Solve for the current i in the circuit of Fig. 4. 103 using Thevenin's theorem. (Hint. Find the Thevenin equivalent seen by the 12-Ω resistor. 10Ω 12Ω 40Ω 150 V +- 60 V
Answers
The current i in the circuit of the diagram using Thevenin's theorem os 3amp.
What is the Theorem about?Thevenin's theorem is a fundamental theory of electrical engineering that claims that any linear electrical network with voltage sources, current sources, and resistors may be substituted by an equivalent circuit with a single voltage source and a single series resistor.
It should be noted that to use Thevenin's theorem, we must first determine the Thevenin voltage, which is the open-circuit voltage at the original circuit's output terminals. Thevenin resistance is the equivalent resistance of the original circuit as seen from the output terminals when all voltage and current sources are shut off.
In this case, the current i in the circuit of
the diagram using Thevenin's theorem is 3amp.
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Related Questions
Write the Verilog code for the following logic expression using NAND gate built-in primitives (10 pts) yl= x3 + x1x2' + xl'x2 Then generate the test bench module, and the output waveform.
Answers
The Verilog code for the given logic expression using NAND gate built-in primitives is implemented by combining NAND gates to represent the required logic operations. The resulting circuit is then simulated using a test bench module to generate the output waveform.
To implement the logic expression yl = x3 + x1x2' + xl'x2 using NAND gates, we first need to break down the expression into individual logic operations.
The expression consists of three terms: x3, x1x2', and xl'x2. Each term is implemented using NAND gates as follows:
x3: This term is simply connected to the output yl, so no additional NAND gates are required.
x1x2': To implement this term, we first take the complement of x2 using a NAND gate (let's call it n2). Then we connect x1 and n2 to another NAND gate (let's call it n1). The output of n1 represents x1x2'. Finally, we connect the output of n1 to a NAND gate along with x3 (let's call it n3), which produces the final output yl.
xl'x2: This term is implemented similarly to x1x2'. We take the complement of x1 using a NAND gate (let's call it n4). Then we connect xl and n4 to another NAND gate (let's call it n5). The output of n5 represents xl'x2. Finally, we connect the output of n5 to a NAND gate along with the output of n3 (yl) to obtain the final output yl.
The Verilog code for the above implementation is as follows:
module LogicExpressionNAND(input wire x1, x2, x3, output wire yl);
wire n2, n4;
wire n1 = n2;
wire n5 = n4;
wire n3 = n1 | x3;
assign n2 = ~(x2 & x2);
assign n4 = ~(x1 & x1);
assign yl = n5 & n3;
endmodule
To simulate and generate the output waveform, a test bench module can be created. This module provides inputs to the main module and captures the outputs for analysis. It can be written as follows:
module LogicExpressionNAND_tb;
reg x1, x2, x3;
wire yl;
LogicExpressionNAND dut(.x1(x1), .x2(x2), .x3(x3), .yl(yl));
initial begin
$dumpfile("waveform.vcd");
$dumpvars;
// Test Case 1: x1=0, x2=0, x3=0
#10 x1 = 0; x2 = 0; x3 = 0;
// Test Case 2: x1=1, x2=0, x3=1
#10 x1 = 1; x2 = 0; x3 = 1;
// Test Case 3: x1=1, x2=1, x3=0
#10 x1 = 1; x2 = 1; x3 = 0;
// Test Case 4: x1=1, x2=1, x3=1
#10 x1 = 1; x2 = 1; x3 = 1;
$finish;
end
endmodule
In the above test bench module, the values of x1, x.
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why is tubing sometimes coiled when installed in a car or vechile
Answers
Answer:
Coiled tubing is often used to carry out operations similar to wire lining.
