Sausage is 1/2 inch thick roll is 6 inches long how many pieces can be cut

Answer:

Gordon types 68 words per minute

Step-by-step explanation:

2584/38=68

Answer:

Do you have weight

Step-by-step explanation:

Are these tests weight the same or different?

Answer:

D

Step-by-step explanation:

In total, there are 5 units (2 + 3). Then, divide 2000 by 5, which equals into 400. Finally, because Fatima takes 3 units, we use 400 times 3, making it D.

AC=5cm

CB=4cm

hypotenuse=5²+4²=25+16=41

hypotenuse=√41=6.40cm

Answer:

Cevap A şkkı

İyi dersler

By using the multiple regression equation, the predicted y-values for the values of the given independent variables include the following:

(a) ý = 207.02.

(b) ý = 194.18.

(c) ý = 270.02.

(d) ý = 305.42.

In Statistics and Mathematics, a regression line simply refers to a statistical line that best describes the behavior of a data set. This ultimately implies that, a regression line refers to a line which best fits a set of data.

Next, we would determine the predicted y-values for the values of the given independent variables as follows;

ý = -51.7+03x₁ + 4.8x₂

(a) x₁ = 72 and x₂ = 8.9

ý = -51.7+03(72) + 4.8(8.9)

ý = 207.02.

(b) x₁ = 65 and x₂ = 10.6

ý = -51.7+03(65) + 4.8(8.9)

ý = 194.18.

(c) x₁ = 81 and x₂ = 16.4

ý = -51.7+03(81) + 4.8(16.4)

ý = 270.02.

(d) x₁ = 88 and x₂ = 19.4

ý = -51.7+03(88) + 4.8(19.4)

ý = 305.42.

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The length of the curve R(t) = \(3t^2 i + 4t^3 j + 2k\) over the interval [1,4] is L = 3.5.

To find the length of the curve defined by a vector-valued function over an interval, we use the formula:

L = ∫[a,b] √[ \((dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2\) ] dt

Given the vector-valued function R(t) = \(3t^2 i + 4t^3 j + 2k\), we need to compute the derivatives with respect to t.

dx/dt = d/dt\((3t^2)\) = 6t

dy/dt = \(d/dt (4t^3) = 12t^2\)

dz/dt = d/dt (2) = 0

Now, substitute these derivatives into the length formula:

L = ∫[1,4] √\([ (6t)^2 + (12t^2)^2 + 0^2 ]\)dt

L = ∫[1,4] √\([ 36t^2 + 144t^4 ]\) dt

L = ∫[1,4] √\([ 36t^2(1 + 4t^2) ]\) dt

L = ∫[1,4] 6t√\((1 + 4t^2)\) dt

To solve this integral, we can use a substitution. Let u = 1 + \(4t^2\), then du = 8t dt. Rearranging, we have dt = du/(8t).

L = ∫[1,4] 6t√u du/(8t)

L = (3/4) ∫[1,4] √u du

L = \((3/4) [ (2/3)u^(3/2)\) ] from 1 to 4

L =\((3/4) [ (2/3)(4^(3/2) - 1^(3/2))\) ]

L = (3/4) [ (2/3)(8 - 1) ]

L = (3/4) [ (2/3)(7) ]

L = (1/2)(7)

L = 7/2

L = 3.5

Therefore, the length of the curve R(t) = \(3t^2 i + 4t^3 j + 2k\) over the interval [1,4] is L = 3.5.

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Answer:

55.9 m

Step-by-step explanation:

The pool measures;

Length = 50 m

Width = 25 m

Now, swimming from one corner to the other means swimming from end of length to end of width which will form a right angle triangle.

So the distance one will swim can be denoted by d and solved using pythagoras theorem.

Thus;

d = √(50² + 25²)

d = √(2500 + 625)

d = √3125

d = 55.9 m

Answer:

5² · 10 + 10² - 2³

Step-by-step explanation:

10(5 · 5 + 10) − 2 · 2 · 2 =

= 5² · 10 + 10² - 2³

Answer:

top left corner

Step-by-step explanation:

adding the 3 shifts it up

and subtracting one shift it right

Answer: 142/1

Step-by-step explanation:

Answer:

1.42 or 71/50

Step-by-step explanation:

In order to get the answer just divide.

