Take a look around the room. Chances are, almost every type of energy is represented in the room somewhere. write down an example of each type from somewhere in the room.A. Which types can you see?B. Which ones are present but you cannot see?C. Are there any types of energy that are missing?
Answers
Part A. In a room, we are able to see luminous energy from the sunlight and electronic devices' screens. There is also the gravitational potential energy of objects that are at a certain height from the surface, and the electrical energy that make this devices work.
Part B. The energies that are present but we can't see are the kinetic energy of air particles moving at a certain speed, the energy that is transferred in the form of heat due to differences in temperature around the room. The rotational kinetic energy of the computer fan.
Part C. The type of energy that can be missing is the nuclear energy from a nuclear reaction.
Related Questions
The matter in this series of images is going threw a change. Draw a conclusion about the type of change shown. Is it a physical change or a chemical change
Answers
The matter in this series of images is going through a change and a conclusion about the type of change is shown which indicates that it is a chemical change.
What is a Chemical change?This is referred to as the type of change which occurs when the substance's composition is changed and it also occurs when a substance combines with another to form a new substance or when one is broken down into two or more different substances.
The image shown indicates that fire was lit and the substance was subjected to heat which therefore means that there will be gases produced as bubbles are likely to be seen also which indicates a new substance being formed and it is a characteristic of a chemical change which is therefore the reason why it was chosen as the correct choice.
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Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
Answers
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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40 POINTS!!!
A wave travels along a stretched horizontal rope. The vertical distance from crest to trough for this wave is 18 cm and the horizontal distance from crest to trough is 26cm.
Part A
What is the wavelength of this wave?
Express your answer using two significant figures
Part B
What is the amplitude of this wave?
Express your answer using two significant figures.
Answers
part a. the wavelength of this wave is 26 cm
part b. The amplitude (A) of a wave is 9 cm
What is wavelength?The wavelength (λ) of a wave is described as the distance between two consecutive points on the wave that are in phase.
In this scenario, the distance between two corresponding points on the wave will be equal to the horizontal distance from crest to trough, which is 26 cm.
Hence, the wavelength of the wave is: λ = 26 cm
The amplitude (A) of a wave is described as the maximum displacement of a particle from its rest position as the wave passes through it.
In this scenario, the vertical distance from crest to trough is 18 cm, which is equal to twice the amplitude.
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HELP PLEASEEEEEE HELP PLEASE
Answers
The letter that represents the various descriptions is as follows:
5.) Angle of incidence: B
6.) Object: D
7.) Plain mirror:A
8.) Reflection: E
9.) Angle of reflection: C
10.) Normal: F
How does the diagram explain the law of reflection?The law of reflection in a plain mirror states that the angle of reflection is equal to the angle of incidence.
The diagram explains the law of reflection on a plain mirror because it shows the reflection of the object D as E after creating an angle of incidence B on the plane mirror surface A which is equal to the angle of reflection C.
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What is Ohm’s law in simple language?
Answers
Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.
A car traveling 85 km/h is 250 m behind a truck
traveling 73 km/h.
Answers
Time needed = t = 20.83 s
Further explanationGiven
car speed = 85 km/h
truck speed = 73 km/h
Required
the time it takes for the car to reach the truck
Solution
When the car reaches the truck, the distance between them will be the same
x car - 250 m = x truck
General formula for distance (d) :
d = v.t
So the equation becomes :
85t-250 = 73t
12t=250
t = 20.83 s
Mass is sometimes described as the difficulty of acceleration of an object. How does Newton's second law agree with this description?
Answers
Answer:
Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.
If the mass increases, it's harder to accelerate
Because force tends to rise with mass while mass tends to decrease with force, mass is sometimes referred to as the difficulty of accelerating an item. As a result, the greater mass's inverse effect balances out the larger force exerted on more massive objects.
Newton's second law agreement with difficulty of acceleration of an object-While acceleration tends to decrease as mass increases, it tends to increase as force increases. As a result, the bigger force acting on more massive objects is balanced off by the greater mass's inverse effect.As a result, all things fall in free fall at the same rate of acceleration regardless of mass. As the mass increases, accelerating becomes more difficult.Newton's second law of motion is applicable when there are unbalanced forces acting on an object.The second law states that an object's rate of acceleration depends on both its mass and the net force acting on it.An object's acceleration is directly proportional to the net force applied on it and inversely proportional to its mass.An object's acceleration increases as the amount of force exerted on it does.A decreasing acceleration is caused by a rise in an object's mass.The acceleration of an item caused by a net force is inversely proportional to the mass of the object and directly proportional to the magnitude of the net force in the same direction.To learn more about Newton's second law of motion click here-
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Help please :)
Ultraviolet waves are transmitted by ....... ?
