Select the correct answer.Frogs lay spherical eggs that are 1.2 millimeters in diameter. Nutrients are absorbed through the egg's surface. What is the approximate area of a frog egg's surface?A. B. C. D.

The magnitude of the resultant vector, representing the actual path of the boat, is approximately 1.42 m/s.

To find the magnitude of the resultant vector, we need to consider the boat's velocity and the velocity of the river. The boat's velocity is given as 0.75 m/s, and the river's velocity is given as 1.2 m/s.

Since the boat is moving in a river, we can think of the boat's velocity as a combination of two velocities: its own velocity and the velocity of the river. The resultant vector represents the actual path of the boat, considering both velocities.

To calculate the resultant vector, we can use vector addition. The magnitude of the resultant vector can be found by taking the square root of the sum of the squares of the boat's velocity and the river's velocity. Mathematically, we have:

Resultant magnitude = √(boat velocity^2 + river velocity^2)

Plugging in the given values, we have:

Resultant magnitude = √(0.75^2 + 1.2^2)

= √(0.5625 + 1.44)

= √2.0025

≈ 1.42 m/s

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180kg is mass of metal .

The definition of specific heat capacity

The amount of heat per unit mass needed to raise the temperature by one degree Celsius is known as the heat capacity or specific heat. The ability to distinguish between two polymeric composites using specific heat can be useful in calculating the processing temperatures and volume of heat required.

The heat capacity per unit mass of a material is known as the specific heat capacity (or simply the specific heat). The results of experiments indicate that three variables affect the amount of heat that is transferred: (1) the temperature change, (2) the mass of the system, and (3) the substance and phase of the material.

Eo is 9.9*10^6 J

ΔT is 55K

c is 1*10^3 J/kg.K

Eo = Mo. c. ΔT

Mo = Eo/ c. ΔT

Mo = 9.9*10^6/ 5 5*1*10^3

Mo = 180kg

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The mass of the helium sample is approximately 0.187 g.

To solve this problem, we can use following formula:

w = nR(T2 - T1)

We can rearrange this formula to solve for n:

n = w / (R * (T2 - T1))

To find the mass of the helium sample, we can use following formula:

m = n * M

where m is the mass of the sample, n is  number of moles of gas, and M is the molar mass of helium.

Substituting the given values into the first equation, we get:

70 J = n * 8.31451 J/mol*K * (358 K - 283 K)

Simplifying this equation, we get:

n = 0.0467 mol

Substituting this value into the second equation, we get:

m = 0.0467 mol * 4 g/mol = 0.187 g

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Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.

According to the Ohm's Law,  the current through a conductor between two points is directly proportional to the voltage across the two points.

Mathematically,

V ∝ I

V = IR

where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.

Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.

Hence All of the above option in the given question are true.

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Answer:

x = A cos (w \sqrt{2y_{o}/g})

a) maximun  Ф= \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) minimun     Ф = \(\frac{\pi }{2}\) - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

Explanation:

For this exercise let's use kinematics to find the time it takes for the mass to reach the floor

         y = y₀ + v₀ t - ½ g t²

as the mass is released from rest, its initial velocity is zero (vo = 0) and its height upon reaching the ground is zero (y = 0)

      0 = y₀ - ½ g t²

      t = \(\sqrt{2y_{o}/g}\)

The bucket-spring system has a simple harmonic motion, which is described by

     x = A cos wt

in this expression we assumed that the phase constant (Ф) is zero

let's replace the time

     x = A cos (w \sqrt{2y_{o}/g})

this is the distance where the system must be for the mass to fall into it.

a) The new system has a total mass of m ’= 3.0 kg, so its angular velocity changes

          w = \(\sqrt{k/m}\)

In the initial state

         w = \sqrt{k/2}

When the mass changes

         w ’= \sqrt{k/3}

the displacement in each case is

         x = A cos (wt)

for the new case

        x ’= A cos (w’t + Ф)

the phase constant is included to take into account possible changes due to the collision of the mass.

we see that this maximum expressions when the cosine is maximum

        cos (w´t + Ф) = 1

         w’t + Ф = 0

        Ф = -w ’t

        Ф = - \(\sqrt{k/3}\) \(\sqrt{2y_{o}/g}\)

       \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) the function is minimun if

        cos (w’t + fi) = 0

        w’t + Ф = π / 2

        Ф = π / 2 - w ’t

        Ф = \(\frac{\pi }{2}\) - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

A golf ball is a unique ball made specifically for the game of golf.

