The car model that is least likely to have a brake failure is model d, and the probability of brake failure for this model is 0.0029%.
The given table provides the probabilities of brake failure for different car models. We need to identify the car model that has the lowest probability of brake failure and the corresponding probability.
From the table, we can see that the probability of brake failure is the lowest for model d, which is 0.0029%. To find this, we simply need to compare the probabilities given in the table and identify the smallest one.
It's worth noting that the total probability of brake failure across all car models is 0.0048%, which means that the probability of brake failure for any individual car model is quite low.
To express this in a more tangible way, we could say that out of 1000 new cars of model d, we can expect only about 2 or 3 to have brake failure. The low probabilities of brake failure suggest that new cars in general are quite safe and reliable when it comes to braking performance.
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What is 7/8% as a decimal
A new “mega-size” pizza costs $29.99. The pizza company wants to get $0.02 per square centimetre of pizza. a) How much area should the pizza cover? b) What should be the pizza's diameter, to the nearest centimetre?
Answer:
d = 437 cm
Step-by-step explanation:
1 cm^2 costs 0.02 cents.
x cm^2 costs 29.99 dollars which is 2999 cents.
1 cm^2 / 0.02 = x / 2999 Cross multiply
0.02 cents x = 2999 cents cm^2 The cents will cancel out and you get
0.02 x = 2999 cm^2 Divide by 0.02
x = 2999 cm^2 / 0.02
x = 149950 cm^2
The area of a circular pizza is going to be pi * r^2 just as it is for any circle.
pi * r^2 = 149950 Since pi = 3.14 divide by 3.14
r^2 = 149950 / 3.14
r^2 = 47754.8 Take the square root of both sides.
sqrt(r^2) = sqrt(47754.8)
r = 218.53 cm
This think is huge -- well over 6 feet. in radius.
r = 218.53
d = 2* r = 437.057
d = 437 cm
Which of the following undergoes controlled chain reaction in a nuclear reactor?
A. Th-232
B. Pb-208
C. Ba-141
D. U-235
Answer:
the answer is option D. Uranium - 235
Erica cut 2/3 yard ribbon into pieces that are 1/6 yard long how many pieces of ribbon did she cut
Answer:
4 pieces
Step-by-step explanation:
To perform the calculation, it's easier for both values to have the same denominator.
2/3 yards is the same as 4/6 yards.
Now we have two values with the same denominator: 4/6 and 1/6.
(4/6) / (1/6) = 4.
Given APQR, complete the table. Use capital letters.
CAN SOMEONE PLEASE HELP ME WITH THIS!!!
Given ΔPQR, the diagram shows possible segments are:
1.SR, 2. PQ AND PS and 3. QR
Segment:
A segment has two distinct endpoints on a line. The length of a line segment is fixed, that is, the distance between two fixed points. Here, length can be measured in metric units such as centimeters (cm), millimeters (mm) or in conventional units such as feet or inches.
Geometric Mean:
The geometric mean (GM) is an average or mean that expresses the central tendency of a set of numbers by multiplying their values. Basically, we multiply the numbers exactly and take the nth root of the multiplied number, where n is the total number of data values. For example: For a given set of two numbers, say 3 and 1, the geometric mean is equal to √(3×1) = √3 = 1.732.
Given:
Segments Geometric Mean
PS and QS \(\sqrt{(PS)* (QS)}\) or RS
PQ and QR PR
PQ and QS QR
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im not sure how to do this please help
Answer:
1+3=4
4+5=9
9+7=16
as we can observe that the we have to add the odd numbers in sequence
16+9=25
25+11=36
hope this helps you
❤ itz indian heart ❤What's the predicted number of runs for the player with only 86 hits? Show your equations, plugging in the values, and your steps to the solution. (2 points)
The predicted number of runs for the player with only 86 hits can be calculated using the equation Runs = Hits + Walks - Home Runs. Plugging in the values given, we get: Runs = 86 + Walks - Home Runs. Therefore, the predicted number of runs for the player is dependent on the number of walks and home runs they have.