71÷60=1.42

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Answer:

Banana made=3.22

Pumpkin made=7.86

Rocky road ice cream made=1.89

Step-by-step explanation:

From the question we are told that

1st year sales(banana, pumpkin, and rocky road ice cream) \(S_1= 13\%\)

2nd year sales:\(S_2=18.1\%\)

Rocky road sales doubled

Banana sales increased by 50%

Pumpkin sales increased by 20%

Rocky road ice cream had one less percent then banana

Let

Banana =x

Pumpkin=y

Rocky road ice cream=z

Generally the first year equation is given mathematically as

\(x+y+z=13......(1)\)

Generally the second year equation is given mathematically as

100% increase in Rocky road ice cream sales()z i.e double

\(2*z=2z\)

50% increase in banana ice cream sales()x

\(=>1*0.50=0.5\\=>0.5+1x=1.5x\)

20% increase in pumpkin(y)

\(=>1*0.20=0.2\\=>0.2+1x=1.2y\)

Therefore second year equation is given as

\(1.5x+1.27y+2z=18.1.....(2)\)

Generally where rocky road ice cream had one less percent of sales than the banana ice cream the equation is given as

\(1.5x-2z=1........(3)\)

Therefore combining the three equations

x+y+z=13

1.5x+1.27y+2z=18.1

1.5x-2z=1

matrix form

\(\begin {bmatrix}1 & 1& 1 & 13\\1.5 & 1.2 & 2 & 18.1\\1.5 & 0 & -2 & 1\end{bmatrix}\)

Generally the determinant of the first three columns

\(\triangle=1.8\)

Solving with Crammers Rule by solving Determinant when;

Column 4 replace column 1

\(\triangle_1=5.8\)

Column 4 replace column 2

\(\triangle_2=14.15\)

Column 4 replace column 3

\(\triangle_3=3.4\)

Therefore x is given my

\(x=\frac{\triangle_1}{\triangle}\)

\(x=\frac{5.8}{1.8}\)

\(x=3.22\)

Therefore y is given my

\(y=\frac{\triangle_2}{\triangle}\)

\(y=\frac{14.15}{1.8}\)

\(y=7.86\)

Therefore z is given my

\(z=\frac{\triangle_3}{\triangle}\)

\(z=\frac{3.4}{1.8}\)

\(z=1.89\)

Therefore

Banana made=3.22

Pumpkin made=7.86

Rocky road ice cream made=1.89

Answer:

equation: 2(2w + 2) = 60

length = 16

width = 14

Step-by-step explanation:

width = w

length = w + 2

perimeter = 2(w + w + 2) = 60

equation: 2(2w + 2) = 60

4w + 4 = 60

4w = 56

w = 14

width = 14

length = w + 2 = 14 + 2 = 16

length = 16

The calculated Cp value is 1.17. The goal for this process is a Cp of 1.33. Since the calculated Cp is lower than the desired value, the process is not considered capable of meeting the specified goal. This indicates that there may be a need for process improvement to achieve the desired capability.

Cp is a statistical tool used in Six Sigma methodology to measure the process capability of a manufacturing process. It is calculated by dividing the allowable spread (the difference between the USL and LSL) by six times the standard deviation.

In this case, the USL is 14 and the LSL is 0, which means the allowable spread is 14. The standard deviation is given as 2. So, Cp can be calculated as follows:

\(Cp = (USL - LSL) / (6 x Standard Deviation)\)

Cp = (14 - 0) / (6 x 2)
Cp = 1.17

A Cp value of 1 indicates that the process is barely capable of meeting the specifications. A Cp value of less than 1 indicates that the process is not capable of meeting the specifications. A Cp value greater than 1 indicates that the process is capable of meeting the specifications.

In this case, the goal is to have a Cp value of 1.33, which indicates that the process is capable of meeting the specifications with some margin. However, since the calculated Cp value is only 1.17, it indicates that the process is not capable of meeting the specifications as per the desired goal. Therefore, some improvements in the process are required to achieve the desired goal.

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The Cp is 1.2

Yes, the process is capable with a goal of 1.33

We need to know that Cp measures the process capability with respect to its specification using Upper Specification Limit (USL) and Lower Specification Limit (LSL).

The formula for calculating Cp is represented as;

Cp = USL - LSL/6δ

Such that the parameters are expressed as;

Now, substitute the values, we get;

Cp = 14 - 0/6(2)

expand the bracket

Cp = 14/12

Divide the values, we get;

Cp = 1. 2

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If the parties to a contract intended a third party to benefit from the contract, that third party is referred to as a "third-party beneficiary" and has the power to enforce the contract for breach.

A third-party beneficiary is someone who is not a party to the contract but is intended to receive a benefit or have rights under the contract.

The rights and ability to enforce the contract by a third-party beneficiary generally depend on the specific terms and intent of the contract.

There are two main types of third-party beneficiaries: intended beneficiaries and incidental beneficiaries.

An intended beneficiary is specifically identified in the contract as someone who is intended to benefit directly from the contract.

An incidental beneficiary, on the other hand, is someone who may receive an unintended benefit from the contract but does not have enforceable rights.

