The voltage needed is 55 Volt.
What is electric power?
The rate at which energy is converted into an electrical circuit or used to produce work is known as electric power. It is a way to quantify how much energy is consumed over a certain period of time.
Given that: the microwaves operate using 1100 W of electrical power and the current in the outlet is 20 A,
Let, voltage needed is V.
We know that: electric power = voltage*current
Hence, Electric voltage = power / currect
= 1100 W/20 A
= 55 Volt.
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I NEED SOMEONE TO HELP ME WITH THIS ONE PLEASE!!
-Car A that has a mass of 2000 kg is moving at 8 m·s-1 to the west. It collides with Car B that has a mass of
4000 kg moving at 1 m-s-1 to the east. Calculate the velocity of car B, if car A moves with a velocity of 4 m.s-1
After the collision.
Explanation:
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The horizontal wire shown on the right in the figure above will break when the tension in it exceeds the value Tmax. What is the maximum mass M that the hanging object can have without the horizontal wire breaking? (Assume the wire on the left does not break prior to the horizontal wire breaking)
A component that runs parallel to the string and one that does. The following will make up the weight component moving in the string's direction: mg cos(θ) The weight's component that is parallel to the string is. — mg sin(θ)
What tension in it exceeds the value Tmax?A numerical value known as the coefficient of friction (fr) is created by dividing the resistive force of friction (Fr), which pushes the objects together, by the normal or perpendicular force (N), which pushes them apart. It is represented by the formula below: fr = Fr/N.
The direction of the object's pull and the length of the provided rope both contribute to tension. It's also crucial to remember that Newton is the SI unit for tension.
Therefore, The horizontal tension in the L wire can be found by Mgcos (theta) so Tmax = Mgcos (theta Tmax / (g cos(theta)) = M.
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what is the wavelength of light that must be absorbed to accomplish this process?
The wavelength of light must be absorbed to accomplish photosynthesis process is blue light.
Photosynthesis is a process in which green plants, blue-green algae capture light energy and convert into chemical energy. Photosynthesis depends on absorption of light by pigments in the leaves.
Wavelength is distance between successive crests of a wave especially in electromagnetic waves. Most important is the chlorophyll a, which is the universal pigment but there are several accessory pigments which helps in the process of photosynthesis.
Plant pigment absorb light in the wavelength range of 700 nanometer to 400 nanometer. It is said to be as photo-synthetically active radiation. Violet and Blue have the shortest wavelength and most energy while red has the longest wavelength and carries the least amount of energy.
One photon with just right amount of energy bump an electron between orbitals and can excite a pigment. This is why different pigments absorb different wavelength of light.
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The complete question is,
What is the wavelength of light that must be absorbed to accomplish this photosynthesis process?
Answer:
Instead, photosynthetic organisms contain light-absorbing molecules called pigments that absorb only specific wavelengths of visible light, while reflecting others. The set of wavelengths absorbed by a pigment is its absorption spectrum.
Consolidation for a 2-ft thick layer (drained at top and bottom) takes 6 months. how long will it take for the same layer to reach 40onsolidation if it is drained only at the bottom.
It is not possible to determine the time required for consolidation to reach 40% with only partial drainage information.
The time required for consolidation to reach 40% cannot be determined with only partial drainage information. The consolidation process depends on various factors such as soil type, initial void ratio, and drainage conditions. Partial drainage at the bottom only will result in a longer consolidation time compared to full drainage at the top and bottom. The degree of consolidation achieved will depend on the time factor, hydraulic gradient, and soil parameters. Therefore, without knowing these parameters, it is not possible to calculate the time required for consolidation to reach 40%. A comprehensive soil analysis and laboratory testing are necessary to determine the appropriate time factor for consolidation of a specific soil type under different drainage conditions.
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List four units commonly used to measure length
Answer:
meter,kilometer,centimeter and millimeter
Explanation:
roller coaster car drops a maximum vertical distance of 35.4 m . part a determine the maximum speed of the car at the bottom of that drop. ignore work done by friction. express your answer with the appropriate units. activate to select the appropriates template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value type vf
The maximum speed of the roller coaster at that drop is 26.34 m/s.
