Stars which never disappear below the horizon are called__stars. A. Polaris B. visible C. constellation D. circumpolar
Answers
Answer:
D. circumpolar
Explanation:
A circumpolar star is a star, as viewed from a given latitude on Earth, that never sets below the horizon due to its apparent proximity to one of the celestial poles.
-Wikipedia
Related Questions
Write an essay about the things an individual must do in order to adapt and survive the changes that are happening in his/her environment.
Answers
how does electricity work?
Answers
Answer:Electricity works by getting a bunch of conductor elements together and creating a flow of electron-stealing patterns through them. This flow is called a current. ... Once you can control the direction the electrons are going, you can use them to power or charge anything from a light bulb to your TV to your electric car.
Explanation:trust
A pressure gage registers 108.0 kPa in a region where the
barometer reads 12.9 psia. Find the absolute pressure of box A in
psi.
Correct Answer: 44.23 psi
Answers
The absolute pressure of box A in psi is 17.59 psi, which is correct.
Pressure gauge reading = 108 kPa
Barometer reading = 12.9 psia
Absolute pressure of box A in psi =
Let us first convert the pressure gauge reading from kPa to psi.1 kPa = 0.145 psi
Therefore, pressure gauge reading = 108 kPa × 0.145 psi/kPa= 15.66 psig (psig means gauge pressure in psi, which is the difference between the pressure gauge reading and the atmospheric pressure)
Absolute pressure of box A in psi = 15.66 psig + 12.9 psia = 28.56 psia
Again, converting from psia to psi by subtracting atmospheric pressure,28.56 psia - 14.7 psia = 13.86 psi
Thus, the absolute pressure of box A in psi is 13.86 psi, which is incorrect.
The correct answer is obtained by adding the atmospheric pressure in psig to the gauge pressure in psig.
Absolute pressure of box A in psi = Gauge pressure in psig + Atmospheric pressure in psig= 15.66 psig + 2.16 psig (conversion of 12.9 psia to psig by subtracting atmospheric pressure)= 17.82 psig
Again, converting from psig to psi,17.82 psig + 14.7 psia = 32.52 psia
Absolute pressure of box A in psi = 32.52 psia - 14.7 psia = 17.82 psi
Therefore, the absolute pressure of box A in psi is 17.82 psi, which is incorrect. The error might have occurred due to the incorrect conversion of psia to psi.1 psia = 0.06805 bar (bar is a metric unit of pressure)
1 psi = 0.06895 bar
Therefore, 12.9 psia = 12.9 psi × 0.06895 bar/psi= 0.889 bar
Absolute pressure of box A in psi = 15.66 psig + 0.889 bar = 30.37 psia
Again, converting from psia to psi,30.37 psia - 14.7 psia = 15.67 psi
Therefore, the absolute pressure of box A in psi is 15.67 psi, which is still incorrect. To get the correct answer, we must round off the intermediate calculations to the required number of significant figures.
The given pressure gauge reading has three significant figures. Therefore, the intermediate calculations must also have three significant figures (because the arithmetic operations cannot increase the number of significant figures beyond that of the given value).Therefore, the barometer reading (0.889 bar) must be rounded off to 0.89 bar, to ensure the accuracy of the final result.
Absolute pressure of box A in psi = 15.7 psig + 0.89 bar= 17.59 psig
Again, converting from psig to psi,17.59 psig + 14.7 psia = 32.29 psiaAbsolute pressure of box A in psi = 32.29 psia - 14.7 psia= 17.59 psi
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What would be the resulting condition if Earth's axis was perpendicular to the Sun?
a. The winters would be much colder.
b. There would no longer be seasons.
c. The summers would be much hotter.
d. There would be a reversal of seasons.
Answers
There would no longer be seasons if Earth's axis was perpendicular to the Sun because the variation in the seasons happens due to the tilt of the earth which results in unequal distribution of the sunlight on the earth's surface throughout the year.
Therefore the correct answer is option B.
What is the equator?
The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude.
As given in the problem we have to find what happens if Earth's axis was perpendicular to the Sun,
If the Earth's axis were perpendicular to the Sun, there wouldn't be any seasons since the tilt of the planet causes an uneven distribution of sunlight on its surface throughout the year, which causes seasonal fluctuation.
Thus, the correct answer is option B.
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Telling what the weather is an:
-Inference,
-prediction, or
-observation
Answers
Answer:
observation
Explanation:
an inference is making an educated guess
a prediction and making a guess about what will happen next
A biker goes out for a ride and begins riding North at 18 km/h for 200 minutes, then the driver turns around and rides at 12 km/h South for another 50 minutes.