To have the power to enforce the contract, an intended third-party beneficiary usually needs to demonstrate that they are a direct and intended beneficiary of the contract and that the contracting parties clearly intended to confer enforceable rights upon them.

This can be established through the language of the contract, the circumstances surrounding its formation, and the parties' intentions.

If a breach of the contract occurs, a third-party beneficiary with enforceable rights typically has the power to sue for damages or seek specific performance.

However, it's important to note that the rights and remedies available to third-party beneficiaries can vary based on the jurisdiction and the specific contract terms.

It is advisable to consult with legal counsel to understand the specific rights and remedies available in a particular situation.

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Step-by-step explanation:

i)   \(\sf 3,25 =\dfrac{13}{4} \\\\ Then :\\\\ 1 \ cans -\$3,25 \\\\8 \ cans -\$\ x \\\\ x=\dfrac{13}{4} \cdot 8=\$26 \Rightarrow yes \\\\ \rm \boldsymbol { \rm Answer: \ 8 \ cans \ of \ energy \ \ costs \ \exactly \ 26\$}\)

Answer is:

A. Yes …..

a) The minimum value of the function f(x) = xcos(x) in the range 0 ≤ x ≤ 5 is approximately -4.92, and it occurs at x ≈ 3.38.

b) The maximum value of the function f(x) = xcos(x) in the range 0 ≤ x ≤ 5 is approximately 4.92, and it occurs at x ≈ 1.57 and x ≈ 4.71.

To find the minimum and maximum values of the function f(x) = xcos(x) in the specified range, we need to evaluate the function at critical points and endpoints.

a) To find the minimum, we look for the critical points where the derivative of f(x) is equal to zero. Taking the derivative of f(x) with respect to x, we get f'(x) = cos(x) - xsin(x). Solving cos(x) - xsin(x) = 0 is not straightforward, but we can use numerical methods or a graphing calculator to find that the minimum value of f(x) in the range 0 ≤ x ≤ 5 is approximately -4.92, and it occurs at x ≈ 3.38.

b) To find the maximum, we also look for critical points and evaluate f(x) at the endpoints of the range. The critical points are the same as in part a, and we can find that f(0) ≈ 0, f(5) ≈ 4.92, and f(1.57) ≈ f(4.71) ≈ 4.92. Thus, the maximum value of f(x) in the range 0 ≤ x ≤ 5 is approximately 4.92, and it occurs at x ≈ 1.57 and x ≈ 4.71.

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These are the exact solutions for x in terms of the square root of 17.

To solve the equation \(2x^2 -1 =3x\)for x, we can rearrange the equation to bring all terms to one side:

\(2x^2 -1 =3x\)

Now we have a quadratic equation in the form \(ax^2 + bx +c = 0\) where a = 2 ,b= -3, and c= -1.

To solve this quadratic equation, we can use the quadratic formula:

\(x = \frac{-b + \sqrt{b^2 -4ac} }{2a}\)

Plugging in the values for a, b, c we get:

\(x = \frac{-(-3) + \sqrt{(-3)^2 - 4(2) (-1)} }{2(2)}\)

Simplifying further:

\(x = \frac{3 + \sqrt{9+8} }{4} \\x= \frac{3+ \sqrt{17} }{4}\)

Therefore, the solutions to the equation \(2x^2 -1 =3x\):

\(x= \frac{3+ \sqrt{17} }{4}\\x= \frac{3- \sqrt{17} }{4}\)

These are the exact solutions for x in terms of the square root of 17.

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Answer:

area=3/5      

length=7/8    

width=?

so  3/5=7/8 times ?

multiply both sides by 8/7 to clear fraction (7/8 times 8/7=56/56=1 and 1 times ?=? so)

24/35=?  

the width= 24/35 mile

The cοrrect system represented in the graph is y > x² + 4x - 2 and y > 3x + 4.

Mathematical expressiοns with inequalities οn bοth sides are knοwn as inequalities. In an inequality, we cοmpare twο values as οppοsed tο equatiοns. In between, the equal sign is changed tο a less than (οr less than οr equal tο), greater than (οr greater than οr equal tο), οr nοt equal tο sign.

The system represented in the graph is y > x² + 4x - 2 and y > 3x + 4.

The graph οf the system is a shaded regiοn abοve twο curves. One curve is a parabοla οpening upward, given by y = x² + 4x - 2. The οther curve is a line with a pοsitive slοpe, given by y = 3x + 4. The shaded regiοn abοve bοth curves satisfies the inequalities y > x² + 4x - 2 and y > 3x + 4.

Therefοre, the cοrrect system represented in the graph is y > x²+ 4x - 2 and y > 3x + 4.

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They will pay me $5368709.12 on the 30th day

Compound interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on principal plus interest.

In simple terms, compound interest is interest you earn on interest.

We start with a one cent.

