Task −2 i [30 pts.] 1. Implement a program in Java that, given an array of n integers, places all positive elements at the end of the array without changing the order of positive and negative elements with an O(n) running time complexity. a. Example: b. Input: arr[]={1,−1,3,2,−7,−5,11,6} c. Output: −1−7−5132116 2. Prove that your algorithm takes (O(n)) running time to compute this task. Formulate the sum equation for this proof.

The river's temperature rises downstream of the power plant are about 1.9°C.

The number and variety of animals and plants that inhabit a waterway are influenced by temperature. Seasonal variations in temperature occur naturally, and in streams, rivers, and lakes, the water is typically colder at the bottom (from groundwater input) and warmer at the surface (from higher air temperature). Short river segments that flow continuously experience annual temperature variations that can range from near freezing in the winter to over 40°C in the summer.

WNET = 106 kW,

TH = 550°C

in kelvin, 550+273

= 823.3 K

=0.6327* 10⁶/ 80000*4.184

=1.9 C

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(a) Prob. of a successful call setup is product of prob. of success for each transmission.

(b) The PMF of K, the number of messages transmitted in a call attempt, is:\(P(K=k) = (n choose k) * p^k * (1-p)^(n-k).\)

(c) The probability that the phone will generate a busy signal is: P(busy signal) = \((1-p)^6.\)

(d) To find the minimum value of n necessary probabilty ,we can use the formula:\(n > log(0.02) / log(1-p)\). Plugging in p=0.9 and solving, we get:

\(n > log(0.02) / log(0.1) ≈ 10.1\)

The diagram represents the process of setting up a cellular phone call, where a SETUP message is transmitted to a nearby base station and the phone waits for a response.

Each transmission attempt has an independent probability of success of p. If a response is not received within 0.5 seconds, the phone tries again up to a maximum of n=6 times.

If no response is received after the sixth attempt, the phone generates a busy signal.

The diagram shows a successful transmission and response after each SETUP message in the top six branches, and a busy signal after the sixth attempt in the bottom branch.

Tree Diagram:

Tree diagram:

 -----> SUCCESS (probability p)

/        |

SETUP     -----> SUCCESS (probability p)

\        |

 -----> SUCCESS (probability p)

/        |

SETUP     -----> SUCCESS (probability p)

\        |

 -----> SUCCESS (probability p)

/        |

SETUP     -----> SUCCESS (probability p)

\        |

 -----> SUCCESS (probability p)

/        |

SETUP     -----> SUCCESS (probability p)

\        |

 -----> SUCCESS (probability p)

/        |

SETUP     -----> SUCCESS (probability p)

\        |

 -----> BUSY SIGNAL (probability 1-p)^6

The PMF (Probability Mass Function) of K, which represents the number of messages transmitted in a call attempt, is described by the binomial distribution. In this case, the total number of trials is \(n=6\), which corresponds to the maximum number of attempts the phone makes to transmit the SETUP message.

The probability of success for each transmission attempt is denoted by p, which is the probability that a SETUP message will get through.

The PMF \(P(K=k)\)gives the probability of having exactly k successful transmissions in a single call setup attempt, where k can take any value from 0 to 6.

The formula for\(P(K=k)\) is given by the binomial distribution, which is the product of three factors: the number of ways to choose k successful transmission attempts out of n total attempts, the probability of success raised to the power of k, and the probability of failure\((1-p)\) raised to the power of n-k (which is the number of failed transmission attempts).

The binomial distribution allows us to calculate the probability of obtaining any number of successful transmission attempts in a single call setup attempt.

The probability that the phone will generate a busy signal is the probability that none of the 6 SETUP messages transmitted receive a response, which is represented by the probability of a SETUP message failing to get through, or \((1-p)\).

Since each SETUP message is transmitted independently, the probability of all 6 messages failing to get through is the product of the individual probabilities, which is \((1-p)^6\).

Therefore, this formula gives the probability that the phone will generate a busy signal.