What is the maximum speed of the roller coaster?The maximum speed of the roller coaster at that drop is calculated by applying the principle of conservation of energy as follows;
Maximum potential energy of the roller coaster at top = Maximum kinetic energy of the coaster at the bottom
mgh = ¹/₂mv²
2gh = v²
v = √ ( 2gh)
where;
h is the height of fall of the roller coasterg is acceleration due to gravityv is the maximum speed at the bottomv = √ ( 2 x 9.8 x 35.4)
v = 26.34 m/s
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according to our present theory of solar system formation, why were objects able to grow larger in the outer solar system than in the inner solar system?
Objects were able to grow larger in the outer solar system due to the presence of ices that allowed for the formation of solid planetesimals.
The current theory of solar system formation, known as the nebular hypothesis, suggests that the solar system formed from a rotating cloud of gas and dust that collapsed under gravity and began to spin faster, flattening into a disk shape. In the inner solar system, only metals and rocky materials could condense and form solid objects due to high temperatures. In contrast, in the colder outer solar system, volatile ices could also condense and form solid objects, allowing outer planetesimals to grow larger and accumulate more mass, eventually forming the giant planets.
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a prize wheel is spinning in a vertical circle at 2.0 rad/s when an acceleration is applied to the wheel to increase the velocity to 6.0 rad/s. how long did this acceleration last if the displacement during this time was 5.0 rad.
The acceleration of wheel will last for 1.25 sec.
What is angular acceleration?Angular acceleration refers to as change of angular velocity per unit of time. It is usually expressed in radians/sec². The direction of the acceleration vector is perpendicular to the plane in which the rotation occurs. As the angular velocity(ω) increases clockwise, the angular acceleration rate moves away from the observer. If the angular velocity increase is counterclockwise, the angular acceleration vector points in the direction of the viewer. In SI units, angular acceleration is measured in radians per second (rad/s²) and is commonly expressed as alpha (α).
For the given case,
Using equation of motion:
ω₂² = ω₁² + 2αθ
6² = 2² + 2 × α × 5
36 = 4 + 10α
10α = 32
α = 3.2 m/s²
Acceleration:
α = (ω₂ - ω₁)/t
t = (ω₂ - ω₁)/α
t = (6 - 2)/3.2
t = 1.25 sec
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Also, I need the answer in like 5 mins. This is kinda hard for me can someone help me. It's about the solar system.
Answer:
North star, its close to our solar system but not in it. hope this helps
If the car's velocity were doubled, what would happen to the time the car
falls as compared to the time the ball falls?
The time it takes for the car to fall from a certain height would not be affected by the time it takes for the ball to fall, even if the car's velocity were doubled.
If the car's velocity were doubled, the time it takes for the car to fall would not be affected by the time it takes for the ball to fall. This is because the time taken for an object to fall from a certain height is determined by the acceleration due to gravity and the distance from the ground, but not by the object's initial velocity.
The acceleration due to gravity is constant, which means that the time taken for an object to fall a certain distance is also constant. This means that the time taken for the ball to fall and the car to fall from the same height would be the same, regardless of the car's velocity.
This can be explained by the equation of motion for a falling object:
d = 1/2gt²,
where d is the distance from the ground, g is the acceleration due to gravity, and t is the time taken to fall.
Since the acceleration due to gravity is constant, the time taken for the car and the ball to fall the same distance would be the same, regardless of their initial velocity.
Therefore, if the car's velocity were doubled, the time it takes for the car to fall would be the same as before, but it would be moving faster when it hits the ground.
In conclusion, the time it takes for the car to fall from a certain height would not be affected by the time it takes for the ball to fall, even if the car's velocity were doubled.
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if you try to look at a 6-volt signal with the "volts/div" dial set to 0.2, you don’t see anything. why not? should you turn the dial to 2 volts/div or to 0.02 volts/div to find the signal?
When the "volts/div" dial is set to 0.2 and you try to view a 6-volt signal, it is not visible because the signal exceeds the vertical display range. To see the signal, you should turn the dial to 2 volts/div.
When you try to look at a 6-volt signal with the "volts/div" dial set to 0.2, you don't see anything because the signal is too large to be displayed properly on the screen.
The "volts/div" setting determines the vertical scaling or sensitivity of the oscilloscope, indicating the number of volts represented by each vertical division on the display.
In this case, with the "volts/div" set to 0.2, each vertical division represents only 0.2 volts. Since the signal has an amplitude of 6 volts, it would require 30 divisions to display the full signal on the screen (6 volts / 0.2 volts/div = 30 divisions).