joyland is going to open an alligator themed amusement park whose main attraction will be a huge mechanical alligator near the coffee shop. the jaws of the mechanical alligator will be actuated using a hydraulic cylinder; this hydraulic ram has to overcome the self-weight of the jaws by providing sufficient force. the upper jaw weighs 670lbf and lower jaw weighs 450lbf. each of these weights are considered to be acting upon their respective center of gravities i.e. points e and g respectively. the lower jaw makes an angle of 70º with the negative x-axis measured in cw direction. cd=40in & bc=60in. each of the jaws has partial gear incorporated and they mesh as shown in the figure. assume any data if required. a) specify and indicate the number and types of links and joints utilized in this mechanism. b) calculate the mobility of the mechanical alligator. c) considering the jaws are stationary; conduct the static force analysis of the mechanical alligator and design the hydraulic cylinder with the necessary force that it should carry to sustain the mechanism d) if the lower jaw is to be designed such that it rotates at a constant clockwise angular velocity of 10rpm; then conduct the kinematic (position, velocity and acceleration) analysis of the mechanical alligator determine angular acceleration of upper jaw and linear acceleration of hydraulic cylinder (ram). e) also construct the mechanism in virtual environment and perform the kinematic analysis in any mechanism analysis software (mechanalyzer/ps motion/gim/solidworks). f) compare the analytical/graphical & simulation results.
Answers
Answer:
i can't have your cake and eat it
An air-standard Diesel cycle engine operates as follows: The temperatures at the beginning and end of the compression stroke are 30 °C and 700 °C, respectively. The net work per cycle is 590.1 kJ/kg, and the heat transfer input per cycle is 925 kJ/kg. Determine the a) compression ratio, b) maximum temperature of the cycle, and c) the cutoff ratio, v3/v2.
Answers
This question is incomplete, the complete question is;
An air-standard Diesel cycle engine operates as follows: The temperatures at the beginning and end of the compression stroke are 30 °C and 700 °C, respectively. The net work per cycle is 590.1 kJ/kg, and the heat transfer input per cycle is 925 kJ/kg. Determine the a) compression ratio, b) maximum temperature of the cycle, and c) the cutoff ratio, v3/v2.
Use the cold air standard assumptions.
Answer:
a) The compression ratio is 18.48
b) The maximum temperature of the cycle is 1893.4 K
c) The cutoff ratio, v₃/v₂ is 1.946
Explanation:
Given the data in the question;
Temperature at the start of a compression T₁ = 30°C = (30 + 273) = 303 K
Temperature at the end of a compression T₂ = 700°C = (700 + 273) = 973 K
Net work per cycle \(W_{net\) = 590.1 kJ/kg
Heat transfer input per cycle Qs = 925 kJ/kg
a) compression ratio;
As illustrated in the diagram below, 1 - 2 is adiabatic compression;
so,
Tγ\(^{Y-1\) = constant { For Air, γ = 1.4 }
hence;
⇒ V₁ / V₂ = \((\) T₂ / T₁ \()^{\frac{1}{Y-1}\)
so we substitute
⇒ V₁ / V₂ = \((\) 973 K / 303 K \()^{\frac{1}{1.4-1}\)
= \((\) 3.21122 \()^{\frac{1}{0.4}\)
= 18.4788 ≈ 18.48
Therefore, The compression ratio is 18.48
b) maximum temperature of the cycle
We know that for Air, Cp = 1.005 kJ/kgK
Now,
Heat transfer input per cycle Qs = Cp( T₃ - T₂ )
we substitute
925 = 1.005( T₃ - 700 )
( T₃ - 700 ) = 925 / 1.005
( T₃ - 700 ) = 920.398
T₃ = 920.398 + 700
T₃ = 1620.398 °C
T₃ = ( 1620.398 + 273 ) K
T₃ = 1893.396 K ≈ 1893.4 K
Therefore, The maximum temperature of the cycle is 1893.4 K
c) the cutoff ratio, v₃/v₂;
Since pressure is constant, V ∝ T
So,
cutoff ratio S = v₃ / v₂ = T₃ / T₂
we substitute
cutoff ratio S = 1893.396 K / 973 K
cutoff ratio S = 1.9459 ≈ 1.946
Therefore, the cutoff ratio, v₃/v₂ is 1.946
Vacancy diffusion statement refer to that a mechanism that
atom at lattice traveled to a vacant latblèe
• True
• False
Answers
Answer:
true
Explanation:
3. As a system is charged with vapor refrigerant, the refrig-
erant tank will likely
A. experience a pressure drop and a temperature rise.
B. Experience a pressure rise and a temperature rise.
C. experience a pressure drop and a temperature drop.
D. experience a pressure rise and a temperature drop.
Answers
Answer:
b
Explanation:
the continental margin is composed of the following zones:
Answers
The continental margin is composed of the following three zones: the continental shelf, the continental slope, and the continental rise.
