Suppose the race car now slows down uniformly from 60.0 m/s to 30.0 m/s in 4.50 s to avoid an accident, while still traversing a circular path 4.00 102 m in radius. Find the car’s (a) centripetal acceleration, (b) angular speed, (c) tangential acceleration, and (d) total acceleration when the speed is 40.0 m/s.

Yes, it is possible to determine who is correct, the aliens or NASA, about the composition of the planet's atmosphere using the data provided in the problem.

The mass of the gas sample is 2.00 g, and the volume of the gas sample is 1.18 L. Therefore, the density of the gas sample can be calculated as follows:

Density = mass/volume

Substituting the given values of mass and volume, we get:

Density = 2.00 g / 1.18 L = 1.69 g/L

The molar mass of a gas can be calculated using the following formula:

Molar mass = density × 22.4

where 22.4 is the molar volume of any gas at STP (Standard Temperature and Pressure), i.e., 0ºC and 1 atm.

Substituting the given value of density, we get:

Molar mass = 1.69 g/L × 22.4 L/mol = 37.9 g/mol

The mass of nitrogen present in the sample can be calculated using the following formula:

Mass of nitrogen = n × Molar mass of nitrogen

where n is the number of moles of nitrogen in the sample. Similarly, the mass of carbon monoxide present in the sample can be calculated using the following formula:

Mass of carbon monoxide = n × Molar mass of carbon monoxide

where n is the number of moles of carbon monoxide in the sample.

Since the alien claimed that their atmosphere is composed of pure nitrogen, we can calculate the mass of nitrogen in the sample using the molar mass of nitrogen, which is 28.0 g/mol. Therefore, we get:

Mass of nitrogen = n × (28.0 g/mol)

Since the density of the sample is 1.69 g/L, we can calculate the number of moles of nitrogen in the sample as follows:

n = density / Molar volume

where the molar volume of the gas at 125ºC and 1502 torr can be calculated using the ideal gas equation, which is:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Therefore, we get:

Molar volume = (RT) / P

Substituting the given values of pressure and temperature, we get:

Molar volume = (0.0821 L · atm/(mol · K)) × (398 K) / (1502 torr) = 0.0264 L/mol

Substituting the given values of density and molar volume, we get:

n = (1.69 g/L) / (0.0264 L/mol) = 64.0 mol

Substituting the calculated value of n in the formula for mass of nitrogen, we get:

Mass of nitrogen = (64.0 mol) × (28.0 g/mol) = 1792 g

Therefore, the calculated mass of nitrogen in the sample is 1792 g, which is greater than the mass of the sample itself. This is not possible, which means that the alien's claim that their atmosphere is composed of pure nitrogen is false.

On the other hand, NASA has collected spectroscopic data which suggest that the planet has an atmosphere of pure carbon monoxide. Therefore, the gaseous sample must be composed of pure carbon monoxide, as claimed by NASA. Thus, NASA is correct about the composition of the planet's atmosphere.

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The magnitude of the angular momentum of the rod immediately after the collision is given as (pf + pi) * d. (Option A).

Angular Momentum may be defined or described as the vector quantity of the rotation of a body, which is arrived at by multiplying its moment of inertia by its angular velocity.

The formula for Angular Momentum is given as:

L = mvr; Where

L = Angular Momentum

m = mass

v = velocity; and

r = radius.

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\(\rm( P_f+P_i)d\) is the magnitude of the rod's angular momentum immediately after the contact. Option A is correct.

Angular Momentum may be defined as the vector quantity of a body's rotation, which is calculated by multiplying its moment of inertia by its angular velocity.

The Angular Momentum formula is as follows:

\(\rm L=I\omega\)

\(\rm L = mvr\)

Where,

L is the angular momentum

m stands for mass.

v stands for velocity, and

r stands for radius.

Hence option A is correct.

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Answer:

left atrium

Explanation:

its the first chamber of the heart to receive oxygenated blood from the lungs

The time on the surface of an object would run most slowly on an object with the same mass as the Sun but twice as large in radius.

What is mass?

Mass is a measure of the amount of matter in an object and is typically expressed in kilograms (kg). It is an intrinsic property of matter and is different from weight, which is a measure of the force of gravity acting on an object. Mass is an important factor in determining the physical properties of an object, such as density, momentum, and inertia. Mass is also used to calculate the gravitational force between two objects, as well as the energy required to move it.

