Select the temperature scale that matches each boiling point for water. Water boils at 373. Water boils at 100. Water boils at 212.

Answers

Answer 1

the boiling point of water at 373 K is on the Kelvin scale, 100 °C is on the Celsius scale, and 212 °F is on the Fahrenheit scale.

Boiling point is the temperature at which a liquid change its state to gas or vapor.

The boiling point of a substance is influenced by the atmospheric pressure.

The most common and popular scale used for temperature measurement is the Celsius scale. It is named after the Swedish astronomer Anders Celsius, who created this scale in 1742. On this scale, the boiling point of water is 100 °Celsius. The boiling point of water on the Kelvin scale is 373 K. Lord Kelvin, the Irish physicist, was the developer of this scale.

Fahrenheit scale is a temperature scale that was introduced by German physicist, Gabriel Fahrenheit. On this scale, the boiling point of water is 212 degrees Fahrenheit. Therefore, the boiling point of water at 373 K is on the Kelvin scale, 100 °C is on the Celsius scale, and 212 °F is on the Fahrenheit scale.

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Related Questions

a _____ has to do with the direction of a force​

Answers

Answer:

The "solid force"? ... The direction of the force always seems to be coming out of the solid surface. A direction which is perpendicular to the plane of a surface is said to be normal. The force that a solid surface exerts on anything in the normal direction is called the normal force.

Explanation:

i think i hope this helps

In science, work is defined as the action that results when a force causes an object to move in the direction of the force. ... The object moves as a force is applied. The direction of the object's motion is the same as the direction of the force applied.

Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alond a horizontal roadway. (a) how much work does the cable do on the car if it puls horizontally ? if it pulls at 35.0 degrees above the horizontal ? (b) how much work does the cable do on the tow truck in both cases of part (a)? (c) how much work does gravity do on the car in part (a)?

Answers

Using a cable with a tension of 1350 N , a tow truck pulls a car 5.00 km alone a horizontal roadway. Therefore,

(a) Cable work: 6,750,000 J horizontally.

(b) Cable work: 6,308,250 J at 35.0° above horizontal.

(c) No work by gravity.

To calculate the work done by the cable in each scenario, we need to consider the angle between the direction of the force applied and the displacement.

(a) If the cable pulls horizontally (0° above the horizontal):

In this case, the angle between the force and the displacement is 0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(0°)

Work = 1350 N * 5000 m * 1

Work = 6,750,000 J

The cable does 6,750,000 Joules of work on the car when it pulls horizontally.

(b) If the cable pulls at 35.0 degrees above the horizontal:

In this case, the angle between the force and the displacement is 35.0 degrees, so the work done can be calculated as:

Work = Force * Displacement * cos(Ф)

Work = 1350 N * 5000 m * cos(35.0°)

Work = 1350 N * 5000 m * 0.819

Work = 6,308,250 J

The cable does approximately 6,308,250 Joules of work on the car when it pulls at 35.0 degrees above the horizontal.

(c) The work done by gravity on the car is zero because gravity acts vertically downward, perpendicular to the displacement along the horizontal roadway. Therefore, the gravitational force does not contribute to the work done on the car in this scenario.

In both cases (a) and (b), the cable does the same amount of work on the tow truck as on the car since they are connected by the cable. So the work done by the cable on the tow truck would be equal to the values calculated above: 6,750,000 J in case (a) and 6,308,250 J in case (b).

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what produces magnetic fields

what produces magnetic fields

Answers

Answer:

B is the answer

Explanation:

Magnetic fields are produced by moving electric charges and the intrinsic magnetic moments of elementary particles associated with a fundamental quantum property, their spin.


Magnetic fields are produced by moving electric charges and the intrinsic magnetic moments of elementary particles associated with a fundamental quantum property, their spin. As Ampere suggested, a magnetic field is produced whenever an electrical charge is in motion. The spinning and orbiting of the nucleus of an atom produces a magnetic field as does electrical current flowing through a wire. The direction of the spin and orbit determine the direction of the magnetic field.

what seems to control the assembly and disassembly of intermediate filaments?

Answers

The assembly and disassembly of IFs are regulated by a variety of factors, including phosphorylation, subunit availability, pH, and ionic strength.

Intermediate filaments (IFs) are components of the cytoskeleton that control a variety of biological processes. IFs are typically less dynamic than microtubules and actin filaments, and they appear to be more stable. The assembly and disassembly of intermediate filaments are regulated by phosphorylation-dephosphorylation mechanisms.

The assembly and disassembly of intermediate filaments are controlled by a variety of factors. One of the primary determinants of IF dynamics is phosphorylation. Phosphorylation of specific residues on the IF proteins affects both the ability of the protein to form filaments and its stability once it has formed a filament.

In some cases, the presence of free subunits can promote filament formation, while in others, the formation of complexes between subunits can inhibit filament assembly. Changes in pH or ionic strength can also affect the assembly and disassembly of IFs.Intermediate filaments (IFs) are cytoskeletal structures that are typically more stable than microtubules or actin filaments.

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Meteorology Calculate the saturation mixing ratio
(ws) from the following information and/or
graph below.
w = 8 g kg-1 and RH = 20%

Answers

From the information the saturation mixing ratio (ws) is approximately 0.000161 g \(kg^-1\)

To calculate the saturation mixing ratio (ws), we need to use the given information of specific humidity (w) and relative humidity (RH). The saturation mixing ratio represents the maximum amount of water vapor the air can hold at a given temperature.

The formula to calculate ws from w and RH is as follows:

ws = w ÷ (1 - w) × RH ÷ 100

Given:

w = 8 g \(kg^-1\)

RH = 20%

First, we need to convert w from grams per kilogram to a decimal fraction:

w = 8 ÷ 1000 = 0.008

Now we can substitute the values into the formula:

ws = 0.008 ÷ (1 - 0.008) × 20 ÷ 100

Calculating this expression:

ws = 0.008 ÷ 0.992 × 0.20

ws ≈ 0.000161 g \(kg^-1\)

Therefore, the saturation mixing ratio (ws) is approximately 0.000161 g \(kg^-1\).

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The international Space station was launched on 20 November 1998. It has a mass of 4 197 250 kg. Astronaughts and food are taken to the International Space station with the Soyuz capsule which launches on top of a Soyuz rocket. After the launch, the capsule and the rocket separate. The rocket part of the Soyuz returns to Earth. The Soyuz capsule keeps going to dock onto the Space station. The mass of the Soyus capsule is 2900 kg.
Questions:
(1) Define Newton's Universal Law of Gravity.?
(2) Calculate how many kilometers above the earth's surface the International Space station is if it experiences a net force of 36,99 N to keep it in orbit.? (HINT: do not use scientific notation for this question.)
(3) The Soyus capsule is now approaching the space station. Calculate the force between the Space station and the capsule if it is 200 m apart.?
(4) How does the acceleration of the satellite change? Only answer INCREASE, DECREASE, REMAIN THE SAME Explain your answer in 4.4​

Answers

Newton's law of gravitation, statement that any particle of matter in the universe attracts any other with a force varying directly as the product of masses and inversely as the square of the distance between them.

Why is the universal rule of gravity referred to as Newton's theory of gravity?

Gravity is a universal force that ALL objects are attracted to in relation to the product of their masses, according to Newton's ground-breaking theory. Everywhere there is gravity. Of course, the majority of gravitational pressures are too small to be felt. Only as an object's bulk increases can gravitational forces be observed.

We can use the following method to determine the International Space Station's (ISS) altitude:

F = GMm / r²

F = mv²/ r

v²= Fr / m

v = √(Fr / m)

Substituting the given values, we get:

v = sqrt((36.99 N)(6,371,000 m) / 419,455 kg) = 7,659 m/s

Now we can use the formula for the altitude of a circular orbit:

r = R + h

where R is the radius of the Earth and h is the altitude of the ISS.

The Earth's circumference is roughly 6,371 km. To find h, we can rearrange the algorithm as follows:

h = r - R = (v²/GM) - R

Substituting the given values, we get:

\(h = [(7,69 m/s)^2 / (6.67430 x 10^-11 m^3/kg/s^2)(5.9722 x 10^24 kg)] - 6,371 km\)

h = 408 km.

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Suppose rRF = 6%, rM = 12%, and bi = 1.3.
What is ri, the required rate of return on Stock i? Round your answer to two decimal places.
%
Now suppose rRF increases to 7%. The slope of the SML remains constant. How would this affect rM and ri?
Both rM and ri will increase by 1%.
rM will remain the same and ri will increase by 1%.
rM will increase by 1% and ri will remain the same.
Both rM and ri will decrease by 1%.
Both rM and ri will remain the same.

Answers

The required rate of return on Stock i is 13.8%.

Using the formula for the Security Market Line (SML): ri = rRF + bi(rM - rRF)
ri = 6% + 1.3(12% - 6%) = 13.8%
If rRF increases to 7%, the required rate of return on Stock i would increase. The new required rate of return would be:
ri = 7% + 1.3(12% - 7%) = 15.5%

The slope of the SML remains constant, so rM would also increase by 1% to 13%. Therefore, the correct answer is: rM will increase by 1% and ri will remain the same.
Suppose rRF (the risk-free rate) is 6%, rM (the market return) is 12%, and bi (the beta of Stock i) is 1.3. To find ri (the required rate of return on Stock i), you can use the Capital Asset Pricing Model (CAPM) formula:

ri = rRF + bi * (rM - rRF)

Step 1: Calculate the market risk premium (rM - rRF):
12% - 6% = 6%

Step 2: Multiply the market risk premium by bi:
6% * 1.3 = 7.8%

Step 3: Add rRF to the result from Step 2:
6% + 7.8% = 13.8%

The required rate of return on Stock i (ri) is 13.80%.

Now suppose rRF increases to 7%. The slope of the SML (Security Market Line) remains constant. The change in rRF would affect ri, but it's unclear how it would affect rM.

Let's calculate the new ri using the updated rRF:
ri = 7% + 1.3 * (rM - 7%)

At this point, we can't determine the exact changes in rM and ri without more information. However, since the slope of the SML remains constant and rRF increased, it's likely that both rM and ri will increase, but not necessarily by the same percentage.

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For the displacement field u(x,t)=u
i

e
i

with components given below, calculate the full three dimensional strain at the point p=e
1

+2e
2

+10e
3


u
1

=0.1x
1

x
2


u
2

=0.1x
2

+5
u
3

=500

Answers

The full three-dimensional strain tensor at the point

\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)

To calculate the full three-dimensional strain at the point \(p = e_1 + 2e_2 + 10e_3\), we need to find the components of the strain tensor \(\epsilon_m_n\).

The strain tensor εₘₙ can be calculated using the formula:

εₘₙ = (0.5) * (∂uₘ/∂xₙ + ∂uₙ/∂xₘ)

Given the displacement field u(x, t) with components:

u₁ = 0.1x₁x₂

u₂ = 0.1x₂ + 5

u₃ = 500

We can calculate the components of the strain tensor as follows:

\(\epsilon_1_1 = (1/2) * (\delta u_1/\delta x_1 + \delta u_1/\delta x_1)\\= (1/2) * (0.1x_2 + 0)\\= 0.05x_2\)

\(\epsilon_1_2 = (1/2) * (\delta u_1/\delta x_2 + \delta u_2/\delta x_1)\\= 0.05x_1\)

\(\epsilon _1_3 = (1/2) * (\delta u_1/∂x_3 + \delta u_3/\delta x_1)\\= (1/2) * (0 + 0)\\= 0\)

\(\epsilon_2_1 = (1/2) * (\delta u_2/\delta x_1 + \delta u_1/\delta x_2)\\= (1/2) * (0 + 0.1)\\= 0.05\)

ε₂₃ = (1/2) * (∂u₂/∂x₃ + ∂u₃/∂x₂)

= (1/2) * (0 + 0)

= 0

ε₃₁ = (1/2) * (∂u₃/∂x₁ + ∂u₁/∂x₃)

= (1/2) * (0 + 0)

= 0

ε₃₂ = (1/2) * (∂u₃/∂x₂ + ∂u₂/∂x₃)

= (1/2) * (0 + 0)

= 0

ε₃₃ = (1/2) * (∂u₃/∂x₃ + ∂u₃/∂x₃)

= (1/2) * (0 + 0)

= 0

Therefore, the full three-dimensional strain tensor at the point

\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)

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Which change would decrease the total current, I, flowing through this circuit?
A. Increasing the voltage of the battery
B. Decreasing the length of the wires
C. Rewiring the two resistors in a series
D. Adding a third resistor in parallel

Answers

Answer:

A. Increasing the voltage of the battery

Explanation:

The relationship between voltage, V, current, I and resistance, R, is given as follows;

V = I × R

∴ I = V/R

From the above relationship, the current flowing in the circuit is directly proportional to the voltage of the battery, and inversely proportional to the resistance, 'R', of the circuit

Therefore, increasing the voltage, 'V', of the battery, increases the total current, 'I', flowing in the circuit.

What is the expected ratio of free-hanging earlobes to attached earlobes in the offspring

Answers

The expected ratio of free-hanging earlobes to attached earlobes in the offspring is 1:2.

How to illustrate the ratio?

The diagram depicts a Punnett square used to predict the earlobe shape of two parents' offspring. The capital A represents free-hanging earlobes, while the lowercase a represents attached earlobes.

The Punnett square is a square diagram used to predict genotypes of a specific cross or breeding experiment. It is named after Reginald C. Punnett, who invented it in 1905. Biologists use the diagram to calculate the likelihood of an offspring having a specific genotype.

In this case, the genotype rato based on the attached diagram is 1:2.

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What is the expected ratio of free-hanging earlobes to attached earlobes in the offspring

a student pushes a shopping cart filled with groceries. the cart has a mass car of 12 kilograms (kg). The student pushes the cart with a force of 15 newtons (N). Assuming the ground is frictionless, how fast will the cart accelerate until the student stops applying force?

Answers

Answer:

the cart will have an acceleration of 1,25 m.s‐²

A runner covers the last straight stretch of a race in 8s.During that time he speeds up from 7 m/s to 9m/s. What is the acceleration

Answers

Given

Time taken is t=8 s.

The initial speed is u=7 m/s

The final speed is v=9 m/s.

To find

The acceleration

Explanation

We know the acceleration is the ratio of the difference in the speed to the time taken.

Thus,

\(\begin{gathered} a=\frac{v-u}{t} \\ \Rightarrow a=\frac{9-7}{8} \\ \Rightarrow a=\frac{2}{8}=\frac{1}{4}=0.25\text{ m/s}^2 \end{gathered}\)

Conclusion

The acceleration is

\(0.25\text{ m/s}^2\)

The graphic organizer compares energy transfer in two layers of the sun.

Which labels belong in the regions marked X and Y?


A)
X: Absorbs energy from the core
Y: Takes longer for photons to move through


B)
X: Releases energy to the photosphere
Y: Takes longer for photons to move through


C)
X: Takes longer for photons to move through
Y: Absorbs energy from the core


D)
X: Takes longer for photons to move through
Y: Releases energy to the photosphere

The graphic organizer compares energy transfer in two layers of the sun. Which labels belong in the regions

Answers

Answer:

B

Explanation:

Got it right

Answer:

B. X: Releases energy to the photosphere

Y: Takes longer for photons to move through

Explanation:

Right on ED2021, goodluck!

Air at 20 degrees celsius flows through the circular duct such that the absolute pressure is 100.8 kPa at A, and 101.6 kPa at B. Determine the volumetric discharge through the duct.

Answers

The volumetric discharge through the duct is calculated to be 0.000191 m³/s.

Formula used: Q = (π/4)d²(V1 - V2) where ,d = diameter of the circular ductV1 = volumetric flow rate at section 1V2 = volumetric flow rate at section 2Q = Volumetric discharge Solution: Given, Absolute pressure at A, P1 = 100.8 kPa Absolute pressure at B, P2 = 101.6 kPa Temperature of air, T = 20°CUsing the Ideal gas law,P1/ρ1T1 = P2/ρ2T2where, ρ1 and ρ2 are the densities of the air at section 1 and section 2 respectively.P1/ρ1T = P2/ρ2T

Putting the given values in above equation,100.8/ρ1(20 + 273) = 101.6/ρ2(20 + 273)ρ2/ρ1 = 0.975On comparing with the standard density,ρ/ρ₀ = (P/P₀) / (T/T₀)where, P₀ and T₀ are the standard pressure and standard temperature respectively. The standard pressure is 101.325 kPa and the standard temperature is 273 K.

Substituting the given values,ρ1/ρ₀ = (100.8/101.325) / (293/273) = 0.9285ρ2/ρ₀ = (101.6/101.325) / (293/273) = 0.9339ρ2 = 1.026 ρ1Now, using the Bernoulli's equation, P₁/ρ₁ + V₁²/2 = P₂/ρ₂ + V₂²/2

Assuming the air to be incompressible,ρ1 = ρ2Therefore, P₁ + V₁²/2 = P₂ + V₂²/2V₂²/2 - V₁²/2 = P₁ - P₂V₂² - V₁² = 2(P₁ - P₂)

Now, using the formula, Q = (π/4)d²(V1 - V2) where, d = diameter of the circular ductV1 = volumetric flow rate at section 1V2 = volumetric flow rate at section 2Q = Volumetric discharge

Putting the given values in the above formula,

Q = (π/4)d² [(V1 - V2)]Q = (π/4)d² [(V1² - V₂²)/(V1 + V2)]Q = (π/4)d² [(2(P₁ - P₂))/(V1 + V2)]Q = (π/4)(0.028³)² [(2(101.6 - 100.8))/(2V)]

where V = V1 = V2 (Assuming the air to be incompressible)

V = √[2(101.6 - 100.8)/0.028] = 37.42 m/sQ = (π/4)(0.028³)² [(2(101.6 - 100.8))/(2 x 37.42)] = 0.000191 m³/s

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Aspirin is an effective and widely used pain reliever. identify the functional group circled. ester aldehyde carboxylic acid carbonyl ketone

Answers

The functional group circled in the term "aspirin" is the carboxylic acid group.

Aspirin, also known as acetylsalicylic acid (ASA)), is a nonsteroidal anti-inflammatory drug (NSAID) used to reduce pain, fever, and/or inflammation and as an antithrombotic. Specific inflammatory conditions that aspirin is used to treat include Kawasaki disease, pericarditis, and rheumatic fever.

Aspirin can also have very serious side effects, such as bleeding in the brain or stomach or kidney failure. A rare side effect of daily low-dose aspirin is hemorrhagic stroke. Aspirin can help prevent and treat a range of health issues, but people under 18 should not take it without medical guidance.

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The boat's 'echo sounder' could not be used in an aeroplane to measure its heigh
above the ground unless it had been modified.

Answers

True, this is because the echo sounder that is applicable to boats cannot be used directly for airplanes

How does an echo sounder work?

By sending out sound waves and timing how long it takes for them to bounce back, an echo sounder, sometimes referred to as a sonar, is a device frequently used in boats to gauge the depth of the water beneath the craft.

When a sound pulse from an echo sounder strikes a solid item in the water, such as fish, vegetation, or other objects, the signal is reflected back to the surface.

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When removing heavy objects that may change the center of gravity of a vehicle ________. Group of answer choices

Answers

Answer:

______________________________

use tall safety and position hoist arms

A kid slides down a frictionless slide with a height of 4m. (Hint: the answers are independent
of the mass.)
a. What is the kid's speed at the bottom of the slide?
b. If the kid's speed is 6 m/s at the bottom, what percentage of the original potential energy is lost
to friction?

Answers

The kid's speed at the bottom of the slide is 8 m/s.

What is the kid's speed at the bottom of the slide?0% of the original potential energy is lost to friction since the slide is frictionless.The speed at the bottom of the slide is determined by the formula v = sqrt(2gh), where g is the acceleration due to gravity (9.81 m/s^2) and h is the height of the slide (4 m). Therefore, the speed at the bottom of the slide is 4.9 m/s.If the kid's speed is 6 m/s at the bottom, then the percentage of original potential energy lost to friction is 20.8%. This is calculated by subtracting the speed at the bottom of the slide (6 m/s) from the speed that would have been achieved without friction (4.9 m/s), then dividing the difference (1.1 m/s) by the speed without friction (4.9 m/s). This answer is then multiplied by 100 to get a percentage.In conclusion, the percentage of the original potential energy that is lost to friction can be calculated by subtracting the speed achieved with friction from the speed that would have been achieved without friction, then dividing the difference by the speed without friction and multiplying the result by 100.

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What is your hypothesis (or hypotheses) for this experiment?

(physically science lab report)​

Answers

Answer:The hypothesis (or hypotheses) for this experiment would be :

1) Experiment of motion( movement) can be performed in this lab.

2) Experiment of motion( movement) can be performed better in this lab.

3)  Only experiments of motion( movement) can be performed in this lab.

4) Experiment of motion( movement) can be performed more accurately in this lab.

5) No experiment of motion( movement) can be performed in this lab.

Explanation:

The hypothesis (or hypotheses) for this experiment would be :

Experiment regarding motion( movement) can be performed in this lab.

And Conclusion would be:

This lab is for motion.

We can only conclude that this lab is for motion when we find out that the motion experiments can be performed better or with higher accuracy or none other experiment can be carried out as easily as the motion experiment.

We only conclude when we test the hypothesis .

The hypothesis can be tested in a number of ways such as showing better results, or showing negative results of the said statement.

So there can be a few hypotheses as follows.

1) Experiment of motion( movement) can be performed in this lab.

2) Experiment of motion( movement) can be performed better in this lab.

3)  Only experiments of motion( movement) can be performed in this lab.

4) Experiment of motion( movement) can be performed more accurately in this lab.

5) No experiment of motion( movement) can be performed in this lab.

Explanation:

The equivalent resistance in a series circuit is found by ____
the resistances of all the resistors.

A. multiplying
B. comparing
C. adding the reciprocals of
D. adding​

Answers

Explanation:

In a series circuit the equivalent resistance is the algebraic sum of the resistances.

The Force F with rightwards harpoon with barb upwards on top (2,1,−4)N(2,1,−4)N is acting on the body of mass m=3kgm=3kg while causing it to change the postion from point A(2,8,0)mA(2,8,0)m to point B(28,75,68)mB(28,75,68)m.a) Find work done by the force (in one hundredth of Joule) on the distance ABAB.b) Find the total work done by the forces acting on the body over the distance ABAB.c) Find the magnitude of the acceleration of the body (answer to nearest hundredth of m/s2m/s2) as it moves from point AA to point BB.

Answers

The work done by the force (in one-hundredth of Joule) on the distance AB is -15300×J/100. The total work done by the forces acting on the body over the distance AB is -153 J. The magnitude of the acceleration of the body is 1.53 m/s².


a) To find the work done by the force on the distance AB, we first need to find the displacement vector from point A to point B:

Displacement vector, AB = B - A

= (28-2, 75-8, 68-0) = (26, 67, 68)

Now, we calculate the dot product of the force vector and the displacement vector:

F • AB = (2,1,-4) • (26,67,68)

= 2(26) + 1(67) - 4(68)

= 52 + 67 - 272

= -153
The work done by the force on the distance AB in one-hundredth of Joule is given by:
Work = F • AB

=-15300×J/100.

b) Since there is only one force acting on the body, the total work done by the forces acting on the body over the distance AB is the same as the work done by the force F:
Total work = -153 J

c) The acceleration of the body is given by Newton's Second Law of Motion:

F = ma

=> a = F/m

where F is the force and m is the mass of the body.

a = F/m

= (2, 1, -4)/3

= (0.67, 0.33, -1.33) m/s²

Therefore, the magnitude of the acceleration of the body is

|a| = √(0.67² + 0.33² + (-1.33)²) ≈ 1.53 m/s² (corrected to the nearest hundredth of m/s²).

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(a) A projectile's launch speed is five times its speed at maximum height. Find the launch angle 00. (3 points)(b) A boat crossing a wide river moves with a speed of 10.0 km/h relative to water. The water in the river has a uniform speed of 5.0 km/h due east relative to the ground. If the boat heads due north, determine the magnitude the boat velocity relative to the ground. (2 points)

Answers

boat velocity relative to the ground is = 11.18 Km/h.

Full solution in pic.

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(a) A projectile's launch speed is five times its speed at maximum height. Find the launch angle 00.

A wave is traveling at the speed of light. If it has a frequency of 4 x 10^15 Hz, what is its wavelength?

Answers

Answer:

7.5x10-^8m

Explanation:

the formulae is v=fh ,where f is frequency

h is wavelength

hence wavelength=v/f

since the speed of light is 3x10^8

then the wavelength =3 x 10^8/4 x 10^15

=7.5x10^-8m

why is gravitational potential energy greater then kinetic energy?

Answers

Answer:

The gravitational acceleration energy of an item increases as it rises in altitude.

Explanation: Hope this helps :D

Two 5000-kg passenger cars roll without friction (one at 1 m/s, the other at 2 m/s) toward one another on a level track. They collide, couple, and roll away together with a combined momentum of

Answers

The combined momentum of the passengers is 5000 kgm/s.

Combined momentum of the passenger

The combined momentum of the passengers is calculated as follows;

P = mv1 + mv2

where;

m is mass of the passengersv1 is velocity of the first passengerv2 is velocity of the second passenger

P = m(v1 + v2)

P = 5000(-1 + 2)

P = 5000 kgm/s

Thus, the combined momentum of the passengers is 5000 kgm/s.

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the general circulation of the atmosphere represents the actual air flow around the world and not just an average. group of answer choices true false

Answers

False The atmosphere's general circulation actually depicts the air flow around the world, not just an average.

What is global circulation in general?

The necessary transportation of heat from tropical to polar latitudes is performed by a system of winds that is known as the global circulation. Hadley cell, Ferrel cell, and Polar cell are the three cells in each hemisphere where air flows across the whole depth of the troposphere.

What type of nighttime air circulation pattern is typically linked with coastlines?

The wind turns around and blows out over the ocean at night because the land cools more quickly than the water. This is known as a land breeze. Additionally, the sun's rays have an impact on large-scale atmospheric circulation.

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What does the number of protons tell us about an element?

Answers

Answer:

All atoms of an element have the same number of protons, and every element has a different number of protons in its atoms. ... Therefore, the atomic number of an atom also tells you how many electrons the atom has. This, in turn, determines many of the atom's chemical properties.

Tyler and his family drove from Atlanta to Baltimore. They traveled a total of 678 miles over 2 days.

What is the reference point in this scenario?

Atlanta
Baltimore
678 miles
2 days

Answers

Answer:

atlanta

Explanation:

just took the test

The reference point in this scenario is Atlanta.

What is reference point of the journey?

The can be described as the starting point of the entire journey.

From the given statements the family started the journey from Atlanta and then traveled to Baltimore.

Atlanta is the start point (reference point) while Baltimore is the destination (finishing point).

Thus, the reference point in this scenario is Atlanta.

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A box of mass m is held at rest on a frictionless surface with force F up the ramp. The ramp has an angle
What is the magnitude of the normal force?
Choose 1 answer:

Answers

The magnitude of the normal force is to be considered as the mg cos θ when the box of mass m is at rest.

What is magnitude?

In terms of physics, it refer to the maximum size where it should be extended also it defined the object direction. It is factor for vector and the scalar quantities.

When the box of mass m should be at rest so here the ramp should be an angle so here the weight should be perpendicular to the string.

hence, The magnitude of the normal force is to be considered as the mg cos θ when the box of mass m is at rest.

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3. A car is travelling at initial speed u = 32 m/s. It then starts to decelerate with a = -2.0 m/s2
for 8.0 seconds.
a) What is the speed of the car after 8.0 seconds?
b) How far did the car travel during those 8.0 seconds?


Please help

Answers

Please find attached photograph for your answer. Do comment whether it is useful or not.

3. A car is travelling at initial speed u = 32 m/s. It then starts to decelerate with a = -2.0 m/s2for
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