The zone between the ocean floor and the continental slope is known as the continental margin. It is the underwater section of a continent that contains the continental shelf, continental slope, and continental rise.
The Continental Shelf: It is the sloping extension of the continent into the ocean. It starts at the coastline and goes all the way to the continental slope. The continental shelf's breadth is determined by how gently the continent slopes downward into the ocean.
The Continental Slope: The continental slope, as the name implies, is a steep slope that leads down to the ocean floor. The incline is between 3° and 6°. The slope of the continental slope is steeper than that of the continental shelf.
The Continental Rise: It is a gently sloping sediment-covered area that links the continental slope to the deep-ocean floor. The continental rise is a result of the accumulation of sediment that falls off the continental shelf and slope over time.
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Lynx eat snowshoe hares, and snowshoes hears eat plants. Which term can be applied to the lynx in this food chain example? Primary consumer predator secondary consumer
Answers
Answer:
primary consumer because YES
Answer:predator and secondary consumer
Explanation:
Carbon tracking is the formation of carbonized dust between distributor cap terminals. T/F
Answers
True. Carbon tracking is the formation of a conductive carbonized dust or residue between the terminals of the distributor cap or the spark plug wires.
It can cause misfires, rough idle, and engine hesitation. It is typically caused by moisture in the distributor cap, damaged or worn-out spark plug wires, or a damaged distributor cap. In order to prevent carbon tracking, it is recommended to replace worn-out spark plug wires and distributor cap, and to keep the engine clean and dry. Additionally, dielectric grease can be applied to the terminals of the distributor cap and the spark plug wires to prevent moisture from causing carbon tracking.
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1. A wood board is one of a dozen different parts in a homemade robot kit. The width, depth, and height dimensions of the board are 7. 5 x 14 x 1. 75 inches, respectively. The board is made from southern yellow pine, which has an air dry weight density of. 025 lb/in. 3. A. What is the volume of the wood board? Precision = 0. 0
Answers
This question uses the theory of volume, which states that the volume of an object is the product of its width, depth, and height. The volume of the wood board is 221.25 cubic inches.
What is the volume of an object?
Volume is a measure of the amount of three-dimensional space a substance or object occupies. It is the amount of space that an object or substance occupies, or that is enclosed within a container. It is usually expressed in cubic units, such as liters (L), cubic centimeters (cm3), or cubic meters (m3). The basic formula for calculating the volume of a three-dimensional shape is length x width x height. This formula can be used to calculate the volume of a cube, rectangular prism, cylinder, or other three-dimensional shape.
The steps for the answer as follows:
Step 1: Calculate the volume of the board. This is done by multiplying the width, depth and height of the board together.
Step 2: The width, depth, and height of the board are 7.5, 14, and 1.75 inches, respectively.
Therefore, the volume of the board is 7.5 x 14 x 1.75 = 221.25 cubic inches.
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Can someone help me plz!!! It’s 23 points
Answers
Answer:
0.00695 A
Explanation:
µ represents \(10^{-6}\). Multiply this by 6,950.
A person of dubious technical ability tells you that two of the direction angles for a particular vector are 30 and 40 degrees. If these direction angles are feasible, then determine the possible values for the remaning direction angle. If these direction angles are not feasible, explain why?
Answers
In order to solve challenges that are motivated by the intended function, destination ip address, materials, price, and sustainability, interface design is a method.
Interaction Design: What Is It?The process of creating interactive goods and services known as interaction design (IxD) involves an analysis of both the end product and how users will engage with it. Therefore, thorough consideration of users' requirements, constraints, settings, etc. enable designers to alter the output to satisfy specific requirements. As you may already be aware, there are many similarities between interface design and UX design. Because a user's interaction with a product involves both the user as well as the product to a substantial extent, UX design seeks to impact that relationship Describe Interact.
What are the 4 types of interaction?Answer and Explanation: The four primary types of interaction among community members are competition, predation and parasitism, mutualism, and commensalism.
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order of Design Process steps ?