This is because the surface gravity of an object is inversely proportional to the square of its radius. Therefore, the object with the same mass as the Sun but twice as large in radius would have a much lower surface gravity, and time would run more slowly on its surface.

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Take the upward and to-the-right directions to be positive (so down and to-the-left are negative).

The vertical forces acting on the object cancel, 6 N - 6 N = 0.

The horizontal forces exert a net force of 20 N - 3 N = 17 N. This net force is positive, so it points to the right. So the answer is A.

Let's look at relationship

\(\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{m}{k}}\)

\(\\ \rm\rightarrowtail T\propto \sqrt{m}\)

Hence

\(\\ \rm\rightarrowtail \dfrac{T_1}{T_2}=\sqrt{\dfrac{m1}{m2}}\)

\(\\ \rm\rightarrowtail \dfrac{1.5}{2}=\sqrt{\dfrac{0.5}{m2}}\)

\(\\ \rm\rightarrowtail 0.75^2=\dfrac{0.5}{m2}\)

\(\\ \rm\rightarrowtail m_2=\dfrac{0.5}{0.75^2}\)

\(\\ \rm\rightarrowtail m_2=0.889\)

Hence

Answer

Mass needs to added =0.889-0.500=0.389kg

Explanation:

If a truck has a linear acceleration of 1.85 m/s² and the wheels have an angular acceleration of 5.23 rad/s², the diameter of the truck's wheels   0.71 m.

Linear acceleration refers to the time rate of change of linear velocity, whereas angular acceleration refers to the time rate of change of angular velocity. This is the primary differential between linear and angular acceleration. Simply said, changes in an object's linear velocity with respect to time are represented by changes in linear acceleration.

The angular acceleration can be deduced immediately from the concept of α =ΔωΔt because the ultimate angular velocity and time are both provided.

The link between linear acceleration (a) and rotational acceleration is expressed as a = r×α . When the angular acceleration increases, so will the linear acceleration's strength. Increased wheel angular acceleration, for instance, denotes an accelerated vehicle.

Linear acceleration is the uniform acceleration caused by a moving body moving along a straight line. There are three equations that are essential in linear acceleration, depending on parameters like start and terminal velocities, displacements, times, and acceleration.

Given :

linear acceleration a = 1.85 m/s²

angular acceleration α  = 5.23 rad/s²

radius r = a/ α  = \(\frac{1.85}{5.23}\) = 0.354 m

diameter  d = 2r = 2 × 0.354 = 0.71 m

diameter of the wheels is  0.71 m.

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Answer:

B. The volume of an object is the same as the

weight of that object.

Explanation:

Every thing else is right and that one is wrong.

Answer:

B. The volume of an object is the same as the

weight of that object.

Explanation:

i hope it helps

The change in entropy of the universe is 201 J/K.

To find the change in entropy of the universe, we need to consider the entropy changes of both the avalanche and its surroundings. The second law of thermodynamics states that the total entropy of a closed system (the universe in this case) always increases.

\(KE = mgh\)

ΔS_avalanche = \(Q/T = KE/T\)

Substituting the expression for KE, we get:

ΔS_avalanche = mgh/T

ΔS_avalanche =\((1800 kg)(9.8 m/s^2)(160 m)/(273 K)\)

ΔS_avalanche = \(201 J/K\)

Q = mcΔT

The total entropy change of the universe is the sum of the entropy changes of the avalanche and its surroundings:

ΔS_universe = ΔS_avalanche + ΔS_surroundings

ΔS_universe =\(201 J/K + 0 J/K\)

ΔS_universe = \(201 J/K\)

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The 21 cm radiation provides information about the gas clouds, including their temperature and density, as well as their magnetic field strength and chemical composition.

The radiation also helps to map out the structure of the Milky Way galaxy and its surrounding regions.21 cm radiation is a type of radio wavelength radiation that is emitted by neutral hydrogen atoms. When these atoms change the direction of their spins, they emit radiation at a wavelength of 21 centimeters. This radiation is able to penetrate dust clouds and other obstacles in space, allowing astronomers to study the gas clouds that make up the Milky Way and other galaxies. The 21 cm radiation provides information about the gas clouds, including their temperature and density, as well as their magnetic field strength and chemical composition. By studying this radiation, astronomers can create detailed maps of the Milky Way galaxy and the regions surrounding it.

