Select the correct answer. When waves travel through water, why do the moving water particles continue to return to their starting position? A. Waves transfer matter, but not energy. B. Waves transfer both matter and energy. C. Waves transfer energy, but not matter. D. Waves don’t transfer matter or energy.

Answer:

\(d=1.98\times 10^{11}\ m\)

Explanation:

Messages from the Perseverance Rover on Mars reach Earth in 11 min i.e. time is 660 s

The speed of light is \(3\times 10^8\ m/s\)

We need to find the distance between Mars and Earth. Let the distance be d.

We know that,

Distance = speed × time

So,

\(d=660\times 3\times 10^8\\\\d=1.98\times 10^{11}\ m\)

So, Mars is \(1.98\times 10^{11}\ m\) from the Earth.

Answer:

D

Explanation:

A is incorrect because it would actually increase the population...

B is incorrect because other birds do not matter, it is only whooping cranes...

C is incorrect because it would also increase the population.

Answer:

C 0.81 m/s (I think, I got around 0.8163, so C seems to be the correct answer)

Explanation:

First, we need the acceleration formula:

a = \(\frac{delta v}{delta t} = \frac{v_{f} - v_{i} }{t}\)

where:

- \(v_{f}\) is the final velocity (speed with direction, which we have, it's west)

- \(v_{i}\) is the starting velocity

- t is total time

Then we plug in what we know and solve:

a = \(\frac{7 - 5}{2.45}\)

a = \(\frac{2}{2.45}\)

a = 0.81632 etc

So our answer becomes 0.82 (they did not round and just cut it off, so we get) C 0.81 m/s as our answer!

Hope this helps :))

Answer:

a) \(E_T=134,484\frac{N}{C}\hat{i}+149954.66\frac{N}{C}\hat{j}\)

b) zero

Explanation:

a) To find the electric field at point C, you sum the contribution of the electric fields generated by the other two charges. The total electric field at C is given by:

\(E_T=E_1+E_2\)

E1: electric field of charge 1

E2: electric field of charge 2

It is necessary to calculate the x and y components of both E1 and E2. You take into account the direction of the fields based on the charge q1 and q2:

\(E_1=k\frac{q_1}{r_{1,3}}[cos\theta\hat{i}+sin\theta \hat{j}]\\\\E_2=k\frac{q_2}{r_{2,3}}[cos\phi\hat{i}-sin\phi \hat{j}]\\\\\)

r13: distance between charges 1 and 3

r12: charge between charges 2 and 3

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

Thus, you first calculate the distance r13 and r23, and also the angles:

\(r_{1,3}=3.00m\\\\r_{2,3}=\sqrt{(3.00m)^2+(4.00m)^2}=5.00m\\\\\theta=90\°\\\\\phi=tan^{-1}(\frac{4.00}{3.00})=53.13\°\)

Next, you replace the values of all parameters in order to calculate E1 and E2:

\(E_1=(8.98*10^9Nm^2/C^2)(\frac{3.30*10^{-4}C}{(3.00m)^2})\hat{j}\\\\E_1=329266.66\frac{N}{C}\\\\E_2=(8.98*10^9Nm^2/C^2)(\frac{6.24*10^{-4}C}{(5.00m)^2})[cos53.13\°\hat{i}-sin(53.13\°)\hat{j}]\\\\E_2=224140.8[0.6\hat{i}-0.8\hat{j}]=134484\hat{i}-179312\hat{j}\)

finally, you obtain for ET:

\(E_T=134,484\frac{N}{C}\hat{i}+(329266.66-179312)\frac{N}{C}\hat{j}\\\\E_T=134,484\frac{N}{C}\hat{i}+149954.66\frac{N}{C}\hat{j}\)

b) The x component of the force exerted by A on C is zero because there is only a vertial distance between them. Thus, there is only a y component force.

here v is the spped of light

f is the frequency of light

now substituting we get

The resistance over the bulb in the circuit set up as shown in the diagram is 30 Ω.

Resistance can be defined as the opposition to current flow in a circuit.

To calculate the resistance over the bulb, we use the formula below.

Formula:

Where:

From the diagram,

Note: Since the bulb and the 60 Ω resistor are connected in parallel, therefore,

From the diagram,

Given:

Substitute these values into equation 1

Hence, the resistance over the bulb is 30 Ω.

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Answer:

Diagram (3).

Explanation:

N3L states that if object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A (\(F_{A} = -F_{B}\)).

The diagram which best represents the gravitational forces, F, between a satellite, S, and Earth is; Choice (3).

The law clearly states a Force of attraction; the two objects come towards each other.

Consequently, Choice (3) best represents the gravitational forces, F, between a satellite, S, and Earth.

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Answer:

Geocentric model of the solar system helped to explain RETROGRADE MOTIONS OF PLANETS.