A golf ball must adhere to specific velocity, distance, and symmetry requirements as well as have a mass of no more than 1.620 oz (45.9 g), a diameter of no less than 1.680 inches (42.7 mm), and no more than 1.620 oz (45.9 g) in total.  

Similar to golf clubs, golf balls must pass testing and approval by The R&A and the United States Golf Association before they can be used in competitions. 

Early in the 20th century, it was discovered that dotting the ball gave the player even more control over the trajectory, flight, and spin of the ball.

Therefore, A golf ball is a unique ball made specifically for the game of golf.

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The maximum height reached by the water is 20.2 cm and it will dislodge the beetle.

The maximum height reached by the water squirted by the arch fish is calculated by applying the following kinematic equation.

H = (v² sin²θ) / 2g

where;

H = (2.6² x (sin50)² ) / (2 x 9.8)

H = 0.202 m

H = 20.2 cm

Thus, the water squirted by the arch fish is dislodge the beetle.

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The complete question is below:

The archerfish hunts by dislodging an unsuspecting insect from its resting place with a stream of water expelled from the fish's mouth. Suppose the archerfish squirts water with a speed of 2.60 m/s

at an angle of 50.0 ∘ above the horizontal, and aims for a beetle on a leaf 2.30 cm above the water's surface. Will the water squirted by the arch fish dislodge the beetle?

A. The period of the motion is 4.18 s

B. The frequency of the oscillations

Hz is 0.2393 Hz

C. The first time the mass is at the position

x = 0 is 2.09 s

D. The first time the mass is at the site of maximum compression of the spring is 6.27s

a) The period of motion is given by the time it takes for the mass to complete one full oscillation. From the equation given, x = (8.8 cm)cos[2t/(4.18 s)], we can see that the function is in the form x = A cos(ωt + φ). The period of the motion T is given by the reciprocal of the angular frequency ω, which is T = 2π/ω.

In this case, the angular frequency is given by the coefficient of t in the argument of the cosine function, 2t/(4.18 s). So,

T = 2π/(2/(4.18 s)) = 4.18 s

b) The frequency of oscillations, f, is given by the reciprocal of the period, so

f = 1/T = 1/4.18 s^-1 = 0.2393 Hz

c) To find the first time the mass is at the position x = 0, we need to find the value of t when the cosine function is equal to 1.

x = (8.8 cm)cos[2t/(4.18 s)] = 8.8cm * 1 = 8.8cm

so,

cos[2t/(4.18 s)] = 1

t = (4.18 s)/2 = 2.09 s

d) To find the first time the mass is at the site of maximum compression of the spring, we need to find the value of t when the cosine function is equal to -1.

x = (8.8 cm)cos[2t/(4.18 s)] = 8.8cm * (-1) = -8.8cm

so,

cos[2t/(4.18 s)] = -1

t = (4.18 s) + (2.09 s) = 6.27s

It should be noted that the mass will be at the site of maximum compression at t = 6.27s and t = 2.09s + 4.18s = 6.27s + 4.18s = 10.45s and so on.

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The new amplitude B is 0.22 m.

Mass of block = M =0.1 kg

Spring constant = k = 15 N/m

Amplitude = A = 0.22 m

Mass of bullet = m = 3 g = 0.003 kg

Velocity of bullet = vᵇ = 42 m/s

Angular frequency of S.H.M is given by = ω₀ = \(\sqrt{\frac{k}{M}}\)

                                                      = \(\sqrt{\frac{15}{0.1} }\)

                                                      = 12.24 rad/sec

Speed of the block immediately before the collision:

Displacement of Simple Harmonic Motion is given as:

x= A Sin(ωt+Ф)

After differentiating:

v = A ω₀cos(ω₀t+Ф)

As bullet strikes at equilibrium position,

   φ = 0

    t= 2nπ

⇒ cos (ω₀t + φ) = 1

⇒ v= A ω₀

⇒ v= (0.22)(12.24)