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The electrons within a rectangular rod will move away when a negatively charged balloon is brought near a negatively charged rod because the electrons are repelled by each other.

Electrostatics is the study of charges at rest.

Charges at rest are charges that are not free to move or charges that do not have a path for them to flow.

The flow of electrons results in an electric current. However, when charged materials are brought near other charged materials, they will either be repelled or attracted to each other depending on the nature of the charges.

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Answer: 0.83333333333 km/h

Explanation: give brainliest

Answer:

TRUE

Explanation:

Answer:

Answer is True

Explanation:

Mark as Brainliest I hope help you

Answer:

5730 yr

Explanation:

25  = 100 (1/2)^11460/x       where x = half life

.25 = (1/2)^11460/x

log .25 / log.5   = 11460/x

x = 5730 yr

11.The time at 75° East longitude would be 1 hour and 20 minutes behind. 12.The time at 135° degrees East longitude would be 4 hours ahead. and 13. the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM.

At 2:00 AM at 90° East longitude, the time at 75° East longitude would be 1 hour and 20 minutes behind. This is because for every 15 degrees of longitude, there is a time difference of approximately 1 hour. Since the two longitudes in question have a difference of 15 degrees, we can divide this by 15 to calculate the time difference.

If it is 8:00 PM at 15° East longitude, the time at 135° East longitude would be 4 hours ahead. Similarly, for every 15 degrees of longitude, there is an approximate time difference of 1 hour. Since the two longitudes in question have a difference of 120 degrees, we can divide this by 15 to calculate the time difference.

There is a 7-hour difference** between 105° West longitude and the Prime Meridian (0° longitude). The Prime Meridian, passing through Greenwich, England, serves as the reference point for determining time zones. As one moves westward from the Prime Meridian, each 15 degrees of longitude corresponds to a time difference of approximately 1 hour. Therefore, the time at 105° West longitude would be 7 hours behind the time at the Prime Meridian.

If it is 9:30 AM in New York (41° North latitude, 75° West longitude), the time in Lima, Peru (15° South latitude, 75° West longitude) would also be 9:30 AM. The latitude does not affect the time difference between the two locations. However, since both locations have the same longitude (75° West), they would experience the same local time. The time difference between different latitudes is primarily significant for determining time zones rather than the actual time within a specific time zone.

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Answer:

Distance = 56km Displacement = 30km

Explanation:

hope I helped

The pilot needs to drop the parcel approximately 101 meters horizontally from the ship's current position to successfully land it on the ship.

To determine the horizontal distance needed for the pilot to drop the parcel onto the ship, we need to consider the relative motion between the airplane and the ship.

Since the ship is moving in the opposite direction to the airplane, we can treat it as having a velocity of -10 m/s (negative because it's in the opposite direction).

Now, let's consider the time it takes for the parcel to drop from the airplane to the ship. The vertical distance is given as 500 m, and we can use the formula for vertical motion under constant acceleration to find the time:

h = ut + (1/2)gt²

Where:

h = vertical distance = 500 m

u = initial vertical velocity = 0 m/s (since the parcel is dropped)

g = acceleration due to gravity = 9.8 m/s²

t = time

Plugging in the values:

500 = 0 * t + (1/2) * 9.8 * t²

500 = 4.9t²

t² = 500 / 4.9

t² ≈ 102.04

t ≈ √102.04

t ≈ 10.10 s (rounded to two decimal places)

Now that we have the time it takes for the parcel to fall, we can calculate the horizontal distance traveled by the ship during that time. The ship's velocity is -10 m/s, and the time is 10.10 s:

Horizontal distance = velocity * time

Horizontal distance = -10 * 10.10

Horizontal distance ≈ -101 m (rounded to two decimal places)

The negative sign indicates that the ship moved in the opposite direction, but since distance is a scalar quantity, we can take the magnitude of the result:

Horizontal distance ≈ 101 m

Therefore, the pilot needs to drop the parcel approximately 101 meters horizontally from the ship's current position to successfully land it on the ship.

