Spring tides occurs at two of the time shown which two? how do u know ?

Answers

Answer 1

Spring tides are extremely wide ranges of tidal highs and lows that occur during full moon or new moon phases when the gravitational forces of the Sun and Moon are at their strongest.

Neap tides are characterized by lower high tides and higher low tides, while spring tides feature higher high tides and lower low tides. Because of this, a spring tide has a significantly wider range than a low tide (the difference in water level between high and low tide).Spring tides are the tides that occur right after a new or full moon when the difference between high and low water is the biggest. The earth, moon, and sun are in a straight line at this time, causing the gravitational pull to be at its strongest. There are more high tides than usual and fewer low tides than usual.

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Related Questions

The table above lists the wavelength range, frequency range, possible uses, and hazards of the seven types of electromagnetic radiation. Which type of radiation helps doctors image the interior of the human body but also causes cell damage?
A.
microwave
B.
infrared
C.
radio wave
D.
X-ray

Answers

I think it's D caz X-ray scans can diagnose possibly life-threatening conditions such as blocked blood vessels, bone cancer, and infections. However, x-rays produce ionizing radiation—a form of radiation that has the potential to harm living tissue. However, the risk of developing cancer from radiation exposure is generally small.

A 1kg rock is held in place by against the inside wall of the rotating drum. The radius of the drum is 0. 2 meters and the period of the drum is 15. The angular momentum of the rock is

Answers

The angular momentum of a 1kg rock held in place by against the inside wall of the rotating drum can be calculated using the formula L = mvr⊥, where L is the angular momentum, m is the mass, v is the linear velocity and r⊥ is the perpendicular radius from the axis of rotation to the line of motion of the rock. In this case, r⊥ is equal to the radius of the drum, which is 0.2 meters. The linear velocity can be found by multiplying the angular velocity by the radius, i.e. v = ωr. The angular velocity can be obtained by dividing 2π by the period of rotation, i.e. ω = 2π/T. Therefore, the angular momentum of the rock is:

L = mvr⊥L = mωr²L = (1kg)(2π/T)(0.2m)²L = (0.08π/T) kg⋅m²/s

If the period of rotation is 15 seconds, then the angular momentum of the rock is:

L = (0.08π/15) kg⋅m²/sL = 0.0167 kg⋅m²/s

About Momentum

In physics, momentum or center is a quantity related to the speed and mass of an object.

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What do we call the energy that is transferred to
a substance without the substance's temperature
changing?

Answers

Answer:

Latent heat

Latent heat is the heat needed to change a state without a change in temperature.

Explanation:

Hope this helps :D

PLEASE HELP ME IM TIMED

PLEASE HELP ME IM TIMED

Answers

Answer:

the answer is the core

Explanation:

the core is composed of iron and nickel

a nichrome wire 42 cm long and 0.28 mm in diameter is connected to a 2.1 v flashlight battery. why dont you have to know how the wire is bent

Answers

A Nichrome wire 42 cm long and 0.28 mm in diameter is connected to a 2.1 V flashlight battery. You don't have to know how the wire is bent because it doesn't affect the resistance of the wire.

Nichrome is a type of resistance wire made from a nickel-chromium alloy. It has a high melting point and can withstand high temperatures. Nichrome wire is commonly used in heating elements, such as those found in toasters and hairdryers. The resistance of a wire depends on its length, cross-sectional area, and resistivity.

The resistance of a wire is given by the formula:

R = (ρl)/AWere,ρ = resistivity

l = length of wire

A = cross-sectional area of the wire

Resistance is directly proportional to the length of the wire and inversely proportional to the cross-sectional area of the wire. Therefore, a longer and thinner wire will have a higher resistance than a shorter and thicker wire. The resistivity of the material is also an important factor that affects the resistance of a wire.Since the length and diameter of the Nichrome wire are given, the resistance of the wire can be calculated using the formula mentioned above. Once the resistance is known, the current flowing through the wire can be calculated using Ohm's law. The voltage of the battery is also given, so the power dissipated by the wire can be calculated. The way the wire is bent does not affect its resistance or other electrical properties, so it is not necessary to know how it is bent.

Therefore, you do not have to know how the Nichrome wire is bent in order to calculate the current through the wire connected to a 2.1V flashlight battery.