Answers
Answer:
Sunlight is the greatest source of UV radiation. Man-made ultraviolet sources include several types of UV lamps, arc welding, and mercury vapour lamps.
Explanation:
In hiking, what fitness component is required of you
Answers
What is the primary evidence used to determine how the Moon formed? O A. Moon craters and Earth craters were caused by the same asteroid
strike.
B. Moon rocks and Earth rocks are made up of many of the same
materials.
O C. The Moon and Earth are exactly the same age.
D. The Moon and Earth have similar atmospheres.
Answers
Explanation it is a
What is the primary evidence used to determine how the Moon formed?
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A. Moon craters and Earth craters were caused by the same asteroid strike. ✅
\(\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}\)
How are magnetic fields like vectors?
Answers
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
How far away should a Cliff be from a source of sound to give an echo in 5.3 second?(given speed of sound at 0°c=331 m/s
Answers
Answer:
Total distance traveled by the sound wave = 2d . Thus we can conclude that the cliff should be at a distance of 877.15 metres from the source of sound to meet the required conditions
Explanation:
this is what i found on the web
A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
Answers
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
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What is the horizontal layer of soil called
Answers
The horizontal layer of soil called are called soil horizons.
What is the horizontal layer of soil called?Soil is made up of clear horizontal layers; these layers are called horizons. They range from rich, organic upper layers (humus and topsoil) to basic rocky layers ( subsoil, regolith, and bedrock). Soils are named and confidentially based on their horizons.
The soil profile has four distinct layers a soil horizon is a horizontal layer of soil with physical or chemical attributes that separate it from layers above and below. More simply, each horizon. Soil is made up of clear horizontal layers. These layers are called horizons.
So we can conclude that A soil horizon is a layer parallel to the soil aspect whose physical, chemical, and biological quality differ from the layers.
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Which TWO types of waves can transmit energy through a vacuum?
A.) radio waves
B.) seismic waves
C.) sound waves
D.) water waves
E.) x-rays
Answers
Answer:
Answer = Radio waves and X-rays
Explanation:
Hope that helps! :)
Explain the light detection technique of photovoltaic detection
Answers
Answer:
Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.
The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.
The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.
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a pound of body fat stores in the amount of chemical energy equivalent to 3500 calories. When sleeping the average adult burns on and expends about 0.45 Cal/h How many calories would a 150 lb person burn during 8 hours of sleep?How how long would the personhave to sleep continuously to lose one pound of body fat
Answers
We know that
• The average is 0.45 calories per hour.
,• The energy stored is 3500 calories per pound of body fat.
,• The mass is 150 pounds.
,• The hours of sleep are 8.
First, we have to multiply the mass 150 lb by the average rate
\(150lb\times0.45=67.5\text{cal}/hr\)This means that this person burns 67.5 calories per hour. Now, we have to multiply this rate by 8 hours.
\(67.5\times8=540\text{cal}\)Therefore, a 150 lb person would burn 540 calories during 8 hours of sleep.Now, we know that 1 pound of body fat is equivalent to 3500 calories. So, let's use a rule of three to find the period of time would take this person to lose one pound of body fat (3500 cal).
\(\frac{67.5\text{cal}}{1hr}=\frac{3500\text{cal}}{x}\)Let's solve for x
\(\begin{gathered} x=\frac{3500}{67.5}hr \\ x\approx51.9hr \end{gathered}\)Therefore, this person would have to sleep continuously for 51.9 hours to lose one pound of body fat.How much force is required to accelerate a 800kg car by 15 m/s2
Answers
Answer:
force=12000
Explanation:
F=m*a aka force equals mass times acceleration so 800*15=12000
Answer:
12000 N
Explanation:
The equation for Force is:
\(Force=mass*acceleration\)
We can plug in the given values into the equation:
\(Force=800kg*15m/s^2\\Force=12000N\)
I actually have 3 questions. >33
1. Write about a time when you felt very cold and did something to make yourself feel warm, or a time when you felt hot and did something to cool yourself down. What caused the heat to transfer from one place to another place? How did this transfer of heat cause a change in temperature?
2. Why is the temperature of the liquid in the flask on the previous page measured when the liquid in the thermometer has stopped rising?