To solve for the predicted number of runs, we can use the following steps:
Therefore, the predicted number of runs for the player with only 86 hits can be calculated by plugging in the values of the number of walks and home runs into the equation Runs = Hits + Walks - Home Runs.
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Guppies are small fish that live in South American rivers. They can have different- sized spots on their bodies.
The river bottoms are covered in rocks. Guppies with spots that are the same size as the rocks on the bottom are harder for bigger fish to see and catch.
The diagram below shows a population of guppies that live in a river. At time 1, the population had the same number of guppies with small and large spots. At time 2, after many generations, there were many more guppies with small spots and fewer guppies with large spots in the population.
How did the environment change between time 1 and time 2? How did the population change?
a. You cannot tell how the environment changed. With each generation, more guppies passed on the gene for small spots to their offspring.
b. The rocks became smaller. With each generation, more guppies with small spots survived long enough to pass on the gene for small spots to their offspring.
c. The rocks became smaller. Guppies with small spots are more likely to survive, so the guppie
The rocks became smaller. Guppies with small spots are more likely to survive, so both kinds of guppies passed on the gene for small spots to their offspring.
The environment changed in such a way that, "guppies with small spots had a better chance of survival and reproduction, leading to an increase in their population and a decrease in the population of guppies with large spots".
Over many generations, guppies with small spots had a survival advantage in the river because the rocks on the river bottom became smaller. This made guppies with small spots harder for larger fish to see and catch, increasing their chances of survival and reproduction.
As a result, more guppies with the small spot gene passed it on to their offspring, leading to an increase in the population of guppies with small spots. At the same time, the population of guppies with large spots decreased as they were more visible to predators and had a lower chance of survival. This process of natural selection led to a change in the frequency of different traits within the population of guppies.
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The number of bacteria in a refrigerated food product is given by N(T)=27T²−155T+59,6
When the food is removed from the refrigerator, the temperature is given by T(t)=4t+1.8, where t is the time in hours.
Find the composite function N(T(t)) :
N(T(t)) = ____Find the number of bacteria after 7.1 hours.
Give your answer accurate to the nearest whole value. ____ bacteria
By substituting T(t) into the equation N(T), we can determine the number of bacteria. After 7.1 hours, the estimated number of bacteria is approximately _______ (rounded to the nearest whole value).
To find the composite function N(T(t)), we substitute T(t) into the equation N(T). Since T(t) = 4t + 1.8, we replace T with 4t + 1.8 in the equation N(T):
N(T(t)) = 27(4t + 1.8)² - 155(4t + 1.8) + 59.6
Simplifying the equation gives:
N(T(t)) = 27(16t² + 14.4t + 3.24) - 620t - 279 + 59.6
N(T(t)) = 432t² + 388.8t + 87.48 - 620t - 219.4
N(T(t)) = 432t² - 231.2t - 131.92
To find the number of bacteria after 7.1 hours, we substitute t = 7.1 into the equation:
N(T(7.1)) = 432(7.1)² - 231.2(7.1) - 131.92
N(T(7.1)) = 22159.392 - 1644.72 - 131.92
N(T(7.1)) ≈ 20482.772
Therefore, after 7.1 hours, the estimated number of bacteria is approximately 20,483 bacteria (rounded to the nearest whole value).
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graph below.
Plumbing Jobs
Total Charge
(in dollars)
225
200
175
150
125
100
75
50
25
5
0 31 2 3 4
Number of Hours
4.
What is the slope of the line graphed
above?
Javier goes to a football game. He pays $5 for a student ticket and $2 per item bought at the concession stand. Is the total cost to attend the football game a function of the number of items purchased at the concession stand? Use a graph to help explain your answer. Show your work explain your answer
Answer:
f(x) = 2x+5
Step-by-step explanation:
As you know, a student ticket is one item, and you only need one of these to enter a football game. We will assume he is by himself and without friends. There are items he can buy for $2 each at the concession stand.
With what we know, we can conclude that the total cost to attend the football game could be a function.
The function will be
f(x) = 2x + 5
This is because you buy the ticket one time and buys x items, which is modeled by the function.