The explanation describes the process to determine the minimum number of trials, denoted by n, required to achieve a probability of a busy signal less than 0.02.

The probability of a busy signal is calculated by finding the probability that all 6 SETUP messages fail to get through, which is\((1-p)^6\). This inequality is then set to be less than 0.02.

By taking the logarithm of both sides, the inequality is simplified to a linear form. Solving for n, we plug in p=0.9 and use logarithmic properties to find that\(n > log(0.02) / log(0.1) ≈ 10.1.\)

Therefore, we conclude that the minimum value of n necessary to achieve a probability of a busy signal less than 0.02 is n=11.

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It doesn't really matter whether your adapters are clean as long as they're not worn is a true statement.

An adapter is said to be a kind of a physical device that gives room for a single hardware or electronic interface to be plugged in(accommodated without loss of function) to another hardware or electronic interface.

An adapter is known to be an electronic device tht is often used in regards to electrical connections.

Note that an adapter can work even if they are dirty. Hence, It doesn't really matter whether your adapters are clean as long as they're not worn is a true statement.

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Answer:

planning of hydraulic and transportation structures

Because the bottom is rich in mineral reserves that are frequently unreachable through conventional mining techniques, seafloor ROV grinders as well as risers are employed for mining.

A person who is employed in the financial sector and consistently produces only little sums of money on modest investments is known by the slang epithet "grinder." Grinders are frequently diligent, well-respected investors who cherish every penny they receive from their assets.

A zombie is a player that is renowned for their intense work ethic and physicality when playing hockey. They often don't get much attention since they rarely create chances and don't make exciting attacking moves.

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Answer:

116,090 Btus

Explanation:

The major types of interior walls and partitions in a larger building are:

It is different because it is more durable than the rest and it is also:

Conclusively, the coats of plaster that are used over expanded metal lath are:

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Technician b is correct that he says affirms that the top main bearing shell will always be pierced by a hole.

A housing, shaft, and lubricant are other parts of the system, which also contains a bearing shell. As a result, they must be developed in concert with the bearing shell as a part of a bearing system as the dependability of the bearing shells is dependent on these other components. Their main objective is to make this rotation of the components almost wear-free. Plain bearings consist of one or two bearing shells that are tightly secured within the bearing seat. The spinning shaft is encircled by the bearing shells at the bearing journals. A steel alloy shell serves as the foundation for every bearing insert, upon which the softer bearing componentsis connected. Bearings may currently be divided into two main categories: those made of aluminum alloy or copper/lead alloy.

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Answer:

D. Turn on the light source and the spectrophotometer.

Explanation:

A spectrophotometer is a machine used to measure the presence of any light-absorbing particle in a solution as well as its concentration. To prepare a spectrophotometer for use, the first step is to turn on the spectrophotometer and allow it to warm up for at least 15 minutes. After this is done, the next step will be to ensure that the samples and blank are ready. Next, an appropriate wavelength is set for the solute being determined. Finally, the absorbance is measured of both the blank and samples.

Answer:

d) "Napoleon Declares Himself Holy Roman Emperor"

Explanation:

The French Revolution is defined as a period of the major social upheaval which began in the year 1787 and lasted till year 1799. This revolution completely redefined the the very nature of the political power in France. and also the relationship between the rulers of France and the people they governed.

The 1789 Estates-General was the 1st meeting since year 1614 of the French Estates-General. It is a general assembly which represents the French estates of  realm.

During the French revolution was at peak, the National Assembly issued the Declaration of the rights of the man to the public.

Maximilien Robespierre was considered to be one of the most influential figure and most important statesman during the French Revolution.

Thus all the options (a),(b) and (c) are headlines about the French Revolution, except option (d).