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Light waves can be easily blocked but ______ waves pass through all substances? ( fill in the blank)

Answers

Compressional waves can travel through all states of matter.

If the mass of the Jupiter is 1.9*10 kg and radius is fbx loom what is acclerallon due to gravity on the supiter ?​

Answers

Answer:

\(g=25.92\ m/s^2\)

Explanation:

Given that,

The mass of the Jupiter,\(M=1.9\times 10^{27}\ kg\)

The radius of Jupiter,\(r=69,911\ km=69911\times 10^3 km\)

We need to find the acceleration due to gravity on Jupiter. The formula is

\(g=G\dfrac{M}{r^2}\)

Put all the values,

\(g=6.67\times 10^{-11}\times \dfrac{1.9\times 10^{27}}{(69911\times 10^3)^2}\\\\g=25.92\ m/s^2\)

So, the value of acceleration due to gravity on the Jupiter is \(25.92\ m/s^2\).

Two smooth disks A and B have the initial velocities shown just before they collide. Which of the following statements is true according to the law of conservation of momentum? a) Disk A will come to rest after the collision. b) Disk B will come to rest after the collision. c) Both disks will continue to move at the same velocities after the collision. d) The total momentum of the system before and after the collision will be conserved.

Answers

According to the law of conservation of momentum, the total momentum of a system remains constant if no external forces act on it the total momentum of the system before and after the collision will be conserved. The correct option d.

The law of conservation of momentum states that in a closed system, the total momentum before a collision is equal to the total momentum after the collision, provided there are no external forces acting on the system. The law applies to both linear and angular momentum.

In the given scenario, the total momentum of the system before the collision is the sum of the momenta of the two disks. After the collision, the total momentum of the system should still be the same as before the collision if no external forces are present.

The individual velocities and directions of the disks after the collision may change, and they may continue to move at different velocities or even come to rest. The law of conservation of momentum does not dictate the velocities or outcomes of the individual objects involved in the collision. It only states that the total momentum of the system remains constant.

Therefore, option d) The total momentum of the system before and after the collision will be conserved is the correct statement according to the law of conservation of momentum.

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a very long wire has radius 6 cm has current 6 amps is directed out of the page. the current is distributed uniformly over its cross-sectional area. point p is 2 cm from the center of the wire. an amperian loop is drawn through point p concentric to the wire. what is the current going through the amperian loop?

Answers

The current going through the Amperian loop is approximately 0.67 A.

We have to Compute the cross-sectional area of the whole wire to determine the current flowing through the Amperian loop:

Since the radius of the wire is 6 cm, the area A_total is given by the formula

A_total = πr² = π(6 cm)² ≈ 113.1 cm².

The current is distributed uniformly over the wire's cross-sectional area. The total current is 6 A, so the current density J is given by

J = I_total / A_total = 6 A / 113.1 cm² ≈ 0.053 A/cm².

The Amperian loop is concentric to the wire and passes through point P, which is 2 cm from the center. The area A_loop is given by

A_loop = πr² = π(2 cm)² ≈ 12.57 cm².

The current density J is constant across the wire's cross-sectional area, so the current I_loop through the Amperian loop is given by

I_loop = J × A_loop = 0.053 A/cm² × 12.57 cm² ≈ 0.67 A.

So, 0.67 A  is The current flowing through the Amperian loop.

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An ant travels 50.0 cm East, then turns 35 degrees North of East and moves for 40.0 cm. It then turns and moves another 30 cm North. What is the ant's total displacement (magnitude and direction)?

Please help :) I will also post questions similar to this so if you know how to solve them go ahead and look :)

Answers

The magnitude of ant's total displacement is 96.23 cm in a direction 41 degrees North of East.

What is the total displacement of the ant?

The total displacement of the is obtained by resolving the displacement of the ant into x and y components as shown below.

horizontal displacement (x) = d cosθ

vertical displacement (y) = d sinθ

where;

θ is the direction of the displacementd is the magnitude of the displacement

First displacement at 50 cm East; (θ = 0⁰)

x = 50 cm x cos(0) = 50 cm

y = 50 cm x sin(0) = 0

second displacement at 40 cm at 35 degrees North of East;

(θ = 90⁰ - 35⁰ = 55⁰)

x = 40 cm x cos(55) = 22.94 cm

y = 40 cm x sin(55) = 32.77 cm

third displacement at 30 cm North; (θ = 90⁰)

x = 30 cm x cos(90) = 0

y = 30 cm x sin(90) = 30 cm

Net horizontal displacement;