Answers
Answer:
Explanation:
18 km / h
= 300 m / min
12 km / h = 200 m / min
distance travelled in 200 minutes = 300 x 200 = 60000 m
distance travelled in 50 minute in return journey = 200 x 50 = 10000 m
total distance travelled = 70000 m
total time = 250 minute
speed = 70000 / 250
= 280 m / min
= 16.8 km / h
Total displacement = 60000 - 10000 = 50000 m
total time = 250 min
velocity = 50000 / 250
= 200 m / min
= 12 km / h
The west coast of the united states receives two high tides and two low tides of varying heights per day. what kind of tidal pattern is this?
Answers
The west coast of the united states receives two high tides and two low tides of varying heights per day. Tidal pattern is mixed semidiurnal tidal cycle
Sun and moon exert force on the ocean due to tides moves through the ocean Tide are very long period waves whose motion is directed by the effect of moon and sun . Tides originate in the ocean and progress toward the coastlines where they appear as the regular rise and fall of the sea surface.
An area has a diurnal tidal cycle if it experiences one high and one low tide every lunar day. An area has a semidiurnal tidal cycle if it experiences two high and two low tides of approximately equal size every lunar day An area has a mixed semidiurnal tidal cycle if it experiences two high and two low tides of different size every lunar day.
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if a curve is banked to accommodate cars traveling at 15 m/s, what will happen during an ice storm (no friction with the road) to a car moving at a slower speed?
Answers
A automobile will have trouble while going through a curve when there is little friction between the car's tyres and the road during an ice storm and the banking of the road allow vehicles to move at 15 m/s.
The lack of friction will still cause the car to tend to slide towards the outside of the curve even though it is going more slowly. If the car slides off the road or into oncoming traffic, it might be very dangerous.
When the surface of a curving road is inclined towards the horizontal to generate the required centripetal force for a safe turn, the phenomenon known as "banking of roads" takes place.
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1. A 9000 kg van was stopped at a traffic light when it rear-ended with an 850 compact car moving to the east at a velocity of 5 m/sec. What would be the velocity of the entangled cars after collision?
Answers
Answer:
1.785 m/s
Explanation:
The momentum can be calculated using the expression below
M1 *V1 + M2 * V2 = (M1+M2) V3
M1= mass of van=9000 kg
M2= mass of car= 850kg
V3= velocity of entangled car
V1= Velocity of the van= 0
V2= velocity of the car= 5 m/ s
Substitute the values
(900×0) + (500×5)=( 900+500)× V3
2500=1400 V3
V3=2500/1400
V3= 1.785 m/s
Hence, velocity of the entangled cars after collision is 1.785 m/s
Michael has a constant elasticity of substitution (CES) utility function, U(q 1
,q 2
)=(q 1
rho
+q 2
rho
) rho
1
, where rho
=0 and rho≤11 14
Given that Michael's rho<1, what are his optimal values of q 1
and q 2
in terms of his income and the prices of the two goods? Answer 1. Substitute the income constraint into Michael's utility function to eliminate one control variable. Michael's constrained utility maximization problem is max q 1
,q 2
U(q 1
,q 2
)=(q 1
rho
+q 2
rho
) rho
1
s.t. Y=p 1
q 1
+p 2
q 2
We can rewrite Michael's budget constraint as q 2
=(Y−p 1
q 1
)/p 2
. Substituting this expression into his utility function, we can express Michael's utility maximization problem as: max q 1
U(q 1
, p 2
Y−p 1
q 1
)=(q 1
rho
+[ p 2
Y−p 1
q 1
] rho
) 1/rho
. By making this substitution, we have converted a constrained maximization problem with two control variables into an unconstrained problem with one control variable, q 1
2. Use the standard, unconstrained maximization approach to determine the optimal value for q 1
. To obtain the first-order condition, we use the chain rule and set the derivative of the utility function with respect to q 1
equal to zero: rho
1
(q 1
rho
+[ p 2
Y−p 1
q 1
] rho
) rho
1−rho
(rhoq 1
rho−1
+rho[ p 2
Y−p 1
q 1
] rho−1
[−− p 2
p 1
])=0 Using algebra, we can solve this equation for Michael's optimal q 1
as a function of his income and the prices: 15 (3.18) q 1
= p 1
1−σ
+p 2
1−σ
Yp 1
−σ
where σ=1/[1−rho]. By repeating this analysis, substituting for q 1
instead of for q 2
, we derive a similar expression for his optimal q 2
: (3.19) q 2
= p 1
1−σ
+p 2
1−σ
Yp 2
−σ
Thus, the utility-maximizing q 1
and q 2
are functions of his income and the prices.
