/s

λ = 0.5 m

\(f = \frac{v}{\lambda} = \frac{20\ m/s}{0.5\ m}\)

f = 40 Hz

4.

v = 80 m/s

λ = 0.2 m

\(f = \frac{v}{\lambda}=\frac{80\ m/s}{0.2\ m}\)

f = 400 Hz

5.

v = 120 m/s

λ = 0.4 m

\(f = \frac{v}{\lambda}=\frac{120\ m/s}{0.4\ m}\)

f = 300 Hz

6.

v = 340 m/s

f = 440 Hz

\(\lambda = \frac{v}{f}=\frac{340\ m/s}{440\ Hz}\\\)

λ = 0.772 m

7.

v = 340 m/s

f = 880 Hz

\(\lambda = \frac{v}{f}=\frac{340\ m/s}{880\ Hz}\\\)

λ = 0.386 m

8.

v = 250 m/s

f = 400 Hz

\(\lambda = \frac{v}{f}=\frac{250\ m/s}{400\ Hz}\\\)

λ = 0.625 m

9.

f = 50 Hz

λ = 2 m

v = (50 Hz)(2 m)

v = 100 m/s

10.

f = 100 Hz

λ = 0.5 m

v = (100 Hz)(0.5 m)

v = 50 m/s

Answer:

it B

Explanation:

I KNOW IT

Answer: A wave is a disturbance that transmits energy as long as it is not transmitting matter?

Answer:

C.) vector C

Explanation:

From the graph provided:

Four vectors are present :

Vectors a, b, c and d.

The x-component of the vector is its magnitude along the x-axis.

Taking the coordinate of each vector:

Vector a = (1,4) : length of x- component = 1

Vector b = (1, 1) : length of x- component = 1

Vector c = (4, -4) : length of x- component = 4

Vector d = (-3, 4) : length of x- component = - 3

Therefore, vector c has an x-component length of 4

The pressure exerted at the base of the container is 100 kg/m².

The pressure at the base of the container can be calculated using the formula:

pressure = force divided by area

where force is the weight of the water and area is the base of the container.

The volume of the water in the container is:

volume = base area x depth = 50 cm x 30 cm x 5 cm

The weight of the water can be calculated using the density of water (PW) and the volume of the water:

Weight = volume x density = 1000 kg/m³ x (50 cm x 30 cm x 5 cm)

Convert cm to m: 1000 kg/m³ x (0.5 m x 0.3 m x 0.05 m)

= 15 kg

Base area = 50 x 30 = 1500 cm².Converting cm² to m² equals 0.15 m².

15 kg force = weight

Pressure = force/area, which equals 15 kg / 0.15 m² = 100 kg/m².

The pressure exerted at the base is 100 kg/m².

The definition of pressure is force per unit area. The pressure at the base of a container filled with water can be calculated by dividing the weight of the water by the area of the base. In this case, the weight of the water is 15 kg, and the area of the base is 0.15 m², thus the pressure exerted is 100 kg/m².

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Answer:

10 ohms

Explanation:

V = IR

2 v is the drop in the battery

2 = .2 R

R = 10 ohms

Answer:

See below

Explanation:

An object at rest tends to stay at rest unless acted on by a force

An object at rest will stay at rest until a force touches it.

such has..

a pencil, not moving and still.

you tap the pencil, or pick it up. by using your force to pick it up.

Answer: 5.96m/s

Explanation:

Given the following :

Mass of car (m) = 1500kg

Velocity (V) = 5.25m/s

Forward force of engine = 1250N

Diatance moved = 4.8m

Final Velocity =?

Final kinetic energy = Initial kinetic energy + work done by engine

Initial kinetic energy = 0.5 × mass × velocity^2

Initial kinetic energy = 0.5 × 1500 × 5.25^2

Initial kinetic energy = 20671.875 J

Work done by engine = Force × distance

Work done by engine = 1250 × 4.8 = 6000J

Final kinetic energy = (20671.875 + 6000) J

= 26671.875 J

From kinetic energy = 0.5mv^2

26671.875 = 1/2 × 1500 × v^2

53343.75 = 1500v^2

v^2 = 35.5625

v = sqrt(35.5625)

v = 5.96m/s

(a) The charge carrier density doubles,(b) The current density doubles, (c) The electron drift velocity doubles, (d) The average time interval between collision halved.

I = nq\(v_{d}\)A

where n is the charge/volume

I is the current.

q is the charge per carrier

\(v_{d}\) is the drift velocity of the charge carriers

A is the cross-sectional area of current flow

Here,

a) The charge carrier density (n) doubles if I doubles.

b) The charge carrier density (J = I/A is the current density).  If I doubles, J doubles.

c)  The electron drift velocity (\(v_{d}\)) doubles if I doubles.

d)  The average time interval between collisions depends inversely on \(v_{d}\).  If I doubles, \(v_{d}\) doubles, so the average time between collisions is halved.

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If energy is conserved, then initial (PE + KE) = final (PE + KE). So, the correct option is A.