⇒ \(v=2.692 ms^{-1}\)

If the simple harmonic motion after the collision is described by x = B sin(ωt + φ), new amplitude B:

S.H.M after collision is given as :

x= B Sin(ωt+Ф)

To find B, consider law of conservation of energy,

\(KE = PE\\KE =\frac{1}{2}(m+M)v^{2} \\PE= \frac{1}{2}kB^{2}\\\frac{(m+M)v^{2}}{k}=B^{2} \\B=\sqrt{\frac{(m+M)}{k}} v\\B= \sqrt{\frac{0.003+0.1}{15} } (2.69)\)

\(B= 0.22 m\)

Therefore, the new amplitude B is 0.22 m.

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a. The two cars are moving at the same speed at t = 3.88 seconds.

b. The two autos are moving at a speed of 4.18 cm/s at that moment.

c. The cars pass each other at time t = 1.05 s and t = 2.54 s, respectively.

d. At t = 1.05 seconds, the first car is located at 12.15 cm, and the second car is located at 16.55 cm. At t = 2.54 seconds, the first car is located at 10.69 cm, and the second car is located at 17.39 cm.

What is the speed of the two cars?

The speed of the cars is derived using the formula for linear velocity.

The velocity of the first car is calculated as follows:

v = v₀ + at

where;

The velocity of the second car can be calculated as:

v = v₀

where;

v₀ is the initial velocity since there is no acceleration.

We equate the two velocities of the two cars and solve for time:

-4.40 + 2.70t = 6.10

2.70t = 10.50

t = 3.88 seconds

b. To find the speeds of the cars at time t, we can substitute t = 3.88 seconds in the velocity equation for the first car:

For the first car:

v = -4.40 + 2.70 * 3.88

v = 4.18 cm/s

c. Solving for the time when the positions of the cars are equal allows us to determine when they pass one another.

The position of the first car will be:

x = x₀ + v₀t + 1/2 at²

where x₀ is the initial position.

The position of the second car will be:

x = x₀ + v₀t

equating the two positions equal and solving for time:

13.5 - 4.40t + 1/2 * 2.70t² = 10.5 + 6.10t

1.35t² + 1.70t + 3.00 = 0

Solving the quadratic equation, we get two times:

t = 1.05 s and t = 2.54 s

d. We can re-insert the time values into the position equation for each car to determine where the automobiles were at the times indicated in (c).

For t = 1.05 seconds:

First car:

x = 13.5 - 4.40 * 1.05 + 1/2 * 2.70 * 1.05²

x = 12.15 cm

Second car:

x = 10.5 + 6.10 * 1.05

x = 16.55 cm

For t = 2.54 seconds:

First car:

x = 13.5 - 4.40 * 2.54 + 1/2 * 2.70 * 2.54²

x = 10.69 cm

Second car:

x = 10.5 + 6.10 * 2.54

x = 17.39 cm

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Answer:

D.number of photons emitted.

Explanation:

These are the options for the question

A.propagation speed of the radiation.

B.wavelength of the radiation.

C.polarization of photons emitted.

D.number of photons emitted.

.

Electromagnetic energy of any radiation is proportional to the photons present. And we know that intensity is ratio of energy and unit time.

Hence, The intensity of the radiation emitted by the oxygen sensor is directly proportional to the number of photons emitted

The intensity of the radiation emitted by the oxygen sensor is directly proportional to the number of photons emitted. The correct answer is D.

The intensity of radiation refers to the amount of energy carried by the radiation per unit of time and unit of area. In the context of the oxygen sensor, the intensity of the radiation emitted by the sensor is directly proportional to the number of photons emitted.

The more photons emitted, the higher the intensity of the radiation. The intensity is not directly related to the propagation speed, wavelength, or polarization of the photons emitted, but rather the quantity or number of photons being emitted.

Therefore, The intensity of the radiation emitted by the oxygen sensor is directly proportional to the number of photons emitted. The correct answer is D.

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The complete question is:

The intensity of the radiation emitted by the oxygen sensor is directly proportional to the

A. propagation speed of the radiation.

B. wavelength of the radiation.

C. polarization of photons emitted.

D. number of photons emitted.

Atom A has 10 protons, 12 neutrons, and 10 electrons, while Atom B has 10 protons, 10 neutrons, and 12 electrons.