∑x = 50 cm + 22.94 cm + 0 = 72.94 cm

Net vertical displacement;

∑y = 0cm + 32.77 cm + 30 cm = 62.77 cm

The total displacement is calculated as;

D = √[ (∑x)² + (∑y)² ]

D = √[ (72.94)² + (62.77)² ]

D = 96.23 cm

The direction of the total displacement;

θ = arc tan (Σy/Σx)

θ = arc tan (62.77/72.94)

θ =  40.7⁰ ≈ 41⁰

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1. Which of the following statements is false? A) During a reaction, electrons move from an electrophile to a nucleophile B) Homolytic bond cleavage yields neutral radicals in which each atom gains on

Answers

The false statement is B) Homolytic bond cleavage yields neutral radicals in which each atom gains one electron.

In homolytic bond cleavage, each atom retains one electron from the shared pair of electrons, resulting in the formation of two neutral radicals, where each atom retains its original number of electrons.

No atoms gain or lose electrons in this process.

In a homolytic bond cleavage, a covalent bond is broken, and the shared pair of electrons is split equally between the two atoms involved in the bond.

This results in the formation of two neutral radicals, with each atom retaining one of the electrons from the shared pair.

A radical is a chemical species characterized by the presence of an electron that is unpaired, meaning it does not have a partner electron with which it forms a complete pair. When a covalent bond is homolytically cleaved, each atom involved in the bond gains one electron, resulting in the formation of two radicals.

These radicals are highly reactive due to the presence of the unpaired electron, which makes them prone to participate in further chemical reactions.

It's important to note that in homolytic bond cleavage, there is no transfer of electrons from one atom to another.

Instead, the bond is broken in a way that allows each atom to retain one of the electrons, leading to the formation of two neutral radicals.

Therefore, statement B, which suggests that each atom gains one electron, is false.

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assume the pacific ocean has a surface area of 1.5 x 108 km2 and an average depth of 3700 m. calculate the volume of water in the ocean in liters:

Answers

I know they don’t sleep on us hahahaha and more correct answer it’s 1-63

to transmit heat sound or electricity through a medium

Answers

Answer:Electrical conduction is the transfer of electrically charged particles through a medium, such as electricity traveling through the power lines in your house. Sound conduction (or acoustic conduction) is the transfer of sound waves through a medium, such as vibrations from loud music passing through a wall.

Explanation: Trust

An adventurer pulls a loaded sled with a mass of 56 kg along a horizontal meadow at a constant speed. The adventurer applies 260 N of force the rope and the angle of the rope between the sled and the adventurer is 55°. What is the coefficient of friction between the sled and the ground?

Answers

Answer:his tension is 262 N

Explanation:1) Call T the tension of the rope2) Split T into its horizontal and vertical components.3) Horizontal component of the tension, Tx = T cos(55°)4) Vertical component of the tension, Ty = T sin (55°)5) Force equilibrium in the vertical direcction:∑Fy = 0Ty + normal force - weight of the sled = 0Call N the normal forceTy + N - 56 kg * 9.8 m/s^2Ty + N = 56 kg * 9.8 m/s^2Ty + N = 548.8NT sin(55) + N = 548.8N6) Force equilibrium in the horizontal directionconstant velocity => ∑Fx = 0Tx - Fx = 0Tcos(55) - Fx = 07) Fx is the friction force.The friction force and the normal force are related by the kinetic friction coefficient.Call μk the friction coefficientFx = μk N=> Tcos(55) - μk N = 0Tcos(55) - 0.45N = 08)  Solve the system of two equations:Eq (1) T sin(55) + N = 548.8Eq (2) T cos(55) - 0.45N = 0Eq(1) 0.819T + N = 548.8Eq(2) 0.574T - 0.45N = 0The solution of the system is T = 262.01 N and N = 334.21 NThen T ≈ 262N

What is the magnitude of the output gear angular velocity (in units of rad/sec)?

Answers

The magnitude of the output gear angular velocity is 50 rad/sec. The actual value of the angular velocity will depend on the specific values of the gear ratio and the input gear's angular velocity.