However, most oscilloscopes have a limited number of vertical divisions available on the screen, typically around 8 to 10 divisions.
Therefore, with the "volts/div" set to 0.2, the signal exceeds the vertical display range of the oscilloscope, and you won't see anything.
To properly view the 6-volt signal, you should turn the "volts/div" dial to a larger value. If you increase it to 2 volts/div, each vertical division would represent 2 volts.
This setting would allow you to see the full 6-volt signal within the available vertical display range (6 volts / 2 volts/div = 3 divisions).
On the other hand, setting the "volts/div" dial to 0.02 volts/div would make the vertical scaling too small.
It would make the signal appear compressed, with a reduced amplitude relative to the screen size, and potentially make it harder to observe and interpret the details of the signal accurately.
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A compressional wave looks most like a:
line of hills and valleys.
a straight line.
coiled spring.
None of the choices are correct.
Answer:
non of the choice are correct
Explanation:
because waves look like waves only
Of the three sciences, physics, chemistry, and biology, the most complex is
A. physics because it involves many mathematical equations.
B. chemistry because there are so many possible combinations of atoms.
C. biology because it is based upon both the laws of chemistry and physics.
D. All three of these sciences are equally complex.
Answer:
I would probably say C to be completely honest
Explanation:
If you agree make sure to give me a like
Cell phones use electromagnetic radiation with energy of about 1.08J/mol photons. Calculate the wavelength and frequency that can be used to describe light with this energy.
We know that the energy of electromagnetic radiation is given by:
\(E=hf\)where E is the energy, h is Planck's constant and f is the frequency. Before we can use this formula we need to convert the amount of energy given to J so let's do that:
\(1.08\text{ }\frac{J}{mol}\cdot\frac{1\text{ mol}}{6.022\times10^{23}}=1.793\times10^{-24}J\)Now that we have the energy of the radiation, we plug it on the energy equation and solve for the frequency:
\(\begin{gathered} 1.793\times10^{-24}=6.63^\times10^{-34}f \\ f=\frac{1.793\times10^{-24}}{6.63\times10^{-34}} \\ f=2.704\times10^9 \end{gathered}\)Therefore, the frequency of the cell phone electromagnetic radiation is:
\(2.704\times10^9\text{ Hz}\)Now that we know the frequency we just need to remember that the frequency and wavelength of electromagnetic radiation are related by:
\(\lambda=\frac{c}{f}\)Then we have:
\(\begin{gathered} \lambda=\frac{3\times10^8}{2.704\times10^9} \\ \lambda=0.111 \end{gathered}\)Therefore, the wavelength is 0.111 m
6. The mass and radius of Mars are approximately 6.39×10^23 kg and 3.3895×10^6 m, respectively. Using the equation find the gravitational field strength of Mars.
Mars has a gravitational field that is roughly 3.71 m/s² strong.
What is the strength of the gravitational field?Newtons per kilogramme (N/kg) are used to measure the gravitational field strength (g). At or near the surface, the gravitational field strength of the Earth is 10 N/kg. This implies that an item will experience 10 N of force for every kilogramme of mass.
To get the gravitational field strength, use the following equation:
g = G*M/r²
where:
g = gravitational field strength
G = gravitational constant = 6.6743 × 10⁻¹¹ N(m/kg)²
M = mass of Mars
r = radius of Mars
Plugging in the values:
g = (6.6743 × 10⁻¹¹ N(m/kg)² * 6.39×10²³ kg) / (3.3895×10⁶ m)²
g = 3.71 m/s²
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gabi has plans with her friends to go to a concert on her birthday in 4 days. she is so excited that she wants to know how many seconds she has left to wait. can you help her determine this?
Answer:
Explanation:
we know there is 24hr in a day so 4 day means 24x4 hrs which is 96hrs
now 1 hr have 60 min and 1 min is 60 sec. so, 1 hr have (60sec x 60) since 60 second is 1 min and 1 hr is 60 times that.
1hr = 60x60 =3600sec.
we know 4 day have 96hrs, so if we multiply 3600 with 96 we get it in seconds.
3600x96 = 345600 seconds.
Gabi has plans with her friends to go to a concert on her birthday in 4 days. Gabi has 345,600 seconds left to wait for her birthday concert.