Atom A and Atom B are not isotopes of each other. Isotopes are atoms of the same element that differ in the number of neutrons but have the same number of protons. In this case, Atom A and Atom B have different numbers of protons, which means they are not isotopes of each other.

The number of protons determines the element, and since Atom A and Atom B have different numbers of protons, they belong to different elements.

Isotopes, on the other hand, have the same number of protons but differ in the number of neutrons.

This variation in the number of neutrons gives isotopes different atomic masses while retaining the same chemical properties.

However, Atom A and Atom B do not fulfill this criterion, so they cannot be considered isotopes of each other.

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3,000 x 1,000 x 3,000 =

FMultiply the whole numbers:

Answer:

\(\mu = 3.36\times 10^{-3}\ A-m^2\)

Explanation:

Given that,

The magnitude of magnetic field, B = 0.55 T

The radus of the loop, r = 43 cm = 0.43 m

The current in the loop, I = 5.8 mA = 0.0058 A

We need to find the magnetic moment of the loop. It is given by the relation as follows :

\(\mu = AI\\\\\mu=\pi r^2\times I\)

Put all the values,

\(\mu=\pi \times (0.43)^2\times 0.0058\\\\=3.36\times 10^{-3}\ A-m^2\)

So, the magnetic moment of the loop is equal to\(3.36\times 10^{-3}\ A-m^2\).

Answer: Insulator

Explanation:

An insulator is a material that restricts the flow of electricity or thermal energy.

Answer:

plastic or wood

Explanation:

If the ball is thrown straight up into the air with an initial velocity of 20m/s, it will be in the air for 4.08 s

a = v / t

a = Acceleration

v = Velocity

t = Time

v = 20 m / s

a = 9.81 m / s²

t = 20 / 9.81

t = 2.04 s

This is the time taken to reach the farthest height the ball will raise. It takes the equal amount of time to reach the point from where it was thrown from.

T = 2t

T = Total time taken

T = 2 * 2.04

T = 4.08 s

Therefore, the ball will be in the air for 4.08 s

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The engine weighs four times as much as a freight car. Therefore, the final velocity following connection is 4 km/h.

v′=m1v1+m2v2m1+m2 m1 is the weight of item 1, v1 is indeed the velocity of the object of item 1, m2 is indeed the mass of argument 2, and v2 is the starting velocity of instrument 2 wherein v' is the final speed of a two objects after they travel as one mass after the collision.

The velocity of the special properties in a head-on object with a projectile that is significantly more massive than target the projectile's speed before and after the contact will be roughly equal, and the projectile's speed will practically remain unaltered.

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Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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F = m.a

a = F/m

a = 1850/500

a = 3.7 m/s²

Answer:

eta: 1.76

Explanation:

solution:

radius of steel ball(r)=5cm=0.05m

density of ball =8000kgm

terminal velocity(v)=25m/s^2

density of air( d) =1.29 kgm

now

volume of ball(V)=4/3pir^3=1.33×3.14×0.05^3=0.00052 m^3

density of ball= mass of ball/Volume of ball

or, 8000=m/0.00052

or, m=4.16 kg

weight of the ball (W)= mg=4.16×10=41.6 N

viscous force(F)=6 × pi × eta × r × v

=6×3.14×eta×0.05×25

=23.55×eta

To attain the terminal velocity,

Fiscous force=Weight

or, 23.55× eta = 41.6

or, eta = 1.76

whete eta is the coefficient of viscosity.

a.

The intensity of a wave (I) at a surface is equal to :

I = P / A

Where:

P = power output of the speaker = 1 w

A= surface area of the speaker = 0.05 m2

I = 1 w / 0.05m^2 = 20 w/m^2

b.

The intensity at a distance r from the speaker is found by:

I = P / (4πr^2)

Solve for r:

r=0.892 m

There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.

However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.

Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.

Explanation:

(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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Answer:

There is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

Explanation:

This is because velocity is constantly increasing. This supports the idea that the kinetic energy of the book doesn't change and that the potential energy of the book-Earth system increases.

The true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

We have to note that from the law of conservation of mechanical energy, the sum of the kinetic and potential energy of the book at any point remains constant.