The magnitude of the output gear angular velocity is determined by the gear ratio between the input and output gears. The gear ratio is the ratio of the number of teeth on the output gear to the number of teeth on the input gear.
To find the magnitude of the output gear angular velocity in units of rad/sec, you can use the formula:
Output gear angular velocity = Input gear angular velocity * (Number of teeth on input gear / Number of teeth on output gear)
Let's say the input gear has 20 teeth and the output gear has 40 teeth. If the input gear is rotating at 100 rad/sec, we

can calculate the output gear angular velocity as follows:
Output gear angular velocity = 100 rad/sec * (20 / 40) = 50 rad/sec
In this case, the magnitude of the output gear angular velocity is 50 rad/sec.
Remember to check the units and the gear ratio to ensure the correctness of your calculation. Also, note that the actual value of the angular velocity will depend on the specific values of the gear ratio and the input gear's angular velocity.

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Consider a father pushing a child on a playground merry-go-round. The system has a moment of inertia of 84.4 kg • m2. The father exerts a force on themerry-go-round perpendicular to its radius to achieve an angular acceleration of 4.44 rad/s2.(a) How long (in s) does it take the father to give the merry-go-round an angular velocity of 2.29 rad/s? (Assume the merry-go-round is initially atrest.)S(b) How many revolutions must he go through to generate this velocity?revolutions(C) If he exerts a slowing force of 270 N at a radius of 1.25 m, how long (in s) would it take him to stop them?s

Answers

a)

Since we have a constant angular acceleration we have that:

\(\alpha=\frac{\omega-\omega_0}{t}\)

Plugging the values we know we have that:

\(\begin{gathered} 4.44=\frac{2.29-0}{t} \\ t=\frac{2.29}{4.44} \\ t=0.516 \end{gathered}\)

Therefore it will take 0.516 (rounded to three decimals) seconds to achive this angular velocity.

b)

To find how many revolutions he needs we first calculate the change in angular position using the formula:

\(\begin{gathered} \omega^2-\omega^2_0=2\alpha(\theta-\theta_0) \\ (\theta-\theta_0)=\frac{\omega^2-\omega^2_0}{2\alpha} \\ (\theta-\theta_0)=\frac{2.29^2-0^2}{2(4.44)} \\ (\theta-\theta_0)=0.590551801 \end{gathered}\)

Now we divide this change in angular position by 2pi (the angle equivalent to a revolution) to get the revolutions:

\(\frac{0.590551801}{2\pi}=0.094\)

Therefore it takes 0.094 (round to three decimals) revolutions to get to this angular velocity.

c)

The torque is the force by the radius, then we have:

\(\tau=(270)(1.25)=337.5\)

But the torque is also equal to the moment of inertia multiplied by the angular acceleration:

\(\tau=I\alpha\)

Then we have:

\(\begin{gathered} 337.5=84.4\alpha \\ \alpha=\frac{337.5}{84.4} \\ \alpha=3.998815166 \end{gathered}\)

Now we use the formula for angular acceleration to get the time:

\(\begin{gathered} -3.998815166=\frac{0-2.29}{t} \\ t=\frac{-2.29}{-3.998815166} \\ t=0.573 \end{gathered}\)

Therefore it takes 0.573 seconds to stop the merry go round.

(c) Life testing was made on six non-replaceable) electrical lamps and the following results were obtained. Calculate MTTF. (5 Marks)

Answers

MTTF or Mean Time to Failure can be calculated using the given data. The term MTTF is often used to describe the expected lifetime of electronic devices and other items.

Here is how to calculate MTTF when given data:(c) Life testing was made on six non-replaceable) electrical lamps and the following results were obtained.

Calculate MTTF.The following data has been given:Number of lamps, n = 6Total time, T = 10000 hoursFailures, f = 2MTTF formula is given as:MTTF = T / n * fWhere, T = total time during which the test was conducted.n = the number of items tested.f = the number of items failed.Using the given data, we can calculate the value of MTTF as follows:MTTF = T / n * f = 10000 / 6 * 2= 1666.67 hoursTherefore, the MTTF of the six non-replaceable electrical lamps is 1666.67 hours.