I'm sorry that I can't send any links, but if you go to desmos graphing calculator, you can find type the function out and get the graph of the function. Remember to look only at the first quadrant!
Your welcome for the answer, and comment if you have any questions! If you could mark this answer as the brainliest, I would greatly appreciate it! :D
I have a question about my math homework : transform y=k(x) by translating it down 3 units. Lable the new function p(x) . What happens to the y-coordinate in each new ordered pair?
Answer:
We have the function y = k(x).
We want to define a new function p(x), such that is equal to k(x) but translated down 3 units.
When we have a general case of a function y = f(x), the function g(x) = f(x) + A is a translation of A units up (if A is positive) or A units down (if A is negative).
Then if we want to go 3 units up, we should have:
p(x) = k(x) + 3.
So now our points are:
(x, y) = (x, p(x)) = (x, k(x) + 3)
So for all the points the y-coordinate has ben mooved 3 units up.
The mean exam score for 49 male high school students is 239 and the population standard deviation is 47 The mean exam score for 53 female high school students is 21.1 and the population standard deviation is 4.3. At α=001, can you reject the claim that male and female high school students ha equal exam scores? Complete parts (a) through (e). Click here to view page 1 of the standard normal distribution table. Click here to view. page 2 of the standard normal distribution table. A. Male high school students have lower exam scores than female students B. Male and temale high school students have different exam scores. C. Male and female high school students have equal exam scores D. Male high school students have greater exam scores than female students
Comparing the means of the two samples, we find that the difference between the means is significant. Therefore, we can reject the claim and conclude that male and female high school students have different exam scores.
To perform the two-sample t-test, we first calculate the standard error of the difference between the means using the formula:
SE = sqrt((s1^2 / n1) + (s2^2 / n2))
Where s1 and s2 are the population standard deviations of the male and female students respectively, and n1 and n2 are the sample sizes. Plugging in the values, we have:
SE = sqrt((47^2 / 49) + (4.3^2 / 53))
Next, we calculate the t-statistic using the formula:
t = (x1 - x2) / SE
Where x1 and x2 are the sample means. Plugging in the values, we have:
t = (239 - 21.1) / SE
We can then compare the t-value to the critical t-value at α = 0.01 with degrees of freedom equal to the sum of the sample sizes minus 2. If the t-value exceeds the critical t-value, we reject the null hypothesis.
In this case, the t-value is calculated and compared to the critical t-value using the provided standard normal distribution table. Since the t-value exceeds the critical t-value, we can reject the claim that male and female high school students have equal exam scores.
Therefore, the correct answer is:
B. Male and female high school students have different exam scores.
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Solve for j
A = 4 j k
Answer:\(a=4jk\\isolate J: divide 4 and k\\= \frac{a}{4k} =J\)
Step-by-step explanation:
Answer:
\(a = 4jk \\ akj = a \\ \frac{akj}{4k} \: = \frac{a}{ak} \\ j = \frac{a}{4k} \\ \)
Here ur ans.
By:- Utsav Xettri
When a mantis shrimp strikes, its arm-club gets up to a velocity of 23 m/s moving away from its body. Scientists calculate the acceleration at 100,000 m/s/s.
How long does it take the arm-club to get to 23 m/s?
Answer:
\(t=4.6\times 10^{-4}\ s\)
Step-by-step explanation:
We have,
Initial velocity of arm club is 23 m/s
Acceleration is 100000 m/s²
It is required to find the time taken by it to take the arm-club to get to 23 m/s. It means v = -23 m/s. It is based on the equation of kinematics such that :
\(v=u+at\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{-23-23}{100000}\\\\t=4.6\times 10^{-4}\ s\)
So, the time taken by it is \(4.6\times 10^{-4}\ s\).
PLEASE GUYS HELP ME I WILL GIVE BRAINLIST OR WHATEVER IS CALLED I HAVE AN IMAGE ATTACHED TO
Rosie draws a triangle, ABC.
• AB = 8 cm
• AC = 9 cm
• Angle BAC = 75
a) Draw a sketch of Rosie's triangle.
b) Use your sketch to work out the area of Rosie's triangle.
cm
Answer:
34.77
Step-by-step explanation:
A rod 200cm long is broken into two parts. the shorter part is one quarter of the length of the rod express the shorter part as a percentage of the longer part
Let's denote the length of the shorter part as x.
According to the given information, the shorter part is one quarter of the length of the rod. Since the rod is 200 cm long, the length of the shorter part can be expressed as:
x = (1/4) * 200
x = 50 cm
Now, to express the shorter part as a percentage of the longer part, we need to calculate the ratio of the shorter part (50 cm) to the longer part (200 cm) and multiply it by 100 to convert it into a percentage:
Percentage = (Shorter Part / Longer Part) * 100
= (50 / 200) * 100
= 0.25 * 100
= 25%
Therefore, the shorter part is 25% of the longer part.
Answer this “PROPERLY”
_______inches = 9.75 feet
Answer:117 feet
Step-by-step explanation:
There are 12 inches in 1 foot
Multiply 12 x 9 which equals 108
Since you have a decimal, you take 75% of 12 which is 9, and add that to your inches
108 + 9 = 117
a diver was collecting water samples from a lake. he collected a sample at every 3m, starting at 5m below water surface. the final sample was collected at a depth of 35m.how many sample did he collected
The diver collected water samples at every 3 meters, starting from 5 meters below the water surface, up to a final depth of 35 meters.
We can find the number of samples collected by dividing the total depth range by the distance between each sample and then adding 1 to include the first sample.
The total depth range is:
35 m - 5 m = 30 m
The distance between each sample is 3 m, so the number of samples is:
(30 m) / (3 m/sample) + 1 = 10 + 1 = 11
Therefore, the diver collected a total of 11 water samples.
Solve for a
va – r + m = y
a = y2 + 2my + m² +r
a = y2 – 2my + m² + r
a = y2 – my + m² +r
a = y2 + m2 +r
how can i solve this equation
Answer:
D. -1.44 and 2.44
Step-by-step explanation:
\(f(x) = 2 {ax}^{2} + (3 - b)x + 7\)
is equal to:
\(g(x) = (a - 1) {x}^{2} + 2bx + 7\)
•◇•◇○◇•◇•
➡️ \( - 2 {x}^{2} + 2x + 7 = 0\)
➡️ \(Δ = {b}^{2} - 4ac = 4 - 4 \times 7 \times ( - 2) = 60 = \sqrt{Δ} = 7.746\)
➡️ \(x = \frac{ - b± \sqrt{Δ} }{2a} = \frac{ - 2± 7.746}{ - Δ} \)
➡️ \( x_{1} = \frac{ - 2 + 7.746}{ - 4} = - 1.44\)
➡️ \( x_{2} = \frac{ - 2 - 7.746}{ - 4} = 2.44\)
Given the following relations on the set of all people. Check ALL correct answers from the following lists:
(a) a is (strictly) older than b
A. irreflexive
B. symmetric
C. antisymmetric
D. reflexive
E. transitive
(b) a and b have a common grandparent
A. irreflexive
B. antisymmetric
C. symmetric
D. reflexive
E. transitive
(c) a has the same first name as b
A. transitive
B. irreflexive
C. antisymmetric
D. symmetric
E. reflexive
(d) a and b were born on the same day
A. transitive
B. reflexive
C. irreflexive
D. antisymmetric
E. symmetric
The correct answers from the given lists are given as follows: Relation (a) a is (strictly) older than bA. irreflexiveB. asymmetricC. antisymmetricD. reflexiveE. transitive Relation (b) a and b have a common grandparentA.
irreflexiveB. antisymmetricC. symmetricD. reflexiveE. transitiveRelation (c) a has the same first name as bA. transitiveB. irreflexiveC. antisymmetricD. symmetricE. reflexiveRelation (d) a and b were born on the same dayA. transitiveB. reflexiveC. irreflexiveD. antisymmetricE. symmetric.
The given lists include different types of relations. Let's discuss the given relations one by one.(a) a is (strictly) older than b:This relation is irreflexive because a person can't be older than oneself. This relation is asymmetric because if a is older than b then it can't be possible that b is older than a.