Explanation:

Geocentric model of planets was proposed by Ptolemy. It stated that all sun, planets and stars revolve round the earth in circular orbits.

Hope it helps you...

(◍•ᴗ•◍)

The stress in Magapascals is 80 Magapascals

This question can be solved by applying Young's modulus.

Young's modulus : Young's modulus states that, stress  is directly proportional to strain.

Where Stress is pressure acting the body. The s.i unit of stress is N/m² or Pascal. And it can be expressed mathematically as,

From the question,

\(P = 10000/(125*10^{-6} )\)

\(P =\) \(8*10^{7}\) Pascals

\(P =\) 80 Magapascals

Hence the stress in Magapascals is 80 Magapascals

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The stress experimented by the tie-bar is 80 megapascals.

The tie-bar is under axial load. Under the assumption that force is distributed uniformly in the cross-section area, we can use the following definition of normal stress (\(\sigma\)), in megapascals:

\(\sigma = \frac{F}{A}\) (1)

Where:

\(F\) - Axial force, in meganewtons.

\(A\) - Cross-section area, in square meters.

If we know that \(F = 10\times 10^{-3}\,MN\) and \(A = 125\times 10^{-6}\,m^{2}\), then the stress experimented by the tie-bar is:

\(\sigma = \frac{10\times 10^{-3}\,MN}{125\times 10^{-6}\,m^{2}}\)

\(\sigma = 80\,MPa\)

The stress experimented by the tie-bar is 80 megapascals.

Answer:

  163 N

Explanation:

The density of copper is about 8.96. The ratio of the weight in water to the weight in air is about 1-1/ρ, so is about 0.8884.

  0.8884 × 184 N ≈ 163 N

The submerged weight is about 163 N.

Answer:

A

Explanation:

volcanoes and plate movement

Answer:The answer is option A.

Momentum=mass×velocity.

Orange train=mass is 200 and velocity is 1.

which is 200×1=200kgm/s.

The initial momentum of the orange train is 200 kgm/s.

The orange train is having mass of 200 kg and it is travelling with speed of 1 m/s.

                     So, the orange trains momentum will be ,

                               P = mv

                            ∴ P = 200 x 1

                            ∴ P = 200 kgm/s

Therefore, the initial momentum of the orange train is 200kgm/s.

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Answer:

A) they both have the same algebraic sign

B)6.377×10^-6 C

Explanation:

From columb's law, the force acting on both charges can be expressed as

F=( kq1*q2)/r^2

Where F= electrostatic force

r= distance between the charges

q1 and q2= charges

The force acting on a spring can be expressed as

F= kx..................eqn(2)

Where

K= spring constant = 180 N/m.

x= stretch of the string= 0.021m

Substitute the values into eqn (2)

F= (180×0.021)

F= 3.78N

If we compare with spring force,

Hence, F( electrostatic) = 3.78N

From

F=( kq1*q2)/r^2 ..............eqn(1)

Where

r= (0.29 m + 0.021m)= 0.311m

K= the electrostatic constant= 8.99×10^9 kg⋅m3⋅s−2⋅C−2.

If we substitute the values we have

Since the charges are the same, then

kq1 and q2 equals "q"

3.78= (8.99×10^9 ×q^2)/(0.311)^2

Making q^2 subject of the formula

3.78× (0.311)^2 = 8.99×10^9 × q^2

q^2= [(0.311)^2 × 3.78]/8.99×10^9

q^2= 40.668×10^-12

q=√40.668×10^-12

q= 6.377×10^-6 C

(a) the possible algebraic signs

They have the same algebraic sign

(b) the magnitude of the charges.

6.377×10^-6 C

The car can take this curve at a speed of 18.8 m/s without skidding to the outside of the curve

The maximum speed at which a car can take a curved road without skidding outward is given by the formula:

v = √(g * r * (cos(theta) + (mu * sin(theta))/mu_s))

where:

v = velocity of the car

g = acceleration due to gravity (9.8 m/s^2)

r = radius of curvature of the road (36 m)

theta = angle of banking of the road (25 degrees)

mu = coefficient of friction between the tires and the road (0.87)

mu_s = coefficient of static friction between the tires and the road (0.87)

So the maximum speed at which the car can take this curve without skidding is:

v = √(9.8 * 36 * (cos(25) + (0.87 * sin(25))/0.87))

v = √(9.8 * 36 * (0.9063 + 0.4696))

v = √(9.8 * 36 * 1.376)

v = √(352.48)

v = 18.8 m/s

Therefore, the car can take this curve at a speed of 18.8 m/s without skidding to the outside of the curve.

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Angular velocity of the platform with its load is 0.94 rad/s.

Since, there is no external torque acting on the system, the momentum is conserved.