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Which choice correctly defines magnetic poles? the points on the end of magnet, where the magnetic field is strongest the point on a magnet where one magnetic field cancels out another magnetic field the middle of a magnet where the magnetic field is zero different ends of a magnet where the magnetic field is weakest

Answers

Answer:

A. The points on the end of magnet, where the magnetic field is strongest.

Explanation:

A magnet is a substance that has the ability to attract magnetic materials, e.g iron, steel etc. It comprises of two poles (north-N and south-S) each at its two ends. The N-pole and S-pole are the points on a magnet that have the strongest magnetic field. The magnetic fields originates from the north pole, and terminates in the south pole of a magnet.

When the poles of two different magnets are brought close together, attraction or repulsion may occur.

The option that defines the magnetic poles is the points on the end of the magnet, where the magnetic field is strongest.

What is a magnetic field?

Attracting other iron-containing objects or aligning themselves in a magnetic field.

There are two poles of the magnet;

1. the North Pole.

2. the South Pole.

The same poles repel each other, while the opposite poles attract each other.

Thus, the correct option is A.

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Use DeMorgan's Theorem, as well as any other applicable rules of Boolean algebra, to simplify the following expression so there are no more complementation bars extending over multiple variables: \[ \

Answers

The expression to be simplified is, A + BC + ABCD. Using De Morgan's theorem, we can convert complementation bars extending over multiple variables into complementation bars over single variables. The De Morgan's theorem states that the complement of a product is equal to the sum of complements. De Morgan's Theorem:

 1.   (AB) = A + B2.  (A + B) = A B The steps to simplify the given expression using De Morgan's theorem are as follows: A + BC + ABCD = A + (BC + ABCD) = A + (BC). (ABCD) = A + (B + C) (A + B + C + D) = A + AB + AC + BC + BD = A + AC + BC + BD.

Hence, the simplified expression is A + AC + BC + BD. Thus, using DeMorgan's Theorem and other applicable rules of Boolean algebra, the given expression is simplified to A + AC + BC + BD.

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Where in the dwelling policy is it stated that earth movement, landslide, mine subsidence, and mudflow are not covered unless resulting from direct loss by fire or explosion?

Answers

common exclusions, Due of their catastrophic character, the aforementioned risks—earth movement, landslide, mine material, and mudflow—are not covered by the dwelling insurance.

The Basic Form is designed on a named dangers basis and only covers the risks of fire, lightning, and internal explosion. It excludes theft and damage to trees, shrubs, and plants.

The Dwelling Policy's Coverage C for Personal Property provides coverage for damaged household and personal property that is being transported between the insured's old and new homes.

What is Dwelling Policy's?

The portion of your homeowners insurance policy known as dwelling coverage, or "dwelling insurance," may assist in covering the cost of repairing or rebuilding the physical structure of your house if a covered hazard causes damage to it.Farm property is not eligible, mobile homes must be firmly affixed to the foundation, and only incidental business is covered if the residence is utilized primarily for domestic purposes.

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A 500 kg roller coaster car crests a 20m high hill at a speed of 10 m/s. It then rolls down the other side, all the way to ground level, and climbs a second hill. What is the speed of the car when it is 10 m up the second hill? Group of answer choices 15.3 m/s 19.7 m/s 8.9 m/s 17.2 m/s

Answers

To find the speed of the roller coaster car when it is 10 m up the second hill, we can apply the principle of conservation of energy.

Initially, at the top of the first hill, the roller coaster car possesses gravitational potential energy, given by mgh, where m is the mass of the car (500 kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height of the hill (20 m). At this point, the car also has kinetic energy, given by (1/2)mv², where v is the initial speed (10 m/s).

As the car rolls down the hill and reaches the bottom, all the potential energy is converted into kinetic energy. Thus, we can equate the initial potential energy to the final kinetic energy:

mgh = (1/2)mv²

Simplifying the equation, we find:

gh = (1/2)v²

Now, to find the speed when the car is 10 m up the second hill, we need to calculate the corresponding potential energy at that point. The potential energy is given by mgh, where h is the height of the second hill (10 m).

Setting this equal to the final kinetic energy (1/2)mv², we have:

mgh = (1/2)mv²

Simplifying further:

gh = (1/2)v²

Now we can substitute the values:

(9.8 m/s²)(10 m) = (1/2)v²

Solving for v, we find:

v² = 196 m²/s²

v = √196 m/s

v ≈ 14 m/s

Therefore, the speed of the car when it is 10 m up the second hill is approximately 14 m/s.

None of the provided answer choices (15.3 m/s, 19.7 m/s, 8.9 m/s, 17.2 m/s) match the calculated result of 14 m/s.