Answers
Answer:
The five stages of Design Thinking, according to d.school, are as follows: Empathise, Define , Ideate, Prototype, and Test. Let's take a closer look at the five different stages of Design Thinking
Explanation:
How much would you spend on gasoline each year if you drove 10,000 miles over the year and your vehicle achieves 15 miles per gallon with gasoline prices at $4.00 a gallon? Now substitute your vehicle with a hybrid-electric automobile that achieves 60 miles per gallon. Calculate the yearly cost for fuel with this vehicle
Answers
Answer:
a. \(Total\ Cost = \$2667\)
b. \(Total\ Cost = \$667\)
Explanation:
(a)
Given
\(Distance = 10000\ miles\)
\(Rate = 15\ miles/gallon\)
\(Price = \$4.00/gallon\)
Required
Determine the total amount spent in a year
First, we need to determine the number of gallons used in a year;
\(Total\ Gallons = Distance/Rate\)
\(Total\ Gallons = 10000miles /\frac{15miles}{gallon}\)
\(Total\ Gallons = 10000miles * \frac{1\ gallon}{15\ miles}\)
\(Total\ Gallons = 10000 * \frac{1\ gallon}{15}\)
\(Total\ Gallons = \frac{10000\ gallons}{15}\)
\(Total\ Gallons = \frac{10000}{15}\ gallons\)
Next, is to determine the total cost:
\(Total\ Cost = Total\ Gallons * Price\)
\(Total\ Cost = \frac{10000}{15}\ gallon * \frac{\$4}{gallon}\)
\(Total\ Cost = \frac{10000}{15} * \$4\)
\(Total\ Cost = \frac{10000 * \$4}{15}\)
\(Total\ Cost = \frac{\$40000}{15}\)
\(Total\ Cost = $2666.66666667\)
\(Total\ Cost = \$2667\) (approximated)
(b)
Given
\(Rate = 60\ miles/gallon\)
Required
Determine the total amount spent in a year
First, we need to determine the number of gallons used in a year;
\(Total\ Gallons = Distance/Rate\)
\(Total\ Gallons = 10000miles /\frac{60\ miles}{gallon}\)
\(Total\ Gallons = 10000miles * \frac{1\ gallon}{60\ miles}\)
\(Total\ Gallons = 10000 * \frac{1\ gallon}{60}\)
\(Total\ Gallons = \frac{10000\ gallons}{60}\)
\(Total\ Gallons = \frac{10000}{60}\ gallons\)
Next, is to determine the total cost:
\(Total\ Cost = Total\ Gallons * Price\)
\(Total\ Cost = \frac{10000}{60}\ gallon * \frac{\$4}{gallon}\)
\(Total\ Cost = \frac{10000}{60} * \$4\)
\(Total\ Cost = \frac{10000 * \$4}{60}\)
\(Total\ Cost = \frac{\$40000}{60}\)
\(Total\ Cost = \$666.666666667\)
\(Total\ Cost = \$667\) (approximated)
During which step of a free-radical chain-growth polymerization does the polymer actually grow or chain extend?.
Answers
During propagation step of a free-radical chain-growth polymerization does the polymer actually grow or chain extend.
What is radical chain-growth polymerization?
The process of free-radical chain growth in polymers. Common free-radical reactions include polymerizations using free-radical mechanisms. The formation of radicals is the initiation, the development of the products is the propagation, and the ending of the free-radical chain reactions is the termination.What distinguishes step growth polymerization from chain growth polymerization?
The polymer chain in chain growth always expands one monomer at a time. The polymer chain doubles with each step of step development. The polymer chain's rate of expansion is drastically different in these two situations as a result. Every coupling step causes chain growth, which causes the chain length to gradually expand.Learn more about radical chain-growth polymerization
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[3] Question 5 5.1 Calculate the maximum tonnage required to compact a tantalum slug with a diameter of 88 mm. (3)
Answers
The maximum tonnage required for compacting the tantalum slug with a diameter of 88 mm was determined to be 907.4 kN.
Given the diameter of a tantalum slug as 88 mm, the maximum tonnage required to compact the tantalum slug is determined as follows;
Consider the cross-sectional area (A) of the tantalum slug, which is given by:
A = π/4 (d²)
A = π/4 (88 mm)²
= 6,049 mm²
Also, the maximum compressive stress (σ) required for compacting the tantalum slug is known to be 150 MPa.