Answer:

Explanation:

Like requested the following function is written in JavaScript and prompts the user for a total amount of Kenyan Currency that needs to be converted. It then places that value in a variable and divides it by 115 Ksh so that it gives us the USD value of that currency. Then that value is returned. The function can be attached to any button but it must be done manually when creating the button's onClick method.

function convertCurrency() {

 var KenyanAmount = prompt("Please enter the amount of Kenyan you want to convert.");

 var usdValue = "$" + (KenyanAmount / 115);

 return usdValue;

}

The program is a sequential program, and does not require loops and conditional statements

The function in JavaScript where comments are used to explain each line is as follows:

//This defines the function

function convertCurrency() {

//This gets input for the amount to convert

var Amount = prompt("Kenyan Shillings: ");

//This converts the Kenyan Shillings to US Dollars

var usdValue = KenyanAmount / 115;

//This returns the converted amount to the main method

return usdValue;

}

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The steps to find the number of times a letter appears in a string python using a for loop is in the explanation part below.

Follow these instructions to find the number of times a letter appears in a text in Python using a for loop:

The code snippet is:

def count_letter_occurrences(string, letter):

   count = 0

   for char in string:

       if char == letter:

           count += 1

   return count

# Example usage

my_string = "Hello, world!"

target_letter = 'o'

occurrences = count_letter_occurrences(my_string, target_letter)

print(f"The letter '{target_letter}' appears {occurrences} times in the string.")

Thus, this way, one can find the number of times a letter appears in a string python using a for loop.

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Because she has a Victim mindset and having low grade in her Math class, Julianna believes: A. her low grades are the fault of her unfair teacher.

A Victim mindset is also referred to as victim mentality and it can be defined as an acquired personality trait in which an individual tends to recognize and believe that the negative and unfair actions of others towards him or her, is responsible for the bad and unpleasant things that happens.

This ultimately implies that, an individual with a Victim mindset is prejudiced and strongly believes that every other person is against him or her, and as such these people are responsible for their failures.

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Answer:

(a) k = 0.09 s⁻¹

(b) The velocity= ± 16.97 mm/s

Explanation:

(a) Given that the acceleration = a = k(100 - x)

Therefore;

\(a = \dfrac{dv}{dt} = \dfrac{dv}{dx} \times \dfrac{dx}{dt} = \dfrac{dv}{dx} \times v = k(100 - x)\)

When x = 40 mm, v = 0 mm/s hence;

\(\int\limits^v_0 {v } \, dv = \int\limits^x_{40} {k(100 - x)} \, dx\)

\(\dfrac{1}{2} v^2 = k \cdot \left [100\cdot x-\frac{1}{2}\cdot x^{2} \right ]_{x}^{40}\)

\(\dfrac{1}{2} v^2 = -\dfrac{ k\cdot \left (x^{2}-200\cdot x+6400 \right ) }{2}\)

At x = 100 mm, v = 18 mm/s hence we have;

\(\dfrac{1}{2} 18^2 = -\dfrac{ k\cdot \left (100^{2}-200\times 100+6400 \right ) }{2} = 1800\cdot k\)

\(\dfrac{1}{2} 18^2 =162 = 1800\cdot k\)

k = 162/1800 = 9/100 = 0.09 s⁻¹

(b) When x = 120 mm, we have

\(\dfrac{1}{2} v^2 = -\dfrac{ 0.09\times \left (120^{2}-200\times 120+6400 \right ) }{2} = 144\)

Therefore;

v² = 2 × 144 = 288

The velocity, v = √288 = ±12·√2 = ± 16.97 mm/s.

Answer:

b. American Society of Mechanical Engineers

Explanation:

The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.

The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.

Answer:

i did not known answer but anobody help you

Answer:

The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.

Explanation:

From Heat Transfer we determine that heat transfer rate due to electromagnetic radiation (\(\dot Q\)), measured in BTU per hour, is represented by this formula:

\(\dot Q = \epsilon\cdot A\cdot \sigma \cdot (T_{s}^{4}-T_{b}^{4})\) (1)

Where:

\(\epsilon\) - Emissivity, dimensionless.

\(A\) - Surface area of the student, measured in square feet.

\(\sigma\) - Stefan-Boltzmann constant, measured in BTU per hour-square feet-quartic Rankine.