The law of conservation of energy states that, energy can neither be created nor be destroyed, but can be transformed from one form to another.

Here,

According to law of conservation of energy,

The total energy of an isolated system remains constant. That means, the total energy of the system in the initial state will be same as that in the final state.

The total mechanical energy is the sum of kinetic energy and potential energy.

TE = KE + PE

Therefore, the energy to be conserved in the system,

Initial TE = Final TE

So, Initial (KE + PE) = Final (KE + PE)

Hence,

If energy is conserved, then initial (PE + KE) = final (PE + KE).

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Answer:Answer:

See diagram for answers. The force and acceleration vectors are directed inwards towards the center of the circle and the velocity vector is directed tangent to the circle.

Explanation:

Answer:

A (cytosine)

Explanation:

ACGT

The basketball player must be going at 3.57 m/s when she leaves the ground.

Given the following data:

We know that acceleration due to gravity (a) for an object or body is equal to 9.8 meter per seconds square.

To find how fast (velocity) the basketball player must be going when she leaves the ground, we would use the third equation of motion;

\(V^2 = U^2 + 2aS\)

Where:

Substituting the given parameters into the formula, we have;

\(V^2 = 0^2 + 2(9.8)(0.65)\\\\V^2 = 12.74\\\\V = \sqrt{12.74}\)

Final velocity, V = 3.57 m/s

Therefore, the basketball player must be going at 3.57 m/s when she leaves the ground.

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The gravitational force (Fg) for the first column is 1.96 x 10⁷ N.

The gravitational force (Fg) for the second column is 2.48 x 10⁷ N.

The gravitational force (Fg) for the third column is 3.24 x 10⁷ N.

The gravitational force (Fg) for the fourth column is 4.4 x 10⁷ N.

The gravitational force (Fg) for the fifth column is 6.36 x 10⁷ N.

The gravitational force (Fg) for the sixth column is 9.94 x 10⁷ N.

The gravitational force (Fg) for the seventh column is 1.77 x 10⁸ N.

Newton's law of universal gravitation states that every two objects in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between the masses.

F = Gm₁m₂/r²

F = (Gm₁m₂) x 1/r²

where;

The gravitational force (Fg) for the first column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg = (6.626 x 10⁻¹¹ x 4 x 10⁹ x 6 x 10⁹) x  1/r²

Fg = 1.59 x 10⁹  x 0.0123

Fg = 1.96 x 10⁷ N

The gravitational force (Fg) for the second column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0156

Fg = 2.48 x 10⁷ N

The gravitational force (Fg) for the third column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0204

Fg = 3.24 x 10⁷ N

The gravitational force (Fg) for the fourth column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0277

Fg = 4.4 x 10⁷ N

The gravitational force (Fg) for the fifth column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0400

Fg = 6.36 x 10⁷ N

The gravitational force (Fg) for the sixth column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0625

Fg = 9.94 x 10⁷ N

The gravitational force (Fg) for the seventh column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.1111

Fg = 1.77 x 10⁸ N

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Answer:

1299N

Explanation:

GIven data

Weight W= 1500N

Angle Ф= 30°

The applied force up the frictionless ramp is gotten by applying the formula below

F= WcosФ

substitute

F=1500 cos 30

F = 1500*0.8660

F= 1299N

Hence the applied force is 1299N

Answer:

it took by 2 and made it 2 yrs

Explanation:

An Oscillator makes 270 vibrations in 3 minutes.

It is know us that the number of vibrations in 4 minutes is given as 360.

Let us follow the basic principle of division to figure out the minimum vibrations that take place in one minute.

The formula used in this question is given below :

Total number of vibrations ÷ Total time taken

Given;

360 ÷ 4 = 90

Therefore, in one minute the oscillator makes 90 vibrations.

Then in 3 minutes, the given oscillator makes ;

90 × 3 = 270

Hence, An Oscillator makes 270 vibrations in 3 minutes.

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The statement that explains why James, who operates an apple orchard that sells a very rare type of gourmet apple, would probably choose not to participate in contract production is because he independently grows a unique product, he is already locked in to the best price of the market (option A).

Contract manufacturing or production occurs when a small business hires another company to produce its products.

This enables small business individuals to begin selling their products without obtaining the large amount of capital necessary to build and run a factory.

However, according to this question, James is a business individual who operates an apple orchard that sells a very rare type of gourmet apple.

Therefore, James would not need to participate in contract production because he independently grows a unique product, he is already locked in to the best price of the market.

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Answer:

If a magnet is moved more quickly through a coil, the induced current in the coil will increase, which would result in a brighter light bulb. This is because the rate of change of magnetic flux through the coil is directly proportional to the magnitude of the induced current.

Moving the magnet more quickly through the coil will increase the rate of change of magnetic flux, which in turn increases the magnitude of the induced current. As a result, the bulb would be brighter.

On the other hand, if the magnet is moved more slowly through the coil, the rate of change of magnetic flux through the coil would decrease, leading to a decrease in the induced current and hence a dimmer light bulb.

The brightness of the light bulb is directly proportional to the rate of change of magnetic flux through the coil, which is determined by the speed at which the magnet is moved through the coil.

Answer:

The brightness of the light bulb does not change if the magnet is moved through the coil more quickly.

Explanation:

The brightness of the light bulb is determined by the amount of current flowing through the coil, which is determined by the strength of the magnetic field and the resistance of the wire in the coil. The speed at which the magnet moves through the coil does not affect the strength of the magnetic field or the resistance of the wire, so the brightness of the light bulb remains constant.

The ball will be traveling at a speed of approximately 18.9 m/s when it strikes the sidewalk below.

What is Speed?

It is defined as the distance traveled per unit of time, usually expressed in units such as meters per second (m/s), kilometers per hour (km/h), or miles per hour (mph).

The horizontal component of the velocity remains constant throughout the motion, and it is given by:

Vx = Vcosθ

where V is the initial velocity of the ball and θ is the angle of projection. In this case, V = 25 m/s and θ = 45°, so:

Vx = 25*cos(45°) = 17.68 m/s

The vertical component of the velocity changes due to the acceleration due to gravity (g = 9.8 m/s^2). At the highest point, the vertical component of the velocity becomes zero, and the ball starts falling downwards. The final velocity (v) of the ball just before hitting the ground can be calculated using the following equation:

v^2 = u^2 + 2as

where u is the initial velocity in the vertical direction, a is the acceleration due to gravity, s is the distance traveled in the vertical direction, and v is the final velocity.

Initially, the ball is at a height of 12.0 m above the ground, so s = 12.0 m. The initial velocity in the vertical direction (Vy) is given by:

Vy = Vsinθ

where V is the initial velocity of the ball and θ is the angle of projection. In this case, V = 25 m/s and θ = 45°, so:

Vy = 25*sin(45°) = 17.68 m/s

When the ball hits the ground, its final velocity in the vertical direction is zero. Therefore, we can write:

v^2 = u^2 + 2as

0 = (17.68)^2 + 2*(-9.8)*12.0 - final velocity^2

final velocity = 18.9 m/s (approx)

Therefore, the ball will be traveling at a speed of approximately 18.9 m/s when it strikes the sidewalk below.

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5 second  will it take for a bug to travel five meters across the floor if it is traveling at 1 m/s.

Distance is the length of an object's real route in its entirety. The displacement of an item between two points is defined as the straight line distance between those two places when directed from one position to another.

The metre is the SI unit for measuring distance and displacement (m).

6.Given:

Distance = 5 m

Speed = 1 m/s

Time = ?

Time = Distance / Speed

= 5 / 1

= 5 s

7.Given:

Distance (D) = 200m

Velocity (v) = 1.5m/s

Time (t) =?

Distance = velocity × time

D = v × t

t = D/v

t = 200 / 1.5

t = 200 × 10 / 15

t = 200 × 2 / 3

t = 400/3

t = 133.34s

Thus, 5 second will it take for a bug to travel 5 meters. 133.34swill it takes to get to your class.

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6. The number of seconds to cover 5 meters is 5 seconds.

7. The number of seconds to cover 200 meters is 133.33 seconds.

Speed is described as the distance traveled by a particle or commodity in an hour. It is a hierarchy parameter. It is the proportion of length to the time span.

We know that the speed formula

Speed = Distance/Time

6. If it is traveling at 1 m/s, then the number of seconds to cover 5 meters is given as,

1 = 5 / t

t = 5 seconds

7. If it is traveling at 1.5 m/s, then the number of seconds to cover 200 meters is given as,

1.5 = 200 / t

t = 133.33 seconds

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Peck drilling might be used instead of standard drilling with a 0.25" diameter hole which is 3 inches deep on an aluminum part to prevent chip buildup and breakage of the drill bit, especially when drilling deep holes.

Peck drilling is a drilling technique that involves drilling a hole incrementally, lifting the drill bit out of the hole periodically to break up the chips and clear the hole. This technique is especially useful when drilling deep holes or when drilling materials that tend to produce long, stringy chips that can clog the drill bit and cause it to break.

In the case of a 0.25" diameter hole that is 3 inches deep on an aluminum part, standard drilling may cause chip buildup, which can increase the friction between the drill bit and the workpiece, leading to heat buildup and potential breakage of the drill bit. Peck drilling, on the other hand, allows for more efficient chip evacuation and reduces the risk of drill bit breakage.

For example, a peck drilling cycle might involve drilling 0.5 inches into the workpiece, then lifting the drill bit out of the hole to break up the chips and clear the hole, before drilling another 0.5 inches into the workpiece, and repeating the process until the full depth of the hole is reached.

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In order to compare the numbers, let's put all of them into the decimal form:

We can see that the greater one is 26.8 (all other numbers are close to 2, and this one is close to 27).

The numbers in decrescent order are:

26.8, 271%, 2.62, 2 2/5, 2.26.

Answer:

26.8

Explanation:

2.26 < 2.4 < 2.62 < 271/100 = 2.71 < 26.8