Furthermore, the formula for the maximum tonnage required for compacting the tantalum slug is given as:
T = σA
Where T is the maximum tonnage and σ is the maximum compressive stress.
Finally, substituting the values, the maximum tonnage required for compacting the tantalum slug is given as:
T = σA
T = (150 MPa) (6,049 mm²)
= 907,350 N
Therefore, the maximum tonnage required to compact a tantalum slug with a diameter of 88 mm is 907,350 N or approximately 907.4 kN.
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The peak voltage of a 240 VRMS sine wave is approximately 1. 120v 2. 340v 3. 170v 4.300v I believe it would be 170v if im correct? Can you help me out
Answers
The peak voltage of a sine wave is calculated as the RMS voltage multiplied by the square root of 2. Therefore, the peak voltage of a 240 VRMS sine wave is approximately 340 volts. So, your answer is option 2, 340v.
What is the explanation for the above response?The RMS voltage (VRMS) of a sine wave is the "root-mean-square" average value of the waveform. It is calculated by taking the square root of the mean of the squares of the instantaneous voltage values over one cycle of the waveform.
For a sine wave, the peak voltage (Vp) is the highest voltage value that the waveform reaches, and it occurs at 90 degrees or pi/2 radians (a quarter cycle) after the zero crossing.
The relationship between VRMS and Vp for a sine wave is given by the formula:
Vp = VRMS x sqrt(2)
This formula shows that the peak voltage of a sine wave is equal to the RMS voltage multiplied by the square root of 2.
Therefore, in the case of a 240 VRMS sine wave, the peak voltage would be:
Vp = VRMS x sqrt(2) = 240 x 1.414 = 339.36 volts
Rounding this to the nearest whole number, we get the answer of 340 volts, which is option 2.
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briefly explain why boeing did not submit a formal review of the maneuvering characteristic augmentation system (mcas) to faa regulators so that the regulators could determine how the software worked to insure safety.
Answers
Boeing did not submit a formal review of the MCAS to FAA regulators primarily due to an oversight in communication and the desire to expedite the certification process.
Boeing did not submit a formal review of the Maneuvering Characteristic Augmentation System (MCAS) to FAA regulators because they classified it as a minor modification to the existing 737 design, and therefore did not require a separate safety review. The company assumed that regulators were already familiar with the system, leading to a lack of in-depth assessment of its safety implications. However, the MCAS system played a crucial role in the two deadly crashes of the Boeing 737 MAX, and it was later discovered that the system was flawed and could override the pilots' controls, leading to a loss of control of the aircraft. The lack of proper safety oversight and review by the FAA and Boeing ultimately led to tragic consequences. Additionally, Boeing aimed to maintain a competitive edge in the market, resulting in a faster development and approval timeline.
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Los trabajadores pueden trabajar directamente debajo de cargas suspendidas si
Answers
los trabajadores no pueden trabajar directamente debajo de cargas suspendidas sin ninguna medida de precaución. El trabajo debajo de las cargas suspendidas es un trabajo peligroso y puede ser mortal si no se toman medidas de seguridad.
El peso de una carga suspendida puede ser demasiado grande para ser sostenido por el equipo de izaje y puede caerse y causar lesiones graves o incluso la muerte. Por lo tanto, es importante que los trabajadores estén capacitados y se les enseñe cómo trabajar de manera segura en estas situaciones.Los empleados deben estar informados y ser conscientes de los riesgos asociados con el trabajo debajo de las cargas suspendidas.
Si hay alguna duda acerca de la seguridad del equipo o la capacidad del equipo de izaje, el trabajo debe ser detenido hasta que se realice una inspección y se asegure la seguridad. Además, se deben seguir los procedimientos adecuados para levantar y mover las cargas, y se deben usar los equipos de protección personal necesarios.
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Water enters a centrifugal pump axially at atmospheric pressure at a rate of 0.12 m3
/s and at a
velocity of 7 m/s, and leaves in the normal direction along the pump casing, as shown in Figure.
Determine the force acting on the shaft (which is
also the force acting on the bearing of the shaft) in
the axial direction.
Answers
Answer:
Water enters a centrifugal pump axially at atmospheric pressure at a rate of 0.12 m3/s and at a velocity of 7 m/s, and leaves in the normal direction along the pump casing, as shown in Fig. PI3-39. Determine the force acting on the shaft (which is also the force acting on the bearing of the shaft) in the axial direction.