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One type of evidence that the Earth has been through colder conditions is the presence of glacial deposits, such as till, striations, and moraines.

Glacial deposit refers to the material that has been deposited by a glacier, either through direct contact or through the action of meltwater.

This material can include rock fragments of various sizes, ranging from fine-grained clay to large boulders, as well as sand and gravel. In some cases, the material may be sorted into distinctive layers, depending on the size and type of the particles.

Glacial deposits can be found in areas that were covered by ice during the last ice age, as well as in areas that are currently covered by glaciers. They provide important clues about the movement and behavior of glaciers and can also be valuable resources for construction and other industries.

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Answer:

i'm pretty sure it's 81 calories

The resistance of a circuit that contains two 50.0 Ω resistors connected in series with a 12.0 V battery is 100 Ω. The resistance of the circuit is equal to the sum of the individual resistors when they are connected in series.

In this case, two 50.0 Ω resistors are connected in series, resulting in a total resistance of 100 Ω. Resistance can be defined as the obstruction that electricity faces when it travels through a conductor. The greater the resistance, the less current is allowed to flow through the circuit. The following equation is used to calculate resistance: R = V / IWhere R is resistance, V is voltage, and I is current.

Resistance can also be calculated using Ohm's Law if we know the values of voltage and current. When resistors are connected in series, the total resistance of the circuit is equal to the sum of the individual resistors. This is expressed by the following equation:RT = R1 + R2 + ... + RNWhere RT is the total resistance of the circuit, and R1, R2, and RN are the individual resistors. In this case, the circuit contains two 50.0 Ω resistors connected in series.

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F = m * a. Algebra can be used to find the acceleration (a = F/m). The following formula is used to determine  the final velocity; if 1000 = 0 + 45t, then 45t = 1000, then t = 1000 / 45, then t = 22.2 seconds

The space shuttle must accelerate from zero to 8,000 meters per second (almost 18,000 miles per hour) in eight and a half minutes in order to reach the minimum height needed to orbit the Earth. To do this, a very special vehicle is required.

A rocket must travel at least 7.9 kilometers per second (4.9 miles per second) in order to reach space if it is launched from the surface of the Earth. The orbital velocity, which is 7.9 km/s and more than 20 times the speed of sound, is measured in this manner.

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Explanation:

Historical sources believe that Henry Ford first saw parts made from vanadium steel in Europe which were been used on racing cars and luxurious vehicles.

Ford was impressed due to the fact that Vanadium steel unlike normal steel was cheaper and at the same time stronger and lighter if it was used on automobiles.

To solve these questions, we can assume that the rate of change of temperature follows a linear model. Let's denote the initial temperature as T0 (20 degrees C), the rate of change as r (unknown), and the time in minutes as t.

(a) To find the reading on the thermometer after 5 more minutes, we need to determine the value of T (temperature) at t = 6 minutes. Using the linear model, we can set up the following equation:

Given that T0 = 20 degrees C and T = 10 degrees C at t = 1 minute, we can substitute these values into the equation:

Simplifying the equation gives us:

Now, we can use the value of r to find the reading after 5 more minutes (t = 6 minutes):

Therefore, the reading on the thermometer after 5 more minutes would be -40 degrees C.

(b) To find when the thermometer will read -11 degrees C, we can set up the following equation using the linear model:

We know that T0 = 20 degrees C, and we want to find the time t when T = -11 degrees C. Substituting these values into the equation, we get:

Simplifying the equation gives us:

Now, we need to use the value of r we found in part (a) (-10) to solve for t:

Dividing both sides by -10 gives:

Therefore, the thermometer will read -11 degrees C approximately 3.1 minutes after it was taken outdoors.

A thermometer, also known as a temperature gauge, is a tool used to measure temperature. The term thermometer comes from the Latin thermo which means heat and meter which means to measure. There are various working principles of the thermometer, the most commonly used is the mercury thermometer.

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\(\longrightarrow \textsf{D. A bicycle sitting on the ground} \)

Let us check all options -

Answer:

mass = 25.5kg

Explanation:

The gravitational force equivalent, or, more commonly, g-force, is a measurement of the type of force per unit mass – typically acceleration – that causes a perception of weight, with a g-force of 1 g equal to the value of gravitational acceleration on Earth, g, of about 9.8 m/s².