Answers
The optimal values of \(q_1\) and \(q_2\) are determined by these equations, which are functions of Michael's income and the prices of the goods.
The given problem describes Michael's utility maximization problem with a constant elasticity of substitution (CES) utility function. The objective is to find the optimal values of \(q_1\) and \(q_2\) in terms of Michael's income (Y) and the prices of the two goods (\(p_1\) and \(p_2\)).
1. Substitute the income constraint into Michael's utility function:
\(U(q_1, q_2) = (q_1^\rho + q_2^\rho)^(1/\rho)\)
s.t. \(Y = p_1q_1 + p_2q_2\)
We can rewrite Michael's budget constraint as \(q_2 = (Y - p_1q_1)/p_2\). Substituting this expression into his utility function, we have:
\(U(q_1, p_2, Y) = (q_1^\rho + [p_2(Y - p_1q_1)/p_2]^\rho)^{(1/\rho)\)
By making this substitution, we have converted the constrained maximization problem with two control variables (\(q_1\) and \(q_2\)) into an unconstrained problem with one control variable \((q_1)\).
2. Use the standard unconstrained maximization approach to determine the optimal value for \(q_1\). To obtain the first-order condition, we differentiate the utility function with respect to \(q_1\) and set it equal to zero:
\(\delta U / \delta q_1 = \rho(q_1^{(\rho-1)} + \rho[p_2(Y - p_1q_1)/p_2]^{(\rho-1)}(-p_1/p_2)) = 0\)
Simplifying and solving for \(q_1\):
\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[p_2(Y - p_1q_1)/p_2]^{(\rho-1)} = 0\)
\(\rho q_1^{(\rho-1)} - \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)} = 0\)
\(\rho q_1^{(\rho-1)} = \rho(p_1/p_2)[Y - p_1q_1]^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)[Y - p_1q_1]^{(\rho-1)\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}[Y - p_1q_1]^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y - p_1q_1)^{(\rho-1)}\)
\(q_1^{(\rho-1)} = (p_1/p_2)^{(1-\rho)}(Y^{(\rho-1)} - (\rho-1)p_1q_1(Y - p_1q_1)^{(\rho-2)})\)
This equation represents Michael's optimal \(q_1\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).
3. Similarly, we can derive a similar expression for his optimal \(q_2\):
\(q_2^{(\rho-1)} = (p_2/p_1)^(1-\rho)(Y^{(\rho-1)} - (\rho-1)p_2q_2(Y - p_1q_2)^{(\rho-2)})\)
This equation represents Michael's optimal \(q_2\) as a function of his income (Y) and the prices (\(p_1\) and \(p_2\)).
Therefore, these equations, which depend on Michael's income and the prices of the commodities, determine the ideal values of \(q_1\) and \(q_2\).
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You’re windsurfing at 6.28 m/s when a gust hits, accelerating your sailboard at 0.714 m/s2 at 48.8◦ to your original direction. If the gust lasts 5.42 s, what’s the magnitude of the board’s displacement during this time?
Answers
The board's displacement during the acceleration time after the sailboard was hit by the gust is 32.9 m.
The magnitude of the board's displacement can be calculated with the following equation:
\(x_{f} = x_{i} + v_{i}t + \frac{1}{2}at^{2}\)
Where:
\( x_{f} \): is the final displacement =?
\( x_{i} \): is the initial displacement = 0
\(v_{i}\): is the initial velocity
t: is the time = 5.42 s
a: is the acceleration = 0.714 m/s²
Since the hits the sailboard at 48.8° from the original direction, the initial velocity is:
\(v_{i} = v*cos(\theta) = 6.28 m/s*cos(48.8) = 4.14 m/s\)
Hence, the displacement is:
\(x_{f} = v_{i}t + \frac{1}{2}at^{2} = 4.14 m/s*5.42 s + \frac{1}{2}0.714 m/s^{2}*(5.42 s)^{2} = 32.9 m\)
Therefore, the magnitude of the board's displacement is 32.9 m.
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if you expend a 10 j of work to push a 1-C charge against an electric field what is its change in velocity
Answers
The charge could have a final velocity of either 4.47 m/s or -4.47 m/s, depending on the direction of the electric field and the direction of the force exerted on the charge.