\(T_{s}\) - Temperature of the student, measured in Rankine.

\(T_{b}\) - Temperature of the bus, measured in Rankine.

If we know that \(\epsilon = 0.90\), \(A = 16.188\,ft^{2}\), \(\sigma = 1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}}\), \(T_{s} = 554.07\,R\) and \(T_{b} = 527.67\,R\), then the heat transfer rate due to electromagnetic radiation is:

\(\dot Q = (0.90)\cdot (16.188\,ft^{2})\cdot \left(1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}} \right)\cdot [(554.07\,R)^{4}-(527.67\,R)^{4}]\)

\(\dot Q = 417.492\,\frac{BTU}{h}\)

Under the consideration of steady heat transfer we find that the net energy transfer from the student's body during the 20 min-ride to school is:

\(Q = \dot Q \cdot \Delta t\) (2)

Where \(\Delta t\) is the heat transfer time, measured in hours.

If we know that \(\dot Q = 417.492\,\frac{BTU}{h}\) and \(\Delta t = \frac{1}{3}\,h\), then the net energy transfer is:

\(Q = \left(417.492\,\frac{BTU}{h} \right)\cdot \left(\frac{1}{3}\,h \right)\)

\(Q = 139.164\,BTU\)

The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.

Answer:

Explanation:

The value of a will be zero as it is provided that the particle is on the x-axis.

Calculate the velocity of particles along x-axis.

\({\bf{V}} = 2{x^2}t{\bf{\hat i}} + [4y(t - 1) + 2{x^2}t]{\bf{\hat j}}{\rm{ m/s}}\)

Substitute 0 for y.

\(\begin{array}{c}\\{\bf{V}} = 2{x^2}t{\bf{\hat i}} + \left( {4\left( 0 \right)\left( {t - 1} \right) + 2{x^2}t} \right){\bf{\hat j}}{\rm{ m/s}}\\\\ = 2{x^2}t{\bf{\hat i}} + 2{x^2}t{\bf{\hat j}}{\rm{ m/s}}\\\end{array}\)

Here,

\(A = 2{x^2}t \ \ and\ \ B = 2{x^2}t\)

Calculate the magnitude of vector V .

\(.\left| {\bf{V}} \right| = \sqrt {{A^2} + {B^2}}\)

Substitute

\(2{x^2}t \ \ for\ A\ and\ 2{x^2}t \ \ for \ B.\)

\(\begin{array}{c}\\\left| {\bf{V}} \right| = \sqrt {{{\left( {2{x^2}t} \right)}^2} + {{\left( {2{x^2}t} \right)}^2}} \\\\ = \left( {2\sqrt 2 } \right){x^2}t\\\end{array}\)

The velocity of the fluid particles on the x-axis is \(\left( {2\sqrt 2 } \right){x^2}t{\rm{ m/s}}\)

Calculate the direction of flow.

\(\theta = {\tan ^{ - 1}}\left( {\frac{B}{A}} )\)

Here, θ is the flow from positive x-axis in a counterclockwise direction.

Substitute \(2{x^2}t\) as A and \(2{x^2}t\) as B.

\(\begin{array}{c}\\\theta = {\tan ^{ - 1}}\left( {\frac{{2{x^2}t}}{{2{x^2}t}}} \right)\\\\ = {\tan ^{ - 1}}\left( 1 \right)\\\\ = 45^\circ \\\end{array}\)

The direction of flow is \(45^\circ\) from the positive x-axis.