Mass, m = \(\frac{Force}{acceleration due to gravity}\)

\(mass,m=\frac{F}{g} = \frac{250}{9.8}= 25.5 kg\)

The radioulnar joint is a synovial joint located at the elbow that connects the radius and the ulna, enabling rotational motion.

The radioulnar joint allows for pronation and supination. Pronation refers to the motion of rotating the forearm so that the palm faces downwards, while supination refers to the motion of rotating the forearm so that the palm faces upwards. The radioulnar joint allows the radius and ulna to move relative to each other, resulting in rotational motion.

When the forearm is pronated, the radius rotates over the ulna and crosses it, while the ulna remains stationary. When the forearm is supinated, the radius rotates back to its original position, and the two bones are parallel to each other.The radioulnar joint is important in many activities, including writing, typing, playing musical instruments, and sports like tennis and golf. Any damage to this joint can result in a loss of pronation and supination, making daily activities challenging.

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Answer:

Explanation:

Given parameters

initial velocity u = 4.9m/s

height of drop H = 100m

acceleration due to gravity g = -9.8m/s²(since the body is ascending i.e moving against gravity)

Required

time taken by the packet to reach the ground 't'

Using the equation of motion

S = ut+1/2gt²

0-100 = 4.9t+1/2(-9.8)t²

-100 = 4.9t-1/2(9.8)t²

-100 = 4.9t-4.9t²

4.9t-4.9t² +100 = 0

4.9t²-4.9t² -100 = 0

Multiplying through by 10

49t²-49t-1000 = 0

Using the general equation t = (-b±√b²-4ac)/2a

t = -(-49)±√(-49)²-4(49)(-1000)/2(49)

t = 49±√(2401+196000)/2(49)

t = 49±√(198401)/98

t = 49±√(198401)/98

t = 49±449.42/98

t = (49+449.42)/98

t = 494.42/98

t = 5.04secs

Hence, it took the packet 5.04secs to reach the ground

The final velocity is calculated using the formula v = u + at

v = u-gt

v = 4.9-(9.8)(5.04)

v = 4.9-49.392

v = -44.492m/s

This shows that the final velocity is 44.49m/s(moving downwards)

A student fires a cannonball vertically upwards with a speed of 42.0m/s. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the cannonball.(a) The cannonball reaches a maximum height of approximately 89.8 meters.(b)The cannonball takes approximately 4.29 seconds to reach its maximum height.(C) The cannonball has a total flight time of approximately 8.58 seconds.

To solve the given questions, we can use the equations of motion for vertical motion under constant acceleration. In this case, the only force acting on the cannonball is gravity, causing it to accelerate downward with an acceleration of approximately 9.8 m/s² (ignoring air resistance).

Given:

Initial velocity (u) = 42.0 m/s

Acceleration due to gravity (a) = -9.8 m/s²

(a) To find the cannonball's maximum height, we can use the equation for displacement (s) in vertical motion:

v² = u² + 2as

At the maximum height, the final velocity (v) will be zero. So we have:

0 = (42.0)² + 2(-9.8)s

Simplifying the equation:

0 = 1764 - 19.6s

19.6s = 1764

s = 1764 / 19.6

s ≈ 89.8 meters

Therefore, the cannonball reaches a maximum height of approximately 89.8 meters.

(b) To find the time it takes for the cannonball to rise, we can use the equation:

v = u + at

At the maximum height, the final velocity (v) is zero. So we have:

0 = 42.0 - 9.8t

9.8t = 42.0

t = 42.0 / 9.8

t ≈ 4.29 seconds

Therefore, the cannonball takes approximately 4.29 seconds to reach its maximum height.

(c) The total flight time of the cannonball is twice the time it takes to reach the maximum height (since it will take the same amount of time to fall back down). So the total flight time is:

2 ×4.29 seconds = 8.58 seconds

Therefore, the cannonball has a total flight time of approximately 8.58 seconds.

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Answer:

R = 1.71 ohms

Explanation:

Two resistors are connected in parallel. There equivalent resistance is given by :

\(\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\)

Put all the values,

\(\dfrac{1}{R}=\dfrac{1}{3}+\dfrac{1}{4}\\\\R=1.71\ \Omega\)

So, the resultant resistance of the circuit is equal to 1.71 ohms.