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An object with a mass of 9 kg accelerates 3 m/s2 when an unknown force is applied to it. What is the unknown force

Answers

Answer:

we have to use the formula f=ma to find out the unknown force

Explanation:

mass = 9kg

accelration=3m/s^2

force = mass * acceleration

force = 9 * 3

force = 27 N(newton)

An object is 12.0 cm from a
concave mirror with f = 15.0 cm.
Find the image distance.
(Mind your minus signs.)
(Unit = cm)

Answers

To find the image distance formed by a concave mirror, we can use the mirror equation:

1/f = 1/di + 1/do

Where:

f is the focal length of the mirror,

di is the image distance,

and do is the object distance.

In this case, the object distance (do) is given as 12.0 cm, and the focal length (f) is given as 15.0 cm. We can rearrange the equation to solve for the image distance (di):

1/di = 1/f - 1/do

Substituting the given values:

1/di = 1/15 - 1/12

To simplify this expression, we need to find a common denominator:

1/di = (12 - 15)/(12 * 15)

1/di = -3/180

Now, we can invert both sides to find di:

di = 180/-3

di = -60 cm

Therefore, the image distance is -60 cm. The negative sign indicates that the image is formed on the same side as the object (in this case, it is a virtual image).

Answer:

60 cm

Explanation:

the U (obj. distance)  =   12  as it is a concave mirror then u  =  -12cm

the f = -15cm

by mirror formula

1/v  +  1/u =  1/f

by substituting values

1/v  +  (1/-12)  =  1/-15

1/v = 1/-15 -(1/-12)

1/v = 1/-15 + 1/12

by taking L C M  60

1/v = -(4/60)  +  5/60

1/v = 1/60

so V = 60 cm

A steam power plant operates between the pressure limit of 3.0 Mpa for the boiler and 75 kPa for the condenser. The plant operates in an ideal Rankine cycle with reheater with superheated vapor enters the high pressure turbine at 3 Mpa and 300 oC, and leaves at 1 MPa. Steam is then reheated at constant pressure to 300 oC before it is expanded to 75 kPa in a low pressure turbine. Determine:
a. the moisture content at the inlet of the condanger.
b. the met works per unit mare of steam tomane In Site.
c. the heat transter to the steam in the boter in lal per ke of steam.
d. the thermal efficiency
e. the heat transfer to cooling water passing through the condenser, in kJ per kg of steam flowing.

Answers

The dryness fraction is 0.96. Using steam tables the enthalpies at points 2, 3, and 4 can be calculated as 2936.4 kJ/kg, 2892.3 kJ/kg, and 1039.2 kJ/kg, respectively. The value of q is found to be 1438.3 kJ/kg.

a) 0.2, b) 2687 kJ/kg, c) 0.16 kJ/kg.K, d) 32%, e) 2549.52 kJ/kgPart (a): The steam is superheated at 300°C and 3 MPa, using steam tables it can be seen that the dryness fraction is 0.96.Part (b): This can be calculated using the formula shown below. The net work done by the turbine is given as follows: Net work = m (h1 - h2) + m (h3 - h4) Where m is the mass of the steam entering the turbine and h1, h2, h3, and h4 are the enthalpies at the different points in the cycle.h1 is given as 3478 kJ/kg, and using steam tables the enthalpies at points 2, 3, and 4 can be calculated as 2936.4 kJ/kg, 2892.3 kJ/kg, and 1039.2 kJ/kg, respectively.

Substituting the values in the formula gives the answer as 2687 kJ/kg.Part (c): Heat transfer per unit mass of steam to the boiler can be calculated using the formula shown below:q = h1 - h4 The value of q is found to be 1438.3 kJ/kg. Part (d): The thermal efficiency of the cycle can be calculated using the formula shown below: Efficiency = Net work output/ Heat inputHeat input can be calculated as follows: Heat input = m (h1 - h4) + m (h3 - h2) The value of heat input is calculated to be 4485.4 kJ/kg Substituting the values in the formula gives the answer as 32%.Part (e): The heat transfer to cooling water passing through the condenser is given as follows:q = m (h4 - h5)Where h4 is 1039.2 kJ/kg and h5 is 48.72 kJ/kg. The value of q is calculated to be 2549.52 kJ/kg.