Gabi determines how many seconds she has left to wait for her birthday concert.
There are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute. So, to calculate the total number of seconds in 4 days:
Total Seconds = 4 days × 24 hours/day × 60 minutes/hour × 60 seconds/minute
Total Seconds = 4 × 24 × 60 × 60
Total Seconds = 345,600 seconds
Therefore, Gabi has 345,600 seconds left to wait for her birthday concert.
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Cane Company manufactures two products called Alpha and Beta that sell for $240 and $162, respectively. Each product uses only one type of raw material that costs $5 per pound. The company has the capacity to annually produce 131,000 units of each product. Its average cost per unit for each product at this level of activity are given below:
Alpha Beta
Direct materials $ 35 $ 15
Direct labor 48 23
Variable manufacturing overhead 27 25
Traceable fixed manufacturing overhead 35 38
Variable selling expenses 32 28
Common fixed expenses 35 30
Total cost per unit $ 212 $ 159
The company considers its traceable fixed manufacturing overhead to be avoidable, whereas its common fixed expenses are unavoidable and have been allocated to products based on sales dollars.
8. Assume that Cane normally produces and sells 80,000 Betas and 100,000 Alphas per year. If Cane discontinues the Beta product line, its sales representatives could increase sales of Alpha by 13,000 units. What is the financial advantage (disadvantage) of discontinuing the Beta product line?
9. Assume that Cane expects to produce and sell 100,000 Alphas during the current year. A supplier has offered to manufacture and deliver 100,000 Alphas to Cane for a price of $160 per unit. What is the financial advantage (disadvantage) of buying 100,000 units from the supplier instead of making those units?
10. Assume that Cane expects to produce and sell 75,000 Alphas during the current year. A supplier has offered to manufacture and deliver 75,000 Alphas to Cane for a price of $160 per unit. What is the financial advantage (disadvantage) of buying 75,000 units from the supplier instead of making those units?
The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000. The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.
To calculate the financial advantage or disadvantage of discontinuing the Beta product line, we need to compare the costs and revenues associated with the current situation and the proposed scenario.
Currently, the company produces and sells 80,000 Betas and 100,000 Alphas. If the Beta product line is discontinued, the sales representatives can increase Alpha sales by 13,000 units.
In the current situation:
Revenue from Beta sales = 80,000 units × $162 = $12,960,000
Revenue from Alpha sales = 100,000 units × $240 = $24,000,000
Total revenue = $12,960,000 + $24,000,000 = $36,960,000
In the proposed scenario:
Increased Alpha sales = 113,000 units × $240 = $27,120,000
Therefore, the financial advantage or disadvantage can be calculated as:
Financial Advantage = Revenue in proposed scenario - Revenue in current situation
Financial Advantage = $27,120,000 - $36,960,000 = -$9,840,000
The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000.
To determine the financial advantage or disadvantage of buying 100,000 units from the supplier instead of making them, we need to compare the costs of production with the purchase cost from the supplier.
Cost of producing 100,000 Alphas:
Direct materials cost = 100,000 units × $35 = $3,500,000
Direct labor cost = 100,000 units × $48 = $4,800,000
Variable manufacturing overhead = 100,000 units × $27 = $2,700,000
Traceable fixed manufacturing overhead = 100,000 units × $35 = $3,500,000
Variable selling expenses = 100,000 units × $32 = $3,200,000
Common fixed expenses = 100,000 units × $30 = $3,000,000
Total cost of producing 100,000 units = $3,500,000 + $4,800,000 + $2,700,000 + $3,500,000 + $3,200,000 + $3,000,000 = $20,700,000
Cost of buying 100,000 units from the supplier = 100,000 units × $160 = $16,000,000
Therefore, the financial advantage or disadvantage can be calculated as:
Financial Advantage = Cost of producing - Cost of buying
Financial Advantage = $20,700,000 - $16,000,000 = $4,700,000
The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.
Similarly, to determine the financial advantage or disadvantage of buying 75,000 units from the supplier instead of making them, we follow the same calculations as in question 9, but with the quantities adjusted accordingly.