This relation is antisymmetric because if a is older than b and b is older than a, then it means that a and b are the same person which is not possible. This relation is not reflexive because there is no one who is older than oneself. This relation is transitive because if a is older than b and b is older than c then a is also older than c.(b) a and b have a common grandparent:This relation is irreflexive because a person can't have a common grandparent with oneself. This relation is antisymmetric because if a has a common grandparent with b then it can't be possible that b has a common grandparent with a. This relation is symmetric because if a has a common grandparent with b then b also has a common grandparent with a. This relation is not reflexive because there is no one who has a common grandparent with oneself. This relation is transitive because if a has a common grandparent with b and b has a common grandparent with c then a also has a common grandparent with c.(c) a has the same first name as b:
This relation is transitive because if a has the same first name as b and b has the same first name as c then a has the same first name as c. This relation is irreflexive because a person can't have the same name as oneself. This relation is antisymmetric because if a has the same name as b then it can't be possible that b has the same name as a. This relation is symmetric because if a has the same name as b then b also has the same name as a. This relation is not reflexive because there is no one who has the same name as oneself.
(d) a and b were born on the same day: This relation is transitive because if a was born on the same day as b and b was born on the same day as c then a was born on the same day as c. This relation is reflexive because every person is born on the same day as oneself. This relation is irreflexive because no person is born on a different day than oneself. This relation is antisymmetric because if a was born on the same day as b then it can't be possible that b was born on the same day as a. This relation is symmetric because if a was born on the same day as b then b was also born on the same day as a.
The correct answers for each given relation are listed above.
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A zoo measured the height, in feet, of 9 giraffes.
18, 16, 22, 14, 17, 19, 15, 19, 22
What is the median height of the giraffes?
16 ft
17 ft
18 ft
19 ft
Answer:
19 ft because the median is 4.5th item so,the commutative frequency just greater than 4.5 is 6.
so,median=9ft
count the number of distinguishable ways in which you can arrange the letters in the words :
(a) children (b) bookkeeper
The number of distinguishable ways to arrange the letters in the word "children" is 362,880 and in "bookkeeper" is 1,44,000.
(a)The number of distinguishable ways to arrange the letters in the word "children" is 362,880.
The word "children" has 8 letters, so there are 8! (8 factorial) ways to arrange them. However, since the letters "i", "l", and "d" appear twice in the word, we need to divide by 2! (the number of ways to arrange the repeated letters) three times. Thus, the total number of distinguishable arrangements is:
8! / (2! × 2! × 2!) = 362,880
(b) The number of distinguishable ways to arrange the letters in the word "bookkeeper" is 1,44,000.
The word "bookkeeper" has 9 letters, so there are 9! (9 factorial) ways to arrange them.
However, since the letters "o" and "k" appear twice, and the letters "e" and "p" appear three times, we need to divide by 2! (the number of ways to arrange the "o" and "k"), 3! (the number of ways to arrange the "e" and "p"), and 2! (the number of ways to arrange the two sets of repeated letters).
Thus, the total number of distinguishable arrangements is:
9! / (2! × 3! × 2!) = 144,000
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A mountain is in the shape of a cone whose height is about 3.8 kilometers and whose base radius is about 3 kilometers. Approximate the volume of the mountain in cubic kilometers.
The volume of the mountain is approximately cubic kilometers.
(Round to the nearest whole number as needed.)
Rounding to the nearest whole number, the approximate volume of the mountain is 36 cubic kilometers.
What is volume?Volume is a measure of the amount of space that a three-dimensional object occupies or contains. It is typically measured in cubic units, such as cubic meters, cubic centimeters, or cubic feet.
In the given question,
The volume of a cone can be calculated using the formula V = (1/3)πr²h, where r is the radius of the base, h is the height, and π is approximately 3.14.
Substituting the given values, we get:
V = (1/3) × 3.14 × 3² × 3.8
V ≈ 35.63
Rounding to the nearest whole number, the approximate volume of the mountain is 36 cubic kilometers.
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A woman had less than 1,100 with her when she went to the market.She spent all her money and used a certain number 50.00notes and twice as many as 20.00 notes.Find the maximum number of 50.00 notes she used
Answer:
12
Step-by-step explanation:
Let x = number of 50.00 notes.
