How to write a solution to the equation x^2=5 using exponents and radicals
Answer:
x = sqrroot(5)
Step-by-step explanation:
The radical form of x²=5 is x= ±√5.
What is Radical form?The √ symbol that is used to denote square root or nth roots.
An expression with a square root is referred to as a radical expression. Radicand: A value or phrase included within the radical symbol.
Radical notation is the usage of a root in an expression, such as the square or cube root.
For example, radical form is ∛3 = √27.
Given:
x²=5
Now, we have to write it in the radical form.
So, we can write
x= ±√5
Hence, the radical form of x²=5 is x= ±√5.
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I really need help understanding proofs. Anyone please explain within a few mins or so?
Answer:
so where is your question..I'm good in proving
(1/2)^3 x 2 need help on this
Answer:
1/2³ = 0.125
0.125 × 2 = 0.25
answer = 0.25
A person is walking at a rate of 9 feet every 4 seconds.
(a) Find their speed, i.e. the rate the distance
Answer:
v = 2.25 ft/s
Step-by-step explanation:
Given that,
A person is walking at a rate of 9 feet every 4 seconds.
We need to find their speed. We know that, the speed of total distance divided by time taken. So,
\(v=\dfrac{d}{t}\\\\v=\dfrac{9\ ft}{4\ s}\\\\v=2.25\ ft/s\)
So, the speed is 2.25 ft/s.
A (non-zero) number multiplied by zero equals zero, whereas a non-zero number divided by zero is undefined.
a. True
b. False
Please help me with this question :)
Answer:
The 3rd option is the correct answer.
Step-by-step explanation:
(-24 *|x|)/8= -30
-24*|x|= -30 *8
-24*|x| =-240
|x|= -240/-24
|x| =10
x= 10 or -10
Answer:
C. Where the points are at 10 and -10.
Step-by-step explanation:
Simply solve this equation by doing opposite operations to isolate and ultimately find x.
\(\frac{-24|x|}{8} =-30\)
Multiple both sides by 8 to get rid of it.
-24|x|=-240
Now, divide both sides of the equation by -24 to get
|x|=10
x=10, x=-10
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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-2|3x + 2| =-12 NEED HELP ASAP
Answer:
x = 4/3
Step-by-step explanation:
First, we cancel the -2 by dividing both sides by -2, so we have
|3x + 2| = -12÷-2
|3x + 2| = 6,
3x + 2 = 6, collecting like terms
3x = 6 - 2
3x = 4
x = 4/3
Identify the cross section that results from slicing the three-dimensional figure.
A)
prism
B)
rectangle
square
D
triangle
answer is b
Answer:
b
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
i thing bbbbbbbbbbbbb
Please answer asap
Use the graph to determine the input value for which f(x) = g(x) is true.
x = 0.5
x = 1
x = 1.5
x = 2
Find the LCM of the polynomials.
x² - x - 42
x2 + x - 56
Answer:
x^3+7x^2-50x-336 or (x-7)(x+6)(x+8)
Step-by-step explanation:
Factor each equation.
x^2-x-42= (x-7)(x+6)
x^2+x-56= (x-7)(x+8)
The common factor is (x-7), therefore the other factors of the expressions must multiply to find the common factor.
(x-7)(x+6)(x+8)=x^3+7x^2-50x-336.
PLEASE PLEASE PLEASE PLEASE (5'1, 5'2, 5'3, 5'4, 5'5, 5'6, 5'7, 5'8, 5'9, 5'9, 5'10, 5'11, 5'12) PLEASE FIND THE ABSOLUTE DEVIATION MAN PLEASE
Answer:
Answer:
A. mean: 5.75
B. 1.8958
Thank you! Please mark me brainliest so that I get encouraged to answer more great questions like this one!
Which of the following tables represents a linear function?
x −4 −1 0 1 2
y −4 2 −4 0 2
x 1 1 1 1 1
y −3 −2 −1 0 1
x −6 −1 0 2 3
y −7 negative sixteen thirds −5 negative thirteen thirds −4
x −2 −1 0 2 4
y −4 negative two thirds −1 two thirds 1
The tables representing linear functions are Table 2 and Table 4.
Table 1. Since the differences are not constant, Table 1 does not represent a linear function.
Table 2. Table 2 represents a linear function.
Table 3. Since the ratios are not constant, Table 3 does not represent a linear function.