We have $0.01 x 2 the following day.

We have $0.01 x 2 x 2 the following day.

and so forth

We will have $0.01 x 2^n-1 on day n.

That is compound interest at work. It equates to daily payments of 100% interest. It immediately soars to inconceivable heights with even a penny as your initial investment.

Thus, on the 30th day, you have $0.01 x 2^29 = $5 368 709.12.

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Step-by-step explanation:

\( \frac{2}{3} x = - 10 \\ \frac{2x}{3} = - 10 \\ 2x = - 10 \times 3 \\ 2x = - 30 \\ x = \frac{ -30}{2} \\ x = - 15\)

The line integral of F around the perimeter of the given rectangle is equal to 20.

To find the line integral, we need to parameterize the path along the perimeter of the rectangle and calculate the line integral of F along that path.

The perimeter of the rectangle consists of four line segments: (5,0) to (5,2), (5,2) to (2,2), (2,2) to (-2,2), and (-2,2) to (-2,0).

Let's go through each segment one by one:

(5,0) to (5,2):

Parameterize this segment as r(t) = (5, t), where 0 ≤ t ≤ 2. The differential vector dr = (0, dt).

Substitute the parameterization into F: F(r(t)) = 5(5 + t)i + 4sin(t).

Calculate the dot product: F(r(t)) · dr = [5(5 + t)i + 4sin(t)] · (0, dt) = 0 + 4sin(t)dt = 4dt.

Integrate over the interval: ∫[0,2] 4dt = [4t] from 0 to 2 = 4(2 - 0) = 8.

Parameterize this segment as r(t) = (5 - t, 2), where 0 ≤ t ≤ 3. The differential vector dr = (-dt, 0).

Substitute the parameterization into F: F(r(t)) = 5(5 - t)i + 4sin(2) = (25 - 5t)i + 4sin(2).

Calculate the dot product: F(r(t)) · dr = [(25 - 5t)i + 4sin(2)] · (-dt, 0) = -(25 - 5t)dt.

Integrate over the interval: ∫[0,3] -(25 - 5t)dt = [-25t + (5t^2)/2] from 0 to 3 = -75 + 45/2 = -60/2 + 45/2 = -15/2.

(2,2) to (-2,2):

Parameterize this segment as r(t) = (t, 2), where 2 ≥ t ≥ -2. The differential vector dr = (dt, 0).

Substitute the parameterization into F: F(r(t)) = 5(t + 2)i + 4sin(2) = (5t + 10)i + 4sin(2).

Calculate the dot product: F(r(t)) · dr = [(5t + 10)i + 4sin(2)] · (dt, 0) = (5t + 10)dt.

Integrate over the interval: ∫[-2,2] (5t + 10)dt = [(5t^2)/2 + 10t] from -2 to 2 = (20 + 40)/2 = 60/2 = 30.

(-2,2) to (-2,0):

Parameterize this segment as r(t) = (-2, 2 - t), where 2 ≥ t ≥ 0. The differential vector dr = (0, -dt).

Substitute the parameterization into F: F(r(t)) = 5(-2 + 2 - t)i + 4sin(2 - t) = -ti + 4sin(2 - t).

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easy. 2 hours for 10 trees? 10x15=150, therefore if you multiply one thing by 10, you must multiply the other (2). 2x10=20 so 20 hours for 150 trees.

The mean of T is -10 and the standard deviation of T is √425 when X1 and X2 are independent.

To find the mean of T, we can use the properties of expected values. Since T = 11X1 - 2X2, the mean of T can be calculated as follows: E(T) = E(11X1) - E(2X2) = 11E(X1) - 2E(X2) = 11(10) - 2(20) = -10. To find the standard deviation of T, we need to consider the variances and covariance of X1 and X2. Since X1 and X2 are independent, the covariance between them is zero. Therefore, Var(T) = Var(11X1) + Var(-2X2) = 11^2Var(X1) + (-2)^2Var(X2) = 121(2^2) + 4(3^2) = 484 + 36 = 520. Thus, the standard deviation of T is √520, which simplifies to approximately √425. When X1 and X2 have a correlation of -0.76, the mean and standard deviation of T remain the same as in the case of independent variables. To calculate the probability P(T > 30) when X1 and X2 are independent, normally distributed variables, we need to convert T into a standard normal distribution. We can do this by subtracting the mean of T from 30 and dividing by the standard deviation of T. This gives us (30 - (-10))/√425, which simplifies to approximately 6.16.  We can then look up the corresponding probability from the standard normal distribution table or use statistical software to find P(T > 30). The probability will be the area under the standard normal curve to the right of 6.16.

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Answer:

3 = D

4 = I

6 = G

7 = J

8 = B

9 = A & C

10 = H

Step-by-step explanation: