Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
The rate of deforestation to create new buildings and farmland has increased over the last 100 years. What effect could this have on the atmosphere in the future?
The increase in deforestation can have a significant impact on the atmosphere in the future, mainly by reducing the number of trees that absorb carbon dioxide during photosynthesis.
Trees take in carbon dioxide and release oxygen as a byproduct, reducing the amount of carbon dioxide in the atmosphere. However, when trees are cut down, the carbon they have stored is released back into the atmosphere, contributing to increased levels of greenhouse gases.
The increase in greenhouse gases can lead to global warming and climate change, which can have a range of negative effects on the environment and human health, such as rising sea levels, increased frequency and severity of natural disasters, and more intense heat waves. Additionally, deforestation can lead to soil erosion, loss of biodiversity, and disruption of local ecosystems.
It is important to find ways to reduce deforestation and promote sustainable land use practices to mitigate the potential impacts on the atmosphere and the environment as a whole.
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how to synthesize 2-benzyl pentanoic acid from acetoacetic ester?
If you're attempting to synthesize 2 benzyl pentanoic acid from acetoacetic ester, keep in mind that you can do so fairly quickly by following these simplified instructions:
Begin by dissolving your acetoacetic ester into anhydrous diethyl ether and adding benzyl bromide and sodium hydroxide to the mix. Stir it all together at room temperature for around thirty minutes before reacting it with hydrochloric acid so that any remaining solvent evaporates out of your crude mixture; Lastly refine your creation by recrystallizing it from ethanol until you have pure 2 benzyl pentanoic acid.What is acetoacetic ester?From its pungent free scent to its solid state at temperatures ranging from 118 120°C, acetoacetic ester (better known as ethyl acetoacetate) offers significant value for those working within organic synthesis.
As one of many potent ketones utilized by researchers around the globe its unique properties make it ideal for building complex molecules essential for modern medicine and more.
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please help!! (3-6 & 1-5)
Answer:
part 1
3) 5.47 molecules
4) 11.15 moles
5) 2.95 × 10^23 molecules
6) 7670.9g
part2
1) 216000g
2) 5.71 molecules
3) 0.18 moles
4) 737.40g
5) 2.89×10^23 molecules
Explanation:
part 1
3) number of moles = (6.02 × 10^23)/11.0
=5.47molecules.
4) moles= (6.02 × 10^23)/(5.40×10^23)
= 11.15 moles
5) molar mass of NH3= 14+(3×1)= 14+3=17
number of molecules= (6.02 × 10^23) × 17/35
= (6.02 × 10^23)× 0.49 =2.95 × 10^23 molecules
6) molar mass of N2I6= (2×14) + (6×127)
= 28+762= 790g/mol
mass= 790 × (6.02 × 10^23)/(6.20×10^22)
=790× 9.71= 7670.9g
part 2
1) molar mass of CuBr= 64+80= 144g/mol
mass= 1500 × 144= 216000g
2) molecules = (6.02 × 10^23)/1.055
= 5.71 molecules
3) moles = (6.02 × 10^23)/(3.35×10^24)
= 0.18 moles
4) molar mass of SiO2= 28+ (2×16)= 28+32
=60gmol
mass= 60 × (6.02 × 10^23)/(4.90×10^22)
= 60× 12.29= 737.40g
5) molar mass of CH4= 12+(4×1)= 12+4=16g/mol
number of molecules= (6.02 × 10^23) × 16/33.6
= (6.02 × 10^23)× 0.48
= 2.89×10^23 molecules
Part E Why does the car stop? Where did the energy go?
When the moving car brakes to the stop the kinetic energy of car will be converted to the heat energy.
The mechanical brake will be applies to the friction force and it convert the kinetic energy of the car into the thermal energy that which then dissipates on atmosphere. The process of the braking will follow the principle of the conservation of the energy.
The conservation of the energy is the principle, that is expressed in its the most general form, and it is the first law of the thermodynamics. The first law of thermodynamics explains that "the energy of the universe remains the same."
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This question is incomplete, the complete question is :
A car in motion has kinetic energy. A moving car is suddenly stopped. Why does the car stop? Where did the energy go?
chlorine monobromide ionic or molecular
Please help. Thank you so much
Enthalpy change (H) and entropy change (S) are 11.7 103 Jmol-1 and 105 Jmol-1K-1, respectively, for a reaction at 25 °C.
What is the change in the free basic energy at 25 °C?The absolute entropies of a reactants and their products are S°(N2H4) (= half of this period J/(mol•K), S°(N2) = 191.6 J/(mol•K), or S°(H2) = 130.7 J/(mol•K) at 25°C, where the standard enthalpy change (H°) is 50.6 kJ/mol.
What is the calomel electrode's reduction potential at 25 C?E0 is known as 0.268 V at standard potential at 25°C, despite a slight variation in the computed value above. Similar to a silver-silver chloride electrode, the electrode potential is dependent on the chloride ion concentration.
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What happened to the liquid in titans lake?
The liquid in Titan's lake is believed to be composed of liquid methane and ethane, which are thought to be supplied by geological processes such as cryovolcanism and seepage from the surrounding terrain. Over time, the liquid in Titan's lake can evaporate, change due to geological or meteorological processes, or be affected by the changing seasons on the moon.
What is the mass in grams of 5.50 moles NH3?
• Your answer should have three significant figures.
Provide your answer below.
n Proctor
deo
DE
SEDRAG
a
Answer:
Mass = 93.5 g
Explanation:
Given data:
Number of moles of NH₃ = 5.50 mol
Mass of NH₃ = ?
Solution:
Formula:
Mass = number of moles × molar mass
Molar mass of ammonia = 17 g/mol
By putting values,
Mass = 5.50 mol × 17 g/mol
Mass = 93.5 g
What is an extended structure? How do extended structures make up substances
2.
Which mixture could be a useful buffer in a solution?
acetic acid (CH3CO2H) and hydrochloric acid (HCl)
sodium hydroxide (NaOH) and elemental sodium (Na)
ammonia (NH3) and ammonium chloride (NH4Cl)
acetic acid (CH3CO2H) and ammonia (NH3)
Pls answer quickly
Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C
A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.
In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.
Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.
Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.
Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).
The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.
Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.
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Which choice shows a true conditional with a correctly identified
hypothesis and conclusion
how much energy is contained in 3moles of chlorine
Answer:
1 mol of cl2 contains 71 g
3 mol of cl2 will contain÷
3×71=213 g
Explanation:
There ;3
Answer:
213 g
Explanation:
multiply 3 moles by relative atomic mass of chlorine which is 35.45×2 because its two chlorines and your answer will be 213g
Chemical reactions cannot involve different states of matter.
True
False
Answer:
False
Explanation:
I really have a strong hunch about my answer ,try that out....
HOPE IT HELPS YOU PO !!!!
Answer:
the answer is false
Explanation:
like me please
1. These values were obtained as the mass of products from the same reaction: 8.83 g;
8.84 g; 8.82 g. The known mass of products from that reaction is 8.60 g. The values
are:
accurate
precise
both precise and accurate
neither precise nor accurate
0
Answer:
precise
Explanation:
precise because they are almost the same measurement over and over ( remember in significant digits the last number is considered to be an estimate on measurements). The known value, 8.60 g, is pretty far from the measurements taken so it cant be accurate.
The values obtained in the measurement of the mass of products from the same reaction are precise but not accurate.
Recall that:
Precision refers to the closeness of repeated measurements made on the same variableAccuracy refers to the proximity of a measurement to its true, predetermined value.In this case, one can see that the repeated measurements of the mass of the products were close to each other with a range of 0.02 g.
The average of the measurement can be calculated such that:
8.83 + 8.84 + 8.82/3 = 8.83 g
The predetermined mass of products from the reaction is 8.60 g. The difference from the average measurement can be calculated as:
8.60 - 8.83 = 0.23
The difference between the measurement and true value is significant. thus, the result is not accurate.
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Please need help ASAP
The effect of table salt and sugar on bubbles is that sugar makes it easier to blow and stronger whereas salt makes it difficult to blow bubbles.
(i) The combination in cup 2 made blowing bubbles simpler since the bubbles lasted longer; nevertheless, when the bubbles struck something, they popped just as easily as the ones in cup 1.
(ii) However, compared to cup 1, the combination in cup 3 made blowing bubbles more challenging.
(iii) Compared to salt, which did not mix well together with liquid dish detergent and made it more difficult to blow huge, forceful bubbles, sugar was an excellent ingredient to mix with liquid dish detergent.
(iv) If we were to carry out this experiment further, we may experiment with other materials in the cups to discover which ones the liquid dish detergent reacted best with. Using cups 4 and 5 for flour and brown sugar and cup 6 for pepper, respectively. Then, we would contrast these combinations with the cups that we had already examined.
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Experiment 4: A chemist mixes aqueous solutions of sodium hydroxide and aluminum chloride in a double-displacement reaction, which forms a white solid precipitate and a clear solution. Write the complete, balanced molecular equation for the reaction. Include physical states.
balanced equation:
The balanced molecular equation for the reaction between sodium hydroxide (NaOH) and aluminum chloride (\(AlCl_3\)) in aqueous solution can be written as follows: 2NaOH(aq) + 3\(AlCl_3\)(aq) → 3NaCl(aq) + \(Al(OH)_3\)(s)
In this reaction, sodium hydroxide (NaOH) reacts with aluminum chloride (\(AlCl_3\)) to form sodium chloride (NaCl) and aluminum hydroxide (\(Al(OH)_3\)). The coefficients in the balanced equation indicate the stoichiometric ratio between the reactants and products.
The physical states of the substances are indicated by the symbols (aq) for aqueous solutions and (s) for the solid precipitate.
The reaction is a double-displacement reaction, also known as a precipitation reaction. Double-displacement reactions involve the exchange of ions between two compounds, resulting in the formation of a precipitate.
In this case, sodium hydroxide and aluminum chloride react to form sodium chloride and aluminum hydroxide, with aluminum hydroxide being the white solid precipitate.
It's worth noting that the actual reaction might involve hydrated forms of the compounds, such as NaOH·x\(H_2O\) and \(AlCl_3\)·y\(H_2O\). However, for simplicity, these hydrated forms are not included in the balanced equation.
Overall, the balanced equation represents the chemical reaction between sodium hydroxide and aluminum chloride, showing the reactants, products, and their stoichiometric ratios.
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What is the value of Ksp for Ag2SO4 if 5.40g is soluble in 1.00 L of water?
The expression for the equilibrium constant is Ksp (= [Ag+][I-] = (x)(x) = x2. Step 3: Use the solubility of AgI to calculate the molar solubility. At 100oC, silver sulphate dissolves in water at a rate of around 1. 4 grams per mL.
How should a Ksp equation be written?The equilibrium formula, Ksp, can be expressed as Ksp (= [products]/[reactants] and represents a ratio of products to reactants. Equilibrium balance between a cationic solid as well as its solution's ions is shown by this statement.
What is the Ksp equivalent of solubility?The greater a substance's K s p chemical value, the more soluble it is. What exactly are K sandeep units. In actuality, it lacks a unit! Since the molar quantities of the products and reactants vary for each equation, the K s p value lacks units.
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how many moles are in 6.7 x 10^25 molecules of H2SO4
Answer:
\( \huge{ \boxed{111.30 \: \: \text{moles}}}\)
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
\( \bold{n = \frac{N}{L} \\ }\)
where
n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities.
From the question.
N = 6.7 × 10²⁵ \( \: H_2SO_4 \: \) molecules
\(n = \frac{6.7 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 111.2956...\)
We have the final answer as.
111.30 molesis Crystallizing sodium Acetate a physical or chemical change
Answer: physical please let me know if its wrong !
2Na + 2H20 - 2NaOH + H2
→
For the reaction shown here, predict the number of moles of both products, sodium hydroxide, and hydrogen gas, when ten moles of
sodium and ten moles of water fully react
A
B)
Ten moles of sodium hydroxide and ten moles of hydrogen gas will be
produced
Ten moles of sodium hydroxide and five moles of hydrogen gas will be
produced
Five moles of sodium hydroxide and ten moles of hydrogen gas will be
produced
moride and five moles of hydrogen gas will be
Answer: B) Ten moles of sodium hydroxide and five moles of hydrogen gas will be produced
Explanation: Got it right on USATestPrep
A sample consists of 75.46% carbon, 4.43% hydrogen, and 20.10% oxygen by mass. Its molar mass is about 318 g/mol.
1.) Determine the empirical formula of the sample.
2.) Determine the molecular formula of the sample.
Which of the following gas samples would contain the same amount of gas as 200 mL of helium, He(g), at 25° C and 1 atm?Select one:a.40 mL of methane, CH4 (g), at 25° C and 1 atmb.400 mL of hydrogen, H2 (g), at 25° C and 1 atmc.200 mL of neon, Ne (g), at 25° C and 1 atmd.all the above
In this question, we have to choose which of the options will present the same amount as 200 mL of Helium gas, at 25°C and 1 atm of pressure.
In order to find this answer, we can use the Avogadro's law, in which we will have the same temperature and pressure, and when two gases have the same value of T and P, and also Volume, the number of moles, or quantity will also be the same.
Therefore we are looking for the option that has the same measurement values as the Helium gas, and the option will be 200 mL of Neon gas at 25°C and 1 atm, the same values will generate the same amount of each gas.
The answer will be letter C
Which layer of the atmosphere is the hottest? Why do you think that is?
Answer:
thermosphere
The thermosphere is often considered the "hot layer" because it contains the warmest temperatures in the atmosphere. Temperature increases with height until the estimated top of the thermosphere at 500 km.
Explanation:
Calculate the relative molecular mass of hydrated Copper (II) tetraoxosulphate (VI) CuSO4.5H₂O (Cu = 64 S = 32 H = 1 0 = 16).
The relative molecular mass of hydrated Copper (II) tetraoxosulphate (VI) CuSO4.5H₂O is 249.
What is molecular mass?Molecular mass is a measure of the total mass of one mole of a substance, which is defined as the mass of the substance divided by the number of molecules it contains. It is typically expressed in g/mol and is also known as molar mass. Molecular mass is determined by the types and number of atoms that compose a molecule, and is an important factor in understanding the properties of a substance.
This is calculated by adding the atomic masses of all the atoms present in the compound.
The atomic mass of copper is 64, sulphur is 32, oxygen is 16, and hydrogen is 1.
So, the relative molecular mass of hydrated Copper (II) tetraoxosulphate (VI) CuSO4.5H₂O is 64 + 32 + (16*4.5) + (1*5) = 249.
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How are prisms and raindrops alike?
They are both transparent.
They both reflect white light.
They are both translucent.
They both refract white light.
they both refract white light.
Answer:
They both reflect white light.
Explanation:
How raindrops and prism are similar?
Raindrops and prisms are similar because they both cause light to bend when it enters a prism or raindrop. When light enters a raindrop it causes the light to bend (refract) and separates the white lights into different wavelengths, allowing us to see the individual colors of the rainbow.
CuBr2 percent composition
The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.
To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.
The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.
Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol
Now, let's calculate the percent composition of each element in CuBr₂:
Percent composition of copper (Cu):
Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%
Percent composition of bromine (Br):
Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%
Therefore, the percent composition of CuBr₂ is approximately:
- Copper (Cu): 28.46%
- Bromine (Br): 71.54%
These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.
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Wind has less energy as it slows, and _____ of sediment occurs.
As the wind slows, silt is deposited because the wind has less energy.
When a stream slows down, what happens to the sediment?Deposition in rivers and streams. A stream or river begins to deposit silt when it begins to slow down. In steep terrain, larger sediments fall, but smaller sediments can still be carried. As the slope gets less steep, smaller sediments are dropped.
What transpires to sediments as wind speed decreases?Sediment that has been eroded is deposited in a new location when the speed of the wind or water slows. Fertile land is produced as a result of the sedimentation process.
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The evidence of quantized energy states in atoms comes from
1. photoelectric effect
2. rainbows from prisms
3. oil drop experiment
4. diffraction
5. bright line or emission spectra 6. gold foil experiment
The evidence for quantized energy states in atoms stems primarily from the photoelectric effect, bright line spectra, and diffraction phenomena. Options 1,4 and 5 are correct.
The evidence of quantized energy states in atoms comes from several experimental observations, which collectively provide a comprehensive understanding of atomic structure and the behavior of electrons within atoms.
One of the key pieces of evidence is the observation of the photoelectric effect (1). When light shines on a metal surface, electrons are ejected from the surface. The observation that electrons are only ejected if the light has a minimum frequency, regardless of its intensity, supports the idea that energy is quantized in discrete packets known as photons.
Another crucial observation is the presence of bright line or emission spectra (5). When atoms are excited, they emit light at specific wavelengths that correspond to distinct energy transitions. These discrete emission lines indicate that electrons can only exist in specific energy levels within an atom, and they transition between these levels by absorbing or emitting photons of precise energy.
The phenomenon of diffraction (4) also provides evidence for quantized energy states. Diffraction occurs when light passes through a narrow slit or encounters a periodic structure. The resulting pattern indicates that light behaves as waves with specific wavelengths. This suggests that the energy of light is quantized and can only exist in certain discrete values.
While rainbows from prisms (2) and the oil drop experiment (3) are not directly related to quantized energy states in atoms, they are important experiments in their own right. Rainbows result from the dispersion of white light into its component colors due to different wavelengths of light bending at different angles. The oil drop experiment explores the behavior of charged oil droplets in an electric field, providing insights into charge quantization.
Lastly, the gold foil experiment, also known as the Rutherford scattering experiment, is significant but not directly related to quantized energy states. It demonstrated that the atom has a small, dense, positively charged nucleus by observing the deflection of alpha particles fired at a thin gold foil.
These experimental observations support the fundamental concept that energy levels in atoms are discrete and that electrons occupy specific energy states within an atom. Options 1,4 and 5 are correct.
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how does the study of genetics and Dna
help the study of evolution
What is the mass of NaCl required to make 150 grams of a 12% solution of NaCl in water? (5 points)
a
13 grams
b
18 grams
c
22 grams
d
32 grams
Answer:
18 grams
Explanation:
Mass of solution = 150 g
Percent concentration = 12%
Percent concentration = mass of solute/mass of solution × 100
Let the mass of solute be x
12= x/150 × 100
12= 100x/150
12 × 150 =100x
x= 12 × 150/100
x = 18 g
Answer:
18
Explanation:
Mass of solution = 150 g
Percent concentration = 12%
Percent concentration = mass of solute/mass of solution × 100
Let the mass of solute be x
12= x/150 × 100
12= 100x/150
12 × 150 =100x
x= 12 × 150/100
x = 18 g