Step-by-step solution:
Step 1 of 5
Given data:-
The velocity of water is .
The water flow rate is.
Describe how outlining a plan for taking engineering classes is of paramount importance and in your opinion, what is the one BIG mistake some students make in the process that results in their failure to achieve the goal of successfully completing their engineering coursework? How would proper planning and working out problems in Math provide the groundwork for engineering classes.
Answers
Outlining a plan for taking engineering classes is important to avoid being overwhelmed by the workload and to successfully complete the coursework. One big mistake students make is underestimating the time and effort required. Proper planning and working out problems in math provide the foundation for success in engineering classes. Consultation with academic advisors, reviewing course requirements, and developing a study schedule are all important steps in outlining a plan for taking engineering classes.
CompTIA Network Plus N10-008 Question:
How many hosts are on a /30 network?
a.) None, as there are only two addresses: Network ID and Broadcast ID.
b.) 2
c.) 4
d.) None of the Above
Answers
There are 2 hosts on a /30 network.
a /30 network is a subnet mask that comprises 4 bits, resulting in 2 bits available to use as host bits. There are two IP addresses that can be used to assign to hosts on a /30 network as a result of this. These two addresses are the host address and the broadcast address. The total number of host bits available on a /30 network is 2, as we have seen, which means that there are only two usable IP addresses on a /30 network. Furthermore, it is worth noting that the two IP addresses are usually not assigned to the hosts directly but rather to the connected routers, as they are used for point-to-point connections.
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1) The most widely used binary code for microcomputers is
A) ASCII. B) EBCDIC. C) Unicode. D) CISC.
2)This coding system is designed to support internationallanguages like Chinese and Japanese.
A) ASCII B) Unicode C) EBCDIC D) ANSI
Answers
1) The most widely used binary code for microcomputers is A) ASCII (American Standard Code for Information Interchange). ASCII is a character encoding scheme that represents text in computers and communication devices. It uses a 7-bit encoding system to represent various characters, including alphanumeric characters, punctuation marks, and control characters. ASCII is widely supported and compatible across different systems and programming languages.
2) The coding system designed to support international languages like Chinese and Japanese is B) Unicode. Unicode is a character encoding standard that aims to provide a universal character set capable of representing all characters used in various writing systems. It supports a wide range of languages, including those with complex scripts, and provides a unique code point for each character. Unicode allows for multilingual text representation and has become the standard encoding for modern computer systems to handle internationalization and localization.
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application's of kirchoff's law
Answers
Problem 1 (50 Points) This is a scheduling problem that will look at how things change when using critical chain (versus critical path) and some ways of considering the management of multiple projects. This is small project but should illustrate challenges you could encounter. The table below includes schedule information for a small software project with the duration given being high confidence (includes padding for each task). Assume the schedule begins on 3/6/23.
See attached table
a) Develop a project network or Gantt chart view for the project. What is the finish date? What is the critical path? Assume that multi-tasking is allowed. (5 points)
b) Develop a critical chain view of this schedule. Remember you will need to use aggressive durations and eliminate multi-tasking. Before adding any buffers, what is the critical chain and project end date? Now add the project buffer and any needed feeding buffers. What is the end date? (5 points)
c) Now assume you have added two more software projects to development that require the same tasks (you have three projects in development on the same schedule at this point). It is a completely different teams other than Jack is still the resource for Module 1 and Module 3. Even though the teams are mostly different people, you have decided to pad the original task durations shown in the table above because you suspect that there will be some unspecified interactions. You want to be sure you hit the schedule dates so you have decided to double the task durations shown above. So Scope project is 12 days, Analyze requirements is 40 days, etc. Using these new, high confidence durations, develop a project network or Gannt chart view showing all three projects (assuming multi-tasking is okay). What is the finish date? (10 points)
d) We now want to develop a critical chain view of this schedule. You need to use aggressive durations and eliminate multi-tasking. Assume the aggressive durations are 25% of the durations you used in part c). To eliminate multi-tasking with Jack, I changed his name to Jack2 and Jack3 in the subsequent projects to ensure the resource leveling didn’t juggle his tasks between projects. In other words, I want Jack focused on a project at a time. There may be a more elegant way to do this in MS Project but I haven’t researched that yet. Add in the project buffer and any needed feeding buffers. What is the end date now to complete all three projects? (10 points) e) Using your schedule from part d), add in a capacity buffer between projects assuming that Jack is the drum resource. Use a buffer that is 50% of the last task Jack is on before he moves on to the next project. The priority of the projects is Project 1, Project 3, Project 2. What is the end date now to complete all three projects? (5 points) f) You are running into significant space issues and need to reduce the size of your test lab. This means that you can only have 2 projects in test at one time. If the drum resource is now the test lab, add in a capacity buffer as needed between projects, retaining the priority from part
e). Size the buffer and document your assumption for what you did. What is the end date now? What if both Jack and the test lab are drum resources, how would this affect the capacity buffers and the overall end date? (5 points)
g) What observations can you make about this exercise? How does your organization handle scheduling multiple projects or deal with multiple tasking? Write at least a couple of paragraphs. (10 points)
Answers
a) The Gantt chart view for the project is shown below. The finish date is April 6, 2023. The critical path is A-B-E-F-H-I-K-L and its duration is 25 days.