3. How can the thermometer in the flask on the previous page be used to demonstrate the relationship between heat transfer and kinetic energy? Explain.
Answers
When you contact anything hot, the heat is transmitted from the object to your hand, making it feel hot. When you contact something cold, heat is transmitted from your hand to the object, making it feel chilly.
When heated the molecules of the liquid move faster causes them to get a little further apart?when heated, the molecules of the liquid in the thermometer move faster, causing them to get a little further apart. this results in movement up the thermometer. when cooled, the molecules of the liquid in the thermometer move slower, causing them to get a little closer together.
When the liquid in the thermometer is heated, the molecules move quicker, forcing them to move wider apart. This causes the thermometer to rise. When the liquid in the thermometer is chilled, the molecules travel slower, leading them to get closer together.
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A 0.0400 kg meter stick is placed on a thin rod at the 30.0 cm mark. What is the minimum mass required to be placed on the 0.00 cm mark on the stick to maintain equilibrium?
Answer in kg
Answers
The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:
τ = r * F * sin(θ)
where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.
In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.
Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:
τ_M = r_M * F_M * sin(θ)
where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.
Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:
τ_M = τ_stick
r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)
Substituting the given values:
30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)
Solving for F_M:
F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)
F_M = 0.0264 kg * 9.8 m/s^2
F_M = 0.25872 N
Finally, we can convert the force into mass using the formula:
F = m * g
0.25872 N = M * 9.8 m/s^2
M = 0.0264 kg
Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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the radiation that is least damaging to humans is
Answers
The radiation that is least damaging to humans is non-ionizing radiation.
What is non ionizing radiationNon-ionizing radiation refers to the type of radiation that does not have enough energy to remove tightly bound electrons from atoms or molecules, thus not causing significant damage to biological tissues.
Examples of non ionizing radiation include radio waves, microwaves, visible light and low energy ultraviolet (UV) radiation. while excessive exposure to any form of radiation can have adverse effects, non-ionizing radiation is generally considered to be less harmful compared to ionizing radiation, which includes X-rays and gamma rays.
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If energy is conserved in a pendulum then the potential energy at the top does what?
Answers
At the greatest point of the pendulum's swing (the top of the arc), the kinetic energy is at its least since the velocity is momentarily zero.
What is Mechanical Energy?Mechanical energy is the product of potential and kinetic energy. The principle of conservation of mechanical energy states that if an isolated system is subject only to conservative forces, then the mechanical energy is constant.
There are two types of mechanical energy – motion (kinetic energy) and stored (potential energy)
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Given the information in the velocity vs. time graph, what is the displacement of the object after 1 second?
_____ m
After 3 seconds?
_____ m
After 5 seconds?
_____ m
Thank you!!!
Answers
The displacement of the object after 1 second, is 3 m.
The displacement of the object after 3 seconds, is 9 m.
The displacement of the object after 5 seconds, is 15 m.
What is displacement?The displacement of an object is the change in the position of the object.
displacement of the object after 1 secondThe displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m
displacement of the object after 3 secondThe displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m
displacement of the object after 5 secondThe displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m
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Describe a volcanic hazard and explain how it could become a natural disaster.
Answers
A farmer hitches her tractor to a sled loaded with firewood and pulls it a distance
of 20 m along level ground (Figure 3). The total weight of sled and load is 14,700
2
N. The tractor exerts a constant 5000 N force at an of 36.9
◦ angle of above the
horizontal. A 3500 N friction force opposes the sled’s motion. Find the work
done by each force acting on the sled and the total work done by all the forces.
Answers
(a) The work done by the force applied by the tractor is 79,968.47 J.
(b) The work done by the frictional force on the tractor is 55,977.93 J.
(c) The total work done by all the forces is 23,990.54 J.
Work done by the applied forceThe work done by the force applied by the tractor is calculated as follows;
W = Fd cosθ
W = (5000 x 20) x cos(36.9)
W = 79,968.47 J
Work done by frictional forceW = Ffd cosθ
W = (3500 x 20) x cos(36.9)
W = 55,977.93 J
Net work done by all the forces on the tractorW(net) = work done by applied force - work done by friction force
W(net) = 79,968.47 J - 55,977.93 J
W(net) = 23,990.54 J
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A driver needs to make a delivery to an office that is 30 KM away. The driver has traveled for 45 minutes W. down the straight Road at 50 KM/H. Has the driver traveled far enough to reach the office? Support your response. 