Cost of producing 75,000 Alphas:
Direct materials cost = 75,000 units × $35 = $2,625,000
Direct labor cost = 75,000 units × $48 = $3,600,000
Variable manufacturing overhead = 75,000 units × $27 = $2,025,000
Traceable fixed manufacturing overhead = 75,000 units × $35 = $2,625,000
Variable selling expenses = 75,000 units × $32 = $2,400,000
Common fixed expenses = 75,000 units × $30 = $2,250,000
Total cost of producing 75,000 units = $2,625,000 + $3,600,000 + $2,025,000 + $2,625,000 + $2,400,000 + $2,250,000 = $15,525,000
Cost of buying 75,000 units from the supplier = 75,000 units × $160 = $12,000,000
Therefore, the financial advantage or disadvantage can be calculated as:
Financial Advantage = Cost of producing - Cost of buying
Financial Advantage = $15,525,000 - $12,000,000 = $3,525,000
The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.
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which layer in a zigbee device is responsible for detecting the presence of an rf signal in the currently selected channel?
In a Zigbee device, the layer responsible for detecting the presence of an RF (Radio Frequency) signal in the currently selected channel is the Physical Layer (PHY).
The PHY layer in Zigbee is responsible for managing the transmission and reception of RF signals. It handles functions such as channel selection, modulation, demodulation, and signal detection. When a Zigbee device is operating in a specific channel, the PHY layer continuously monitors that channel for incoming RF signals. It performs energy detection, which involves measuring the power level of the received signal. By analyzing the received signal strength, the PHY layer can detect the presence of an RF signal in the selected channel.
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447/10.7.1: Consider a disk with mass m, radius R, and moment of inertia I = 1/² mR²2. disk has a string The disk string wrapped around it with one end attached to a fixed support and allowed to fal
The question involves a disk with mass, radius, and moment of inertia, along with a string wrapped around it. One end of the string is attached to a fixed support, and the disk is allowed to fall.
In this scenario, the disk is initially held in a vertical position with the string wrapped around it. When the disk is released, it starts to fall due to the force of gravity. The key factors to consider in this situation are the mass and radius of the disk, as they determine the gravitational force acting on it, and the moment of inertia, which affects the rotational motion of the disk. The string plays a crucial role in transferring the force from the falling disk to the fixed support.
Unique keywords in the explanation are "fall," "moment of inertia," "gravitational force," and "rotational motion." These terms highlight the key elements of the question, including the motion of the falling disk, the influence of the moment of inertia on its rotation, the gravitational force as a driving factor, and the involvement of the string in transmitting the force to the fixed support.
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Calculate the probability of an antiproton, of energy E, crossing a potential energy barrier Vo(x), where E < Vo(x). The probability of an electron of the same energy E passing through the above potential energy barrier is equal to 0.2.
The probability of an antiproton, of energy E, crossing a potential energy barrier Vo(x), where E < Vo(x). The probability of an electron of the same energy E passing through the above potential energy barrier is equal to 0.2.\(exp\ [-\sqrt{[\frac{h\ ln (0.2)^2}{32 m (Vo(x)-E)}} ]]\)
The probability of an antiproton crossing an electric potential energy barrier (Vo(x)), where E < Vo(x) is given by:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
Where, h is the Planck constant and m is the mass of the particle. To calculate the probability of an electron passing through the same energy barrier, we are given that P(E) = 0.2. The probability of an antiproton crossing the same energy barrier is:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
The energy of the antiproton is given as E. Therefore, substituting this value in the above expression, we have:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
As per the given condition, the probability of an electron passing through the same energy barrier is 0.2. Therefore, substituting this value in the above expression, we have:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
Taking the natural logarithm on both sides, we have:
\(ln0.2 = -2\sqrt{[2m\frac{(Vo(x)-E)}{h}]}\)
Taking the square of both sides, we have:
\(4\ ln 0.2 = 8 [2m\frac{(Vo(x)-E)}{h}]\)
Simplifying, we get:
\(Vo(x) - E = (\frac{h}{8m}) \frac{[ln 0.2]^2}{2}\)
\(Vo(x) = E + (\frac{h}{8m}) \frac{[ln 0.2]^2}{2}\)
Therefore, the probability of an antiproton crossing the electric potential energy barrier \((Vo(x))\), where is given by:
\(P(E) = exp(-2\sqrt{[2m\frac{(Vo(x)-E)}{h}]})\)
Substituting the value of Vo(x), we get:
\(P(E) = exp(-2\sqrt{[2m\frac{(h)}{8m}\frac{[ln 0.2]^2}{2h}{(Vo(x)-E)}]})\)
Simplifying, we get:
\(P(E) = exp[-\sqrt{[\frac{(h ln 0.2)^2}{32m}(Vo(x)-E)]}]\)
Therefore, the required probability is \(exp[-\sqrt{[\frac{(h ln 0.2)^2}{32m}(Vo(x)-E)]}]\).