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The position of the front bumper of a test car under microprocessor control is given by x(t)=2.17m+(4.80m/s2)t2?(0.100m/s6)t6.a. Find its position at the first instant when the car has zero velocity.b. Find its acceleration at the first instant when the car has zero velocity.c. Find its position at the second instant when the car has zero velocity.d. Find its acceleration at the second instant when the car has zero velocity.

Answers

Using velocity and acceleration, a. To determine the location of the car when its velocity is zero, we must identify the roots (time instances) of the velocity equation, which is the first derivative of the position equation.

The velocity equation is as follows: \(v(t) = (9.60m/s^3) t - (0.600m/s^7)t^7.\)

What numerical techniques may we use to find an equation's roots?

To find the roots of this equation, we can use numerical techniques like Newton-Raphson or bisection. The velocity equation can also be seen to be a seventh-degree polynomial with up to seven roots. By setting the velocity equation to zero and calculating the root, we can apply a numerical solution or perform a hand calculation to obtain the first root (i.e., the first time the car has zero velocity).

b. The formula for the acceleration equation, which is the second derivative of the position equation, is: \(a(t) = (9.60m/s^2) - (6.00m/s^6)\)\(t^6\)

c. and d. To discover the acceleration at the second time occurrence when the car has zero velocity, find the second root by repeating step a and using the acceleration equation to find the acceleration.

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we have a liquid with 3.8736 x 10-4 atm-1 at 25 oc (typical values of for liquids are in the order of 10-3 atm-1 to 10-4 atm-1 and for solids around 10-5 atm-1 to 10-6 atm-1). using the above definition, calculate the value of the pressure in atm that must be applied to a liquid initially at 1.000 atm to decrease its volume by 1.00%. you can assume that the value of remains constant for the range of pressures involved and the temperature is fixed at 25 oc.

Answers

Answer:

The pressure that must be applied to the liquid initially at 1.000 atm to decrease its volume by 1.00% is 0.990 atm.

Explanation:

To calculate the pressure required to decrease the volume of a liquid by 1.00%, we can use the formula:

P2 = P1 * (1 - ΔV/V1)

Where:

P2 is the final pressure,

P1 is the initial pressure,

ΔV is the change in volume, and

V1 is the initial volume.

Given:

P1 = 1.000 atm

ΔV/V1 = 1.00% = 0.01

Substituting these values into the formula, we can solve for P2:

P2 = 1.000 atm * (1 - 0.01)

P2 = 1.000 atm * 0.99

P2 = 0.990 atm

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A planet is most likely to have tectonic activity if it has:.

Answers

Answer: Heyo Kenji Here! Here's your answer- A planet is most likely to have tectonic activity.

Explanation: Hope this helps!

Have a nice day!

- Kenji ^^

if the old radiator is replaced with a new one that has longer tubes made of the same material and same thickness as those in the old unit, what should the total surface area available for heat exchange be in the new radiator to achieve the necessary heat exchange rate at the recommended temperature gradient?

Answers

Total surface area = 3/2 * area of an old radiator.

Solution:

K = \(\frac{Qd}{A*changeinT}\)

change in T =  ΔT  

Therefore New Area  ( A ) = 3/2 * area of the old radiator.

If you need faster cooling rates, replacing the rubber hoses with silicone hoses is one option. These can withstand higher heat, are less likely to break over time, and last longer. Apart from that, you can also upgrade the radiator fan and shroud to help with cooling. The radiator is an important component of the engine's cooling system.

Its main role is to spread the antifreeze/water mixture around the fins, letting off some of the engine's heat while drawing in the cool air before it passes through the rest of the engine. Replacing your home's radiator has a variety of benefits, and many properties will benefit from this.

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can someone please answer this, ill give you brainliest and your getting 100 points.

can someone please answer this, ill give you brainliest and your getting 100 points.

Answers

Answer: A

Explanation:Convection currents in the mantle Mantle convection is the very slow creeping motion of Earth's solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface. The Earth's surface lithosphere rides atop the asthenosphere and the two form the components of the upper mantle.

Answer:

B

Explanation:

A is lithosphere (The above surface of earth)B is asthenosphereC is outer coreD is inner core .

true or false When hydrogen joins with oxygen, a hydrogen bond has been formed.

Answers

Answer:

hydorgen bond

Explanation: pls give me branliest

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