Answers
Answer:
Yes, the driver traveled far enough to reach the office.
Explanation:
We can use the formula
\(v=\frac{x}{t}\)
We are given
\(x=30\) KM
\(t=45\) min
\(v=50\) KM/H
Lets convert minutes to hours.
To convert minutes to hours divide the speed by 60.
\(\frac{45}{60} =\frac{3}{4} =0.75\)
Now we have
\(x=30\) KM
\(t=0.75\) H
\(v=50\) KM/H
\(v=\frac{x}{t}\)
Solve for x.
\(x=vt\)
Lets substitute our values into the equation.
\(x=50*0.75\)
\(x=37.5\)
\(37.5 > 30\) So the answer is yes; the driver traveled far enough to reach the office.
The driver has to travel 35 km to reach the office. The distance he covered with a speed of 50 km/h within 45 minutes or 0.75 hour is 37.5 km. Hence, he travelled enough to reach the office.
What is velocity?Velocity of a moving body is the measure of distance it covered within unit time. The velocity is a vector quantity and have a magnitude and direction. The units of velocity are km/h, m/s etc.
Velocity is the ratio of change in distance to the change in time. Hence, distance can be calculated by multiplying the velocity with time.
Given that, velocity of the driver = 50 Km/h
time taken = 45 minutes = 45/60 =0.75 hr
Therefore, the distance = 0.75 hr × 50 km/h = 37.5 km
The distance to the office is 30 km. Therefore, the driver traveled far enough to reach the office.
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the earth's moon has a gravitational field strength of about 1.6 n/kg near its surface. the moon has a mass of 7.35x10^22 kg. what is the radius of the moon? please show work.
Answers
Answer:
1737 kilometers
ConsolidatedEdison'sIndianPointNo.2reactorisdesignedtooperateatapowerof 2,758 MW. Assuming that all fissions occur in 235U, calculate in grams per day the rate at which 235U is (a) fissioned, (b) consumed.
Answers
Answer:
a) the rate at which 235U is fissioned is 2895.9 grams per day
b) the rate at which 235U is consumed is 3385.3071 gram/day
Explanation:
Given the data in the question;
a)
designed operation thermal power = 2758 MW.
we know that, the burn up rate fission rate of 235U is 1.05 grams per MW-day.
so, the rate at which 235U is fissioned will be;
⇒ 2758 × 1.05 = 2895.9 grams per day
Therefore, the rate at which 235U is fissioned is 2895.9 grams per day
b)
Consumption rate is given as;
Cr = 1.05 × ( 1 + ∝ )P gram/day
where ∝ is 0.169 for U-235
so,
Cr = 1.05 × ( 1 + 0.169 )2758 gram/day
Cr = 1.05 × 1.169 × 2758 gram/day
Cr = 3385.3071 gram/day
Therefore, the rate at which 235U is consumed is 3385.3071 gram/day
Kindly please tell me the answer to this question...
Answers
Following are the answers:
Pressure = \(force/area = 1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 PaDensity = Pressure/ (acceleration due to gravity x height) =\(9.79 N/m^2 / (9.8 m/s^2 x 0.92 m)\) = 1060 kg/m^3.What is the pressure and density?1. To calculate the pressure exerted by the water column on the surface of the mercury, we can use the formula:
Pressure = force/area
The force is the weight of the water column and the area is the cross-sectional area of the container.
The weight of the water column is given by the mass of the water times the acceleration due to gravity:
mass = density x volume
volume = area x height
So, mass = density x area x height = 1000 kg/m^3 x pi x (0.025 m)^2 x 0.25 m = 0.196 kg
Weight = mass x acceleration due to gravity =\(0.196 kg * 9.8 m/s^2\) = 1.92 N
The cross-sectional area of the container is pi x (0.025 m)^2 =\(0.196 m^2.\)
So, Pressure = force/area = \(1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 Pa
2. To calculate the density of the oil, we can use the formula:
density = mass/volume
Since the height of the oil column is 0.92 m and the cross-sectional area of the container is 0.196 m^2, the volume of the oil column is 0.196 m^2 x 0.92 m = 0.18012 m^3.
We do not know the mass of the oil, but we can calculate it using the pressure exerted by the oil column on the surface of the mercury:
Pressure = force/area = density x acceleration due to gravity x height
So, density = Pressure/ (acceleration due to gravity x height) = 9.79 N/m^2 / (9.8 m/s^2 x 0.92 m) = 1060 kg/m^3.
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