If the book is being raised at constant speed, the the true statement is that ;there is no change in the kinetic energy of the book and the potential energy of the book-Earth system increases.

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Answer:

It is A. Light blue

_____________

Hope this helps!

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Answer:

The answer is 5×10‐⁵

Step-by-step Explanation:

\( \alpha = \frac{l2 - l1}{l1( \beta 2 - \beta 1)} \)

let ß be ø

\( \alpha = \frac{40.05 - 40}{40(45 - 20)} \)

\( \alpha = \frac{0.05}{40 \times 25} \)

\( \alpha = \frac{0.05}{1000}\)

\( \alpha = \frac{0.05}{1000}\)\( \alpha = 5.0 \times {10}^{ - 5} \)

The cannon and ball are initially moving at a speed of 1.27 m/s. The cannon is fired, propelling the ball forward at a speed of 75 m/s. The post-explosion velocity of the gun is 6.18 m/s.

Total momentum prior = Total momentum subsequent

(3.5 kg + 0.52 kg) × 1.27 m/s = 3.5 kg × \(v_{cannon}\) + 0.52 kg × 75 m/s

where \(v_{cannon}\)is the velocity of the gun following the explosion.

When we simplify and solve for \(v_{cannon}\), we get:

\(v_{cannon}\) = (0.52 kg × 75 m/s - (3.5 kg + 0.52 kg) × 1.27 m/s) / 3.5 kg

\(v_{cannon}\) = 6.18 m/s.

Velocity is a measure of how quickly an object changes its position in a particular direction. It is commonly represented as a vector quantity with both magnitude and direction. The magnitude of velocity is the speed at which an object is moving, while the direction is the path it is following.

In physics, velocity is a fundamental concept used to describe motion in various contexts, including mechanics, kinematics, and dynamics. It is calculated as the rate of change of displacement with respect to time, expressed in meters per second (m/s) or other units.

Velocity is a critical parameter in understanding the behavior of objects and systems, such as vehicles, projectiles, fluids, and celestial bodies. It affects their acceleration, force, energy, and other characteristics that determine their motion and interactions. Engineers, scientists, and other professionals use velocity to design, analyze, and optimize a wide range of applications, from transportation to manufacturing to space exploration.

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3.57 seconds

Number of loops, N = 55

Initial flux, Φ₁ = 0 Wb

Final flux, Φ₂ = 0.0266 Wb

ΔΦ = Φ₂ - Φ₁

ΔΦ = 0.0266 - 0

ΔΦ = 0.0266 Wb

The EMF, e = 5.22 V

e = NΔΦt

5.22 = 55 x 0.0266 x t

5.22 = 1.463 t

t = 5.22/1.463

t = 3.57 seconds

\(\huge{\mathbb{\tt { QUESTION↓}}}\)

In the early solar system,comets that struck earth may have brought in

\(\color{green}{\tt{O} \: \: \color{black}{\tt {A.water}}}\)

\(\color{green}{\tt{O} \: \: \color{black}{\tt {B.Advanced Life}}}\)

\(\color{green}{\tt{O} \: \: \color{black}{\tt {C.Plankton}}}\)

\(\color{green}{\tt{O} \: \: \color{black}{\tt {D. All \: of \: the \: above}}}\)

\(\huge{\mathbb{\tt { ANSWER↓}}}\)

\(\color{red}{\tt {D. \: All \: of \: the \: above}}\)

\(\color{black}{\tt {because \: the \: true \: answer \: is \: comet}}\)

\({\boxed{\boxed{\tt{WHAT \: IS \: COMET?}}}}\)

\(\color{black}{\tt{A \: comet \: is \: an \: icy, \: small \: Solar \: System \: body}}\)

\(\color{black}{\tt { that, \: when \: passing \: clos \: e to}}\)

\( \color{black}{\tt {the \: Sun, \: warms \: and \: begins \: to \: release}}\)

\(\color{black}{\tt { gases, \: a \: process \: that \: is \: called \: outgassing. }}\)

\(\color{black}{\tt{This \: produces \: a \: visible \: atmosphere \: or \: coma,}}\)

\(\color{black}{\tt{and \: sometimes \: also \: a \: tail}}\)

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