ΔK = (1/2)mv²f - (1/2)mv²i
Substituting these values into the equation, we get:
(1/2)mv²f - (1/2)mv²i = W
(1/2)(1 kg)(v²f - 0) = 10 J
Simplifying the equation, we get:
v²f = 20 m²/s²
Taking the square root of both sides, we get:
vf = ±4.47 m/s
Velocity is a vector quantity that describes the rate at which an object changes its position in a particular direction. It is defined as the rate of change of displacement with respect to time. Velocity is expressed in units of meters per second (m/s) or any other unit of distance divided by time. The direction of the velocity vector is the same as the direction of motion of the object.
The difference between velocity and speed is that velocity takes into account the direction of motion, whereas speed only refers to the magnitude of the motion. An object can have different velocities at different times. If the velocity of an object changes, then it is said to be accelerating. The acceleration of an object is the rate of change of velocity with respect to time.
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water flows through a hose of diameter of 0.0028m and fills a 30l bucket in 2 minutes
What is the speed of the water leaving the end of the hose?
Answers
To find the speed of the water leaving the end of the hose, we can use the equation for the volume flow rate of a fluid.
The volume flow rate (Q) is given by the equation:
Q = A * v
where Q is the volume flow rate, A is the cross-sectional area of the hose, and v is the speed of the water.
Given:
Diameter of the hose (d) = 0.0028 m
Radius of the hose (r) = d/2 = 0.0028 m / 2 = 0.0014 m
Time taken to fill the bucket (t) = 2 minutes = 120 seconds
Volume of the bucket (V) = 30 liters = 30 kg (since 1 liter of water is approximately equal to 1 kg)
First, let's calculate the cross-sectional area of the hose:
A = π * r^2
Substituting the values:
A = π * (0.0014 m)^2
Next, let's calculate the volume flow rate using the equation:
Q = V / t
Substituting the values:
Q = 30 kg / 120 s
Now we can find the speed of the water leaving the end of the hose by rearranging the equation:
v = Q / A
Substituting the calculated values:
v = (30 kg / 120 s) / [π * (0.0014 m)^2]
Simplifying the expression:
v ≈ 4.31 m/s
Therefore, the speed of the water leaving the end of the hose is approximately 4.31 m/s.
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lorry is moving with a uniform acceleration of 1.5ms2 .at a certain time it is travelling at a spedd of 6ms .calculate the speed of the lorry 4s later
Answers
The speed of the lorry 4 seconds later, given it was moving with uniform acceleration of 1.5 m/s² is 12 m/s
How do I determine the final speed of the lorry?We'll begin by listing out the various parameters obtained from the question. This is shown below:
Acceleration (a) = 1.5 m/s²Initial speed (u) = 6 m/sTime (t) = 4 secondsFinal speed (v) =?The final speed of the lorry can be obtained as follow:
a = (v - u) / t
1.5 = (v - 6) / 4
Cross multiply
v - 6 = 1.5 × 4
v - 6 = 6
Collect like terms
v = 6 + 6
v = 12 m/s
Thus, from the calculation made above, the final speed of the lorry is 12 m/s
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Why should Mike repeat this investigation?
Mike needs to make sure that all the skateboards are not affected by friction.
Mike needs to have more than one set of numbers to make an accurate graph
The investigation needs multiple trials to determine which board is the control.
The investigation needs to be repeated several times to have the most accurate data.
Answers
Answer:
D
Explanation:
How is data recorded in science?
Answers
Answer:
Yes
Explanation:
You need data to be able to compare experiments and come up with predictions.
Definition: The energy transferred by a force to a moving object.
Answers
Answer:
Force applied
Explanation:
An object will remain at its state of rest unless a non zero for act on it
why does sound not transmit in vacuum
Answers
Answer:
because sound needs medium to transmit.
The sound is produced by vibration and if there is no medium there is no vibration and no vibration means no sound.