So, Initial momentum, L₁ = Final momentum, L₂

I₀ω₁ = (I₀ + m₁r₁² + m₂r₂²)ω₂

I₀ω₁ = [1/2 x 80.7 x (1.91)²] (1.57)

I₀ω₁ = 147.2 x 1.57 = 231.1 kgm²/s

So,

231.1 = [147.2 + 9.57(4/5 x 1.91)² + 21.1(1.91)²]ω₂

Therefore, the final angular velocity,

ω₂ = 231.1/246.5

ω₂ = 0.94 rad/s

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The statement "B. Gravity exists only on Earth" and the statement "E. Gravity doesn't exist between Earth and the sun"  is not true about gravity.

Gravity is a fundamental force of nature that exists in the whole universe, not just on Earth. It is a force that acts between any two objects that have mass. This means that statement "C. Gravity is a force that pulls two objects together" and "D. Gravity exists between two objects that have mass" are both true. Gravity plays a significant role in the functioning of our solar system. The sun's gravitational force acts on the planets, including Earth, keeping them in their orbits. Similarly, Earth's gravitational force attracts objects towards its center, giving weight to objects on its surface. Gravity is the force that holds Earth in orbit around the sun and is responsible for the planets' motion in the solar system. Gravity is a universal force that exists throughout the universe, acts between objects with mass, and plays a crucial role in celestial bodies' movements, including the interaction between Earth and the sun.

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Answer:

Storing it at a temperature greater than its Curie temperature will demagnetize it. The Curie temperature--named after the French scientist Pierre Curie--is the temperature at which magnets lose their permanent magnetism. ... Samarium cobalt, neodymium, and ceramic/ferrite magnets are brittle.

The system accelerates by 2.45 \(m^{2} /s\).and m2's final speed after 1.5 seconds is 3.675 m/s.

The pulley's mass is related to how quickly an object accelerates. You can determine the acceleration if you know the mass and moment of inertia of the pulley.

The most massive object will accelerate downhill and the least massive object will accelerate upward in a circumstance like this where two objects are strung above a pulley. Each object will experience the same amount of acceleration.

calculation T= m1*g + m2*a g= 9.8 since T = M x A.

a= 9.8 \(m^{2}/s\).

\(v^{2} = u^{2} +2as\).

v= 3.675 m/s.

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Elastic potential energy of spring is twice the gravitational potential energy of the object.

Height of the object, h = 0.5 m

Displacement of the spring, x = 0.5 m

Given that,

Potential energy of the object = Elastic potential energy of spring

mgh = 1/2 kx² = E

When the distance and height are doubled,

GPE = 2 mgh = 2E

Elastic PE = 1/2 k(2x)²

Elastic PE = 4 x 1/2 kx² = 4E

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Answer:

The initial velocity of Billy is 66.6 m/s.

Explanation:

Given;

acceleration of Billy, a = 12.3 m/s²

distance moved by Billy, d = 455 m

final velocity of Billy, v = 125 m/s

let the initial velocity of Billy = u

Apply the following equation of motion;

v² = u² + 2ad

125² = u² + 2(12.3 x 455)

15625 = u² + 11193

u² = 15625 - 11193

u² = 4432

u = √4432

u = 66.57 m/s

u = 66.6 m/s.

Therefore, the initial velocity of Billy is 66.6 m/s.

The magnitude of the charge of the given moveable beads is 9.33 nC.

The tension in the string is calculated as follows;

Tcos45 = mg

where;

F = Tsin45

\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)

\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)

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\(\left(95\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{231}{1.00}\dfrac{\mathrm{in}^3}{\rm gal}\right)\left(\dfrac{1.0}{12}\dfrac{\rm ft}{\rm in}\right)^3\left(\dfrac{1.0}{60}\dfrac{\rm min}{\rm s}\right)\approx0.211661\dfrac{\mathrm{ft}^3}{\rm s}\)

Multiplying 95 gal by 231 converts it to in^3. Dividing by 12^3 converts in^3 to ft^3. Dividing by 60 converts min to s.

Answer:

a. hydroelectric power plant

Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

Answer:

Cool. What’s the Question?

Explanation:

Answer:

45 degrees

Explanation:

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

Given that,

Wavelength of the human light is 560 nm

To find,

The temperature of a black body that would radiates most intensely at this wavelength.

Solution,

The relation between temperature and the wavelength is given by :

\(\lambda=\dfrac{c}{T}\)

T is temperature

c is \(2.898\times 10^{-3}\ m-K\)

So,

\(T=\dfrac{c}{\lambda}\\\\T=\dfrac{2.898\times 10^{-3}}{560\times 10^{-9}}\\\\T=5175\ K\)

So, the temperature of a black body that would radiates most intensely at this wavelength is 5175 K.