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science (Friction/Forces)
which option is correct?
Answer:
A
Explanation:
At constant speed, acceleration=0
From the formula, Fnet=ma (Resultant force= mass x acceleration), sub a=0
Fnet=0
Since the resultant force=0, the pushing force is equal to the frictional force
what is the only form of heat transfer that can operate in a vacuum?
The only form of heat transfer that can operate in a vacuum is radiation.
Unlike convection and conduction, which require a medium to transfer heat, radiation is the transfer of heat through electromagnetic waves. This means that even in the absence of air or any other medium, heat can still be transferred through radiation.
Instead, heat is transferred through electromagnetic waves, primarily in the form of infrared radiation. In a vacuum, where there is no matter to conduct or convect heat, radiation remains the sole method for heat transfer, enabling heat to travel across vast distances in space.
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II. Practice calculations:
1. A current of 2.24A flows in a straight wire oriented along the x-axis so the current flows to the left. What is the
magnitude and direction of the magnetic field created by the wire at a point that is 0.022m above the wire? What is the
magnitude of the field at a point twice as far above the wire as point X? 10 times as far below the wire?
Hi there!
For a straight wire, we can use Ampère's Law to find its magnetic field at various distances from the wire.
Using the equation:
\(\oint B\cdot dl = B \cdot l = \mu_0 i\)
B = Magnetic field strength (T)
l = length of path of integration (m)
μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)
i = Enclosed current (2.24 A)
This is a dot-product, so the cosine of the angle between the magnetic field and the path of integration is considered. However, since we are always tangential to the magnetic field, cos(0) = 1. We can simplify to B * l.
The length of the path of integration is equivalent to the circumference of a circle produced with a radius 'r' as a straight, long wire creates circular magnetic fields around the wire.
Therefore:
\(C = 2\pi r\\\\B \cdot 2\pi r = \mu_0 i\)
Solve for 'B'.
\(B = \frac{\mu_0i}{2\pi r}\)
1.
Plug in the given values and solve for the strength of the magnetic field at r = 0.022m.
\(B = \frac{(4\pi \times 10^{-7})(2.24)}{2\pi (0.022)} = \boxed{20.364 \mu T}\)
Using magnetic hand rules, a left-flowing (-x axis) current will result in a magnetic field of this strength INTO THE PAGE (or +y-axis if we assign the +/- z-axis to be up/down respectively) above the wire.
2.
Since B ∝ 1/R, if we double 'R', B will be halved.
Therefore:
\(B_{2R} = \frac{B_R}{2} = \frac{20.364 \mu T}{2} = \boxed{10.182 \mu T}\)
3.
The same logic applies. If we increase 'R' by 10x, B will decrease by 10x.
\(B_{10R} = \frac{B_R}{10} = \frac{20.364\mu T}{10} = \boxed{2.0364 \mu T}\)
However, since this point is BELOW the wire, the direction of the magnetic field differs. Using hand rules, the field would point OUT OF THE PAGE, or to the -y-axis.
SCIENCE
Why is the nervous system in the human body a system?
A. It is made of tissues that can conduct electricity, a required function in a system.
B. Like all systems, the nervous system is contained within a living organism.
C. It is made of several components that act interdependently to perform a function as a whole.
D. The nervous system acts together with other systems to control a larger organism
Answer:
A. It is made of tissues that can conduct electricity, a required function in a system.
Explanation:
The nervous system helps all the parts of the body to communicate with each other. It also reacts to changes both outside and inside the body. The nervous system uses both electrical and chemical means to send and receive messages.
Answer:
D
Explanation:
it is D because a system needs to manage a large organism like us to allow us to live, therefore, needs to work with other systems to keep us alive
Como puedo saber la carga de una partícula en un campo magnético
The charge of a particle in a magnetic field can be determined by measuring the force, velocity, and strength of the magnetic field using the Lorentz force equation. There are various methods to measure the charge, such as using a particle accelerator or mass spectrometer.