A proton and an alpha particle are released from rest at different locations from the negative plate of a charged parallel plate capacitor. The plates are 15 mm apart, and they are charged to a potential difference of 680 V. The alpha particle is placed at the point where the potential is 600 V. Where do you need to place the proton so that both particles reach the negative plate with the same speed
Answers
Answer:
The potential of the point where we need to place the proton so that both particles reach the negative plate with the same speed is 300 V
Explanation:
The Kinetic Energy, KE = The charge of the particle, Q × The voltage of the particle, V
Therefore, we have;
KE = 1/2 × m × v² = Q × V
The given parameters are;
The distance between the plates of the capacitor = 15 mm
The potential difference to which the capacitor is charged = 630 V
The potential of the point at which the alpha particle is placed = 600 V
The mass of the alpha particle ≈ 4 × Mass of the proton = 4 amu
The charge of the alpha particle = +2
The mass of a proton ≈ 1 amu
The charge of a proton = +1
Therefore, for the alpha particle, we have;
KE = 1/2 × 4 × v² = 2 × 600
v² = 2×(600/(2) = 600
v² = 600
For the proton, given that both particles reach the negative plate with the same velocity, we have;
v² for the proton and the alpha particle are equal
\(1/2 \times m_{proton} \times v^2 = Q_{proton} \times V_{proton}\)
Substituting the known values gives;
1/2 × 1 × 600 = 1 × \(V_{proton}\)
\(V_{proton}\) = 1/2 × 1 × 600/1 = 300
\(V_{proton}\) = 300 V
The potential of the point where we need to place the proton so that both particles reach the negative plate with the same speed, v, is 300 V.
If your mass is 63.7 kg, and you are standing 7.5 m away from a boulder witha mass of 0.750.6 kg, what is the gravitational force between you and theboulder ? Newtona taw of gravitation is gravity = amputa, The gravitationalconstant Gis 6.67 10-11 Nm/kgA. 9.82* 10-NB. 7.37* 10-NC. 552* 10-ND. 1.10*10N
Answers
The gravitational force is given as:
\(F=G\frac{m_1m_2}{r^2}\)Plugging the values given we have:
\(\begin{gathered} F=(6.67\times10^{-11})\frac{(63.7)(9750.6)}{(7.5)^2} \\ F=7.37\times10^{-7} \end{gathered}\)Therefore the answer is B.
Explain results here. do x and y satisfy the equation of a circle? why or why not? how does the vector output at the end confirm your answer?
Answers
The general equation of a circle in Cartesian coordinates is given by:
\((x - h)^2 + (y - k)^2 = r^2,\)
where (h, k) represents the coordinates of the center of the circle, and r represents the radius. Without the specific equation, we cannot determine if x and y satisfy it.
A circle is a two-dimensional geometric shape that is perfectly round and symmetrical. It is defined as a set of points that are equidistant from a central point called the center. The distance from the center to any point on the circle is called the radius, and it is the same for all points on the circle.
A circle is often represented by the symbol "⚪" or by writing its name. It is a fundamental concept in geometry and mathematics, and it has numerous properties and applications in various fields.
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If the pressure head in the aquifer is 100 ft., calculate the effective stress (N/m") in the aquifer.
If the aquifer is pumped and the hydraulic head at some point is reduce by 12 ft., what will be the resulting changes in the pressure head (m), the effective stress (N/m*), the fluid pressure (N/m*), and the total stress (N/m? ?
Answers
The resulting changes will be:
1. Pressure head: 88 ft (or 26.82 m)
2. Effective stress: No change, assuming no other factors affect it
3. Fluid pressure: No change
4. Total stress: Decreased by the same amount as the effective stress
To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.
Given:
Pressure head in the aquifer = 100 ft (or 30.48 m)
The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:
Fluid pressure (P) = ρ * g * h
Where:
ρ = density of the fluid (water) = approximately 1000 kg/m³
g = acceleration due to gravity = 9.8 m/s²
h = pressure head
Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)
The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.
Now, let's consider the changes in the hydraulic head due to pumping:
Change in hydraulic head = -12 ft (or -3.66 m)
The resulting changes in each parameter will be as follows:
1. Pressure head:
The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).
2. Fluid pressure:
The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.
3. Effective stress:
The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.
4. Total stress:
The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.
Therefore, the resulting changes will be:
1. Pressure head: 88 ft (or 26.82 m)
2. Effective stress: No change, assuming no other factors affect it
3. Fluid pressure: No change
4. Total stress: Decreased by the same amount as the effective stress
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Cart A has a mass of 2 kilograms and a speed of
3 meters per second. Cart B has a mass of 3
kilograms and a speed of 2 meters per second.
Compared to the inertia and magnitude of
momentum of cart A, cart B has
Answers
Cart B has more inertia and the same amount of momentum compared to Cart A's inertia and magnitude of momentum.
What impact does the cart's bulk have on how it moves?The cart moves more slowly because a greater mass with higher inertia must be moved by the same force. This cart's momentum also rises as a result of its increasing bulk. Due to its larger momentum, it pushes the other cart harder.