Table 4. Since the differences are constant, Table 4 represents a linear function.
A linear function is a function where the relationship between the independent variable (x) and the dependent variable (y) can be expressed as a straight line.
To determine which of the given tables represents a linear function, we need to check if the differences or ratios between the y-values are constant for the corresponding x-values.
Let's examine each table:
Table 1:
x: -4, -1, 0, 1, 2
y: -4, 2, -4, 0, 2
The differences between consecutive y-values are not constant. For example:
2 - (-4) = 6
-4 - 2 = -6
Since the differences are not constant, Table 1 does not represent a linear function.
Table 2:
x: 1, 1, 1, 1, 1
y: -3, -2, -1, 0, 1
The x-values are all the same, indicating that the y-values do not change based on the value of x.
This means that for any value of x, the corresponding y-value remains constant.
Table 2 represents a linear function.
Table 3:
x: -6, -1, 0, 2, 3
y: -7, -16/3, -5, -13/3, -4
The ratios between consecutive y-values are not constant. For example:
(-16/3) / (-7) = 16/21
(-5) / (-16/3) = 15/16
Since the ratios are not constant, Table 3 does not represent a linear function.
Table 4:
x: -2, -1, 0, 2, 4
y: -4, -2/3, -1, 2/3, 1
The differences between consecutive y-values are constant. For example:
(-2/3) - (-4) = 10/3
(-1) - (-2/3) = 1/3
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what statement require's proof before it's acceptable as a true statement? ...... A. defined terms B. postulate .C. undefined terms D. theorem...... hope your watching XxdeathshootxX
Answer:
D. Theorem
Step-by-step explanation:
Which equation is modeled below?
O 2x+(-2)=-2x+
O 4x+(-2)=-2x+6
O 2x+4 = 6x + 2
O-2x+4=6x+(-2)
Answer:
4x + (-2) = -2x+6
Step-by-step explanation:
im not gonna explain a diagram but it won't let me submit.
smalles of 3 .3 .33 .333
0.3 is the lowest possible value
4. Suppose that the water level of a river is 34 feet and that it is receding at a rate of 0.5 foot per day. a. Write a linear equation in slope-intercept form that relates the water level to the number of days. __________________________ b. After 38 days, how high is the water level of the river? c. In how many days will the water level be 26 feet?
Question A:
A linear equation in slope-intercept form is of the form:
\(\begin{gathered} y=mx+c \\ \text{where,} \\ m=\text{slope of the linear graph} \\ c=y-\text{intercept of the linear graph.} \\ \\ \\ \text{For our question, }y\text{ represents the water level of the river in feet. }x\text{ represents the number of days, }m\text{ represents} \\ \text{the rate of change of the level of water per day, while }c\text{ is the initial level of water.} \end{gathered}\)From the question, we can conclude that:
m = -0.5 (the slope is negative because the water level is reducing)
c = 34.
Thus, the equation is given as:
\(\begin{gathered} y=-0.5x+34 \\ \text{where,} \\ x=\text{ number of days} \\ y=\text{level of water in feet} \end{gathered}\)
Question B:
\(\begin{gathered} \text{After 38 days, we need to find the level of water.} \\ \text{This means that:} \\ x=38\text{ and we need to find the value of }y \\ \\ y=-0.5(38)+34 \\ y=-19+34 \\ \therefore y=15\text{feet} \end{gathered}\)Thus, the water level after 38 days is 15 feet
Question C:
\(\begin{gathered} \text{ We need the number of days when the water level is 26 feet.} \\ \text{This means that:} \\ y=26,x=? \\ \\ \text{Thus, we can say:} \\ 26=-0.5x+34 \\ \text{Subtract 34 from both sides} \\ 26-34=-0.5x \\ -8=-0.5x \\ \text{Divide both sides by }-0.5 \\ -\frac{0.5x}{-0.5}=-\frac{8}{-0.5} \\ \\ x=16 \end{gathered}\)16 days have elapsed when the water level is at 26 feet
Answer
Question A:
The equation is:
\(y=-0.5x+34\)Question B:
The water level after 38 days is 15 feet
Question C:
16 days have elapsed when the water level is at 26 feet
Help its urgent i need to get these done
The planes that are parallel in the cube shown would be C. NOR and LMP.