Solution :

Let \($x(t) = \frac{\sin (20 \pi t)}{\pi t}$\)

\($T_s = 20$\) ms, so \($f_s=\frac{1}{T_s}\)

                           \($=\frac{1}{20}$\)

                           = 0.05 kHz

\($f_s=50 $\) Hz , ws = \($2 \pi f_s = 100 \pi$\)  rad/s

We know that,

FT → \($\frac{\sin (20 \pi \omega)}{\pi \omega}$\)

The sampled signal is :

\($XS(\omega) = \frac{1}{T_s} \sum_{k=- \infty}^{\infty}X (\omega-k\omega S)\)

So, \($XS(\omega) = \frac{1}{20 \times 10^{-3}} \sum_{k=- \infty}^{\infty}X (\omega-100 k \pi)\)

     \($XS(\omega) = 50 \sum_{k=- \infty}^{\infty}X (\omega-100 k \pi)\)

Answer: Kirchhoff's voltage law

Answer:

faster

Explanation:

because in a big grinder you ca only grind bigger things but not Small things , some parts of your things that will

remain as they were in the beginning, so it will take more time to grind Small things .

To create an application with two buttons (Increment and Decrement) and a label to display a numeric value (initially 50), you can use a graphical user interface (GUI) framework like PyQt or Tkinter in Python.

To create an application with the desired functionality, you can use a GUI framework like PyQt or Tkinter in Python. Here's a step-by-step explanation:

1. First, import the necessary modules from the chosen GUI framework.

2. Create a main application window and define its dimensions.

3. Add a label widget to display the numeric value (initialize it with 50).

4. Create two button widgets, one labeled "Increment" and the other "Decrement".

5. Define event handlers for button clicks. In the event handler for the "Increment" button, increment the displayed value by 1. In the event handler for the "Decrement" button, decrement the displayed value by 1.

6. Connect the event handlers to the corresponding buttons.

7. Run the application's main event loop to capture user interactions and update the display accordingly.

That's it! With these steps, you can create an application that presents two buttons (Increment and Decrement) and a label to display a numeric value, allowing the user to increment or decrement the value with each button click.

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The energy required to move one electron through a potential difference of 1.0 x 10^2 volts is 1.6 x 10^-17 joules.

The energy required to move a charged particle, such as an electron, through a potential difference can be calculated using the formula:

E = qV

where E is the energy required in joules (J), q is the charge of the particle in coulombs (C), and V is the potential difference in volts (V).

In this case, we are given the potential difference of 1.0 x 10^2 volts and the charge of an electron, which is 1.6 x 10^-19 C. To find the energy required to move one electron through this potential difference, we simply substitute these values into the formula:

E = (1.6 x 10^-19 C) x (1.0 x 10^2 V)

E = 1.6 x 10^-17 J

Therefore, the energy required to move one electron through a potential difference of 1.0 x 10^2 volts is 1.6 x 10^-17 joules.

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Answer:

The velocity at section is approximately 42.2 m/s

Explanation:

For the water flowing through the pipe, we have;

The pressure at section (1), P₁ = 300 kPa

The pressure at section (2), P₂ = 100 kPa

The diameter at section (1), D₁ = 0.1 m

The height of section (1) above section (2), D₂ = 50 m

The velocity at section (1), v₁ = 20 m/s

Let 'v₂' represent the velocity at section (2)

According to Bernoulli's equation, we have;

\(z_1 + \dfrac{P_1}{\rho \cdot g} + \dfrac{v^2_1}{2 \cdot g} = z_2 + \dfrac{P_2}{\rho \cdot g} + \dfrac{v^2_2}{2 \cdot g}\)

Where;

ρ = The density of water = 997 kg/m³

g = The acceleration due to gravity = 9.8 m/s²

z₁ = 50 m

z₂ = The reference = 0 m

By plugging in the values, we have;

\(50 \, m + \dfrac{300 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{(20 \, m/s)^2}{2 \times 9.8 \, m/s^2} = \dfrac{100 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)50 m + 30.704358 m + 20.4081633 m = 10.234786 m + \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

50 m + 30.704358 m + 20.4081633 m - 10.234786 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

90.8777353 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

v₂² = 2 × 9.8 m/s² × 90.8777353 m

v₂² = 1,781.20361 m²/s²

v₂ = √(1,781.20361 m²/s²) ≈ 42.204308 m/s

The velocity at section (2), v₂ ≈ 42.2 m/s

Answer:

All of them.

Explanation:

I take this class rn too and those are answers