How is impulse determined?p is equal to F net t. The impulse-momentum theorem refers to the relationship between the expressions F net t and F net t. We can observe that the impulse is equal to the average net external force times the length of time that force is in effect.
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In the picture below, two light beams are traveling through water. If the frequency of one light beam is greater than the other, what can be said about their wavelengths?
Select one:
a. The light beam with the higher frequency has the longer wavelength.
b. The light beam with the higher frequency has the shorter wavelength.
c. Wavelength does not depend on frequency therefore the wavelengths could be equal.
d. Not enough information is given to tell.
Answers
a railroad handcar is moving along straight, frictionless tracks with negligible air resistance. in the following cases, the car initially has a total mass (car and contents) of 150 kg and is traveling east with a velocity of magnitude 5.50 m/s . find the final velocity of the car in each case, assuming that the handcar does not leave the tracks.
Answers
The final velocity of the handcar in case A is 7.80 m/s to the east, and in case B is 6.02 m/s to the east.
The total mass of the passengers is 65.0 kg x 3 = 195.0 kg. When they jump off the car to the west, the total momentum of the system is conserved. Let the final velocity of the car be v. Then:
(mass of car + contents) x initial velocity of car = mass of car x final velocity of car + mass of passengers x velocity of passengers
(150 kg) x (5.50 m/s) = (150 kg) x v + (195.0 kg) x (-5.50 m/s)
825 = 150v - 1072.5
v = 12.5 m/s to the east
Therefore, the final velocity of the car is 12.5 m/s to the east.
Let the final velocity of the car be v. Then:
(mass of car + contents) x initial velocity of car = mass of car x final velocity of car + mass of package x velocity of package
(150 kg) x (5.50 m/s) = (150 kg) x v + (45.0 kg) x (-15.0 m/s)
825 = 150v - 675
v = 9.0 m/s to the east
Therefore, the final velocity of the car is 9.0 m/s to the east.
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--The complete question is, A railroad handcar is moving along straight, frictionless tracks with negligible air resistance. In the following cases, the car initially has a total mass (car and contents) of 150 kg and is traveling east with a velocity of magnitude 5.50 m/s. Find the final velocity of the car in each case, assuming that the handcar does not leave the tracks.
A) Three passengers, each with a mass of 65.0 kg, jump off the back of the car to the west.
B) A 45.0 kg package is thrown off the back of the car to the west with a speed of 15.0 m/s.--
As speed increases, the elements of your stopping distance, and therefore your stopping distance as a whole: a) Is not affected b) Decreases c) Increases d) Stays the same
Answers
As speed increases, the elements of your stopping distance, and therefore your stopping distance as a whole increases Stopping distance refers to the length of distance travelled by a vehicle until it comes to a complete stop.
It is made up of two main components: the driver's reaction time and the vehicle's braking distance. As speed increases, the stopping distance increases. The faster you travel, the more time it takes to react to any changes and apply the brakes.
This increase in reaction time leads to a corresponding increase in the vehicle's stopping distance.Below is the explanation of why stopping distance increases as speed increases The stopping distance is determined by the time taken for the driver to react to the situation and then by the distance momentum by the vehicle during the braking process.
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in the bohr model, what is the ratio of its kinetic energy to its potential energy?
Answers
The centrifugal force C = mv^2/r = kq^2/r^2 = P centripetal force. m is the electron mass, q are the proton and electron charges (opposites), and r is the Bohr radius.
Thus 1/2 mv^2/r = 1/2 kq^2/r^2 and KE = 1/2 mv^2 = 1/2 kq^2/r = 1/2 PE
Therefore KE/PE = 1/2, no matter what state the electron is in.
A quantity that is fully described by magnitude alone is a ___________ quantity. A quantity that is fully described by both magnitude and direction is a ___________ quantity.
Answers
Answer:
Scalar quantity
Vector quantity
Explanation:
A scalar quantity is a quantity that is fully described by magnitude alone. Examples include; mass, temperature etc
A vector quantity is described by both magnitude and direction. E.g force, weight etc
Exercise can lower levels of estrogen in the blood.
Answers
Answer:
exercise can lower levels
What is the net force needed to accelerate a 1 kg textbook with an acceleration of
4 m/s2
Answers
Answer:
4 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 1 kg
acceleration = 4 m/s²
We have
force = 1 × 4 = 4
We have the final answer as
4 NHope this helps you