What are parallel planes ?Two planes that are located on a cube and are always opposite and never intersect; they remain continuously at the same distance from each other. A cube consists of three pairs of parallel planes in correspondence with its triplet of opposing faces.
From the given options, the only parallel planes would be NOR and LMP. One of the reasons for this, is that these planes have no point of intersection unlike the planes in the other options.
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Explain the process you would use to find the area of the shaded region. Then calculate the shaded region.
You may leave your answer in terms of m or round to the nearest tenth.
Given statement solution is :- To find the area of the shaded region, we first need to determine the shapes involved and their respective areas. A general process that you can apply to various scenarios, Identify the shapes , Break down the region, Calculate individual areas.
To find the area of the shaded region, we first need to determine the shapes involved and their respective areas. Without a specific diagram or description, I'll provide a general process that you can apply to various scenarios.
Identify the shapes: Examine the diagram and determine the shapes that make up the shaded region. These shapes can include rectangles, triangles, circles, or combinations of them.
Break down the region: If the shaded region consists of multiple shapes, break it down into simpler, recognizable shapes. This step is crucial for accurately calculating the total area.
Calculate individual areas: Determine the area of each shape by using the appropriate formulas. Here are some common formulas:
Rectangle: Area = length × width
Triangle: Area = (base × height) / 2
Circle: Area = π × radius²
Sum the individual areas: Add up the areas of all the individual shapes to find the total area of the shaded region.
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100 points will mark brainliest
Answer:
A is the answer
Step-by-step explanation:
if its wrong than its C
HELPPPP PLZZZZZZ HELPPP
Answer:200
Step-by-step explanation:
100 x 2
the cube of it is five my five by four and you'll get your answer
Drag the tiles to the correct locations on the image. Not all the tiles will be used.
The figure is a square, with side lengths as shown.
4√5mm
What are the perimeter and area of the square
The perimeter of the square is 16√5 mm, and the area of the square is 80 mm².
To calculate the perimeter and area of the square, we can use the formulas:
Perimeter = 4 * side length
Area = side length * side length
Substituting the given side length of 4√5mm into the formulas, we have:
Perimeter = 4 * 4√5mm = 16√5mm
Area = (4√5mm) * (4√5mm) = 16 * 5mm = 80mm²
Therefore, the perimeter of the square is 16√5mm, and the area of the square is 80mm².
Please note that the values are based on the provided side length of 4√5mm. If there are any changes to the side length, the perimeter and area will differ accordingly.
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The perimeter of the square is 16√5 mm, and the area of the square is 80 mm².
I took the test on plato.
HELP PLEASEEE
A party rental company has chairs and tables to rent. There were two customers who rented both chairs and tables last week. The table below shows the number of chairs, the number of tables, and the total cost (in dollars) for those two customers.
By setting up the equation, we get the system of linear equations are
9x + 7y = 77
3x + 5y = 49
solving these equation Cost to rent a chair = $1.75
cost to rent a table = $8.75
What is system of linear equation?A system of linear equations is a collection of one or more linear equations involving the same variables.
What are the method to solve system of linear equations?There are several methods for solving systems of linear equations, including:
Graphing: One way to solve a system of linear equations is to graph each equation on the same set of axes and look for the point of intersection. This method is useful when you want to visualize the solution, but it can be time-consuming if you have a large system of equations.
Substitution: The substitution method involves solving one of the equations for one of the variables and substituting this expression into the other equation. This will result in an equation with only one variable, which you can then solve.
Elimination: The elimination method involves adding or subtracting the equations in such a way that one of the variables is eliminated. This will result in an equation with only one variable, which you can then solve.
etc.
To solve the system of equations 9x + 7y = 77 and 3x + 5y = 49, you can use the substitution method.
First, solve the first equation for y:
9x + 7y = 77
7y = -9x + 77
y = (-9/7)x + 11
Now substitute this expression for y into the second equation:
3x + 5((-9/7)x + 5(11) = 49
3x - (45/7)x + 55 = 49
solving for x :
x = 1.75
Now substitute this value for x back into the first equation to find y:
y = 8.75
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This Venn diagram shows the pizza topping preferences for 9 students let event A= The student likes pepperoni let event B= the student likes olives
What is P(a or b)
Answer:
B. 5/9
Step-by-step explanation:
There are 5 names listed in the circles representing pepperoni and olives, so of the 9 students, 5 like pepperoni or olives.