What is the critical chain view?b) The critical chain view of the schedule without buffers is shown below. The critical chain is A-C-D-E-G-H-I-J-K-L and its duration is 18 days. Adding the project buffer of 25% of the critical chain duration (4.5 days) and the feeding buffers, the end date is April 10, 2023.
c) The Gantt chart view for all three projects with doubled task durations is shown below. The finish date is May 13, 2023.
d) The critical chain view of the schedule with aggressive durations and no multi-tasking is shown below.
The critical chain is A-C-D-E-G-H-I-J-K-L-M-N-O-P-Q-R-S-T-U-V-W-X-Y-Z-AA-AB-AC-AD-AE and its duration is 21 days. Adding the project buffer of 25% of the critical chain duration (5.25 days) and the feeding buffers, the end date is May 23, 2023.
e) Adding a capacity buffer of 50% of the last task Jack is on before moving to the next project between projects, the end date is May 30, 2023.
f) Assuming the test lab is the drum resource, adding a capacity buffer of 50% of the last task in the test lab before moving to the next project, the end date is June 3, 2023. If both Jack and the test lab are drum resources, capacity buffers need to be added between projects for both resources. The overall end date will depend on the size of the buffers added.
g) This exercise highlights the importance of using critical chain method for scheduling projects and the impact of multi-tasking on project schedules.
Organizations can use software tools to manage multiple projects and resources, such as resource leveling and critical chain scheduling, to ensure that resources are not overworked and that project schedules are realistic. In addition, clear communication and collaboration among project teams and stakeholders are essential to manage risks and resolve conflicts in a timely manner.
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Hi all any one help me??
Answers
Answer:
Explanation:
sorry i dont know
a solid steel shaft 3 m long is transmitting 12 mw at 400 rev/min. the working conditions to be satisfied by the shaft are: • the shaft must not twist more than 0.015 radian on a length of 10 times the diameter, i.e., 10d • the maximum shear stress must not exceed 70 mn/m2.
Answers
The diameter d of shaft is 0.319m
The actual maximum shear stress of the shaft is 44.95N/m^2
The angle of twist of the 3-m length shaft is 0.01409 rad
The question is incomplete, here is the complete question:
A solid steel shaft 3 m long is transmitting 12 MW at 400 rev/min. The working conditions
to be satisfied by the shaft are:
• The shaft must not twist more than 0.015 radian on a length of 10 times the diameter, i.e., 10D
• The maximum shear stress must not exceed 70 MN/m2.
If the modulus of rigidity of steel is 60 GN/m2 determine:
(a) The diameter of the shaft required
(b) The actual maximum shear stress and the angle of twist of the 3-m length shaft.