In a magnetic field, charged particles experience a force that can be used to determine their charge. This force, known as the Lorentz force, is given by the equation F = q(v x B), where F is the force, q is the charge of the particle, v is the velocity of the particle, and B is the strength of the magnetic field.
To determine the charge of a particle in a magnetic field, you can measure the velocity of the particle and the strength of the magnetic field, and then measure the force experienced by the particle. By rearranging the equation F = q(v x B), you can solve for the charge q.
It is important to note that the Lorentz force only applies to charged particles that are in motion. If the particle is stationary, it will not experience any force in a magnetic field.
In practice, there are many ways to measure the charge of a particle in a magnetic field, such as using a particle accelerator or a mass spectrometer. These techniques involve manipulating the motion of the particle in a controlled way and measuring the resulting forces and velocities to determine its charge.
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Complete question:
How can I know the charge of a particle in a magnetic field?
Person 1 speaks to person 2. Explain how the sound is created by person 1 and how it is possible for person 2 to hear the conversation.
We've put together a step-by-step explanation of how people hear—from the moment sound waves arrive to the outer ear, then travel through the middle and inner ear and transform into meaningful signals sent on to the brain. Our brain uses these signals to organize and communicate with the external world.
Which example best illustrates that light behaves like particles? Light bends as it strikes a window. Light bounces off a white cement sidewalk. Light travels in space at a speed of about 3. 0 x 108 m/s. Light increases in speed as it moves through matter.
The statement that best illustrates that the light behaves like particles is "light bounces off a white cement sidewalk".
What is Light?Light is electromagnetic radiation which can be seen by Bare eyes. It is the part of the electromagnetic spectrum.
Light is a particulate matter the reflection of light by striking to a surface is the best example to understand its nature.
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A body is under the action of two forces 7N and 10N. Find the resultant of the two forces if: 1.) The forces are parallel and act in the same direction 1.) The forces are inclined at an angle of 60° to each other. .2) The forces act at 90° to each other.
Answer:
The answer is below
Explanation:
1) The resultant force of two forces acting in the same direction is equal to the sum of the two magnitudes. Therefore:
Resultant force = 10N + 7N = 17 N
2) The resultant force(R) between two forces A and B at an angle θ is given by:
\(R=\sqrt{A^2+B^2+2ABcos\theta} \\\\R=\sqrt{7^2+10^2+2(7)(10)cos(60^o)} =14.8^o\\\\\)
3) The resultant force (R) between perpendicular forces (90°) A and B is given by:
\(R=\sqrt{A^2+B^2}\\ \\R=\sqrt{7^2+10^2}=12.2\ N\)
How can gas density be used to explain why hydrogen rises in air and carbon dioxide sinks?
Answer:
Explanation: The density of gas differentiates all the varieties of gas present in the atmosphere.
HYDROGEN- it is a lighter gas having a lesser density.
For example, a hydrogen balloon displaces the air around it thus making it rise.
CARBON DIOXIDE: It is a denser gas as it makes the balloon heavier than the air pressure around it thus making it sink.
I hope the explanation was helpful. :)
2) how much work does the moon do in stopping the asteroid if neither the moon nor the asteroid heats up in the process? (express your answer to three significant figures.)
The moon does approximately -2.66 x 10⁹ J of work in stopping the asteroid.
To calculate the work done by the moon in stopping the asteroid, we need to determine the initial kinetic energy (KE_initial) of the asteroid and subtract it from zero, as the final kinetic energy (KE_final) is zero when the asteroid comes to a stop.
The initial kinetic energy (KE_initial) can be calculated using the equation:
KE = (1/2)mv²
where m is the mass of the asteroid (100 kg) and v is its velocity (200 m/s).
KE_initial = (1/2)(100 kg)(200 m/s)² = 2 x 10⁶ J
Since the moon does an equal amount of work but in the opposite direction to stop the asteroid, the work done by the moon is equal to the negative value of the initial kinetic energy.
Therefore, the work done is -2.66 x 10⁹ J. The negative sign indicates that the moon does work against the motion of the asteroid to bring it to a stop.
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the complete question is:
A small asteroid that has a mass of 100 kg is moving at 200 m/s when it is 1330 km above the Moon.
how much work does the moon do in stopping the asteroid if neither the moon nor the asteroid heats up in the process? (express your answer to three significant figures.)