P(A or B) = 5/9
The price of milk tripled and then rose another $0.75 per gallon. If the price now is at least $4.50 per gallon which inequality express this situation
This inequality states that the sum of 3 times the original price plus $0.75 must be greater than or equal to $4.50.
Let's denote the original price of milk as "p" per gallon.
According to the given information, the price of milk tripled, which means it became 3 times the original price, or 3p per gallon.
Afterward, an additional $0.75 was added to the price, resulting in a total price of 3p + $0.75 per gallon.
We are told that the price now is at least $4.50 per gallon, so we can express this situation with the following inequality:
3p + $0.75 ≥ $4.50
This inequality states that the sum of 3 times the original price plus $0.75 must be greater than or equal to $4.50.
Please note that if you have a specific value for "p" (the original price), you can solve this inequality to determine the range of prices that satisfy the given conditions.
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A game has a spinner with 8 equal- sized sections. The results of 450 spins are shown in the table. Part Frequency 1 58 2 52 3 39 4 77 5 50 6 43 7 60 8 71
For Which Number is the number difference between the theoretical probability and experimental probability greatest?Explain
The theoretical probability of each section is 1/8, since there are 8 equal-sized sections on the spinner. To find the theoretical frequency, we multiply the theoretical probability by the total number of spins:
Theoretical frequency = (1/8) x 450 = 56.25
We can then calculate the experimental probability for each section by dividing the frequency by the total number of spins:
Experimental probability = Frequency/Total number of spins
Using this formula, we can calculate the experimental probabilities for each section:
Part 1: Experimental probability = 58/450 ≈ 0.129
Part 2: Experimental probability = 52/450 ≈ 0.116
Part 3: Experimental probability = 39/450 ≈ 0.087
Part 4: Experimental probability = 77/450 ≈ 0.171
Part 5: Experimental probability = 50/450 ≈ 0.111
Part 6: Experimental probability = 43/450 ≈ 0.096
Part 7: Experimental probability = 60/450 ≈ 0.133
Part 8: Experimental probability = 71/450 ≈ 0.158
To find the number with the greatest difference between the theoretical and experimental probability, we can calculate the difference between the two probabilities for each section:
Part 1: |0.125 - 0.129| = 0.004
Part 2: |0.125 - 0.116| = 0.009
Part 3: |0.125 - 0.087| = 0.038
Part 4: |0.125 - 0.171| = 0.046
Part 5: |0.125 - 0.111| = 0.014
Part 6: |0.125 - 0.096| = 0.029
Part 7: |0.125 - 0.133| = 0.008
Part 8: |0.125 - 0.158| = 0.033
As we can see, the greatest difference between the theoretical and experimental probability is for Part 4 with a difference of 0.046. This indicates that the experimental frequency for Part 4 is significantly different from the theoretical frequency, which may suggest that the spinner is biased towards that section.
Remove the parentheses from the following expression, and combine like terms: (a + b - c) + 3a - 2c
Answer:
4a + b - 3c
Step-by-step explanation:
you combine a and 3 a, there is nothing to add to be, and since both c's are negative you get - 3c
Answer:
4a + b - 3c
Step-by-step explanation:
Evaluate the expression: −(8 − 12) + 60 + (−4)2.
Answer: 80
Step-by-step explanation:
⇒ −(8 − 12) + 60 + (−4)²
⇒ -(-4) + 60 + 16
⇒ 4 + 60 + 16
⇒ 80
Solve the system of equations.
\begin{aligned} & -4x+3y = -2 \\\\ & y=x-1 \end{aligned}
−4x+3y=−2
y=x−1
Answer:
x = -1 ; y=0
Step-by-step explanation:
We plug in the y, from the second equation, in the first one. By doing so we obtain:
-4x +3(x-1) = -2
-4x + 3x - 3 =-2
-x = 1
x= -1
Now we take this value and plug it in the second equation:
y = 1-1 = 0
Solution:
(-1,0)
.
Find the slope of the line y=-5/7x-1
Answer:
-5/7
Step-by-step explanation:
With the equation y = mx + b, m is the slope of the line.
Since the equation is y = -5/7x - 1, m is -5/7
So, the slope of the line is -5/7
Answer:
m = -5/7
slope = -5/7
Step-by-step explanation:
Use y = mx + b to find the slope m.