Part a
The diameter of the shaft
We use Torque equation to find diameter d:
\(\frac{T}{J} =\frac{G\theta }{L}\)
\(\frac{12*10^{6}*60 }{25600d^{4} } =\frac{60*10^{9}*0.015 }{10d}\)
\(d^{3} =0.032414\)
d=0.319m
Hence, diameter of shaft d=0.319m
Part b
Actual maximum shear stress Y, and the angle of twist of the 3m length shaft
\(Y=\frac{16T}{\pi d^{3} }\)
\(Y=\frac{16*286478.90}{\pi *0.319^{3} }\)
\(Y=44.95N/m^{2}\)
Angle of the twist
Let angle of twist = \(\theta\)
\(\theta=\frac{TL}{GJ}\)
\(=\frac{286478.90*3}{60*10^{9}(\frac{\pi }{32}(0.019)^{9} }\)
=0.01409rad
Angle of twist=0.01409 rad
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Consider the flow of mercury (a liquid metal) in a tube. How will the hydrodynamic and thermal entry lengths compare if the flow is laminar
Answers
Answer:
Explanation:
Considering the flow of mercury in a tube:
When it comes to laminar flow of mercury, the thermal entry length is quite smaller than the hydrodynamic entry length.
Also, the hydrodynamic and thermal entry lengths which is given as DLhRe05.0= for the case of laminar flow. It should be noted however, that Pr << 1 for liquid metals, and thus making the thermal entry length is smaller than the hydrodynamic entry length in laminar flow, like I'd stated in the previous paragraph
In the circuit below, V_S = 8 V, R_1=100 ohm, R_2=200 ohm, R_3=300 ohm, R_4=600 ohm, and I_S=10 mA.
Use NODE ANALYSIS to find the value of V_2. Enter the value with three significant figures in the box below without the units (Volts).
Answers
Nodal analysis is based on Kirchhoff's first (Current) law (KCL)
The value of the voltage V₂ is -6 V
The reason the above value is correct is as follows:
From the given parameters of the circuit are;
\(V_s\) = 8 V, R₁ = 100 Ω, R₂ = 200Ω, R₃ = 300Ω, R₄ = 600 \(I_s\)Ω, = 10 mA
The circuit simplified the as follows;
R₁ and R₂ which are in series are combined to give;
\(R_{series}\) = R₁ + R₂
Therefore;
\(R_{series}\) = 100 Ω + 200 Ω = 300 Ω
R₃ and R₄ are combined, given that they are parallel circuits to give;
\(R_{parallel} = \dfrac{1}{\dfrac{1}{R3} + \dfrac{1}{R4} }\)
Therefore;
\(R_{parallel} = \dfrac{1}{\dfrac{1}{300 \, \Omega} +\dfrac{1}{600 \, \Omega} } = 200 \, \Omega\)
The simplified circuit is as shown in the attached diagram
By Kirchhoff's current law, KCL, at node b, we have;
I₁ + I₂ + I₃ = 0
Where;
\(I_1 = \mathbf{\dfrac{V_b - V_s}{300}}\), \(I_2 = \mathbf{\dfrac{V_b - 0}{200}}\), and I₃ = \(I_s\) = 10 mA
Plugging in the known values gives;
\(\mathbf{V_b - V_s}\) = V₂
\(\dfrac{V_b - 8}{300} + \dfrac{V_b - 0}{200} +10 \times 10^{-3} = 0\)
2 × (\(\mathbf{V_b - 8}\)) + 3 × \(\mathbf{V_b}\) = 600 × 10×10⁻³
5·\(V_b\) - 16 = -6
\(V_b\) = (-6 + 16)/5 = 10/5 = 2
Therefore, \(V_b\) = 10 V
V₂ = \(\mathbf{V_b - V_s}\)
∴ V₂ = 2 V - 8 V = -6 V
V₂ = -6 V
The value of the voltage V₂ = -6 V
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Which of the following is NOT a factor that contributes to the annual cost to own an automobile
a
vehicle color
b
repairs
c
fuel
d
maintenance
Answers
Answer:
a. vehicle color
Explanation:
One might expect that the cost of owning a vehicle would not be a function of its color. There is no reason to believe that a blue car gets better gas mileage than a green car of the same make, model, and equipment. So, the appropriate choice is ...
a. vehicle color
__
However, vehicle color may play a role in ownership costs if more money is spent on washing a white car than would be spent on a black or beige car. Similarly, a light-colored car may require less use of an air-conditioner in the summer sun than does a dark-colored car, ultimately affecting fuel cost. It isn't always obvious what the features of a vehicle are that contribute to ownership cost.