They are worth 50x
Then, 2x = number of 20.00 notes.
They are worth 2x * 20 = 40x
50x + 40x < 1100
90x < 1100
9x < 110
x < 12.2
Answer: 12
Check:
x = 12 (number of 50.00 notes)
2x = 24 (number of 20.00 notes)
12 * 50 + 24 * 20 = 1080
If she used one more 50.00 note, she'd go over 1,100, so 12 is correct.
The population of a country town is
decreasing at a rate of 5% p.a.
How many years will it take for the town's
population of 17000 to fall below 10000?
Time taken =
years
Answer:
It would take 9 years for the population to fall below 10000.
Solve for x:
2x² - 2x+5=0
By quadratic formula, the roots of the quadratic function 2 · x² - 2 · x + 5 = 0 are two conjugated complex numbers: x₁ = 0.5 + i 1.5 and x₂ = 0.5 - i 1.5, respectively.
How to solve a quadratic function by the quadratic formula
Let be a quadratic function of the form a · x² + b · x + c = 0, whose roots can be found by means of the following formula:
\(x = \frac{-b \pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}\) (1)
Where a, b, c are the coefficients of the quadratic function.
In we know that 2 · x² - 2 · x + 5 = 0, then the roots of the polynomial are, respectively:
\(x_{1} = \frac{2 + \sqrt{(-2)^{2}-4\cdot (2)\cdot (5)}}{2\cdot (2)}\)
\(x_{1} = \frac{2 + \sqrt{4-40}}{4}\)
x₁ = 0.5 + i 1.5
\(x_{2} = \frac{2 - \sqrt{(-2)^{2}-4\cdot (2)\cdot (5)}}{2\cdot (2)}\)
\(x_{2} = \frac{2 - \sqrt{4-40}}{4}\)
x₂ = 0.5 - i 1.5
By quadratic formula, the roots of the quadratic function 2 · x² - 2 · x + 5 = 0 are two conjugated complex numbers: x₁ = 0.5 + i 1.5 and x₂ = 0.5 - i 1.5, respectively.
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The eccentricity of a hyperbola is defined as \( \mathrm{e}=\frac{\mathrm{c}}{\mathrm{a}} \). Find an equation of a hyperbola with vertices \( (2,2) \) and \( (-6,2) \) and \( e=\frac{5}{4} \) . The equation of the hyperbola is
The eccentricity of a hyperbola is defined as
(Type an equation. Type your answer in standard form.)
The equation of the hyperbola is \(\frac{(x+2)^2}{a^2} - \frac{(y-2)^2}{b^2} = 1\).
To find the equation of the hyperbola, we need to determine the values of \(a\), \(b\), and \(c\). Given the vertices \((2,2)\) and \((-6,2)\), we can find the distance between them, which represents \(2a\), the length of the major axis.
Distance between vertices: \(2a = |-6-2| = 8\)
\(a = \frac{8}{2} = 4\)
The eccentricity of the hyperbola, \(e\), is given as \(\frac{c}{a} = \frac{5}{4}\). Solving for \(c\):
\(\frac{c}{4} = \frac{5}{4}\)
\(c = 5\)
The distance between the center and each focus is \(c\), so the coordinates of the foci are \((-2+5,2)\) and \((-2-5,2)\), which simplifies to \((3,2)\) and \((-7,2)\).
Now we can write the equation of the hyperbola using the given information:
\(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\)
Since the center is \((-2,2)\), we have:
\(\frac{(x+2)^2}{4^2} - \frac{(y-2)^2}{b^2} = 1\)
To find \(b^2\), we can use the relationship between \(a\), \(b\), and \(c\):
\(c^2 = a^2 + b^2\)
\(5^2 = 4^2 + b^2\)
\(25 = 16 + b^2\)
\(b^2 = 9\)
Thus, the equation of the hyperbola is:
\(\frac{(x+2)^2}{16} - \frac{(y-2)^2}{9} = 1\)
This is the standard form of the equation of the hyperbola.
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